A constant force acting on a body of mass 2 kg changes its
velocity from 1 m/s to 2 m/s in 20 s. If the direction of motion of
the body remains unchanged, the magnitude of the force that acted
on the body was 0.1 N.
True or False

Answers

Answer 1

Answer:

the correct answer is b

Answer 2

Answer:

true

Explanation:

just did it on ck12 lol


Related Questions

The ___________________ ______________ (two words) is the least dense layer of the Earth.

Answers

Answer:

lithosphere

Explanation:

the least densest layer is the outer most layer

the densest layer is the inner most layer and the inner most layer is the inner core

Answer:

lithosphere

Explanation:

i took the test and i got it right

A 2,100kg car drives toward a 55kg cart that has a velocity of 0.50m/s west. The two objects collide giving the car a final velocity of 6.31m/s east and the shopping cart a velocity of 13.5m/s east what the initial velocity of the car?

A. 6.68m/s east
B. 7.19m/s west
C. 6.68m/s west
D. 7.19m/s east

Answers

Answer: A. 6.68m/s east

Explanation: just did it on ap3x

a baby carriage is sitting on the top of a hill that is 21 m high. the carriage with a baby 75kg. the carriage has what energy? calculate it

Answers

Answer:

It has potential energy

PE = 15450.75 J

Explanation:

we know its potential energy because the carriage is not moving, although it can

PE = mgh

in this case, m is 75, h is 21, and g is always 9.81

plug these in: PE = (75) (21) (9.81)

your answer: PE = 15450.75 J

A car of mass 1167 kg accelerates on a flat highway from 10 m/s to 28.0 m/s. How much work does the car's engine do on the car?

Answers

Answer:

Workdone = 465766038 Joules.

Explanation:

Given the following data;

Mass = 1167

Initial velocity = 10m/s

Final velocity =28m/s

To find the workdone;

We know that from the workdone theorem, the workdone by an object or a body is directly proportional to the kinetic energy possessed by the object due to its motion.

Mathematically, it is given by the equation;

W = Kf - Ki

W = ½MVf² - ½MVi²

Substituting into the equation

W = ½(1167)*28² - ½(1167)*10²

W = ½ * 1361889* 784 - ½ * 1361889 * 100

W = 533860488 - 68094450

Workdone = 465766038 Joules.

Someone help me plz. I have no idea. ​

Answers

Answer:

fault im pretty sure

Explanation:

Answer:

fault............

...........

An object is projected straight upward with an initial speed of 25.0 m/s. What's the maximum height obtained by the object ?

Answers

Answer:

The maximum height obtained by the object is approximately 31.855 m

Explanation:

The vertical velocity of the object = 25.0 m/s

The height reached by the object, is given by the following formula;

v² = u²  -  2 × g × h

Where;

u = The initial velocity of the object = 25.0 m/s

v = The final speed of the object = 0 m/s at maximum height

h = The maximum height obtained by the object

g = The acceleration due to gravity = 9.81 m/s²

Substituting the values, gives;

0² = (25.0 m/s)²  -  2 × 9.81 m/s² × h

2 × 9.81 m/s² × h = (25.0 m/s)²

h = (25.0 m/s)²/(2 × 9.81 m/s²) ≈ 31.855 m

The maximum height obtained by the object, h ≈ 31.855 m.

1. Calculate the pressure of an object with an area of 10m2 force of 5N exerted
on it​

Answers

Answer:

2

Explanation:

pressure(p)=force(f)\area(a)

In a container there are 2 liters of liquid, of which 75% is alcohol and the remaining 25% is water.
Determine how many cm3 of alcohol must be added to bring the alcohol percentage to 80%.

Answers

Answer:

There must be added 500 cm3 of alcohol to bring the concentration to 80%.

Explanation:

Concentration

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solution.

In the container, there are 2 liters (2000 cubic centimeters) of a solution, 75% of which is alcohol (solute) and 25% of water (solvent).

The original amount of alcohol is:

H = 2000*75% = 1500 cc

The original amount of water is:

W = 2000*25% = 500 cc

When we add x cc of pure alcohol, there are 1500+x cc of alcohol out of 2000+x cc of solution.

The new concentration is calculated as:

[tex]\displaystyle \frac{1500+x}{2000+x}[/tex]

And it's known this concentration is 80% (0.8), thus:

[tex]\displaystyle \frac{1500+x}{2000+x}=0.8[/tex]

Multiplying by 2000+x:

[tex]1500+x = 0.8(2000+x)[/tex]

Operating:

[tex]1500+x = 1600+0.8x[/tex]

Rearranging:

[tex]x-0.8x=1600-1500[/tex]

[tex]0.2x=100[/tex]

[tex]x=100/0.2[/tex]

x= 500

There must be added 500 cm3 of alcohol to bring the concentration to 80%

How do I graph distance ,speed ,velocity, and acceleration?

Answers

Answer:

distance is how much space is between, speed is how fast they are going, velocity is money and acceleration is going

Explanation:

The force of a plane's engine is moving the plane toward the right with 800N. Coming from the left you have
resistance forces of air with 60N and friction with 40N. What is the direction and net forces that is being applied
the plane?

Answers

Answer:es la F

Explanation:

A 200 N net force acts on a 50 kg box. What is the acceleration of the box?

Answers

Answer:

a= 4m/s^2

Explanation:

Fnet =200N

m=50kg

a=?

Fnet = ma

200=50a then divide both sides by 50 to get acceleration

Taking into account the Newton's second law, the acceleration of the box is 4 [tex]\frac{m}{s^{2} }[/tex].

In first place, you have to know that Newton's second law, called the fundamental law or fundamental principle of dynamics, states that a body accelerates if a force is applied to it.

Then, the amount of force necessary is proportional to the acceleration that the body acquires, and the constant of proportionality  is the mass of the body.

Mathematically, Newton's second law is:

F= m×a

where:

F = Force [N] m = Mass [kg] a = Acceleration [m/s²]

In this case, you know:

F= 200 N m= 50 kg a= ?

Replacing in the Newton's second law:

200 N= 50 kg×a

Solving:

a=200 N÷ 50 kg

a= 4 [tex]\frac{m}{s^{2} }[/tex]

In summary, the acceleration of the box is 4 [tex]\frac{m}{s^{2} }[/tex].

Learn more about the Newton's second law:

brainly.com/question/23845187?referrer=searchResults brainly.com/question/13959891?referrer=searchResults

The distance recorded for riding a motorcycle on its rear wheel without stopping is more than 320 km! Suppose the rider in this impressive position is traveling with an initial velocity of 8.0 m/s before accelerating. Then the rider travels 40.0 m at a constant acceleration of 2.00 m/s2. What is the rider's velocity after the acceleration?

Answers

Answer:

14.97m/s

Explanation:

Given

Initial velocity of the car u = 8m/s

Distance travelled by the rider S = 40m

Acceleration a = 2m/s²

Required

rider's velocity after the acceleration v

Using the equation of motion

v² = u²+2as

v² = 8²+2(2)(40)

v² = 64+160

v² = 224

v = √224

v = 14.97m/s

Hence the rider's velocity after the acceleration is 14.97m/s

if you had to be an animal, which would you be and why?​

Answers

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ:.:


If a car manufacturer reduced the mass of a new car model, so that it took a force of 4000 N
to accelerate towards the barrier at 4 m/s2, what would be the mass of
the new car?

Answers

Answer:

1000 kg

Explanation:

Force = mass x acceleration, Hence, mass = Force/acceleration

mass = 4000/4 = 1000 kg

5. Explain how forming an ionic bond makes metal and nonmetal atoms more stable.
6. Describe how metallic bonds contribute to the physical characteristics of a metal.
7. Describe the type of ions created through metallic bonding.
8. List the three types of atomic bonds and describe the types of atoms-metal
or nonmetal-that form each type of bond.

Answers

do you have the paper or doc ?

When you open the front door to your warm house on a cold day, which way does the heat flow? For example, which is correct to say: "Close the door, you're letting the cold in!" or "Shut the door, you're letting the heat in!".

Answers

“Close the door, you’re letting the cold in!”

Answer:

close the door your letting the cold in

What happens to potential energy as the car goes up the hill?

Answers

The potential energy will increase
As a car goes up a hill, gravitational potential energy increases and kinetic energy decreases. I hope this helps!

The table shows the specific heat capacities of various substances. How much energy is required to raise the temperature of 5g of air by 10°C? Use the table below to help you.

Answers

Answer:

50.25 j

Explanation:

Alex HEYYYYYYYYY

Answer:

The table shows the specific heat capacities of various substances. How much energy is required to raise the temperature of 5g of air by 10°C? Use the table below to help you.

"10 J" is WRONG

The right answer is "50.25 J"

Explanation:

hope this helps

A box sitting still on the ground by itself has a Normal Force of 700N, what is the mass? (gravity’s acceleration is 9.80 m/s²)

Answers

The answer is 71.42 because you would need to use the formula m=w/g

"Johnson is throwing rocks at a bug. The bug in response first flies up 117 Cm, then down 32 cm. After dodging another rocks, the bug again flies up 15 cm. This all takes place of 7 seconds"

What is the Average Velocity of the bug in m/s?
What is the Average Speed of the bug in m/s?

(I know this is very dry, but I could really use some help)
Don't solve the problem, just give the equation/method of solving

Answers

IM SORRY THIS IS JUST FUNNY TO ME AHDAHJASHJHADJAS THE BUG FLEW HIGH GOD DAYUM

The planet Jupiter is about 300 times as massive as Earth, but an object on its surface would weigh only 2.5 times as much as it would on earth. Can you come up with an explanation?

Answers

Answer:

here you go

Explanation:

so it might seem that a body on the surface of Jupiter would weigh 300 times as much as on Earth. ... But the radius of Jupiter is about 10 times that of Earth, weakening gravity by a factor of 100, resulting in 3 times its Earth weight.

An object O is acted upon by a 6 N force and a 5 N force. The angle between these two forces is 60°. Draw a scale diagram showing the forces acting on object O and determine the resultant force.​

Answers

Answer:

Resultant force = [tex]\sqrt{91}[/tex]N

Explanation:

Rf = [tex]\sqrt{f1²+f2²+2.f1.f2.cos60}[/tex]

Rf = [tex]\sqrt{6²+5²+2.6.5.1/2}[/tex]

Rf = [tex]\sqrt{36+25+30}[/tex]

Rf = [tex]\sqrt{91}[/tex]

doesn't look right though...

The magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.

What is force?

An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.

The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.

Given parameters:

Two forces are 6 N and 5N.

Angle between them is 60 degree.

So, magnitude of resultant force be = √(6² + 5² + 2× 6 × 5 × cos60°) N =  = 9.54 N.

Angle of the resultant force with respect to 5 N is = tan⁻¹{6sin60°/(5 +6 cos60°)  } = 33⁰.

Hence, magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.

To find more about force, refer the link:

https://brainly.com/question/13191643

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Which situation is most likely to lead to improving a scientific theory?

A. Repeating an experiment to verify results
B. Development of new technologies
C. Increased funding for research
D. Relaxing government restrictions

Answers

Answer:

A. Repeating an experiment to verify results

Explanation:

A scientific theory may be defined as the theory of science that is a thought out explanation of the observations done in the nature or that happens in the natural world. They are constructed using several scientific methods by observing many facts and hypothesis.

According to the question, repeating of an experiment a number of times and verifying its result may help in improving a scientific theory as if we get the similar result for each experiments, then it confirms the basis of the hypothesis or the facts that are observe in the nature and conclude a scientific theory.

Answer:

b

Explanation:

An object with a mass of 43 kg measured on Earth is taken to the Moon. What is the mass of the object on the Moon's surface if the acceleration due to gravity on the Moon is one-sixth of that on Earth? O a. 16 kg O b. 43 kg O c. 7.9 kg O d. 26 kg​

Answers

Answer:

b 43 kg

Explanation:

mass doesn't differ from place to place.

but the weight may

What are the main differences between asexual reproduction and sexual reproduction?
Asexual reproduction requires two parents and produces non-identical offspring, while sexual reproduction requires only one parent and produces identical offspring.
Asexual reproduction requires two parents and produces identical offspring, while sexual reproduction requires only one parent and produces non-identical offspring.
Asexual reproduction requires only one parent and produces identical offspring, while sexual reproduction requires two parents and produces non-identical offspring.
Asexual reproduction requires only one parent and produces non-identical offspring, while sexual reproduction requires two parents and produces identical offspring.

Answers

Answer:

option c

Asexual reproduction requires only one parent and produces identical offspring, while sexual reproduction requires two parents and produces non-identical offspring.

Answer:

C

Explanation:

In which scenario will the two objects have the least gravitational force between them?​

Answers

Answer:

A

Explanation:

In  scenario A the two objects have the least gravitational force between them.

What is  gravitational force?

Gravitational force is defined as the force which one mass exert on the other mass separated by finite distance. Mathematically gravitational force is directly proportional to product of mass and inversely proportional to square of distance between them.

Force between two mass,

F = Gmm/r²

Given question, to find when have the least gravitational force between two masses so from option A we see there separation distance is maximum 1.5 m and mass product is less than option B.

So least gravitational force when masses are 12 kg and separation distance is 1.5 meter.

To learn more about gravitational force refer to the link:

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Erik Erikson's theory of psychosocial development emphasizes that development occurs by overcoming an emotional
crisis in each of the eight stages of one's lifetime.
Please select the best answer from the choices provided
true or false??????

Answers

Answer:

trueeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Explanation:

The theory is true that psychosocial development emphasizes that development occurs by overcoming an emotional crisis.

What is psychosocial development?

The term "psychosocial development" refers to how a human's personality changes during childhood and adulthood, as well as how social skills are acquired. The eight phases of psychosocial development were first described by psychologist Erik Erikson in the 1950s. According to Erikson, each stage is marked by a "psychosocial crisis" that can either have a good or negative impact on a person's personality.

Erikson asserts that a person's personality and social abilities change over the course of eight stages that span the entirety of their life. A person encounters a psychosocial crisis—critical issues—at each level, which must be overcome.

The way a person handles each of these crises has an impact on their personality. If people respond favorably, they acquire virtue (moral behavior).

To know more about psychosocial development:

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in a free body diagram the weight is

Answers

Answer:

Explanation:

a. WEIGHT: As we have seen, weight is the gravitational force exerted on an object by the Earth (or any other celestial body). If an object is near the Earth's surface and has mass, then the object has a weight. The magnitude of its weight is w = mg and its direction is toward the center of the Earth.

A car drives 0.696 km North, and then turns and drives 4.326 km East. Calculate the magnitude of the car's resultant displacement. Include equation, substitution with units, and answer with units.

Answers

Answer:

4.3186km

Explanation:

If a car drives 0.696 km North, and then turns and drives 4.326 km East, the magnitude of the car's resultant displacement will be gotten using the Pythagoras theorem as shown;

d² = x²+y²

Given;

x = 4.326km

y = 0.696km

Substitute into the formula and get d;

d² = (4.326)²+(0.696)²

d² = 18.714276+0.484416

d² =19.198692

d = √19.198692

d = 4.3816km

Hence the magnitude of the car's resultant displacement is 4.3186km

Three vectors , , and , each have a magnitude of 52.0 m and lie in an xy plane. Their directions relative to the positive direction of the x axis are 29.0 ˚, 191 ˚, and 311 ˚, respectively. What are (a) the magnitude and (b) the angle of the vector (relative to the +x direction in the range of (-180°, 180°)), and (c) the magnitude and (d) the angle of in the range of (-180°, 180°)? What are (e) the magnitude and (f) the angle (in the range of (-180°, 180°)) of a fourth vector such that ?

Answers

Answer:

a)   A´= A  

b)   θ₁´ = 29º,  θ₂´ = - 169º ,  θ₃´ = -49º

Explanation:

In this exercise you are asked to give the magnitudes and angles of the vectors from another system of

reference

a) The magnitudes

The magnitude of a vector, the size of which is a scalar, this does not depend on the reference system, since it is obtained by subtracting the coordinates of the end point minus the coordinate of the origin of the vector

          A = [tex]x_{f}[/tex]- x₀

if the vectors are measured in another reference frame

         x_{f}´ = xx_{f}- U

         x₀´ = x₀ -U

where U is the distance between the two reference frames

         A´ = x_{f}´ - x₀´

we substitute

         A´ = (x_{f} - U) - (x₀-U) = x_{f} - x₀

         A´ = A

 it does not change

b) Angles

The given angles are measured from the positive part of the x axis in a counterclockwise direction, it is asked to give these angles from the x axis

     θ₁ = 29º

     does not change

     θ₁´ = 29º

    θ₂ = 191º

   we measure clockwise

     θ₂´ = θ₂ - 360

     θ₂´ = 191 - 360

     θ₂´ = - 169º

     θ₃ =311º

    we measure clockwise

     θ₃´ = 311 -360

     θ₃´ = -49º

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