Answer:
B. Antonio is applying a 1-pound force to hold the 1-pound bag. E. The mass of the bag in his left hand is less than the mass of the bag in his right hand.Explanation:
In order for one to carry something, they need to be exerting a force that is equal to the weight of the object. For Antonio therefore to hold the 1-pound bag, he needs to apply a 1-pound force.
Pounds measure the mass of an object. On his left hand Antonio has 1 pound and on the right he has 2. He is therefore carrying more mass on his right hand than on his left.
A merry-go-round of radius 2 m is rotating at one revolution every 5 s. A
child is located at 1 m from the axis. A teenager is located at 2 m from the
axis.
What is the angular speed of the child?
What is the angular speed of the teenager?
What is tangential speed of the child?
What is the tangential speed of the teenager?
Answer:
a) The angular speed of the child is approximately 1.257 rad/s
b) The angular speed of the teenager is approximately 1.257 rad/s
c) The tangential speed of the child is approximately 1.257 m/s
d) For the child, r = 2 m
The tangential speed of the teenager is approximately 2.513 m/s
Explanation:
The revolutions per minute, r.p.m. of the merry-go-round = 1 revolution/(5 s)
The radius of the merry-go-round = 2 m
The location of the child = 1 m from the axis
The location of the teenager = 2 m from the axis
1 revolution = 2·π radians
Therefore, we have;
The angular speed, ω = (Angle turned)/(Time elapsed) = (2·π radians)/(5 s)
∴ The angular speed of the merry-go-round, ω = 2·π/5 radians/second
a) The angular speed of the child = The angular speed of the merry-go-round = 2·π/5 radians/second ≈ 1.257 rad/s
b) The angular speed of the teenager = The angular speed of the merry-go-round = 2·π/5 radians/second ≈ 1.257 rad/s
c) The tangential speed, v = r × The angular speed, ω
Where;
r = The radius of rotation of the object
For the child, r = 1 m
The tangential speed of the child = 1 m × 2·π/5 radians/second = 2·π/5 m/s ≈ 1.257 m/s
d) For the child, r = 2 m
The tangential speed of the teenager = 2 m × 2·π/5 radians/second = 4·π/5 m/s ≈ 2.513 m/s
Din Djarin pushes on a crate of frog eggs (with a mass of 88) with a force of 240 N, if µs= .4 and µk= .133 what is the net force acting on the crate?
I'll give brainliest to anyone who can answer this, too.
Answer:
R = mg
F = µsR
Fs= 0.4 × ( 88 × 10)
Fs = 772 N
Fk= µk R
Fs= 1.33 × 880 N
Net force = (772+(1.33×880))-240 N
Which of the following is an example of an unbalanced force?
A. Book sitting on a table
B. Car sitting in the garage
C. Person on an elevator going down
D. Person leaning on a wall
A weight of 6 kg increases the speed of its force from 2 m / s to 4 m / s. By how many joules does the kinetic energy of the body increase?
Answer:
36 J
Explanation:
Let's start off with the Kinetic Energy formula: 1/2m[tex]v^{2}[/tex]
So to find the change in Kinetic Energy, you would first have to find the Kinetic Energy in the beginning and in the end.
*Note: Mass: you incorrectly wrote weight = 6 kg- because weight is a force you have to write 6 Newtons. If you are talking about the mass, you would write 6 kg. If you are talking about weight, you would write 6 Newtons. The difference will make significant changes to the answer, so I will give you the answer for both.
If 6 kg is the MASS:
Beginning: find the kinetic energy.
Plug in all parts of the formula: 1/2mv^2 = [tex]\frac{1}{2}[/tex](6)(2 squared)= [tex]\frac{1}{2}[/tex](6)(4)= 12 J
End: find the kinetic energy.
Plug in all parts of the formula: 1/2mv^2=[tex]\frac{1}{2}[/tex](6)(4 squared)=[tex]\frac{1}{2}[/tex](6)(16)= 48 J
Answer:
36 J
If 6 kg is the WEIGHT:
We know that the weight formula is mg, or mass times acceleration due to gravity (which is always 9.8 m/s^2). Plug in the numbers:
Weight = mass x acceleration due to gravity
6 = mass x 9.8
6 = 9.8m
*Divide both sides*
mass = 0.6 kg
Now, we can use the mass to find the kinetic energy.
Beginning: find the Kinetic Energy
Plug in all parts of the formula: 1/2mv^2 = [tex]\frac{1}{2}[/tex](0.6)(2 squared)= [tex]\frac{1}{2}[/tex](0.6)(4)= 1.2 J
End: find the Kinetic Energy
Plug in all parts of the formula: 1/2mv^2=[tex]\frac{1}{2}[/tex](0.6)(4 squared)=[tex]\frac{1}{2}[/tex](0.6)(16)= 4.8 J
Answer:
3.6 J
(this answer is not very feasible, so 36 J is the way to go. But just remember, don't mix up weight and mass again- as you can see, they lead to different answers!)
The blades of a metal cutter are shorter than the blades of paper cutter scissor. Give reason
Answer:
Metal is a tougher material to cut though, so the blades must be shorter to create more pressure to break through the metal. Paper on the other hand is easier to cut through so the blades can be longer in order to cut more in each snip.
Given that both liquid A and B exert the same amount of pressure .What would be the height of column of liquid A if the density of liquid A is twice the density of liquid B and the height of column of liquid B is 10cm ?show you are work?
Answer:
ans 5
Explanation:
hope it's help It seems to me
Soccer is technically know as what ?
a - Futbol
b - Association football
c - Association soccer
Answer:
c - Association soccer
because there is football in form of American football, hence it's soccer
Answer:
B.
Explanation:
Soccer was the only football-type game in the United States until American-style football became popular in the 1870s