I’ll give you a star if you answer this question. Which of the following is the best example of work being done
on an object?

Ill Give You A Star If You Answer This Question. Which Of The Following Is The Best Example Of Work Being

Answers

Answer 1
The answer would be C because you are working hard for the object to not move pls mark as brainliest

Related Questions

A plane flying at a speed of 59.1 m/s is dropping a package 521 m above the intended target. How long does it take for the package to hit the ground?
A.) 10.3 seconds
B.) 0.1 seconds
C.) 106.3 seconds
D.) 8.8 seconds

Answers

Answer:

t = 10.31 seconds which agrees with answer option A)

Explanation:

Notice that the horizontal velocity of the plane imparted to the package, doesn't affect the vertical motion for which the original (vertical velocity) is zero.

Then the equation for the distance travelled by the package is:

d = (1/2) a t^2

in our case, d = 521 m, and a = g (acceleration of gravity 9.8 m/s^2)

then we can solve for t in the equation:

521 = 9.8/2   t^2

t^2 = 521/4.9

t^2 = 106.32 s^2

t = 10.31 seconds

In 1993, Wayne Brian threw a spear at a record distance of 201.24 m. (This is not an official sports record because a special device was used to “elongate” Brian’s hand.) Suppose Brian threw the spear at a 35.0° angle with respect to the horizontal. What was the initial speed of the spear? 2. Find the maximum height and time of flight of the spear in problem #1.

I really don't know how to do any of this please help me :(

Answers

Answer:

V₀ = 45.81 m/s

H = 70.45 m

T = 5.36 s

Explanation:

The motion of the spare is projectile motion. Therefore, we will first use the formula of range of projectile:

R = V₀² Sin 2θ/g

where,

R = Range of Projectile = 201.24 m

V₀ = Initial Speed = ?

θ = Launch Angle = 35°

g = 9.8 m/s²

Therefore,

201.24 m = V₀²[Sin 2(35°)]/9.8 m/s²

V₀ = √[(201.24 m)/(0.095 m/s²)

V₀ = 45.81 m/s

Now, for maximum height:

H = V₀² Sin² θ/g

H = (45.81 m/s)² Sin² 35°/9.8 m/s²

H = 70.45 m

For the total time of flight:

T = 2 V₀ Sin θ/g

T = 2(45.81 m/s) Sin 35°/9.8 m/s²

T = 5.36 s

What was used as a basket at each end of the gym?

Group of answer choices

bucket

hula hoop

apple basket

peach basket

Answers

Apple basket hope this helped

Answer: apple basket ✨

Explanation:

What is the force used when a 7 kg bowling ball is rolled with an acceleration of 3 m /s2? Use the formula to find the force in Newtons (N): F = 7 kg × 3 m/s2

Answers

Answer:

21 Newtons

Explanation:

Force= mass * acceleration

Force= 7 kg * 3 m/s^2

Force= 21 Newtons

9. What distance is a book from the floor if the book contains 196 Joules of potential energy and has a mass of 5 kg?​

Answers

Answer:

the book is 4 meters from the floor

Explanation:

Use the formula for potential energy:

U = m g h

196 J = 5kg 9.8m/s^2 h

h = 196 / (5*9.8 ) m

h = 4 m

How long does it take a vehicle to reach a velocity of 32 m/s if it accelerates from rest at a rate of 4.2 m/s^2? ANSWER ALL PLEASE!! Im dumb:(
What is the initial velocity of the vehicle?

What is the final velocity of the vehicle?

What is the acceleration of the vehicle?

Write the equation you will use to solve the problem.

How long does it take the vehicle to reach its final velocity?
0.13 seconds
18.1 seconds
7.62 seconds
134.4 seconds

Answers

Answer: Givens

a = 4.4 m/s^2 This is an acceleration and is positive.

vi = 10.2 m/s

t = 4.2 seconds

vf = ????? The cruising speed in this case is vf.

Formula

a = (vf - vi)/t Notice the 3 givens and what you seek determine the formula

Solve

4.4 m/s^2 = (vf - 10.2)/4.2 Multiply both sides by 4.2

4.4 * 4.2 = vf - 10.2

18.48 = vf - 10.2 Add 10.2 to both sides

18.48 + 10.2 = vf 8.28 is the second best answer.

28.68 = vf This is your cruising speed.

C <<<< Answer

7.62 (2dp)

Explanation:

U = 0m/s

V = 32m/s

A = 4.2m/s^2

T = ?

[tex]a = \frac{v - u}{t}[/tex]

[tex]t = \frac{v - u}{a} [/tex]

[tex]t = \frac{32 - 0}{4.2} [/tex]

[tex]t = \frac{32}{4.2} [/tex]

[tex]t = 7.62 \: (2dp)[/tex]

If you liked this answer, brainliest?

Friction that occurs in gases and liquids is called

Answers

The answer is fluid friction

Skier pushes him self along the snow on flat ground he feels Erizo cents on his body which way

Answers

Answer:

Forward

Explanation:

Since the skier pushes himself along the snow on flat ground and he feels air resistance, he will only feels air resistance when he starts moving (unless wind is blowing in opposite direction). The net force vector is dependent on the amount of force applied by the skier here we assume that skier continues to move in forward direction. The net force vector will act in the direction of acceleration, since the skier continues to move in the forward direction, therefore the net force vector will also point in the forward direction.

Using a maximum allowable shear stress of 70 MPa, find the shaft diameter needed to transmit 40 kW when (a) The shaft speed is 2500 rev/min. (b) The shaft speed is 250 rev/min

Answers

Answer:

a

 [tex]d = 0.0223 \ m[/tex]

b

[tex]d = 0.0481 \ m[/tex]  

Explanation:

From the question we are told that

   The maximum allowable shear stress is  [tex]\sigma = 70 MPa = 70 *10^{6} \ Pa[/tex]

    The power is  [tex]P = 40 \ kW = 40 *10^{3} \ W[/tex]

considering question a

   The shaft speed is given as [tex]v = 2500\ rev/min[/tex]

Generally the torque experienced by the shaft is mathematically represented as

       [tex]\tau = \frac{ 9.55 * P}{v}[/tex]

=>    [tex]\tau = \frac{ 9.55 * 40 *10^{3}}{ 2500}[/tex]

=>    [tex]\tau = 152.8 \ N \cdot m[/tex]

Generally the maximum torque experienced by the shaft is mathematically represented as

          [tex]\tau_m = \frac{2 \tau }{ \pi r^2 }[/tex]

Generally diameter  =  2 *  radius (r)

So

        [tex]\tau_m = \frac{2 \tau }{ \pi 4 d^2 }[/tex]

Generally the maximum allowable shear stress is mathematically represented as

                [tex]\sigma = \frac{2 \tau }{ \pi 4 d^2 } * \frac{32}{d}[/tex]

=>             [tex]\sigma = \frac{16 \tau }{ \pi d^3}[/tex]

=>            [tex]d = \sqrt[3]{\frac{16 * \tau }{ \pi \sigma } }[/tex]

=>          [tex]d = \sqrt[3]{\frac{16 * 152.8 }{ \pi * 70 *10^{6} } }[/tex]

=>          [tex]d = 0.0223 \ m[/tex]

considering question b

   The shaft speed is given as [tex]v = 250\ rev/min[/tex]

Generally the torque experienced by the shaft is mathematically represented as

       [tex]\tau = \frac{ 9.55 * 40 *10^{3}}{250 }[/tex]

=>    [tex]\tau = 1528 \ N \cdot m[/tex]

Generally the shaft diameter is mathematically represented as

   [tex]d = \sqrt[3]{\frac{16 * \tau }{ \pi \sigma } }[/tex]

=>[tex]d = \sqrt[3]{\frac{16 * 1528 }{ 3.142 * 70 *10^{6} } }[/tex]  

=>[tex]d = 0.0481 \ m[/tex]  

In a warehouse, the workers sometimes slide boxes along the floor to move them. Two boxes were sliding toward each other and crashed. The crash caused both boxes to change speed. Based on the information in the diagram, which statement is correct? In your answer, explain what the forces were like and why the boxes changed speed.

Box 1 has more mass than Box 2.
Box 1 and Box 2 are the same mass.
Box 1 has less mass than Box 2.

**YOU MUST BE DESCRIPTIVE! Any short answers not explaining it wont get brainliest!**

Answers

Answer:

box 1 has larger mass than box 2

Explanation:

We need to consider the linear momentum of the boxes immediately before and after they crash.

Recall that momentum is defined as mass times velocity.

So for before the collision, the linear momentum of the system of two boxes is:

m1 * 4km/h  - m2 * 8km/h

with m1 representing mass "1" on the left, and m2 representing mass 2 on the right.

Notice the sign of the linear momentum (one positive (moving towards the right) and the other one negative (moving towards the left)

For after the collision, we have or the linear momentum of the system:

- m1 * 2km/h - m2 * 1km/h

Then, since the linear momentum is conserved in the collision, we make the  initial momentum equal the final and study the mass relationship between m1 and m2:

4 m1 - 8 m2 = - 2 m1 - m2

combining like terms for each mas on one side and another of the equal sign, we get;

4 m1 + 2 m1 = 8 m2 - m2

6 m1 = 7 m2

therefore m1 = (7/6) m2

which (since 7/6 is a number larger than one) tells us that m1 is larger than m2 by a factor of 7/6

Therefore, answer 1 is the correct answer.

How can you find directions using satellite orbiting?

Answers

Answer:

Satellites may move north to south, or south to north, or west to east, but never from east to west. When satellites are launched, they always head eastward to take advantage of the Earth's rotation, going more than 1,000 miles per hour near the equator. This saves a lot of fuel.

An extraterrestrial creature is standing in front of plane mirror. The height of this creature is H and we know that this creature has eyes positioned h below the top of its head. This creature sees its reflection which fit exactly the mirror, it means, this creature can just see the top of head and the bottom of its feet (or whatever it uses for motion). We can conclude that the top of a mirror is exactly:________

a. H/2 above the ground
b. H above the ground
c. (H-h/2) above the ground
d. (H-h) above the ground
e. We can not guess anything without information about the nature of this creature.

Answers

Answer:

c. (H-h/2) above the ground

Explanation:

The mirror must be at least half as tall as the alien, and its base must be located at half of the distance between the alien's eyes and the ground (assuming that the alien doesn't float or levitate).

This question is about the Law of Reflection which states that the angle of reflection = angle of incidence.

I attached an image that can help you understand the concept, although the alien is not included.

A 67.6-kg boy is surfing and catches a wave which gives him an initial speed of 1.56 m/s. He then drops through a height of 1.65 m, and ends with a speed of 8.30 m/s. How much nonconservative work was done on the boy?

Answers

Answer:

The nonconservative work was done on the boy is 1154.87 J.

Explanation:

Given;

mass of the boy, m = 67.6 kg

initial speed of the boy, u = 1.56 m/s

height of fall, h = 1.65 m

final speed of the boy, v = 8.30 m/s

The initial energy of the boy is given by;

E₁ = K.E₁ + P.E₁

E₁ = ¹/₂mu² + mgh

E₁ = ¹/₂(67.6)(1.56)² + (67.6 x 9.8 x 1.65)

E₁ = 82.134 + 1091.475

E₁ = 1,173.61 J

The final energy of the boy is given by;

E₂ = K.E₂

E₂ = ¹/₂mv²

E₂ = ¹/₂(67.6)(8.3)²

E₂ = 2,328.482 J

The nonconservative work was done on the boy is given by;

W = E₂- E₁

W = 2,328.482 J - 1,173.61 J

W = 1154.87 J

Therefore, the nonconservative work was done on the boy is 1154.87 J.

Please help
A golfer hits a ball is at 15 m/s at an angle of 40 degrees above the horizontal. How far from where the ball was
hit will the ball land?

Answers

Answer:

Range = 22.61 m

Explanation:

We can use the formula for the Range in flat ground, given by:

[tex]Range=v_i^2\frac{sin(2\theta)}{g}[/tex]

which for our case renders:

[tex]Range=15^2\frac{sin(80^o)}{9.8} \approx 22.61\,\,m[/tex]

By using the range formula in the motion of a projectile, the ball will land 22.6 meters from where it was hit.

Given that a golfer hits a ball at 15 m/s at an angle of 40 degrees above the horizontal, To calculate how far the ball travelled, we will use the range formula to calculate the total distance travelled.

Range R = [tex]u^{2}[/tex]sin2∅ /g

Where

u = 15 m/s

g = 9.8 m/[tex]s^{2}[/tex]

∅ = 40 degrees

Substitute all the parameters into the above formula.

R = [tex]15^{2}[/tex]sin(2 x 40) / 9.8

R = 225sin80/9.8

R = 221.58/9.8

R = 22.6 m

Therefore, the ball will land 22.6 meters from where it was hit.

Learn more here: https://brainly.com/question/25299583

How do bones develop and grow?

Answers

Answer:

Explanation:

Bones grow in length at the epiphyseal plate by a process that is similar to endochondral ossification. The cartilage in the region of the epiphyseal plate next to the epiphysis continues to grow by mitosis. The chondrocytes, in the region next to the diaphysis, age and degenerate.

What is the mass of a toy truck if 18 N of force is needed to accelerate the boat to
2 m/s2 ?

Answers

Answer:

9 kg

Explanation:

Force= Mass * Acceleration

18 N= Mass * 2 m/s^2

(18 N / 2 m/s^2) = Mass

Mass= 9 kg

The statement "46 m, East" refers to the ______________ of an object.
velocity
distance
displacement
speed
acceleration

Answers

Answer:

Distance

Example:

Answer:

Displacement

Explanation:

displacement implies a vector quantity that expresses the distance (in a straight line) between the starting and finishing points. Hence, the statement "46 m, East" refers to a displacement of 46 m toward the East.

A 500-N box is at rest on the floor. Dennis Elbo makes several
attempts to move the box, pushing against the box with varying
amounts of horizontal force. Yet the box never does move. In this
situation, the amount of static friction force experienced by the box
Select all that apply.
-
0 is 500 N
O is equal to the force with which Dennis exerts on the
box
has an upper limit and Dennis O has not yet exceeded the upper limit
Ois always the coefficient of friction multiplied by the normal force value

Answers

Answer:

Select the second and the third options you listed.

Explanation:

Select the answer options:

"is equal to the force with which Dennis exerts on the  box."

and

"has an upper limit and Dennis has not yet exceeded the upper limit."

In fact, this upper limit of the static friction force is the product of the coefficient of static friction ([tex]\mu[/tex]) times the weight of the box.

an object falls from a hovering helicopter and hits the ground at a speed of 30m per seconds. how long does it take the object to reach the ground and how far does it fall? sketch a velocity-time graph for the object ( ignore air resistance

Answers

Answer:

45.9m

Explanation:

Given parameters:

Final velocity  = 30m/s

Initial velocity  = 0m/s

Unknown:

Time it takes for the object of fall  = ?

Height of fall = ?

Solution:

For the first problem, we use the equation below to solve for t;

      V = U + gt

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

t is the time taken

          30  = 0 + 9.8 x t

          30  = 9.8t

            t  = [tex]\frac{30}{9.8}[/tex]  = 3.1s

Now, height of fall;

  V² = U²  + 2gH

   30² = 0² + 2 x 9.8 x H

   900  = 19.6H

      H  = 45.9m

HELP !Which is an example of a destructive force that shapes Earth's surface?
clouds
volcanoos
wind orosion
sodiment deposits

Answers

Answer:

wind orosion is the correct answer dkr this

If a bicyclist has a mass of 70 kg and a velocity of 25 m/s, what is the momentum of the bicyclist? p=mv *

Answers

Answer:

1750Nm/s

Explanation:

70*25=1750Nm/s

Answer:

1750 kgm/s

Explanation:

The equation for momentum is p = mv = 70 * 25 = 1750

What is potential energy? Use in your own words.

Answers

Answer:

Potential energy is the latent energy in an object at rest.

Explanation:

Hope this helps- this is how I would answer :)

A 760-kg horse whose power output is 1 hp is pulling a sled over the snow at 3.9 m/s. Find the force the horse exerts on the sled. Round your intermediate step to one decimal place and the final answer to two decimal places.

Answers

Answer:

191 N

Explanation:

Power can be regarded as the amount of energy that is been transfered at a unit time and can be calculated using the Express below

Po = F*V

P= power

F= force

V= velocity

From the question, we were given power output as 1 hp and velocity= 3.9 m/s.

But

1hp= 746 Watts = 746 Joules/s.

Then substitute the values

Po = F*V = 746 J/s

F ×3.9 = 746

F= 746/3.9

F = 191 N.

Therefore, the force the horse exerts on the sled iss 191 N

If a ball rolls down an incline with a starting velocity of 0m/s and a final velocity of 6m/s
and it takes a total of 1.4 seconds, calculate its acceleration.

Answers

Answer:

If a ball rolls down an incline with a starting velocity of 0m/s and a final velocity of 6m/s

and it takes a total of 1.4 seconds, calculate its acceleration.

Answer:

Acceleration is 4.28 m/s²

Explanation:

Acceleration is change of speed in time. To solve this, we will assume that the acceleration is constant, meaning that every second the velocity increases for the same constant value.

a = ∆v/t

∆v is the difference between two measured velocities:

a = (v2 - v1) / t

v1 = 0m/s

v2 = 6m/s

t = 1.4 s

Now, we only plug in the given values:

a = (6 - 0) / 1.4

a = 6 m/s / 1.4 s

a = 4.28 m/s²

On a surface of a planet of radius R and mass M the acceleration due to gravity is 7m/s?. Consider another planet of radius 2R and mass 0.4M. What would the acceleration due to gravity be on this new planet? Show your calculations.

Answers

Answer:

0.7 m/[tex]s^{2}[/tex]

Explanation:

From Newton's law of universal gravitation,

F = [tex]\frac{GMm}{r^{2} }[/tex]

and from Newton's second law of motion,

F = mg

So that;

mg = [tex]\frac{GMm}{r^{2} }[/tex]

⇒ g = [tex]\frac{GM}{r^{2} }[/tex]

For the first planet,

7 = [tex]\frac{GM}{R^{2} }[/tex]

⇒ G = [tex]\frac{7R^{2} }{M}[/tex] .............. 1

For the second planet,

g = [tex]\frac{0.4GM}{(2R)^{2} }[/tex]

   = [tex]\frac{0.4GM}{4R^{2} }[/tex]

⇒ G = [tex]\frac{4gR^{2} }{0.4M}[/tex] ............. 2

Equating 1 and 2, we have;

[tex]\frac{7R^{2} }{M}[/tex] = [tex]\frac{4gR^{2} }{0.4M}[/tex]

g = [tex]\frac{7R^{2} *0.4M}{4R^{2}M }[/tex]

  = [tex]\frac{7*0.4}{4}[/tex]

  = [tex]\frac{2.8}{4}[/tex]

g = 0.7

Therefore, the acceleration due to gravity on the new planet is 0.7 m/[tex]s^{2}[/tex].

An electron is accelerated from rest through a potential difference of 300V. it then passes through a uniform 0.001-T magnetic field, oriented perpendicular to the electrons velocity. what is the magnitude of the magnetic force on the electron?

Answers

Given :

Potential difference, V = 300 V.

Magnetic Field, B = 0.001 T.

To Find :

The magnitude of the magnetic force on the electron.

Solution :

We know, for perpendicular orientation, force is given by :

[tex]F = qVB\\\\F = 1.6 \times 10^{-19} \times 300\times 0.001\ N\\\\F = 4.8\times 10^{-20}\ N[/tex]

Hence, this is the required solution.

A 806 kg automobile is sliding on an icy street. It collides with a parked car which has a mass of 682 kg. The two cars lock up and slide together with a speed of 23.1 km/h. What was the speed of the first car just before the collision?

Answers

Answer:

42.6km/h

Explanation:

Step one:

given data

mass of the first car M1= 806kg

the velocity of the first car V1=?

mass of the second car mass M2=682kg

velocity of the second car V2= 0km/h -----Note the car is parked

common velocity V=23.1km/h------Note: the two cars have common velocity

since the collision is inelastic:

Step two:

Required:

The velocity of the moving car

We know that the expression for the conservation of linear momentum for inelastic collision is given as

M1V1+M2V2=V(M1+M2)

substitute

806*V1+682*0=23.1(806+682)

806V1+0=23.1(1488)

806V1=34372.8

V1=34372.8/806

V1=42.6km/h

The speed of the first car just before the collision is 42.6km/h

A long wire carries a current 5 A from west to east. A magnetic compass pointing North is placed underneath the wire at a distance of 2 mm. What is the deflection of the compass when it is placed under the wire?

Answers

Answer:

no deflection

Explanation:

current is flowing from west to east. As the magnetic field of a long wire carrying current is circular, its direction will be north below the wire and south above the wire (according to the right hand rule). So, when the compass is placed underneath the wire, it will still point towards the north direction.

A student wants to determine the coefficient of static friction μ between a block of wood and an adjustable inclined plane. Of the following, the minimum additional equipment the student needs to determine a value for μ is

Answers

Answer:

A protractor to measure the angle of the inclined plane with the horizontal

Explanation:

The student needs to lift the free end of the adjustable inclined plane until the object barely starts sliding, and measure the angle at which such happens. At that point, the force of friction equals the component of the weight in the direction of the incline. That is:

[tex]f=\mu\,* N = \mu * m g\, cos(\theta)[/tex]

and  [tex]w_{//}= m\,g\,sin(\theta)[/tex]

Then  

[tex]f = w_{//}\\\mu *\,m \,g\,cos(\theta) = m\,g\,sin(\theta)\\\mu = tan(\theta)[/tex]

and therefore, the coefficient of static friction is fully determined just by calculating the tangent of the angle that the incline forms with the horizontal.

Then the only extra instrument needed is a protractor to measure the angle.

carrier concentration for n type​

Answers

Answer:

Consider an n-type silicon semiconductor at T = 300°K in which Nd = 1016 cm-3 and Na = 0. The intrinsic carrier concentration is assumed to be ni = 1.5 x 1010 cm-3. - Comment Nd >> ni, so that the thermal-equilibrium majority carrier electron concentration is essentially equal to the donor impurity concentration.

Explanation:

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