Njoki planted trees at intervals of 22m apart on the diagonal of a rectangular plot of land that measures 48m by 20m . How many trees did he plant​

Answers

Answer 1

Answer:

The number of tree is 2

Explanation:

the diagonal of the rectangular plot of land  can be found using Pythagoras theorem (the diagonal is the hypotenuse)

Given

length of land x= 48m

width of land y= 20m

digonal z= ?

[tex]z^2= x^2+y^2\\\\z=\sqrt{ x^2+y^2} \\[/tex]

substituting the values of x and y into the equation we can solve for z

[tex]z=\sqrt{ 48^2+20^2} \\\\z=\sqrt{ 2304+400} \\z=\sqrt{ 2704} \\z=52m\\[/tex]

The diagonal is 52m

Hence since the interval = 22m the number if treee is

[tex]\frac{52}{22} = 2.36\\[/tex]

The number of trees must be whole numbers , the number of tree is 2


Related Questions

A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 65 m/s in 5 seconds. What
is the acceleration?
-13 m/s
-6 m/s²
6mis?
13 m/s2

Answers

Acceleration = (change in speed) / (time for the change)

Change in speed = (speed after the change) - (speed before the change)

Change in speed = (65 m/s) - (35 m/s)  =  30 m/s

Acceleration = (30 m/s) / (5 s)

Acceleration = 6 m/s²

An escalator is used to move 25 passengers every minute from the first floor of a department store to the second. The second floor is located 5.30 meters above the first floor. The average passenger's mass is 60 kg. Determine the power requirement of the escalator in order to move this number of passengers in this amount of time.
Please help me quickly!

Answers

Answer:

1298.5watt

Explanation:

Power is defined as the rate at which work is done

Expressed mathematically as;

P = F × d/ t; F = force or weight of object ;d is height or distance sustain and t is time covered

Hence for 1 person the power consumption is ;

Note weight =mass× acceleration of free fall due to gravity,g

g is known as 9.8m/S2

Time taken is 1min which is 60 sec

60 ×9.8 × 5.3/60 = 51.94 watt

Hence for 25 persons we have

25 × 51.94 =1298.5watt

1.3kilo watt( kilo is 1000)

The work done by the escalator is 3,080.4 joules and the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.

The Work Done is calculated as:

Force (F) = 60 × 9.8

Distance (d) = 5.30 meters

Work (W) = F × d

Work (W) = (60 × 9.8) × 5.30

Work (W) = 3,080.4 joules

The Power is calculated as:

Time (t) = 1 minute

Power (P) = Work / Tim (t)

Power (P) = 3,080.4 / 60

Power (P) = 51.34 watts

Therefore, the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.

To know more about the work done and power:

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Benda setinggi 3 cm diletakkan pada jarak 10 cm di depan cermin cekung yang berjari-jari


kelengkungan 10 cm. Tentukan:


 Jarak bayangan


 Perbesaran bayangan


 Sifat bayangan

Answers

Answer:

a) Shadow distance

10 cm in front of the mirror.

b) Zoom in the shadow

The shadow formed is the same height as the object and is placed also at the centre of curvature of the mirror as shown in the attached image to this solution.

c) The nature of the shadow

The shadow formed is real, inverted, same size as the object and formed at the centre of curvature.

Explanation:

English Translation

Objects as high as 3 cm are placed at a distance of 10 cm in front of a concave mirror with 10 cm curvature. Determine:

a) Shadow distance

b) Zoom in the shadow

c) The nature of the shadow

Solution

The mirror equation is given as

(1/f) = (1/v) + (1/u)

f = focal length of the mirror = (radius of curvature)/2 = 10/2 = 5 cm

v = image distance = ?

u = object distance = 10 cm

We can then calculate the shadow' s distance from the mirror thus

(1/5) = (1/v) + (1/10)

(1/v) = 0.2 - 0.1 = 0.1

v = (1/0.1) = 10 cm

b) Zoom in the shadow

Since the object is placed at the centre of curvature, as shown in the attached image, the image is formed at a point of intersection of rays. The image formed is the same height as the object and is placed also at the centre of curvature of the mirror.

c) The nature of the shadow

Since the mirror is a concave mirror, the image is real and formed in front of the mirror. The image is also inverted and formed at the centre of curvature of the mirror.

Hope this Helps!!!

3.
If you are part of a center or network, you can use program-level data to
A. change the way you record and maintain information.
B. identify professional development needs.
C. improve the management systems to support child learning.
D. change the way you speak with families

Answers

Answer:

A

Explanation:

Answer: A

Explanation:

a care starting from rest has an acceleration 0.3 m/s square, calculate the velocity and distance travelled by this car after 2 minutes?

Answers

Answer:

Final velocity (v) = 36 m/s

Distance traveled (s) = 2,160 m

Explanation:

Given:

Initial velocity (u) = 0

Acceleration (a) = 0.3 m/s

Time travel (t) = 2 minutes = 120 seconds

Find:

Final velocity (v) = ?

Distance traveled (s) = ?

Computation:

v = u + at

v = 0 + 0.3(120)

v = 0.3(120)

v = 36 m/s

Final velocity (v) = 36 m/s

Distance traveled (s) = ut + (1/2)at²

Distance traveled (s) = (0.5)(0.3 × 120 × 120)

Distance traveled (s) = 2,160 m

a vector points 12.0 units along the x-axis and 9.00 units along the y-axis. find the magnitude of the vector

Answers

Explanation:

R = [tex]\sqrt{(12.0)^{2} + (9.00)^{2}}[/tex] = 15 UNIDADES

right auricale is bigger then left aurical, why?

Answers

Explanation:

Veins carry deoxygenated blood from different parts of the body to our heart. ... Since a larger volume of blood is collected in the right auricle than that of the left auricle, right auricle is larger than the left auricle.

A closed-pipe resonator has a length of 1.73 m. The frequency of its second harmonic if the speed of sound is 343 m/s is: a)49,5 Hz b)99.13 Hz c)20.6 Hz d)72 Hz

Answers

Answer:

There is no answer, since a closed-pipe resonator can NOT have a second harmonic. However, if you were to plug the pipe length and the speed of sound into the closed-pipe equation anyway you would get 49.56 as your fundamental frequency, which means that 99.13 would be your "plug and play" 2nd harmonic.

Explanation:

How much energy (in Joules) is released when 12.0 g of water cools from 20.0 °C to 11.0 °C? This is a grade 10 question from the Climate unit (from Canada)

Answers

Answer: - 452.088joule

Explanation:

Given the following :

Mass of water = 12g

Change in temperature(Dt) = (11 - 20)°C = - 9°C

Specific heats capacity of water(c) = 4.186j/g°C

Q = mcDt

Where Q = quantity of heat

Q = 12g × 4.186j/g°C × - 9°C

Q = - 452.088joule

An injured monkey sits perched on a tree branch 9 m above the ground, while a wildlife veterinarian is kneeling down in the bushes 90.0 m away attempting to subdue the monkey with a tranquilizer gun. The vet knows that the moment the gun fires, the monkey will be frightened and fall down from the branch. At what angle up from the ground must the veterinarian aim the gun so that the tranquilizer dart will hit the falling monkey? Given the angle, what is minimum speed at which the tranquilizer dart must leave the gun to still hit the monkey?

Answers

Answer:

The hunter should aim directly at the perched monkey because the tranquilizer dart will fall away from the line sight at the same rate that the monkey falls from its perch.

Tan theta = 9 / 90 = .1      so theta = 5.71 deg

The time for the monkey to reach the ground is

t = (2 h / g)^1/2 = (18 / 9.8)^1/2 = 1.36 sec

So the horizontal speed of the dart must be at least

Vx = 90 m / 1.36 sec = 66.4 m/s

Vx = V cos theta

V = 66.4 m/s / cos 5.71 = 66.7 m/s

The angle of projection of the tranquilizer dart is 5.7⁰

The horizontal speed of the tranquilizer dart is 66.5 m/s

The given parameters;

vertical position of the monkey, y = 9 mhorizontal position of the veterinarian, x = 90

The angle of projection of the tranquilizer dart is calculated as;

[tex]tan(\theta) = \frac{y}{x} \\\\tan(\theta) = \frac{9}{90} \\\\tan(\theta) = 0.1\\\\\theta = tan^{-1}(0.1)\\\\\theta = 5.71 ^0[/tex]

The speed of the tranquilizer dart is calculated as;

X = v₀ₓt

where;

t is the time to reach maximum height

X is the horizontal displacement = 90 m

The time to reach maximum height is calculated as;

[tex]h = v_0_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 9}{9.8} } \\\\t = 1.36 \ s[/tex]

The horizontal speed of the tranquilizer dart is calculated as;

[tex]X = v_0cos(\theta) \times t\\\\90 = v_0\times cos(5.71) \times 1.36\\\\90 = 1.353 v_0\\\\v_0= \frac{90}{1.353} \\\\v_0 = 66.5 \ m/s[/tex]

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what are two things that are infinite?

Answers

Answer:

Infinity = Never ending

Explanation:

The universe could be infinite, both in terms of space and time, but there is currently no way to test whether it goes on forever or is just very big. The part of the universe we are able to observe is finite, measuring about 46 billion light years in diameter.

The set of natural numbers is an infinite set. This kind of infinity is, by definition, called countable infinity. All sets that can be put into a bijective relation to the natural numbers are said to have this kind of infinity. This is also expressed by saying that the cardinal number of the set is aleph-naught (ℵ0).

Hope this helps. Mark as brainliest!

STARS ARE INFINITE , NUMBERS ARE INFINITE

Explanation:

Explain how series circuits use current and voltage and Explain how parallel circuits use current and voltage

Answers

'''In a series circuit, the sum of the voltages consumed by each individual resistance is equal to the source voltage. Components connected in parallel are connected along multiple paths so that the current can split up; the same voltage is applied to each component.''

HELLO PLZ HELP
Write the properties of brake fluid

Answers

Answer:

Explanation:

If you look at the chemistry behind most brake fluid, it comes from the combination of various types of glycols, which are basically a mixture of non-petroleum and other alcohol-based fluids. After a mixing process, the chemical name gets shortened to “polyglycol”. In addition, there are also high-grade silicone-based fluids, which cannot be mixed with any other type of fluid. So whether it's used in the brake or clutch system, it's important to understand the differences between these common types of brake fluid.

The brake fluid must maintain specific properties. Our brakes can get hot, sometimes up to 1200 degrees, so the fluid needs a high boiling point. Also, because our vehicles experience seasons just as we do, it’s important to have low freezing point as well. On top of maintaining both extremes, it's designed not to damage any rubber components in the brake system.

As a result, the chemical properties found in most brake fluids can permanently dull or damage paint. So be sure to handle with care and be quick to clean any accidental overspills. Brake fluid is hydroscopic, meaning it has a natural tendency to absorb moisture. And over enough time the added moisture can result in corrosion build up or a decreased boiling point. It’s never a bad idea to change your brake fluid every couple of years and try not to leave your reservoir cap off any longer than needed

Answer: high operation temperatures, good low-temperature and viscosity-temperature properties, physical and chemical stability, protection of metals from corrosion, inactivity with respect to mechanical rubber articles, and lubricating effect

Hope this helps

The amplitude of a particle executing simple harmonic motion is 5cm, while its angular velocity is 10 rads -1 . Calculate the magnitude of the maximum acceleration of the particle.

Answers

Answer:

a_max = 50 cm/s^2

Explanation:

To find the magnitude of the maximum acceleration of the particle, you take into account the equation of motion in a simple harmonic motion:

[tex]x=Acos(\omega t)[/tex]

ω: angular velocity = 10 rad/s

A: amplitude = 5 cm

The acceleration is given by:

[tex]a=\omega^2 x[/tex]

and the maximum acceleration is obtained when the cosine function is maximum, that is, when cos(wt) = 1. Then, you have:

[tex]a_{max}=\omega^2 x_{max}=\omega^2A[/tex]

Then, you replace the values of w and A in order to calculate a_max:

[tex]a_{max}=(10rad/s)^2(5cm)=50\frac{cm}{s^2}[/tex]

hence, the maximum acceleration is 50 cm/s^2

Just need the answer to D please

Answers

The boat has to pull with MORE force. Don't forget about the force of friction with the water, pulling the skier in the backwards direction. The force that accelerates him is the NET force ... boat force minus water resistance. So the boat force has to be greater than the net accelerating force.

The object will feel minimum force of gravity at the

Answers

Answer:

space , small amount of gravity is found in the space ,infact we can say that there is no gravity in the space

Answer:

Poles

Explanation:

The gravitational force is maximum at the equator and minimum at the poles.

a motorcar is moving with a velocity of 108 km / h and it takes 4s to stop after the brakes are applied calculate the force exerted by the brakes on the motorcar if it's mass along with the passengers is 1000 kg​

Answers

Answer:

-7500 N

Explanation:

v₀ = 108 km/h = 30 m/s

v = 0 m/s

t = 4 s

a = Δv / Δt

a = (0 m/s − 30 m/s) / 4 s

a = -7.5 m/s²

F = ma

F = (1000 kg) (-7.5 m/s²)

F = -7500 N

Answer:-7500

Explanation v₀ = 108 km/h = 30 m/s

v = 0 m/s

t = 4 s

a = Δv / Δt

a = (0 m/s − 30 m/s) / 4 s

a = -7.5 m/s²

F = ma

F = (1000 kg) (-7.5 m/s²)

F = -7500 N

Ahoy starting from rest moves with a distance of 200m in 10 seconds...Find the magnitude of acceleration

Answers

Answer:

The magnitude of acceleration is 2m/s² .

Explanation:

First, you have to find the velocity as it starts to travel 200m in 10s. The formula of velocity is V = Distance/Time, then you have to substitute the values into the formula :

[tex]v = d \div t[/tex]

[tex]let \: d = 200 \\ let \: t = 10[/tex]

[tex]v = 200 \div 10[/tex]

[tex]v = 20m/s[/tex]

Next, you have to substitute the values into the acceleration formula, a = (v-u)/t where v represents final velocity, u is initial velocity and t is time taken :

[tex]a = \frac{v - u}{t} [/tex]

[tex]let \: v = 20 \\ let \: u = 0 \\ let \: t = 10[/tex]

[tex]a = \frac{20 - 0}{10} [/tex]

[tex]a = \frac{20}{10} [/tex]

[tex]a = 2m/ {s}^{2} [/tex]

If mass = 30kg, gravity = 10 N/kg and height is 2m of a car. Calculate the gravitational potential energy.

Answers

Answer:

P.E.=600Nm

Explanation:

m=30kg

g=10m/s²

h=2m

P.E.=?

as we know that

P.E.=mgh

P.E.=30kg×10m/s²×2m

P.E.=600Nm

Which of the following characterizes the particles in this diagram?

A. Two positive charges
B. One positive charge and one negative charge
C. Two negative charges
D. Two neutral charges

Answers

Answer:

B

Explanation:

One positive charger and one negative charger

a motorcar is moving with a velocity of 108 km / h and it takes 4s to stop after the brakes are applied calculate the force exerted by the brakes on the motorcar if it's mass along with the passengers is 1000 kg​

Answers

Answer: - 7500N

Explanation:

Given the following :

Initial Velocity of car = 108km/hr

Time taken to stop after applying brakes = 4s

Mass of passengers in car = 1000kg

Force exerted by the brakes on the car =?

After 4s, then final Velocity (V) = 0

Initial Velocity (u) of the car = 108km/hr

108km/hr = (108 × 1000)m ÷ (3600)s = 30m/s

Force exerted = mass(m) × acceleration(a)

Acceleration of car = Change in Velocity with time

a = (v - u) / t

a = (0 - 30) / 4

a = - 30/ 4

a = - 7.5m/s^2

Therefore,

Force exerted = mass(m) × acceleration(a)

Force exerted = 1000kg × (-7.5)m/s^2

Force exerted = - 7500N

Answer:

The force exerted by the brakes on the motor car is -7500 N.

Explanation:

Given :-

Mass of the motor car along with passengers (m)= 1000 kgInitial velocity (u) = 108 km/hTime taken (t) = 4 s

To find :-

The force exerted by the brakes on the motor car.

Solution :-

Since the car stops, the final velocity (v) will be 0 m/s.

• Initial velocity (u) = 108 km/h.

Converting initial velocity into m/s.

We know that,[tex] \sf{1\:km/h=\dfrac{5}{18}\:m/s}[/tex]

Then initial velocity,

= [108 × 5/18 ] m/s

= 30 m/s

Now find the force exerted by the brakes.

Formula used :

[tex]{\boxed{\sf{F=\dfrac{m(v-u)}{t}}}}[/tex]

   [put values]

[tex]:\implies \sf \: F= \dfrac{1000(0 - 30)}{ 4} \\ \\ : \implies \sf \: F \: = \dfrac{ - 30000}{4} \\ \\ : \implies \sf \: F \: = - 7500[/tex]

The force exerted by the brakes on the motor car = -7500 N.

•The negative sign of force(F) means that the force was applied in opposite direction of motion.

__________________

Which of these would not improve accuracy? 

A)Taking a bigger sample size

B)Using a bigger range of the independent variable

C)Using measuring instruments that can read to a greater number of decimal places

D)Remove anomalies​

Answers

I think it’s D, mostly just because all the other ones seem like they couldn’t be the answer.
It’s not D, it’s B. Using a bigger range would mean there’s a greater expanse of answers, not a precise, accurate reading. Removing anamalies would make it more accurate- they’re results that don’t fit the pattern, so removing them would make the results even more results. Therefore, the answer is B. Hope this helps!

PLEASE HELP. Really important

Answers

Explanation:

2) C would need the least effort, because the longer the effort distance, the least the effort applied.

potential energy is frequintly converted into kenetic energey. kenetic energey

Answers

Answer:

When an object falls, its gravitational potential energy is changed to kinetic energy. ... Gravitational potential energy for a mass m at height h near the surface of the Earth is mgh more than the potential energy would be at height 0. (It's up to you where you choose height 0.)

Explanation:

Answer:

Qwertyujiknb vcdxrftyhbvcdxrft6y7uij

Explanation:

conditions for equilibriam

Answers

Statics is the study of forces in equilibrium. Two conditions must be met to achieve equilibrium, which is defined to be motion without linear or rotational acceleration. The first condition necessary to achieve equilibrium is that the net external force on the system must be zero, so thatnet F=0. net F = 0 .

What is the wavelength of a 1.28 x 10^17 Hz wave?

Answers

Answer:

The wavelength of the wave is 2.34 nm.

Explanation:

It is required to find the wavelength of a [tex]1.28\times 10^{17}\ Hz[/tex] wave. A wave moves with a speed of light. Speed of a wave is given in terms of wavelength and frequency. So,

[tex]v=f\lambda[/tex]

[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{1.28\times 10^{17}}\\\\\lambda=2.34\times 10^{-9}\ m\\\\\text{or}\\\\\lambda=2.34\ nm[/tex]

So, the wavelength of the wave is 2.34 nm.

The wavelength of the wave is 2.34 × 10⁻⁹ meters.

Given the data in the question;

Frequency; [tex]f = 1.28*10^{17}Hz[/tex]

Wavelength; [tex]\lambda =\ ?[/tex]

To determine the wavelength of the wave, we use the expression for the relations between wavelength, frequency and speed of light.

[tex]\lambda = \frac{c}{f}[/tex]

Where [tex]\lambda[/tex] is wavelength, f is frequency and c is speed of light ( [tex]3*10^8m/s[/tex] )

We substitute our values into the equation

[tex]\lambda = \frac{3*10^8m/s}{1.28*10^{17}Hz} \\\\\lambda = \frac{3*10^8m/s}{1.28*10^{17}s^{-1}} \\\\\lambda = 2.34 * 10^{-9}m[/tex]

Therefore, the wavelength of the wave is 2.34 × 10⁻⁹ meters.

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Ethan pushes a wooden box across a carpeted floor. Then he pushes the same box across a smooth marble floor. Why does Ethan find it easier to push the box on the marble floor than on the carpeted floor?

A. The box experiences more friction on the marble floor.
B.The box experiences less friction on the marble floor.
C.The box experiences more applied force on the marble floor.
D.The box experiences less normal force on the marble floor.

Answers

Answer:

B.The box experiences less friction on the marble floor

Explanation:

Answer:

B. The Box experiences less friction on the marble floor

Explanation:

This is because the the carpet is not a flat surface and the marble is smooth

40 POINTS!!! + BRAINLIEST!!!

In your own words, explain how a pendulum demonstrates the concepts of the conservation of energy. (1 or 2 sentences long)

Answers

Answer:

I think it is better if you read and shortly write my explanation

Explanation:

simple pendulum with no friction, mechanical energy is conserved. Total mechanical energy is a combination of kinetic energy and gravitational potential energy. As the pendulum swings back and forth, there is a constant exchange between kinetic energy and gravitational potential energy.

Consider a cylindrical crew module with a diameter of 5 meters, a length of 15 meters, and a crew of 6 people. The module contains air that is at
standard sea-level atmospheric pressure and temperature. The sea level density of air at 20 degrees Celsius is 1.204 kg/m3.
What is the volume of the crew module? Provide your answer in m' with at least 2 decimal places.​

Answers

Answer:

  294.524 m^3

Explanation:

The volume of a cylinder is given by the formula ...

  V = πr^2h

For a radius of 2.5 m and a length of 15 m, the volume is ...

  V = π(2.5 m)^2(15 m) = 93.75π m^3 ≈ 294.524 m^3

The volume is about 294.52 cubic meters.

I NEED ANSWER RN OR ILL BE DED

Answers

Answer:

i) O m/s² as velocity is constant

ii) 20m/s

iii)Hint:Calculate the area of the graph,that is;below the line, for the first 15 seconds only

Hope this helps.

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