Answer:
The selection probability to be assigned to each of the package designs is 0.20
Step-by-step explanation:
Firstly, we need to assume that one design is just as likely to be selected by a consumer as any other design
so the probability of selecting any of the design is same and that is 1/5 = 0.20
Thus, what we are trying to say is that each of the package designs have an equal selection probability of 0.20
Graph: y = 3/4 x + 5
Answer: The graph is
The graph is plotted and attached.
What is a Function?A function is a law that relates a dependent and an independent variable.
The function is y = 3/4 x + 5
The slope of the line is (3/4)
and the y intercept is 5.
The graph is plotted and attached with the answer.
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5 of 5
It is worked out that if 5 ladles full of soup are given to
each person,
140 people can be fed.
The customers have complained in the past that the
portions are too small.
The cook decides to give 7 ladles full of soup to each
person.
How many people can now be fed soup?
people
Answer:
Number of people that can be served 7 ladles = 100 people
Step-by-step explanation:
We are told that;
Initial number of ladles proposed per person = 5
Number of persons to be fed based on 5 ladles = 140 persons
Thus, amount of ladles based on that data is;
140 people x 5 ladle/1 person = 700 ladles full of soup
Now, since the cook decides to give 7 ladles full of soup to each person, the number of people that can be fed will now be;
700 ladles ÷ 7 ladles/person = 100 persons
Which formula can be used to describe the sequence? - 2/3, -4, -24, -144
Answer:
They are all multiplied by 6
Answer:
Geometric sequence.
Step-by-step explanation:
Here are the terms :
-2/3, -4, -24, -144
Now the first term T1 = -2/3
The second Term T2 = -4
But T2/T1 = -4÷ -2/3 = -4 x -3/2 = 6
Similarly Term 3, T3 = -24
T3/T2 = -24/-4= 6
Hence the expression is a geometric sequence.
a×r^(n-1); a is the first term
r is the common ratio 6
n is the number of terms.
What’s the correct answer for this question?
Answer:
Arc EF = 11.30
Step-by-step explanation:
For Circle A
S = r∅
18.08=(8)∅
Where ∅ is the angle subtended by the Arc
So
∅ = 18.08/8
∅ = 2.26 (in radians)
Now
For Circle C
S = r∅
S = (5)(2.26)
S = 11.30
Solving an Equation Using Algebra Tiles
Arrange the tiles on both boards to find the value of x.
What is the value for x when solving the equation
-x+ (-1) = 3x + (-5) using algebra tiles?
O x= -1
O x= 1
OX= 2
O x=3
Board sum: (-x) + (-1) = 3x + (-5)
Reset
The tiles are ready for moving
Done
Intro
Answer:
[tex]\boxed{ \ x = 1 \ }[/tex]
Step-by-step explanation:
hi,
-x+(-1)=3x+(-5)
<=>
-x-1=3x-5
<=>
3x+x = -1+5 = 4
<=>
4x=4
<=>
x=1
thanks
The value of x when solving the equation -x+ (-1) = 3x + (-5) is 1
Algebraic expression:Algebraic expression is a union of terms by the operations such as addition, subtraction, multiplication, division, etc
-x + (-1) = 3x + (-5)
The value of x can be found as follows:
-x + (-1) = 3x + (-5)
Let's open the parenthesis, Therefore,
-x - 1 = 3x - 5
-x - 3x = -5 + 1
-4x = -4
divide both sides by -4
-4x / -4 = -4 / -4
x = 1
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Use any method to multiply (-14ab)(a + 3b - 4c).
Answer:
-14a^2b-42ab^2+56abc
Step-by-step explanation:
You can use the FOIL method
multiply the first numbers
then inner
then outer
then last
Three dogs eat 30 pounds of food in 10 days. If each dog eats the same amount, how much food does 1 dog eat in 1 day? 1 pound 3 pounds 9 pounds 10 pounds
Answer:
Unable to read entire question, but see explanation for answer
Step-by-step explanation:
First, you need to find the unit rate per dog. If it takes 3 dogs 10 days to finish 30 pounds of food, then it takes 1 dog 1 day to finish 1 pound of food. I cannot read the entirety of the question because of the cropping, but you can find how much food a single dog eats in that amount of days by just multiplying by the number of days (say, 1 pound in 1 day, or 3 pounds in 3 days). Hope this helps!
Answer:
1
Step-by-step explanation:
took test
What is the value of (Negative one-half)–4?
A) -16
B) Negative StartFraction 1 Over 16 EndFraction
C) StartFraction 1 Over 16 EndFraction
D) 16
Answer:
It would be 16!!!
The value of the exponent numerical expression (-1/2)⁻⁴ will be 16. Then the correct option is D.
What is the value of the expression?When the relevant components and basic processes of a numerical method are given values, the expression's result is the result of the computation it depicts.
The definition of simplicity is making something simpler to achieve or grasp while also making it a little less difficult.
The expression is given below.
⇒ (-1/2)⁻⁴
Simplify the equation, then we have
⇒ (-1/2)⁻⁴
⇒ (-2)⁴
⇒ -2⁴
⇒ 16
The value of the exponent numerical expression (-1/2)⁻⁴ will be 16. Then the correct option is D.
More about the value of the expression link is given below.
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For the following report about a statistical study, identify the items below.
To find the public’s views on pollution, researchers waited outside a car dealership they had randomly selected from a list of such establishments. They stopped every 10th person who came out of the dealership and asked whether he or she thought pollution was a serious problem.
A) The population...
B) The population parameter of interest..
C) The sampling frame...
D) The sample...
E) The sampling method, including whether or not randomization was employed...
F) Any potential sources of bias you can detect and any problems you see in generalizing to the population of interest...
Answer:
Check Explanation
Step-by-step explanation:
In finding the public's view on pollution, the researchers waited outside a car dealership they had randomly selected from a list of such establishments. They stopped every 10th person who came out of the dealership and asked whether he or she thought pollution was a serious problem.
A) The population
The population is the sum total of every member of the public whose opinions on pollution, the researchers are interested in.
B) The population parameter of interest
Since the researchers stopped every member of the sample to ask them whether they thought pollution was a serious problem or not, it follows that the population parameter of interest is the proportion of the population who think that pollution is a serious problem.
C) The sampling frame
The sampling frame is defined as the source material where the sample is drawn from. And for this question, the sampling frame is the population of people leaving car dealership establishments.
D) The sample
The sample is the set of people that were asked the question of whether population was a serious problem or not. The sample includes every 10th person that came out of the chosen car dealership establishments.
E) The sampling method
Note that
- In random sampling, each population member would have an equal chance of being surveyed.
- Stratified sampling divides the population into groups called strata. A sample is taken from some or all of these strata using either random, systematic, or convenience sampling.
- In systematic sampling, a particular number, n, is counted repeatedly and each of the nth member is picked to be sampled.
Hence, this stratified sampling method uses random sampling technique to pick the strata where the samples will be obtained from and systematic sampling is now used for the picking of the members of the sample.
F) Any potential sources of bias you can detect and any problems you see in generalizing to the population of interest.
This survey only limits the members of the sample to those who visit a car dealership, and this cuts out a large percentage of the total population of humans.
Mostly men visit car dealership establishments, Hence, women, children, old people are at a disadvantage as they do not all have an equal chance of being surveyed.
Infact, only a financial class of the population visits car dealership establishments, so, it would be very wrong with all of this bias to use the results of this surveyor generalize for the whole population of people.
Hope this Helps!!!
123 grams is rounded to nearest whole. Write down the minimum possible mass it could have been.
Answer:
The nearest whole is 122.99 repeated
Step-by-step explanation:
If a graphical solution to a linear equation
results in the point of intersection (8. 13), then
the solution to the equation is _____
Answer:
The solution to the equation is (8,13).
Step-by-step explanation:
A linear system of equations is composed by two lines.
The solution of the system is the point where the two lines intersect, that is.
In this question:
Point of intersection (8,13).
So
The solution to the equation is (8,13).
a football team had 50 players at the start of the season, but then some players left the team. After that, the team had 42 players
Answer:
50 = p + 42
Step-by-step explanation:
The unknown part of this equation is the variable p, the number of people that left. So you want to add p to 42 and that will give you the total number of football players, which is 50. In order to get p, you need to get it by itself and make it equal something. Subtract 42 from both sides and you are stuck with 50-42 = p
p = 8
Answer:
50-p=42
Step-by-step explanation:
help me about this integral
The gradient theorem applies here, because we can find a scalar function f for which ∇ f (or the gradient of f ) is equal to the underlying vector field:
[tex]\nabla f(x,y,z)=\langle2xy,x^2-z^2,-2yz\rangle[/tex]
We have
[tex]\dfrac{\partial f}{\partial x}=2xy\implies f(x,y,z)=x^2y+g(y,z)[/tex]
[tex]\dfrac{\partial f}{\partial y}=x^2-z^2=x^2+\dfrac{\partial g}{\partial y}\implies\dfrac{\partial g}{\partial y}=-z^2\implies g(y,z)=-yz^2+h(z)[/tex]
[tex]\dfrac{\partial f}{\partial z}=-2yz=-2yz+\dfrac{\mathrm dh}{\mathrm dz}\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C[/tex]
where C is an arbitrary constant.
So we found
[tex]f(x,y,z)=x^2y-yz^2+C[/tex]
and by the gradient theorem,
[tex]\displaystyle\int_{(0,0,0)}^{(1,2,3)}\nabla f\cdot\langle\mathrm dx,\mathrm dy,\mathrm dz\rangle=f(1,2,3)-f(0,0,0)=\boxed{-16}[/tex]
A glucose solution is administered intravenously into the bloodstream at a constant rate r. As the gulcose is added, it is converted into other substances and removed from the bloodstream at a rate that is proportional to the concentration at the time. Thus a model for the concentration C=C(t) of the glucose solution in the bloodstream is
dC/dt=r-kC
Where r an dk are positive constants.
1. Suppose that the concentration at time t=0 is C0. Determine the concentration at any time t by solving the differential equation.
2. Assuming that C0
Answer:
[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]
[tex]C(t) =\dfrac{ r}{k}- e^{ -kt}[/tex] ,thus, the function is said to be an increasing function.
Step-by-step explanation:
Given that:
[tex]\dfrac{dC}{dt}= r-kC[/tex]
[tex]\dfrac{dC}{r-kC}= dt[/tex]
Taking integration on both sides ;
[tex]\int\limits\dfrac{dC}{r-kC}= \int\limits \ dt[/tex]
[tex]- \dfrac{1}{k}In (r-kC)= t +D[/tex]
[tex]In(r-kC) = -kt - kD \\ \\ r- kC = e^{-kt - kD} \\ \\ r- kC = e^{-kt} e^{ - kD} \\ \\r- kC = Ae^{-kt} \\ \\ kC = r - Ae^{-kt} \\ \\ C = \dfrac{r}{k} - \dfrac{A}{k}e ^{-kt} \\ \\[/tex]
[tex]C(t) =\frac{ r}{k} - \frac{A}{k}e^{ -kt}[/tex]
here;
A is an integration constant
In order to determine A, we have [tex]C(0) = C0[/tex]
[tex]C(0) =\frac{ r}{k} - \frac{A}{k}e^{0}[/tex]
[tex]C_0 =\frac{r}{k}- \frac{A}{k}[/tex]
[tex]C_{0} =\frac{ r-A}{k}[/tex]
[tex]kC_{0} =r-A[/tex]
[tex]A =r-kC_{0}[/tex]
Thus:
[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]
2. Assuming that C0 < r/k, find lim t→[infinity] C(t) and interpret your answer
[tex]C_{0} < \lim_{t \to \infty }C(t) \\ \\C_0 < \dfrac{r}{k} \\ \\kC_0 <r[/tex]
The equation for C(t) can be rewritten as :
[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}C(t) =\dfrac{ r}{k} - \left (+ve \right )e^{ -kt} \\ \\C(t) =\dfrac{ r}{k}- e^{ -kt}[/tex]
Thus; the function is said to be an increasing function.
What’s the correct answer for this?
Answer:
C
Step-by-step explanation:
It's of the shape of a cone
3. Find the mean and range of the following data.
14, 14, 15, 15, 16, 15, 15, 16
A 15; 15
B 12; 15
C 12; 2
D 15; 2
Answer:
D: 15 and 2
Step-by-step explanation:
Mean
To find the mean, or average, add up all the values in the data set,then divide by the number of values in the data set.
1. Add up all the values
Values: 14, 14, 15, 15, 16, 15, 15, 16
Add them :14+14+15+ 15+16+15+15+16=120
120
2. Divide by the number of values
Count how many numbers are in the data set. In this case there are 8. Divide 120 by 8.
120/8=15
The mean is 15
Range
To find the range, subtract the smallest number in the set from the biggest number in the set.
14, 14, 15, 15, 16, 15, 15, 16
Biggest number: 16
Smallest number: 14
biggest-smallest
16-14=2
The range is 2
Therefore, the answer is D: 15 and 2
observation means number.
mean= sum of all observation ÷ number of observation
= 14+ 14+ 15+ 15+ 16+ 15+ 16
7
= 105
7
= 15
range= the highest observation - lowest observation
= highest number- 16
lowest number- 14
= 16-14
= 2
therefore the answer is
OPTION- D 15;2
The mean of 3 numbers is 4
The two numbers are 1,9
what is the missing number?
Answer:
2
Step-by-step explanation:
1+9+2 = 12
12/3= 4
Answer:2
Step-by-step explanation:9+2+1=12
So 12/3=4
ANSWER=2
Help me, please ?? :)
Answer:
a) 11
b) 16
c) between 5 and 6
d) 16
Step-by-step explanation:
[tex]\text{a. }\quad\sqrt{121}=\sqrt{11^2}=\boxed{11}\\\\\text{b. }\quad 8\sqrt{4}=8\sqrt{2^2}=8\cdot 2=\boxed{16}\\\\\text{c. }\quad\sqrt{35}\ \dots\ \sqrt{25}<\sqrt{35}<\sqrt{36}\\\\\text{ }\qquad\sqrt{5^2}<\sqrt{35}<\sqrt{6^2}\\\\\text{ }\qquad \boxed{5<\sqrt{35}<6}\\\\\text{d. }\quad\dfrac{.8}{.05}=\dfrac{0.80\cdot 20}{.05\cdot 20}=\dfrac{16}{1}=\boxed{16}[/tex]
What is the square root of x if x = 25?
Answer:
5 is your answer
Step-by-step explanation:
The [tex]\sqrt{25}[/tex] will equal to 5, because [tex]5^2[/tex] = 25
Answer:
5
Step-by-step explanation:
5 x 5 =25, so it is the square root of 25
The accompanying data are the times to failure (in millions per cycle) of high-speed turbine engine bearings made out of two different compounds. These were taken from "Analysis of Single Classification Experiments Based on Censored Samples from the Two-parameter Weibull Distribution" by J.I. McCool (The Journal of Statistical Planning and Inference, 1979) Compound 1 3.03 5.53 5.60 9.30 9.92 12.51 12.95 15.21 16.04 16.84 Compound 2 3.19 4.26 4.47 4.53 4.67 4.69 5.78 6.79 9.37 12.75 (a) Find the 0.84 quantile of the Compound 1 failure times (b) Give the coordinates of the two lower-left points that would appear on a normal plot of the compound 1 data (c) Make back-to-back stem-and-leaf plots for comparing the life length properties of bearings made from Compounds 1 and 2 (d) Make (to scale) side-by-side boxplots for comparing the life lengths for the two compounds. Mark numbers on the plots indicating the locations of their main features (e) Compute the sample means and standard deviations of the two sets of lifetimes (f) Describe what your answers to parts (c), (d), and (e) above indicate about the life lengths of these turbine bearings.
Find the given attachments
Please answer I need help!
Answer:
c & d
Step-by-step explanation:
the description matches the information in the table
Answer: A, B, C
Step-by-step explanation:
domain = x
range = y
A taxi company manager is trying to decide whether the use of radial tires instead of regular belted tires improves fuel economy. Twelve cars were equipped with radial tires and driven over a prescribed test course. Without changing drivers, the same cars were then equipped with regular belted tires and driven once again over the test course. The gasoline consumption, in kilometers per liter, was recorded as follows:
Car Radial-Tires Belted-Tires
1 4.2 4.1
2 4.7 4.9
3 6.6 6.2
4 7.0 6.9
5 6.7 6.8
6 4.5 4.4
7 5.7 5.7
8 6.0 5.8
9 7.4 6.9
10 4.9 4.7
11 6.1 6.0
12 5.2 4.9
A two-sample t-test was used to compare the mean kilometers per liter for the two types of tires using a .05 level of significance. The resulting p-value was .0152.
State the null and alternate hypotheses, state whether the null hypothesis should be rejected or not rejected and your reason for that conclusion, state the meaning of that conclusion specifically in terms of the problem being studied.
Answer:
Step-by-step explanation:
Corresponding gasoline consumption when radial tires is used and gasoline consumption when regular belted tires is used form matched pairs.
The data for the test are the differences between the gasoline consumption when radial tires is used and gasoline consumption when regular belted tires is used.
μd = the gasoline consumption when radial tires is used minus the gasoline consumption when regular belted tires is used.
For the null hypothesis
H0: μd ≥ 0
For the alternative hypothesis
H1: μd < 0
The resulting p-value was .0152.
Since alpha, 0.05 > than the p value, 0.0152, then we would reject the null hypothesis. Therefore, at 5% significance level, we can conclude that the gasoline consumption when regular belted tires is used is higher than the gasoline consumption when radial tires is used.
The vertex of this parabola is at (-2,-3). When the x-value is -1, the y-value is -5. What is the coefficient of the squared expression in the parabola’s equation? A. 8 B. -8 C. -2 D. 2
Answer:
Option C is correct
Step-by-step explanation:
Given: vertex of this parabola is at (-2,-3)
To find: coefficient of the squared expression in the parabola’s equation if the x-value is -1, the y-value is -5
Solution:
The equation of parabola is of the form [tex]y=a(x-h)^2+k[/tex]
Here, a is the coefficient of the squared expression in the parabola’s equation.
Put [tex](h,k)=(-2,-3)\,,\,(x,y)=(-1,-5)[/tex]
[tex]-5=a(-1+2)^2-3\\-5+3=a(1)^2\\-2=a\\a=-2[/tex]
So, the coefficient of the squared expression in the parabola’s equation is [tex]-2[/tex]
Borachio eats at the same fast food restaurant every day. Suppose the time X between the moment Borachio enters the restaurant and the moment he is served his food is normally distributed with mean 4.2 minutes and standard deviation 1.3 minutes. Find the probability that when he enters the restaurant today it will be at least 5 minutes until he is served.
Answer:
26.94% probability that when he enters the restaurant today it will be at least 5 minutes until he is served.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 4.2, \sigma = 1.3[/tex]
Find the probability that when he enters the restaurant today it will be at least 5 minutes until he is served.
This is 1 subtracted by the pvalue of Z when X = 5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{5 - 4.2}{1.3}[/tex]
[tex]Z = 0.615[/tex]
[tex]Z = 0.615[/tex] has a pvalue of 0.7308.
1 - 0.7308 = 0.2694
26.94% probability that when he enters the restaurant today it will be at least 5 minutes until he is served.
I need help solving this
Answer:
The answer is the first one on the bottom left.
Step-by-step explanation:
please help i dont know how to answer this
Answer:
The answer is s / s + 3
Step-by-step explanation:
I applied the fraction rule a/b divided by c/d = a/b times c/d
Please mark BRAINLIEST!
The data from the data sample o 10 paired observations are shown:
Pair Population 1 Population 2
1 19 24
2 25 27
3 31 36
4 52 53
5 49 55
6 34 34
7 59 66
8 47 51
9 17 20
10 51 55
1. If you wish to test whether these data are sufficient to indicate that the mean for population 2 is larger than that for population 1, what are the appropriate null and alternative hypotheses?
2. Assuming that the within-pair differences are approximately normally distributed, conduct
the test using α = 0.1. What is your decision.
3. Find a 90% confidence interval for µd.
Answer:
Step-by-step explanation:
Corresponding means for population 1 and population 2 form matched pairs.
The data for the test are the differences between the mean for population 1 and mean for population 2.
μd = the mean for population 1 minus the mean for population 2.
Population 1 population 2 diff
19 24 - 5
25 27 - 2
31 36 - 5
52 53 - 1
49 55 - 6
34 34 0
59 66 - 7
47 51 - 4
17 20 - 3
51 55 - 4
Sample mean, xd
= (- 5 - 2 - 5 - 1 - 6 + 0 - 7 - 4 - 3 - 4)/10 = - 3.7
xd = - 3.7
Standard deviation = √(summation(x - mean)²/n
n = 10
Summation(x - mean)² = (- 5 + 3.7)^2 + (- - 2 + 3.7)^2 + (- 5 + 3.7)^2+ (- 1 + 3.7)^2 + (- 6 + 3.7)^2 + (0 + 3.7)^2 + (- 7 + 3.7)^2 + (- 4 + 3.7)^2 + (- 3 + 3.7)^2 + (- 4 + 3.7)^2 = 73.7
Standard - eviation = √(73.7/10
sd = 2.71
For the null hypothesis
H0: μd ≥ 0
For the alternative hypothesis
H1: μd < 0
The distribution is a students t. Therefore, degree of freedom, df = n - 1 = 10 - 1 = 9
The formula for determining the test statistic is
t = (xd - μd)/(sd/√n)
t = (- 3.7 - 0)/(2.71/√10)
t = - 4.32
We would determine the probability value by using the t test calculator.
p = 0.00097
Since alpha, 0.1 > than the p value, 0.00097, then we would reject the null hypothesis. Therefore, at 0.1 level of significance, we can conclude that these data are sufficient to indicate that the mean for population 2 is larger than that for population 1.
3) for population 1,
Mean = (19 + 25 + 31 + 52 + 55 + 34 + 59 + 47 + 17 + 51)/10 = 38.4
Summation(x - mean)² = (19 - 38.4)^2 + (25 - 38.4)^2 + (31 - 38.4)^2+ (52 - 38.4)^2 + (49 - 38.4)^2 + (34 - 38.4)^2 + (59 - 38.4)^2 + (47 - 38.4)^2 + (17 - 38.4)^2 + (51 - 38.4)^2 = 2042.4
Standard deviation, s1 = √2042.4/10 = 14.3
for population 2,
Mean = (24 + 27 + 36 + 53 + 55 + 34 + 66 + 51 + 20 + 55)/10 = 42.1
Summation(x - mean)² = (24 - 42.1)^2 + (27 - 42.1)^2 + (36 - 42.1)^2 + (53 - 42.1)^2 + (55 - 42.1)^2 + (34 - 42.1)^2 + (66 - 42.1)^2 + (51 - 42.1)^2 + (20 - 42.1)^2 + (55 - 42.1)^2 = 2248.9
Standard deviation, s2 = √2248.9/10 = 15
The formula for determining the confidence interval for the difference of two population means is expressed as
Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)
For a 90% confidence interval, we would determine the z score from the t distribution table because the number of samples are small
Degree of freedom =
(n1 - 1) + (n2 - 1) = (10 - 1) + (10 - 1) = 18
z = 1.734
x1 - x2 = 38.4 - 42.1 = - 3.7
√(s1²/n1 + s2²/n2) = √(14.3²/10 + 15²/10)
= 6.55
Margin of error = 1.734 × 6.55 = 11.4
The 90% confidence interval is
- 3.7 ± 11.4
HELP ME QUICK!! The best answer I will mark brainlest!
Answer: 1. (4, 8); 2. (3, 4)
Step-by-step explanation: I tried to get this to you fast but I can give you an explaination if you would like one :)
Express this number in scientific notation. 5.3×104+4.7×104
Answer:
for [tex]5.3 * 10^4 + 4.7 * 10^4[/tex] the answer would be [tex]1 * 10^5[/tex]
Step-by-step explanation:
After adding like terms we would get [tex]10^4 *10[/tex]
Then we use the exponent rule and get [tex]10^1^+^4[/tex]
Which after adding would result in [tex]10^5[/tex]
Using the following data on the Observations 10, 13, 4, and 20 confirm that the complete linkage distance between the cluster containing 《10, 13) and the cluster containing (4, 20) s 2.577 units as displayed in the dendrogram
Observation
13 20 0.032 0.195 -0510 0.466 0.741 0.8750.207 0.474 0.700 0.748 -0.004 -0.490 -0.892 0.735 0.219 0.655 -0.1731.013 0.943 0.083 -0.693 -0.489-0.702 -0.458 1.620 2.275 1328 1.733 -0.863 1.035 0.724 0.721 10 Income/Debt Return Cost Load Peak Sales TotalFuelCosts
If required, round your answers to three decimal places.Do not round intermediate calculations
1. Distance from Observation 10 and Observation 4:
2. Distance from Observation 10 and Observation 20:
3. Distance from Observation 13 and Observation 4:
4. Distance from Observation 13 and Observation 20:
Answer:
Step-by-step explanation:
The distance between:
10 and 4: 1.492
10 and 20: 2.055
13 and 4: 2.577
13 and 20: 2.226
The R code:
#Convert your datafile into csv and make sure your row names are 10,13,4 and 20
data=read.csv(file.choose())
data
row.names(data)=c(10,13,4,20)
data
d=dist(data,method="euclidean")
d
fit=hclust(d,method="complete")
plot(fit)
groups=cutree(fit,k=2)
rect.hclust(fit,k=2,border="red")