Answer:
Part A: The speed the car should be travelling when leaping the river is approximately 37.948 m/s
Part B: The speed of the car just before it lands is approximately 41.92345 m/s
Explanation:
The parameters of the car attempting leaping the river are;
The height of the car over the river = 18 m
The height of the opposite side of the bridge above the river = 1.8 m
The width of the river, x = 69.0 m
Part A
The time, 't' it would take the car to fall from 18 m above the river to 1.8 m above the river is given as follows;
t = √(2·h/g)
Where;
h = The height of the fall = 18 m - 1.8 m = 16.2 m
g = The acceleration due to gravity = 9.8 m/s²
∴ t = √(2×16.2 m/(9.8 m/s²)) = (9/7)·√2 s
The horizontal speed, 'vₓ', with which the car should be travelling at the time it leaves the road in order just to clear the river and land safely on the opposite side is given as follows;
vₓ = x/t = 69.0 m/((9/7)·√2 s) = (161/6)·√2 m/s ≈ 37.948 m/s
The horizontal speed the car should be travelling when leaping the river, vₓ ≈ 37.948 m/s
Part B;
The vertical velocity of the car is given as follows;
[tex]v_y[/tex]² = [tex]u_y[/tex]² + 2·g·h
∴ [tex]v_y[/tex]² =2·g·h = 2 × 9.8 m/s² × 16.200 m = 317.52m²/s²
[tex]v_y[/tex] = √(317.52 m²/s²) = (63/5)·√2 ≈ 17.819 m/s
The magnitude of the speed of the car, 'v', just before it lands is given using Pythagoras' theorem for resultant vectors as follows;
v = √([tex]v_y[/tex]² + vₓ²) = √(317.52 m²/s² +((161/6)·√2 m/s)²) ≈ 41.92345 m/s
The speed of the car just before it lands, v ≈ 41.92345 m/s.
Arturo and Bianca are discussing the speeds of cars A and B. Arturo says: It looks like when the time is exactly 1.0s, the speed of Car B is greater than the speed of Car A. Bianca says: It also looks to me like the speed of Cars A and B are exactly the same at about 2.0s. Do you agree or disagree with Arturo and Bianca
Answer:
he two people agree with your answer
v_B = v_{oB} - a t
v_A = cte
Explanation:
To analyze if they are both in Kurdish, let's see the movement of the two cars
at t = 1s
the velocity of carriage B is greater than the speed of carriage a
v_B> v_A
at t = 2 s
the speed of the two cars is nipple
v_B = v_A
For this to be true, the speed of car B must be decreasing
v_B = v_{oB} - a t
v_A = cte
therefore the two people agree with your answer
Which of the following is NOT a characteristic of noble gases?
unreactive
odorless
solid at room temperature
colorless
a sensor light installed on the edge of a home can detect motion for a distance of 50 feet in front and with a range of motion of 200 degrees. what is the arc length of the area covered
Answer:
4363.3231 feets²
Explanation:
Given that :
Distance, r = 50 ft
θ = 200°
The arc length of area covered :
Arc length = θ/360° * πr²
Arc length = (200/360) * 50 ft ^2 * π
Arc length = 0.5555555 * 2500 * π
Arc length = 4363.3231 feets²
A student stretches a spring, attaches a 1.20 kg mass to it, and releases the mass from rest on a frictionless surface. The resulting oscillation has a period of 0.750 s and an amplitude of 15.0 cm. Determine the oscillation frequency, the spring constant, and the speed of the mass when it is halfway to the equilibrium position.
Answer:
the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s
Explanation:
Given that;
mass of the object m = 1.20 kg
period of oscillation = 0.750 s
Amplitude ( A/x) = 15.0 cm = 0.15 m
now;
a) Determine the oscillation frequency;
oscillation frequency f = 1/T
we substitute
f = 1 / 0.750 s
f = 1.33 Hz
Therefore, the oscillation frequency is 1.33 Hz
b) Determine the spring constant;
we solve for spring constant from the following expression;
T = 2π√(m/k)
k = 4π²m / T²
so we substitute
k = (4π² × 1.20) / (0.750)²
k = 47.3741 / 0.5625
k = 84.22 N/m
Therefore, the spring constant is 84.22 N/m
c) determine the speed of the mass when it is halfway to the equilibrium position
So, at equilibrium, the energy is equal to K.E
such that;
1/2mv² = 1/2kx²
mv² = kx²
v² = kx² / m
v = √( kx²/m)
we substitute
v = √( 84.22×(0.15 m)²/ 1.2 )
v = √( 1.89495 / 1.2 )
v = √ 1.579125
v = 1.26 m/s
Therefore, the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s
Solving steps and answer!
Answer:
162 cm
Explanation:
We are told that the Body surface are of a patient is given by the formula;
BSA = (√wh)/60
Where;
w is weight in kg
h is height in cm
We ware now given that;
w = 50 kg
BSA = 1.5
Thus;
1.5 = (√50h)/60
Multiply both sides by 60 to get;
90 = (√50h)
Square both sides to get;
90² = 50h
h = 90²/50
h = 162 cm
Please help me I’ll mark brainless
Answer:
ITS B NOT A
Explanation:
What is the average speed of a car that travels 60 meters in 2
seconds?
Answer:
30 m/s
Explanation:
Speed is distance over time. 60 meters / 2 seconds, = 30 m/s.
What does the word quantum mean?
Answer:
a required or allowed amount, especially an amount of money legally payable in damages.
OR
In physics it means a discrete quantity of energy proportional in magnitude to the frequency of the radiation it represents.
Explanation:
A helicopter is hovering at a constant height of 35 m. The upward lift force on the helicopter is 85500. What is the weight of the helicopter
The nucleus of an atom can be modeled as several protons and neutrons closely packed together.Each particle has a mass of 1.67 3 10227 kg and radius on the order of 10215 m.
(a) Use this model and the data provided to estimate the density of the nucleus of an atom.
(b) Compare your result with the density of a material such as iron. What do your result and comparison suggest about the structure of matter?
Answer:
Explanation:
Let n be number of total number of nucleons ( protons + neutrons )
Total mass inside nucleus = n x 1.67 x 10⁻²⁷ Kg
volume of nucleus = 4/3 π r³
= 1.33 x 3.14 x (10⁻¹⁵)³ m
= 4.17 x 10⁻⁴⁵ m³
Density = mass / volume
= n x 1.67 x 10⁻²⁷ / 4.17 x 10⁻⁴⁵
= .4 n x 10¹⁸ kg / m³
or of the order of 10¹⁸ kg/m³
b )
Density of iron = 7900 kg / m³
or of the order of 10⁴ kg / m³
So nucleus of a matter is about 10¹⁴ times denser than iron .
Can someone please help me with this worksheet. It’s due today and I have no idea what to do.
Do You think History is the most important subject that deserves first place? Do you see a way that learning history could assist you in your future career?
yes
Explanation:
history is an important class and it helps to you understand what went on in the past so that we can learn from our mistakes and help us grow
A 6.00 nC is 2.00 m from a 3.00 nC charge. Find the magnitude of the electric field at a point midway between
the two charges? Which way does the electric field point, towards the positive or the negative charge?
Answer:
E_total = 26.97 N/C
Electric field points towards the positive charge
Explanation:
We are given;
Charge 1; q1 = 6 nC = 6 × 10^(-9) C
Charge 2; q2 = 3 nC = 3 × 10^(-9) C
Distance between both charges; R_o = 2 m
Since we want to find electric field midway, the distance midway is r = 2/2 = 1 m
Using coulumbs law;
E = kq/r²
Where k is a constant with a value of 8.99 × 10^(9) N.m/C²
Thus;
E1 = kq1/r²
E1 = (8.99 × 10^(9) × 6 × 10^(-9))/1²
E1 = 53.94 N/C
Similarly;
E2 = kq2/r²
E2 = (8.99 × 10^(9) × 3 × 10^(-9))/1²
E2 = 26.97 N/C
Since both electric fields are positive, it means that they are both moving towards the midpoint of the distance between both charges.
This implies they will have opposite directions.
Thus, total electric field at the midway point is;
E_total = E1 - E2
E_total = 53.94 - 26.97
E_total = 26.97 N/C
3. Do you think Lynn’s (the protagonist)actions were justifiable by her motives? Why or why not? Please help me Bad Genius the movie
Answer:
I do believe her actions were justified.
Explanation:
Due to the school charging extra fee from her father who makes a modest amount as a teacher. There was sum of money involved that could change how he lived and her.
I do not believe her actions where justified
She had a lot going for her. She could have skipped the hardship of helping grace and pass. She could have easily have gotten a good job with a degree and paid back all the debts owed. Alot of troubles could have been avoided just by doing her own thing.
A single, monochromatic indigo light source is shined through an etched, flat prism with a slit separation of .0250mm. The resulting interference pattern is viewed on a screen 1.25m away. The third maximum is found to be 6.6cm from the central maximum. What is the wavelength of the indigo light
Answer:
λ = 440 nm
Explanation:
The phenomenon of constructive interference is described by the expressions
d sin θ= m λ (1)
where d is the separation of the slits d = 0.0250 mm = 2.50 10⁻⁵ m, lam is the wavelength of the incident radiation and m is an integer indicating the order of interference
let's use trigonometry to find the angle
tan θ = y / L
where L is the distance to the screen L = 1.25 m
in general interference experiments angles are very small
tan θ = [tex]\frac{sin \ \theta }{cos \ \theta}[/tex]
ten θ = sin θ
substituting
sin θ = y / L
we substitute 1
d y / L = m λ
λ = [tex]\frac{ d \ y }{m \ L}[/tex]
in the exercise indicate
m = 3
y = 6.6 cm = 6.6 10-2 m
we calculate
λ = 2.50 10⁻⁵ 6.6 10⁻² /( 3 1.25)
λ = 4.4 10⁻⁷ m
let's reduce to nm
λ = 4.4 10⁻⁷ m (10⁹ nm / 1 m)
λ = 440 nm
Which of the following sentences is an example concerns smerne might have at lunchtime?
I would be to have brocoll stead of fres,
I wonder if my chicken is ooked all the way
I have never ordered smething I did not ke,
of ordered a salad with the dressing on the site
Answer:
yes
Explanation:
becausw yesnssjsdkwww
Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant (and quite modest) acceleration. A train travels through a congested part of town at 4.0 m/s . Once free of this area, it speeds up to 11 m/s in 8.0 s. At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s to reach a higher cruising speed. Part A What is the final speed
Answer:
25 m/s
Explanation:
Given that:
Initial speed, u = 4 m/s
Final velocity, V = 11 m/s
Time, t = 8 seconds
t2, = 16 seconds
Acceleration, a= (change in velocity) / time interval
a = (11 - 4) / 8
a = 7 / 8 = 0.875m/s²
Final velocity, v2 ;
Acceleration * t2
0.875 * 16 = 14
V2 = 14 m/s
Final speed : v + v2 = (11 + 14)m/s = 25m/s
A car initially traveling at 15 m/s speeds up at a constant rate of 2.0 m/s2 for 3 seconds. The velocity of the car at the end of the 3 second interval is _________ m/s.
Answer:
Vf = 21 m/s
Explanation:
Data:
Initial Velocity (Vo) = 15 m/sAcceleration (a) = 2.0 m/s²Time (t) = 3 sFinal Velocity (Vf) = ?Use formula:
Vf = Vo + a * tReplace:
Vf = 15 m/s + 2.0 m/s² * 3sMultiply the acceleration with time:
Vf = 15 m/s + 6 m/sSolve the sum:
Vf = 21 m/sThe velocity of the car at the end of the 3 second interval is 21 meters per second.
A 200-N force acts on a 10-kg object. The acceleration of the object is
help? its a short question
Answer:
i think its ancestor
Explanation:
sry if im wrong
Answer:
scientists compare organisms DNA to support the theory that all species share a common Ancestor.
Peter, a 100 kg basketball player, lands on his feet after completing a slam dunk and then immediately jumps up again to celebrate his basket. When his feet first touch the floor after the dunk, his velocity is 5 m/s downward; when his feet leave the floor 0.50 s later, as he jumps back up, his velocity is 4 m/s upward. a. What is the impulse exerted on Peter during this 0.50 s
Answer:
Explanation:
Impulse = change in momentum
Initial momentum = mass x initial velocity = 100 x 5 = 500 kg m/s
final momentum = mass x final velocity = 100 x - 4 = -400 ( - ve sign due to reversal of direction )
change in momentum = final momentum - initial momentum
= - 400 - 500 = - 900 kg m/s .
As it is - ve , it acts upwards .
So magnitude of impulse on Perter = 900 kg m/s
A wheelbarrow is pushed 10 meters with a force of 75 N for 30 seconds. What is the work done?
How much power is needed?
What term is used to describe DNA Replication?
Conservative
Un-conservative
Non-conservative
Semi-conservative
Answer:
Semi-conservative
Explanation:
Each strand of the original DNA molecule serves as a template for the production of its counterpart
Which of these is an effect of gravity?
А
A cup placed on a table won't float away.
B
You can throw a ball or a rock up.
С
The brakes on a bike can make it stop.
D
Liquid water can become a gas.
Answer:
(A)
A cup placed on a table won't float away
HELP ASAP PLS
A balloon with a positive charge will stick to a wall that has a negative charge.
What force causes this?
A. Gravity
B. Electric force
C. Magnetic force
D. Air gesistance
Desperado, a roller coaster built in Nevada, has a mass of 800 kg. It also has a vertical drop of 225 feet down the first hill. The roller coaster is designed so that the speed of the cars at the end of this drop is 80 mi/h. Assume the cars are at rest at the start of the drop. How much work is done by friction on the car as it drops down the hill
Answer:
the work done by friction on the car is 524,582 J.
Explanation:
Given;
mass of the roller coaster, m = 800 kg
distance moved by the coaster, d = 225 ft = 68.58 m
final velocity of the coaster, v = 80 mi/h = 35.76 m/s
The time taken for the coaster to drop down the hill is calculated as;
[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\ \times \ 68.58}{9.8} } \\\\t = 3.74 \ s[/tex]
The work done by friction on the car is calculated as;
[tex]W =F\ \times \ d = \frac{mv}{t} \times \ d\\\\W = \frac{800 \ \times \ 35.76 }{3.74} \times \ 68.58\\\\W = 524,582 \ J[/tex]
Therefore, the work done by friction on the car is 524,582 J.
I have a massive rock weighing 3,000 Newtons but I can only accelerate it to 500 m/s2 what is its mass?
Answer:
6 kg
Explanation:
F=ma
F is Force(newtons)
m is mass(kg)
a is acceleration(m/s^2)
Plug in the numbers
3000 = m(500)
divide both sides by 500 to cancel out the 500.
3000/500=6
6 = m
6kg is the mass
Pulling a rubber band back and then letting it fly across the room is an example of
A. converting energy to work
B. converting elastic energy to gravitational
C. converting kinetic energy to potential
Answer:
b
Explanation:
because a elastic band uses elastic energy
The nearest neighbor interaction force is of magnitude 481 nanoNewtons, e.g., the magnitude of the force of the leftmost electron on the proton, or the magnitude of the force of any of the three on its nearest neighbor electron. Calculate the size of the net force on the leftmost proton.
Answer:
F = 120.25 10⁻⁹ N
Explanation:
In this exercise, the force between the closest neighbors is indicated by f = 481 10⁻⁹ N, in general between the one-dimensional solid the distances remain the same, if the distance between the first neighbor is d, the distance between the second neighbors is 2d.
For most solids the attractive forces are electrical, therefore force is proportional to the electrical charges and the inverse of the distance squared,
F = [tex]k \frac{q_1 q_2}{r^2}[/tex]
if we call fo the force for the first neighbors
F₀ = k \frac{q_1 q_2}{d^2}
the force for the second neighbors r= 2d
F = k \frac{q_1 q_2}{(2d)^2}
F = F₀ / 4
let's calculate
F = 481 10⁻⁹ / 4
F = 120.25 10⁻⁹ N
What inspired Ronald McNair to do science
Answer:
While working as a staff physicist at hughes Research Laboratories McNair learned that the National Aeronautics and Space Administration (NASA) was looking for scientist to join the shuttle program;)