Nam owns a used car lot. He checked the odometers of the cars and recorded how far they had driven. He then created both a histogram and a box plot to display this same data (both diagrams are shown below). Which display can be used to find how many vehicles had driven more than 200{,}000\,\text{km}200,000km200, comma, 000, start text, k, m, end text (kilometers)? Choose 1 answer: Choose 1 answer: (Choice A) A The histogram (Choice B) B The box plot Which display can be used to find that the median distance was approximately 140{,}000\,\text{km}140,000km140, comma, 000, start text, k, m, end text? Choose 1 answer: Choose 1 answer: (Choice A) A The histogram (Choice B) B The box plot

Answers

Answer 1

Answer:

(a) The correct option is (A).

(b) The correct option is (B).

Step-by-step explanation:

Nam collected the data for the distance traveled by all the cars in his car lot.

(a)

A histogram is a bar graph representing the distribution of a random variable. The height of the bars of the histogram represents the frequency for a specific interval.

If Nam wants to know how many vehicles had driven more than 200,000 km, the histogram would be the best display of this data. This is because the histogram shows the frequency for various interval values.

The correct option is (A).

(b)

A boxplot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

Minimum (shown at the bottom of the chart) First Quartile (shown by the bottom line of the box) Median (or the second quartile) (shown as a line in the center of the box) Third Quartile (shown by the top line of the box) Maximum (shown at the top of the chart).

So, if Nam wants to find whether the median distance was approximately 140,000 km, a box plot would be a better choice. This is because the box plot represents the median of the data by a line within the box.

The correct option is (B).

Answer 2

Answer: For the first one is A second one is B

Step-by-step explanation: I took the khan test. UwU♡


Related Questions

Find the VOLUME of this composite solid.

Answers

Answer:

  (294π +448) cm³ ≈ 1371.6 cm³

Step-by-step explanation:

The half-cylinder at the right end has a radius of 7 cm, as does the one on top. Together, the total length of these half-cylinders is 8 cm + 4cm = 12 cm. That is equivalent in volume to a whole cylinder of radius 7 cm that is 6 cm long.

The cylinder volume is ...

  V = πr²h = π(7 cm)²(6 cm) = 294π cm³

__

The cuboid underlying the top half-cylinder has dimensions 4 cm by 8 cm by 14 cm (twice the radius). So, its volume is ...

  V = LWH = (4 cm)(8 cm)(14 cm) = 448 cm³

Then the total volume of the composite figure is ...

  (294π +448) cm³ ≈ 1371.6 cm³

The probability that a can of paint contains contamination is 3.23%, and the probability of a mixing error is 2.4%. The probability of both is 1.03%. What is the probability that a randomly selected can has contamination or a mixing error?

Answers

Answer:

4.6%.

Step-by-step explanation:

The probability that a can of paint contains contamination(C) is 3.23%

P(C)=3.23%

The probability of a mixing(M) error is 2.4%.

P(M)=2.4%

The probability of both is 1.03%.

[tex]P(C \cap M)=1.03\%[/tex]

We want to determine the probability that a randomly selected can has contamination or a mixing error. i.e. [tex]P(C \cup M)[/tex]

In probability theory:

[tex]P(C \cup M) = P(C)+P(M)-P(C \cap M)\\P(C \cup M)=3.23+2.4-1.03\\P(C \cup M)=4.6\%[/tex]

The probability that a randomly selected can has contamination or a mixing error is 4.6%.

simplify 2^3 ÷ 2^-3
leave your answer in the form 2^x, where x is an integer
these are the options for the answer
1

0

2^0

2^6

Answers

Answer:

[tex]2^{6}[/tex]

Step-by-step explanation:

[tex]2^3 \div 2^{-3}[/tex]

[tex]2^{3-(-3)}[/tex]

[tex]2^{3+3}[/tex]

[tex]2^{6}[/tex]

It took jack 4 and half minutes to do 100 multiplication facts how long it takes him to do 150

Answers

Answer:

6.75 min

Step-by-step explanation:

100 facts/4.5 min = 150 facts/x min

x=(150*4.5)/100=6.75

What is another way to write 2×5 without using the multiplication sign?

Answers

Answer:

see below

Step-by-step explanation:

You could write it as 2+2+2+2+2 or 5+5 bc multiplication is like repeated addition.

Answer:

You can use the repeated additional as given below.

Step-by-step explanation:

2+2+2+2+2 or 5+5

-5,-20,-80 find the common ratio

Answers

Answer:

The common ratio is 4

Step-by-step explanation:

To find the common ratio take the second term and divide by the first term

-20/-5 = 4

To verify take the third term and divide by the second

-80/-20 = 4

The common ratio is 4

Answer:

4

Step-by-step explanation:

To find the common ratio, divide one term by the term before it.

-20 ÷ -5 = 4

-80 ÷ -20 = 4

Each number is multiplied by 4 to get to the next number.

I hope this helps :))

How do I find the value of x for which line a is parallel to line b?

Answers

Answer:

x = 20

Step-by-step explanation:

3x + 6x = 180, if you make them supplementary then they will be parallel

9x = 180

x = 20

Using the data in the table, use the exponential smoothing method with alpha=0.5 and a February forecast of 500 to forecast
sales for May

Month Demand
January 480
February 520
March 535
April 550
May 590
June 630

Answers

Answer:

Step-by-step explanation:

The formula to calculate the forecast could be determine by using the exponential smoothing method :

[tex]Ft = F(t-1) + \alpha [A(t-1) - F(t-1)][/tex]

Where ,Ft is the Forecast for period t

F(t-1) is the Forecast for the period previous to t

A(t-1) is the Actual demand for the period previous to t

[tex]\alpha[/tex] = Smoothing constant

To get the forecast for may and june   the above formula with [tex]\alpha =0.5[/tex] and april forecast of 500 will be used

For march

[tex]=500+0.5(520-500)\\\\=500+0.5\times20\\\\=500+10\\\\=510[/tex]

For April

[tex]=510+0.5(535-510)\\\\=510+0.5\times25\\\\=510+12.5\\\\=522.5[/tex]

For May

[tex]=522.5+0.5(550-5225)\\\\=522.5+0.5\times27.5\\\\=522.5+13.75\\\\=536.25[/tex]

So forecast for May = 536.25

Two competing gyms each offer childcare while parents work out Gym A charges $9.00 per hour of childcare. Gym B
charges $0.75 per 5 minutes of childcare. Which comparison of the childcare costs is accurate?

Answers

Answer:

They charge an equal amount of money each hour.

Answer:

Gym B and Gym A charge the same hourly rate for childcare.

Step-by-step explanation:

answer on edge

Write an expression without exponent that is equivalent to 2 to 3rd power nd 4 to the 3rd power

Answers

Answer:

8 and 64

Step-by-step explanation:

[tex]2^3[/tex] and [tex]4^3[/tex]

[tex]2^3=8[/tex]

[tex]4^3=64[/tex]

Brian invests £6300 into his bank account.

He receives 4.9% per year compound interest.

How much will Brian have after 2 years?

Give your answer to the nearest penny where appropriate.

Answers

Answer:

Amount that Brian has after 2 years = £6932.53

Step-by-step explanation:

To find, the amount that Brian will have after 2 years:

Formula for amount where compound interest is applicable:

[tex]A = P \times (1+\dfrac{R}{100})^t[/tex]

Where A is the amount after t years time

P is the principal.

R is the rate of interest.

In the question, we are given the following details:

Principal amount,P = £6300

Rate of interest,R = 4.9%

Time,t = 2 years

Putting the values in formula:

[tex]A = 6300 \times (1+\dfrac{4.9}{100})^2\\\Rightarrow 6300 \times (\dfrac{104.9}{100})^2\\\Rightarrow 6932.53[/tex]

Hence, Amount that Brian has after 2 years = £6932.53

Answer:

THE ANSWER IS ABOVE

Step-by-step explanation:

hahahaha

What is the mixed number3 3/8 as a fraction

Answers

Answer:   Mixed Number to Fraction

Mixed Numbers to Improper Fraction

Mixed Numbers Improper Fraction

3 3/4                      15/4

3 3/8                      27/8

3 8/9                      35/9

Hope this helps!!

what function is increasing? will give brainlist !

Answers

Answer:

Option B.

Step-by-step explanation:

Option A.

f(x) = [tex](0.5)^{x}[/tex]

Derivative of the given function,

f'(x) = [tex]\frac{d}{dx}(0.5)^x[/tex]

      = [tex](0.5)^x[\text{ln}(0.5)][/tex]

      = [tex]-(0.693)(0.5)^{x}[/tex]

Since derivative of the function is negative, the given function is decreasing.

Option B. f(x) = [tex]5^x[/tex]

f'(x) = [tex]\frac{d}{dx}(5)^x[/tex]

      = [tex](5)^x[\text{ln}(5)][/tex]

      = [tex]1.609(5)^x[/tex]

Since derivative is positive, given function is increasing.

Option C. f(x) = [tex](\frac{1}{5})^x[/tex]

f'(x) = [tex]\frac{d}{dx}(\frac{1}{5})^x[/tex]

      = [tex]\frac{d}{dx}(5)^{(-x)}[/tex]

      = [tex]-5^{-x}.\text{ln}(5)[/tex]

Since derivative is negative, given function is decreasing.

Option D. f(x) = [tex](\frac{1}{15})^x[/tex]

                f'(x) = [tex]-15^{-x}[\text{ln}(15)][/tex]

                       = [tex]-2.708(15)^{-x}[/tex]

Since derivative is negative, given function is decreasing.

Option (B) is the answer.

Seventy-six percent of sunflower seeds will germinate into a flower, and a sample of 800 such sunflower seeds is randomly selected. The standard deviation for the number of sunflower seeds that will germinate in such samples of size 800 is:

Answers

Answer:

12.08

Step-by-step explanation:

For each sunflower, there are only two possible outcomes. Either it germinates, or it does not. The probability of a sunflower germinating is independent of other sunflowers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Seventy-six percent of sunflower seeds will germinate into a flower

This means that [tex]p = 0.76[/tex]

Samples of 800:

This means that [tex]n = 800[/tex]

The standard deviation for the number of sunflower seeds that will germinate in such samples of size 800 is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{800*0.76*0.24} = 12.08[/tex]

Quick Start Company makes a 12-volt car batteries. After many years of product testing, the company knows the average life of a Quick Start battery is normally distributed, with mean=45 months and a std. deviation = 8 months.

If Quick start guarantees a full refund on any battery that fails within the 36 month period after purchase, what percentage of its batteries will the company expect to replace?

If quick Start does not want to make refunds for more than 10% ofits batteries under the full refund guarantee policy, for how longshould the company guarantee the batteries (to the nearest month)

Answers

Answer:

The company will expect to replace 13.03% of batteries.

The company should guarantee the batteries for 35 months.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 45, \sigma = 8[/tex]

If Quick start guarantees a full refund on any battery that fails within the 36 month period after purchase, what percentage of its batteries will the company expect to replace?

This is the pvalue of Z when X = 36. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{36 - 45}{8}[/tex]

[tex]Z = -1.125[/tex]

[tex]Z = -1.125[/tex] has a pvalue of 0.1303.

The company will expect to replace 13.03% of batteries.

If quick Start does not want to make refunds for more than 10% ofits batteries under the full refund guarantee policy, for how longshould the company guarantee the batteries

They should guarantee to the 10th percentile, which is X when Z has a pvalue of 0.1. So it is X when Z = -1.28.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.28 = \frac{X - 45}{8}[/tex]

[tex]X - 45 = -1.28*8[/tex]

[tex]X = 34.76[/tex]

Rounding to the nearest month

The company should guarantee the batteries for 35 months.

Select the correct answer
Why are online payment services necessary?
OA
Individuals who sell items online cannot afford to deal with credit card companies.
B.
It is too risky to use credit cards online, and online payment services have better security
C. Government regulations require all online transactions be made using online payment services.
D.
Online payment services are the only payment method that individuals who sell items online trust.
Reset
Nalut

Answers

Answer:

B

Step-by-step explanation:it is really too risky to use credit card online because for someone who doesnt now if the busines is really considered as a trustful source or just a scam.

Answer:

Its A.) Individuals who sell items online cannot afford to deal with credit card companies.

Step-by-step explanation:

On plato

I need help please help

Answers

Answer:

Step-by-step explanation:

Note that 28 + 110 + 42 = 180, and that 28 + 42 + 110 = 180 also.

Since all three angles of one triangle are the same as the corresponding angles of the other triangle, the triangles are similar.

Want to donate to a better cause? Consider micro-lending. Micro-lending is a process where you lend directly to entrepreneurs in developing countries. You can start lending at $25. Kiva.org boasts a 99% repayment rate. The average loan to an entrepreneurs is $388.44 and the average loan amount is $261.14. With a total amount loaned of $283,697,150, how many people are lending money if the average number of loans per lender is 8?

Answers

Answer:

  135,797

Step-by-step explanation:

If the total loan amount is $283,697,150 and the average loan amount is $261.14, then the number of loans is ...

  $283,697,150/$261.14 = 1,086,379.5

If the average number of loans per lender is 8, then the number of lenders is ...

  1086379.5/8 = 135,797 . . . . people lending money

Assume that the heights of men are normally distributed with a mean of 70.9 inches and a standard deviation of 2.1 inches. If 36 men are randomly selected, find the probability that they have a mean height greater than 71.9 inches. Round to four decimal places.

Answers

Answer:

The probability that they have a mean height greater than 71.9 inches

P(  x⁻ ≥71.9) =  0.0022

Step-by-step explanation:

Explanation:-

Given mean of the Population μ= 70.9

Standard deviation of the Populationσ = 2.1

Given sample size 'n' =36

let x⁻ be the mean height

given  x⁻ =71.9 inches

[tex]Z=\frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }[/tex]

[tex]Z=\frac{71.9 -70.9}{\frac{2.1}{\sqrt{36} } } = \frac{1}{0.35} = 2.85[/tex]

The probability that they have a mean height greater than 71.9 inches

P(  x⁻ ≥71.9) = P(Z ≥ 2.85)

                    = 1 - P(Z≤ 2.85)

                   =  1 - ( 0.5 + A(2.85)

                   = 0.5 - A( 2.85)

                  = 0.5 - 0.4978

                  = 0.0022

The probability that they have a mean height greater than 71.9 inches

 P(  x⁻ ≥71.9) =  0.0022

Answer:

the answer is 0.0022

Step-by-step explanation:

The average number of children a Japanese woman has in her lifetime is 1.37. Suppose that one Japanese woman is randomly chosen. a. In words, define the random variable X. b. List the values that X may take on. c. Give the distribution of X.X~ _____(_____,_____) d. Find the probability that she has no children. e. Find the probability that she has fewer children than the Japanese average.

Answers

Answer:

a. X: amount of children that a Japanese woman has in her lifetime.

b. X can take natural numbers (all positive integers) as values.

c. X~Poi(1.37).

d. P(X=0)=0.2541

e. P(X<1.37)=0.6022

Step-by-step explanation:

a) This can be modeled with a Poisson distribution.

We let the variable X be the amount of children that a Japanese woman has in her lifetime.

The parameter of the Poisson distribution is λ=1.37.

This is also the value of the mean and the standard deviation.

b) X can take all positive integer values.

c) X is modeled as a Poisson variable with λ=1.37.

d) This can be calculated as:

[tex]P(0)=\lambda^ke^{-\lambda}/k!=1.37^{0} \cdot e^{-1.37}/0!=1*0.2541/1=0.2541\\\\[/tex]

e) Having fewer children than the average means that she has one or none children.

This can be calculated as:

[tex]P(X<1.37)=P(0)+P(1)\\\\\\P(0)=1.37^{0} \cdot e^{-1.37}/0!=1*0.2541/1=0.2541\\\\P(1)=1.37^{1} \cdot e^{-1.37}/1!=1.37*0.2541/1=0.3481\\\\\\P(X<1.37)=0.2541+0.3481=0.6022[/tex]

Solve the equation. 3= x/3.3 what is x=

Answers

Answer:

9.9

Step-by-step explanation:

remember your distribution rules.

x/3.3=3 make sure x is by itself. so take 3*3.3

When you have x divided by a number equaling a number take the number it equals to and multiply by the number that x is being divided by.

3=x/3.3

move 3.3 by multiplying it by 3 which gives you 9.9.

The solution of x in equation 3 = x / 3.3 is,

⇒ x = 9.9

We have to given that;

Expression is,

⇒3 = x / 3.3

Now, We can simplify the equation for x as;

⇒ 3 = x / 3.3

Multiply by 3.3 both side,

⇒ 3 × 3.3 = x

⇒ 9.9 = x

⇒ x = 9.9

Thus, Solution is,

⇒ x = 9.9

Learn more about the equation visit:

brainly.com/question/28871326

#SPJ6

Which number best represents the location of the point on the line?
X
-4.44
-T
11
3
_V17
RETRY

Answers

Answer:

- 11 over 3 Just did it on edg 2021

Which solution set is graphed on the number line?
1
4
x>1
0 x > 1
Ox<1
X31​

Answers

Answer:

4

Step-by-step explanation:

ur welcome hopefully this helps

An amount was invested at % r per quarter. What value of rwill ensure that accumulated amount at the end of one year is 1.5 times more than amount invested? Correct to 2 decimal places

Answers

Answer:

  42.67%

Step-by-step explanation:

The annual growth factor for interest at annual rate r compounded quarterly is ...

  (1 +r/4)^4

You want that value to be 1.5:

  1.5 = (1 +r/4)^4

  1.5^(1/4) = 1 +r/4

  (1.5^(1/4) -1) = r/4

  4(1.5^(1/4) -1) = r ≈ 0.426728

The rate r must be about 42.67%.

_____

Comment on the wording

We interpreted the problem to mean the end-of-year amount is 1.5 times the beginning-of-year amount. That is, it is "1.5 times the amount invested."

The word "more" is typically used when addition is involved. For example, "25% more" means 25% of the original is added to the original. We occasionally see "more" where "x times more" is intended to mean "x times", rather than "x times the amount, added to the original amount."

Factorizar e indicar cuántos factores primos tiene -3+3x^2+y-x^2*y-y^2+x^2*y

Answers

the answer is -3+3x2+y-y2

Please answer this correctly

Answers

The right answer is 40 cm

please see the attached picture for full solution

Hope it helps

Good luck on your assignment

The value z is directly proportional to c. When z = 20, c = 10. Find an equation relating z and c. *

Answers

Answer:

a) The equation of Z and C is Z =K C

b) K = 2

Step-by-step explanation:

Explanation :-

Given data Z is directly proportional to C

              ⇒   Z ∝ C

               ⇒  Z = K C

The equation of relating Z and C    

               Z = K C

Given Z = 20 and C =10

              20 = K ( 10)

          ⇒ K = 2

A 15-inch candle is lit and steadily burns until it is burned out. Let b represent the burned length of the candle (in inches) and let r represent the remaining length of the candle (in inches).
a. Write a formula that expresses r in terms of b.When 3.1 inches have burned from the candle, the remaining length of the candle is inches.
b. Graph the relationship between a and b

Answers

Answer:

(a)r=15-b

11.9 Inches

(b)See attached

Step-by-step explanation:

Length of the candle =15 inch

Let b represent the burned length of the candle (in inches)

Let r represent the remaining length of the candle (in inches).

Therefore:

(a) r+b=15

r=15-b

When b=3,1 Inches

Remaining Length, r=15-3.1=11.9 Inches

(b)The graph showing te relationship between r and b is shown below.

r is plotted on the y-axis while b is plotted on the x-axis as labelled.

Formula that express r in terms of b is

[tex]r=15-b[/tex]

Remaining length of candle is 11.9 inches

Given :

A 15-inch candle is lit and steadily burns until it is burned out

Let b represent the burned length   and let r represent the remaining length  

We need to write the formula

remaining length = initial length - burned length

[tex]r=15-b[/tex]

When 3.1 inches have burned from the candle, the remaining length of the candle is inches.

b is 3.1

remaining length [tex]r=15-3.1=11.9[/tex] inches

now we graph the relationship

Graph is attached below.

Learn more :  brainly.com/question/13844802

Find the constant of variation k for the direct variation 3x+5y=0

Answers

Answer:

-3/5

Step-by-step explanation:

3x+5y=0

Subtract 3x from each side

3x+5y-3x=0-3x

5y = -3x

Divide each side by 5

5y/5 = -3x/5

y = -3/5 x

A direct variation is y = kx

y = -3/5 x

The constant of variation is -3/5

Calculating the standard deviation (σ) for a list of n data values: 1. Calculate the average value. 2. Subtract the average value from each individual data value and enter the results in a column to the right of the data values. 3. Square each of the results obtained in step 2, and enter these in a new column to the right. 4. Sum the squares obtained in step 3. 5. Divide the result from step 4 by (n - 1) (the total number of measurements minus 1). 6. Take the square root of the result from step 5. This is the standard deviation. Expressed as an equation, the standard deviation of n measurements of data value x is: σ = ( Σ (x - xavg)2 / (n - 1) )1/2 Using the 6 steps above (or the spreadsheet function), calculate the standard deviation for the six values on page 16 and enter your answer below. Enter your result with only one sig fig, and remember to use a zero before the decimal point for values less than 1, for example 0.05 or 0.01.

Answers

Answer:

Step-by-step explanation:

The missing list of the data values for the question are as follows:

1             1.03

2             1.01

3             0.96

4             0.96

5             0.99

6             1

7             1.01

8             0.98

9             1.02

10            1.03

11             1

12             0.99

13             1

14             0.97

15             1.01

               [tex]x_i[/tex]                          [tex](x_i - \bar x)[/tex]                              [tex](x_i - \bar x)^2[/tex]

1             1.03                         0.03                                  0.0009

2             1.01                         0.01                                   0.0001

3             0.96                        -0.4                                   0.0016

4             0.96                        -0.4                                   0.0016

5             0.99                        -0.1                                   0.0001

6             1                               0.0                                   0.0

7             1.01                           0.1                                   0.0001

8             0.98                        -0.2                                   0.0004

9             1.02                          0.2                                   0.0004

10            1.03                          0.3                                   0.0009

11             1                               0.0                                   0.0

12             0.99                        -0.1                                   0.0001

13             1                               0.0                                   0.0

14             0.97                        -0.03                                   0.0009

15             1.01                           0.1                                   0.0001

The average value for x is calculated as:

[tex]\bar x = \dfrac{14.96}{15}[/tex]

[tex]\bar x = 0.997 \\ \\ \bar x \approx 1.00[/tex]

[tex]\sum (x-x_i)^2 = 0.0072[/tex]

[tex]\dfrac{\sum (x-x_i)^2 }{n-1}= \dfrac{0.0072}{15-1} \\ \\ = \dfrac{0.0072}{14} \\ \\ = 0.00051[/tex]

[tex]\sigma = \sqrt{\dfrac{\sum (x-x_i)^2 }{n-1}} = \sqrt{0.00051} \\ \\ \sigma =0.0226 \\ \mathbf { \\ \sigma =0.02 \ to \ one \ significant \ figure}[/tex]

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