Answer:
The set of all pages in the book:
S={1, 2, 3, ..., 428}
Step-by-step explanation:
The sample space is the set containing all possible outcomes for the experiment. In this problem, the experiment is stopping at a random page of the textbook, and the sample space is the set of all pages in the book:
S={1, 2, 3, ..., 428}.
Answer:
s
Step-by-step explanation:
what is the area of this circle?
Answer:
69.08
Step-by-step explanation:
Area equals pi r times 2
A equals 3.14 times 11 times 2
Step-by-step explanation:
area of circle = pi r^2
area = 22/7 × 11yd× 11yd
area = (2662yd^2)/7
area = 380.3 yd^2
-4x - 3(2x + 8) = 36 solve for x
Answer:
x = -6
Step-by-step explanation:
-4x - 3(2x + 8) = 36
-4x - 6x - 24 = 36
-10x = 60
-x = 6
x = -6
Answer:
[tex]x = - 6[/tex]
Step-by-step explanation:
[tex] - 4x - 3(2x + 8) = 36 \\ - 4x - 6x - 24 = 36 \\ - 10x = 36 + 24 \\ - 10x = 60 \\ \frac{ - 10x}{ - 1 0} = \frac{60}{ - 10} \\ x = - 6[/tex]
hope this helps
brainliest appreciated
good luck! have a nice day!
5. Write down the nth term of each of the following G.Ps
whose first two terms are given as follows. Also find
the term stated besides each G.P. i) 12,-3b,......sixth term
Answer:
1i) nth term = 12(-b/4)^(n-1)
ii) nth term = 3(-1/9)^(n-1)
2i) Sixth term= (-3b^5)/256
ii) Eight term = -1/1594323
Question:
The complete question as found on brainly (question-10746111):
Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.
i) 12,-3b,......sixth term
ii) 3,-1/3,..........;8th term?
Step-by-step explanation:
1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.
i) 12,-3b,......;sixth term
1st term = a= 12
r = common ratio = 2nd term /1st term
r = -3b/12 = -b/4
Then we would find the nth term
See attachment for details
ii) 3,-1/3,..........;8th term
1st term = a= 3
r = common ratio = 2nd term /1st term
r = (-⅓)/3 = (-⅓)(⅓) = -1/9
Then we would find the nth term
See attachment for details
2) we are to determine the sixth term in (i) and eight term in (ii)
See attachment for details
Sixth term= (-3b^5)/256
Eight term = -1/1594323
(4x2 + 7x)(5x2 – 3x)
A. 2034 + 35x3 - 21x2
O B. 202A + 23x3 - 21x2
C. 20x4 + 23x2 - 21%
O D. 20A + 35x2 – 21x
Answer:
work is shown and pictured
60cm in the ratio 5:7
Answer:
[tex]25:35[/tex]
Step-by-step explanation:
[tex]\frac{60}{5+7}[/tex]
[tex]\frac{60}{12}[/tex]
[tex]=5[/tex]
[tex]5:7[/tex]
[tex]5 \times 5 :7 \times 5[/tex]
[tex]25:35[/tex]
pls answer this qn i need it urgently
Answer:
First rationalize the surd
(√3 +√2)(√3 - √2)/(√3 - √2)(√3 -√2)
The final answer will be 5 + 2√6
So x = 5 + 2√6
I) x + 1/x
5 + 2√6 + 1/5 + 2√6
Find the LCM
The final answer will be 10
ii) x² +1/x²
(5 + 2√6)² + 1/(5 +2√6)²
= 49 + 20√6 + 1/49 + 20√6
Find the LCM
The final answer will be 98
For i) x = 10
ii) x = 98
Hope this helps.
Answer:
i) 10
ii) 98
Step-by-step explanation:
x= (√3+√2)/(√3-√2)
i)
x+1/x= (√3+√2)/(√3-√2) + (√3-√2)/(√3+√2)= ((√3+√2)²+(√3-√2)²)/(√3+√2)(√3-√2)=(3+2+2√6+3+2-2√6)/(3-2)= 10ii)
x²+1/x²= (x+1/x)² - 2x*1/x= 10² - 2= 100 - 2= 98A set of data includes 107 data points ranging from 0 – 300. If the data is split into classes with a range of 50 (1 – 50, 51 – 100, etc), and there are no values that fall in the class 201 – 350, what can you say about the data? a.All the data lies below 200. b.The median could be in the range 201 - 350. c.The relative frequency of the class 201 - 350 is 0. d.The mean of the data will not be between 201 - 350.
Answer:
D
Step-by-step explanation:
The mean is the average summing all values together and dividing by the number of values been investigated.
Hence since no values exist between 201-350 that means the mean can not be there.
Answer:
The relative frequency of the class 201 - 350 is 0.
Step-by-step explanation:
A rectangle has a length of 6 inches, and a width
of 4 inches. What is the area of this rectangle
Answer:
length times width so.... 24
what is the sum of (2x - 6) + (4x - 4)
Answer:
6x - 10
Step-by-step explanation:
2x + 4x = 6x
6 + 4 = 10
6x - 10
The sum of two numbers is no more than 28. Let x represent the first number, and let y represent the second number. Which
inequality represents this situation?
O Y<X+28y
O Y<_X+28
O X+ y<28
O X+y<_28
Answer:
C
Step-by-step explanation:
A company which sells farm equipment must pay a federal tax of 5.5% on every sale. Last month the company’s sales totaled $335,000. How much federal tax is owed?
Answer:
Federal tax amount = $18,425
Step-by-step explanation:
Given:
Total sales amount = $335,000
Federal tax rate = 5.5%
Find:
Federal tax amount = ?
Computation:
⇒ Federal tax amount = Total sales amount × Federal tax rate
⇒ Federal tax amount = $335,000 × 5.5%
⇒ Federal tax amount = $335,000 × 0.055
⇒ Federal tax amount = $18,425
Therefore, total amount of federal tax owed is $18,425
solve the system of equations using elimination 3c - 8d =7 and c + 2d = -7
Answer:
d=-2 c=-3
Step-by-step explanation:
3c-8d=7
4(c+2d=-7)
3c-8d=7
4c+8d=-28
4c+3c-8d+8d=7-28
7c=-21
c=-3
c+2d=-7
-3+2d=-7
2d=-4
d=-2
Given.
[tex](3c-8d=7)=(c+2d=-7)[/tex]
Multiply 4 to the second equation.
[tex]4(c+2d=-7)[/tex]
[tex]3c+8d=-28[/tex]
Compare the like terms.
[tex]4c+3c-8d+8d=7-28[/tex]
Solve.
[tex]7c=-21[/tex]
Divide 7 to both sides
[tex]\frac{7c}{7}=\frac{-21}{7}[/tex]
[tex]c=-3[/tex]
Substitute (-3) for c into the original second equation.
[tex]c+2d=-7[/tex]
[tex]-3+2d=-7[/tex]
Add (3) to both sides.
[tex](-3+2d=-7)+3[/tex]
[tex]2d=-4[/tex]
Divide (2) to both sides.
[tex]\frac{2d}{2}=\frac{-4}{2}[/tex]
[tex]d=-2[/tex]
Check your work.
[tex]3(-3)-8(-2)=7[/tex]
[tex]-9+16=7[/tex]
[tex]7=7[/tex]
[tex]c+2d=-7[/tex]
[tex]-3+2(-2)=-7[/tex]
[tex]-3-4=-7[/tex]
[tex]-7=-7[/tex]
Therefore your answer is.
[tex]c=-3\\d=-2[/tex]
If f(x) = 3x + 5, find f(2).
Answer:
f(2) = 11
hope this helps
Step-by-step explanation:
3(2)+5
6+5
11
Answer:
11
Step-by-step explanation:
3(2)+5=11
Substitution -- :D
Two fair dice are renumbered using -2, -1, 0, 1, 2, 3 instead of the
usual numbers. The two dice are thrown in the normal way.
Draw a table to show the total score for each of the possible
outcomes
(b) How many ways are there of scoring 0 ?
Pls help ASAP
Answer:
6
Step-by-step explanation:
the number of occurs over 0
Help………………………!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:d
Step-by-step explanation:(2√7 +3√6) (5√2 +4√3)
To open the bracket, multiply the first rational number (2√7 ) with the two numbers in the other bracket and 3√6 with the other numbers in the other brackets.
2√7(5√2+4√3) + 3√6(5√2+4√3)
Multiply number with number and root with root
10√14 +8√21+15√12+12√18
Then look for the roots which have a perfect number and can be broken down. There is 12 and 18 which have perfect numbers.
10√14 +8√21+(15√4 x√3) +(12√9 x √2)
10√14 +8√21 +15 x 2 x√3 +12 x 3 x √2
10√14+8√21+30√3 +36√2 ans
oPr
on (x - 2)(x + 5) = 0?
________________________________
Hey!!
Solution,
(x-2)(X+5)=0
Either,
x-2=0
X=0+2
X=2
or,
X+5=0
X=0-5
X=-5
Hope it helps
Good luck on your assignment
____________________________
how to write 1/4 as a decimal
Answer:
0.25
Step-by-step explanation:
As a decimal, 0.25
As a fraction, 1/4
As a percentage, 25%
Answer:
0.25
Step-by-step explanation:
1/4
= 1*25/4*25
= 25/100
(Multiplying to both numerator and denominator doesn't change the value)
Now to write 25/100 as a decimal
The decimal point goes two places to the left in 25
(Since 100 has 2 zeroes so two values back)
25/100 = .25
= 0.25
Matthew is a salesman and earns commission on merchandise he sells. Last week he sold $7000 in merchandise. How much money does Matthew get in commission? The percent of the commsion is 3%
Answer:
I think the commission amount is $210
Find m∠UTS, if m∠UTV=x+15, m∠VTS=140∘, and m∠UTS=15x+15.
Answer:
165
Step-by-step explanation:
First, m<UTS=m<UTV+m<VTS by Angle Addition Postulate. Then, you substitute all the values that you provided for the angles. 15x+15=x+15+140. You then solve for x.
15x+15=x+155
14x=140
x=10
You then plug back in 10 for X in the value of m<UTS. 15(10)+15=165
Which procedure justifies whether Negative 3 x (5 minus 4) + 3 (x minus 6) is equivalent to Negative 12 x minus 6? The expressions are not equivalent because Negative 3 (2) (5 minus 4) + 3 (2 minus 6) = negative 18 and Negative 12 (2) minus 6 = negative 30. The expressions are not equivalent because Negative 3 (2) (5 minus 4) + 3 (2 minus 6) = negative 18 and Negative 12 (3) minus 6 = negative 42. The expressions are equivalent because Negative 3 (2) (5 minus 4) + 3 (2 minus 6) = negative 18 and Negative 12 (negative 2) minus 6 = 18. The expressions are equivalent because Negative 3 (2) (5 minus 4) + 3 (2 minus 6) = negative 18 and Negative 12 (1) minus 6 = negative 18.
Answer:
The correct option is;
The expressions are equivalent because Negative 3 (2) (5 minus 4) + 3 (2 - 6) = negative 18 and Negative 12 (1) minus 6 = negative 18
Step-by-step explanation:
The parameters given are;
First expression 3 × X × (5 - 4) + 3 ×(X - 6)
Second expression -12 × X - 6
Therefore;
For the first expression, for all X, e have;
3 × X × 1 + 3 ×(X - 6) = -3·X + 3·X -18 = -18
The second expression gives -12·X - 6
When both expressions are equal, we have;
-12·X - 6 = -18
∴ X = (-18 + 6)/(-12) = 1
Hence the correct option is that the expressions are equivalent because Negative 3 (2) (5 minus 4) + 3 (2 - 6) = negative 18 and Negative 12 (1) minus 6 = negative 18.
Answer:
The expressions are not equivalent because Negative 3 (2) (5 minus 4) + 3 (2 minus 6) = negative 18 and Negative 12 (2) minus 6 = negative 30
Or
Answer A
Step-by-step explanation:
Apparently, we're trying to see if ...
-3(x)(5 -4) + 3(x -6) = -12(x) -6
by evaluating the expressions for x=2:
-3(2)(5-4) +3(2 -6) ?= -12(2) -6
-6 -12 ?= -24 -6
-18 ≠ -30 . . . . . . . . . shows expressions are not equivalent
what is the definition of an opposite ray
Answer:
'''A ray has one endpoint and extends indefinitely in one direction. A pair of opposite rays are two rays that have the same endpoint and extend in opposite directions. Rays are always named with two points and the first point in the name must be the endpoint.'''
A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours, it can go 40 km upstream and 55 km down-stream. Determine the speed of the stream and that of the boat in still water.
Answer:
Average speed of boat = 3.67 km/h
Average speed of stream = 0.63 km/h
Step-by-step explanation:
30 km upstream in 10 hours gives a speed of 30/10 = 3 km/h relative speed of boat and stream
Same way, 44 km in 10 hrs = 4.4 km/h relative speed of boat and stream.
Let the speed of the stream be y
Let the speed of both be x, then
x - y = 3.... (1)
x + y = 4.4.... (2)
Subtract 1 from 2
2y = 1.4
y = 1.4/2 = 0.7 km/h
substitute value of y in 1
x - 0.7 = 3
x = 3.7 km/h
Also, 40 km upstream in 13 hrs gives speed of 3.08 km/h
55 km in 13 hrs gives 4.2 km/h
Let speed of boat be x and that of stream be y
x - y = 3.08.... (1)
x + y = 4.2..... (2)
Subtract 1 from 2
2y = 1. 12
y = 0.56 km/h
Substitute value of y in 1
x - 0.56 = 3.08
x = 3.64 km/h
Average speed of boat = (3.7 + 3.64)/2
= 3.67 km/h.
Average speed of stream = (0.7 + 0.56)/2 = 0.63 km/h
Answer:
Let the speed of boat in stream be x km/hrAnd the speed of boat in still water be y km/hr.For upstream = x - yFor downstream = x + yAs we know that,
[tex]\bigstar \: \: \sf Time = \dfrac{Distance}{Speed} \\ \\ [/tex]
[tex]\bigstar\:\underline{\boldsymbol{According\: to \:the\: Question\:now :}} \\[tex]
[tex]:\implies \sf \dfrac{30}{x - y} + \dfrac{44}{x + y} = 10 \\ \\ \\ [/tex]
[tex]:\implies \sf \dfrac{40}{x - y} + \dfrac{55}{x + y} = 13 \\ \\ \\[/tex]
[tex]\sf Let \: \dfrac{1}{x - y} = \textsf{\textbf{m}} \sf \: \: and \: \: \sf{\dfrac{1}{x + y} = \textsf{\textbf{n} }}\\ \\ \\[/tex]
[tex]:\implies \sf 30m + 44n = 10\: \: \: \: \Bigg\lgroup \textsf{\textbf{Equation (i)}}\Bigg\rgroup \\ \\ \\[/tex]
[tex]:\implies \sf 40m + 55n = 13\: \: \: \: \Bigg\lgroup \textsf{\textbf{Equation (ii)}}\Bigg\rgroup \\ \\ \\[/tex]
[tex]\qquad\tiny \underline{\frak{ Multiply \: equation \: (ii) \: by \: 3 \: and \: equation \: (i) \: by \: 4 :}} \\[/tex]
[tex]:\implies \sf 120m + 176n = 40\: \: \: \: \Bigg\lgroup \textsf{\textbf{Equation (iii)}}\Bigg\rgroup \\ \\ \\[/tex]
[tex]:\implies \sf 120m + 165n = 39\: \: \: \: \Bigg\lgroup \textsf{\textbf{Equation (iv)}}\Bigg\rgroup \\ \\ \\[/tex]
[tex]\qquad\tiny \underline{\frak{ Substracting \: equation \: (iii) \: from \: equation \: (iv) \: we \: get :}} \\[/tex]
[tex]\sf 120m + 176n = 40 \\ \\
\sf 120m + 165n = 39 \\ \\ [/tex]
[tex]\sf \: \: ( - ) \:\:\: \: \: ( - ) \: \: \: \: \: \: \: ( - ) [/tex]
_____________________
[tex]\: \: \: \: \qquad\sf 11n= 1 \\[/tex]
[tex]\: \: \: \: \: \qquad\sf n= \dfrac{1}{11} \\ \\ [/tex]
[tex]\qquad\tiny {\frak{ Put\: n = \dfrac{1}{11}\:in\:equation \: (i) \: we \: get :}} \\[/tex]
[tex]\dashrightarrow\:\:\sf 30m + 44 \times \dfrac{1}{11} = 10 \\ \\ \\[/tex]
[tex]\dashrightarrow\:\:\sf 30m= 10 - 4 \\ \\ \\[/tex]
[tex]\dashrightarrow\:\:\sf 30m= 6 \\ \\ \\[/tex]
[tex]\dashrightarrow\:\:\sf m= \dfrac{6}{30} \\ \\ \\ [/tex]
[tex]\dashrightarrow\:\:\sf m= \dfrac{1}{5} \\ \\ \\[/tex]
____________________....[tex]\dashrightarrow\:\:\sf \dfrac{1}{x - y} = m\\ \\ \\[/tex]
[tex]\dashrightarrow\:\:\sf x - y= 5\: \: \: \: \Bigg\lgroup \textsf{\textbf{Equation (v)}}\Bigg\rgroup \\ \\ \\[/tex]
[tex]\dashrightarrow\:\:\sf \dfrac{1}{x + y} = n\\ \\ \\[/tex]
[tex]\dashrightarrow\:\:\sf x + y= 11\: \: \: \: \Bigg\lgroup \textsf{\textbf{Equation (vi)}}\Bigg\rgroup \\ \\ \\[/tex]
[tex]\qquad\tiny {\frak{Adding\:equation \: (v) \: and \: equation \: (vi) \: we \: get :}} \\[/tex]
[tex]:\implies \sf 2x = 16 \\ \\ \\[/tex]
[tex]:\implies \underline{ \boxed{ \textsf {\textbf{x = 8 km/hr}}}} \\ \\[/tex]
[tex]\qquad\tiny {\frak{Putting\:x = 8\: in \: equation \: (v) \: we \: get :}} \\[/tex]
[tex]:\implies \sf 8 - y = 5 \\ \\ \\ [/tex]
[tex]:\implies \sf y = 8 - 5 \\ \\ \\[/tex]
[tex]:\implies \underline{ \boxed{ \textsf {\textbf{y = 3 km/hr}}}} \\ \\[/tex]
_________________....[tex]\bigstar\:\underline{\sf{Therefore\: speed\: of \:boat\: in\: still \:water\: and\: speed\: of\: stream:}} \\[/tex]
[tex]\bullet\:\:\textsf{Speed of boat in stream = \textbf{8 km/hr}}\\[/tex]
[tex]\bullet\:\:\textsf{Speed of boat in still water = \textbf{3 km/hr}}\\[/tex]
The lengths of two sides of a triangle are 3 inches and 8inches. Find the range possible for lengths for the third side, s.
Answer:
Using triangular inequality:
[tex]0< s\leq 3+8\\\ 0<s\leq 11\\[/tex]
What is the scale factor from small triangle to the larger triangle
Answer:
scale factor = 3
Step-by-step explanation:
The scale factor is the ratio of corresponding sides, larger to smaller.
scale factor = [tex]\frac{BC}{TB}[/tex] = [tex]\frac{12}{4}[/tex] = 3
A bag has 5 blue marbles, 4 red marbles, and 3 green marbles. A student randomly picks a marble from the bag and then rolls a number cube
with sides labeled 1 through 6.
What is the probability that the student picks a blue marble from the bag, and then rolls a 4?
A.5/72
B.5/42
C.1/3
D.7/12
Answer:
A. 5/72
Step-by-step explanation:
5 + 4 + 3 = 12 marbles
5/12 - the probability that the student picks a blue marble.
1/6 - the probability that 4 is on the cube
The probability that the student picks a blue marble from the bag, and then rolls a 4
5/12 * 1/6 = 5/72
Select the correct answer.
For which value of b can the expression x2 + bx + 18 be factored?
Answer:
11x
Step-by-step explanation:
(x + 2)(x + 9)
x2 + 9x + 2x + 18
x2 + 11x + 18
This is one possibility :)
A company produces a cardboard box in the shape of a rectangular prism. The surface area of the box is represented by
S= 4x, where x is the length of the base. Find the inverse by solving for x without switching the variables.
The inverse function is x =
Answer:
x=S/4
Or
x=S(1/4)
Step-by-step explanation:
Surface Area(S)=4x
Where
x=length
Inverse by solving for x without switching the variables
S=4x
Divide both sides by 4
S/4=4x/4
S/4=x
x=S/4
Or can also be written as
x=S(1/4)
make x the subject of the formula 6x+a=5(x+t)
Answer:
x= 5t - a
Step-by-step explanation:
6x + a = 5(x+t)
If you expand 5(x+t), you will get 5x + 5t
i.e. 6x + a = 5x + 5t
Add the additive inverse of 5x to both sides (The additive inverse of 5x is -5x)
i.e. 6x + a - 5x = 5x + 5t - 5x
x + a = 5t
Then, add the additive inverse of "a" to both sides (The additive inverse of a is -a)
i.e. x + a - a = 5t - a
x = 5t - a
Hope this helps!!!
Please help! Correct answer only!
In a raffle, one ticket will win a $900 prize, and the remaining tickets will win nothing. There are 500 in the raffle. If you have a ticket, what is the expected payoff?
Answer:
" Expected Payoff " ⇒ $ 1.80 ; Type in 1.80
Step-by-step explanation:
Take the probability of winning into consideration;
[tex]Total Number of Tickets - 500,\\Tickets 1 Person Can Enter - 1 Ticket,\\\\Probability of Winning - 1 / 500,\\Money Won - 900 Dollars,\\\\Proportionality - 1 / 500 = x / 900 - where, x = " Expected Payoff "\\1 / 500 = x / 900 - CrossMultiplication,\\\\500 * x = 900,\\x = 900 / 500,\\x = 1.80 Dollars Won!\\\\Conclusion ; x = 1.80 Dollars[/tex]
Solution ; " Expected Payoff " ⇒ $ 1.80
Solve:
-9(-5-3x)=21
A) 8/9
B) -8/9
C) 22/9
D) -22/9
Answer: B) -8/9
Step-by-step explanation:
I would start by looking inside the parenthesis to see if anything could be simplified. We see the terms -5 and -3x, and upon realizing that there is no way to simplify, we can go ahead and just simplify the left side of the equation as much as we can before worrying about breaking the equation down. Distribute the -9 to the -5 and the -3x (multiply -9 by -5 and -9 by -3x). Multiplying two negative numbers will result in a positive value, so the left side of your equation should end up looking like this: 45+27x=21. Now, we can start working to get the variable on its own. Subtract 45 from both sides of the equation. On the left side this cancels out and leaves you with 27x. On the right side you have more of the negative value than positive value, so you end up with -24. The equation now looks like this: 27x=24. The only thing left to do is divide the equation by 27. On the left side of the equation, this leaves you with just x. On the right side, you get -24/27. Normally at this point I would divide out to get the decimal form (I prefer working with decimals) but bc the answer choices are all fractions there's not really a good use to, so instead let's just find the greatest common denominator (GCD) which would be 8. (Just as a clarification the GCD is the largest number you can divide both numbers by evenly.) Divide both the numerator and denominator by eight leaves you with -8/9. Therefore, x= -8/9.