Answer:
It has potential energy
PE = 15450.75 J
Explanation:
we know its potential energy because the carriage is not moving, although it can
PE = mgh
in this case, m is 75, h is 21, and g is always 9.81
plug these in: PE = (75) (21) (9.81)
your answer: PE = 15450.75 J
A balloon drifts 140 m toward the west in 45 s; then the wind suddenly changes and the balloon flies 90 m toward the east in the next 25 s. a. What distance did it travel during the first 45 s? b. What distance did it travel during the next 25 s? c. What total distance did it travel? d. What was its average speed during the first 45 s? e. What was its average speed during the next 25 s? f. What was its average speed for the entire trip? g. What was its displacement during the first 45 s? h. What was its displacement during the next 25 s? i. What was its total displacement?
Answer:
Explanation:
Given
1 ) 140 m west in 45 s .
2 ) 90 m east in 25 s .
a )
distance travelled in first 45 s = 140 m
b ) distance travelled in next 25 s = 90 m
c ) Total distance travelled = 140 m + 90 m
= 230 m
d ) average speed in first 45 s
= distance in 45 s 45
= 140 / 45 = 3.11 m /s
e ) average speed in next 25 s
distance in 25 s / 25
= 90 / 25 = 3.6 m /s
f ) average in entire trip
= total distance / total time
= (140 + 90) / ( 25 + 45 )
= 3.28 m /s
g )
displacement in first 45 s = 140 m towards west
h )
displacement in next 25 s = 90 m towards east
i )
total displacement = 140 - 90
= 50 m towards west .
An electron with a total energy of 19GeV travels through an accelerator tube with proper length 7.7km. a) What is the length of the tube in the electron's frame? E= m b) How long does it take in the frame of the electron? E= s c) How long does it take in the frame of the tube? T= s Note: the rest energy of an electron is: 0=0.51MeV.
Answer:
a) Approximately 0.2066 m
b) 0.00002568443 s
c) Approximately 188.87 s
Explanation:
a) The total energy of the electron = 190GeV
The rest energy of the electron = 0.51 MeV
[tex]\dfrac{19 \ GeV}{0.51 \ MeV} = 37254.902 = \dfrac{1}{\sqrt{1 + \dfrac{u^2}{c^2} } }[/tex]
[tex]\left ( 1 - \dfrac{u^2}{c^2} \right ) = \dfrac{1}{37254.902^2} } }[/tex]
[tex]\left ( 1 - \dfrac{1}{37254.902^2} } } \right ) = \dfrac{u^2}{c^2}[/tex]
u = √(299792458² × (1 - 1/37254.902²)) = 299792457.892
β = v/c = 299792457.892/299792458 = 0.99999999964
[tex]\beta = \sqrt{1 - \left ( \dfrac{\Delta x}{\Delta x'} \right )^2}[/tex]
Δx = √(Δx'²×(1 - β²)) = √(7700²×(1 - 0.99999999964²)) ≈ 0.2066 m
The length of the tube in the electron's frame ≈ 0.2066 m
b) The time in the frame of the electron is given as follows;
Δt' = 7700/299792457.892 = 0.00002568443 s
c) The time in the frame of the tube is given as follows;
[tex]\beta = \sqrt{1 - \left ( \dfrac{\Delta t'}{\Delta t} \right )^2}[/tex]
1 - β² = (Δt'/Δt)²
Δt = √(Δt'/(1 - β²)) = √(0.00002568443 /(1 - 0.99999999964²)) ≈ 188.87 s.
How can you increase the pressure on an object?
Can someone Plzzz help meee.
solid...............
You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 280 N in the positive x direction to try and move the 63 kg refrigerator. The coefficient of static friction is 0.55.
Complete Question
You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 280 N in the positive x direction to try and move the 63 kg refrigerator. The coefficient of static friction is 0.55.
(a) How much static frictional force does the floor exert on the refrigerator? Give both magnitude and direction.
magnitude N
direction
(b) What maximum force do you need to apply before the refrigerator starts to move?
Answer:
a
The magnitude is [tex]F_f = 339.57 \ N[/tex]
The direction is [negative x - axis ]
b
The maximum force to be applied for the refrigerator to start moving is
[tex]F_{max} = 339.57 \ N[/tex]
Explanation:
From the question we are told that
The horizontal force applied is [tex]F_a = 280 \ N[/tex] the direction is +ve x-axis
The mass of the refrigerator is [tex]m = 63 \ kg[/tex]
The coefficient of static friction is [tex]\mu_s = 0.55[/tex]
Generally the frictional force exerted on the refrigerator is mathematically represented as
[tex]F_f = \mu * m * g[/tex]
=> [tex]F_f = 0.55 * 63 * 9.8[/tex]
=> [tex]F_f = 339.57 \ N[/tex]
From the value obtained we see that the static force exerted by the floor on the refrigerator is greater than the force (280 N ) exerted by the person and the direction is -ve x-axis
Generally the maximum force that is to be applied by the person is mathematically equal to the force exerted by the floor on the refrigerator but the direction is in the positive x-axis i.e
[tex]F_{max} = F_f = 339.57 \ N[/tex]
What is another example of convection?
(A) A heater in a fish tank the bottom of the tank
(B) Batteries in a flashlight converting chemical energy into light
(C) Touching a stove and burning your hand
(D) Warming up next to a fire on a cold night
Answer: The answer is c!
A heater in a fish tank warming the water at the bottom of the tank is an another example of convection.
What is convection of heat?Convection, which is the extensive movement of molecules within gases and liquids, is the mechanism through which heat is transported. Although most of the heat transfer occurs as a result of fluid motion, conduction is initially employed to transfer heat from the item to the fluid.
As a result of material movement, heat is transmitted through fluids by convection.Both gases and liquids can contain it.It might be forced or organic.It is important to transfer part of the fluid in bulk.Convection is therefore demonstrated by a heater in a fish tank warming the water at the tank's bottom.
Learn more about convection of heat here:
brainly.com/question/16600140
#SPJ2
What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100 g of the substance increases in temperature from 10 degrees Celsius to 70 degrees Celsius?
Answer:
I'm sorry to inform that I couldn't find an answer to this question. Socratic can help! This learning app, powered by Google AI, helps you understand your school work at a high school and university level. Ask Socratic a question and the app will find the best online resources for you to learn the concepts.
Explanation:
25 POINTS!
A 60 kg man is moving at 2 m/s. What is his kinetic energy?
A. 60 J
B. 240 J
C. 30 J
D. 120 J
You throw a ball straight down off the roof of a 47 m tall building with an initial velocity of -8m/s.
When does the ball hit the ground?
Answer:
t = 2.38 [s]
Explanation:
To solve this problem we must use the following equation of kinematics. We must clarify that both the acceleration and the initial velocity were taken as positive, since the velocity of the movement coincides with the direction of the acceleration.
[tex]x =x_{o} +v_{o} *t+(\frac{1}{2} )*a*t^{2}[/tex]
where:
x - Xo = distance = 47 [m]
Vo = initial velocity = 8 [m/s]
a = gravity acceleration = 9.81 [m/s²]
t = time [s]
Now replacing these values in the equation:
47 = 8*t + 0.5*9.81*t²
47 = 8t + 4.905t²
47 = 4.905*t(1.63 + t)
9.58 = t*(1.63 + t) solving this equation (cuadratic)
we found that t = 2.38 [s]
A dog jumps 0.80 m to catch a treat. The dog's displacement vector is shown below.
Which diagram shows the vertical and horizontal components of the dog's displacement?
Choose 1 answer:
Answer:D
Explanation:
It was right o khan academy
A dog jumps 0.80 M to catch a treat. The dog's displacement vector is shown below.
Which diagram shows the vertical and horizontal components of the dog's displacement?
THE ANSWER IS IN THE ATTACHMENT!
A ball weighing 60 N is swinging like a pendulum at the end of a 6.0 m rope. As the
ball swings through its lowest point, its speed is measured at 5.0 m/s. What is the
tension in the rope at this point?
Answer:
Tension = 60 N
Explanation:
The ball is executing a motion like a pendulum. The lowest point of a pendulum's motion is the mean position, where its potential energy becomes zero and kinetic energy becomes maximum. At this point the rope becomes straight vertical. Hence, the tension in the rope becomes exactly equal to the weight of the object at the lowest point. Also, in this case when the ball swings through the lowest point during its motion like a pendulum, the tension in the rope will become equal to the weight of the ball.
Tension = Weight
Tension = 60 N
There is friction between the block and the
table.
The suspended 2 kg mass on the left is
moving up, the 4 kg mass slides to the right
on the table, and the suspended mass 4 kg on
the right is moving down.
The acceleration of gravity is 9.8 m/s
2
.What is the magnitude of the acceleration
of the system?
1. 1.67253
2. 1.9845
3. 1.75311
4. 2.47673
5. 2.1315
6. 2.058
7. 2.548
8. 1.33933
9. 1.5288
10. 2.03127
Answer in units of m/s
2
.
Answer:
5 no
Explanation:
actually the 4kg lying on table has no influence
it slides towards 4kg weight hung
as it has excess 2kg force
force=miu × m ×g
The magnitude of acceleration of the entire system is [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.
Given data:
The masses suspended from the table are, m = 2 kg and m' = 4 kg.
And the mass kept on the table is, m'' = 4 kg.
The frictional force will oppose the motion of mass 4 kg, kept on the table. Then the required value of frictional force is,
[tex]f = \mu \times m'' \times g\\\\f = 0.11 \times 4 \times 9.8\\\\f = 4.312 \;\rm N[/tex]
Since, the mass kept on the right side is more. Then at equilibrium,
-f + m''g + (m' +m)a = m'g
Here,
a is the magnitude of acceleration of the system.
Solving as,
-4.312+ 4(9.8) + (4 -2)a = 4(9.8)
2a = 4.312
[tex]a \approx 2.1315 \;\rm m/s^{2}[/tex]
Thus, we can conclude that the magnitude of acceleration of the entire system is [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.
Learn more about the linear acceleration here:
https://brainly.com/question/14214161
A 200 g blob of clay moves with a speed of 10 m/s towards a 300 g cart that is initially at rest.
a. What is the momentum of the system before the blob of clay strikes the cart?
b. What must be the momentum of the system after they come together?
c. If the blob of clay sticks to the cart, with what speed will the clay and cart move after they come together?
Answer:
a. 2 kg*m/s
b. [tex]p_{T_{f}} = 0.5v_{f} = 2 kg*m/s[/tex]
c. 4 m/s
Explanation:
a. The momentum of the system ([tex]p_{Ti}[/tex]) before the blob of clay strikes the cart is:
[tex] p_{Ti} = p_{b} + p_{c} [/tex]
Where:
[tex]p_{b}[/tex] is the momentum of the blob clay
[tex]p_{c}[/tex] is the momentum of the car
[tex] p_{Ti} = m_{b}v_{b} + m_{c}v_{c} [/tex]
Since the car is initially at rest, [tex]v_{c}[/tex] = 0
[tex] p_{Ti} = 200 g*\frac{1 kg}{1000 g}*10 m/s + 0 = 2 kg*m/s [/tex]
b. The momentum of the system after they come together:
[tex]p_{T_{f}} = m_{b}v_{b} + m_{c}v_{c}[/tex]
Since they come together, [tex]v_{b}[/tex] =
[tex]p_{T_{f}} = v_{f}(m_{b} + m_{c}) = v_{f}(0.2 kg + 0.3 kg) = 0.5v_{f}[/tex] (1)
Because we do not have the final speed we can not calculate the final momentum.
c. We can find the speed of the clay and car by conservation of the momentum:
[tex] p_{i} = p_{f} [/tex]
The initial momentum of the system was founded in part "a" (p = 2 kg*m/s), so we have:
[tex] 2 kg*m/s = m_{b}v_{b_{f}} + m_{c}v_{c_{f}} [/tex]
Again, when they come together, the final speed is the same:
[tex] 2 kg*m/s = v_{f}(m_{b} + m_{c}) [/tex]
[tex] v_{f} = \frac{2 kg*m/s}{0.2 kg + 0.3 kg} = 4 m/s [/tex]
Now, since we found the final speed we can calculate the momentum of the system after they come together (equation 1):
[tex] p_{T} = 0.5v_{f} = 0.5 kg*4m/s = 2 kg*m/s [/tex]
I hope it helps you!
What is the current in the 10.0 resistor?
Answer:
12.0V
12.0V
Explanation:
.
.
.
.
.
.
.
.
.
.
.
Answer:
2.00 A
Explanation:
When an 8 V battery is connected to a resistor, a 2 A current flows in the resistor. What is the resistor's value?
Ο Α. 2Ω
Ο Β. 4 Ω
Ο C. 8Ω
Ο D. 16 Ω
Answer:
B
Explanation:
V=IR I= curren V=volt R=resistor
8=2.R 8/2=R R=4
A box sitting still on the ground by itself has a Normal Force of 700N, what is the mass? (gravity’s acceleration is 9.80 m/s²)
Answer:
Mass, m = 71.42 kg
Explanation:
Given that,
Normal force acting on a box, F = 700 N
We need to find the mass of a box. Let it is m. Normal force acting on an object is balanced by its weight such that,
F = mg
Where m is the mass of the box
[tex]m=\dfrac{F}{g}\\\\m=\dfrac{700\ N}{9.8\ m/s^2}\\\\m=71.42\ kg[/tex]
So, the mass of the box is 71.42 kg.
Please help me fast
Answer:
b I think. sorry if it's wrong
If a force of 12 N is applied to an object
and it accelerates 4 m/s2, what is the
mass of the object?
Answer:
The answer is 3 kgExplanation:
The mass of the object can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{12}{4} \\ [/tex]
We have the final answer as
3 kgHope this helps you
How much voltage is required to run 0.054 A of current through a 152
resistor? Use AV = IR.
A. 3.6 x 10-3V
B. 2.8 x 102V
C. 1.2 V
D. 0.81 V
V = I • R
V = (0.054 A) • (152 ohms)
V = 8.208 volts
None of the listed choices is correct.
A 3kg ball moving at 8 m/s strikes a 2kg ball at rest,if the collision is elastic,what is the speed of the lighter ball if the heavier ball moves at 2m/s in the opposite direction
Answer:
Speed of lighter ball is 4 m/s.
Explanation:
Applying the principle of conservation of linear momentum,
momentum before collision = momentum after collision.
[tex]m_{1}[/tex][tex]u_{1}[/tex] + [tex]m_{2}[/tex] [tex]u_{2}[/tex] = [tex]m_{1}[/tex][tex]v_{1}[/tex] - [tex]m_{2}[/tex][tex]v_{2}[/tex]
[tex]m_{1}[/tex] = 3 kg, [tex]u_{1}[/tex] = 8 m/s, [tex]m_{2}[/tex] = 2 kg, [tex]u_{2}[/tex] = 0 m/s ( since it is at rest), [tex]v_{1}[/tex] = 2 m/s, [tex]v_{2}[/tex] = ?
(3 x 8) + (2 x 0) = (8 x 2) - (2 x [tex]v_{2}[/tex])
24 + 0 = 16 - 2[tex]v_{2}[/tex]
2[tex]v_{2}[/tex] = 16 - 24
2[tex]v_{2}[/tex] = -8
[tex]v_{2}[/tex] = [tex]\frac{-8}{2}[/tex]
= -4 m/s
This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.
A sample contains 20 kg of radioactive material. The decay constant of the material is 0.179 per second. If the amount of time that has passed
is 300 seconds, how much of the of the original material is still radioactive? Show all work
Answer:
There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.
Explanation:
From Physics we know that radioactive materials decay at exponential rate, whose differential equation is:
[tex]\frac{dm}{dt} = -\lambda\cdot m[/tex] (1)
Where:
[tex]\frac{dm}{dt}[/tex] - Rate of change of the mass of the radioactive material, measured in kilograms per second.
[tex]m[/tex] - Current mass of the radioactive material, measured in kilograms.
[tex]\lambda[/tex] - Decay constant, measured in [tex]\frac{1}{s}[/tex].
The solution of the differential equation is:
[tex]m(t) = m_{o}\cdot e^{-\lambda\cdot t}[/tex] (2)
Where:
[tex]m_{o}[/tex] - Initial mass of the radioactive material, measured in kilograms.
[tex]t[/tex] - Time, measured in seconds.
If we know that [tex]m_{o} = 20\,kg[/tex], [tex]\lambda = 0.179\,\frac{1}{s}[/tex] and [tex]t = 300\,s[/tex], then the initial mass of the radioactive material is:
[tex]m(t) = (20\,kg)\cdot e^{-\left(0.179\,\frac{1}{s} \right)\cdot (300\,s)}[/tex]
[tex]m(t) \approx 9.537\times 10^{-23}\,kg[/tex]
There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.
1. A force acting on an object in the upward direction is 3 N. The force that would
balance this force could be written as
will balance because 3 N + (____
-) =
acts in the
direction.
You that know these forces
The balancing force
Answer:
See the explanation below
Explanation:
We must perform a sum of forces on the body, that sum of forces is equal to zero. That is, the body is in balance and does not move.
ΣF = 0
3 - 3 = 0
This force is negative and acts by pointing downwards.
Answer: ow consider a book sliding from left to right across a tabletop. Sometime in the prior history of the book, it may have been given a shove and set in motion from a rest position. Or perhaps it acquired its motion by sliding down an incline from an elevated position. Whatever the case, our focus is not upon the history of the book but rather upon the current situation of a book sliding to the right across a tabletop.
Explanation:
PLS HELP ME THIS IS DUE TONIGHT
By listening for it underwater, using SONAR.
Hope this helped!
A fighter jet flies 3 km west and then 2 km east in 8 minutes. Determine the jet's average velocity. (Remember to convert!)
Answer:
7.69km/hr due east
Explanation:
Given parameters:
Displacement due west = 3km
Displacement due east = 2km
Time taken = 8 minutes
Unknown:
Average velocity = ?
Solution:
Average velocity is the rate of change of displacement with time.
Velocity = [tex]\frac{displacement}{time }[/tex]
Displacement is deals with the start and the end;
Here, displacement = 3km - 2km = 1km due east
Time = 8min
60min = 1hr
8min = [tex]\frac{8}{60}[/tex] = 0.13hr
Average velocity = [tex]\frac{1km}{0.13hr}[/tex] = 7.69km/hr due east
005 (part 1 of 2) 10.0 points
A runner is jogging in a straight line at a
steady vr= 8.5 km/hr. When the runner is
L=6.4 km from the finish line, a bird begins
flying straight from the runner to the finish
line at vý= 17 km/hr (2 times as fast as the
runner). When the bird reaches the finish
line, it turns around and flies directly back to
the runner
What cumulative distance does the bird
travel? Even though the bird is a dodo, as-
sume that it occupies only one point in space
(a "zero" length bird). travels in a straight
line, and that it can turn without loss of
Speed
Answer:
7.53 km
Explanation:
We at given;
Speed of runner; v_r = 8.5 km/hr
Speed of bird; v_y = 17 km/hr
L = 6.4 km
We know that; time = distance/speed.
We are told that the bird starts from 6.4 km from the start and that it flies back to meet the runner after it reaches the finish line. If the total distance back to the runner is x, it means bird distance is 6.4 + (6.4 - x) = 12.8 - x
Thus;
Time of bird(t_y) = (12.8 - x)/17
Thus,
Time of runner(t_r) = x/8.5 hr
To find x, we have to equate the times of the runner and the bird.
Thus;
x/8.5 = (12.8 - x)/17
Multiply both sides by 17 to get;
2x = 12.8 - x
2x + x = 12.8
3x = 12.8
x = 12.8/3
x = 4.27 km
Thus, cumulative distance traveled by bird is; 12.8 - 4.27 = 7.53 km
Choose the best real world exzample of convection:
A. clouds forming in the atmosphere
B. touching a warm cooking pot handle
C. sitting in front of a warm fireplace
WHICH ONE IS THE ANSWER HELP PLESEEE
For a substance to change phases, the amount of Internal energy must change. Water exists in three phases: liquid, solid (ce), and gas (water vapor). Which of the following lists the
phases in order of increasing total energy?
O
gas, liquid, solid
solid, gas, liquid
solid, liquid, gas
oliquid, gas, solld
which of the following influences healthy sexual attitude
1.family 2.friends 3.media 4.self
A weight lifter is trying to lift a 1,500 N weight but can apply a force of only 1,200 N on the weight. One of his friends helps him lift it at a constant velocity. What force was applied to the rope
Answer:
400N is applied to the rope
Answer:
300N
Explanation:
Assuming his friend didn't throw the box, they would need a total of 1,500N to lift it, if the first person is already applying 1,200N, the only other amount of force needed is 300N to make a total of 1,500N! Simple math problem :)
Hope this helps! <3
What is the radius of an automobile tire that turns with a period of 0.091 s and has a linear
speed of 20.0 m/s? What kind of force is the centripetal force?
Answer:
1) The radius of the tire is approximately 0.28966 meters
2) The centripetal force is the force that keeps a body moving on a circular path
Explanation:
1) The linear speed of the automobile tire = 20.0 m/s
The period with which the tire turns = 0.091 s
The period = The time it takes to make a complete turn
Therefore;
The number of turns in 1 second = 1/0.091 ≈ 10.989 turns
The distance covered with 10.989 turns, assuming no friction = 10.989 × The circumference of the tire
∴ The distance covered with 10.989 turns, assuming no friction = 10.989 × 2 × π × Radius of the tire
From the speed of the car, 20.0 m/s, we have;
The distance covered in 1 second = 20.0 meters
Therefore;
10.989 × 2 × π × Radius of the tire = 20.0 meters
Radius of the tire = (20.0 meters)/(10.289 × 2 × π) ≈ 0.28966 meters
The radius of the tire ≈ 0.28966 meters
2) The centripetal force is the force required to maintain the curved motion of an object, and having a direction towards the center of the rotary motion.
The centripetal force is given by the formula, [tex]F = \dfrac{m \cdot v^2}{r}[/tex]
Where;
F = The centripetal force
m = The mass of the object
v = The linear velocity of the object
r = The radius of the rotational motion.