Answer:
Step-by-step explanation:
The formula for determining the confidence interval for the difference of two population means is expressed as
Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)
Where
x1 = sample mean salary of city 1 librarians
x2 = sample mean salary of city 2 librarians
s1 = sample standard deviation for city 1
s2 = sample standard deviation for city 2
n1 = number of soles for city 1
n1 = number of soles for city 2
For a 95% confidence interval, we would determine the z score from the t distribution table because the number of samples are small
Degree of freedom =
(n1 - 1) + (n2 - 1) = (15 - 1) + (15 - 1) = 28
z = 2.048
x1 - x2 = 28,900 - 30,300 = - 1400
Margin of error = 2.048√(s1²/n1 + s2²/n2) = 2.036√(2300²/15 + 2100²/15)
= 1647
The upper boundary for the confidence interval is
- 1400 + 1647 = 247
The lower boundary for the confidence interval is
- 1400 - 1647 = - 3047
An inverted conical tank starts the day with 250 ft^3 of crayon wax in it. As the factory commences work, the tank is filled with an additional 40 ft^3 of wax per minute. The height of the wax is modeled by H(V)=3 piV/25. A. Write a function , V(t) to model the volume of wax in the tank after t minutes. B. Find an expression for the composition (HoV)(t) C. The composition in B (above) can be described as the ________ of the wax in terms of _______
Answer:
A. V(t) = 40t + 250 B. (HoV)(t) = 24πt/5 + 30π C. The composition in B (above) can be described as the height of the wax in terms of time.
Step-by-step explanation:
A. Let the rate of change of volume V with respect to time be dV/dt = 40 ft³/min
Solving this, V = 40t + C. At the start of the day, that is t = 0, V = 250 ft³
Substituting these values, we have
250 ft³ = 40(0) + C
C = 250 ft³
So, V(t) = 40t + 250
B. Since H(V) = 3πV/25
(HoV)(t) = 3π(40t + 250)/25
= 24πt/5 + 30π
C. The composition in B (above) can be described as the height of the wax in terms of time.
Round 8326 to the nearest hundred
Answer:
The answer is 8300.
Step-by-step explanation:
1) We round the number up to the nearest hundred, if the last two digits in the number are 50 or above.
2) We round the number down to the nearest 100 if the last two digits in the number are 49 or below.
3) If the last two digits are 00, then we do not have to do any rounding because it is already to the hundred.
a cone has the diameter of 3 inches. the cone holds 12 cubic inches of water. to the nearest inch, what is the height of the cone?
Answer:
The height is about 5 inches.
Step-by-step explanation:
The volume for a cone is [tex]\frac{1}{3}[/tex] × π × r² × h
The radius of the cone is 1.5
12= [tex]\frac{1}{3}[/tex] × π × 1.5² × h
12= [tex]\frac{1}{3}[/tex] × π × 2.25 × h
12=0.75×π×h
Divide both sides by 0.75
16=π×h
Divide both sides by π
5≈h
The height is about 5 inches.
Please help. I’ll mark you as brainliest if correct!
answer is g(x)=|x+2|-1
[tex]answer \\ g(x) = - |x + 2| - 1\\ as \: we \: can \: see \: from \: the \: given \: graph \\ above \: that \: the \: graph \: of \: absolute \\ function \: has \: been \: reflected \: over \: the \\ x \: axis \: \: shifted \: 2 \: units \: left \: and \: 1 \: \\ units \: down. \\ due \: to \: reflection \: there \: is \: a \: negative \\ sign \: shift \: of \: 2 \: units \: left \: is \: given \\ by \: x + 2 \: and \: 1 \: units \: down \: is \: given \\ by \: - 1 \\ hope \: it \: helps[/tex]
last year we had 250 of employees and due to attrion we lost 12% we only have blank employees left ?
Answer:
220
Step-by-step explanation:
If we lost 12% we still have 100 - 12 = 88% of the employees left. 88% can be written as 0.88. 0.88 * 250 = 220 employees left.
Given that d is the midpoint of line segment ab and k is the midpoint of line segment bc, which statement must be true? (May give brainliest)
Answer:
B is the midpoint of line segment AC
I’ll give the bralyist to the first correct answer
Let f be defined as shown.
What is f1 (-7)?
Answer:
The answer is 2
From the function when the input is 2 the output is -7. The inverse reverses the order so the input will be -7 and the output will be 2.
Which of the following measurements is more precise?
4.69 m or 8.99 m
Answer:
The measures represent the same precisionWhen we talk about precision in measurements, we need to mention the significant figures, because that determines the precision.
Specifically, the more significant figures there are, more precise will be the number.
In this case, you can observe that both numbers have the same number of significant figures, which is 3, which means both numbers are equal in precision.
What is true about the number 3.872? Check all that apply.
The 8 is in the tens place.
The 7 is in the hundredths place.
The 3 is in the ones place.
This number is read as "three and eight seventy-two hundredths."
3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001).
Answer:
The 7 is in the hundredths place.
The 3 is in the ones place.
3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001).
Step-by-step explanation:
Given the number 3.872, to check all the given options that are true apply to the number, let's take a look at each position occupied by each digit. In order words, let's consider their place value.
Thus,
The 3 is in the ones place and as such has a value of 3.
8 is in the tenths place having a place value of 0.8 (⁸/10)
7 is in the hundredths place having a place value of 0.07 (⁷/100)
2 is in the thousandths place having a place value of 0.002 (²/1000)
Going by these, the following statements are true :
"The 7 is in the hundredths place."
"The 3 is in the ones place."
"3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001)."
The number is pronounced as three and eight hundred seventy-two thousandths rather than the option given.
Therefore, only 3 if the options are correct
Answer: The 7 is in the hundredths place.
The 3 is in the ones place.
3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001).
Step-by-step explanation:
In the question, 3 is in the ones place. The first number after the decimal point is the tenths. In the question, the place value of 8 is 8 tenths; 7 is in the hundredths place.
3.872 = (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001)
= 3 + 0.8 + 0.07 + 0.002
= 3.872
The number is pronounced as three and eight hundred seventy-two thousandths
A college basketball player makes 80% of his freethrows. Over the course of the season he will attempt 100 freethrows. Assuming free throw attempts are independent, the probability that the number of free throws he makes exceeds 80 is approximately:____________.
A) 0.2000
B) 0.2266
C) 0.5000
D) 0.7734
Answer:
The probability that the number of free throws he makes exceeds 80 is approximately 0.50
Step-by-step explanation:
According to the given data we have the following:
P(Make a Throw) = 0.80%
n=100
Binomial distribution:
mean: np = 0.80*100= 80
hence, standard deviation=√np(1-p)=√80*0.20=4
Therefore, to calculate the probability that the number of free throws he makes exceeds 80 we would have to make the following calculation:
P(X>80)= 1- P(X<80)
You could calculate this value via a normal distributionapproximation:
P(Z<(80-80)/4)=1-P(Z<0)=1-50=0.50
The probability that the number of free throws he makes exceeds 80 is approximately 0.50
The probability that the number of free throws he makes exceeds 80 is approximately 0.5000.
Given that,
A college basketball player makes 80% of his free throws.
Over the course of the season, he will attempt 100 free throws.
Assuming free throw attempts are independent.
We have to determine,
The probability that the number of free throws he makes exceeds 80 is.
According to the question,
P(Make a Throw) = 80% = 0.80
number of free throws n = 100
Binomial distribution:
Mean: [tex]n \times p = 0.80 \times 100 = 80[/tex]
Then, The standard deviation is determined by using the formula;
[tex]= \sqrt{np(1-p)} \\\\=\sqrt{80\times (1-0.80)}\\\\= \sqrt{80 \times 0.20 } \\\\= \sqrt{16} \\\\= 4[/tex]
Therefore,
To calculate the probability that the number of free throws he makes exceeds 80 we would have to make the following calculation:
[tex]P(X>80)= 1- P(X<80)[/tex]
To calculate this value via a normal distribution approximation:
[tex]P(Z<\dfrac{80-80}{4})=1-P(Z<0)=1-0.50=0.5000[/tex]
Hence, The probability that the number of free throws he makes exceeds 80 is approximately 0.5000.
To know more about Probability click the link given below.
https://brainly.com/question/21586810
On a coordinate plane, triangle A B C is shifted 4 units up and 3 units to the left to form triangle A prime B prime C prime. Triangle ABC is reflected over the line y = 1. What are the coordinates of B’? (–2, 3) (–2, 5) (2, –3) (4, –3)
Answer:
(–2, 5)
Step-by-step explanation:
I know its late now but here is the answer.
Answer:
The answer is a
Step-by-step explanation:
what is the radius of the circle that has an area of [tex]81*x*pi[/tex] degrees
Answer:
R=9
Step-by-step explanation:
the formula for area of a circle is pi r squared
where r denotes the radius of the circle
equating the formula for area with the area of the circle provided
p\i r squared = 81 p\i
r squared = 81
r = radical 81
r =9 inches
g Question 6 1 pts A 3x3 matrix with real entries can have (select ALL that apply) Group of answer choices three eigenvalues, all of them real. three eigenvalues, all of them complex. two real eigenvalues and one complex eigenvalue. one real eigenvalue and two complex eigenvalues. only two eigenvalues, both of them real. only two eigenvalues, both of them complex. only one eigenvalue -- a real one. only one eigenvalue -- a complex one.
Answer:
(A)three eigenvalues, all of them real.
(D)one real eigenvalue and two complex eigenvalues.
(G)only one eigenvalue -- a real one.
Step-by-step explanation:
Given an [tex]n \times n[/tex] matrix, the characteristic polynomial of the matrix is the degree n polynomial in one variable λ:
[tex]p(\lambda) = det(\lambda I- A)[/tex]
If such [tex]n \times n[/tex] matrix A has real entries, its complex eigenvalues will always occur in complex conjugate pairs.
Therefore, for a [tex]3 \times 3[/tex] matrix with real entries, the following are possible:
(A)three eigenvalues, all of them real.
(D)one real eigenvalue and two complex eigenvalues.
(G)only one eigenvalue -- a real one.
A [tex]3 \times 3[/tex] matrix with real entries cannot have the following:
(B)three eigenvalues, all of them complex.
(C)two real eigenvalues and one complex eigenvalue.
(E)only two eigenvalues, both of them real.
(F)only two eigenvalues, both of them complex.
(H)only one eigenvalue -- a complex one.
A high school track is shaped as a rectangle with a half circle on either side.Jake plans on running four laps. How many meters will Jake run? Use 3.14 for Pi.
Answer:
if you go around a track one time thats 400 meters but if you go around 4 times thats 1600 meters, you dont need to use 3.14 pi for this " no offense", i do track and field myself and i do the short distance, which is 100 meters and 200 meter but for for long distance runners they go around the track 4- 8 times so it is 1600 meters is ur answer. and when u go around 8 times, thats 3200 meters.
Step-by-step explanation:
Write an equation of a line that contains the following two points in slope intercept form
(-2,4) (3,-1)
Answer:
y = -x + 2
Step-by-step explanation:
The slope intercept form equation of this line can be written like this :
y = my + p ; where m is the slope and p is the y intercept.
[tex]m = \frac{-1-4}{3-(-2)} = \frac{-5}{5} =-1[/tex]
then the equation becomes y = -x + p
(-2,4) is a point of the line means 4 = -(-2) + p
then p = 4 - 2 = 2
finally, y = -x + 2
Does anyone know this?
PLEASE HURRY! Circle B is shown. Line segments A B and C B are radii. The length of A B is 6. Sector A B C is shaded. The measure of central angle ABC is StartFraction pi Over 2 EndFraction radians. What is the area of the shaded sector? 6Pi units squared 9Pi units squared 18Pi units squared 36Pi units squared
Answer:
(B)[tex]9 \pi $ units squared[/tex]
Step-by-step explanation:
In circle B, AB is one of the radii; and
AB=6
Central Angle of ABC [tex]=\dfrac{\pi}{2}$ radians[/tex]
Now, Area of a Sector
[tex]\text{Area of a Sector}=\dfrac{\theta}{2\pi} \times \pi r^2 \\=\dfrac{\frac{\pi}{2}}{2\pi} \times \pi \times 6^2\\=\dfrac{\pi}{4\pi} \times \pi \times 6^2\\=\dfrac{36}{4} \times \pi \\= 9 \pi $ units squared[/tex]
Answer:
b
Step-by-step explanation:
In ΔEFG, ∠E \cong≅∠G, GE = 7 and FG = 15. Find the length of EF.
Answer: EF = 15
Step-by-step explanation:
The given description is that of an isosceles triangle. The base angles are congruent, therefore the sides opposite of those angles are also congruent.
The base angles are ∠E and ∠G and the vertex angle is ∠F.
The sides opposite to the base angles are EF and FG.
Thus, EF ≡ FG.
Since FG = 15 and FG = EF, then 15 = EF.
Based on the definition of an isosceles triangle, the length of EF in the triangle is: 15 units.
What is an Isosceles Triangle?An isosceles triangle has two sides that are congruent. The angles opposite these congruent sides are also congruent.
ΔEFG is an isosceles triangle. The congruent sides are, FG and EF.
Therefore, EF = FG = 15 units.
Learn more about isosceles triangle on:
https://brainly.com/question/11884412
A standard deck of cards contains 52 cards. One card is selected from the deck. (a) Compute the probability of randomly selecting a seven or king. (b) Compute the probability of randomly selecting a seven or king or jack. (c) Compute the probability of randomly selecting a queen or spade.
Answer:
(a)[tex]\dfrac{2}{13}[/tex]
(b)[tex]\dfrac{3}{13}[/tex]
(c)[tex]\dfrac{4}{13}[/tex]
Step-by-step explanation:
In a standard deck, there are 52 cards which are divided into 4 suits.
(a)
Number of Seven Cards =4
Number of King cards =4
Probability of randomly selecting a seven or king
=P(Seven)+P(King)
[tex]=\dfrac{4}{52} +\dfrac{4}{52} \\=\dfrac{8}{52}\\=\dfrac{2}{13}[/tex]
(b)
Number of Seven Cards =4
Number of King cards =4
Number of Jack(J) cards =4
Probability of randomly selecting a seven or king
=P(Seven)+P(King)+P(Jack)
[tex]=\dfrac{4}{52} +\dfrac{4}{52}+\dfrac{4}{52} \\=\dfrac{12}{52}\\=\dfrac{3}{13}[/tex]
(c)
Number of Queen Cards =4
Number of Spade cards =13
Number of Queen and Spade cards =1
Probability of randomly selecting a seven or king
[tex]=P$(Queen)+P(Spade)-P(Queen and Spade Card)\\=\dfrac{4}{52} +\dfrac{13}{52} -\dfrac{1}{52} \\=\dfrac{16}{52} \\=\dfrac{4}{13}[/tex]
What is the gcf of 96x5 and 64x2
Answer:
The GCF is going to be 32
Answer:
32x^2
Step-by-step explanation:
B on edge
HELP!!! PLEASE!!!
The U.S. Federal Income Tax is a progressive tax, which means that higher incomes are taxed at higher percent rates.
The table shows the 2018 Federal Income Tax rates that are applied to the incomes of unmarried individuals.
Tuan is an unmarried man who earned a taxable income of $48$48,000000 during 2018.
Use the table to complete the statements below.
Answer:
10%$29,175$2,046$6,499.50Step-by-step explanation:
a) The %tax comes from the "Rate" column on the line "up to $9525". It is 10%.
__
b) Simply compute the difference shown:
$38,700 -$9,525 = $29,175
__
c) 22% of $9,300 is ...
0.22 × $9,300 = $2,046
__
d) The total from the three previous calculations is ...
$952.50 +3,501.00 +2,046.00 = $6,499.50
Answer:
10%
$29,175
$2,046
$6,499.50
got it right on ttm.
Step-by-step explanation:
just believe me it works
When Sunita weighed herself on Monday, she found that she had gained 1 1/4 kg. Earlier her weight was 46 3/8 kg. What was her weight on Monday? Please give me Statements! Please Do it fast(Its ok if you dont do it fast ok its not like that much of an urgent) #GoAwayCoronaVirus
Answer:
[tex]47\frac{5}{8}[/tex]
Step-by-step explanation:
Weight from before + Weight gained
[tex]46\frac{3}{8} +1\frac{1}{4}[/tex]
Convert to improper fractions.
[tex]371/8 + 5/4[/tex]
Find the common denominator.
[tex]371/8 + 10/8[/tex]
Add.
[tex]381/8[/tex]
Convert to a mixed fraction.
[tex]47\frac{5}{8}[/tex]
Answer:
47 5/8 kg
Step-by-step explanation:
Ealier weight + gained weight = Monday's weight
46 3/8 + 1 1/4
= 371/8 + 5/4
= 371/8 + 10/8
= 381/8
= 47 5/8 kg
What’s the degree of the rotation?
Answer: The answer is C 90
Step-by-step explanation: Rotations is ¼ and the Radians is π/2
In the western region of the state the times of all boys running in this event are normally distributed with standard deviation 12 seconds, but with mean 5 minutes 22 seconds. Find the proportion of boys from this region who qualify to run in this event in the state meet. (Hint: normalcdf)
Here is the full question.
The average finishing time among all high school boys in a particular track event in a certain state is 5 minutes 17 seconds. Times are normally distributed with standard deviation 12 seconds.
A. The qualifying time in this event for participation in the state meet is to be set so that only the fastest 5% of all runners qualify. Find the qualifying time in seconds (round it to the closest second). (Hint: Convert minutes to seconds.)
B. In the western region of the state the times of all boys running in this event are normally distributed with standard deviation 12 seconds, but with mean 5 minutes 22 seconds. Find the proportion of boys from this region who qualify to run in this event in the state meet. (Hint: normalcdf)
Answer:
a. x ≅ 337 seconds.
b. P(x > 337 ) = 0.1056
Step-by-step explanation:
A.
Given that ;
Mean [tex]\mu =[/tex] 5 minutes 17 seconds =( (60× 5)+17 ) seconds = 317 seconds ( since 60 seconds make 1 minute.
Standard deviation: [tex]\sigma[/tex] = 12 seconds.
Only the fastest 5% of all runners qualify
The objective is to determine the qualifying time in seconds
Let's look for the Z-score of 0.95;
The Z-score is 1.645 from the tables
[tex]x= ( \sigma * z ) + \mu[/tex]
[tex]x = ( 12 * 1.645 ) + 317 \\ \\x = 336.74[/tex]
x ≅ 337 seconds.
B. Given that the standard deviation = 12 seconds
Mean = 5 minutes 22 seconds = (5 × 60 + 22 )seconds = 322 seconds
he objective is to find P(x > 337 ) i.e the proportion of boys from this region who qualify to run in this event in the state meet.
we are using command normalcdf (SEE THE ATTACHED FILE BELOW FOR THE COMPUTATION)
we have P(x > 337 ) = 0.1056
the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard deviation of 2.1 minutes. He walks in once a day during term time, 180 days per year, and leaves home 20 minutes before his first lecture. a. Find the probability that he is late for his first lecture. b. Find the number of days per year he is likely to be late for his first lecture.
Answer:
a) 2.84% probability that he is late for his first lecture.
b) 5.112 days
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 16, \sigma = 2.1[/tex]
a. Find the probability that he is late for his first lecture.
This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{20 - 16}{2.1}[/tex]
[tex]Z = 1.905[/tex]
[tex]Z = 1.905[/tex] has a pvalue of 0.9716
1 - 0.9716 = 0.0284
2.84% probability that he is late for his first lecture.
b. Find the number of days per year he is likely to be late for his first lecture.
Each day, 2.84% probability that he is late for his first lecture.
Out of 180
0.0284*180 = 5.112 days
Find the value of z Subscript alpha divided by 2 that corresponds to a confidence level of 89.48%.
Answer:
For this case we know that the confidence level is 89.48% or 0.8948 and the significance would be: [tex] \alpha=1-0.8948 = 0.1052[/tex] and the value of [tex]\alpha/2 =0.0526[/tex]
Now we need to find a quantile in the normal standard distribution who accumulate 0.0526 of the area on each tail of the normal standard distribution and we got:
[tex] z_{\alpha/2}= \pm 1.62015[/tex]
And we can use the following excel code for example:
"=NORM.INV(0.0526,0,1)"
Step-by-step explanation:
For this case we know that the confidence level is 89.48% or 0.8948 and the significance would be: [tex] \alpha=1-0.8948 = 0.1052[/tex] and the value of [tex]\alpha/2 =0.0526[/tex]
Now we need to find a quantile in the normal standard distribution who accumulate 0.0526 of the area on each tail of the normal standard distribution and we got:
[tex] z_{\alpha/2}= \pm 1.62015[/tex]
And we can use the following excel code for example:
"=NORM.INV(0.0526,0,1)"
g It is known that 20% of products on a production line are defective. Products are inspected until first defective is encountered. a) What is the probability that the experimenter must inspect six products
Question:
It is known that 20% of products on a production line are defective. Products are inspected until first defective is encountered. a) What is the probability that the experimenter must inspect six products to find a defective product?
Answer:
P(x = 6) = 0.0655
P(x = 6) = 6.55%
Step-by-step explanation:
It is given that 20% of products on a production line are defective.
p = 0.20
Then
q = 1 - p = 1 - 0.20 = 0.80
Which means that 80% of products on the production line are not defective.
We want to find out the probability that the experimenter must inspect six products to find a defective product.
Let x is the number of inspections to get a defective product.
P(x = 6) = ?
If out of 6 inspections 1 is defective then it means 5 are not defective
so the probability is
P(x = 6) = p¹ × q⁵
P(x = 6) = 0.20¹ × 0.80⁵
P(x = 6) = 0.20 × 0.32768
P(x = 6) = 0.0655
P(x = 6) = 6.55%
Therefore, there is 6.55% chance that the experimenter finds a defetive product in 6 inspections.
Jack uses triangles in the construction of bridges, such as the one shown below. A triangle has angles G, 72 degrees, and blank. The exterior angle to the blank angle is 133 degrees. What is the measure of Angle?
Answer: The answer is 61
Step-by-step explanation: did it on 2020 edg pls mark me brainliest
Answer:
61
Step-by-step explanation:
Any help would be greatly appreciated.
There are 300 raffle tickets.
The prizes are as follows:
First prize - voucher for meal at local restaurant
Second prize - food hamper
Third prize - chocolate cake
4x homemade jams
3x homemade pickles
A prize is won after the first raffle ticket is drawn.
What is the probability of winning a prize when the next ticket is drawn?
Answer: 0.007
Step-by-step explanation:
Suppose that you have a ticket.
We have 3 prizes, and 300 tickets.
After the first tiket is drawn, someone win a prize, so now we have 299 tikets left and 2 prizes left.
Then, for the next draw, you have p = 1/299 of wining a prize.
If you did not win there, the probability for the third price is p = 1/298 (because there are 2 less tickets now)
Then the probability of winning at least one prize is:
P = 1/299 + 1/298 = 0.007
Very confused, need help quick! (see attachment) Simplify and show your work.
Answer:
27/(4x^6y^8)
Step-by-step explanation:
Target the variables first. (x^a)^b is the same as x^(a x b).
In the numerator, it is x^(2 x 3) , which is x^6, and y^(4 x 3), which is y^12.
Same principle on the bottom. the denominator is x^12 and y^20.
In the numerator, the number 4 is alone so don't do anything to it. Cube 3. The coefficient of the numerator is 4 x 3^3 . The coefficient of the denominator is 2^4. Cancel like terms. when you divide same terms' exponents, you subtract the exponent on top by the exponent on the bottom. Remember that you can only simplify LIKE terms. (x with x, y with y, number with number.)