Can someone please help, ty!!
Will mark brainliest.

Answer:

Isabella will not be able to spray Ferdinand.

Explanation:

We'll begin by calculating the time taken for the water to get to the ground from the hose held at 1 m above the ground. This can be obtained as follow:

Height (h) = 1 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =.?

h = ½gt²

1 = ½ × 9.8 × t²

1 = 4.9 × t²

Divide both side by 4.9

t² = 1/4.9

Take the square root of both side

t = √(1/4.9)

t = 0.45 s

Next, we shall determine the horizontal distance travelled by the water. This can be obtained as follow:

Horizontal velocity (u) = 3.5 m/s

Time (t) = 0.45 s

Horizontal distance (s) =?

s = ut

s = 3.5 × 0.45

s = 1.58 m

Finally, we shall compare the distance travelled by the water and the position to which Ferdinand is located to see if they are the same or not. This is illustrated below:

Ferdinand's position = 10 m

Distance travelled by the water = 1.58 m

From the above, we can see that the position of the water (i.e 1.58 m) and that of Ferdinand (i.e 10 m) are not the same. Thus, Isabella will not be able to spray Ferdinand.

Answer: Examples of conductors include metals, aqueous solutions of salts (i.e., ionic compounds dissolved in water), graphite, and the human body. Examples of insulators include plastics, Styrofoam, paper, rubber, glass and dry air.

Answer:

t = 5.88 10⁻² s

Explanation:

The speed of the sound wave after it is emitted by the bat is constant, so we can use the uniform motion relationships

          v = [tex]\frac{x}{t}[/tex]

          t = [tex]\frac{x}{v}[/tex]

in this case the distance is that of the sound in going from the bat to the insect and back

         x = 2d

         x = 2 10

         x = 20 m

let's calculate

        t = 20/340

        t = 5.88 10⁻² s

We can see that the time is very short, so the distance traveled by the two animals has little influence on the result.

Answer:

X axis   F=0

Y axis    Fg = - 2.94 j ^

Explanation:

The motion of a ball in air where the air residence is indicated to be negligible can be analyzed using Newton's second law.

We set a reference system, where the x-axis is horizontal and the y-axis vertical.

X axis

There are no forces on this axis, therefore the ball goes at constant speed.

Force is zero

Y axis  

In this axis it is subjected to the acceleration of gravity that creates a force equal to the weight of the body, in a vertical direction.

           Fg = m g

           Fg = 0.3 9.8

           Fg = 2.94 N

           Fg = - 2.94 j ^

the boold are vectors; negative sign indicates that the force eta directed vertically downward

Answer:

It's A. White light is made up of many different wavelengths of light.

Answer:

the Potential Energy is 2.304 × 10⁻¹⁶ J

Explanation:  

Given the data in the data in the question;

The expression for the electric potential energy between the charges can be expressed as follows;

PE = qV ------equ 1

where q is the charge and V is the electric potential

Also the formula for electric potential due to point a point in a field is;

V = kq /  r -------equ 2

where k is the electrostatic constant and r is the distance form the charged particle

input equation 2 into 1

PE = q × kq /  r

PE = kq²/r ------- equ 3

so we substitute into equation 3; 1.00×10⁻¹² for r, 9.00×10⁹ for k( constant ) and 1.60×10⁻¹⁹ for q( charge )

PE = ((9.00×10⁹) (1.60×10⁻¹⁹)²) / 1.00×10⁻¹²

PE = 2.304 × 10⁻²⁸ / 1.00×10⁻¹²

PE = 2.304 × 10⁻¹⁶ J

Therefore, the Potential Energy is 2.304 × 10⁻¹⁶ J

Answer: the higher the kinetic energy

Explanation:

Answer:

d = 200 m

Explanation:

Data:

Use formula:

Replace:

Sum in the numerator:

It divides:

Simplify the seconds (s), and multiply:

How far does it go?

Travel a distance of 200 meters.

Answer:

1. positive acceleration represents an object speeding up; negative acceleration represents an object slowing down

Explanation:

Acceleration is clearly defined as the rate of change of velocity with time. When are body is speeding up as we say, it is accelerating. When a body is coming to rest, it is decelerating.

Positive acceleration occurs when the speed of a moving continues to increase.

Negative acceleration is when the speed of a moving body reduces drastically.

Answer:

Ep = 117600 J

Explanation:

Data:

Use formula:

Replace:

Multiply operations, and units:

What is the potential energy?

The potential energy is 117600 Joules.

The force formula can be rewritten  to solve the acceleration as:

acceleration = force/mass.

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

From Newton's 2nd law of motion, we can write that:

Force = mass × acceleration

⇒ acceleration = force/mass.

Hence, the force formula can be rewritten  to solve the acceleration as:

acceleration = force/mass.

Learn more about acceleration here:

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Answer:

the work done by the field is positive and the potential energy of the electron field system decreases

Explanation:

This exercise asks to find the work and the potential energy of an electron in an electric field.

Work is defined by

         W = F .d = F d cos θ

the electric force is

          F_e = q E

         W = q E d cos θ

since the charge of the electron is negative the force is in the opposite direction to the electric field

          W = - e E d

we select the direction to the right is positive, point i is to the left of point f,

therefore the work moving from point i to point F has two possibilities

* The electric field lines go from i to f point , so that point i is on the side of the positive charges, so the electron approaches them, This movement is opposite to that indicated

* the field line reaches point i, this implies that the charges are negative, so the electrioc field is then negativeand the electron charge is negative too.  The electron moves away from this point, this is in accordance with the indicated movement

In the latter case the electric field lines go from f to i point, therefore the Work is positive

Now let's examine the potential energy

            ΔU = - q E .d

so we see that this definition is related to work,

            ΔU = -W

Therefore, as the work is positive, the power energy must decrease

When reviewing the different answers, the correct ones are:

the work done by the field is positive and the potential energy of the electron field system decreases

The work done by the electron while moving from point [tex]i[/tex] to point [tex]f[/tex] in the direction of uniform electric field is negative and the potential energy of the electron increases.

An electron moves from point i to point f, in the direction of a uniform electric field, then  the potential energy of the electron can be calculated s given below.

[tex]\Delta V=-qEd[/tex]

Where [tex]\Delta V[/tex] is the potential energy, [tex]E[/tex] is the electric field, [tex]q[/tex] is the charge and [tex]d[/tex] is the displacement of the electron.

The work done by the electron in the uniform electric field can be calculated as,

[tex]W = F\times d \times cos\theta[/tex]

Where [tex]W[/tex]is the work done by electron, [tex]F[/tex] is the electric force, [tex]d[/tex] is the displacement of the electron and  for uniform electric field, the value of [tex]\theta[/tex] is zero.

Hence  [tex]W=F\times d\times 1\\W=F \times d[/tex]

Electric force  [tex]F = q E[/tex]

By substituting the value of electric force on the above formula,

[tex]W = qEd[/tex]

Hence, the relation between the work done the electron in an uniform electric field and potential energy of the electron can be given below.

[tex]W = -\Delta V[/tex]

The work done by the electron is negative and the potential energy of the electron increases.

For more information, follow the link given below.

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Answer:

the radius of curvature of the track for this instant is 266 m

Explanation:

Given that;

The Initial Velocity u = 100 km/h = 100 × [tex]\frac{5}{18}[/tex] = 27.77 m/s

velocity of the train at t=12 s is;

[tex]V_{t=12}[/tex] = 50 km/h = 50 × [tex]\frac{5}{18}[/tex] = 13.89 m/s

now, we calculate the deceleration of the train

[tex]V_{t=12}[/tex]  = u + at

13.89 = 27.77 + [tex]a_{t}[/tex]12

[tex]a_{t}[/tex] = (13.89 - 27.77) / 12

[tex]a_{t}[/tex] = -13.88 / 12

[tex]a_{t}[/tex] = - 1.1566 m/s²

Now, the velocity of the train at 6 seconds is;

[tex]V_{t=6}[/tex]  = u + at

[tex]V_{t=6}[/tex]  = 27.77 + ( - 1.1566 m/s²)6

[tex]V_{t=6}[/tex]  = 27.77 - 6.9396

[tex]V_{t=6}[/tex]  = 20.83 m/s

The acceleration at t=6 s is;

a = √[ ([tex]a_{t}[/tex] )² + ([tex]a_{n}[/tex])²]

a = √[ ([tex]a_{t}[/tex] )² + ([tex]a_{n}[/tex])²]

we substitute

2m/s² = √[ (- 1.15 )² + ([tex]a_{n}[/tex])²]

4 = (- 1.1566 )² + ([tex]a_{n}[/tex])²

4 = 1.3377 +  ([tex]a_{n}[/tex])²

([tex]a_{n}[/tex])² = 4 - 1.3377

([tex]a_{n}[/tex])² = 2.6623

[tex]a_{n}[/tex] = √2.6623

[tex]a_{n}[/tex]  = 1.6316 m/s²

Now the radius of curve is;

a = V² / p

[tex]p_{t=6}[/tex] = ( [tex]V_{t=6}[/tex] )² /  [tex]a_{n}[/tex]

[tex]p_{t=6}[/tex] = ( 20.83 m/s )² /  1.6316 m/s²

[tex]p_{t=6}[/tex] = 433.8889 / 1.6316

[tex]p_{t=6}[/tex] = 265.9 m ≈ 266 m

Therefore;  the radius of curvature of the track for this instant is 266 m

Answer:

(a) The negative charge on one of the charges is -8.79630245 × 10⁻⁷C

(b) The positive charge on one of the other charges is 8.79630245 × 10⁻⁷C

Explanation:

The given parameters are;

The force of attraction between the two spheres = 0.0988 N

The distance between their centers = 44.5 cm = 0.445 m

Therefore, we have;

[tex]F = \dfrac{k \cdot q_1 \cdot q_2}{d^2}[/tex]

Therefore, we have;

[tex]0.0988 \ N = -\dfrac{8.99 \times 10^9 N\cdot m^2 \cdot C^{-2}\cdot q_1 \cdot q_2}{(0.445 \ m)^2}[/tex]

Therefore, we have;

q₁·q₂ = -0.0988 N × (0.445 m)²/(8.99 × 10⁹ N·m²·C⁻²) = -2.17629255 × 10⁻¹² C²

q₁·q₂ = -2.17629255 × 10⁻¹² C²...(1)

When the two charges are connected, we get;

[tex]F_2 = \dfrac{k \cdot \left (\dfrac{q_1 + q_2}{2} \right) ^2}{d^2}[/tex]

Therefore, we have;

[tex]q_1 + q_2 = \sqrt{\dfrac{4 \cdot F_2 \cdot d^2}{k} }[/tex]

[tex]q_1 + q_2 = \sqrt{\dfrac{4 \times 0.0276 \ N \times(0.445 \ m)^2}{8.99 \times 10^9 N\cdot m^2 \cdot C^{-2}} } = 1.59446902743 \times 10^{-6} \ C[/tex]

q₁ + q₂ = 1.59446902743 × 10⁻⁶ C...(2)

From, equation (2), we have;

q₁ = 1.59446902743 × 10⁻⁶ C -  q₂

Plugging in the value of q₁ in equation (1) givens;

q₁·q₂ = -2.17629255 × 10⁻¹²

Therefore, we have;

(1.59446902743 × 10⁻⁶ -  q₂) × q₂ = -2.17629255 × 10⁻¹²

Which gives;

-q₂² + 1.59446902743 × 10⁻⁶·q₂+2.17629255 × 10⁻¹² = 0

Solving, with a graphing calculator, we get;

q₂ = 2.4741×10⁻⁶ C, or -8.79630245 × 10⁻⁷C

q₁ = 8.79630245 × 10⁻⁷C or -2.4741×10⁻⁶ C

Therefore, we have;

(a) The negative charge on one of the charges = -8.79630245 × 10⁻⁷C

(b) The positive charge on one of the other charges = 8.79630245 × 10⁻⁷C

Answer:

There is net loss of gravitational energy .

Explanation:

When Xanaxa is on the ground , her potential energy is assumed to be zero . When she leaps to a height of 153 m , she gains gravitational energy . When she dives and reaches the surface , she loses potential energy and on reaching the ground her potential energy becomes zero . When she further goes down inside ground to a depth of 17.5 m , she loses potential energy further . Her potential energy becomes less than zero or negative .

Ultimately her potential energy changes from zero to negative in the whole process . So there is net loss of potential energy .

Answer:

B

Explanation:

Friction is a force that opposes motion between any surfaces that are touching. Friction occurs because no surface is perfectly smooth Friction produces heat because it causes the molecules on rubbing surfaces to move faster and have more energy.

This question is incomplete, the complete question;

you make an interferometer using 50-50 beam splitter and two mirrors, one being a perfect mirror and one which does not reflect all light. The wavelength of the 9 mW incident laser is 400 nm.

Because the top mirror is not perfectly reflective (it reflects 90% of the photons, allowing 10% of them to go through), the power measured at the detector when only the vertical arm is blocked is 2.25 mW, while the power measured at the detector when only the horizontal arm is blocked is only 2.025 mW. Assume initially the intensity is at its maximum. How much would we need to translate the perfect mirror to the right to get a minimum intensity at detector, and what is that minimum intensity

Options;

a) 200 nm; 0.9 mW

b) 100 nm, 0.0059 mW

c) 200 nm; 0 mW

d) 100 nm; 0.9 mW

e) 200 nm; 0.0059 mW

Answer:

the amount we need to translate the perfect mirror to the right to get a minimum intensity at detector  and the minimum intensity are;

100 nm; 0.0059 mW

Option b) 100 nm, 0.0059 mW is the correct answer

Explanation:

Given that the instrument here is an interferometer.

Maximum intensity is obtained when the two waves are exactly in phase.

that is the peaks (crusts and troughs) and nodes (zero value points) of the two waves will be at the exact same point when the wave falls on the detector.

The phase factor of this point is taken as ∅ = 0

Now, to get a minimum point, the phase difference between the two waves should be should be ∅ = π

This corresponds to a path difference between the two waves as half of the wavelength. λ/2

The light gets reflected from the mirror.

Hence, when we move the mirror by a length l, the extra/less path the light has to travel is 2l (light is going and coming back)

hence, to get a path difference of λ/2 the mirror should move half of this distance only

so, the mirror should move;

[tex]l[/tex] = λ/4

here, wavelength is 400nm

the length moved by the mirror = 400/4 = 100 nm

The intensity is given by the equation;

[tex]l[/tex] = [tex]l[/tex]1 + [tex]l[/tex]2 + 2√[tex]l[/tex]1[tex]l[/tex]2cos(∅)

where

[tex]l[/tex]1 = 2.25 mW

[tex]l[/tex]2 = 2.025 mW

∅ = π

so we substitute

[tex]l[/tex] = 2.25 + 2.025 - 2√(2.25 × 2.025)

[tex]l[/tex] = 4.275 - 4.26907

[tex]l[/tex] = 0.0059

Therefore; the amount we need to translate the perfect mirror to the right to get a minimum intensity at detector  and the minimum intensity are;

100 nm; 0.0059 mW

Option b) 100 nm, 0.0059 mW is the correct answer  

Answer:

a=∆v/∆t

Explanation:

The definition of Acceleration is the change in velocity in a given time. So this means you first calculate ∆v (Change in velocity), and you calculate ∆t which is the time taken to apply that change in velocity. Then you find a= ∆v/∆t. This gives us the equation of Acceleration.

Answer:

Explanation:

Heart disease is the leading cause of death for both men and women. This is the case in the U.S. and worldwide. More than half of all people who die due to heart disease are men.

TRUE

Answer:

  t = 781.25 s

Explanation:

This is an exercise in velocity composition, if we set a reference system where the x-axis is perpendicular to the river and the y-axis is parallel to the river.

The swimmer has a velocity on the x axis

           vx = 1.60 m / s

a velocity on the y axis, created by the current of the river

           vy = 0.549 m / s

time is a scalar, therefore the time it takes to cross the river is the same time it creates the displacement in e; Axis y

X axis

            vₓ = x / t

            t = x / vₓ

            t = 1250 / 1.6

            t = 781.25 s

in this time a distance has descended

            y = v_y t

            y = 0.549 781.25

            y = 428.9 m

Answer:

Meandering valley like features on the Moon's surface are called rilles

Explanation:

NOUN

rilles (plural noun)

a fissure or narrow channel on the moon's surface.

Answer:

[tex]0.3\ \text{m}^3/\text{kg}[/tex]

[tex]36\ \text{kJ}[/tex]

[tex]18\ \text{kJ/kg}[/tex]

Explanation:

V = Volume of air = [tex]0.6\ \text{m}^3[/tex]

P = Power = 10 W

t = Time = 1 hour

m = Mass of air = 2 kg

Specific volume is given by

[tex]v=\dfrac{V}{m}\\\Rightarrow v=\dfrac{0.6}{2}\\\Rightarrow v=0.3\ \text{m}^3/\text{kg}[/tex]

The specific volume at the final state is [tex]0.3\ \text{m}^3/\text{kg}[/tex]

Work done is given by

[tex]W=Pt\\\Rightarrow W=10\times 60\times 60\\\Rightarrow W=36000\ \text{J}=36\ \text{kJ}[/tex]

The energy transfer by work, is [tex]36\ \text{kJ}[/tex]

Change in specific internal energy is given by

[tex]\Delta u=\dfrac{Q}{m}+\dfrac{W}{m}\\\Rightarrow \Delta u=0+\dfrac{36}{2}\\\Rightarrow \Delta u=18\ \text{kJ/kg}[/tex]

The change in specific internal energy of the air is [tex]18\ \text{kJ/kg}[/tex]

Answer:

Tt = 70 + 135e^-0.031t

13 minutes

Explanation:

Given that :

Initial temperature, Ti = 205°

Temperature after 2.5 minutes = 195°

Temperature of room, Ts= 70

Using the relation :

Tt = Ts + Ce^-kt

Temperature after time, t

When freshly poured, t = 0

205 = 70 + Ce^-0k

205 = 70 + C

C = 205 - 70 = 135°

T after 2.5 minutes to find proportionality constant, k

Tt = Ts + Ce^-kt

195 = 70 + 135e^-2.5k

125 = 135e^-2.5k

125 / 135 = e^-2.5k

0.9259 = e^-2.5k

Take In of both sides :

−0.076989 = - 2.5k

k = −0.076989 / - 2.5

k = 0.031

Equation becomes :

Tt = 70 + 135e^-0.031t

t when Tt = 160

160 = 70 + 135e^-0.031k

90 = 135e^-0.031t

90/135 = e^-0.031t

0.6667 = e^-0.031t

In(0.6667) = - 0.031t

−0.405465 = - 0.031t

t = 0.405465/ 0.031

t = 13.071

t = 13 minutes

Answer:

Part A: The speed the car should be travelling when leaping the river is approximately 37.948 m/s

Part B: The speed of the car just before it lands is approximately 41.92345 m/s

Explanation:

The parameters of the car attempting leaping the river are;

The height of the car over the river = 18 m

The height of the opposite side of the bridge above the river = 1.8 m

The width of the river, x = 69.0 m

Part A

The time, 't' it would take the car to fall from 18 m above the river to 1.8 m above the river is given as follows;

t = √(2·h/g)

Where;

h = The height of the fall = 18 m - 1.8 m = 16.2 m

g = The acceleration due to gravity = 9.8 m/s²

∴ t = √(2×16.2 m/(9.8 m/s²)) = (9/7)·√2 s

The horizontal speed, 'vₓ', with which the car should be travelling at the time it leaves the road in order just to clear the river and land safely on the opposite side is given as follows;

vₓ = x/t = 69.0 m/((9/7)·√2 s) = (161/6)·√2 m/s ≈ 37.948 m/s

The horizontal speed the car should be travelling when leaping the river, vₓ ≈ 37.948 m/s

Part B;

The vertical velocity of the car is given as follows;

[tex]v_y[/tex]² = [tex]u_y[/tex]² + 2·g·h

∴ [tex]v_y[/tex]² =2·g·h = 2 × 9.8 m/s² × 16.200 m = 317.52m²/s²

[tex]v_y[/tex] = √(317.52 m²/s²) = (63/5)·√2 ≈ 17.819 m/s

The magnitude of the speed of the car, 'v', just before it lands is given using Pythagoras' theorem for resultant vectors as follows;

v = √([tex]v_y[/tex]² + vₓ²) = √(317.52 m²/s² +((161/6)·√2 m/s)²) ≈ 41.92345 m/s

The speed of the car just before it lands, v ≈ 41.92345 m/s.

Answer:

D

Explanation:

A and C are balanced, B has a resultant force of 5N right, and D has a resultant force of 20N right.

Answer:

Electrons

Explanation:

Only Protons and Neutrons are found in the nucleus

Answer: On Earth, flowing of liquid metal in the outer core of the planet generates electric currents. The rotation of Earth on its axis causes these electric currents to form a magnetic field which extends around the planet.

Explanation:

Answer:

the rotation of earth on its axis causes electric currents to form a magnetic field which extends around the planet