he number-average molecular weight of a polypropylene is 1,000,000 g/mol. Compute the degree of polymerization.

a) A1₂S₃ + 6H₂O → 3H₂S + 2Al(OH)₃ +3H₂S

b) 5.72grams of aluminum hydroxide.

It demonstrates that each molecule of aluminum sulfide yields two molecules of aluminum hydroxide, or two molecules of Al(OH)3 for every molecule of aluminum sulfide.

Al(OH)3 has a molecular weight of 78 while Al2S3 has a molecular weight of 150. Starting with 5.5 grams of aluminum sulfide, we can set up the ratio by dividing it by 150 to get x/156.

5.5/ 150 = x/156

where x represents the quantity of Al(OH)3 that was created.

Since two moles of Al(OH)3 are created for every mole of Al2S3 that reacts, we utilize 156, which is twice as much as 78. As a result, we arrive at x = (5.5)(156)/150 = 5.72 gm. To the nearest decigram, we obtain 5.72grams of aluminum hydroxide.

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Answer:

CO2 < CH3Br < CH3OH < RbF

Explanation:

The boiling point of the compounds can be determined in terms of the strength of the intermolecular forces present in each compound.

Intermolecular forces are weak forces joining non-polar and polar molecules together. We have London dispersion forces, dipole-dipole forces of attraction, and hydrogen bonding.

London dispersion forces are weak attractions found between non-polar and polar symmetrical molecules. They are the weakest of all the electrical forces and they act between atoms and molecules e.g CO2

The dipole-dipole attractions are forces of attraction existing between polar unsymmetrical molecules. The dipole-dipole force of attractions is much stronger than London dispersion forces but weaker than Hydrogen bonding. e.g  CH3Br

Hydrogen bonding is a special dipole-dipole attraction between polar molecules in which a hydrogen atom is directly joined to a highly electronegative atom (e.g. oxygen, nitrogen, or fluorine). Here, the bond in CH3OH is a hydrogen bond.

Ionic bonding is a bond that is formed between two kinds of atoms having a large electronegative difference such as in RbF,

Thus, in increasing order of boiling point;

CO2 < CH3Br < CH3OH < RbF

The mass in grams of 255mL of mercury if it has a density of 13.34g/mL is 3401.7g.

The mass of a substance can be calculated by multiplying the volume of the substance by its density as follows:

Mass = density × volume

According to this question, 255mL of mercury has a density of 13.34g/mL. The mass is calculated as follows:

Mass = 13.34g/mL × 255mL

Mass = 3401.7g

Therefore, the mass in grams of 255mL of mercury if it has a density of 13.34g/mL is 3401.7g.

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Answer:

a. 2.6 x 102 ms

Explanation:

Initial mass [Ao] = 99 g

Final mass [A] = 0.50 g

Half life (t1/2) = 35 ms

Time ( t ) = ?

]The integrated rate law for first order reactions is given as;

To obtain k, we look at the expression for the half life of a first order reaction;

t1/2 = 0.693 / k

k = 0.693 / 35 = 0.0198 ms-1

ln[A] = ln[Ao] - kt

kt = ln[Ao] - ln[A]

t =   ( ln[Ao] - ln[A]  )  / k

t =  ( ln(99) - ln (0.50)  )  /  0.0198

t = 5.288 / 0.0198

t = 267.07 ms

correct option is;

a. 2.6 x 102 ms

when nitric oxide reacts with oxygen GIVES Nitrogen dioxide.

NO(g)+ [tex]0_2[/tex]=2N[tex]O_2[/tex] is the balanced reaction

here, from the above reaction, we have found that

1 mole of NO and 2 mole of [tex]0_2[/tex] gives 2 mole of N[tex]O_2[/tex]

from the mole concentration, we can conclude that oxygen is limiting reactant.

A limiting reactant is an active ingredient in a reaction that is totally consumed by its conclusion. The limiting reactant determines how much product is produced in a chemical process.

In a chemical reaction, the reactants react in a stoichiometric sequence to produce the products. The limiting reactant is the one that is present in lower stoichiometric amounts. The amount of the product created depends on how much of the limiting reactant is used up in the reaction. Excess reactants are the additional reactants in the reaction besides the limiting reactants.

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Answer:

The percent composition of a component in a compound is the percent of the total mass of the compound that is due to that component. To calculate the percent composition of a component in a compound: Find the molar mass of the compound by adding up the masses of each atom.

Answer:bromine , neon , helium , argon , lithium , beryllium

Explanation:

Elements can be divided into three state that are solid, liquid and gas depending the intermolecular forces of attraction, distance between the particles etc. Lithium, beryllium, boron, carbon, sodium, magnesium, iron, copper, etc. are solid at room temperature.

Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same.

Two or more than two atoms with different physical or chemical properties can not combine together to form an element. Elements can be solid liquid or gas at room temperature.

Therefore,  Lithium, beryllium, boron, carbon, sodium, magnesium, iron, copper, etc. are solid at room temperature.

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The amount that the child should receive is 10 mg.

The term dose refers to the amount of drugs that a person should take. The dose of the drug  is in proportion to the magnitude of the illness. The more severe the symptoms, the higher the dosage.

Since the child is to receive only 20% of the adult dose, we have;

20/100 * 50.0 mg

= 10 mg

The amount that the child should receive is 10 mg.

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Answer:

the answer is neurtons

Explanation:

Mass of Zirconium (Zr) in 0.040 moles : 3.6 g

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

[tex]\tt n(mol)=\dfrac{m(mass)}{MW(molecular~weight)}[/tex]

moles of Zirconium : 0.04

mass of Zirconium (MW=91,224 g/mol) :

[tex]\tt mass=mol\times MW\\\\mass=0.04\times 91,224\\\\mass=3.6~g[/tex]

Answer:

Q8) True

Q9) First ionization energy

Q10) Metal oxides

Explanation:

A common property of group one elements (alkali metals) is their combination with water to form basic solutions. E.g 2K(s)+2H2O(l)→2KOH(aq)+H2​(g).

The distance of the outermost electron in the atom from the nucleus is inversely related to the first ionization energy. As the distance between the outermost electron and the nucleus in group 17 elements gets larger, the corresponding first ionization energies of elements in the group gets smaller.

Group 1 elements can combine with oxygen to give metal oxides. E.g  4K + O2 --> 2 K2O

Answer:

B. Protons and Electrons

Explanation:

Protons have a positive charge and electrons have a negative charge. When an element contains the same number of both of those particles the charges will cancel out leaving the atom with a neutral charge, as neutrons already have a neutral charge.

Answer:

The answer is 59

Explanation:

Answer:

what are the options? I'll edit my answer to the correct one once you inform me lol

Answer:

Superscript 6 Subscript 2 Baseline Upper H e right arrow Superscript 6 Subscript 3 Baseline Upper L i + Superscript 0 Subscript negative 1 Baseline e

Explanation:

Helium decays by beta emission, in beta emission, the mass number of the parent and daughter nuclei are the same but the atomic number of the daughter nucleus increases by one hence it is found one place to the right of its parent in the periodic table.

Having said this, the decay of Helium to lithium may be written as follows;

6/2He -> 6/3Li + 0/-1e

Answer:

C

Explanation:

Edge 2020

Answer:snow i think

Explanation:

Answer:

snow

Explanation:

Answer:

East

Explanation:

Given Newton's third law of motion; "Action and reaction are equal and opposite", when a student jumps off a sled toward the west after it stops at the bottom of an icy hill, the sled will move in the East direction.

This is because, the force exerted on the sled is a reaction force and is opposite in direction to the force that thrusts the boy westward though equal in magnitude with the former.

Answer:

Answer:

D. fusing 5 kg of hydrogen.

Explanation:

So to answer this question first let's decribe precision vs accuracy.

Precision in this case means exact and accurate; in this scenario all of the dots next to each other mean that it is highly precise.

Whereas Accuracy means aiming for the middle of the circle in this case. Thus   the accuracy is low, but the precision is high.

TLDR: It is highly precise but not accurate.

Look up "Accuracy vs. Precision: What’s the Difference?" for a better detailed example and solution.

Answer:

ATP is a stored form of energy

Explanation:

it is the main source of this

Answer:

The correct answer is Pu, 234.

Explanation:

In the given case, let us consider the reactant as X. Now the mass number (balanced) on both the sides will be,

Mass of X = Mass of Molybdenum + Mass of Tin + Mass of neutrons

M = 1 * 103 + 1 * 131 + 2 * 0

M = 234

Now the atomic number (balanced) on both the sides,

Atomic number of X = Atomic number of Molybdenum + Atomic number of Tin + Atomic number of neutrons

A = 1*42 + 1*50 + 2*1

A = 94

The atomic number 94 is for the element Plutonium, whose symbol is Pu. Thus, the reactant is 234-Pu.

Answer:

Each principal energy level has one sublevel containing one orbital, an s orbital, that can contain a maximum of two electrons.

Explanation:

Answer:

2n

Explanation:

This question is incomplete, the complete question is;

A 1.00 g sample of NH4NO3 is decomposedin a bomb calorimeter. The temperature increases by 6.12°C. What is the molar heat of decomposition for ammonium nitrate?

Molar mass, NH4NO3 80.0 g/mol

Calorimeter Constant   1.23 kJ/°C

Answer:

the molar heat of decomposition for ammonium nitrate is - 602.4 kJ/mol

Explanation:

Given that;

change in temperature ΔT = 6.12 °C

Calorimeter Constant C = 1.23 kJ/°C

Molar mass, NH4NO3 = 80.0 g/mol

we know that;

Heat gained by the calorimeter (Q1) = Heat lost by the decomposition of NH4NO3 (Q2)

Q1 = C × ΔT

Q1 = (1.23 kJ/K) × (6.12 K) = 7.53 kJ

Q value we get becomes negative since we are talking about reaction and not calorimeter

hence

Q1 = - 7.53 kJ

now

1 g NH4NO3 decomposed, - 7.53 kJ of heat is released

so if 80 g which is 1 mol NH4NO3 decompose, the heat will be;

(80 g/mol x -7.53 kJ) / 1 g = - 602.4 kJ/mol

Therefore the molar heat of decomposition for ammonium nitrate is - 602.4 kJ/mol

Viscosity is an crucial factor in food preparation and serving. Cooking oils' viscosity may or may not change as they heat, but many become much more viscous as they cool.

Viscosity refers to the resistance of a fluid (liquid or gaseous state) to a shape shift or mobility of neighboring portions relative to one another. Viscosity indicates flow resistance.

Gathering viscosity data on a material allows manufacturers to predict how the material will start behaving in the real world. For example, if toothpaste does not have the correct viscosity, it may be difficult or impossible to pump out of the tube.

Thus, it is important to have the knowledge of viscosity.

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Answer:

HCl

Explanation:

Volume = 25L

Temperature = 25.0 oC + 273 = 298 K (Converting to kelvin units)

Pressure = 1.2 atm

Mass of gas = 44.7g

Formular of gas = HX

To solve this, we have to know the identity of X. One qay to do that is by obtaining the molecular mass of the compound.

To get the molar mass, we need the number of mole.

Using the ideal gas equation;

PV = nRT

where R = gas constant = 0.082 057 L atm K−1  mol−1

n = PV / RT

n = 1.2 * 25  / 0.082 057 * 298

n = 30  /  24.45

n = 1.227 mol

The relationship between number of moles and molar mass is given as;

Nummber f moles = mass  / molar mass

Molar mass = mass  / Number of moles

Molar mass = 44.7 / 1.227

Molar mass =  36.43 g/mol

Molar mass of gas X = Molar mass of H + Molar mass of X

36.43 = 1 + X

X = 36.43 - 1 = 35.43

Chlorine is the only element with molar mass approximate to 35.43

Hence X = Cl

The chemical formular = HCl

Answer: Two equatorial positions so as to minimize the repulsion.

Explanation:

Formula used for calculating number of electrons :

[tex]\frac{1}{2}[V+N-C+A][/tex]

where,

V = number of valence electrons present in central atom  = 8

N = number of monovalent atoms bonded to central atom = 4

C = charge of cation  = 0

A = charge of anion  = 0

Now we have to determine the hybridization of the [tex]XeF_4[/tex]   molecule.

[tex]\frac{1}{2}[8+4-0+0]=6[/tex]

Bond pair electrons = 4

Lone pair electrons = 2

The number of electrons are 6 that means the hybridization will be [tex]sp^3d^2[/tex] and the electronic geometry of the molecule will be octahedral.

The molecular geometry will be square planar as two alternate positio ns will be occupied by lone pair of electrons so as to minimize the repulsion.

Answer:

False

Explanation:

Answer

is it FALSE?

I always answer question but people don't ever give me brainiest that why i got 0