Please help me !!!! ASAP

148+35=183

80+(-53)=27

(-125) x (-42)=5250

Answer:

Step-by-step explanation:

85miles¯\_(ツ)_/¯

Answer:

7:2

14:4

Step-by-step explanation:

Answer:

Katherine will rent at least 64 movies and 20 games to make a profit

Step-by-step explanation:

The given parameters are;

The amount for which she rents games = 4

The amount for which she rents movies = 4

The number of games and movies she most rent to make profit = 84

The number of games she ≤ 20

Let x represent the number of games, let y represents the number movies, we have;

x + y ≥ 84

x ≤ 20

64 ≤ y ≤ 84

The graph of the inequality created with Microsoft Excel showing the feasible region is included

Answer:

This is an obtuse scalene triangle with the length of E measuring around 749 cm.

<D = 54.754° ≈ 55°

<E = 114°

<F = 11.246° ≈ 11°

Side D = 670 cm

Side E = 749.46937 cm ≈ 749 cm

Side F = 160 cm

Explanation:

When given two sides, and an angle, we can use trigonometry to find the missing angles, and sides.

Given the triangle ∆DEF with side D measuring 670 cm, side F measuring 160 cm, and angle E measuring 117°, we can apply the law of sines to identify the missing information. A & a chronologically refers to the first angle, and side. B & b chronologically refers to the second angle, and side. And C & c chronologically refers to the third angle, and side.

a / Sin (A) = b / Sin (B) = c / Sin (C)

[side 1]. [side 2]. [side 3].

↓ ↓ ↓

sideD/sin(<D) SideE/sin(<E) SideF/sin(<F)

______________________________

670cm / Sin(D) = E cm / Sin(114) = 160 / sin(F).

Since we are only given two sides with an angle measure, we can refer to the law of cosines to figure this one out.

It states that A = arccos(b²+c²-a²/2bc) → cos(A) = b²+c²-a²/2bc

B = arccos(a²+c²-b²/2ac) → cos(B) = a²+c²-b²/2ac

and C = arccos(a²+b²-c²/2ab) → cos(C) = a²+b²-c²/2ab

capital A, B, and C are angles A, B, and C.

lowercase a, b, and c are sides a, b, and c.

Therefore c² = a² + b² − 2ab cos(C),

b² = a² + c² - 2ac cos (B), and a² = b²+c² - 2bc.

SOH CAH TOA.

Since we know this, we can solve for pretty much everything as long as we are given at least 3 variables. Chronologically, because we are solving for side e, we must use b² = a² + c² - 2ac cos (B), because the rest are only variables we are given, making it easy to solve. So b² = 670² + 160² - 2(670 × 160) × cos(114°) = 561704.3362754.

Now take the square root of that to get b by itself, so √561704.3362754.... = 749.4693698046.... ≈ 749

Answer:749

Step-by-step explanation:

S.A.S law or Cosines

e=561704.33628= 749.469= 749

Answer:

w=v/lh

Step-by-step explanation:

Answer:

121/12 is the answer your welcome

The value of x in the equation (m^5/6) (m^1/6)^7 = m^x is 2

The exponents of numbers are added when the numbers are multiplied, subtracted when the numbers are divided, and multiplied when raised by still another exponent: a^m×a^n = a^(m+n); a^m÷a^n = a^(m−n);

(am)ⁿ = a^mn.

Given an equation, (m^5/6) (m^1/6)^7 = m^x

Using the law of exponent, we get,

(m^5/6) (m^1/6)^7 = m^5/6*m^7/6

= m^(5/6+7/6)

= m^12/6

= m^2

Hence, the value of x in the equation (m^5/6) (m^1/6)^7 = m^x is 2

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Answer:

p= 2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Answer:

Answer is D. 2 & -2

Answer:D

I THINK

Step-by-step explanation:

Hopefully this is the right one

Answer:

There's no options but it will get closed

Step-by-step explanation:

Answer:

Step-by-step explanation:

-75.5

Answer:

x2+ 16k+ 64= not factorable with rational numbers

x2+ 7x+ 10= (x+2)(x+5)

These are what I got from your picture, so don't quote me on this the picture wasn't the best.

Answer:

There are 480 lockers in school.

Step-by-step explanation:

480

Step-by-step explanation:

180÷3=60

60x5=300

300+180=480

$146.52

You times the 407 by 6%, then you multiply the product by 6, which would leave you with the added amount.

Answer:

d

Step-by-step explanation:

listen bud i am trying to level up so i am doing the challenge 25 questions for 400 points i need 3 brainliest on the way can you help me out with this?

Answer:

The correct option is;

A vertical line can be represented using a table but not a function because the slope is undefined

Step-by-step explanation:

A function, f(x), representing a linear relationship can be presented as follows;

f(x) = m·x + c

Where;

m = The slope = Δy/Δx = (y₂ - y₁)/(x₂ - x₁)

c = The y-intercept

Whereby the line is a vertical line, x₂ = x₁ and x₂ - x₁ =

Therefore;

The slope of a vertical function, m =  (y₂ - y₁)/(x₂ - x₁) = (y₂ - y₁)/0 = ∞ from which we have;

f(x) = ∞·x + c = ∞ which is undefined and the vertical line can only be represented using a table but not a function because the slope is undefined

Answer:

B

Supplementary means they add to make 180 deg, so solve (4x-8)+(2x+2)=180

Answer:

angle a + angle b=180

4x-8+(2x+2)=180

6x-6=180

6x=180+6

x=186/6

{x=31°}

Answer:

6 1/4 and 1 1/4

1 and 1/5

Step-by-step explanation:

These are the only ones I think

[tex]6\frac{1}{4}[/tex] kilometer:  [tex]1\frac{1}{4}[/tex] minutes and 1 kilometer: 1/5 minutes has unit rate as 5.

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

The given, ratios are:

4/5 km : 5 minutes

[tex]3\frac{1}{10}[/tex] km: 3/10 minutes

1 kilometer: 1/5 minutes

1/3 kilometer: [tex]1\frac{2}{3}[/tex] minutes

[tex]4\frac{1}{2}[/tex] kilometer: 2 minutes

[tex]6\frac{1}{4}[/tex] kilometer:  [tex]1\frac{1}{4}[/tex] minutes

We need to check which ratios have 5 as unit rate.

[tex]6\frac{1}{4}[/tex] kilometer:  [tex]1\frac{1}{4}[/tex] minutes has unit rate as 5

25/4/5/4

5

1 kilometer: 1/5 minutes

5

Hence, [tex]6\frac{1}{4}[/tex] kilometer:  [tex]1\frac{1}{4}[/tex] minutes and 1 kilometer: 1/5 minutes has unit rate as 5.

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Answer:

no they don't form a proportion

Step-by-step explanation:

16:18/2:2 = 8:9

8:9 and 1:2 are unequal

Answer:

[tex]L=2l[/tex] where [tex]l,L[/tex] denote arc lengths of two circles

Step-by-step explanation:

Let [tex]l,L[/tex] denote arc lengths of two circles, [tex]r,R[/tex] denote corresponding radii and

[tex]\alpha _1\,,\alpha _2[/tex] denote the corresponding central angles.

So,

[tex]l=r\alpha _1[/tex] and [tex]L=R\alpha _2[/tex]

This implies [tex]\alpha _1=\frac{l}{r}[/tex] and [tex]\alpha _2=\frac{L}{R}[/tex]

As each circle has an arc where the measures of the corresponding central angles are the same, [tex]\alpha _1=\alpha _2[/tex]

[tex]\frac{l}{r}=\frac{L}{R}[/tex]

As radius of one circle is twice the radius of the other circle,

[tex]R=2r[/tex]

[tex]\frac{l}{r}=\frac{L}{2r}\\\frac{l}{1} =\frac{L}{2}\\L=2l[/tex]

Answer:

13.4

27.1

8.8

Step-by-step explanation:

hope that helps

Answer: m=0

Step-by-step explanation: simplify each individual expression first. The left side of the equation is equal to -12m-6, and the right side is equal to 30m-6. Then together, it equals to -12m-6=30m-6. The -6 cancel each other out. M=0

Answer:

$7.56

Step-by-step explanation:

$7(.08) = .56 in tax

$7 item cost + .56 in tax

Answer:

8 inches on each side

Step-by-step explanation:

Answer: side AB is 5.7 units

Step-by-step explanation:

If you look at the congruence marks on the angles, you can see that side AB and side KL correspond. Since we know KL is 5.7, AB must be 5.7 as well. :)

Answer: The answer is some

I know this because I go to Harvard

Answer:

The answer is some

Answer:

The height of the kite is approximately 278.6 feet

Step-by-step explanation:

The length of Jason's Kite string, l = 325 feet

The angle of elevation of the kite string, θ = 58°

The height of Jason's hand, h = 3 feet above the ground

Therefore, we have;

The height of the kite = The vertical component of the length of the kite string + The height of Jason's hand above the ground

The height of the kite = l × sin(θ) + h

Substituting the values, we get

The height of the kite = 325 × sin(58°) + 3 ≈ 278.6 (which is obtained by rounding the answer to the nearest tenth)

The height of the kite ≈ 278.6 feet.

Answer:

[tex]a^{2}[/tex]

Step-by-step explanation:

√a^4 is the same as:

√a × √a × √a × √a

group them as 2 pairs of

(√a × √a) × (√a × √a)

which makes

a × a

which is the same as [tex]a^{2}[/tex]

The measure of the other 7 angles are;

m∠2 = m∠3 = 109°; m∠4 = m∠5 = m∠8  = 71°;  m∠6 = m∠7 = 109°

We are given;

m∠1 = 71°

Thus;

m∠1 and m∠2 are angles that form a straight line and as such they are supplementary angles and sum up to 180°

Thus; m∠1 + m∠2 = 180°

71 + m∠2 = 180°

m∠2 = 180 - 71

m∠2 = 109°

Now, m∠2 and m∠3 are alternate angles and as such;

m∠2 =  m∠3

Thus; m∠3 = 109°

Similarly,

m∠1 and m∠4 are alternate angles and as such;

m∠1 =  m∠4

Thus;

m∠4 = 71°

m∠1 and m∠5 are corresponding angles and as such;

m∠1 =  m∠5

Thus;

m∠5 = 71°

m∠2 and m∠6 are corresponding angles and as such;

m∠2 = m∠6

Thus;

m∠6 = 109°

Similar to how angles were gotten earlier, we can say that;

m∠5 = m∠8  = 71°

and m∠6 = m∠7 = 109°

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