Florida's No-Fault requires owners of motor vehicles must cover the
below minimum Personal Injury Liability (PIP) insurance coverage:
o $10,000 of Personal Injury Protection (PIP)
o $30,000 of Personal Injury Protection (PIP)
o $50,000 of Personal Injury Protection (PIP)
o $100,000 of Personal Injury Protection (PIP)

Answers

Answer 1

Answer:

The correct option is;

$10,000 of Personal Injury Protection (PIP)

Explanation:

Personal injury protection, PIP, otherwise known as No-Fault Law coverage is a part of auto insurance that takes care of medical cost of treatment of an accident victim regardless of who is at fault

In Florida, the No-Fault Law requires motor vehicle owners to have and retain PIP providing $10,000 in medical care, resulting disability and expenses of a funeral resulting from an accident in which the motorist is involved

Therefore, the correct option is $10,000 of Personal Injury Protection.

Answer 2
What they said^^^^^^^

Related Questions

What is one way a C47 can be used on set?

Answers

Answer:

C47 may seem like a fancy word, but in the film world, it is the name of one of the simplest, most useful and versatile tools, which is commonly knows as a clothespin.

Following are major uses of C47 on a film set.

1) Lightning Purposes

C47 are used for attaching materials like gel and diffusion to the adjustable flaps, that control the direction of light

2) Adjusting Wardrobes

C47 are used to shorten, tighten or redesign a material of clothing for a specific purpose. It avoids permanent change and the hassle of sewing.

3) Modifications

These can be used for temporary repairs or to modify the set and shooting locations, e.g if a curtain is not hanging properly, C47 can be used

It transfers military men

Luis is installing some 12 gage wire. How much resistance will there be throughout a distance of 400 feet

Answers

Answer:

0.635 m

Explanation:

When calculating the resistance R of a wire, we need  its length(l), its cross-sectional area (A) and the resistivity of the material(ρ). The resistance of a wire  is given by the equation:

Resistance (R) = Resistivity(ρ) × length (l) / cross-sectional area (A)

For a 12 guage wire,

Resistivity (ρ) = 1.724 × 10 ⁻⁸ ohm m, length (l) = 400 ft = 121.92 m,

Diameter (d) = 0.00205232, cross-sectional area (A) = πd²/4 = π(0.00205232)²/4 = 3.31 × 10 ⁻⁶ m²

[tex]R=\frac{\rho l}{A}=\frac{1.724*10^{-8}*121.92}{3.31*10^{-6}} =0.635m[/tex]

The answer is 0.635 m that’s the answer
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