What is the ionic charge of elements in column 1?
Every element in the first column varieties a cation with charge 1+. Every component in the 2d column varieties a cation with charge 2+. Elements in the third to remaining column nearly all shape an anion with a 2- charge and factors dwelling in the 2d to closing column nearly all structure anions with a 1- charge.
How many moles are in 68 grams of copper (II) hydroxide, Cu(OH)2
heres your answer mate...
If you want to warm 3.10 g of water from 56.4 C to 82.4 C, how many calories would you need to add to the water?
Answer: 80.6
Explanation:
q = mcAt
we have the grams of water, temp change, and specific heat of water is 4.186 J/g so we can plug in our numbers to find the heat energy in joules
q = (3.10)(4.184)(82.4-56.4)
q= 337.2304 J
we need our answer to be in calories so divide our answer by 4.184 and we get 80.6 calories
The amount of calorie required to warm 3.10 g of water from 56.4°C to 82.4°C is 80.6 calories.
HOW TO CALCULATE CALORIES:
The amount of calories can be calculated by using the formula as follows:Q = m × c × ∆T
Where:
Q = amount of heat in caloriesc = specific heat capacity (J/g°C)∆T = change in temperature (°C)m = mass (g)According to this question, c = 4.184J/g°C, m = 3.10g, ∆T = 82.4°C - 56.4°C = 26°CQ = 3.10 × 4.184 × 26Q = 337.23JSince 1J = 0.2390057361 calories337.23 J = 80.6calories.Therefore, amount of calorie required to warm 3.10 g of water from 56.4°C to 82.4°C is 80.6 calories.Learn more at: https://brainly.com/question/8097823?referrer=searchResults
If 100 yards = 1 football field, what is the length, in meters, of 4.9
football fields?
For this reaction, C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ. If two moles of C3H8(g) reacted with excess oxygen, what would be true?
A) 4400 kj of heat released into surroundings
B) 4400 kj of heat absorbed by system
C) 1100 kJ heat released into surroundings
D) 1100 kJ heat absorbed by system
A) 4400 kj of heat released into surroundings
Further explanationReaction
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ
Reaction exothermic( ∆H=-, released heat to surrounding) and for combustion of 1 mole of C3H8
So for two moles of C3H8, the enthalpy :
[tex]\tt -2200\times 2=-4400~kJ[/tex]
Give two properties that glass and plastic sometimes share.
Answer:
Wall, cup, mug, plastic spoon
Explanation:
Because all of those are glass and it is important to us to make sure that if you are touching this brle careful
Answer:
Example aflask that is made in plastic,a plastic jag
Explanation:
they share some of the things in common such us
1.the height
2. the density
What causes metamorphic rocks to form from existing rocks?
O magma and minerals
O heat and pressure
O exposure to Earth's mantle
exposure
to Earth's surface
I think it's Heat and pressure
Answer:
heat and pressure did on edge
Explanation:
Express the measurement using the appropriate SI prefix. 2.50 x 10-3g
Potassium cyanide is a toxic substance, and the median lethal dose depends on the mass of the person or animal that ingests it. The median lethal dose of KCN for a person weighing 215 lb (97.5 kg ) is 8.84×10−3 mol .
What volume of a 0.0250 M KCN solution contains 8.84×10−3 mol of KCN?
Express the volume to three significant figures and include the appropriate units.
Answer:
0.354L
Explanation:
Given parameters:
Molarity of KCN = 0.025M
Number of moles = 8.84 x 10⁻³mol
Unknown:
Volume of KCN = ?
Solution:
The molarity of a substance is expressed as;
Molarity = [tex]\frac{number of moles }{volume }[/tex]
Volume of KCN = [tex]\frac{number of moles }{molarity}[/tex]
Now insert the parameters and solve;
Volume of KCN = [tex]\frac{0.00884}{0.025}[/tex] = 0.354L
What is a chemical reaction
A student is attempting to identify an unknown liquid. She places 10 mL of the liquid in a test tube and begins heating it over a burner. She checks and records the temp every minute until it begins to boil. What is the independent variable?
Answer:
The time of heating
Explanation:
Let us analyse the experiment closely; the temperature of the liquid increases as the time of heating increases. This implies that the temperature of the liquid is dependent on the time of heating of the liquid. The longer the time of heating, the greater the increase in temperature until the boiling temperature is eventually attained.
Hence, the temperature of the liquid is the dependent variable, the time of heating is the independent variable when the heating rate is held constant.
Objects with more (less or more) molecules have
heat energy than objects with (greater or fewer)
molecules? fill in the blanks
How much heat is absorbed when 15.0 g of liquid water is
heated until the temperature increases by 6.0°C? The specific
heat of liquid water is 4.18 J/gºC.
Answer:
376.56
Explanation:
using the formula q=mcΔT, where m=15g, C=4.18J/g°C and ΔT=6.0°C
Brass and bronze are both of copper because copper is the component in brass and bronze.
Answer:1 alloys 2 main
Explanation: Brass and bronze are both constructed from copper because copper is the main component in brass
If 30cm³ of 0.45 mol dm3 HCl reacted with NaOH, how many moles of HCl reacted?
Moles HCl reacted : 0.0135
Further explanationMolarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
[tex]\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}[/tex]
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
So to find the number of moles can be expressed as
n = V x M
The volume of HCl 30 cm³=3.10⁻² dm³
Molarity of HCl = 0.45 mol/dm³
so moles HCl reacted :
[tex]\tt n=3.10^{-2}\times 0.45=0.0135[/tex]
Predict the products for the following chemical reaction: H2 + O2 →
a. H30
b. H20
c. H2OH
d. OH + OH
O a
When an aluminum atom becomes an ion, what is its charge?
Answer:
Initially, the aluminum atom had a charge of +13 + (−13) = 0; in other words, its charge was neutral due to the equal numbers of protons and electrons. When it becomes an ion, it loses 3 electrons, leaving behind only 10. Now the charge is +13 + (−10) = +3.
Thank you and please rate me as brainliest as it will help me to level up
3x - 12 = 7x + 8
-4x - 12 = 8
-4x - 20
X = -5
Answer:
1.Set your equations Raquel to each other
2.given
3.subtract 7x from both sides
4. Add 12 to both sides
5.divide both sides by four and you get negative 5
Explanation:
oxygen - 17
Atomic #
Atomic mass
# of protons
# of neutrons
# of electrons
Answer:
atomic #8
atomic mass 15.999U
# protons 8
# neutrons 8
# protons 8
The diagram shows a transform fault. What is a likely result of slippage along
this fault?
Fault
O.
A. Pyroclastic flow
B. Shield volcano
C. Earthquake
D. Crater
Answer:
C. Earthquake
Explanation:
Earthquake is a likely result of the slippage along this fault boundary.
At a transform margin, rocks are moving parallel to one another. This often causes a slippage that leads to the generation of earthquakes.
An earthquake is a sudden displacement within the earth that leads to a sudden release of energy in all direction. The slippage on the surface of a transform fault often lead to earthquakes.Answer:
C
Explanation:
(04.01 LC)
Fill in the blank with the correct number to balance the equation: __KCIO3 - 2KCI +
302. (Enter only a whole number.) (3 points)
How many moles of Oxygen are in 1 mile of CaCo3?
[tex]\huge\boxed{3moles}[/tex]
_____________________________________Compound:The compound given in the question is [tex]CaCO_{3}[/tex] which is called Calcium Carbonate. A 1 mole of Calcium Carbonate has,
1 Moles of Calcium.
1 Moles of Carbon.
3 Moles of Oxygen.
_____________________________________Question:In the Question, It is asked that how many moles are present in the 1 mole of Calcium Carbonate, So as per information we have, there are 3 moles of oxygen present in Calcium Carbonate.
__________________________________________________________
Much simpler way to understand why there are 3 mole is look at the subscript along the element. There is no number in the subscript of Calcium and Carbon thus 1 Mole, There is 3 present in the subscript thus 3 moles of calcium. Remember that subscript suggests the number of moles of an element in only 1 MOLE OF COMPOUND
_____________________________________Best Regards,'Borz'
Give the applications of EMF measurement
Answer: Determination of Equilibrium Constant, Determination of Solubility Products, Determination of pH, Determination of Activity Coefficients,
Explanation:
9. 1.2 x 102 yd =
10. 1535 fl. oz. =
L
Answer:
9. 122.4 yards
10. 45.395 litres
What Most Often Causes The Availability Of Water To Change?
A. type of plants
B. type of soil
C. local geography
Answer:the answer is C
Explanation:
What is happening in this picture?
Answer:
in first picture pressure is low and in second picture the pressure is high
2ans in first picture air is
less amount
in second picture air is high amount
What is arcade in south Center
Answer: game stop and mind games
Explanation:
i live near there
if your mass was 200 grams what would your weight be on this planet.
Answer:
200
Explanation:
Explanation:
take your weight times by the amount of newtons in a pound, which is 4.45
then convert newtons into grams.
Determine which equations you would use to solve the following problem: Calculate the amount of heat needed to change 20.0 g of ice at -10.0°C to water at 89.0°C.
Answer:
Q = 4019.4 J
Explanation:
Given data:
Mass of ice = 20.0 g
Initial temperature = -10°C
Final temperature = 89.0°C
Amount of heat required = ?
Solution:
specific heat capacity of ice is 2.03 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 89.0°C - (-10°C)
ΔT = 99°C
Q = 20.0 g ×2.03 J/g.°C × 99°C
Q = 4019.4 J
A 75.0 gram sample of water at 25.0 degrees Celsius is mixed with a 100. Gram sample of water at 60.0 degrees Celsius. What is the final temperature of the water?
Answer:
The final temperature of the water = 45°C
Explanation:
Heat lost = heat gained
Heat lost by water at 60°C = m₁CΔT₁
Heat gained by water at 25°C = m₂CΔT₂
where m₁ is mass of water at 60°C = 100.0 g; m₂ is mass of water at 25°C = 75.0 g
C, specific heat capacity of water = 4.18 J/g°C
ΔT₁ = (60 - T); ΔT₂ = (T - 25); T = final temperature of the water
m₁CΔT₁ = m₂CΔT₂
100 * C * (60 - T) = 75 * C * (T - 25)
-100T + 6000 = 75T - 1875
-(100T + 75T) = -(6000 + 1875)
175T = 7875
T = 45°C
Therefore, final temperature of the water = 45°C