Energy that comes from the heat inside the Earth is called ________ energy.

Answer:

a unit of mass or weight equaling one thousand grams

Answer:

a. 50

Explanation:

Answer:

convection currents in the earth's mantle, heat and pressure within the earth cause the hot magma to flow in convection currents. This causes the movement of the tectonic plates.

rift valley, Africa

plz mark me as brainliest

Answer:

I = 1.666... amps

Explanation:

P = I*V or Power = Current * Voltage

(100 watts) = I * (60 Volts)

I = 1.666... amps

Answer:

A

Explanation:

The wavelength is the spatial time of an occasional wave, the distance over which the wave's shape rehashes.

Hope this helped!!

Answer:

wavelength

Explanation:

Answer:

the answer is true.

Explanation:

hope it will help you

Answer:2,030

Explanation:

40 atm x 10.0 L = 400

400/0.197 atm = 2,030

Answer: 98 kN/m

Explanation:

Given

Mass of elephant [tex]m=5000\ kg[/tex]

Spring compresses from [tex]1\ m\ (100\ cm) \text{to}\ 50\ cm[/tex]

i.e. change in length is [tex]100-50=50\ cm[/tex]

spring force is given by  [tex]kx[/tex]

where k=spring constant

x=change in length

The weight of elephant must be equal to the spring force

[tex]\Rightarrow W=kx\\\Rightarrow 5000\times 9.8=k\times 0.5\\\Rightarrow k=98,000\ N/m\ or\ 98\ kN/m[/tex]

Answer:

Folk dance

Explanation:

hope i helped :)

Answer:

We know that the gravitational force between two objects of mass M1 and M2 that are at a distance R, is given by:

F = G*(M1*M2)/R^2

Where G is a constant.

If you reduce one of the masses, then the gravitational force between the objects will change.

So if we take un account the Earth and the Sun, when you reduce the mass of Earth, the force between Earth and the Sun will decrease, and this will change the orbit of the Earth around the Sun.

(The orbit also depends on the gravitational force between the Earth and the other planets in the system, and all those forces also change, which also has an impact in the orbit change)

Answer:

Stars i think

Explanation:

Answer:

it goes up until we help it to but the moment we stop support it gets affected by gravity and goes back

Explanation:

Answer:

1.63 A and in clockwise direction

Explanation:

The magnetic field due to the rectangular loop is :

[tex]$B=\frac{2 \mu_0 I}{\pi}\left(\frac{\sqrt{L^2+W^2}}{LW}\right)$[/tex]

Given : W = 4.20 cm

                [tex]$=4.20 \times 10^{-2} \ m$[/tex]

            L = 9.50 cm

               [tex]$= 9.50 \times 10^{-2} \ m$[/tex]

            [tex]$B = 3.40 \times 10^{-5} \ T $[/tex]

   Rearranging the above equation, we get

[tex]$I=\frac{B \pi LW}{2 \mu_0\sqrt{L^2+W^2}}$[/tex]

[tex]$I=\frac{(3.40 \times 10^{-5}) \pi(9.50 \times 10^{-2})(4.20 \times 10^{-2})}{2(4 \pi \times 10^{-7})\sqrt{(9.50 \times 10^{-2})^2+(4.20 \times 10^{-2})^2}}$[/tex]

I = 1.63 A

So the magnitude of the current in the rectangular loop is 1.63 A.

And the direction of current is clockwise.

Answer:

a.16.125 N b. The force is an attractive force. c. 2.68 × 10¹³ electrons d. 3.75 × 10¹³ electrons

Explanation:

a. What is the magnitude of the electric force between the corks?

The electrostatic force of attraction between the two corks is given by

F = kq₁q₂/r² where k = 9 × 10⁹ Nm²/C², q₁ = +6.0 μC = +6.0 × 10⁻⁶ C, q₂ = -4.3 μC = -4.3 × 10⁻⁶ C and r = distance between the corks = 0.12 m

Substituting the values of the variables into the equation, we have

F = kq₁q₂/r²

F = 9 × 10⁹ Nm²/C² × +6.0 × 10⁻⁶ C × -4.3 × 10⁻⁶ C/(0.12 m)²

= -232.2 × 10⁻³ Nm²/(0.0144 m)²

= -16125 × 10⁻³ N

= -16.125 N

So, the magnitude of the force is 16.125 N

b. Is this force attractive or repulsive?

Since the direction of the force is negative, it is directed towards the positively charged cork, so the force is an attractive force.

c. How many excess electrons are on the negative cork?

Since Q = ne where Q = charge on negative cork = -4.3 μC = -4.3 × 10⁻⁶ C and n = number of excess electrons and e = electron charge = -1.602 × 10⁻¹⁹ C

So n = Q/e = -4.3 × 10⁻⁶ C/-1.602 × 10⁻¹⁹ C = 2.68 × 10¹³ electrons

d. How many electrons has the positive cork lost?

We need to first find the number of excess positive charge n'

Q' = n'q where Q = charge on positive cork = + 6.0 μC = + 6.0 × 10⁻⁶ C and n = number of excess protons and q = proton charge = +1.602 × 10⁻¹⁹ C

So n' = Q'/q = +6.0 × 10⁻⁶ C/+1.602 × 10⁻¹⁹ C = 3.75 × 10¹³ protons

To maintain a positive charge, the number of excess protons equals the number of electrons lost = 3.75 × 10¹³ electrons

Answer:

 α = 2.13 10⁻⁵ C⁻¹    ,  the closest material is ALUMINUM

Explanation:

The expression for thermal expansion is

          ΔL = α L₀ ΔT

temperatures are

         ΔT = 85 - 10 = 75 ° C

the length of the rod is L₀ = 125 m and L_f = 125.20 m

        ΔL = 125.20 - 125 = 0.20 m

        α = [tex]\frac{1}{L_o} \frac{\Delta L }{\Delta T}[/tex]

        α = [tex]\frac{ 1}{125} \ \frac{0.20 }{75}[/tex]

        α = 2.13 10⁻⁵ C⁻¹

When reviewing the table, the closest material is ALUMINUM

Answer:

a) 500 J

Explanation:

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

[tex] P.E = mgh[/tex]

Where,

P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

In Science, the potential energy possessed by an object or body is the same as the work done by the object or body.

Since we know that the object possessed 500 Joules of potential energy; it would ultimately require to do a work of 500 Joules to lift the object.

Mathematically, work done = force * distance

But force = mass * acceleration due to gravity

F = mg; d = h

Substituting into the work done formula, we have;

Hence, Workdone = Fd = mgh

Answer:

d=v1t - .5at^2

d=4.88 x .872 - 0.5 x (4.88/0.872) x 0.872^2

d=4.255 - 2.12

d= 2.135m

Explanation:

acceleration is negative because she is slowing down.

Answer:

Yes, va

Explanation:

Answer:

The police car is moving at 41.24 m/s.

Explanation:

To find the speed of the police car we need to use the Doppler equation:

[tex] f = f_{0}(\frac{v + v_{r}}{v + v_{s}}) [/tex]      

Where:

v: is the speed of the sound = 343 m/s

[tex]v_{r}[/tex]: is the speed of the receiver = 12 m/s

[tex]v_{s}[/tex]: is the speed of the source =?

f: is the observed frequency = 959 Hz

f₀: is the emitted frequency = 1038 Hz          

Both terms are positive in the fraction because the velocity of the sound is in the opposite direction to both velocities of the police car and the other car.  

By solving the above equation for [tex]v_{s}[/tex] we have:        

[tex] v_{s} = \frac{f_{0}(v + v_{r})}{f} - v = \frac{1038(343 + 12)}{959} - 343 = 41.24 m/s [/tex]  

Therefore, the police car is moving at 41.24 m/s.

I hope it helps you!                  

Answer:

The can would be heavier.

Explanation:

The more rust is on the can, (Or object) the more it weights it down.

Answer:

The answer would be heavier, though it depends upon the type of metal. Rusting is essentially corrosion. Rust is often caused by a piece of metal getting soaked in water and then being exposed to oxygen. The rust will add more weight to the can so it becomes heavier.

Answer:

i think its its c but im not positive :>

Explanation:

Answer:

Absorbed

Explanation:

Hope this helped!!!

Answer:

46.67 miles/s

Explanation:

...........

Answer: I'm not sure about this one, but you can go to this link to understand it better https://youtu.be/wEQxtUwiV1E.Its a Khan Academy Video Hope This Helps

Explanation:

Explanation:

jouleeeee is the unit kinetic energy is measured in and kinetic energy formula is 1/2mv (square)

Answer:

Explanation:

Let the potential difference between the middle point and one of the plate be ΔV .

electric potential energy will be lost and it will be converted into kinetic energy .

Electrical potential energy lost = Vq , where q is charge on charge particle .

For proton

ΔV× q = 1/2 M V² ( kinetic energy of proton )

where M is mass and V be final velocity of proton .

For electron

ΔV× q = 1/2 m v² ( kinetic energy of electron  )

where m is mass and v be final velocity of electron . Charges on proton and electron are same in magnitude .

As LHS of both the equation are same , RHS will also be same . That means the kinetic energy of both proton and electron will be same

1/2 M V² =  1/2 m v²

(V / v )² = ( m / M )

(V / v ) = √ ( m / M )

In other words , their velocities  are  inversely proportional to square root of their masses .

Answer:

For which the reasoning of the boy is correct for small heights, but as height increases his analysis is not correct.

Explanation:

The force of gravity comes from Newton's second law with the force the universal attraction

         F = ma

         F = [tex]G \frac{m_1 M}{(R_e +h)^2}[/tex]

we substitute

          [tex]G \frac{m_1 M}{ (R_e+ h)^2}[/tex] = m₁ a

where Re is the radius of the Earth 6.37 106 m

          a = [tex]G\frac{M}{R_e^2} \ ( 1 + \frac{h}{R_e})^{-2}[/tex]

In general, the height is much less than the radius of the earth, therefore the term ha / Re is very small and we can use a series expansion leaving only the first fears.

             (1 + x)⁻² = 1 -2x + [tex]\frac{2 \ 1}{2!}[/tex]  x²

we substitute

          a = g₀ ([tex]1 - 2 \frac{h}{R_e}[/tex] )

with

         g₀ = [tex]G \frac{M}{R_e^2}[/tex]

let's launch the expression.

* For small height compared to the radius of the earth we can neglect the last term

          g = g₀

* For height comparable to the radius of the Earth

          g = g₀  [tex](1 - \frac{2h}{Re} )[/tex]

We see that the acceleration of gravity is decreasing.

For which the reasoning of the boy is correct for small heights, but as height increases his analysis is not correct.

The student's reasoning gone wrong when the analysis is undertaken for the increasing heights, to drop the object.

The given problem is based on the concept of gravity and gravitational force. The force of gravity comes from Newton's second law with the force the universal attraction as,

F = ma

[tex]F=G\dfrac{mM}{(R+h)^{2}}\\\\\\ma = G\dfrac{mM}{(R+h)^{2}}[/tex]

Here, a is the linear acceleration, m is the mass of object, M is the mass of Earth, R is the radius of Earth and h is the height from where the objects will be dropped. Then,

[tex]a = \dfrac{GM}{R^{2}} \times(1+h/R)^{-2}[/tex]

In general, the height is much less than the radius of the earth, therefore the term h/ R is very small, hence can be neglected.

[tex]a = \dfrac{GM}{R^{2}}\\\\a=g = \dfrac{GM}{R^{2}}[/tex]

g is the gravitational acceleration.

For small height compared to the radius of the earth we can neglect the last term as,

a = g

And for the height comparable to radius of Earth,

[tex]a = \dfrac{GM}{R^{2}} \times(1+h/R)^{-2}\\\\a=g \times(1+h/R)^{-2}[/tex]

Clearly, the acceleration of gravity is decreasing, for which the reasoning of the boy is correct for small heights, but as height increases his analysis is not correct.

Thus, we can conclude that the student's reasoning gone wrong when the analysis is undertaken for the increasing heights, to drop the object.

Learn more about the gravitational force here:

https://brainly.com/question/15647838

Answer:C

Explanation:I think sorry if it’s wrong