find the perimeter of this figure to the nearest hundredth use 3.14 to approximate pi P=?ft

Answer:

what is this boiii?

Answer:

-4

Step-by-step explanation:

Answer:

62.93%

Step-by-step explanation:

We have to solve it by a Poisson distribution, where:

p (x = n) = e ^ (- l) * l ^ (x) / x!

Where he would come being the number of birds that there would be in 40 minutes, we know that in 2 hours, that is 120 minutes there are 13, therefore in 40 there would be:

l = 13 * 40/120

l = 4,333

Now, we have p (x> 3) and that is equal to:

p (x> 3) = 1 - p (x <= 3)

So, we calculate the probability from 0 to 3:

 p (x = 0) = 2.72 ^ (- 4.33) * 4.33 ^ (0) / 0! = 0.01313

p (x = 1) = 2.72 ^ (- 4.33) * 4.33 ^ (1) / 1! = 0.0568

p (x = 2) = 2.72 ^ (- 4.33) * 4.33 ^ (2) / 2! = 0.12310

p (x = 3) = 2.72 ^ (- 4.33) * 4.33 ^ (3) / 3! = 0.17767

If we add each one:

0.01313 + 0.0568 + 0.12310 + 0.17767 = 0.3707

replacing:

p (x> 3) = 1 - 0.3707

p (x> 3) = 0.6293

Which means that the probability is 62.93%

Answer:

7/3

Step-by-step explanation:

Write this symbolically as:

  7/9

 -------

   1/3

Invert the denominator fraction and then multiply:

(7/9)(3/1)

Reducing this, we get 7/3

Answer:

the answer as a mixed number is 2 and 1/3  (2 1/3)

and as a normal fraction its 7/3

Answer:

D

Step-by-step explanation:

divide 10 times starting with 100.

The answer is 25/256 or 0.09765625

The height of the ball dropped from 100 feet on the 10th bounce is 0.09766 feet

An equation is an expression that shows the relationship between two or more numbers and variables.

Let y represent the height of the ball after x bounce. Given that the ball rises to the height from which it has fallen, hence:

y = 100(1/2)ˣ

After the 10th bounce:

y = 100(1/2)¹⁰ = 0.09766

The height of the ball dropped from 100 feet on the 10th bounce is 0.09766 feet.

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Answer:

The range of the random variable is {0, 1, 2}.

Step-by-step explanation:

The bag contains red and blue marbles.

The experiments consists of two draws, with reposition.

The random variable assigns the number of blue  marbles to each outcome.

If we have only two draws, we can only get 0, 1 or 2 blue marbles.

The range of the random variable is {0, 1, 2}.

Answer:

Step-by-step explanation:

Let P=Mount Peak

Let K=Mount Killimanjaro

The equation should then be

12555=P+K    ...1

P=K+765   ... 2

sub equation 2 into 1

12555=P+P+765

12555=2P+765

12555-765=2P+765-765               (subtracting 765 from both sides)

11790=2P

P=5895, now that we know P

we just make a new equation that was similiar to 1

12555=5895+K

K=6660

the height of Mount K is 6660 Metres

Answer:

a) [tex]x(t) = 13*e^(^-^\frac{t}{100}^)[/tex]

b) 10.643 kg

Step-by-step explanation:

Solution:-

- We will first denote the amount of salt in the solution as x ( t ) at any time t.

- We are given that the Pure water enters the tank ( contains zero salt ).

- The volumetric rate of flow in and out of tank is V(flow) = 50 L / min  

- The rate of change of salt in the tank at time ( t ) can be expressed as a ODE considering the ( inflow ) and ( outflow ) of salt from the tank.

- The ODE is mathematically expressed as:

                            [tex]\frac{dx}{dt} =[/tex] ( salt flow in ) - ( salt flow out )

- Since the fresh water ( with zero salt ) flows in then ( salt flow in ) = 0

- The concentration of salt within the tank changes with time ( t ). The amount of salt in the tank at time ( t ) is denoted by x ( t ).

- The volume of water in the tank remains constant ( steady state conditions ). I.e 10 L volume leaves and 10 L is added at every second; hence, the total volume of solution in tank remains 5,000 L.

- So any time ( t ) the concentration of salt in the 5,000 L is:

                             [tex]conc = \frac{x(t)}{1000}\frac{kg}{L}[/tex]

- The amount of salt leaving the tank per unit time can be determined from:

                         salt flow-out = conc * V( flow-out )  

                         salt flow-out = [tex]\frac{x(t)}{5000}\frac{kg}{L}*\frac{50 L}{min}\\[/tex]

                         salt flow-out = [tex]\frac{x(t)}{100}\frac{kg}{min}[/tex]

- The ODE becomes:

                               [tex]\frac{dx}{dt} = 0 - \frac{x}{100}[/tex]

- Separate the variables and integrate both sides:

                       [tex]\int {\frac{1}{x} } \, dx = -\int\limits^t_0 {\frac{1}{100} } \, dt + c\\\\Ln( x ) = -\frac{t}{100} + c\\\\x = C*e^(^-^\frac{t}{100}^)[/tex]

- We were given the initial conditions for the amount of salt in tank at time t = 0 as x ( 0 ) = 13 kg. Use the initial conditions to evaluate the constant of integration:

                              [tex]13 = C*e^0 = C[/tex]

- The solution to the ODE becomes:

                           [tex]x(t) = 13*e^(^-^\frac{t}{100}^)[/tex]

- We will use the derived solution of the ODE to determine the amount amount of salt in the tank after t = 20 mins:

                           [tex]x(20) = 13*e^(^-^\frac{20}{100}^)\\\\x(20) = 13*e^(^-^\frac{1}{5}^)\\\\x(20) = 10.643 kg[/tex]

- The amount of salt left in the tank after t = 20 mins is x = 10.643 kg

Answer: 0.401294

Step-by-step explanation:

z=x-μ/σ

z=20-22/8

z=-0.25

the probability for this z-score is 0.401294.

Answer:

  c)  x = 6, y = 9

Step-by-step explanation:

The figure is a parallelogram. The diagonals of a parallelogram bisect each other, so each part of a given diagonal is equal to the other part.

  3x = 2y

  2x = y+3

__

Solving the second equation for y, we have ...

  y = 2x -3

Substituting into the first equation gives ...

  3x = 2(2x -3)

  3x = 4x -6 . . . . simplify

  6 = x . . . . . . . . .add 6 -3x

  y = 2(6) -3 = 9 . . . . use the above expression for y

The values of x and y are (x, y) = (6, 9).

Answer:

452

Step-by-step explanation:

plz mark brainliest!

Answer:

i'll say you have to multiple 9 by 9 than 5 by 5 BUT 23 25 13 and 7 IDK sorry hope i helped :)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Two sides and the angle between are marked as congruent. That immediately tells you that the Side-Angle-Side (SAS) theorem of congruence applies.

The angle is a right angle, which makes the adjacent sides be "legs" of the right triangle. Then the Leg-Leg (LL) theorem of congruence for a right triangle also applies.

Appropriate choices are ...

  SAS, LL

Answer:

49/6 or 8 16/99

Step-by-step explanation:

2 1/3 *3 1/2 = (7/3*7/2)= 49/6

First convert to fraction form

then multiply across numerator to numerator and denominator to deominator

Simplify if needed

Turn to mixed fraction if needed

Answer:

= 0.0041

Step-by-step explanation:

Given that:

A farmer was interest in determining how many grasshoppers were in his field. He knows that the distribution of grasshoppers may not be normally distributed in his field due to growing conditions. As he drives his tractor down each row he counts how many grasshoppers he sees flying away

mean number of flights to be 57

a standard deviation of 12

fewer flights on average in the next 40 rows

[tex]\mu = 57\\\\\sigma=12\\\\n=40[/tex]

so,

[tex]P(x<52)[/tex]

[tex]=P(\frac{x-\mu}{\sigma/\sqrt{n} } <\frac{52-57}{12/\sqrt{40} } )\\\\=P(z<\frac{-5\times6.325}{12} )\\\\=P(z<\frac{-31.625}{12})\\\\=P(z<-2.64)[/tex]

using z table

= 0.0041

The probability of the farmer will count 52 or fewer flights on average in the next 40 rows down which he drives his tractor is 0.0041 and this can be determined by using the properties of probability.

Given :

The probability of the farmer will count 52 or fewer flights on average in the next 40 rows down which he drives his tractor, can be determined by using the following calculations:

[tex]\rm P(x<52)=P\left (\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n} }}<\dfrac{52-57}{\dfrac{12}{\sqrt{40} }}\right)[/tex]

[tex]\rm P(x<52)=P\left (z<\dfrac{-5\times 6.325}{12 }}\right)[/tex]

[tex]\rm P(x<52)=P\left (z<\dfrac{-31.625}{12 }}\right)[/tex]

[tex]\rm P(x<52)=P\left (z<-2.64\right)[/tex]

Now, using z-table:

P(x < 52) = 0.0041

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Answer:

Step-by-step explanation:

image attached (representing first perpetuity on number line)

Present value is 7.21

[tex]7.21=\frac{1}{1-u^2} \\\\1-\frac{1}{7.21} =u^2\\\\\frac{6.21}{7.21} =(1+i)^{-2}\\\\(1+i)^2=\frac{7.21}{6.21} \\\\(i+1)=\sqrt{\frac{7.21}{6.21} }\\\\ i=\sqrt{\frac{7.21}{6.21} } -1\\\\=0.77511297[/tex]

image attached (representing second perpetuity on number line)

we have ,

[tex]7.21=\frac{Ru}{1-u^3}[/tex]

Here,

[tex]V=\frac{1}{1+i}[/tex]i

i = 0.077511297 + 0.01

[tex]\therefore V =\frac{1}{1.087511295} =(1.087511297)^-^1\\\\7.21=\frac{R(1.087511297)^-^1}{1-(1.087511297)^-^3} \\\\7.21=4.132664645R\\\\R=\frac{7.21}{4.132664645} \\\\R= 1.7446370\approx1.74[/tex]

Therefore, value of R is 1.74

Answer:

Step-by-step explanation:

a. Two methods of fund raising is being tested here in the first case study. To make a completely randomized experiment. I would use and randomly assign half the population of the 1000 donor sample that will be sent literature about the successful activities of the charity and asked to make another donation to one of the two treatment conditions: which is a sent literature about the successful activities of the charity. While the placebo group would be the other 500 donors contacted by phone and asked to make another donation with no influence whatever from the charity.

b. For the second case study, To make a completely randomized experiment. I would use and randomly assign 43 particupants which are to be given a gel that contains the tooth-whitening chemicals to the treatment condition containing the tooth-whitening chemicals while the placebo group would be the remaining 42 which are to be given a similar-looking package of gel that does not contain the tooth-whitening chemicals.

c. Using three blocks: the completely randomized design experiment would be:

Donors younger than 30 years old:

Sent literature: Yes No

Contact by phone: Yes No

Donors 30 to 59 years old:

Sent literature: Yes No

Contact by phone: Yes No

Donors 60 and older:

Sent literature: Yes No

Contact by phone: Yes No

(Yes means yes to another donation and No means no to another donation)

Answer:

Step-by-step explanation:

a. Two methods of fund raising is being tested here in the first case study. To make a completely randomized experiment. I would use and randomly assign half the population of the 1000 donor sample that will be sent literature about the successful activities of the charity and asked to make another donation to one of the two treatment conditions: which is a sent literature about the successful activities of the charity. While the placebo group would be the other 500 donors contacted by phone and asked to make another donation with no influence whatever from the charity.

b. For the second case study, To make a completely randomized experiment. I would use and randomly assign 43 particupants which are to be given a gel that contains the tooth-whitening chemicals to the treatment condition containing the tooth-whitening chemicals while the placebo group would be the remaining 42 which are to be given a similar-looking package of gel that does not contain the tooth-whitening chemicals.

c. Using three blocks: the completely randomized design experiment would be:

Donors younger than 30 years old:

Sent literature: Yes No

Contact by phone: Yes No

Donors 30 to 59 years old:

Sent literature: Yes No

Contact by phone: Yes No

Donors 60 and older:

Sent literature: Yes No

Contact by phone: Yes No

(Yes means yes to another donation and No means no to another donation)

Answer: THE SOLUTION IS B

x=4  gives the linear factor x-4

x=6 gives the linear factor x-6

Step-by-step explanation:

Correction

The revenue function for a school group selling n bookmarks is given by R(n) =2n and the total cost function is given by C(n)=144+0.08n. Determine the number of bookmarks sold at which they break-even.

Answer:

75 bookmarks

Step-by-step explanation:

The break-even point is the point at which revenue earned is equal to the cost of production.

Given the cost and revenue functions respectively:

Cost=Revenue

C(n)=R(n)

144+0.08n=2n

144=2n-0.08n

144=1.92n

Divide both sides by 1.92

n=75

When 75 bookmarks are sold, the school group will break even.

Complete Question

The complete question is shown on the first uploaded image

Answer:

The confidence level interval is  [tex]0.016 \le C \le 0.404[/tex]

Step-by-step explanation:

The sample size is  [tex]n = 20[/tex]

The number planning to increase workforce is  [tex]x = 3[/tex]

 The confidence level is  [tex]c = 98[/tex]%

The value of proportion for a plus 4 method is

      [tex]p = \frac{x+2}{n+4}[/tex]

substituting values

      [tex]p = \frac{3+2}{20+4}[/tex]

       [tex]p =0.21[/tex]

The z-critical value at confidence level of 98% is

     [tex]z_{c}=z_{0.98} = 2.33[/tex]

This values is obtained from the standard normal table

The confidence level interval can be mathematically represented as

      [tex]C =p \ \pm z_{c} * \sqrt{\frac{p(1-p)}{n+4} }[/tex]

substituting values

      [tex]C = 0.21 \pm 2.33 * \sqrt{\frac{0.21(1- 0.21)}{20 +4} }[/tex]

       [tex]C = 0.21 \pm 0.194[/tex]

=>   [tex]0.016 \le C \le 0.404[/tex]

Answer: obtuse and scalene

Step-by-step explanation:

Answer:

Obtuse And Scalene

Step-by-step explanation:

trust me!

The transformation matrix for the mapping T is the matrix T such that

[tex]\mathbf T(\vec x)=T\,\vec x[/tex]

where

[tex]T=\begin{bmatrix}1&4&0&0\\0&0&0&0\\0&3&0&1\\0&1&0&-1\end{bmatrix}[/tex]

The correct matrix A is

[tex]A=\left[\begin{array}{cccc}1&4&0&0\\0&0&0&0\\0&3&0&1&0&1&0&-1\end{array}\right][/tex]

To find the matrix A that represents the linear transformation T, we need to determine the coefficients that map the input vector (X₁, X₂, X₃, X₄) to the output vector (x₁ +4x₂, 0, 3x₂ +x₄, x₂ -x₄)

By comparing the corresponding entries in the input and output vectors, we can determine the coefficients of the matrix A.

The first row of A will have the coefficients for X₁ and X₂, which are 1 and 4 respectively. The second row will have all zeros since the output vector has a zero in the second position. The third row will have the coefficient 3 for X₂ and 1 for X₄. Finally, the fourth row will have the coefficient 1 for X₂ and -1 for X₄.

Thus, the matrix A that implements the mapping T is:

[tex]A=\left[\begin{array}{cccc}1&4&0&0\\0&0&0&0\\0&3&0&1&0&1&0&-1\end{array}\right][/tex]

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Answer:

Step-by-step explanation:

=20

This take 30 minutes to finish filling the remaining jugs.

To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

Given that;

A person needs to fill 20 water jugs with a hose. Filling the first 2 jugs has taken 3 minutes.

Now,

Let the time to finish filling the remaining jugs = x

Since, A person needs to fill 20 water jugs with a hose. Filling the first 2 jugs has taken 3 minutes.

Hence, By definition of proportion we get;

⇒ 20 / x = 2 / 3

⇒ 20 × 3 / 2 = x

⇒ x = 30

Thus, The time to finish filling the remaining jugs =  30 minutes

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Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = proportion of households that have three cell phones NOT known.

So, Null Hypothesis, [tex]H_0[/tex] : p = 30%      {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, [tex]H_A[/tex] : p [tex]\neq[/tex] 30%     {means that the actual percentage of households different from 30%}

The test statistics that would be used here One-sample z-test for proportions;

                                T.S. =  [tex]\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }[/tex]  ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of households having three cell phones = [tex]\frac{43}{150}[/tex] = 0.29

           n = sample of households = 150

So, the test statistics  =  [tex]\frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }[/tex]  

                                     =  -0.27

The value of z test statistic is -0.27.

Also, P-value of the test statistics is given by;

              P-value = P(Z < -0.27) = 1 - P(Z [tex]\leq[/tex] 0.27)

                            = 1 - 0.6064 = 0.3936

Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the actual percentage of households is equal to 30%.

Answer:

yes it does

17 is the longest side.

Iff  Iff 17%5E2+=+8%5E2+%2B+15%5E2 it's a right triangle.  it's a right triangle.

Ps "iff" means if and only if

hope it helps

if so please mark me  as brainliest

Answer:

[tex]\frac{1}{3}[/tex] probability of drawing a bead which is not a pearl

Step-by-step explanation:

For each bead that you draw, there are only two possible outcomes. Either it is a pearl bead, or it is not. The sum of these probabilities = 100% = 1.

So

2/3 probability of drawing a pearl bead.

p probability of drawing a non pearl bead.

What is the probability of drawing a bead which is not a pearl?

[tex]p + \frac{2}{3} = 1[/tex]

[tex]p = 1 - \frac{2}{3}[/tex]

[tex]p = \frac{3*1 - 2}{3}[/tex]

[tex]p = \frac{1}{3}[/tex]

[tex]\frac{1}{3}[/tex] probability of drawing a bead which is not a pearl

Answer:

C

Step-by-step explanation:

Answer:

[tex]P(x>20)=9.67*10^{-10}[/tex]

Step-by-step explanation:

If we call x the number of correct answers, we can said that P(x) follows a Binomial distribution, because we have 25 questions that are identical and independent events with a probability of 1/4 to success and a probability of 3/4 to fail.

So, the probability can be calculated as:

[tex]P(x)=nCx*p^{x}*q^{n-x}=25Cx*0.25^{x}*0.75^{25-x}[/tex]

Where n is 25 questions, p is the probability to success or 0.25 and q is the probability to fail or 0.75.

Additionally, [tex]25Cx=\frac{25!}{x!(25-x)!}[/tex]

So, the probability that the student answers more than 20 questions correctly is equal to:

[tex]P(x>20)=P(21)+P(22)+P(23)+P(24)+P(25)[/tex]

Where, for example, P(21) is equal to:

[tex]P(21)=25C21*0.25^{21}*0.75^{25-21}=9.1*10^{-10}[/tex]

Finally, P(x>20) is equal to:

[tex]P(x>20)=9.67*10^{-10}[/tex]

Answer:

A and B

Step-by-step explanation:

1) Distance to the focus

From (x,y) to the focus(2,-4) {using distance formula}

=√(x-2)²+(y+4)²

2) Distance to the directrix

Is, y+p where P here is (-6)

So

d2 = y+p

= y+(-6)

= y-6