Help me please (btw I live in the U.S)

Answer:

The atom contains a vey small small nucleus that contains most of its mass.

Explanation:

The Rutherford gold leaf experiment concluded that most (99%) of all the mass of an atom is in the nucleus of the atom, that the nucleus is very small (105 times small than the size of the atom) and that is is positively charged.

Answer: FeF3      Iron(III) fluoride

Explanation: 5.6 g = 1/10 mole Fe

11.3-5.6g F = 5.7 = 3/10 mole F

Answer:

13.22 L

Explanation:

Given data:

Volume of ammonia = ?

Mass of ammonia = 10.0 g

Temperature = standard = 273.15 K

Pressure = standard = standard = 1 atm

Solution:

First of all we will calculate the number of moles of ammonia.

Number of moles = mass/molar mass

Number of moles = 10.0 g/ 17 g/mol

Number of moles = 0.59 mol

one mole of any substance at standard temperature and pressure occupy 22.41 L . Thus, 0.59 moles of ammonia will occupy,

0.59 mol × 22.4 L / 1 mol

13.22 L

Answer: 12.4L

Explanation:

mw NH3 18

1 mole = 22.4L

10g = 10/18 moles

Answer:

3rd law

Explanation:

His third laws states that every action has an equal and opposite reaction. because you are putting force on your wall, the wall is giving the force of wall on your finger.

sorry i can only figure out 1 but the answer is

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124

hope you do good on your test :D

Answer:

19 electrons in first group of 4th period element that is potassium K

Explanation:

Answer: 0.800 M

Basically, the ratio is 2:1, so when you have 1 M of Li2HPO4 it means you have 2 M in the concentration of lithium ions. So knowing the ratio, we know we just need to multiply 0.400 x 2.

I'm bad at explaining it, but got it right on chem101 sooo

The concentration of lithium ion, Li⁺ in 0.4 M Li₂HPO₄ is 0.8 M.

The concentration of a substance is simply the amount of the substance in 1 L of water.

To obtain the concentration of lithium ion, Li⁺ in Li₂HPO₄, we'll begin by writing the dissociation equation of Li₂HPO₄. This is illustrated below:

From the balanced equation above,

1 mole of Li₂HPO₄ produced 2 moles of Li²⁺.

Finally, we shall determine the concentration of lithium ion, Li⁺ in 0.4 M Li₂HPO₄. This can be obtained as follow:

From the balanced equation above,

1 mole of Li₂HPO₄ produced 2 mole of Li⁺.

Therefore, 0.4 M Li₂HPO₄ will produce = 2 × 0.4 = 0.8M Li²⁺

Thus, 0.8 M lithium ion, Li⁺ is present in the solution.

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Answer:

What is ^ for?

Explanation:

Answer:

The water phase with the smallest temperature increase when adding 10 kcal of heat is solid ice.

Explanation:

The rest of the statements are incorrect. The density of ice is lower than the density of water. The heat capacity of solid ice is greater almost twice the heat capacity of the liquid water. The heat capacity of vapors is less than heat capacity of liquid.

Answer:

the flow rate of the gas stream leaving the condenser is 71.9 moles/min

Explanation:    

Given the data in the question and the figure below;

N2 BALANCE

(100% - 18%) × ( mole rate in ) = ( 100% - 5%) × ( mole rate out)

0.82 × ( mole rate in ) = 0.95 × ( mole rate out)

mole rate in = 0.95 × ( mole rate out) / 0.82

mole rate in = 1.1585365853 × ( mole rate out)

now;

HEXANE BALANCE

0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate  --- equ 1

but condensate = 1.5 L/min × ( density of hexane ) × 1/molar mass of hexane

we know that;

density of hexane is 0.6548 g/mL

and molar mass of hexane is 86.18 g/mol

so,

condensate = 1.5 L/min × ( 0.6548 g/mL × 1000 mL/L ) × ( 1/86.18 g/mol)

condensate = 11.3970758876

now lets substitute into equation 1

0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate

⇒ 0.18 × ( 1.1585365853 × ( mole rate out) ) = 0.0500 × ( mole rate out) + 11.3970758876

⇒ 0.208536585354(mole rate out) = 0.0500( mole rate out) + 11.3970758876

⇒ 0.208536585354(mole rate out) - 0.0500( mole rate out) = 11.3970758876

⇒ 0.158536585354(mole rate out) = 11.3970758876

mole rate out = 11.3970758876 / 0.158536585354

mole rate out =  71.889247 ≈ 71.9 moles/min

Therefore, the flow rate of the gas stream leaving the condenser is 71.9 moles/min

Answer:

30 yard per second

Explanation:

300/10 = 30

Answer:

2812.6 g of H₂SO₄

Explanation:

From the question given above, the following data were obtained:

Mole of H₂SO₄ = 28.7 moles

Mass of H₂SO₄ =?

Next, we shall determine the molar mass of H₂SO₄. This can be obtained as follow:

Molar mass of H₂SO₄ = (1×2) + 32 + (16×4)

= 2 + 32 + 64

= 98 g/mol

Finally, we shall determine the mass of H₂SO₄. This can be obtained as follow:

Mole of H₂SO₄ = 28.7 moles

Molar mass of H₂SO₄ =

Mass of H₂SO₄ =?

Mole = mass / Molar mass

28.7 = Mass of H₂SO₄ / 98

Cross multiply

Mass of H₂SO₄ = 28.7 × 98

Mass of H₂SO₄ = 2812.6 g

Thus, 28.7 mole of H₂SO₄ is equivalent to 2812.6 g of H₂SO₄

Answer:

[tex]APF(atomic packing factor)=0.31736[/tex]

Explanation:

From the question we are told that

Density of metal [tex]\rho=11.6 g/cm3[/tex]

Atomic weight of [tex]W=157.6 g/mol[/tex]

Atomic radius of [tex]r= 0.127 nm[/tex]

Lattice parameters=>[tex]x=0.523nm[/tex]  and [tex]y=0.330 nm[/tex]

Generally the equation for atomic packing factor is mathematically given as

[tex]APF(atomic packing factor)=\frac{Spere's\ volume}{unit\ cell\ volume}[/tex]

[tex]APF(atomic packing factor)=\frac{N*VN}{VC}[/tex]

Generally the equation for number of atoms N is mathematically given as

[tex]N=\frac{\rho }{atomic raduis*Avacados constant}[/tex]

[tex]N=\frac{11.6 }{0.127*10^{-9}*6.02214086*10^{23} mol-1}[/tex]

[tex]N=4[/tex]

Therefore APF(atomic packing factor)

[tex]APF(atomic packing factor)=\frac{N*VN}{VC}[/tex]

[tex]APF(atomic packing factor)=\frac{4*\frac{4}{3} \pi (0.127)^3}{(0.523)^2 *0.330}[/tex]

[tex]APF(atomic packing factor)=0.31736[/tex]

Answer:

side-by-side, or lateral orbital overlap with the electron density concentrated on opposite sides of the internuclear axis.

Explanation:

Pi bond is a type of covalent bond in which the internuclear axis has regions of orbital overlap below and above it i.e on opposite sides. As a result of the orbital overlap, a node is created along the internuclear axis.

This ultimately implies that, a pi bond is formed due to the lateral (side-by-side) overlap of the unhybridized P-orbital comprising of at least a node along the internuclear axis.

Hence, a pi bond involves side-by-side, or lateral orbital overlap with the electron density concentrated on opposite sides of the internuclear axis.

Additionally, a node is typically formed where an electron cannot be found.

Answer:

Glucose!!

Explanation:

Also keep in mind that the actual sugar produced from photosynthesis is C6H12O6, which is the basis for glucose as well as other complex molecules

Answer:

Glucose

Explanation:

photosynthesis uses the energy from the light to convert carbon dioxide molecules which makes glucose

Answer:

1-6

3 1 3 3 2 2

Explanation:

Answer:

The answer to your question is D. 25 grams.

Answer

22 grams hope this helps

Answer:

90 mV

Explanation:

Faraday constant, F = 96487

Gas constant, R = 8.314

Number of mole of electron transferred, Z = 2

MgCl in solution A, = 0.1 mm

MgCl in solution A, = 100 mm

Using the relation :

E=(RT/ZF) In(Mg out/Mgin)

E = (8.314*298) / (2*96485) * In(100/0.1)

E = (2477.572 / 192970) * 6.9077552

E = 0.0128391 * 6.9077552

E = 0.0886897 V

E = 88.68 mV (approximately 90 mV)

Answer:

The name of the process happening in the picture is explained below in details.

Explanation:

The process in the picture is photosynthesis. The plant is taking CO2 and H2O and using light to form glucose which would be the sugars and creating a byproduct of oxygen that is being released into the atmosphere. How did you know this is photosynthesis? A big thing clearly is the plant and how it’s taking H2O and CO2 and making glucose so it isn’t cellular respiration (if you don’t know what that is don’t worry, if you are learning about this you are bound to come across that later) and it’s releasing oxygen into the atmosphere and light has a function in this process according to the image.

Answer:

1.34 * 10^-7 M

Explanation:

The Ksp of lead II chromate is 1.8 x 10^-14

So, we have that;

PbCrO4(s) -----> Pb^2+(aq) + CrO4^2-(aq)

                             s                  s

Where s = molar concentration of Pb^2+(aq) and  CrO4^2-(aq)

and;

[Pb^2+] = [CrO4^2-]

This implies that Ksp = s^2

s = √Ksp

s = √1.8 x 10^-14

s = 1.34 * 10^-7 M

Answer:

44.84 ml

Explanation:

14.86

+

15.0

+

14.980

_______

44.84

Answer:

See explanation below

Explanation:

According to what you state in the problem, we have an ethyne bonded to a cyclopentane.

So, in the 1st step reacts with NaNH₂. In this step, the base which is very strong will substract the hydrogen from carbon 2, forming an anion in there. In the second step, this anion will react with  CH₃I, and form a larger chain, the methyl group is attached to the alkyne.

Finally in the last step reacts with sodium in ammonia, this is to reduct the triple bond to just a single bond and leave an alkane only. The picture below shows these steps.

Hope this helps.

Answer:

The balanced molecular equation for the reaction is:

[tex]2HNO_{3_{(aq)} }[/tex] + [tex]K_{2} CO_{3} _{(s)}[/tex] → [tex]2KNO_{3} _{(s)}[/tex] + [tex]H_{2} O_{(l)[/tex] + [tex]CO_{2} _{(g)}[/tex]↑

Explanation:

The weak nitric acid reacts with the strong potassium base to produce salt, water and carbon dioxide which is given off.

Molecular ratio of reactants is 2 : 1.

All phases are represented in the equation: aq for aqueous, l for liquid and g for gas (notice how they are written in subscript).

I hope this was helpful.

Answer:

The equilibrium concentrations of HF = 0.058 , F2 = 0.006M , HClO =0.16M , and ClO2 = 7.7 × 10⁻⁷M.

Explanation:

The Ka values for HClO₃ and HF are given as 2.9 × 10⁻⁸ and 6.6 × 10⁻⁴ respectively. The molar concentration for HF = 0.23/ 3.60L = 0.064 M and 0.57/ 3.60 = 0.16 M.

When HF is reacted with water, it ionizes to form H₃O⁺ and F⁻. The concentration of H₃O⁺ and F⁻ can be calculated below:

HF(aq) <------------------------> H30^+ + F^-.

Ka = [H^+] [F^-]/[HF] .

6.6× 10^-4 = [x][x]/ ( 0.064- x).

x = 0.0060 M.

The concentration of H₃O⁺ and F⁻ = 0.0060 M respectively.

The pH = - log [ H₃O⁺ ] = -log [0.0060] = 2.22.

When HClO is reacted with water, it ionizes to form H₃O⁺ and F⁻. The concentration of H₃O⁺ and ClO⁻ can be calculated below:

HClO(aq) <------------------------> H30^+ + ClO^-.

Ka = [H^+] [ClO^-]/[HClO] .

6.6× 10^-4 = [0.006 + x] [x]/ ( 0.16 - x).

x = 7.7 × 10^-7M.

[ClO^-] = 7.7 × 10^-7 M.

[HClO] = 0.16 - 7.7 × 10^-7 = 0.16M.

[F^-] = 0.006 M.

[HF] = 0.064 - 0.006 = 0.058 M.

Answer:

B.

Explanation:

Answer:

B is the correct answer

Explanation:

The percent by weight (w/w%) of sugar in soda : 6.216%

Given

mass of sugar = 23 g

total mass = 370 g

Required

the percent weight

Solution

%weight = (mass of solute : mass of solution) x 100%

solute = sugar

solution = solvent + solute = water + sugar

percent weight of sugar in soda :

= (23 : 370) x 100%

= 6.216 %

b = 0;

this (x, y);

this(0, 0);

x = a;

y = b;

a =x

This above solution is just according to the public boolean equals(Point p) { return (x == p.x && y == p.y ); and public void equals(Point p) { System.out.println(x == p.x && y == p.y);}

An abstract class contains a pure virtual function. Pure virtual class cannot be instantiated but it can be subclassed and the subclass can provide an implementation of the function.

A virtual function declaration in the class is preceded by the virtual keyword. For example, virtual void print();

A pure virtual function declaration is followed by '=0;'

public: virtual void print()=0;

The main method header is written as public static void main(String[] args). A main method is something that is required in Java. You must have at least one class with a method named main. In Java, main is a static method, which means that it is part of its class but not parts of objects.

Therefore, This above solution is just according to the public boolean equals(Point p) { return (x == p.x && y == p.y ); and public void equals(Point p) { System.out.println(x == p.x && y == p.y);}

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