Answer:
Step-by-step explanation:
The test to use is the t-test of independent means.
To determine the cutoff for the study then you need to find the degree of freedom and the alpha level. After the hypothesis testing, the calculated t value is then compared to the critical t value from the t distribution table using the degrees of freedom.
The relationship of variance and mean informs researchers about the spread of data. If a researcher calculates the mean abundance per unit area of a species, and then calculates the variance, the relationship between mean and variance will reflect the distribution pattern.
Which distribution pattern pictured below will have variance greater than the mean?
Answer:
The distribution pattern that will have variance greater than mean is one where the population of species is clustered and thus far from the mean abundance of species per unit area.
This distribution pattern can be found, using the POISSON distribution.
Step-by-step explanation:
Variance is a measure of dispersion while Mean is a measure of central tendency.
The mean is the average of all values (in this case, the abundance or concentration of species per unit area). It is the sum total of all values, divided by the number of values there are.
The variance of a given set of data, on the other hand, is a measure of the spread or distance or dispersal of the data from the mean. It measures the spread between each datum/value and the mean value.
The relationship between mean and variance surely reflects the pattern that the distribution will take. The kind of distribution pattern that will have a greater variance than mean is a Poisson distribution. Sample size is usually large here. Since the variance is greater than the mean, the population is a clustered or clumped distribution.
The probability that a member of a certain class of homeowners with liability and property coverage will file a liability claim is 0.04, and the probability that a member of this class will file a property claim is 0.10. The probability that a member of this class will file a liability claim but not a property claim is 0.01. Calculate the probability that a randomly selected member of this class of homeowners will not file a claim of either type.
Answer:
The probability that a randomly selected member of this class of homeowners will not file a claim of either type is 0.89.
Step-by-step explanation:
Denote the events as follows:
X = liability claim will be filled
Y = property claim will be filled
The information provided is:
P (X) = 0.04
P (Y) = 0.10
P (X ∩ Y') = 0.01
The probability that a randomly selected member of the class of homeowners will not file a claim of either type will be given by:
[tex]P[(X\cup Y)']=1-P(X\cup Y)=1-[P(X)+P(Y)-P(X\cap Y)][/tex]
According to the law of total probability:
[tex]P(B)=P(B\cap A)+P(B\cap A')[/tex]
Use the law of total probability to determine the value of P (X ∩ Y) as follows:
[tex]P(X)=P(X\cap Y)+P(X\cap Y')\\\\P(X\cap Y)=P(X)-P(X\cap Y')\\\\=0.04-0.01\\\\=0.03[/tex]
The value of P (X ∩ Y) is 0.03.
Compute the value of P (X ∪ Y) as follows:
[tex]P[(X\cup Y)']=1-P(X\cup Y)[/tex]
[tex]=1-[P(X)+P(Y)-P(X\cap Y)]\\\\=1-[0.04+0.10-0.03]\\\\=1-0.11\\\\=0.89[/tex]
Thus, the probability that a randomly selected member of this class of homeowners will not file a claim of either type is 0.89.
The sum of two numbers is 978. One of the numbers is 152. What is the other number?
Answer:
826
Step-by-step explanation:
a+b=978
a=152
b=978-152=826
4x-y+ 2z=-1
Given the system -x+2y + 5z = 2, which is true?
|-x+y-3z= 1
Answer:
Y = 0
X= 1/2
Z = -1/2
Step-by-step explanation:
4x-y+ 2z=-1
-x+y-3z= 1
-x+2y + 5z = 2
Solving simultenously
Y= 4x + 2z -1
Y =1+ 3z+ x
Y =x/2 -( 5z/2) - 1
Equating y will give two equations
3x-z = 2
3x + 11z = -4
Subtracting the equations
-12z =6
Z= -1/2
Substituting z
3x +1/2 = 2
3x = 3/2
X= 1/2
Substituting x and z to find y in
-x+y-3z= 1
-1/2 + y +3/2 = 1
Y = 1-1
Y = 0
Answer: b) is answer
Step-by-step explanation:
Los dueños de un restaurante cultivan sus propios
tomates, hierbas aromáticas, acelgas y otros vegetales
que utilizan en la preparación de sus comidas. Para el
riego de sus plantas, han construido un reservorio, cuya
capacidad es de 6,25 m3. Si al cabo de unos días han
utilizado los 2/3 de esta cantidad, ¿cuántos metros
cúbicos de agua todavía quedan en el reservorio y a
cuántos litros equivale?
(Considera 1 m3 = 1000 L).
Answer:
Quedan 2.083 m^3 de agua en el reservorio.
Equivalen a 2083 litros.
Step-by-step explanation:
Los dueños del restaurante tienen un reservorio de agua cuyo volumen es de 6.25 m^3.
Si han utilizado 2/3 del reservorio, esto implica que aún quedan en el reservorio una tercera parte del volumen original (1/3).
Entonces, la cantidad de metros cúbicos (m^3) de agua que quedan en el reservorio se puede calcular como:
[tex]V=(1/3)\cdot V_0=(1/3)\cdot6.25\,m^3=2.083\,m^3[/tex]
Este valor equivale a un volumen en litros de:
[tex]V=2.083\,m^3\cdot \dfrac{1,000\,l}{1m^3}=2,083\,l[/tex]
A small college has 1460 students. What is the approximate probability that more than six students were born on Christmas day? Assume that birthrates are constant throughout the year and that each year has 365 days.
Answer:
The approximate probability that more than six students were born on Christmas day is P=0.105.
Step-by-step explanation:
This can be modeled as a binomial variable, with n=1460 and p=1/365.
The sample size n is the total amount of students and the probability of success p is the probability of each individual of being born on Christmas day.
As the sample size is too large to compute it as a binomial random variable, we approximate it to the normal distribution with the following parameters:
[tex]\mu=n\cdot p=1460\cdot (1/365)=4\\\\\sigma=\sqrt{n\cdot p(1-p)}=\sqrt{1460\cdot(1/365)\cdot(364/365)}=\sqrt{3.989}=1.997[/tex]
We want to calculate the probability that more than 6 students were born on Christmas day. Ww apply the continuity factor and we write the probability as:
[tex]P(X>6.5)[/tex]
We calculate the z-score for X=6.5 and then calculate the probability:
[tex]z=\dfrac{X-\mu}{\sigma}=\dfrac{6.5-4}{1.997}=\dfrac{2.5}{1.997}=1.252\\\\\\P(X>6.5)=P(z>1.252)=0.105[/tex]
Which pairs of non-overlapping angles share a ray to make a right angle?
Please Select all that Apply. There are multiple answers. 50 POINTS
∠FGK and ∠FGH Im pretty sure its right
A ray is a half-infinite line. The pairs of non-overlapping angles that share a ray to make a right angle are ∠FGE and ∠FGH.
What is a ray?A half-infinite line (also known as a half-line) with one of the two points and is commonly used to represent a ray. It is assumed to be infinite.
A straight line has an angle of measurement of 180°. And a 90° angle is made when two lines are perpendicular to each other.
As we can see the line EGH is a straight line, and FG is another line that is perpendicular to line EH, therefore, it will form two angles measuring 90°. These angles will be ∠FGE and ∠FGH.
Hence, the pairs of non-overlapping angles that share a ray to make a right angle are ∠FGE and ∠FGH.
Learn more about Ray:
https://brainly.com/question/17491571
Will give Brainliest Talia took the bus from her home to the bank and then walked back to her home along the same route. The round trip took 0.9 hours total. The bus traveled at an average speed of 40 km/h and she walked at an average speed of 5 km/h. The rate of Trip 2 is blank km/h. The time of Trip 1 is blank hours.
Answer:
The rate of trip 2 is 5 km/h
The time of trip 1 is 0.9-x
Step-by-step explanation:
The rate of trip 2 is 5 km/h because it tells you she walked at an avg speed of 5 km/h.
The time of trip 1 is 0.9-x. It's because the time in trip 2 is x, and it says the total is 0.9. So just subtract 0.9-x.
Also I took the test on edge and attached a pic.
(like Ross 6.28) The time that it takes to service a car is an exponential random variable with rate 1. (a) If Lightning McQueen (L.M.) brings his car in at time 0 and Sally Carrera (S.C) brings her car in at time t, what is the probability that S.C.’s car is ready before L.M.’s car? Assume that service times are independent and service begins upon arrival of the car.
Answer: provided in the explanation section
Step-by-step explanation:
The complete question says:
The time that it takes to service a car is an exponential random variable with rate 1. (a) If Lightning McQueen (L.M.) brings his car in at time 0 and Sally Carrera (S.C) brings her car in at time t, what is the probability that S.C.'s car is ready before L.M.'s car? Assume that service times are independent and service begins upon arrival of the car Be sure to: 1) define all random variables used, 2) explain how independence of service times plays a part in your solution, 3) show all integration steps. (b) If both cars are brought in at time 0, with work starting on S.C. 's car only when L.M.'s car has been completely serviced, what is the probability that S.C.'s car is ready before time 2?
Ans to this is provided in the images uploaded as it is not possible to put the symbols here...
i hope you find this helpful.
cheers !!
Select all fractions that are equal to 3/4
3/4, 6/8, 9/12, 12/16 , 15/20, 18/24, 21/28, 24/32 , 27/36, 30/40, 33/44, 36/48 , 39/52, 42/56, 45/60, 48/64 , 51/68, 54/72, 57/76, 60/80, ect..
I hope this is what you are looking for :)
A business office orders paper supplies from one of three vendors, V1, V2, or V3. Orders are to be placed on two successive days, one order per day. Thus, V2V3 might denote that vendor V2 gets the order on the first day and vendor V3 gets the order on the second day.
Required:
a List the sample points in this experiment of ordering paper on two successive days.
b Assume the vendors are selected at random each day and assign a probability to each sample point.
c Let A denote the event that the same vendor gets both orders and B the event that V2 gets at least one order. Find P( A), P( B), P( A U B), and P( A ∩ B) by summing the probabilities of the sample points in these events.
Find the given attachments
A motorboat can maintain a constant speed of 28 miles
per hour relative to the water. The boat makes a trip
upstream to a certain point in 35 minutes; the return trip
takes 21 minutes. What is the speed of the current?
Answer:
7mph
Step-by-step explanation:
Given
Time Taken to go upstream Tup = 35 min
Time Taken to go downstream Tdown=21 min.
Let the absolute speed (i.e speed relative to the stationary riverbed) be :
Vup : going upstream
Vdown: going downstream.
We know that the distance traveled upstream = distance traveled downstream, hence we can equate both distances, i.e. :
Distance Traveled Upstream = Distance Traveled Downstream
Vup · Tup = Vdown · Tdown (substituting the values for time above)
35Vup = 21Vdown
Vup = (21/35) Vdown ------------(eq 1)
We are also given that the motorboat can travel at V = 28 mph relative to the water.
Since going upstream, we are going AGAINST the current, relative to the riverbed, we expect to be travelling slower. In fact, the absolute difference between the speed relative to the water (i.e V = 28 mph) and the speed relative to the seabed (i.e Vup), is equal to the speed of the current.
The same can be said for going downstream WITH the current, that the absolute difference between V = 28mph and Vdown is also equal to the speed of the current.
Hence we can equate the two:
28 - Vup = Vdown - 28
Vup + Vdown = 2(28)
Vup + Vdown = 56 ---------------------(eq 2)
If we solve the system of equations (eq 1) and (eq2), we will get
Vup = 21 mph and Vdown = 35 mph
(sanity check tells us that this makes sense because we expect to be going slower upstream because we are going against the current)
Hence current speed
= 28-Vup
= 28 - 21
= 7 mph. (answer)
Sanity Check:
Current speed can also be written:
= Vdown-28
= 35 - 28
= 7 mph (same as what we found above, so this checks out)
The speed of the current motorboat = 7 mph
What is an expression?
Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Speed of boat in still water = 28 mph
Let the speed of stream = w
Here, The upstream time is 35 min = 35/60 h = 7/12 h
downstream time is 21 min = 21/60 h = 7/20 hours
Since, The distance (d = vt) traveled either way is the same, but at different speeds and times.
Hence, Set upstream and downstream distances (vt) equal and solve for w as;
⇒ (28 - w)(7/12) = (28 + w)(7/20)
⇒ 20 (28 - w) = 12 (28 + w)
⇒ 5(28 - w) = 3(28 + w)
⇒ 140 - 5w = 84 + 3w
⇒ 140 - 84 = 5w + 3w
⇒ 56 = 8w
⇒ w = 7
Thus, The speed of the current = 7 mph
Learn more about the mathematical expression visit:
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7. Tyson obtained a loan from the bank at 7.5% simple interest for 2. 5 years. If the simple interest was
N$347.50, how much did he borrow?
8. Hilma invested N$20 000 on 01/01/2018 at 9.5 % interest p.a compounded semi-annually.
How much will she receive by 01/01/2022?
Answer:
7.He borrowed $1853.33
8.She received $28990.936
Step-by-step explanation:
7.Let x be the amount borrowed by Tyson
Rate of interest = 7.5%
Time = 2.5 years
Simple Interest = 347.50
Formula : [tex]Si = \frac{P \times T \times R}{100}[/tex]
Where SI = simple interest
P = Principal
T = Time
R = Rate of interest
Substitute the values in the formula :
[tex]347.50=\frac{x \times 2.5 \times 7.5}{100}\\\frac{347.50 \times 100}{2.5 \times 7.5}=x\\1853.33=x[/tex]
Hence he borrowed $1853.33
8) Principal = 20000
Rate of interest = 9.5%
No. of compounds per year = 2
Time = 4 years
Formula : [tex]A=P(1+\frac{r}{n})z^{nt}[/tex]
Where A= amount
r = Rate of interest
n = no. of compounds
t = time
Substitute the values in the formula :
So, [tex]A=20000(1+\frac{9.5}{200})^{2(4)}[/tex]
A=28990.936
Hence she received $28990.936
lect the best answer for the question.
3
1. Find the value of y in the equation
-=8.
y-2
3
A. y = 2
8
B. y=-2-
3
8
5
C. y=-1
8
5
D. y =
loo
Which size would you see on the box for a new television whose screen measures 36 inches wide by 27 inches high? A. 9" B. 45" C. 50" D. 63"
Answer: b) 45"
Step-by-step explanation:
Tv's are measured by their diagonal length.
Use Pythagorean Theorem to find the diagonal of the tv.
a² + b² = c²
36² + 27² = c²
1296 + 729 = c²
2025 = c²
√2025 = c
45 = c
Suppose that a random sample of adult males has a sample mean heart mass of x¯=310.1 grams, with a sample standard deviation of s=6.6 grams. Since adult male heart masses are generally symmetric and bell-shaped, we can apply the Empirical Rule. Between what two masses do approximately 68% of the data occur? Round your answer to the nearest tenth.
Answer:
Between 303.5 grams and 316.7 grams
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 310.1 grams
Standard deviation = 6.6 grams
Between what two masses do approximately 68% of the data occur?
By the Empirical Rule, within 1 standard deviation of the mean.
310.1 - 6.6 = 303.5 grams
310.1 + 6.6 = 316.7 grams
Between 303.5 grams and 316.7 grams
ASAP
What is the sum of 16.87 + (–98.35)?
–115.22
–81.48
81.48
115.22
Solution,
16.87+(-98.35)
=16.87-98.35
= -81.48
Hope it helps
Good luck on your assignment
Answer:-81.48
Step-by-step explanation:
16.87 + (–98.35)
-81.48
If you stumble in other questions like there you can use a calculator or ask me. :D hope that helps
3ab-9ab+7ab and hurry up
Answer:ab
Step-by-step explanation:3-9=-6 +7=1 1ab also equals just ab
Answer:
Since its adding and subtracting just add the coefficients of similar terms (coefficient is the number in front, term is the coefficient. and variables, similar terms are terms that have the same variables)
3ab-9ab+7ab
3-9=-6: -6ab+7ab
-6+7=1: 1ab or ab :)
Noaya read a book cover to cover in a single session, at a rate of 55 pages per hour. After 4 hours, he had 350 pages left to read. Let y represent the number of pages left to read after x hours.
Answer: –55x + 570
Step-by-step explanation:
The person above me completely missed the question so this is the right one
Simple regression was employed to establish the effects of childhood exposure to lead. THe effective sample size was about 122 subjects. THe independent variable was the level of dentin lead (parts per million). Below are regressions using various dependent variables.
Calculate the t statistic for each slope, at significance level = 0.01.
Dependent Variable R2 Estimated Std. t calculated p-value Differ from 0?
Slope Error
Highest grade achieved .061 −0.027 0.009 .008 No / Yes
Reading grade equivalent .121 −0.070 0.018 .000 No / Yes
Class standing .039 −0.006 0.003 .048 No / Yes
Absence from school .071 4.8 1.7 .006 No / Yes
Grammatical reasoning .051 0.159 0.062 .012 Yes / No
Vocabulary .108 −0.124 0.032 .000 No / Yes
Hand-eye coordination .043 0.041 0.018 .020 No / Yes
Reaction time .025 11.8 6.66 .080 No / Yes
Minor antisocial behavior .025 −0.639 0.36 .082 Yes / No
B) It would be inappropriate to assume cause and effect without a better understanding of how the study was conducted.
1. No
2. Yes
Answer:
Step-by-step explanation:
Simple regression was employed to establish the effects of childhood exposure to lead. THe effective sample size was about 122 subjects. THe independent variable was the level of dentin lead (parts per million). Below are regressions using various dependent variables.
Calculate the t statistic for each slope, at significance level = 0.01.
Dependent Variable R2 Estimated Std. t calculated p-value Differ from 0?
Slope Error
Highest grade achieved .061 −0.027 0.009 .008 No / Yes
Reading grade equivalent .121 −0.070 0.018 .000 No / Yes
Class standing .039 −0.006 0.003 .048 No / Yes
Absence from school .071 4.8 1.7 .006 No / Yes
Grammatical reasoning .051 0.159 0.062 .012 Yes / No
Vocabulary .108 −0.124 0.032 .000 No / Yes
Hand-eye coordination .043 0.041 0.018 .020 No / Yes
Reaction time .025 11.8 6.66 .080 No / Yes
Minor antisocial behavior .025 −0.639 0.36 .082 Yes / No
B) It would be inappropriate to assume cause and effect without a better understanding of how the study was conducted.
1. No
2. Yes
solution[tex]t=\frac{\text {estimated slope}}{\text {std error}}[/tex]
a)
Estimated Slope Std error t - calculated
-0.027 0.009 -3
-0.070 0.018 -3.89
-0.006 0.003 -2
4.8 1.7 2.82
0.159 0.062 2.56
-0.124 0.032 -3.87
0.041 0.018 2.28
11.8 6.66 1.77
-0.639 0.36 -1.78
b) Yes, It would be inappropriate to assume cause and effect without a better understanding of how the study was conducted.
A club is choosing 2 members to serve on a committee. The club has nominated 2 women and 4 men. Based on chance alone, what is the probability that one woman and one man will be chosen to be on the committee
Answer:
53.33% probability that one woman and one man will be chosen to be on the committee
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which the members are chosen is not important, so we use the combinations formula to solve this question.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
What is the probability that one woman and one man will be chosen to be on the committee?
Desired outcomes:
One woman, from a set of 2, and one man, from a set of 4. So
[tex]D = C_{2,1}*C_{4,1} = \frac{2!}{1!1!}*\frac{4!}{1!3!} = 8[/tex]
Total outcomes:
Two members from a set of 2 + 4 = 6. So
[tex]T = C_{6,2} = \frac{6!}{2!4!} = 15[/tex]
Probability:
[tex]p = \frac{D}{T} = \frac{8}{15} = 0.5333[/tex]
53.33% probability that one woman and one man will be chosen to be on the committee
8. A biotech company is looking for a user experience researcher to organize and report on some user experience data for a health and wellness app. They need to know the demographics of the users and the average time the app is open for each demographic. In the technical interview, you are asked to describe your approach to the initial analysis. When describing your analysis plan for the request, with what type of statistics would you tell the interviewer you would start your analysis
Answer:
Descriptive statistics
Step-by-step explanation:
Descriptive statistics describes and summarizes the basic features of a given dataset. It explains features from a collection of information, it is also said to be a form of summary statistics. Here data is characterized using its properties.
In this case, I was asked to describe my approach to the initial analysis. When describing the analysis plan for the request, I would tell the interviewer to start analysis using descriptive statistics.
42,000 as a multipul of a power of 10
Answer:
[tex] 4.2 \times {10}^{4} [/tex]
Step-by-step explanation:
[tex]42000 = 4.2000 \times \times {10}^{4} \\ = 4.2 \times {10}^{4} [/tex]
John leaves school to go home.his bus drives 6 kilometers north and then goes 7 kilometers west.how far is John's house from the school?
Answer:
John is 9.21 km form the school.
Step-by-step explanation:
John leaves school to go home. His bus drives 6 kilometres north and then goes 7 kilometres west. It is required to find John's distance from the school. It is equal to the shortest path covered or its displacement. So,
[tex]d=\sqrt{6^2+7^2} \\\\d=9.21\ km[/tex]
So, John is 9.21 km form the school.
The lengths of pregnancies in a small rural village are normally distributed with a mean of 267 days and a standard deviation of 15 days. A distribution of values is normal with a mean of 267 and a standard deviation of 15. What percentage of pregnancies last beyond 246 days? P(X > 246 days) =
Answer:
91.92% of pregnancies last beyond 246 days
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 267, \sigma = 15[/tex]
What percentage of pregnancies last beyond 246 days?
We have to find 1 subtracted by the pvalue of Z when X = 246. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{246 - 267}{15}[/tex]
[tex]Z = -1.4[/tex]
[tex]Z = -1.4[/tex] has a pvalue of 0.0808
1 - 0.0808 = 0.9192
91.92% of pregnancies last beyond 246 days
Solve:
5 thousands
ones
5 thousand ones is the same as 5,000. Each one takes up one place.
Answer:
5000
Step-by-step explanation:
Carefully review the research matrix presented below. If this is a within subjects design, how many total participants will be used in the experiment?
Immaculate Appearance Neat Appearance Sloppy Appearance
15 participants 15 participants 15
participants
a. 15
b. 30
c. 45
d. 60
Answer:
c. 45
Step-by-step explanation:
there are 15 participant in each category, and there are 3 categories, so total participants = 15 * 3
= 45
Hope this helps, and please mark me brainliest if it does!
I need help with problem ASAP!
Answer:
the first option
Step-by-step explanation:
Sum means addition so the sum of 9 and half a number is 9 + 1/2x. The only answer option that has this on the left side is the first option.
Simplify the expression and then evaluate it for the given value of the variable: (6−2x)+(15−3x) for x=−0.2
PLEASE HELP!!!!!!
Answer:
20
Step-by-step explanation:
The simplified expression is -5x+21
-5(0.2)+21=
-1+21= 20
Answer:
24
Step-by-step explanation:
f(x)= (6−2x)+(15−3x)
x=-0.2
f(-0.2)=(6−2(-0.2)+(15−3(-0.2))
f(-0.2)=(6+0.4)+(15+0.6)
f(-0.2)=6.4+15.6
f(-0.2)=22
82
R5
6
,92 5
4 8
12
12
0
Answer:
see below
Step-by-step explanation:
The first subtraction has a zero result (blue) from the thousands digit, so we know the dividend has 4 in that place. The 5 in the 1s place of the dividend is brought down to fill the space on the bottom line. 6 goes into that number 0 times, so the final quotient digit is 0.
4,925 = 6×820 +5
or
4,925 ÷ 6 = 820 r5