Answer:
[tex]z=-1.28<\frac{a-23.1}{2.9}[/tex]
And if we solve for a we got
[tex]a=23.1 -1.28*2.9=19.388[/tex]
And for the 90 percentile we can do this:
[tex]z=1.28<\frac{a-23.1}{2.9}[/tex]
And if we solve for a we got
[tex]a=23.1 +1.28*2.9=26.812[/tex]
The P10 would be 19.388 and the P90 26.812
Step-by-step explanation:
Let X the random variable that represent the chocolate chip cookies of a population, and for this case we know the distribution for X is given by:
[tex]X \sim N(23.1,2.9)[/tex]
Where [tex]\mu=23.1[/tex] and [tex]\sigma=2.9[/tex]
For this part we want to find a value a, such that we satisfy this condition:
[tex]P(X>a)=0.90[/tex] (a)
[tex]P(X<a)=0.10[/tex] (b)
We can find a z score value who that satisfy the condition with 0.10 of the area on the left and 0.90 of the area on the right it's z=-1.28.
Using this value we can do this:
[tex]P(X<a)=P(\frac{X-\mu}{\sigma}<\frac{a-\mu}{\sigma})=0.10[/tex]
[tex]P(z<\frac{a-\mu}{\sigma})=0.10[/tex]
And we can solve for the value of interest
[tex]z=-1.28<\frac{a-23.1}{2.9}[/tex]
And if we solve for a we got
[tex]a=23.1 -1.28*2.9=19.388[/tex]
And for the 90 percentile we can do this:
[tex]z=1.28<\frac{a-23.1}{2.9}[/tex]
And if we solve for a we got
[tex]a=23.1 +1.28*2.9=26.812[/tex]
The P10 would be 19.388 and the P90 26.812
A type of friction that occurs when air pushes against a moving object causing it to negatively accelerate
Answer:
Air resistance
Step-by-step explanation:
Air resistance is a type of friction that occurs when air pushes against a moving object causing it to negatively accelerate
Answer:
Air resistance
Step-by-step explanation:
Air resistance is a type of friction that occurs when air pushes against a moving object causing it to negatively accelerate.
One angle of a right triangle measures 51 degrees. What is the measure of the other small angle?
Answer:
39 degrees
Step-by-step explanation:
Given
triangle is right angled i.e one angle is 90 degrees
other angle is 51 degrees.
let the third angle be x degrees
we know that sum of angles of any triangle is 180 degrees
thus,
90 + 51+ x = 180
=> 141 + x = 180
=> x = 180 - 141 = 39.
Thus, measure of other small angle is 39 degrees.
Answer:
Step-by-step explanation:
m∠A+m∠B+m∠C = 180
90+51+x1= 180
41+x=180
x=39
g Suppose you have $100 of endowment, and you are offered a chance to buy a lottery which costs $36. The lottery has 18% of chance to win a prize of $G, or you just lose and get nothing. Suppose your utility function on wealth is U(w)=\sqrt{w}. What is the least prize size G that you will be willing to buy the lottery?
Answer:
$301.23
Step-by-step explanation:
We have that the function of wealth is U (w) = w ^ (1/2)
So, since what you have at the start is 100, we replace:
U (w) = 100 ^ (1/2)
U = 10
Now we have two cases:
the first one we win, then the winnings would be 100 minus the cost of the lottery, that is 36 and to that add G of the prize:
100 - 36 + G = 64 + G
In the second case, where we lose, the subtraction of 100 that we have minus the cost of the lottery would be equal 36
100 - 36 = 64
Therefore, we have to win with an 18% probability, therefore losing would be 82% (100% - 18%)
0.18 * (64 + G) ^ (1/2) + 0.82 * 64 ^ (1/2)
solving:
0.18 * (64 + G) ^ (1/2) + 6.56
Now this is equal to U which is equal to 10:
10 = 0.18 * (64 + G) ^ (1/2) + 6.56
(10 - 6.56) /0.18 = (64 + G) ^ (1/2)
(64 + G) ^ (1/2) = 19.11
(64 + G) = 365.23
G = 365.23 - 64
G = 301.23
Therefore, the smallest G prize size that the lottery will be willing to buy is $ 301.23
Simon makes 30 cakes he gives 1/5 of the cakes to sali he gives 10 percent of the 30 cakes to jane what fraction of the 30 cakes does he have left
Answer:
7/10 or 70% left
Step-by-step explanation:
total cakes= 30
Gave to Sali
30*1/5= 6 cakesGave to Jane
30*1/10= 3 cakesCakes left:
30- (6-3)=21Cakes left fraction:
21/30= 7/10 or 70 %Answer:
7/10
Step-by-step explanation:
Cakes Simon gave to Sali = 30*1/5
= 6
Cakes Simon Gave to Jane = 30 * 1/10
= 3
Cakes left = 30 - (6-3)
= 21
21 cakes were left, so in terms of a fraction, it'd be 21/30, which can be reduced to 7/10
Hope this helps!
Identify the level of measurement of the data, and explain what is wrong with the given calculation. In a survey, the favorite sports of respondents are identified as 100 for basketball comma 200 for baseball comma 300 for football comma and 400 for anything else. The average (mean) is calculated for 597 respondents and the result is 256.1 .The data are at the _________________
level of measurement.
Answer:
The data are at the Nominal level of measurement.
The given calculation is wrong because average (mean) cannot be calculated for nominal level of measurement.
Step-by-step explanation:
The objective here is to Identify the level of measurement of the data, and explain what is wrong with the given calculation.
a)
The data are at the Nominal level of measurement due to the fact that it portrays the qualitative levels of naming and representing different hierarchies from 100 basketball, 200 basketball, 300 football, 400 anything else
b) We are being informed that, the average (mean) is calculated for 597 respondents and the result is 256.1.
The given calculation is wrong because average (mean) cannot be calculated for nominal level of measurement. At nominal level this type of data set do not measure at all , it is not significant to compute their average (mean).
what is the value of x?
Answer:
solution
Step-by-step explanation:
x=5
y=4
A commuter train travels 65 kilometers in 27 minutes. What is it’s speed in kilometers per hour?
Answer:
Per hour: 2.40740740741
Step-by-step explanation:
you have to divided 65 and 27 so
65/27
which is 2.40740740741
Consider the following.x = t − 2 sin(t), y = 1 − 2 cos(t), 0 ≤ t ≤ 8πSet up an integral that represents the length of the curve.8π0 dtUse your calculator to find the length correct to four decimal places.
The length of the parametric curve (call it C ) is given by
[tex]\displaystyle\int_C\mathrm ds=\int_0^{8\pi}\sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt[/tex]
We have
[tex]x=t-2\sin t\implies\dfrac{\mathrm dx}{\mathrm dt}=1-2\cos t[/tex]
[tex]y=1-2\cos t\implies\dfrac{\mathrm dy}{\mathrm dt}=2\sin t[/tex]
Now,
[tex]\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2=5-4\cos t[/tex]
so that the arc length integral reduces to
[tex]\displaystyle\int_0^{8\pi}\sqrt{5-4\cos t}\,\mathrm dt[/tex]
which has an approximate value of 53.4596.
Hello! I'm stuck on this problem. Can someone help me? Thanks!
The model below represents an equation.
2 long x tiles and 3 square 1 tiles = 3 long x tiles
Which represent like terms in the model of the equation?
2 long x tiles and 3 square 1 tiles
2 long x tiles and 3 long x tiles
3 long x tiles and 3 square 1 tiles
1 long x tile and 1 square 1 tile
Answer:
Answer is B
Step-by-step explanation:
This is because you can combine both the green tiles. With the other options, you can't combine them.
(also I did the test )
Answer:
The answer is in ur head lololol
Step-by-step explanation:
Its b
Any help would be appreciated
Answer:
increase 40
% increase is 40 %
Step-by-step explanation:
Take the new amount and subtract the original amount
140-100 = 40
Divide by the original amount
40/100
.40
Multiply by 100 %
40%
The percent increase is 40%
The amount of coffee that people drink per day is normally distributed with a mean of 17 ounces and a standard deviation of 4 ounces. 15 randomly selected people are surveyed. Round all answers to 4 decimal places where possible.
a) What is the distribution of XX? XX ~ N(,)
b) What is the distribution of ¯xx¯? ¯xx¯ ~ N(,)
c) What is the probability that one randomly selected person drinks between 15.5 and 18 ounces of coffee per day?
d) For the 15 people, find the probability that the average coffee consumption is between 15.5 and 18 ounces of coffee per day.
e) For part d), is the assumption that the distribution is normal necessary? YesNo
f) Find the IQR for the average of 15 coffee drinkers.
Q1 = ounces
Q3 = ounces
IQR: ounces
Answer:
Step-by-step explanation:
(a)
The distribution of X is Normal Distribution with mean [tex]= \mu =17[/tex] and Variance [tex]= \sigma^{2} = 16 \ i.e., X \sim N (17, 16),[/tex]
(b)
The distribution of [tex]\bar{x}[/tex] is Normal Distribution with mean [tex]= \mu =17[/tex] and Variance = [tex]\sigma^{2}/n = 16/15= 1.0667[/tex].i.e., [tex]\bar{x}\sim N(17,1.0667)[/tex]
c)
To find P(15.5 < X < 18):
Case 1: For X from 15.5 to mid value:
Z = (15.5 - 17)/4 = - 0.375
Table of Area Under Standard Normal Curve gives area = 0.1480
Case 2: For X from mid value to 18:
Z = (18 - 17)/4 = 0.25
Table of Area Under Standard Normal Curve gives area = 0.0987
So,
P(15.5 < X< 18) = 0.1480 +0.0987 = 0.2467
So,
Answer is:
0.2467
(d)
[tex]SE = \sigma/\sqrt{n}\\\\= 4/\sqrt{15}[/tex]
= 1.0328
To find [tex]P(15.5 < \bar{x}< 18):[/tex]
Case 1: For [tex]\bar{x}[/tex] from 15.5 to mid value:
Z = (15.5 - 17)/1.0328 = - 1.4524
Table of Area Under Standard Normal Curve gives area = 0.4265
Case 2: For X from mid value to 18:
Z = (18 - 17)/1.0328 = 0.9682
Table of Area Under Standard Normal Curve gives area = 0.3340
So,
[tex]P(15.5 < \bar{x}< 18) = 0.4265 + 0.3340 = 0.7605[/tex]
So,
Answer is:
0.7605
(e)
Correct option:
No
because Population SD is provided.
(f)
(i)
Q1 is given by:
[tex]- 0.6745 = (\bar{x} - 17)/1.0328[/tex]
So,
X = 17 - (0.6745 * 1.0328) = 17 - 0.6966 = 16.3034
So,
Q1 = 16.3034
(ii)
Q3 is given by:
[tex]0.6745 = (\bar{x} - 17)/1.0328[/tex]
So,
X = 17 + (0.6745 * 1.0328) = 17 + 0.6966 = 17.6966
So,
Q3= 17.6966
(iii)
IQR = Q3 - Q1 = 17.6966 - 16.3034 = 1.3932
So
Answers are:
Q1 = 16.3034 ounces
Q3 = 17.6966 Ounces
IQR = 1.3932 Ounces
An employee wants to invest $50,000 in a pension plan. One investment offers 6% compounded quarterly. Another offers 5.75% compounded continuously.
(a) Which investment will ear more interest in 5 yr?
(b) How much more will the better plan earn?
Answer:
a. 6% one is better
b. $12,285.95
Step-by-step explanation:
a. For determining which investment earn more first we have to calculate both the investment which are as follows
a. Based on compound quarterly, the amount is find out by using the following formula
[tex]Amount = {Present\ value\times (1 + interest\ rate)} ^{number\ of\ years}[/tex]
where,
Present value is $50,000
Interest rate is = [tex]\frac{0.06}{4}[/tex] = 0.015
And, the number of years is
= [tex]4\times4[/tex]
= 16
So, the amount is
[tex]= \$50,000 \times (1 + 0.015)^{16}[/tex]
= $63,449.28
And, based on compounded continuously, the amount is determined by using the following formula
[tex]Amount = Present\ value\times e^{rt}[/tex]
[tex]= \$50,000 \times e.^{0575(4)}[/tex]
= $51,163.33
Therefore, The the investment at 6% is better
b. Now the difference in earning is
= $63,449.28 - $51,163.33
= $12,285.95
what is the value of x?
Answer:
x = 5
Step-by-step explanation:
52 = y since they are the base angles of an isosceles triangle and the base angles are equal
The sum of the angles of a triangle are 180
52+y+14x+6 =180
Substitute for y
52+52+14x+6 = 180
Combine like terms
110 + 14x = 180
Subtract 110 from each side
110+14x-110 = 180-110
14x =70
Divide by 14
14x/14 = 70/14
x =5
A certain car can travel on a highway for 350 miles on 15 gallons of gas and in a city for 280 miles on 18 gallons of gas. If the car uses twice as many gallons for city driving as for highway driving, what is the car's average number of miles per gallon? Express your answer to the nearest whole number.
Answer:
The car's average 18 number of miles per gallon
Step-by-step explanation:
The car has different efficiencies depending if its used on highway or city streets.
The efficiency on a highway is:
[tex]E_h=\dfrac{350}{15}\;\text{miles/gal}=23.33\;\text{miles/gal}[/tex]
The efficiency for city driving is:
[tex]E_c=\dfrac{280}{18}\;\text{miles/gal}=15.56\;\text{miles/gal}[/tex]
We now that the car uses twice as many gallons for city driving as for highway driving. This means that, for every gallon consumed, 2/3 are for city driving and 1/3 are for highway driving.
Then, we can calculate how many miles makes the car on average as:
[tex]E=\dfrac{1}{3}E_h+\dfrac{2}{3}E_c\\\\\\E=\dfrac{1}{3}\cdot 23.33+\dfrac{2}{3}\cdot15.56=7.78+10.37=18.15\;\text{miles/gal}[/tex]
which answer shows 9 x 10 ^ -5 written in standard form ?
A -0.000009
B -0.00009
C 0.0009
D 0.00009
Answer:
D 0.00009
Step-by-step explanation:
9 × 10^-5 = 9 × 1/10^5 = 9 × 1/100,000
= 9 × 0.00001
= 0.00009
_____
Comment on place value
The exponent of 10 associated with the place value in a decimal number increases from 0 to the left of the decimal point, and decreases from -1 to the right of the decimal point:
100. = 10²
10. = 10¹
1. = 10⁰
0.1 = 10⁻¹
0.01 = 10⁻²
0.001 = 10⁻³
0.0001 = 10⁻⁴
0.00001 = 10⁻⁵
This simple realization can help you immensely with scientific notation.
If g(x) = 2x - 4), find the value of xf g(x) = 20. 12 points)
Answer:
x = 12
Step-by-step explanation:
g(x)= 2x-4
g(x)= 20
Therefore,
2x-4 = 20
Bringing -4 to the other side it becomes positive,so..
2x= 20+4
= 24
x =24/2
= 12
Skyler is out shopping and sees that striped shirts are on sale for
$19.00 each, and plaid pants are on sale for $19.50 each. He
buys 8 shirts and 6 pairs of pants. What is the total of his
purchase?
The total was $_______
Answer:
His total is $269
Step-by-step explanation:
8x19 = 152
6x19.50 = 117
152+117 = 269
Use the following equation to answer the questions below:
y − 2 = 1 /3 (x + 4)
Find the equation of the line that is passing through (8, 2) and is perpendicular to the given line.
Answer:
Step-by-step explanation:I don't say u must have to mark my ans as brainliest but if it has really helped you plz don't forget to thank me...
What are the next two numbers in the pattern of numbers;
45, 15, 44, 17, 40, 20, 31, 25, …
Answer:
Next two numbers are 15 and 32 respectively.
Step-by-step explanation:
The given pattern is
45, 15, 44, 17, 40, 20, 31, 25, …
Here, we have two patterns.
Odd places : 45, 44, 40, 31,...
Even places : 15, 17, 20, 25,...
In series of odd places, we need to subtract square of integers.
[tex]45-(1)^2=45-1=44[/tex]
[tex]44-(2)^2=44-4=40[/tex]
[tex]40-(3)^2=40-9=31[/tex]
So, 9th term of given pattern is
[tex]31-(4)^2=31-16=15[/tex]
In series of even places, we need to add prime numbers.
[tex]15-2=17[/tex]
[tex]17+3=20[/tex]
[tex]20+5=25[/tex]
So, 10th term of given pattern is
[tex]25+7=32[/tex]
Therefore, the next two numbers in the pattern of numbers are 15 and 32 respectively.
9. ABCD is a square and ABK is an equilateral triangle outside the square,
Find measurment of angle DKC
Answer:
< DKC = [tex]60^{0}[/tex]
Step-by-step explanation:
A square is a quadrilateral that has equal length of side. While an equilateral triangle is one with equal length of sides and equal values of angles.
Given square ABCD and that equilateral triangle ABK is outside the square, both figures share side AB. This shows that the length of the sides of the triangle is the same as the length of the side of the square.
i.e /AD/ = /CD/ = /BC/ = /AB/ = /AK/ = /KB/
Thus, < DKC = [tex]60^{0}[/tex] (property of angles in an equilateral triangle)
f(x)= 2x^3- x^2 +x+ 1 is divided by 2x +1.
Answer:
Step-by-step explanation:
x^2
--------------------------------------------------
2x + 1 / 2x^3 - x^2 + x + 1
2x^3 + x^2
-----------------------
0 + x + 1
x + 1
The quotient is x^2 + ------------
2x + 1
if a polynomial is divided by (x-a) and the remainder equals zero, then (x-a) is a factor of the polynomial
Answer:
True.
Step-by-step explanation:
This is the basis for polynomial division/remainder theorem.
Given a polynomial p(x) and a divisor (x - a), if p(a) = 0, then the expression factors in perfectly.
Likewise, if the remainder in p(x)/(x-a) = 0, then the expression factors in perfectly.
I hope this helps!
Answer:
True
Step-by-step explanation:
a p e x
What’s the correct answer for this?
Answer:
C.
Step-by-step explanation:
Density = Mass / Volume
2.7 = 54 / V
V = 54 / 2.7
V = 20 cubic cm
To convert a measurement, Pete must move the decimal point to the left 4 places. This is a shortcut for an operation. Which operation is he using? Which power of 10 is involved? iLL GIVE 50 POINTS PLEASE IM TIMED IM PANICKING
Answer: The moving of decimal to the left is a shortcut to the operation of multiplying number by decimal numbers
Step-by-step explanation:
the power of 10 that is involved in converting the measurements of pete is -4, so he needs to multiply the measurement by 10^-4 to convert it.
Answer:
Sample Response: Because he moved the decimal 4 places to the left, Pete is dividing by 10 to the 4th power, or 10,000. Pete moved the decimal place 4 places to the left. Pete is dividing by 10 to the 4th power, or 10,000.
Step-by-step explanation:
it was on edg
hope it helps :b
Can someone help me please
Answer:
the triangles are not similar.
In monitoring lead in the air after the explosion at the battery factory, it is found that the amounts of lead over a 6 day period had a standard error of 1.93. Find the margin of error that corresponds to a 95% confidence interval. (Round to 2 decimal places) 4.56
Answer:
1.54
Margin of error M.E = 1.54
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
x+/-M.E
Where M.E = margin of error
M.E = zr/√n
Given that
Standard deviation r = 1.93
Number of samples n = 6
Confidence interval = 95%
z(at 95% confidence) = 1.96
Substituting the values we have;
M.E = (1.96×1.93/√6) = 1.544321633166
M.E = 1.54 (to 2 decimal place)
Margin of error M.E = 1.54
Two airplanes leave an airport at the same time, flying in the same direction. One plane is flying at twice the speed of the other. If after 4 hours they are 1800 km apart, find the speed of each plane.
Answer:
The slower plane has a speed of 450 km/h and the faster one has a speed of 900 km/h.
Step-by-step explanation:
Two planes:
The first one's speed is x
The second is y.
One plane is flying at twice the speed of the other.
I will say that y = 2x.
Two airplanes leave an airport at the same time, flying in the same direction
Same direction, so their relative speed is the subtraction of their speeds. 2x - x = x.
Means that after 1 hour, they will be x miles apart.
If after 4 hours they are 1800 km apart, find the speed of each plane
After 1 hour, x km apart. After 4, 1800. So
1 hour - x km apart
4 hours - 1800 km apart
4x = 1800
x = 1800/4
x = 450
2x = 2*450 = 900
The slower plane has a speed of 450 km/h and the faster one has a speed of 900 km/h.
Suppose point (4, −9) is translated according to the rule (, ) → ( + 3, − 2). What are the coordinates of ′? Explain.
Please help
Answer:
(7, -11)
Step-by-step explanation:
If the point is shifted 3 to the right and 2 down, you just have to add 3 to the x-coordinate and subtract 2 from the y-coordinate. 4+ 3 = 7 and -9 - 2 is -11. So, the new point will be (7, -11).
Answer:
(7, -11)
Step-by-step explanation:
The point is translated three units to the right, and 2 units down.
[tex](4,-9)=>(4+3,-9-2)=>(7,-11)[/tex]
Point " ' " should be (7,-11)
The table shows the daily sales (in $1000) of shopping mall for some randomly selected days Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 Days 18 27 31 40 56 55 23 Use it to answer questions 13 and 14. 13. What is the approximate value for the modal daily sales? A. $3,129.41 B. $2,629.41 C. $3,079.41 14. The approximate median daily sales is ... A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $3,123.53 D. $2,664.29
Answer:
Step-by-step explanation:
From the question; we are given the following inclusive frequency distribution information
Class Frequency f
1.1-1.5 18
1.6-2.0 27
2.1-2.5 31
2.6-3.0 40
3.1-3.5 56
3.6-4.0 55
4.1-4.5 23
Convert the above inclusive frequency distribution to exclusive frequency distribution with respect of the upper and lower class limit ; we have:
Class Frequency f
1.05 - 1.55 18
1.55 - 2.05 27
2.05 - 2.55 31
2.55 - 3.05 40
3.05 - 3.55 56
3.55 - 4.05 55
4.05 - 4.55 23
Class Frequency f cf
1.05 - 1.55 18 18
1.55 - 2.05 27 45
2.05 - 2.55 31 76
2.55 - 3.05 40 116
3.05 - 3.55 56 172
3.55 - 4.05 55 227
4.05 - 4.55 23 250
n = 250
To determine the daily sales; we can derive that from estimated Mode by using the relation :
Estimated Mode = L + fm − fm-1(fm − fm-1) + (fm − fm+1) × w
here:
L = the lower class boundary of the modal group
fm-1 = the frequency of the group before the modal group
fm = the frequency of the modal group
fm+1 = the frequency of the group after the modal group
w = the group width
However;
It is easier now to determine the modal group (i.e the group with the highest frequency), which is 3.05 -3.55
L = 3.05
fm-1 =40
fm =56
fm+1 = 55
w = 0.5
∴[tex]mode = 3.05 + \dfrac{56 - 40 }{(56 - 40) + (56 -55)} * 0.5 \\ \\ mode = 3.05 + 0.4705 \\ \\ mode = 3.5205[/tex]
To find Median Class ; we use the formula;
Median Class = value of (n / 2)th observation
Median Class = value of (250 / 2)th observation
Median Class = value of 125th observation
From the column of cumulative frequency cf,
we will see that the 125th observation lies in the class 3.05-3.55.
∴ The median class is 3.05-3.55.
Thus;,
L=lower boundary point of median class =3.05
n=Total frequency =250
cf=Cumulative frequency of the class preceding the median class =116
f=Frequency of the median class =56
c=class length of median class =0.5
[tex]Median M=L+n2-cff- c \\ \\ =3.05+125-11656⋅0.5 \\ \\=3.05+0.08036 \\ \\ =3.13036[/tex]
hence median sales = $3130.36
If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (9-1(3)?
Answer:
( g − f ) ( 3 ) = 23
Step-by-step explanation:
(g-f)(x)=g(x)-f(x)
=6x-(4-X(2))
=x(2)+6x-4
to evaluate (g-f) (#) substitute x=3 into (g-f)(x)
(g-f)=(9)+(6 x 3) -4=23