One compound in the list below is a gas at room conditions, while all of the others are liquids or solids. For each compound, indicate whether it is the gas or the force most responsible for it being a liquid or solid.
First list:
A. CH3OH
1. a gas2. dispersion forces 3. dipolar forces4. hydrogen bonds5. ionic bonds6. covalent bondsB. CH4
1. a gas2. dispersion forces 3. dipolar forces4. hydrogen bonds5. ionic bonds6. covalent bondsC. CaCO3
1. a gas2. dispersion forces 3. dipolar forces4. hydrogen bonds5. ionic bonds6. covalent bondsD. C6H14
1. a gas2. dispersion forces 3. dipolar forces4. hydrogen bonds5. ionic bonds6. covalent bondsSecond list:
A. H2O
B. C2H2
C. CCl4
D. KCl

Answers

Answer 1

Answer:

First list

A. CH3OH----hydrogen bonds

CH4----dispersion forces

CaCO3---ionic bonds

C6H14----dispersion forces

Second list

H2O------ liquid----hydrogen bonds

C2H2----gas---dispersion forces

CCl4---liquid---dispersion forces

KCl----solid---ionic bonds

Explanation:

For every compound, the intermolecular forces decide whether the substance will be solid liquid or gas. Molecules are known to associate with each other in any particular state of matter. These molecules are held together by different intermolecular interactions with varying degrees of strength. The strength of the intermolecular interaction between the molecules of a substance will decide if the substance will be a solid, liquid or gas.

When the intermolecular forces are very strong such as in ionic solids and covalent network solids, the substance exists as a solid. When the intermolecular forces are not so strong such as dispersion forces and hydrogen bonds, the substance exists as a liquid. However, very weak intermolecular dispersion forces are found in gases hence the molecules are relatively free when compared to molecules of liquids and solids.


Related Questions

When researchers need to prepare many reactions for polymerase chain reaction (PCR) amplification, they often create a "master mix" solution. A master mix contains the reagents common to all the planned PCR amplifications, regardless of the target DNA. Making a master mix is a way to minimize the number of pipetting steps.Suppose a researcher needs to PCR amplify seven different genes of interest from different organisms. The researcher prepares a master mix and dispenses it to seven different PCR tubes, one for each gene of interest.Select the PCR components the researcher must add to each of the seven tubes of master mix to selectively amplify each gene of interest.dNTPsMg2+-Mg2+-based bufferprimersDNA polymeraseDNA template

Answers

Answer:

The master mix contains the following reagents: dNTPs, DNA Polymerase, PCR buffer and MgCl2.

Explanation:

The DNA templates are the gene fragments to amplify by PCR, thereby they have to be added separately in each tube. Moreover, the primer pairs are specific for each gene, thereby they have to be added separately in each tube.  

Deoxynucleotide triphosphates (dNTPs) are the building blocks of the DNA molecules: dGTP, dATP, TTP, and dCTP.

The PCR buffer provides a suitable medium for the activity of the DNA polymerase, often it contains Tris-Hcl and KCl.

MgCl2 is a cofactor for the activity of the DNA Polymerase.

The DNA Polymerase is an enzyme that amplifies DNA by adding nucleotides to the 3' end.

A pure sample of the R enantiomer of a compound has a specific rotation, [ α], of +20 °. A solution containing 0.2 g/mL of a mixture of enantiomers rotates plane polarized light by −2 ° in a 1 dm polarimeter. What is the enantiomeric excess (%ee) of the mixture?

Answers

Answer:

Explanation:

The specific rotation of the sample is -2 degrees/0.2 g/mL of mixture

This equals -10 degrees/g/mL of sample.

let the proportion of the R (+) enantiomer be x. The proportion of the S (-) enantiomer in the mixture will be given by (1-x).

specific rotation of the mixture = proportion of R enantiomer* its specific rotation + proportion of S enantiome * its specific rotation

i.e.

-10 = x *(+20) + (1-x)*(-20)

-10 = 20x-20 + 20x

-10+20 = 40x

+10 = 40 x

x=10/40 = 25%

Since the proportion of the other enantiomer is 1-x, it is 0.75 or 75%

So the mixture contains 25% R, 75% S, giving you an excess of 50%.

Answer:

10%

Explanation:

Enantiomeric excess is a way of describing how optically pure a mixture is by calculating the purity of the major enantiomer. It can range from 0%-100%. Enantiomeric excess ( ee ) can also be defined as the absolute difference between the mole fractions of two enantiomers.

Enantiomeric excess is also called optical purity. This is because chiral molecules cause the rotation of plane-polarized light and are said to be optically active. An enantiomerically pure sample has an enantiomeric excess of 100 percent

Enantiomeric excess = observed specific rotation/specific rotation of the pure enantiomer x 100

From the data given in the question;

observed specific rotation= -2°

specific rotation of the pure enantiomer = +20°

Therefore;

ee= 2/20 ×100

ee= 10%

Explain why both square planar and tetrahedral complexes have coordination number=4, and yet square planar complexes can never be chiral while tetrahedral complexes can.

Answers

Answer:

The coordination number is 4.  

Explanation:

Square planar clusters can be either cis or trans, as they form 180 and 90-degree bond angles. Therefore, a pair of ions may be adjacent (cis) to one another and immediately across (trans) from one another. A square planar molecule could never be simultaneously cis and trans, so because several coordinators are 4. Since linear complexes have only an angle of a bond of 180 degrees, they can not have cis or trans-isomers. In the coordination complex, there is only yet another way possible of bonding the two binding sites to the steel.

How many significant figures are in 382.90?

Answers

Answer:

5

Explanation:

Answer:

5

Explanation:

The realization that guanine and thymine base pair to cysteine and adenine, respectively, through their keto-like tautomeric forms has ultimately led to which types of technologies seen in popular TV shows like CSI and Law and Order?
a. DNA sequencing and profiling
b. Flexible display monitors
c. Smart phones
d. Police cars

Answers

Answer:

The correct answer to the following question will be Option A (DNA sequencing and profiling).

Explanation:

It is indeed a procedure through which a specific DNA sequence named as the profile is chosen to take from either a sample or perhaps a survey. For humans, much more of the DNA sequence will be the same, although only different regions differ in sequencing, such locations are considered polymorphic. The disparity between individuals regardless of such a particular process is named as polymorphisms, and then this method is being used in the detection of murders, parental conflicts, etc.

The other three situations aren't connected to the situation in question. That option 1 seems to be the right answer.

Please choose one of the choices

Answers

Answer:

A. the law of constant composition

Explanation:

The molecules in the container would have the same composition because they would have traded around atoms until an equilibrium was reached with every molecule having 1 Hydrogen and 1 Chlorine.

What would cause a balloon to expand if taken to the top of a mountain?
O A. Increased molecular collision
O B. Increased amount of molecules
O C. Lowered temperature
D. Lowered pressure

Answers

Answer:

D. Lowered pressure

Explanation:

As you go to more altitude or height, the atmospheric pressure significantly lowers so the gas molecules are free to expand and take up as room as possible.

This is best explained by Boyle's law where pressure and volume are inversely related, where if one thing goes up another goes down. Here the pressure goes down, so volume increases and ballon expands.

A microwave has a wavelength of 0.028 m. What us this wavelength in scientific notation

Answers

Answer:

2.8 times 10^ -2

Explanation:

scientific notation is supposed to be a number between 1 and 10

the decimal point moves 2 to the right in order to get 2.8 which makes the exponent negative

The calculated yield for the production of carbon dioxide was 73.4g. When the
experiment was performed in the lab, a yield of 72.3g was produced. What is the
percent yield of carbon dioxide?

Answers

Answer:10 grams of CO2

Explanation:

Yeild= exp. yeild÷ thoretical yeild × 100

Yeild= 73.3÷73.4 × 100

Yeild= 0.1 ×100

Yeild= 10

A gaseous system undergoes a change in temperature and volume. What is the entropy change for a particle in this system if the final number of microstates is 0.842 times that of the initial number of microstates

Answers

Answer: -2.373  x 10^-24J/K(particles

Explanation: Entropy is defined as the degree of randomness of a system which is a function of the state of a system and depends on the number of the random microstates present.

The entropy change for a particle in a system  depends on the initial and final states of a system and is given by Boltzmann equation as  

S = k ln(W) .

where S =Entropy

K IS Boltzmann constant ==1.38 x 10 ^-23J/K

W is the number of microstates available to the system.

 The  change in entropy is given as

S2 -S1 = kln W2 - klnW1

dS = k ln (W2/W1)

where w1 and w2 are initial and final microstates

from the question, W2(final) = 0.842 x W1(initial), so:

= 1.38*10-23 ln (0.842)

=1.38*10-23  x -0.1719

= -2.373  x 10^-24J/K(particles)

6. To isolate benzoic acid from a bicarbonate solution, it is acidified with concen- trated hydrochloric acid, as in experiment 1. What volume of acid is needed to neutralize the bicarbonate

Answers

Answer:

For our assumed experiment; the expected  volume of Hcl acid needed to neutralize the bicarbonate is 0.13 mL

Explanation:

We are going attempt this question experimentally.

We know that benzoic acid originate from the relationship between  benzene and a carboxylic group. So basically , the functional group of a carboxylic acid (-COOH) joins with a benzene ring(C₆H₆) to form a simple aromatic carboxylic acid known as Benzoic acid. (C₇H₆O₂)

However, it is possible to isolate benzoic acid from  a bicarbonate solution in the presence of an acidified concentrated hydrochloric acid.

Let assume that ;

0.20 g of benzoic acid was reacted with 2 mL of a 20% solution of NaHCO₃, the amount of the  excess NaHCO₃ can be determined by subtracting the amount of benzoic acid from the amount of NaHCO₃.

Let first calculate the number of moles in 0.20 g of benzoic acid

we know that the standard  molar mass of benzoic acid is 122.12 g/mol

number of moles of benzoic acid = mass of benzoic acid/molar mass of benzoic acid =

number of moles of benzoic acid = 0.20/ 122.12

number of moles of benzoic acid = 0.0016 mol

number of moles of bicarbonate  solution = mass of bicarbonate solution/ molar mass of bicarbonate solution

number of moles of bicarbonate  solution =  0.2/84.00654 g/mol

number of moles of bicarbonate  solution =  0.00238 mol

(0.00238 - 0.0016) mol

= 7.8 × 10⁻⁴ mol

Let assume that the concentrated HCl is 12  M

Also. HCl and NaHCO₃ react together at the ratio of 1:1; thus the  volume of Hcl acid needed to neutralize the bicarbonate is:

[tex]= ( 7.8 * 10^{-4} \ \ mol )* ( \dfrac{2\ L}{ 12 \ M})*( \dfrac{10^3 \mL}{1 \ L})[/tex]

= 0.13 mL

Thus; for our assumed experiment; the expected  volume of Hcl acid needed to neutralize the bicarbonate is 0.13 mL

How many grams of 02 are needed to react with 7.50g of ethanol

Answers

write eqn, find mols, compare ratio and take mols times mr of O2 to find mass

How to treat stream water for drinking

Answers

Answer:

Explanation:

Boiling.

Use water filter

Use Ultraviolet Light.

Use chlorine drops

I would recomade boiling as the main

because its the easiest and cheapest Or water filter if you have one

2 FONS
How does the electric force between two charged particles change if the
distance between them is increased by a factor of 22
A. It increases by a factor of 4.
B. It increases by a factor of 2.
C. It decreases by a factor of 4
O
D. It decreases by a factor of 2.
SUB

Answers

Answer:

C. It decreases by a factor of 4

Explanation:

F1 = kq1*q2/r²

F2 = kq1*q2/(2r)² = kq1*q2/(4r²) = kq1*q2/(r²*4)  = F1/4

What is in period 6 group 8

Answers

Answer:

Osmium

Explanation:

If you take a look at the attached image of a periodic table below, you will see that the element in the 6th period and 8th group is Osmium. Hope this helps!

The decomposition of Ca(OH)2(s) intoCaO(s) and H2O(g) at constant pressure requires the addition of 109 kJ of heat per mole of Ca(OH)2.
A. Write a balanced thermochemical equation for the reaction.
B. Draw an enthalpy diagram for the reaction, showing the activation energy, Ea, and the enthalpy change for the reaction.

Answers

Answer:

A. Ca(OH)2 ----> CaO + H2O; ∆H = +109KJ

B. Check attached document below for the enthalpy diagram

Explanation:

A thermochemical equation is a balanced chemical equation in which enthalpy change is variable. It tells about the nature of the reaction.

Enthalpy change is the difference between the heat content of the products and reactants in a thermochemical equation.

∆H is negative for an exothermic reaction (a reaction where heat is given out), while it is positive for an endothermic reaction ( a reaction in which heat is added).

The activation energy, Ea, is the minimum amount of energy reactant particles must possess in order for a reaction to proceed towards product formation.

As per the decomposition of the Ca(OH) 2 and the CaO the constant pressure needs to be added of the 109KJ.

The balance thermochemical equation for the reaction is expressed as  Ca(OH)2 ----> Ca O + H2O; ∆H = +109KJThe diagram for the reaction and the activation energy is given above.

Learn more about decomposition.

brainly.com/question/14797703.

. The pI is called ________________. The rule of calculating pI of an amino acid is that first, write the dissociation equation from fully protonated form to fully deprotonated form, label the charge of each form; second, identify the zwitterionic form (zero charge) and find the closest pKs (left and right side in the dissociation equation); third, average these two pKs. Write the dissociation equations for amino acids, glutamate, histidine, and calculate their pIs.

Answers

Answer:

The isoelectric point is that the pH at which the compound is in an electronically neutral form.

For diss equations, please find them in the enclosed file.

The pIs of 2 amino acids:

Glutamate: pI = 3,2Histidine: pI = 7,6

Explanation:

Formula for the pI calculation: pI = (pKa1 + pKa2)/2

Given 3 pKa :

Acid glutamic with an acid sidechain:

Use the lower 2  pKas (corresponding with 2 -COOH groups)

pKa1 = 2,19; pKa2 = 4,25; so pI = 3,2

Histidine with 2 amino groups:

Use the higher 2 pKas ( -COOH group and -NH= group)

pKa1 = 6; pKa2 = 9,17; so pI = 7,6

What allows two or more atoms to be held together?

Answers

Answer:

Atoms come together to form molecules because of their electrons. Electrons can join (or bond) atoms together in two main ways. When two atoms share electrons between them, they are locked together (bonded) by that sharing. These are called covalent bonds.

Explanation:

Answer:

Electrons

Explanation:

took the test got 100%

URGENT!! This is timed, PLEASE HELP!
Nitrogen gas can be prepared by passing gaseous ammonia over solid copper (II) oxide at high temperatures, as described by the following balanced equation:
2 NH3(g) + 3 CuO(s) → 1N2(g) + 3 Cu(s) + 3 H2O(g)
How many grams of N2 are formed when 120.51 g of NH3 are reacted with excess CuO?
(Please explain using steps and show the whole process. Make sure the answer is in sig figs)

Answers

Answer:

99.24 gm of nitrogen .

Explanation:

molecular weight of ammonia = 17 , molecular weight of nitrogen = 28.

2 NH₃(g) + 3 CuO(s) → 1N₂(g) + 3 Cu(s) + 3 H₂O(g)

2 x 17 gm                      28 gm

( 34 gm )

34 gm of ammonia forms 28 gms of nitrogen

1 gm of ammonia   forms 28 / 34 gms of nitrogen

120.51 gn of ammonia forms 28 x 120.51 / 34 gms of nitrogen

28 x 120.51 / 34 gms

= 99.24 gms of nitrogen will be formed .

Hi I have a lab for Chemistry I am struggling with. I have to do calculations given the following information
1. Mass of evaporating dish plus sample 26.57 g
2. Mass of evaporating dish 24.29 g
3. Mass of evaporating plus NaCl 68.66 g
4. Mass of evaporating dish 67.84 g
5. Mass of filter paper plus sand 37.69 g
6. Mass of filter paper 36.34 g
CALCULATIONS AND CONCLUSIONS
1. Calculate the mass of unknown mixture g

2. Calculate the mass of NaCl recovered g

3. Calculate the mass of sand recovered g

4. Calculate the percentage of NaCl in your unknown mixture %

5. Calculate the percent sand in your unknown mixture %

6. Calculate the total mass of sand and salt recovered g

7. Calculate the percent recovery of the components %

Answers

Answer:

1.  2.28 g

2. 0.82 g

3. 1.35 g

4. 36 %

5. 59 %

6. 2.17 g

7. 95 %

Explanation:

Hello,

1. In this case, the mass of the unknown mixture is obtained by subtracting the mass of the dish plus sample and the mass of the dish:

m = 26.57 g- 24.29 g = 2.28 g

2. In this case, the mass of the NaCl recovered is obtained by subtracting the mass of the dish plus NaCl and the mass of the dish:

m = 68.66 g- 67.84 g = 0.82 g

3. In this case, the mass of the sand recovered is obtained by subtracting the mass of the filter paper plus sand and the mass of the filter paper:

m = 37.69 g- 36.34 g = 1.35 g

4. The percentage of NaCl is computed by considering its mass and the mass of the unknown mixture:

% NaCl = 0.82 g / 2.28 g * 100 % = 36 %

5. The percentage of sand is computed by considering its mass and the mass of the unknown mixture:

% sand = 1.35 g / 2.28 g * 100 % = 59 %

6. Here,we have to add the mass of NaCl and sand:

m = 0.82 g + 1.35 g = 2.17 g

7. Finally, the percent recovery is obtained by diving the total recovered mass by the total obtained mass of the mixture:

% recovery = 2.17 g / 2.28 g * 100 % = 95 %

Best regards.

What mass of carbon dioxide is produced from the complete combustion of 7.30×10−3 g of methane?

Answers

We know that the reaction goes to completion, so all the methane will be reacted. To find the mass of carbon dioxide used, we can use the number of moles from the above equation, and the molecular weight of CO2 (= 44.009 g/mol). The mass of CO2 produced is 3.29*10^-3g.

why are the products of light reaction of photosythesis important

Answers

Answer: light reaction produces oxygen and water as we know the general importance of oxygen and water they are useful for organism to survive if plants do not produce oxygen then how could we get oxygen from the environment

When a saturated solution of NH4Br dissolved in 100 grams of water is cooled from 60°C to 30°C, how much NH4Br will precipitate?

Answers

Answer:

[tex]m_{precipitated}=24.8g[/tex]

Explanation:

Hello,

In this case, since at 60 °C, 108 grams of ammonium bromide are completely dissolved in 100 grams of water for a saturated solution, once it is cooled to 30 °C, wherein only 83.2 grams are completely dissolved in 100 grams of water, the following mass will precipitate:

[tex]m_{precipitated}=108g-83.2g\\\\m_{precipitated}=24.8g[/tex]

Best regards.

how do you create flu vaccine,

Answers

Answer:

Explanation:

The fluid containing virus is harvested from the eggs. For inactivated influenza vaccines (i.e., flu shots), the vaccine viruses are then inactivated (killed), and the virus antigen is purified. The manufacturing process continues with quality testing, filling and distribution.

symbol for carboxylic acid​

Answers

C(=O)OH The general formula of a carboxylic acid is R–COOH, with R referring to the alkyl group.

A student dissolved 5.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution and then diluted it with water to give 275. mL of a final solution. How many grams of NO3- ion are there in the final solution?

Answers

Answer:

0.136g

Explanation:

A student dissolved 5.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution and then diluted it with water to give 275. mL of a final solution. How many grams of NO3- ion are there in the final solution?

[tex]Co(NO_3)_2(aq)\rightarrow Co^{2+}(aq)+2NO_3^{-}(aq)[/tex]

Initial mole of Co(NO3)2  [tex]=\frac{mass}{molar mass}[/tex]

[tex]=\frac{5.00}{182.94} \\\\=0.02733mol[/tex]

Mole of Co(NO3)2 in final solution

[tex]=\frac{4.00}{100}\times 0.02733\\\\=0.04\times 0.02733\\\\= 0.001093mol[/tex]

Mole of  NO3- in final solution = 2 x Mole of Co(NO3)2

[tex]=2\times 0.001093\\\\=0.002186mol[/tex]

Mass of  NO3- in final solution is mole x Molar mass of NO3

[tex]=0.002186\times62.01\\\\=0.136g[/tex]

The final solution contains 0.24 g of nitrate ion.

Number of moles of  Co(NO3)2 =  5.00 g/183 g/mol = 0.027 moles

Number of moles = concentration × volume

concentration = Number of moles /volume

Volume of solution = 100 mL or 0.1 L

concentration =  0.027 moles/0.1 L = 0.27 M

Using the dilution formula;

C1V1 = C2V2

C1 =  0.27 M

V1 = 4.00 mL

C2 = ?

V2 =  275. mL

C2 = C1V1/V2

C2 = 0.27 × 4.00/ 275

C2 = 0.0039 M

Number of moles of NO3- ion in Co(NO3)2 = 0.0039 M × 62 g/mol = 0.24 g

Learn more: https://brainly.com/question/1340582

What is the molar mass of CH2O2 ? ( C= 12.01 g/mol, H=1.008 g/mol, O=16.00)

Answers

Answer:

Molar Mass of CH2O2 is 46.026

Explanation:

What is the molar mass of CH2O2 ? ( C= 12.01 g/mol, H=1.008 g/mol, O=16.00)

C = 12.01g/mol

H = 1.008g/mol

O = 16g/mol

CH2O2 = 12.01+1.008x2+16x2 = 46.026g/mole

When 25ml of sulphuric acid, was titrated with 0.0820 mol/L sodium hydroxide solution the end point was detected (with phenolphthalein) at 22.5ml . Calculate the concentration of sulphuric
acid in mol/L.​

Answers

Answer:

the concentration of sulphuric acid is 14mol/l

Quantum number of boron

Answers

Answer:

The answer is 5.

A student sets up the following equation to solve a problem in solution stoichiometry. (The ? stands for a number the student is going to calculate.) Enter the units of the student's answer

(1.26mol)1mL10^−3L / (7.9mol/L)= ?

Answers

Answer:

mL * L²

Explanation:

The question in t his problem is to calculate the units of the final answer.

The units in the numerator is mol, ml and L.

The unit in the denominator is mol/L

This leads us to;

Numerator / Denominator =  mol * mL * L / (mol / L )

The final units is mL * L²

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