answer this question if an object weighs 30N on the surface of the moon. What will be its weighs on the surface of the earth​

Answer:

[tex]Pressure = 29723.1\ N/m^2[/tex]

Explanation:

Given

[tex]Force = 8694N[/tex]

[tex]Length = 0.45m[/tex]

[tex]Width = 0.65m[/tex]

Required

The force exerted on the floor by the box

First, calculate the area covered by the box (i.e. the base area)

[tex]Base\ Area = Length * Width[/tex]

[tex]Base\ Area = 0.45m * 0.65m[/tex]

[tex]Base\ Area = 0.2925m^2[/tex]

Pressure is calculated as:

[tex]Pressure = \frac{Force}{Area}[/tex]

[tex]Pressure = \frac{8694N}{0.2925m^2}[/tex]

[tex]Pressure = 29723.0769231\ N/m^2[/tex]

[tex]Pressure = 29723.1\ N/m^2[/tex] --- approximated

Answer: B

Explanation: I can tell the block weights more since the water went down

Answer:

cause you crazy..

Explanation:

Answer:

mass of liquid = total mass - mass of container

m = 52000kg - 200kg

m = 519800

D = m/v

D = 519800/160

D = 3,248.75 kgm-³

Answer:

III. The lift force is present because the pressure across the top is less than the pressure across the bottom of the wing.

Explanation:

Answer:

Hello, Yes i believe it would be a positive charge considering electrons have a negative charge while protons have a positive charge.

Explanation:

Answer:

Explanation:

In chemistry, the term transition metal has three possible definitions: The IUPAC definition defines a transition metal as "an element whose atom has a partially filled d sub-shell, or which can give rise to cations with an incomplete d sub-shell".

Answer:

Transition elements (also known as transition metals)

Explanation:

are elements that have partially filled d orbitals. IUPAC defines transition elements as an element having a d subshell that is partially filled with electrons, or an element that has the ability to form stable cations with an incompletely filled d orbital.

Answer:

The answer is B - the bending of rock layers happens due to stress, and this process is called folding. Faults are when it looks broken/displaced

Answer:

V = f x λ

Explanation:

The options are confusing

Answer:

2

Explanation:

wave length is the distance between corresponding points of two consecutive waves

3. hertz

Answer:

v₂ = 16 m/s

Explanation:

We can use the continuity equation, which is as follows:

[tex]A_1v_1 = A_2v_2\\[/tex]

where,

A₁ = Area of inlet = πd²/4

A₂ = Area of outlet = π(d/2)²/4 = πd²/16

v₁ = velocity at inlet = 4 m/s

v₂ = velocity at outlet = ?

Therefore,

[tex](\frac{\pi d^2}{4})(4\ m/s)=(\frac{\pi d^2}{16})v_2\\\\[/tex]

v₂ = 16 m/s

Answer:

F=mv^2/r = 50x(900)/625 = 72N

The centripetal force of 180 N is acting on the girl who is in the roller coaster ride with a speed of 30 m/s in a horizontal circle with a radius of 25m.

A centripetal force is the force which makes a body follow a circular path. Here, the direction is always orthogonal to the motion of body and towards a fixed point of instantaneous center of curvature of path.

The centripetal force acting on an object in circular path can be calculated with the help of a formula:

F = mv²/r

where, F = centripetal force acting on the object,

m = mass of the object,

v = velocity of the object,

r = radius of the circular path.

By putting the given values into the formula, we get:

F = [50 × (30)²]/25

F = [50 × 900]/25

F = 4500/25

F = 180 N

Therefore, the centripetal force acting on the girl is 180 N.

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Answer:

[tex]5.2\ \text{m/s}[/tex]

[tex]70^{\circ}[/tex] south of east

Explanation:

[tex]v_a[/tex] = 3 m/s

[tex]\theta_a[/tex] = [tex]20^{\circ}[/tex] north of east

[tex]v_b[/tex] = 6 m/s

[tex]\theta_b[/tex] = [tex]40^{\circ}[/tex] south of east = [tex]360-40=320^{\circ}[/tex] north of east

x and y component of [tex]v_a[/tex]

[tex]v_{ax}=v_a\cos \theta\\\Rightarrow v_{ax}=3\times \cos 20^{\circ}\\\Rightarrow v_{ax}=2.82\ \text{m/s}[/tex]

[tex]v_{ay}=v_a\sin\theta\\\Rightarrow v_{ay}=3\times \sin20^{\circ}\\\Rightarrow v_{ay}=1.03\ \text{m/s}[/tex]

x and y component of [tex]v_b[/tex]

[tex]v_{bx}=v_b\cos \theta\\\Rightarrow v_{bx}=6\times \cos 320^{\circ}\\\Rightarrow v_{bx}=4.6\ \text{m/s}[/tex]

[tex]v_{by}=v_b\sin\theta\\\Rightarrow v_{by}=6\times \sin320^{\circ}\\\Rightarrow v_{by}=-3.86\ \text{m/s}[/tex]

[tex]\Delta v=v_b-v_a\\\Rightarrow \Delta v=(4.6-2.82)\hat{i}+(-3.86-1.03)\hat{j}\\\Rightarrow \Delta v=1.78\hat[i}-4.89\hat{j}[/tex]

Magnitude

[tex]|\Delta v|=\sqrt{(-4.89)^2+1.78^2}\\\Rightarrow \Delta v=5.2\ \text{m/s}[/tex]

Direction

[tex]\theta=\tan{-1}|\dfrac{-4.89}{1.78}|\\\Rightarrow \theta=70^{\circ}[/tex]

The magnitude of the change in velocity vector is [tex]5.2\ \text{m/s}[/tex] and the direction is [tex]70^{\circ}[/tex] south of east.

The change in velocity will be  [tex]\Delta V=5.2\ \frac{m}{s}[/tex] and the direction will be [tex]70^o[/tex] South to east.

Any quantity which is defined by its magnitude and direction both are called as the vector quantities.

Now the data given in the question will be given as:

[tex]V_a[/tex] = 3 m/s

[tex]\theta[/tex] = [tex]20^o[/tex] north of east

[tex]V_b[/tex] = 6 m/s

[tex]\theta[/tex] =  [tex]40^o[/tex]south of east =  360-40=320 north of east

Now we will find the x and y component of [tex]V_a[/tex]

[tex]V_{ax}=V_acos\theta[/tex]

[tex]V_{ax}=3\times Cos20[/tex]

[tex]V_{ax}=2.82\ \frac{m}{s}[/tex]

[tex]V_{ay}=V_aSin\theta[/tex]

[tex]V_{ay}=3\times Sin20[/tex]

[tex]V_{ay}=1.03\ \frac{m}{s}[/tex]

Now we will find the x and y component of [tex]V_b[/tex]

[tex]V_{bx}=V_bcos\theta[/tex]

[tex]V_{bx}=6\times cos\320[/tex]

[tex]V_{bx}=4.6\ \frac{m}{s}[/tex]

[tex]V_{by}=V_bSin\theta[/tex]

[tex]V_{by}=6\times Sin320[/tex]

[tex]V_{by}=-3.86\ \frac{m}{s}[/tex]

Now change in velocity will be

[tex]\Delta V=V_b-V_a[/tex]

[tex]\Delta V=(4.6-2.82)i+(-3.86-1.03)j[/tex]

[tex]\Delta V=1.78i-4.89j[/tex]

The magnitude can be find out as follows:

[tex]\Delta V=\sqrt{(-4.89^2+(1.78^2)}[/tex]

[tex]\Delta V=5.2\ \frac{m}{s}[/tex]

The direction of the vector will be

[tex]\theta= tan^{-1}(\dfrac{-4.89}{1.78})[/tex]

[tex]\theta=70^o[/tex]

Thus the change in velocity will be  [tex]\Delta V=5.2\ \frac{m}{s}[/tex] and the direction will be [tex]70^o[/tex] South to east.

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The question is incomplete as it does not provide options to choose from or any context. instead of this, I will explain how to improve communication skills. improving communication skills takes practice, self-awareness, and a willingness to learn and grow. By focusing on these key areas, you can improve your ability to communicate effectively with others in a variety of settings.

Communication skills refer to the ability to convey information effectively and efficiently to others, both verbally and non-verbally. Effective communication involves active listening, clarity of expression, and an understanding of the message being conveyed.

There are several ways to improve communication skills, including:

Practice: Communication skills can be improved through regular practice. Look for opportunities to communicate with others, and take the time to reflect on your communication style and how you can improve.

Active listening: Effective communication requires active listening skills. Pay attention to what others are saying and ask questions to clarify your understanding.

Nonverbal communication: Nonverbal cues such as body language, eye contact, and facial expressions can convey important messages. Practice being aware of and controlling your own nonverbal cues to enhance your communication skills.

Clarity of expression: Clearly expressing your ideas and thoughts is essential for effective communication. Practice organizing your thoughts and speaking clearly and concisely.

Empathy: Being able to put yourself in someone else's shoes and understand their perspective is an essential communication skill. Practice showing empathy by actively listening and acknowledging the other person's feelings.

Feedback: Seek feedback from others on your communication skills. This can help you identify areas for improvement and refine your communication style.

Therefore, It takes time, effort, self-awareness, and a commitment to learn and develop new abilities to improve communication. You can enhance your capacity to interact successfully with others in a range of circumstances by concentrating on five important areas.

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Answer:

because u feel pain and u get shaky and fall

Explanation:

Answer:

Explanation:because it hurts so you fall

Answer:

Period = 0.68 seconds

Explanation:

Given the following data;

Number of oscillation = 22

Time = 14.9 seconds

To find the period;

Method I.

Period = time/number of oscillation

Period = 14.9/22

Period = 0.68 seconds.

Method II.

We would find the frequency of the wave;

Frequency = time/number of oscillation

Frequency = 22/14.9

Frequency = 1.48 Hertz

Next, we find the period;

Period = 1/frequency

Period = 1/1.48

Period = 0.68 seconds

Answer:

Prefer Soil more than sand

Explanation:

Answer:

Potential energy is related to mass and height. More context is required otherwise the answer here is an equation with several unknowns. PE = mgL(1 – COS θ) where θ is the angle away from the vertical and L is the length of the string.

Explanation:

Answer:

40 cm

Explanation:

Since Bob pulls with a force of F = 200 N when the spring is attached to the wall and it extends a length x = 20 cm, from Hooke's law,

F = kx where k = spring constant

So, k = F/x = 200 N/20 cm = 10 N/cm

Now, sine both Bob and Carlos pull with a force of F = 200 N in opposite directions, the spring stretches about its center and has an extension, x' in each direction.

So, from F = kx

x = F/k = 200 N/10 N/cm = 20 cm

So, the spring stretches 20 cm in both directions.

So, the total extension is thus x' + x' = 2x' = 2(20 cm) = 40 cm

The spring will stretch 40 cm.When a force is act om the spring the spring will stretch or compress depeds on the application of force.

Hooke's law states that the force used to extend the spring is directly equal to the amount of stretch.

The force needed to extend the spring is proportional to its displacement. It is stated as

F=Kx

The given data in the problem is;

F is the force of pull to bob=  200 N

x is the length of extension= 20 cm.

F' is the force act on the another end=  200 N

According to Hooke's law,

[tex]\rm F = Kx \\\\ \rm K= \frac{F}{x} \\\\ \rm K= \frac{200}{20} \\\\ \rm K=10 \ N/cm[/tex]

The extension due to another end force is found by;

[tex]\rm x' = \frac{F}{K} \\\\ \rm x' = \frac{200}{10} \\\\ \rm x' = 20[/tex]

The total extension of the spring will be;

[tex]\rm x_t = x+x' \\\\ \rm x_t = 2(20) \\\\ \rm x_t =40\ cm[/tex]

Hence the spring will stretch 40 cm.

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Answer:

30. $3.85

31. $2.22

Explanation:

30. The time duration of the kitchen clock is left on = All day = 24 hours

The power rating of the kitchen clock, P = 4 watts

The electricity cost in Alberta, R = $0.11 per kilowatt hour

The total number of hours the kitchen clock is on during the year, 't', is given as follows;

t = Number of hours per day × Number of days per year

∴ t = 24 hours/day × 365 days/year = 8,760 hours

The energy consumption of the kitchen clock, per year, E = P × t

∴ E = 4 watts × 8,760 hours = 35,040 watts-hour = 35.040 kw·h

The cost of operating the clock in one year, C = E × R

∴ Operating cost for the kitchen clock

∴ C = 35.040 kw·h × $0.11/(kw·h) = $3.8544 ≈ $3.85

The cost of operating the clock in one year, C ≈ $3.85

31. The power rating of the ghetto blaster, P = 28 watts

The time duration the ghetto blaster was on during an average month = All day = 24 hours

The number of days during an average month, n = 30 days

The cost of electricity in Alberta, R = $0.11 per kilowatt hour

The time in hours the ghetto blaster was on, t = 30 days/month × 24 hours/day

∴ t = 720 hours per month

The cost of operating the ghetto blaster in one month, C = P × t × R

∴ C = 28 W × 720 hours × 1 kw·h/(1000 w·h)× $0.11/(kw·h) = $2.2176

∴ The cost of operating the ghetto blaster in one month, C ≈ $2.22

Answer:

Because the two genes depend on each other, it is possible for someone to actually be a carrier of a dominant trait like brown eyes.  And if two blue eyed parents are carriers, then they can have a brown eyed child.  Genetics is much bkj

Explanation:

So all you light eyed parents with dark eyed kids, stop asking those paternity questions (unless you have other reasons to be suspicious).  Darker eyed kids are a real possibility that can now be explained with real genes.  

Answer:

B. A hill 70ft tall.

Explanation:

Answer:

Perpendicular ; Parallel

Answer:

The answer is "1.0748 and 1.0875".

Explanation:

Please find the complete question in the attachment file.

The incidence angle is [tex]i=45^{\circ}[/tex] for all colors When the angle is r, then use [tex]\frac{\sin{i}}{\sin{r}}=\frac{n_{o}}{n}[/tex] . Snell's rule Where [tex]n_{o}[/tex] is an outside material reflectance (same hue index) or n seems to be the crown glass index of the refraction, That index of inclination is [tex]90^{\circ}[/tex] as the light in color shifted behaver from complete inner diffraction to diffraction.

Whenever the external channel has a thermal conductivity for the red light, that's also

[tex]n_{o}=\frac{n_{r}\sin{45^{\circ}}}{\sin{90^{\circ}}}=\frac{1.520\times\sin{45^{\circ}}}{\sin{90^{\circ}}}=1.0748[/tex]

When outside the material has a refractive index, this happens with violet light.

[tex]n_{o}=\frac{n_{r}\sin{45^{\circ}}}{\sin{90^{\circ}}}=\frac{1.538\times\sin{45^{\circ}}}{\sin{90^{\circ}}}=1.0875[/tex]

In point a, The only red light flows out from the leaned face and the residual colors are mirrored mostly on prism for the primary benefits [tex]n_{o}=1.0748[/tex] (and slightly larger than that).

In point b, The only violet light is shown in the prism with the majority of the colors coming out from the sloping face for a scale similar to [tex]n_{o}= 1.0875[/tex] (and slightly smaller than this).

Answer:

carpet

Explanation:

Diffuse reflection is the reflection of light from a surface such that an incident ray is reflected at many angles rather than at just one angle as in the case of specular reflection.

The structure of carpet's surface is as shown. Thus it shows large amount of diffuse reflection.

The statement 'CO2 is removed from the atmosphere, and O2 is released' describes the redox reaction involved in photosynthesis. It is a redox reaction.

Photosynthesis refers to a series of reactions by which plants can produce simple carbohydrates by using solar radiation and oxygen (O2).

These photosynthetic reactions are well known to release carbon dioxide (CO2) into the atmosphere.

During Photosynthesis, CO2 is reduced to simple carbohydrates (e.g., glucose), while water (H2O) is oxidized to O2, thereby producing a redox reaction.

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