If OP=17 and QP=6, what is OQ? First, complete the Segment Addition Postulate for this problem.

OQ + QP= BLANK?

Fill in what you know and solve for OQ

OQ= BLANK?

Step-by-step explanation:

The starting amount is the coefficient of the exponent which is 595.

The growth factor is 1.075 and the growth rate would be 7.5%.

There are 2 factors in the equation.

Answer:

the rise is 2 and the run is 5

Step-by-step explanation:

2/5

Answer:

Step-by-step explanation:

the slope is = 2/5

the y-intercept = 2

Answer:

(a, 0), (0, b), (-a, 0), (0, - b)

Step-by-step explanation:

Since, all vertices of the rhombus lie in the x and y axes.

x - axis is given by a and y - axis is given by b.

Therefore, coordinates of vertices lying on x - axes will be (a, 0) & (-a, 0) and coordinates of vertices lying on y - axes will be (0, b) & (0, - b).

Answer: 6.452cm.

As 1 decimal place it would be 6.5cm.

Answer:

6.9 cm

Step-by-step explanation:

a^2 + b^2 =C^2

a^2 + b^2 = 8^2

6.9^2 +4^2 =64

47.61 + 16 = 64

47.61  about 48

Answer: (6, -3)

(x^2-4x+4)/16-(y^2+6y+9)/25 = 1

x = 6

y = -3

6^2 = 36

4 * 6 = 24

36 - 24 = 12

12 + 4 = 16

16/16 = 1

-3^2 = 9

6 * -3 = -18

9 - 18 = -9

-9 + 9 = 0

0/25 = 0

1 - 0 = 1

I really hope this helped, at least a little bit.

The coordinates of the center of the hyperbola is  (6,-3).

Hyperbola is a type of "smooth curve, lying in the plane defined by its geometric properties or by the equation for which it is in solution set".

According to the question,

[tex]\frac{(x-2)^2}{4^2}[/tex]  -  [tex]\frac{(y+3)^2}{5^2}[/tex] = 1

Standard form of hyperbola = [tex]\frac{(x-k)^2}{a^2}[/tex]  -  [tex]\frac{(y-h)^2}{b^2}[/tex]  = 1.

The expression 'y' is positive leading coefficient so the hyperbola so the hyperbola is open upward and downward . Comparing with standard equation we get center of hyperbola (2,-3) and 'a' point the hyperbola is 4 and the 'b' point of hyperbola is 5 and mark point 5 unit right as well as left on x-axis and 4 unit up and down on y-axis.

From above discussion we get clearly the coordinate of hyperbola is

(6-3).

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Answer: The speed is 105 miles/ hr and  the direction of the train would be East if the girl is the frame of reference.

Step-by-step explanation:

Since we have given that

Speed of train = 100 miles per hour

Speed of girl = 5 miles per hour

Since the girl is moving towards the back of train.

So,it means train and girl are moving in opposite direction.

So, Relative speed would be

[tex]100+5=105\ miles/hr[/tex]

Hence, the speed is 105 miles/ hr and  the direction of the train would be East if the girl is the frame of reference.

Answer:

The second one

Step-by-step explanation:

Answer:

C. zero

Step-by-step explanation:

a * (-b/b)

-b/b = -1

a* -1

If a = 0 then

0 * -1 = 0

Answer:

0

Step-by-step explanation:

pls give brainliest

Answer:

8.75° south of west

26.3 mph

Step-by-step explanation:

Let's say that east is +x and north is +y.

The sailor's horizontal velocity is -26 mph.  The vertical velocity is -4 mph.  So the velocity vector is in the 3rd quadrant.  The direction is:

θ = tan⁻¹(-4 / -26)

θ = 188.75°, or 8.75° south of west.

The magnitude of the speed is:

v = √((-4)² + (-26)²)

v = 26.3 mph

Answer:

The bus will travel 20km within 15 minutes

Step-by-step explanation:

Answer: 20 km

Step-by-step explanation:

Distance = speed / time

Answer: y<-12

Step-by-step explanation:

[tex]-\frac{3}{4}y>9[/tex] is our einequality we are given. To solve, we want to get x alone. We would have to multiply both sides by -4/3.

[tex]y>-12[/tex]

You may thing this is the answer, but it is very close. When you multiply or divide by a negative number, you flip the sign. Therefore, the answer is [tex]y<-12[/tex].

Answer:

the answer is A

Step-by-step explanation:

Answer:

ΔCTA ≅ ΔDRA

Step-by-step explanation:

Triangles CTA and DRA are congruent by ASA postulate. This is because:

Then, correspondent angles and sides are congruent, for example, ∠3 ≅ ∠4

Answer:

B

Step-by-step explanation:

Square root of 3 is between 1 and 2

1^2 =1

(sqrt(3)) ^2 =3

2^2 = 4

So it must be point B

Answer:

B

Step-by-step explanation:

Answer:

a−b=aa=1

Step-by-step explanation:

Since the graph of the linear function f has intercepts (a,0) and (0,b), the two points satisfy the function. Therefore, the slope becomes a−b=aa=1, which is positive.

Answer:

a=7

Step-by-step explanation:

7(a – 10) = 13 – 2(2a + 3)

Open the bracket

7a-70=13-4a-6

Collect like terms

7a+4a=13-6+70

11a=77

divide both sides by 11

11a/11=77/11

a=77/11

a=7

Answer: -2y -8x = 4

Step-by-step explanation:

y - 6x - 11 - 2x - 3y = -7

y -3y -6x -2x = -7 +11

-2y -8x = 4

Answer: -4

Step-by-step explanation:

Answer:

≈ 93.06 cm²

Step-by-step explanation:

Subtract the area of the rectangle from the area of the circle

area of circle = πr² = π × 8² = 64π cm²

area of rectangle = 12 × 8 = 108 cm²

Thus

shaded area = 64π - 108 = 201.062 - 108 ≈ 93.05 cm² ( nearest hundredth )

Answer:

The area of the shaded region = area of the circle - area of the rectangle

area of circle = πr² = π × 8² = 201.14 cm²

area of rectangle = 12 × 2 = 24 cm²

shaded area = 201.14 - 24 ≈ 177.14 cm²

Answer: B

Explanation: Baseballs(b) minus 3 which is b-3

Answer:

a) The bacterium is longer;

b) The bacterium is 0.1543 mm longer than the yeast.

Step-by-step explanation:

In order to compare the length of the two beings we need to convert them to the same unit. We can do it either way, but we'll choose to convert from meters to milimetres, since we're dealing with small numbers. To do that we need to multiply the length that is in "m" by 1000.

[tex]length_{bac} = 0.000163*1000 = 0.163 \text{ mm}[/tex]

a) The bacteria is longer than the yeast.

b) We need to subtract their length in order to find this answer:

[tex]\text{dif} = length_{bac} - length_{yeast}\\\text{dif} = 0.163 - 0.0087 = 0.1543 \text{ mm}[/tex]

Answer:

2^5

explanation:

I did this already man this is easy

Answer:

(40/3)*pi

Step-by-step explanation:

lets first find the area of the little circle

A=pi*r^2

A=pi*3^2

A=9pi

Now, lets find the area of the big circle

A=pi*r^2

A=pi*(3+4)^2

A=pi*7^2

A=49pi

now lets subtract the area of the little circle from the area of the big circle

49pi-9pi=40pi, now we found the area of the "bagel)

lets find what portion of the bagel is the shaded region

120/360=1/3

now lets multiply the bagel area by the fraction

40pi*(1/3)=

(40/3)*pi   or  (40*pi)/3

Area of the shaded regions is equal to 7π/3

The circumference (or) perimeter of a circle = 2πr units. The area of a circle = πr2 square units. Where r is the radius of the circle. The circumference of the circle or the perimeter of the circle is the measurement of the boundary of the circle. Whereas the area of the circle defines the region occupied by the circle.

Given here: radius of the smaller circle= 3 and larger circle =4 cm

Now A = (θ/360°) × πr2

θ is the sector angle subtended by the arcs at the center (in degrees), r is the radius of the circle. If the subtended angle θ is in radians, the area is given by, A = 1/2 × r² × θ.

Thus we have  Area ADBC= 1/2 × 16×2π/3 -1/2×9×2π/3

                                              =16π/3 -3π

                                               =7π/3

Hence, Area of the shaded regions is equal to 7π/3

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Answer:

[tex]\left( -\dfrac{4}{25}, -\dfrac{98}{25} \right)[/tex]

Step-by-step explanation:

[tex]x+2y=-8 \\\\y=12x-2[/tex]

Substitute:

[tex]x+2(12x-2)=-8[/tex]

Expand:

[tex]x+24x-4=-8[/tex]

Simplify:

[tex]25x=-4[/tex]

Divide both sides by 25:

[tex]x=-\dfrac{4}{25}[/tex]

Plug this back into one of the original equations to find y:

[tex]-\dfrac{4}{25}+2y=-8 \\\\\\2y=-7 \dfrac{21}{25}=-\dfrac{196}{25} \\\\\\y=-\dfrac{98}{25}[/tex]

The ordered pair that represents this solution is therefore:

[tex]\left( -\dfrac{4}{25}, -\dfrac{98}{25} \right)[/tex]

Hope this helps!

Answer: YOUR ANSWER IS -3

Step-by-step explanation:

4y + 4 = -8

     -4     -4

___________

4y = -12

Divide -12 by 4

Y = -3