Bubba-Joe carries out a careful investigation to determine the melting point of salicylic acid, and concludes that the value
is 161.4 degrees Celcius.
The melting point of salicylic acid is known very well as 158.6 degrees Celcius.
What is Bubba's percent error?

Answers

Answer 1

Bubba-Joe carries out a careful investigation to determine the melting point of salicylic acid, and concludes that the value is 161.4 degrees Celsius. The melting point of salicylic acid is known very well as 158.6  degrees Celsius. Bubba's percent error will be 1.74 %

Percentage error is the difference between estimated value and the actual value in comparison to the actual value and is expressed as a percentage. In other words, the percent error is the relative error multiplied by 100.

estimated value of melting point = 161.4 °C

true value of melting point = 158.6 °C

percent error = ((true value - expected value) / expected value) * 100

                       = ((158.6 - 161.4 ) / 161.4 ) * 100

                       = 1.74 %

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Related Questions

Copmared with a sound of 60 decibles a sound of 80 decibles has an intesity what times greater

Answers

According to sound power level, 80 decibel sound has greater intensity.

We need to know about sound power levels to solve this problem. The sound power level can be defined by a decibel unit. The decibel unit is proportional to the logarithm intensity ratio. It can be written as

dB = 10 log(I1 / I0)

where dB is sound power level, I1 is sound intensity and I0 is reference sound intensity (10¯¹² W/m²)

From the question we know that

Ia = 60 dB

Ib = 80 dB

Because the decibel unit is proportional to the logarithm intensity ratio, the sound with greater decibel will have greater intensity.

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A 2 kg block of cheese is in an elevator accelerating down at a rate of 1.5 m/s².
What is the normal force on the cheese?

Answers

F=ma
M: 2kg
A: 1.5 m/^2
F=2*1.5
F= 3

What is the purpose of a free body diagram?

to show the velocity of an object
to show the acceleration of an object
to show the forces acting on an object
to show the direction of motion vectors of an object

Answers

Answer:

c: to show forces acting on an object

Answer please with working out

Answers

1.
a. Speed = distance/time
b. 1500/300 = 5m/s
c. 10 - 2 = 8/2.4 = 3.33 seconds

2.
a. 0.46 x 2.4 = 1.104 metres
b. 78.4/8 = 9.8 m/2²

Answer:

(1) a) S=D/T

b)5m/s

c)3.33s

(2) a) 1.104m

Explanation:

(1) b) S=D/T

 S=1500/300

 S=5m/s

c) T= V-U/a

 v=10

 u= 2

 a= 2.4

10-2=8/2.4=3.33s

(2) a) d=s×t

 0.46×2.4=1.104m



Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it.

Answers

   The value of the acceleration of the earth toward it when it accelerates toward the earth with 9.8m/s² is a = 7.35×10-²³m/s².

What is acceleration?

  Acceleration is defined as the second derivative of displacement or the derivative of velocity:

a = d/dt(dS/dt) = dV/st.

   It is the rate of change of velocity, it generates a constant change over time.

What are forces?

   Forces are the definition of Newton's second law, which is stated under the relation:

∑ Force = mass × acceleration.

  In other words, force is the origin of motion since it generates acceleration in a system.

   In this case we must complete the statement:

"A student with mass 45 kg jumps off a high diving board. Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it."

  We determine the Force of the student:

F = ma

F = 45kg * 9.8m/s².

F = 441N

  Now we go to the acceleration of the earth:

a = F/m

a = 441N / 6×10²⁴ Kg

a = 7.35×10-²³m/s².

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The subatomic particles that are least massive and most massive respectively are the.

Answers

The subatomic particles that are least massive and most massive are the electron and neutron respectively.

Subatomic particles are defined as the elementary particles which make the fundamental constituents of all matter. The subatomic particles constitute the negatively charged electrons, the positively charged protons, and the neutral neutrons which do not have any charge on them.

Protons and neutrons on the other hand are made up of other elementary particles namely quarks. Subatomic particles have emerged a lot in the coming days with the construction of particle accelerators.

The electron is the least massive subatomic particle. It carries a negative charge of 1.602176634 × 10^−19 coulomb which is about 0.000548 amu.

Neutron is the heaviest subatomic particle having a mass of about 1.008 amu.

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The rest energy of an electron is 0.511MeV. The rest energy of a proton is 938MeV. Assume both particles have kinetic energies of 2.00MeV. Find the speed of(d) Repeat the calculations in parts (a) through (c) assuming both particles have kinetic energies of 2000MeV

Answers

Answer:

The speed of the electron is 0.98c, given that the rest energy of an electron is 0.511MeV and the rest energy of a proton is 938MeV, with both particles having kinetic energies of 2.00MeV.

Explanation:

A particle's total energy and the rest energy follow the laws of physics and the theory of relativity. The energy of any particle is equal to mass times the speed of the light-squared relatively.

Where;  E=γ.〖mc〗^2

γ is the ratio of total energy to rest energy of the particle.

m_0 is known as the rest mass of the particle.

Rest energy can be written as: E_0=〖m_0 c〗^2

γ=K/E_0 +1         (1)

γ=1/(√1-v^2/c^2)     (2)

Putting the values of the electron energy into equation (1):

γ=2.00MeV/0.511MeV+1

γ= 3.91 + 1

γ=4.91

From equation (2),

γ=1/(√1-v^2/c^2)

Squaring both sides of the equation,

γ^2=1/(1-v^2/c^2)

1/γ^2 =1-v^2/c^2  

v^2/c^2 =1-1/γ^2  

v/c=√1-1/γ^2    

Making v subject of the formula,

v=√1-1/γ^2 ×c    (3)

Inserting the values into Equation 3,

v=√1-1/〖4.91〗^2 ×c

v=√1-1/24.11×c

v=√0.959×c

v=0.98×c

v=0.98c

Therefore, the speed of the electron is 0.98c.

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A wire 2.80m in length carries a current of 5.00A in a region where a uniform magnetic field has a magnitude of 0.390T. Calculate the magnitude of the magnetic force on the wire assuming the angle between the magnetic field and the current is (b) 90.0° .

Answers

The force on the wire will be

F = 5.46 Newton.

We have a current carrying wire in a uniform magnetic field.

We have to determine the magnitude of the magnetic force on the wire assuming the angle between the magnetic field and the current is 60.0°.

What is the magnitude of force acting on a current (I) carrying wire of length (L) placed in a Magnetic field (B)?

The force on the current carrying wire will be -

F = IBL sinθ

According to the question, we have -

L = 2.80 m

I = 5 A

B = 0.39 T

Therefore -

F = IBL sinθ

F = 5 x 0.39 x 2.80 x sin(90)

F = 5.46 x sin(90)

F = 5.46 Newton

Hence, the force on the wire will be

F = 5.46 Newton

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The magnitude of the magnetic force on the wire 5.46 N.

To find the magnetic force, the values given are:

Length A = 2.80m

Current I = 5 A

Magnetic field B = 0.390 T

Angle = 90° .

What is meant by magnetic force?

The attraction or repulsion that arises between electrically charged particles because of their motion is called Magnetic force.Magnetic force is the basic force which is responsible for such effects as the action of electric motors and the attraction of magnets.A force experienced through the magnetic field with some moving charges is perpendicular to its own velocity.The formula to find the magnetic force,

                      F =iBLsinθ Newton

Substituting the values given,

Magnetic force,

F = 5 A × 0.390 T × 2.80 m × Sin 90°

  = 5 A × 0.390 T × 2.80 m × 1

F = 5.46 N.

The magnitude of the magnetic force on the wire 5.46 N.

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Owen and Dina are at rest in frame S' , which is moving at 0.600 c with respect to frame S . They play a game of catch while Ed , at rest in frame S , watches the action (Fig. P39.75). Owen throws the ball to Dina at 0.800 c (according to Owen), and their separation (measured in S' ) is equal to 1.80 × 10¹²m .(a) According to Dina, how fast is the ball moving?

Answers

The speed of the ball with respect to Dina is 0.800c.

A frame of reference is a set of reference points—geometric points whose positions are known mathematically and physically—that define the origin, orientation, and scale of an abstract coordinate system.

If a body does not continuously adjust its position in relation to its environment throughout the course of time, it is said to be at rest.

In frame S', Dina and Owen are at rest.

The speed of the ball with respect to Owen, u =0.800c

The speed of the frame S' with respect to frame S,  v = 0.600c

Distance between Dina and Owen, L(p) = 1.8 × 10¹² m

Speed of light, c = 3 × 10⁸ m/s

Therefore, the speed of the ball according to Dina is 0.800c. As Dina and Owen are in the same frame.

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A single-turn square loop of wire, 2.00 cm on each edge, carries a clockwise current of 0.200 A . The loop is inside a solenoid, with the plane of the loop perpendicular to the magnetic field of the solenoid. The solenoid has 30.0 turns/cm and carries a clockwise current of 15.0A . Find (a) the force on each side of the loop

Answers

The force on each side of the loop is [tex]2.26\times10^{-4}N[/tex] away from the centre .

Magnetic field at the centre of a solenoid of length 'L' having 'N' number of turns with a current 'I' is given by   [tex]B=\frac{u_0NI}{L}[/tex]   ...(1)  where [tex]u_0[/tex] is the permittivity of free space whose value is [tex]4\pi \times10^{-7}Tm/A[/tex]  .Force due to current carrying wire 'I' in a magnetic 'B' having length 'L' is given by [tex]F=BILsin\theta[/tex]     ...(2) where θ is the angle between current and length of the wire .

It is given that solenoid has 30.0 turns/cM which means we have given number of turns per unit length [tex]n=\frac{N}{L} =30\times10^{2}m[/tex] and carries a clockwise current of 15.0A .

Putting above values in equation (1) , we get

[tex]B=4\pi \times10^{-7}\times 30\times10^{2} \times15.0\\B=0.0565T[/tex]

The magnetic force exerted due to their magnetic field on the sides of the loop will be away from the center of loop and is given by equation (2) .

It is given that current in the loop is  0.200 A and length of the each side of the loop is  2.00 cm [tex]=2\times10^{_2}m[/tex] and plane of the loop perpendicular to the magnetic field of the solenoid.

Putting above values in equation (2) , we get

[tex]F=0.0565\times0.2\times2\times10^{-2}\times sin90\\F=2.26\times10^{-4}N[/tex]

Direction of force is found by Fleming' Left Hand rule which states that when the thumb, index finger and middle finger of the left hand are placed perpendicular to each other,  the thumb points in the direction of the magnetic force, the index finger points in the direction of the magnetic field, and the middle finger points in the direction of the flow.

According to Fleming's left hand rule, the magnetic force exerted due to their magnetic field on the sides of the loop will be away from the center of loop and is given by equation (2) .

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Rank the wavelengths of the following quantum particles from the largest to the smallest. If any have equal wavelengths, display the equality in your ranking. (a) a photon with energy 3eV(b) an electron with kinetic energy 3eV(c) a proton with kinetic energy 3eV(d) a photon with energy 0.3eV(e) an electron with momentum 3eV/c

Answers

The wavelengths of the following quantum particles from the largest to the smallest is (d) > (a) = (e) > (b) > (c)

De Broglie proposed that because light has both wave and particle properties, matter exhibits both wave and particle properties. This property has been explained as the dual behavior of matter. From his observations, de Broglie derived the relationship between the wavelength and momentum of matter. This relationship is known as de Broglie's relationship.

De Broglie's relationship is given by  [tex]\lambda=\frac{h}{mv}[/tex] .

This can be written as [tex]\lambda=\frac{h}{p}[/tex]  .....(1) where λ  is known as de Broglie wavelength and p is momentum , h = Plank’s constant .

As we know that mass of proton is greater than electron and photon .

(a)For photon , the momentum is given by [tex]p=\frac{E}{c}[/tex]     ...(2)  where c is the speed is the speed of light .

Putting E = 3eV in equation (2) , we get

              [tex]p=\frac{3\times 1.6\times10^-^1^9}{3\times 10^8} \\p=1.6\times10^-^2^7Js/m[/tex]

Putting this value of p in equation (1) , we get

  [tex]\lambda=\frac{6.62\times10^{-34}}{1.6\times10^{-27}}\\\lambda=4.13\times10^{-7}[/tex]

(b) As we know that  kinetic energy is given by

         [tex]K.E=\frac{1}{2} mv^2\\\\2K.E = mv^2\\2K.E\times m = m^2v^2\\2K.E\times m = (mv)^2\\2K.E\times m = p^2\\\\\sqrt{2K.E\times m }=p[/tex]      ...(3)

Where mass of electron is [tex]9.1\times10^-^3^1 kg[/tex] .

Putting K.E = 3eV in equation (3) , we get

    [tex]\sqrt{2K.E\times m }=p\\p=\sqrt{2\times3\times1.6\times10^{-19} \times 9.31\times10^{-31} }\\p=\sqrt{89.376\times10^{-50}} \\p=9.45\times10^{-25}Js/m[/tex]

Putting this value of p in equation (1) , we get

[tex]\lambda=\frac{6.62\times10^{-34}}{9.45\times10^{-25}}\\\lambda=0.7005\times10^{-9}[/tex]

(c) Putting [tex]m=1.67\times10^{-27}kg[/tex] and K.E = 3eV in equation (3) , we get

     [tex]\sqrt{2K.E\times m }=p\\p=\sqrt{2\times3\times1.6\times10^{-19} \times 1.67\times10^{-27} }\\p=\sqrt{16.032\times10^{-46}} \\p=4.003\times10^{-23}Js/m[/tex]

Putting this value of p in equation (1) , we get

[tex]\lambda=\frac{6.62\times10^{-34}}{4.003\times10^{-23}}\\\lambda=1.65\times10^{-11}[/tex]

(d) Putting E = 0.3eV in equation (2) , we get

   [tex]p=\frac{0.3\times 1.6\times10^-^1^9}{3\times 10^8} \\p=1.6\times10^-^2^8Js/m[/tex]

Putting this value of p in equation (1) , we get

[tex]\lambda=\frac{6.62\times10^{-34}}{1.6\times10^{-28}}\\\lambda=4.13\times10^{-6}[/tex]

(e) Putting [tex]p=3eV/c[/tex] in equation (1) , we get

    [tex]\lambda=\frac{6.62\times10^{-34}\\\times3\times10^8}{3\times1.6\times10^{-19}}\\\lambda=4.13\times10^{-7}[/tex]

On comparing the wavelength order should be (d) > (a) = (e) > (b) > (c) .

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A 100kg box is on an incline of 60 degrees. What is the perpendicular force

Answers

Answer:

490N

Explanation:

the formula to use for perpendicular force is:

[tex]Fg=mg(cos\theta)[/tex]  

now we plug in:

*for g, it can be 9.8 m/s^2 or 10 m/s^2 depending on your teacher

[tex]Fg=(100)(9.8)(cos60)[/tex]

then you get:

[tex]Fg=490N[/tex]

a spring is compressed by 1 cm when a force of 5.0N is applied. what is the potential energy stored in the spring when it is compressed by 10.cm

Answers

The potential energy stored in the spring is 0.025 J.

What is potential energy stored in a spring?

This is the energy stored in a spring when its is stretched or compressed through a certain length.

To calculate the potential energy stored in a spring, we use the formula below.

Formula:

E = Fe/2............... Equation 1

Where:

E = Potential energy of the springF = Force applied to the springe = Extension or Compression

From the question,

Given:

F = 5 Ne = 1 cm = 0.01 m

Substitute these values into equation 1

E = 5×0.01/2E = 0.025 J

Hence, the potential energy stored in the spring is 0.025 J.

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Help me to answer this..​
Click the picture to see the full question.

Answers

Explanation:

Newton second law of motion

Please someone help me.
is the block of wood at rest or in motion?
refer to the figure below draw the forces acting on the block of wood use the gas as the origin of the forces.

thank you very much for answering this.​

Answers

Answer:

1)  The block of wood is at rest.

2)  Weight and Normal Reaction (see attached diagram).

Explanation:

Assumptions

The block of wood is a particle (a body whose mass acts at a point, so its dimensions don't matter).There are no other external forces involved.

Question 1

"At rest" or "resting" means that the object isn't moving.

Therefore, the block of wood is at rest.

Question 2

Forces that are acting on the block of wood:

Weight (W):  Due to the particle's mass, m, and the acceleration due to gravity, g:  W = mg
(Weight always acts downwards).Normal Reaction (R or N):  The reaction from a surface.
(Normal Reaction is always at 90° to the surface).

See attached diagram.

An amusement park designer wants his swing to have a centripetal
acceleration of 21 m/s2. If the velocity of the swing is 13 m/s, how long
should the chain on the swing be?

Answers

The chain on the swing should be 8.0 m long .

Centripetal Acceleration ( a ) = v ² / r ........... Eq. 1

It is given that ,

a = 21 m / s ²

v = 13 m / s

Now ,  using the values of ' a ' and ' v ' i.e. 21 m / s ² & 13 m / s respectively in Eq. 1

a =  v ² / r

21 = ( 13 ) ² / r

21 = ( 13 x 13 ) / r

r = ( 13 x 13 ) / 21

r = 8.047 m

⇒ r = 8.0 m ( rounded off to nearest tenth )

Hence , the chain on the swing should be 8.0 m long .

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velocity changes from 2m/s to 12m/s time taken is 5 seconds (with the guess method pleasee)

Answers

Answer:

a  = 2 m/c²

Explanation:

Given:

V₁ = 2 m/s

V₂ = `12 m/s

t = 5 c

______________

a -?

Acceleration:

a = ( V₂ - V₁) / t

a = ( 12 - 2 ) / 5 = 10 / 5 = 2 m/c²

How much kinetic energy does a 3.50kg block with a speed of 4.00m/s have?

Answers

Taking into account the definition of kinetic energy, the kinetic energy of a 3.50kg block with a speed of 4.00 m/s is 28 J.

Definition of kinetic energy

Kinetic energy is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.

In other words, kinetic energy is defined as the amount of work necessary to accelerate a body of a certain mass and in a position of rest, until it reaches a certain speed.

Kinetic energy is represented by the following expression:

Ec = 1/2×m×v²

where:

Ec is kinetic energy, which is measured in Joules (J). m is mass measured in kilograms (kg).v is velocity measured in meters over seconds (m/s).

Kinetic energy in this case

In this case, you know:

m= 3.50 kgv= 4 m/s

Replacing in the definition of kinetic energy:

Ec = 1/2× 3.50 kg× (4 m/s)²

Solving:

Ec= 28 J

Finally, the kinetic energy of a 3.50kg block with a speed of 4.00 m/s is 28 J.

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the coefficient of performance of a residential heat pump is 1.6. calculate the heating effect in kj/s this heat pump will produce when it consumes 2 kw of electrical power.

Answers

The heating effect in with the residential heat pump will be  3.2 KJ/s

Heat pump - mechanical device which convert heat from low temperature to high temperature reservoir with the use of external work.

Heating effect - it is the change of electrical energy which passes through the conductor into heat energy.

The rate of heat produced. [tex]Q_{H}[/tex] is calculated by

The coefficient of residential heat pump = 1.6

The consume of electric power = 2kw

The rate of heat produced.( [tex]Q_{H}[/tex]) =

The coefficient of performance × consume of electric power

[tex]Q_{H}[/tex] = 1.6 × 2

= 3.2 KJ/s

The heating effect in with the residential heat pump will be  3.2 KJ/s

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which of these statements about density is true? group of answer choices the density of an object depends on the force of gravity. density does not depend on temperature. density is a physical property. larger objects are more dense.

Answers

The statement about density that is true is: density is a physical property

The density of an object is the relation that exist between the mass and the space that the object occupies. The general formula of the density is:

ρ = m/v

Where:

v= volumeρ= densitym= mass

For example if we want to know which is the density of a body that has a mass of 100g and a volume of 150 cm³, applying the density formula we get:

ρ = 100 g/150 cm³

ρ = 0.666 g/cm³

What is density?

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

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list 5 example where pivot is present​

Answers

The five examples where pivot can be seen include the following: 1. Nut Cracker · 2. Seesaw · 3. Scissors · 4. Plier · 5. Stapler

What is a pivot?

A pivot is the fulcrum of a simple machine that serves as a point in the machine that allows for easy movement when force of load or effort is being applied at either ends.

The pivot can eithe be located at the either ends of the simple machine or at the middle of the simple machine.

Typical examples of machines that has pivot include the following:

Nut Cracker,

Seesaw,

Scissors,

Plier, and

Stapler.

From the examples listed above, the pivot of nutcracker and stapler are located at its end while the pivot of seesaw, scissors and pliers are located at the middle.

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who is Isacc.Newton??​

Answers

Answer:

Sir Isaac Newton contributed significantly to the field of science over his lifetime. He invented calculus (opens in new tab) and provided a clear understanding of optics. But his most significant work had to do with forces, and specifically with the development of a universal law of gravitation and his laws of motion

Explanation:

A genius with dark secrets. Isaac Newton changed the way we understand the Universe. Revered in his own lifetime, he discovered the laws of gravity and motion and invented calculus. He helped to shape our rational world view.

13. Two identical metallic spheres A and B, each carry- ing a charge q, repel each other with a force F. A third metallic sphere C of the same size, but un- charged, is successively made to touch the spheres A and B, and then removed away. What is the force of repulsion between A and B? (Ans. 3F/8) 4.​

Answers

Answer:

Who knows the answer please I need the answer

What is the mass of a rocket 5,000m above the Moon’s surface if 84kJ
of gravitational potential energy is stored? Assume g on the Moon =
1.63N/kg.

Answers

Considering the definition of potential energy, the mass of a rocket 5,000 m above the Moon’s surface is 10.31 kg.

Potential energy

Potential energy is the energy that measures the ability of a system to do work based on its position. In other words, this is the energy that a body located at a certain height above the ground has.

Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the strength of gravity. Then, the expression applied to the gravitational energy of the object is:

Ep= m×g×h

Where:

Ep is the potential energy in joules (J).m is the mass in kilograms (kg). h is the height in meters (m).g is the acceleration of the fall in m/s².

Mass of the rocket

In this case, you know:

Ep= 84 kJ= 84,000 J (being 1 kJ= 1,000 J)m= ?h= 5,000 mg= 1.63 N/kg= 1.63 m/s²

Replacing in the definition of gravitational potential energy:

84,000 J= m×1.63 m/s²×5,000 m

Solving:

84,000 J= m× 8,150 m/s²×m

84,000 J÷ (8,150 m/s²×m)= m

10.31 kg= m

Finally, the mass of a rocket 5,000 m above the Moon’s surface is 10.31 kg.

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Which two types of potential energies would be types of mechanical energies?

electrical and kinetic
nuclear and chemical
radiant and thermal
elastic and gravitational

Answers

The two types of potential energies which would be types of mechanical energies are elastic and gravitational.

The correct answer choice is option D

What is meant by potential energy?

Potential energy means the energy a body possess in relation to its position. Other forms of energy include

Electrical energyKinetic energyChemical energySound energyNuclear energy Thermal energy Radiant energy

Kinetic energy is the energy a body possesses due to its motion.

So therefore, the two types of potential energies which would be types of mechanical energies are elastic and gravitational. The correct answer choice is option D

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Answer: it is d

Explanation: i took the unit test on edge

What is inertia and how does it relate to Newton's first law of motion?

Answers

Answer:

inertia is basically the fact that something will continue moving until something else stops it.  take friction for example.  If you roll a ball on the ground, it will eventually stop because of friction, you can kind of think of it like a gear wheel.  and i guess it relates to newtons first law of motion because it is his first law?? i don't know how to answer that

Explanation:

three scientists measure the standard meter bar kept at the international bureau of standards (the definition of a meter). their measurements are 1.01 m, 0.99 m, and 1.00 m. are their measurements accurate, precise, or both? group of answer choices accurate but not precise neither accurate nor precise precise by not accurate accurate and precise

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The measurements by the different scientists were 1.01 m, 0.99 m and 1.00 m,  which are not exactly same as the standard value of a meter. But all the three values are very much close to each other.

Meter is a fundamental unit of length in the metric system and in the International Systems of Units (SI). It is denoted by m.

Therefore the measurements for the bar kept at the international bureau of standards taken by the three scientists were precise but not accurate.

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Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it.

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   The value of the acceleration of the earth toward it when it accelerates toward the earth with 9.8m/s² is a = 7.35×10-²³m/s².

What is acceleration?

  Acceleration in theoretical terms refers to the derivative of the velocity function, it is the rate of change of this variable, and the physical magnitude of the motion that gives rise to the change of position.

What are forces?

   Forces are the definition of Newton's second law, which is stated under the relation:

∑ Force = mass × acceleration.

  In other words, force is the origin of motion since it generates acceleration in a system.

   In this case we must complete the statement:

"A student with mass 45 kg jumps off a high diving board. Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it."

  We determine the Force of the student:

F = ma

F = 45kg * 9.8m/s².

F = 441N

  Now we go to the acceleration of the earth:

a = F/m

a = 441N / 6×10²⁴ Kg

a = 7.35×10-²³m/s².

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Q|C A large set of unoccupied football bleachers has solid seats and risers. You stand on the field in front of the bleachers and sharply clap two wooden boards together once. The sound pulse you produce has no definite frequency and no wavelength. The sound you hear reflected from the bleachers has an identifiable frequency and may remind you of a short toot on a trumpet, buzzer, or kazoo.(d) the duration of the sound on the basis of data you specify.

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As a result, it is a noise without a pitch or wavelength. When the time comes, part of it is incidental and radiates away from you in all directions.

Following that, there is a temporal delay of 60 cm, or 0.6 m divided by 340 m/s, or 0.002 seconds. This is the amount of time it takes for the sound impulse to travel from one riser to the next. Any material will now reflect a significant portion of the sound that reaches it, and the reflected wave will sound substantially different from the shop. first sound. If there are 20 rows of seats and you hear a tone with 20 crests coming from the stands,

What is sound pulse?

We are informed about this sound wave problem that a loud, sharp sound is produced in the middle of a field in an empty stadium. We hear an echo with a distinct pitch but no frequency or Waveland in the pulse.

Now that the sound has been accounted for, we need to estimate its frequency, wavelength, and duration in terms of orders of magnitude. We will now graph the air pressure versus time and model the Lord Sharp sound impulse as a single narrow peak.

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when driving downhill, gravity will cause you to go slower and decrease your stopping distance. a. true b. false

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False.While driving downhill, the gravity will cause you to go faster and increase your stopping distance.

What is stopping distance?

Brakes are suddenly applied while the body is travelling at a given speed. You would have observed that after travelling a given distance, the body stops entirely. The stopping distance is that distance.

The distance travelled between the moment the body decides to stop a moving vehicle and the moment the vehicle comes to a complete stop is known as the stopping distance. The stopping distance, indicated by the letter d, is dependent on a number of variables, including as the road's surface and the driver's reflexes.

Stopping Distance formula is given by,

[tex]d=\frac{v^{2} }{2ug}[/tex]

Where,

d = stopping distance (m)

v = velocity (m/s)

μ = friction coefficient

g = the gravitational acceleration

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