A computer manufacturer conducted a survey. It showed that a younger customer will not necessarily purchase a lower or higher priced computer. What is likely true? There is no correlation between age and purchase price. There is a correlation between age and purchase price. There may or may not be causation. Further studies would have to be done to determine this. There is a correlation between age and purchase price. There is probably also causation. This is because there is likely a decrease in the purchase price with a decrease in age.

Answers

Answer 1

Answer:

There is no correlation between age and purchase price

Step-by-step explanation:

In the survey, the researcher found out that a younger customer will not necessarily purchase a lower or higher priced computer thing it is likely true that there might be no correlation between purchase price and age.

It assumes that a younger customer can buy either buy a lower priced computer or can also buy a higher priced if he or she has the money for it.


Related Questions

you need 418 yards of blue silk to make one bridesmaid’s dress and 358 yards of the same fabric to make another. How many yards of blue silk do you need to make both dresses?

Answers

Answer: you would need 776 yards to make both dresses

Step-by-step explanation:

You would need to find the sum of the amount if yards needed for both dresses.

The first dress needs 418 yards

The seconds dress needs 358 yards

418 + 358 = 776

Therefore you would need 776 yards to be able to make both of the dresses

what is 2/3 of 460? Just a little easy one for points​

Answers

Answer:

2/3 * 460 = 306 and 2/3

Multiply 460 by 2/3 by first multiplying 460 by 2, then divide that by 3:

460 x 2 = 920

920 /3 = 306 2/3

The answer is 306 2/3

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16. Which sentence would be a good counterexample to this statement?

A line can exist in only one plane.

A) A line intersects one plane and then another.
B) A line that is coplanar exists in more than one plane.
C) A line is the intersection of two planes.
D) A line is parallel to one plane at a time.

17. Which statement is needed to complete this syllogism?

If the angles of a triangle are all equal, then the sides of a triangle are all equal.
If the sides of a triangle are all equal, then the triangle is equilateral.
Therefore, if the angles of a triangle are all equal,then________________________.


A) the sides of a triangle are all equal
B) the angles of a triangle are all equal
C) the triangle is equiangular
D) the triangle is equilateral

Answers

Answer:

16. A

17. D

Step-by-step explanation:

16. By saying that a line intersects one plane and then another, you are saying that a line is existing on two planes. This is a direct contradiction to the statement.

17. The triangle is equilateral because syllogism is basically connecting the dots. If the angles in the triangle are all equal, it has all equal sides, and if it has all equal sides, then it is equilateral, therefore, it is D, not C.

Find the general solution to y′′+6y′+13y=0. Give your answer as y=.... In your answer, use c1 and c2 to denote arbitrary constants and x the independent variable. Enter c1 as c1 and c2 as c2.

Answers

Answer:

[tex]y(x)=c_1e^{-3x} cos(2x)+c_2e^{-3x} sin(2x)[/tex]

Step-by-step explanation:

In order to find the general solution of a homogeneous second order differential equation, we need to solve the characteristic equation. This is basically as easy as solving a quadratic.

For a second order differential equation of type:

[tex]ay''+by'+cy=0[/tex]

Has characteristic equation:

[tex]a r^{2} +br+c=0[/tex]

Whose solutions [tex]r_1 , r_2 ,.., r_n[/tex] are the roots from which the general solution can be formed. There are three cases:

Real roots:

[tex]y(x)=c_1e^{r_1 x} +c_2e^{r_2 x}[/tex]

Repeated roots:

[tex]y(x)=c_1e^{r x} +c_1 xe^{r x}[/tex]

Complex roots:

[tex]y(x)=c_1e^{\lambda x}cos(\mu x) +c_2e^{\lambda x}sin(\mu x)\\\\Where:\\\\r_1_,_2=\lambda \pm \mu i[/tex]

Therefore:

The characteristic equation for:

[tex]y''+6y'+13y=0[/tex]

Is:

[tex]r^{2} +6r+13=0[/tex]

Solving for [tex]r[/tex] :

[tex]r_1_,_2= -3 \pm 2i[/tex]

So:

[tex]\mu = 2\\\\and\\\\\lambda=-3[/tex]

Hence, the general solution of the differential equation will be given by:

[tex]y(x)=c_1e^{-3x} cos(2x)+c_2e^{-3x} sin(2x)[/tex]

The percent, X, of shrinkage on drying for a certain type of plastic clay has an average shrinkage percentage :, where parameter : is unknown. A random sample of 45 specimens from this clay showed an average shrinking percentage of 18.4 and a standard deviation of 2.2. est at 5% level of significance whether the true average shrinkage percentage : is greater than 17.5 and write your conclusion. Report the p-value.

Answers

Answer:

[tex]t=\frac{18.4-17.5}{\frac{2.2}{\sqrt{45}}}=2.744[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=45-1=44[/tex]  

The critical value for this case is [tex]t_{\alpha}=1.68[/tex] since the calculated value is higher than the critical we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 18.4

[tex]p_v =P(t_{(44)}>2.744)=0.0044[/tex]  

We see that the p value is lower than the significance level so then we can reject the null hypothesis in favor of the alternative.

Step-by-step explanation:

Information given

[tex]\bar X=18.4[/tex] represent the sample mean

[tex]s=2.2[/tex] represent the sample standard deviation

[tex]n=45[/tex] sample size  

[tex]\mu_o =17.5[/tex] represent the value to verify

[tex]\alpha=0.05[/tex] represent the significance level

t would represent the statistic

[tex]p_v[/tex] represent the p value

We want to test if the true mean is higher than 17.5, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 17.5[/tex]  

Alternative hypothesis:[tex]\mu > 17.5[/tex]  

The statistic is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex]  (1)  

And replacing we got:

[tex]t=\frac{18.4-17.5}{\frac{2.2}{\sqrt{45}}}=2.744[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=45-1=44[/tex]  

The critical value for this case is [tex]t_{\alpha}=1.68[/tex] since the calculated value is higher than the critical we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 18.4

The p value would be given by:

[tex]p_v =P(t_{(44)}>2.744)=0.0044[/tex]  

We see that the p value is lower than the significance level so then we can reject the null hypothesis in favor of the alternative.

(x-5)(x+1)=x-5 3(x+1) 3 For what values of x are the two expressions equal ?

Answers

Answer:

x=-77+5√ 231 x=-77-5√231

I got this answer for x and the both equations are equal

what the product of the reciprocals of 2/3, 1/8, and 5​

Answers

Answer:

12/5

Step-by-step explanation:

Reciprocal of 2/3 is 3/2

Reciprocal of 1/8 is 8/1

Reciprocal of 5 is 1/5

[tex]\frac{3}{2} \times \frac{8}{1} \times\frac{1}{5} = \frac{24}{10} \\[/tex]

Can be simplified to

[tex]\frac{12}{5}[/tex]

In 1970, 59% of college freshmen thought that capital punishment should be abolished; by 2005, the percentage had dropped to 35%. Is the difference real, or can it be explained by chance

Answers

Answer:

there is significant distinction in opinion regarding abolition of capital punishment.

Step-by-step explanation:

Compute the p cost of 2-proportion for estimating difference. The Minitab output pronounces the p valu eto be 0.000. This is less than the assumed importance degree of alpha = 0.05. Therefore, reject null hypothesis to finish that there is significant distinction in opinion regarding abolition of capital punishment.

Provide three logically possible directions of causality, indicating for each direction whether it is a reasonable explanation for the correlation based on the variables involved. Explain why?

Answers

Answer:

Step-by-step explanation:

find ∠AEC in the figure below.

Answers

Answer:

  C. 105°

Step-by-step explanation:

Angles BED and CED are supplementary, so ...

  (2y +x) +(-2y +3x) = 180

  4x = 180

  2x = 90

Substituting this into the expression for angle AEB, we have ...

  Angle AEB = (90 -15)° = 75°

Angle AEC is the supplement to that, so is ...

  ∠AEC = 180° -75° = 105° . . . . . matches choice C

Answer: C. 105

Step-by-step explanation:

Adding BED and DEC for being adjacent angles we obtain:

[tex]2y+x +-2y+3x = 180\\4x = 180\\x=45\\[/tex]

Substituting x in BEA

[tex]BEA=2(45)-15=75[/tex]

Adding BEA and AEC for being adjacent angles we obtain:

[tex]BEA+AEC=180\\AEC=180-BEA\\AEC=180-75\\AEC=105[/tex]

Moise Moliere
Mrs. Johnson has 159 chickens that she puts in shelters at night to keep safe. She places 12 chickens in a shelter
and continues putting this number of chickens in each shelter until she comes to the last one. How many chickens
will Mrs. Johnson put in the last shelter?
3
4
13
11
6
7
8 9 10
14
Back
2 3 4 5
9:3
INTL​

Answers

Answer: she putz 9 in the last shelter

Step-by-step explanation:

Peter, Gordon and Gavin share £36 in a ratio 2:1:1. How much money does each person get?

Answers

Answer:

Peter gets 18£

Gordon and Gavin each get 9£

Answer:

peter = 18 Gordon = 9 Gavin = 9

Step-by-step explanation:

2+1+1 = 4

36 div 4 = 9

2 times 9 = 18

1 times 9 = 9

What is the value of
3/7x0.1/5/21
?
7
А.1/98
B.9/50
С.9/5
D.18/1

Answers

Answer:

B

Step-by-step explanation:

[tex]\dfrac{3}{7}\times 0.1 \div \dfrac{5}{21}= \\\\\\\dfrac{3}{7}\times \dfrac{1}{10}\times \dfrac{21}{5}= \\\\\\\dfrac{3\times 1 \times 21}{7 \times 10 \times 5}=\\\\\\\dfrac{63}{350}=\\\\\\\dfrac{9}{50}[/tex]

Therefore, the correct answer is choice B. Hope this helps!

Answer:

The answer to your question is 9/50

The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min. If one such class is randomly selected, find the probability that the class length is between 50.1 and 51.1 min. P(50.1 < X < 51.1) =

Answers

Answer:

P(50.1 < X < 51.1) = 0.5

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X between c and d is given by the following formula:

[tex]P(c < X < d) = \frac{d - c}{b - a}[/tex]

The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.

This means that [tex]a = 50, b = 52[/tex]

So

[tex]P(50.1 < X < 51.1) = \frac{51.1 - 50.1}{52 - 50} = 0.5[/tex]

Which values for h and k are used to write the function f(x) = x2 + 12x + 6 in vertex form?
h=6, k=36
h=-6, k=-36
h=6, k=30
h=-6, k=-30

Answers

Answer: The answer is h=-6, k=-30

Step-by-step explanation:

d on edg

A soup can has a diameter of 8 centimeters and a height of 15 centimeters how much soup does the can hold?

Answers

Answer:

V = 240 pi

Step-by-step explanation:

We want the volume of a cylinder

V = pi r^2 h

We have the diameter and want the radius

r = d/2 = 8/2 = 4

V = pi ( 4)^2 * 15

V = pi * 16* 15

V = 240 pi

Let pi = 3.14

V =753.6 cm^3

Let pi be the pi button

V =753.9822369 cm^3

Answer:

240 pi

Step-by-step explanation:

found the answer online so now work (don't delete my answer)

I need help please help me

Answers

Answer:

4

Step-by-step explanation:

10-2(1)=8 which is >=4

10-2(2)=6 which is >=4

10-2(3)=4 which is >=4

10-2(4)=2 which isn't >=4

Therefore 4 doesn't satisfy the inequality

Answer:

4

Step-by-step explanation:

Let's test each possibility.

10-2(1)≥4

10-2=8 so it works

10-2(2)≥4

10-4=6 so it works

10-2(3)≥4

10-6=4 so it works

10-2(4)≥4

10-8=2

2<4 so it dosen't fit the solution

Solve the equation A = bh for b.

b = Ah

b = A/h

b = h/A

b = h – A

Answers

Answer:

A/h = b

Step-by-step explanation:

A = bh

Divide each side by h

A/h = bh/h

A/h = b

Answer:

[tex]b=\frac{A}{h}[/tex]

Step-by-step explanation:

→To get "b," by itself, all you need to do is divide both sides by "h," like so:

[tex]A=bh[/tex]

[tex]\frac{A}{h} =\frac{bh}{h}[/tex]

[tex]\frac{A}{h} = b[/tex]

What’s the correct answer for this?

Answers

Answer:

D.

Step-by-step explanation:

If we rotate the 3-D figure around y-axis, we'll obtain a cylinder with a radius of 1 unit.

If you are offered one slice from a round pizza (in other words, a sector of a circle) and the slice must have a perimeter of 32 inches, what diameter pizza will reward you with the largest slice

Answers

Answer:

A 16 inches diameter will reward you with the largest slice of pizza.

Step-by-step explanation:

Let r be the radius and [tex]\theta[/tex] be the angle of a circle.

According with the graph, the area of the sector is given by

[tex]A=\frac{1}{2}r^2\theta[/tex]

The arc length of a circle with radius r  and angle  [tex]\theta[/tex] is r [tex]\theta[/tex]

The perimeter of the pizza slice is composed of two straight pieces, each of length r inches, and an arc of the circle which you know has length s = rθ inches. Thus the perimeter has length

The perimeter of the pizza slice is composed of two straight pieces, each of length r inches, and an arc of the circle which you know has length s = rθ inches.

Thus the perimeter has length

[tex]2r+r\theta=32 \:in[/tex]

We need to express the area as a function of one variable, to do this we use the above equation and we solve for [tex]\theta[/tex]

[tex]2r+r\theta=32\\\\r\theta=32-2r\\\\\theta=\frac{32-2r}{r}[/tex]

Next, we substitute this equation into the area equation

[tex]A=\frac{1}{2}r^2(\frac{32-2r}{r})\\\\A=\frac{1}{2}r(32-2r)\\\\A=16r-r^2[/tex]

The domain of the area is

[tex]0<r<12[/tex]

To find the diameter of pizza that will reward you with the largest slice you need to find the derivative of the area and set it equal to zero to find the critical points.

[tex]\frac{d}{dr} A=\frac{d}{dr}(16r-r^2)\\\\A'(r)=\frac{d}{dr}(16r)-\frac{d}{dr}(r^2)\\\\A'(r)=16-2r16-2r=0\\\\-2r=-16\\\\\frac{-2r}{-2}=\frac{-16}{-2}\\\\r=8[/tex]

To check if r=8 is a maximum we use the Second Derivative test

if [tex]f'(c)=0[/tex] and [tex]f''(c)<0[/tex] , then f(x) has a local maximum at x = c.

The second derivative is

[tex]\frac{d}{dr} A'(r)=\frac{d}{dr} (16-2r)\\\\A''(r)=-2[/tex]

Because [tex]A''(r)=-2 <0[/tex]  the largest slice is when r = 8 in.

The diameter of the pizza is given by

[tex]D=2r=2\cdot 8=16 \:in[/tex]

A 16 inches diameter will reward you with the largest slice of pizza.

While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between 2.00 m and 7.00 m. What is the probability that a randomly selected depth is between 2.25 m and 5.00 m?

Answers

Answer:

55% probability that a randomly selected depth is between 2.25 m and 5.00 m

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X between c and d is given by the following formula.

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between 2.00 m and 7.00 m.

This means that [tex]a = 2, b = 7[/tex]

What is the probability that a randomly selected depth is between 2.25 m and 5.00 m?

[tex]P(2.25 \leq X \leq 5) = \frac{5 - 2.25}{7 - 2} = 0.55[/tex]

55% probability that a randomly selected depth is between 2.25 m and 5.00 m

A triangle has two sides of length 10 and 19. What is the smallest possible whole-number length for the third side?

Answers

Answer:

answer for the question is 130 length

There are 10 balls in a bag, 4 red balls and 6 black balls. If you pick one red ball, you will take it without replacement. If you pick one black ball, you will return it into the bag. Now you pick two times and each time you can only take one ball. What is the probability that you will pick two red balls

Answers

Answer:

The probability of selecting two red balls is 0.132.

Step-by-step explanation:

In a bag there are 10 balls in a bag, 4 red balls and 6 black balls.

The conditions of selecting a ball are:

If you pick one red ball, you will take it without replacement. If you pick one black ball, you will return it into the bag.

It is also provided that only one ball can be picked at a time.

Now, it is given that two balls are picked.

The number of ways to select a red ball in the first draw is: [tex]{4\choose 1}=4\ \text{ways}[/tex]

Compute the probability of selecting a red ball in the first draw as follows:

[tex]P(\text{First ball is Red})=\frac{{4\choose 1}}{{10\choose 1}}=\frac{4}{10}=0.40[/tex]

Now as a red ball is selected it will not be replaced.

So, there are 9 balls in the bag now.

The number of ways to select a red ball in the second draw is: [tex]{3\choose 1}=3\ \text{ways}[/tex]

Compute the probability of selecting a red ball in the second draw as follows:

[tex]P(\text{Second ball is Red})=\frac{{3\choose 1}}{{9\choose 1}}=\frac{3}{9}=0.33[/tex]

Compute the probability of selecting two red balls as follows:

[tex]P(\text{Two Red balls})=P(\text{First ball is Red})\times P(\text{Second ball is Red})[/tex]

                            [tex]=0.40\times 0.33\\\\=0.132[/tex]

Thus, the probability of selecting two red balls is 0.132.

how to find a local minimum of a function?

Answers

Answer:

  Find the places where the derivative is zero and the second derivative is positive.

Step-by-step explanation:

By definition, a function has a minimum where the first derivative is zero and the second derivative is positive.

That will be a "local" minimum if there are other points on the function graph that have values less than that. It will be a "global" minimum if there are no other function values less than that. A global minimum is also a local minimum.

__

On a graph, a local minimum is the bottom of the "U" where the graph changes from negative slope to positive slope.

p(x) is a polynomial with integer coefficients and p(-3) = 0. Which statements must be true? Choose all that apply. x - 3 is a factor of the polynomial. -3 is the constant term of the polynomial. p( x) can have at most 3 linear factors. x + 3 is a factor of the polynomial.

Answers

Answer:

yes all that apply to this q9

which quadrilateral will always have four reflection symmetry

Answers

Step-by-step explanation:

a rectangle has reflectional symmetry when reflected over the line through the midpoints of its opposite sides

Answer: A square always has a four reflection symmetry no matter the size.

Ari thinks the perfect milkshake has
3
33 ounces of caramel for every
5
55 scoops of ice cream. Freeze Zone makes batches of milkshakes with
6
66 ounces of caramel and
8
88 scoops of ice cream.
What will Ari think about Freeze Zone's milkshakes?

Answers

Answer:

  too much caramel

Step-by-step explanation:

3 ounces : 5 scoops = 3·2 ounces : 5·2 scoops = 6 ounces : 10 scoops

If the Freeze Zone shakes have 6 ounces : 8 scoops, then Ari will think they need more ice cream (2 scoops per shake) or less caramel.

As is, the ratio of caramel to ice cream is too high.

A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Select one answer for question A, and select one answer for question B. B: (x+3)(x−3) B: (x+3i)(x−3i) B: (x−3i)(x−3i) B: (x+3)(x+3) A: x=3 or x=−3 A: x=3i or x=−3i A: x=3 A: x=−3i

Answers

Answer:

A. The solutions are [tex]x=3i,\:x=-3i[/tex].

B. The factored form of the quadratic expression [tex]x^2+9=(x-3i)(x+3i)[/tex]

Step-by-step explanation:

A. To find the solutions to the quadratic equation [tex]x^2+9=0[/tex] you must:

[tex]\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}[/tex]

[tex]x=\sqrt{-9} = \sqrt{-1}\sqrt{9}=\sqrt{9}i=3i\\\\x=-\sqrt{-9}=-\sqrt{-1}\sqrt{9}=-\sqrt{9}i=-3i[/tex]

The solutions are:

[tex]x=3i,\:x=-3i[/tex]

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

To factor [tex]x^2+9[/tex]:

First, multiply the constant in the polynomial by [tex]i^2[/tex] where [tex]i^2[/tex] is equal to -1.

[tex]x^2+9i^2[/tex]

Since both terms are perfect squares, factor using the difference of squares formula

[tex]a^2-i^2=(a+i)(a-i)[/tex]

[tex]x^2+9=x^2+9i^2=\left(-3i+x\right)\left(3i+x\right)[/tex]

I need help again‍♀️,

Answers

Answer:

The second choice.

Step-by-step explanation:

Answer:

2nd graph down

Step-by-step explanation:

3a+11 > 5

Subtract 11 from each side

3a+11-11 > 5-11

3a > -6

Divide each side by 3

3a/3 > -6/3

a >-2

Open circle at 02

line going to the right

Using propositional logic to prove that each argument is valid.If Jose took the jewelry or Mrs. Krasov lied, then a crime was committed. Mr. Kraso was not in town. If a crime was committed, then Mr. Krasov was in town. Therefore Jose did not take the jewerly. Use letters J, L, C, T.So for this question, I am very confused and would appreciate any help offerd.

Answers

Answer:

Step-by-step explanation:

We will first translate the situation to propositional logic. First, some notation is needed: [tex]\lor[/tex] is the or logical operation and [tex]\implies[/tex] is the symbol for logical implication. Define the following events:

J: Jose took the jewelry. L: Mrs Krasov lied, C: a crime was committed. T: Mr Krasov  was in town.

We will symbol the propositions in logical symbols. Recall that [tex]\neg[/tex] means negation

If Jose took the jewelry or Mrs. Krasov lied, then a crime was committed: [tex]J\lor L \implies C[/tex]

Mr. Krasov was not in town: [tex]\neg T[/tex]

If a crime was committed, then Mr. Krasov was in town: [tex]C\implies T[/tex]

We want to check if the conclusion Jose did not take the jewerly: [tex]\neg J[/tex] can be deduced from the premises.

First, recall the following:

- if [tex] a\implies b[/tex] and a is true, then b is true.

- [tex] a\implies b[/tex] is logically equivalent to [tex]\neg b \implies a[/tex]

Coming back to the problem, we have the following premises

[tex]J\lor L \implies C, \neg T, \neg T \implies \neg C, \neg C \implies \neg(J\lor L)[/tex]

where the equivalence for the logical implication was applied. REcall that the negation of an or  statement is g iven by

[tex] \neg( a \lor b ) = \neg a \land \neg b [/tex] where [tex] \land[/tex] is the and logical operator.

USing this, we get the premises

[tex]J\lor L \implies C, \neg T, \neg T \implies \neg C, \neg C \implies \neg J\land \neg L[/tex]

Since [tex]\neg T[/tex], by having [tex]\neg T \implies \neg C[/tex], then it must be true that [tex]\neg C[/tex]. Since [tex]\neg C \implies \neg J\land \neg L[/tex], then it must be true that [tex] \neg J\land \neg L[/tex]. This final conclusion implies that it is true that [tex]\neg J[/tex] which is the statement that Jose did not take the jewelry.

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:,))) what is the volume of the pyramid? Someone please help me 10.1 Populations and Samples1. A company uses a computer to identify their 600 most loyal customersfrom its database and then surveys those customers to find out how10.2 Making Inferences from a Random Sample2. A university has 30,330 students. In a random sample of 270 students,18 speak three or more languages. Predict the number of studentsat the university who speak three or more languages.10.3 Generating Random SamplesA store receives a shipment of 5,000 MP3 players. In a previous shipmentnumbers 1 through 300 represent defective MP3 players, and the numbersnumbers to simulate a random sample of this shipment. The clerk lets the301 through 5,000 represent working MP3 players. The results are given.13 2,195 3,873 525 900 167 1,094 1,472 7095,000they like their service. Identify the population and determine whetherof 5,000 MP3 players, 300 were defective. A store clerk generates random3. Based on the sample, how many of the MP3 players might the clerk4. Can the manufacturer assume the prediction is valid? Explain.5. How can you use random samples to solve real-world problems?the sample is random or biased,predict would be defective?ESSENTIAL QUESTION 100 POINTS If (pq)/2 =3 and rprq=12, then r= (A) 1 (B) 1 (C) 2 (D) 4 (E) It cannot be determined from the information given Which of the following is pictured in the dotted line below?A. IDB. SuperegoC. Ego Which describes the typical procedure during a dental cleaning A rectangle with an area of 25 square centimetres is rotated and reflected in the coordinate plane. What will be the area of the resulting image? Explain. Describe the imagery of the engraving, and note any specific details you find important. Insurance Underwriters have established that the probability of city experiencing disasters in the next five years is 0.3 for a Tornado, 0.4 for Hurricane, and 0.1 for both Tornado and Hurricane. A) What is the probability of city experiencing only a Tornado in the next five years?B) What is the probability of city experiencing neither a Tornado nor Hurricane in the next five years? if f(x)=6x^2-4 and g(x)=2x+2 find (f-g)(x) Please answer this correctly The bookkeeper for Riverbed Company has prepared the following balance sheet as of July 31, 2017.RIVERBED COMPANYBALANCE SHEETAS OF JULY 31, 2017Cash $ 72,350 Notes and accounts payable $ 47,350Accounts receivable (net) 43,850 Long-term liabilities 78,350Inventory 63,350 Stockholders equity 158,850Equipment (net) 84,000 $284,550Patents 21,000 $ 284,550 The following additional information is provided.1. Cash includes $1,200 in a petty cash fund and $12,050 in a bond sinking fund.2. The net accounts receivable balance is comprised of the following two items: (a) accounts receivable $47,350 and (b) allowance for doubtful accounts $3,500.3. Inventory costing $5,110 was shipped out on consignment on July 31, 2017. The ending inventory balance does not include the consigned goods. Receivables in the amount of $5,110 were recognized on these consigned goods.4. Equipment had a cost of $115,350 and an accumulated depreciation balance of $31,350.5. Income taxes payable of $6,000 were accrued on July 31. Riverbed Company, however, had set up a cash fund to meet this obligation. This cash fund was not included in the cash balance, but was offset against the income taxes payable amount.Prepare a corrected classified balance sheet as of July 31, 2017, from the available information, adjusting the account balances using the additional information. How would you prove that the triangle below is equilateral?A. Shows all angles to be congruent B. Show all sides to be congruent C. Show at least two sides to be congruent D. Show two sides are of equal measure Please help me with this I need help what is the slope of the line shown below (4,8) (2,2) Which actions were taken by many African nations following World War II? refused to join international organizations rejected ideas of modernization created a strong, united Africa demanded independence from colonial rulers *I WILL MARK YOU BRAINLIEST!!!!!* Assume the three blocks (m. = 1.0 kg, m = 20 kg and m = 40 ko) portrayed in the figure below move on a frictionless surface and a force F: 36w acts as shown on the 4.0 kg block. a) Determine the acceleration given this system (in m/s2 to the right). m/s2 (to the right) b) Determine the tension in the cord connecting the 4.0 kg and the 1.0 kg blocks in N). Determine the force exerted by the 1.0 kg block on the 2.0 kg block (in N). N (a) What If How would your answers to parts (a) and (b) of this problem change if the 2.0 kg block was now stacked on top of the 1.0 kg block? Assume that the 2.0 kg block sticks to and does not slide on the 1.0 kg block when the system is accelerated. (Enter the acceleration in m/s2 to the right and the tension in N.) acceleration m/s (to the right) tension Whats the best way to figure out what wires what and goes where? Tiptop Flight School offers flying lessons at a small municipal airport. The school's owner and the manager have been attempting to evaluate performance and control costs using a variance report that compares the planning budget to actual results. A recent variance report appears below: Tiptop Flight School Variance Report For the Month Ended July 31 Actual Results Planning Budget Variances Lessons 155 150 Revenue $33,900 $33,000 $900 F Expenses: Instructor wages 9,870 9,750 120 U Aircraft depreciation 5,890 5,700 190 U Fuel 2,750 2,250 500 U Maintenance 2,450 2,330 120 U Ground facility expenses 1,540 1,550 (10) F Administration 3,320 3,390 (70) F Total expense 25,820 24,970 850 U Net operating income $8,080 $8,030 $50 F After several months of using such variance reports, the owner has become frustrated. For example. she is quite confident that instructor wages were very tightly controlled in July. but the report shows an unfavorable variance. The planning budget was developed using the following formulas, where q is the number of lessons sold: Cost Formulas Revenue $220 q Instructor wages $65 q Aircraft depreciation $38 q Fuel $15 q Maintenance $530 + $12 q Ground facility expenses $1,250 + $2 q Administration $3,240 + $1 q Required: 1. Should the owner feel frustrated with the variance reports? Explain. 2. Prepare a flexible budget performance report for the school for July. 3. Evaluate the school's performance for July. Little Equipment for Hire is a subsidiary in the Giant Machinery and currently under the liquidation plan due to the severe contraction of operation due to corona virus. The company plans to pay total dividend of $2.5 million now and $ 7.5 million one year from now as a liquidating dividend. The required rate of return for shareholders is 12%. Calculate the current value of the firms equity in total and per share if the firm has 1.5 million shares outstanding. (4 marks)