Jack has a rectangular patio with a length that is one foot less than twice its width. His neighbor Ron's patio has the same width but a length that is 5 feet more than its width. If Jack's patio is 120 square feet and Ron's patio is 104 square feet, how many square feet longer is Jack's patio than Ron's?

Answers

Answer 1

Answer:

difference in area = 16 ft²

if you use 8 the difference in length between Jack patio and his neighbor patio will be will be 15 - 13 = 2 ft

if you use 13 the difference i length will be 25 - 18 = 7 ft

Step-by-step explanation:

Jacks rectangular patio

width = a

length = 2a - 1

area = lw

where

l = length

w = width

area = 120 ft²

a(2a - 1)

2a² - a - 120 = 0

(a - 8) (2a + 15)

a = 8 or -15/2

Ron's rectangular patio

width = a

length = a + 5

area = lw

area = 104 ft²

a (a + 5) = 104

a² + 5a -104 = 0

(a + 8)  (a - 13)

a = -8 or 13

How many square feet longer is jack patio longer than Ron's patio is the difference in their area. Therefore,

120 - 104 = 16 ft²

The value 8 or 13 can be used for a since the width a have to be the same.

if you use 8 the difference in length between Jack patio and his neighbor patio will be will be 15 - 13 = 2 ft

if you use 13 the difference i length will be 25 - 18 = 7 ft


Related Questions

if you start with (2,6) and move 2 units right and 3 units down what will you end up with?

Answers

For (2,6) the 2 is the x value which is the left/right position and 6 is the y value which is the up/down position.

Moving 2 units to the right, you would add 2 to the x value. Moving 3 units down you would subtract 3 from the y value.

The answer would be (4,3)

The Employment and Training Administration reported that the U.S. mean unemployment
insurance benefit was $238 per week (The World Almanac, 2003). Aresearcher in the state
of Virginia anticipated that sample data would show evidence that the mean weekly unemployment
insurance benefit in Virginia was below the national average.
a. Develop appropriate hypotheses such that rejection of H0 will support the researcher’s
contention.
b. For a sample of 100 individuals, the sample mean weekly unemployment insurance
benefit was $231 with a sample standard deviation of $80. What is the p-value?
c. At αα = .05, what is your conclusion?
d. Repeat the preceding hypothesis test using the critical value approach.

Answers

Answer:

Step-by-step explanation:

a) We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 238

For the alternative hypothesis,

H1: µ < 238

This is a left tailed test

b) Since the population standard deviation is not given, the distribution is a student's t.

Since n = 100

Degrees of freedom, df = n - 1 = 100 - 1 = 99

t = (x - µ)/(s/√n)

Where

x = sample mean = 231

µ = population mean = 238

s = samples standard deviation = 80

t = (231 - 238)/(80/√100) = - 0.88

We would determine the p value using the t test calculator. It becomes

p = 0.19

c) Since alpha, 0.05 < than the p value, 0.19, then we would fail to reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed insignificant evidence that the mean weekly unemployment insurance benefit in Virginia was below the national average.

d) Since α = 0.05, the critical value is determined from the t distribution table. Recall that this is a left tailed test. Therefore, we would find the critical value corresponding to 1 - α and reject the null hypothesis if the test statistic is less than the negative of the table value.

1 - α = 1 - 0.05 = 0.95

The negative critical value is - 1.66

Since - 0.88 is greater than - 1.66, then we would fail to reject the null hypothesis.

Let two cards be dealt successively, without replacement, from a standard 52-card deck. Find the probability of the event. The first card is a queen and the second is a seven

Answers

Answer: 4 / 663

Step-by-step explanation:

There are 4 queens in a deck of 52 cards.

Probability = 4/52 = 1/13

There are 4 sevens

Probability = 4/51

Total probability = 1/13 x 4/51 = 4 / 663

The probability of drawing a queen first and a seven-second is 3/613.

What is probability?

Probability is defined as the possibility of an event being equal to the ratio of the number of favorable outcomes and the total number of outcomes.

There are 4 queens in a standard deck, and once one queen is drawn, there are 51 cards left, including 3 sevens.

So, the probability of drawing a queen first is 4/52 or 1/13, and the probability of drawing a seven-second is 3/51.

By the multiplication rule of probability, multiply the probabilities of each event occurring:

P(Queen and Seven) = P(Queen) × P(Seven after Queen)

P(Queen and Seven) = (1/13) × (3/51)

P(Queen and Seven) = 3/613

Thus, the probability of drawing a queen first and a seven-second is 3/613.

Learn more about the probability here:

brainly.com/question/11234923

#SPJ2

ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. I say no guessing because people usually guess on my questions.

Answers

Answer:

D. It would be less steep.

Step-by-step explanation:

→When the absolute value of the number in front of x is greater than 1, the function on the graph narrows. When the absolute value of the number in front of x is less than 1, the function on the graph widens.

In this case, the number is less than 1, making it grow wider. And as a result of it growing wider, it also becomes less steep.

Name the x-axis of symmetry for the parabola sketched below

Answers

Answer:

x=-3

Step-by-step explanation:

The vertex is at x = -3

The axis of symmetry is along the vertex

x=-3

Answer:

x=-3

Step-by-step explanation:

To find the axis of symmetry, you just need to find the x-coordinate of the vertex using this formula: -b/2a=x  

*Only when provided a three variable quadratic equation.

For looking at a graph, you find the center of the parabola in which when you reflect it over itself, it will be symmetrical.

According to the graph, x=-3 is the line which you can draw to fold over to the other side and it can fit perfectly.

HELP WITH THIS PLEASE

Answers

Answer:

a = 35º

b = 140º

c = 40º

d = 140º

e = 58º

Step-by-step explanation:

Angle A is supplementary to the angle that is 145º, and supplementary angles always add up to 180º. Therefore, 180 - 145 = 35, the measure of angle a. Angle B is supplementary to the 40º angle, so its measure is 140. Angle C is opposite the 40º angle, and opposite angles are congruent, so its measure would also be 40º. Angle D is also 140º because it is opposite of angle B. Angle E is supplementary to the angle that measures 122º, so 180 - 122 = 58. Hope this helped!

Is​ f(x) continuous at x equals 4​? Why or why​ not? A. ​No, f(x) is not continuous at x equals 4 because ModifyingBelow lim With x right arrow 4 f (x )does not exist. B. ​Yes, f(x) is continuous at x equals 4 because f (4 )exists. C. ​No, f(x) is not continuous at x equals 4 because f (4 )is undefined. D. ​Yes, f(x) is continuous at x equals 4 because ModifyingBelow lim With x right arrow 4 f (x )equals f (4 ).

Answers

Corrected Question

Is the function given by:

[tex]f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right[/tex] ​

continuous at x=4​? Why or why​ not? Choose the correct answer below.

Answer:

(D) ​Yes, f(x) is continuous at x = 4 because [tex]Lim_{x \to 4}f(x)=f(4)[/tex]

Step-by-step explanation:

Given the function:

[tex]f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right[/tex]

A function to be continuous  at some value c in its domain if the following condition holds:

f(c) exists and is defined.[tex]Lim_{x \to c}$ f(x)[/tex] exists. [tex]f(c)=Lim_{x \to c}$ f(x)[/tex]

At x=4

[tex]f(4)=\dfrac{1}{4}*4+1=2[/tex][tex]Lim_{x \to 4}f(x)=2[/tex]

Therefore: [tex]Lim_{x \to 4}f(x)=f(4)=2[/tex]

By the above, the function satisfies the condition for continuity.

The correct option is D.

WILL GIVE BRAINLIEST! HURRY

Answers

Answer:

4

Step-by-step explanation:

2(6x+4)-6+2x=3(4x+3)+1

=14x+2=12x+10

=14x+2-2=12x+10-2

=14x=12x+8

=14x-12x=12x+8-12x

=2x=8

=2x/2=8/2

x=4

$17,500,000 is what percent of $70,000,000?

Answers

Answer: 1/4 of 70,000,000

Step-by-step explanation: 17,500,000 / 70,000,000 = 0.25

Answer:

[tex]25\%[/tex]

Step-by-step explanation:

[tex]\frac{17,500,000}{70,000,000}[/tex]

[tex]\frac{1}{4}=0.25=25/100=25\%[/tex]

Find the range of the set of numbers shown by the box-and-whisker plot.
6
6
7
8
9
10
11
12
13
14
16
16
17
18
19
20
21
22

Answers

I’m confused on what you are asking in this I think it would be 6

Answer:

16

Step-by-step explanation:

The range is the difference between the highest and lowest number of a data set. 22-6=16

Landes is a sales representative for a company. She earns a basic pay of $2,750 a month plus commission of 1.5%. How much does Landes [now that the moderators are gone just answer this question and claim points lol]

Answers

Answer:

2,748.5

Step-by-step explanation:

Answer:

thank uuu

Step-by-step explanation:

The mean of 6 numbers is 32.If one of the numbers is excluded, the mean reduces by 2.Find the excluded number.

Answers

Answer:

42

Step-by-step explanation:

Mean = Sum of numbers/ Total numbers

Sum of 6 numbers = 32 x 6

= 192

If one number is excluded the mean reduce by 2 . so it becomes 30

Sum of 5 Numbers = 5 x 30

=150

Therefore the excluded number is

= 192 - 150

= 42.

From a sample with nequals24​, the mean number of televisions per household is 4 with a standard deviation of 1 television. Using​ Chebychev's Theorem, determine at least how many of the households have between 2 and 6 televisions. At least nothing of the households have between 2 and 6 televisions.

Answers

Answer:

At least 18 of the households have between 2 and 6 televisions.

Step-by-step explanation:

Chebyshev Theorem

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]100(1 - \frac{1}{k^{2}})[/tex].

In this question:

Mean = 4

Standard deviation = 1

Percentage of households that have between 2 and 6 televisions.

2 = 4 - 2*1

So 2 is two standard deviations below the mean

6 = 4 + 2*1

So 6 is two standard deviations above the mean

By Chebyshev's Theorem, at least 75% of the measures are within 2 standard deviations of the mean.

Out of 24

0.75*24 = 18

At least 18 of the households have between 2 and 6 televisions.

A fluctuating electric current II may be considered a uniformly distributed random variable over the interval (9, 11)(9,11). If this current flows through a 2-ohm resistor, find the probability density function of the power P = 2I^2P=2I 2 .

Answers

Answer:

Step-by-step explanation:

A fluctuating electric current II may be considered a uniformly distributed random variable over the interval (9, 11)

[tex]p_1=\{^{\frac{1}{2}:9\leq i\leq 11}_{0:otherwise[/tex]

Now define

[tex]p = 2I^2[/tex]

[tex]\Rightarrow I^2=(\frac{p}{2} )\\\\\Rightarrow I=(\frac{p}{2} )^{\frac{1}{2} }\\\\\Rightarrow h^{-1}(p)=(\frac{p}{2} )^{\frac{1}{2}}[/tex]

[tex]\frac{dh^{-1}}{dp} =\frac{d[h^{-1}(p)]}{dp} \\\\=\frac{d(p/2)^{\frac{1}{2} }}{dp}[/tex]

[tex]=\frac{1}{2} \times \frac{1}{2} (\frac{p}{2} )^{{\frac{1}{2}-1} }\\\\=\frac{1}{4}(\frac{p}{2} )^{{\frac{1}{2}-1} }\\\\=\frac{1}{2}(\frac{2}{p} )^{{\frac{1}{2}} }[/tex]

using the transformation method, we get

[tex]f_p(p)=f_1(h^{-1}(p))|\frac{d[h^{-1}(p)]}{dp} |\\\\=\frac{1}{2} \times \frac{1}{4} (\frac{2}{p} )^{\frac{1}{2} }\\\\=\frac{1}{8} (\frac{2}{p} )^{\frac{1}{2} }[/tex]

[tex]f_p(p)=\{^{\frac{1}{8} (\frac{2}{p} )^{\frac{1}{2} },162\leqp\leq 242} }_{0,otherwise}[/tex]

a ford truck enters a highway and travles uniform speed of 50 mph. half an hour later a jaguar enters the highway at the same junction and heads in the same direction at 55 mph. how long after the ford enters the highway does the jaguard catch up

Answers

Answer:

5.5 hours

Step-by-step explanation:

We have that the distance is given by:

d = v * t = 50 mph * 1/2 h = 25 miles

The relative speed is given by:

 vr = 55 mph - 50 mph = 5 mph

Now the time required to reach

 would come being:

t = t '+ d / vr

we know that t '= 1/2 h, replacing:

t = 1/2 h + 25 mi / 5 mph

t = 1/2 h + 5 h

t = 5.5 h

Therefore, the required time is 5.5 hours.

At the beginning of an experiment, a scientist has 300 grams of radioactive goo. After 150 minutes, her sample has decayed to 37.5 grams.




What is the half-life of the goo in minutes?


________



Find a formula for


G(t),


the amount of goo remaining at time T.


G= _________



How many grams of goo will remain after 32 minutes?

Answers

Answer:

Half-life of the goo is 49.5 minutes

[tex]G(t)= 300e^{-0.014t}[/tex]

191.7 grams of goo will remain after 32 minutes

Step-by-step explanation:

Let [tex]M_0\,,\,M_f[/tex] denotes initial and final mass.

[tex]M_0=300\,\,grams\,,\,M_f=37.5\,\,grams[/tex]

According to exponential decay,

[tex]\ln \left ( \frac{M_f}{M_0} \right )=-kt[/tex]

Here, t denotes time and k denotes decay constant.

[tex]\ln \left ( \frac{M_f}{M_0} \right )=-kt\\\ln \left ( \frac{37.5}{300} \right )=-k(150)\\-2.079=-k(150)\\k=\frac{2.079}{150}=0.014[/tex]

So, half-life of the goo in minutes is calculated as follows:

[tex]\ln \left ( \frac{50}{100} \right )=-kt\\\ln \left ( \frac{50}{100} \right )=-(0.014)t\\t=\frac{-0.693}{-0.014}=49.5\,\,minutes[/tex]

Half-life of the goo is 49.5 minutes

[tex]\ln \left ( \frac{M_f}{M_0} \right )=-kt\Rightarrow M_f=M_0e^{-kt}[/tex]

So,

[tex]G(t)= M_f=M_0e^{-kt}[/tex]

Put [tex]M_0=300\,\,grams\,,\,k=0.014[/tex]

[tex]G(t)= 300e^{-0.014t}[/tex]

Put t = 32 minutes

[tex]G(32)= 300e^{-0.014(32)}=300e^{-0.448}=191.7\,\,grams[/tex]

An individual closes out help desk tickets at a rate of 4 tickets per hour for h hours. Write an equation that expresses the situation, let x be the independent variable and y be the dependent variable

Answers

Answer:

y=4x

Step-by-step explanation:

an independent variable is the variable  that is changed or controlled in an experiment or observation to test the effects on the dependent variable

a dependent variable is variable being tested and measured in a scientific experiment

in this case, the number of help desk tickets  closed out is dependent on the number of hours the individual works so y is the number of tickets closed (dependent variable). The number of tickets closed of will be 4 multiplied by the number of hours worked i.e. y=4x

Researchers want to know about the true proportion of adults with at least a high school education. 1000 adults are surveyed, and 710 of them have at least a high school education. Create a 95% confidence interval for the true population proportion of adults with at least a high school education. Interpret this interval in context of the problem.

Answers

Answer:

The 95% confidence interval for the true population proportion of adults with at least a high school education is (0.6819, 0.7381). This means that we are 95% sure that the true proportion of adults in the entire population surveyed with at least a high school education is (0.6819, 0.7381).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 1000, \pi = \frac{710}{1000} = 0.71[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.71 - 1.96\sqrt{\frac{0.71*0.29}{1000}} = 0.6819[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.71 + 1.96\sqrt{\frac{0.71*0.29}{1000}} = 0.7381[/tex]

The 95% confidence interval for the true population proportion of adults with at least a high school education is (0.6819, 0.7381). This means that we are 95% sure that the true proportion of adults in the entire population surveyed with at least a high school education is (0.6819, 0.7381).

Please answer this correctly

Answers

Answer:

432

Step-by-step explanation:

l x w

4x3

4x19

8x24

8x19

432

x^2 + 5x - 24 = 0 How do I solve by factoring

Answers

Answer:

x = -8 or x = 3

Step-by-step explanation:

To factor ax² + bx + c, use AC method.

a times c is 1 × -24 = -24.

Factors of ac (-24) that add up to b (5) are 8 and -3.

Divide by a and reduce: 8/1 and -3/1.

Therefore, the factors are x + 8 and x − 3.

x² + 5x − 24 = 0

(x + 8) (x − 3) = 0

x = -8 or 3

Find the values of x in the figure below. Express your answer in simplest radical form.

Answers

Answer:

Step-by-step explanation:I don't say u must have to mark my ans as brainliest but if it has really helped u plz don't forget to thank me...

What is the slope intercept form.

Answers

Answer:

y = 1/4x + 2

Step-by-step explanation:

Since they gave you point slope form already, all you need to do is convert that into slope-intercept form. Just distribute the parenthesis and move the 4 over. Once you do so, you should get C/3rd option as your answer.

need answers to 30 and 31

Answers

Answer:

C ; A

Step-by-step explanation:

Question 30:

Perimeter is the sum of all sides.

Perimeter for a recatngle can be found with the formula:

2(L+W)

Length is 7

Width is 4

Plug our values in.

2(7+4)

2(11)

22

Answer C

Question 31:

Circumference of a circle can be found with the formula:

πd.

Diameter of the given circle is 6.

Plug it in

Round π to 3.14

6(3.14)

18.84

Answer A

A sample​ mean, sample​ size, and population standard deviation are provided below. Use the​ one-mean z-test to perform the required hypothesis test at the 10​% significance level.
x = 20​, n = 36​, sigma = 9​, H0​: mu = 25​, H a​mu : < 25.

Answers

Answer:

[tex]z=\frac{20-25}{\frac{9}{\sqrt{36}}}=-3.33[/tex]  

The p value for this case is given by:

[tex]p_v =P(z<-3.33)=0.000434[/tex]  

For this case the p value is a very low value compared to the significance level of 0.1 so then we can reject the null hypothesis and we can conclude that the true mean is significantly less than 25 at 10% of significance.

Step-by-step explanation:

Information given

[tex]\bar X=20[/tex] represent the sample mean  

[tex]\sigma=9[/tex] represent the population deviation

[tex]n=36[/tex] sample size  

[tex]\mu_o =25[/tex] represent the value to verify

[tex]\alpha=0.1[/tex] represent the significance level

tzwould represent the statistic

[tex]p_v[/tex] represent the p value

System of hypothesis

We want to test the hypothesis that the true mean is lower than 25  and the system of hypothesis are:  

Null hypothesis:[tex]\mu \geq 25[/tex]  

Alternative hypothesis:[tex]\mu < 25[/tex]  

The statistic is given by:

[tex]z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}[/tex] (1)  

Replacing the info given:

[tex]z=\frac{20-25}{\frac{9}{\sqrt{36}}}=-3.33[/tex]  

The p value for this case is given by:

[tex]p_v =P(z<-3.33)=0.000434[/tex]  

For this case the p value is a very low value compared to the significance level of 0.1 so then we can reject the null hypothesis and we can conclude that the true mean is significantly less than 25 at 10% of significance.

What is the image of (-4,12) after a dilation by a scale factor of 1/4 centered at the origin

Answers

Answer:

(-1,4)

Step-by-step explanation:

Divide each imput by 4

The required image of the given point (-4, 12) dilation by a scale factor of 1/4 and centered at the origin is (1, -3).

Given that,
To determine the image of  (-4,12) after dilation by a scale factor of 1/4 centered at the origin.

What is a graph?

The graph is a demonstration of curves that gives the relationship between the x and y-axis.

What is coordinate?

Coordinate, is represented as the values on the x-axis and y-axis of the graph

Here,
For the point, we have a dilation factor of 1/4,
So dilated coordinate,
= (1/4 * - 4 ,   1/4 * 12)
= (-1 , 3)
To form the image across the origin
= - (-1, 3)
= (1, -3)

Thus, the required image of the given point (-4, 12) with a scale factor of 1/4 and centered at the origin is (1, -3).

Learn more about coordinate here:

brainly.com/question/13498438

#SPJ2

There are nine saxophone players in the band. The number of saxophone players is one less than twice the number of tuba players. Find the number of tuba players.

Answers

Answer:

[tex]5[/tex]

Step-by-step explanation:

Let [tex]x[/tex] be the number of tuba players.

We are given that the number of saxophone players is one less than twice the number of tuba players.

There are 9 saxophone players.

[tex]9 = 2 x-1[/tex]

[tex]9+1=2x[/tex]

[tex]10=2x[/tex]

[tex]10 \div 2=x[/tex]

[tex]5=x[/tex]

The Gleason family has a monthly budget of $4,500. Mr. Gleason has a full-time job and takes home $900 each week. Mrs. Gleason works part time and brings home $9 each week. For every hour she works. How many hours per month must Mrs. Gleason work to make sure that she and Mr. Gleason have met their monthly budget?

Answers

Answer:

The value of x from the equation is 100. Thus, Mrs. Gleason should work for 100 hours per month. 

Step-by-step explanation:

To answer this item, we let x be the number of hours per month that Mrs. Gleason should work. The total budget is equal to sum of the amount acquired by Mr. Gleason and Mrs. Gleason. The equation that would express this is,

                         4,500 = 900(4) + 9x

The value of x from the equation is 100. Thus, Mrs. Gleason should work for 100 hours per month. 

I am sorry if you get this wrong.

Question 1 Muit Choice Worth 1 points)
(08.01 LC)
The school principal wants to know whether the students in the entire school prefer football or basketball. The principal draws a random sample from the following groups:
• All school teachers
. All girls in each grade
. All students in each grade
• All students on the basketball team
Which of the following groups best represents the population she should take a random sample from to get the best results for her survey?
All school teachers
All girls in each grade
All students in each grade
All students on the basketball team

Answers

Answer:

I think its C. All students in each grade

Step-by-step explanation:

because it should be the students choice.

A recent national survey found that parents read an average (mean) of 10 books per month to their children under five years old. The population standard deviation is 5. The distribution of books read per month follows the normal distribution. A random sample of 25 households revealed that the mean number of books read last month was 12. At the .01 significance level, can we conclude that parents read more than the average number of books to their children

Answers

Answer:

Step-by-step explanation:

Null hypothesis: u = 10

Alternative hypothesis: u =/ 10

Using the formula: t = (x - u) / (s /√n)

Where x = 12, u = 10, s = 5 and n = 25

t= (12-10) / (5/√25)

t = (2)/(5/5)

t = 2/1= 2

t = 2.0

At a 0.01 level of significance with a degree of freedom of 24, the p-value is 0.0569, which is greater than 0.01 we will fail to reject the null and conclude that parents do not read more than the average number of books to their children

A washer and a dryer cost $639 combined. The washer costs $61 less than the dryer. What is the cost of the dryer?

Answers

Answer:

$350

Step-by-step explanation:

Let d = price of dryer

Then d - 61 is the price of the washer.

The sum of the prices is $639.

d + d - 61 = 639

2d - 61 = 639

2d = 700

d = 350

The price of the dryer is $350

Other Questions
Need help on #1 thank youu! This problem leads you through the derivation of a corrected equation for RF in yeast tetrad analysis that takes into account double crossover (DCO) meioses. A yeast strain that cannot grow in the absence of the amino acid histidine (his) is mated with a yeast strain that cannot grow in the absence of the amino acid lysine (lys). Among the 400 unordered tetrads resulting from this mating, 233 were PD, 11 were NPD, and 156 were T.a. What types of spores are in the PD, NPD, and T tetrads?b. Are the his and lys genes linked? How do you know? c. Using the simple equation RF = 100 [NPD +(1/2)T]/total tetrads, calculate the distance in mapunits between the his and lys genes.d. If you think about all the kinds of meiotic eventsthat could occur (refer to Fig. 5.24), you can see that the calculation you did in part (c) may substantially underestimate RF. What kinds of meioses (NCO, SCO, or DCO) generated each of the tetrad types in this cross? e. What incorrect assumptions does the simple RFequation you used in part (c) make about themeiotic events producing each type of tetrad? Whencould these assumptions nevertheless be correct? f. Use your answers to part (d) to determine thenumber of NCO, SCO, and DCO meioses thatgenerated the 400 tetrads.g. Use your answers to part (f) to write a generalequation that relates the number of DCO meiosesto the number of the various tetrad types. Thenwrite another general equation that computes thenumber of SCO meioses as a function of the number of the various tetrad types.h. Based on your answer to part (f), calculate theaverage number of crossovers per meiosis (m)between his and lys.i. Use your answer to (h) to write an equation for min terms of NCO, SCO, and DCO meioses.j. What is the relationship between RF and m?k. Use your answer to part (j) to write a corrected equation for RF in terms of SCO, DCO, and NCO meioses. l. Using your answer to part (g), rewrite the corrected RF equation from part (k) in terms of the numbersof the various tetrad types.m. The equation you just wrote in part (l) is a corrected equation for RF that takes into account doublecrossovers that would otherwise have been missed. Use this improved formula to calculate a moreaccurate distance between the his and lys genes than the one you calculated in part (c). What is the tone of the PSA? Check all that apply.informativeformalfriendlysillyeducational Determine the number of ways three trumpet players out of 6 are chosen for 1st chair, 2nd chair, and 3rd chair. Five people (Aaron , Byron , Carina , Duncan , and Evelyn ) form a club, Nequals {A, B, C, D, E}. Carina and Evelyn are women, and the others are men. If they choose a treasurer randomly, find the odds in favor of Evelyn becoming treasurer . The odds in favor of Evelyn becoming treasurer are 1. He is tired _________ watching television. A/ of B/ for C/ at D/ in 2. Are high school students interested ____________Math? A/ of B/ by C/ at D/ in 3. Meseret lives ________ Bahir Dar. She always goes ________school _______ foot. A/ in / on / to b/ in / to / on C/ on / to / in D/ to / to /on 4.Do you think that you are good ____________drawing? A/ at B/ by C/ with D/ from 5. The students go to school ___________ the morning and come back home _______ the afternoon. A/ on / of C/ at / in B/ at / at D/ in / in 8. It is raining. I hate a weather _________ this. A/ as B/ like C/ when D/ as if what is the volume of a cylinder with a height of 10 cm and a radius of 2 cm ? John goes to a restaurant and has a bill of $ 32. 57. He uses a 10% off coupon on the cost of his meal. The tax is 8%. He leaves a tip of 18% on the amount before the coupon or tax is applied. How much does he spend? Find the area of a regular hexagon with a side length of 5cm, Round to the nearest tenth. Restaurants do a large volume of business by credit and debit cards. Suppose Spring Garden Salads restaurant had these transactions on January 28, 2016: National Express credit card sales $10,500 ValueCard debit card sales 6,000 Requirements 1. Suppose Spring Garden Salads' processor charges a 3% fee and deposits sales net of the fee. Journalize these sales transactions for the restaurant. 2. Suppose Spring Garden Salads' processor charges a 3% fee and deposits sales using the gross method. Journalize these sales transactions for the restaurant. Which of these issues would be a concern for Americans as world war 1 drew to a close A 38 gram sample of a substance that is used to sterilize surgical instruments has a k-value of 0.113. Find the substance's half-life in days, round to the nearest tenth. explain the role microbiologist play in researching and treating the disease 8. Which of the following is NOT a recommendation to minimize a phlebotomist's risk of developing a MSCA. Adjust the height of the outpatient phlebotomy chair to minimize bendingB. Perform recommended exercises throughout the dayC. Place supplies so that it is necessary to reach across the body to obtain themD. When going to inpatient rooms, use a rolling phlebotomy cart instead of a phlebotomy tray Betty is considering investing in a company's stock and is aware that the return on that investment is particularly sensitive to how the economy is performing. Her analysis suggests that four states of the economy can affect the return on the investment. Probability Return Boom 0.3 25.00% Good 0.4 15.00% Level 0.1 10.00% Slump 0.2 -5.00%a) What is hte expected return on Barbara's investment? (Round answer to 3 decimal places, e.g. 0.076)b) What is the standard deviation of the return on Barbara's investment? (Round answer to 5 decimal places, e.g. 0.07680) the square root of 7/16 Why do you think President Kennedy says to the American people "...The size of thisundertaking makes clear that it has been planned for some months"? What is he suggesting tothe American people? what is the role of robot in man's life ? please dont copy from google Kyei weighed half the total weight of his two brothers. his two brothers be weighed 44 1/2kg and 32 1/2kg.what was kyei's weight Requirements 1. Record each transaction in the journal using the following account titles: Cash; Accounts Receivable; Office Supplies; Prepaid Insurance; Land; Furniture; Accounts Payable; Utilities Payable; Unearned Revenue; Common Stock; Dividends; Service Revenue; Salaries Expense; Rent Expense; and Utilities Expense. Explanations are not required. 2. T-accounts have been opened for each of the accounts. Post the journal entries to the T-accounts, using transaction dates as ledger accounts. Label the balance of each account Bal posting references in the ledger accounts.3. Prepare the trial balance of Beth Stewart, Designer, as of November 30, 2018.Nov.1 Received $41,000 cash and issued common stock to Stewart Nov. 1 4 Purchased office supplies, $1,200, and furniture, $2,300, on account. 6 Performed services for a law firm and received $2,100 cash. 7 Paid $27,000 cash to acquire land to be used in operations. 10 Performed services for a hotel and received its promise to pay the $800 within one week. 14 November 4 on account Paid for the furniture purchased 14 on. 15 Paid assistant's semimonthly salary, $1,470. 17 Received cash on account, $500. 20 Prepared a design for a school on account, $680. 25 Received $1,900 cash for design services to be performed in December. 28 Received $3,100 cash for consulting with Plummer & Gordon. 29 Paid $840 cash for a 12-month insurance policy starting on December 1. 30 Paid assistant's semimonthly salary, $1,470. 30 Paid monthly rent expense, $650. 30 Received a bill for utilities, $650. The bill will be paid next month 30 Paid cash dividends of $2,800. Post the journal entries to the T-accounts, using transaction dates as posting references in the ledger accounts. Label the balance of each account Bal.We will post to the accounts one transaction at a time. Begin by posting the events from the 1st.July1: Yangcontributed $64,000 cash to the business in exchange for Common Stock.Date Accounts Debit CreditJul.1 Cash 68,000 Commom Stock 68,000