Please help me with this math problem ASAP!!

Answer:

Graph A

Step-by-step explanation:

Answer:

its graph A

Step-by-step explanation:

Answer:

208

Step-by-step explanation:

2080 Divided by 10 = 208

Answer:

y=6x+3

Step-by-step explanation:

Answer: B is the answer

Step-by-step explanation:

The answer for A) is x=-9/10

The answer for B) is no solution

The answer for C) is x=0

The answer for D) is =-8x

Yes; the domain values are at regular intervals and the range values have a common factor of 0.25 so option (D) will be correct.

A function's range is the set of all values that the function accepts, and its domain is the set of all values for which the function is defined.

The domain is for the independent variable while the range is for the dependent variable.

Given a table of dependent(x) and independent variable (y)

Now the domain is set of the dependent variable so x {3,2,1,-1} so it is decreasing between two points so it is an interval.

Now in the independent variable (x)

If we multiply by 0.25 then the next term will come so it has a common factor of 0.25.

Hence "Yes; the domain values are at regular intervals and the range values have a common factor of 0.25".

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The given question is incomplete, the complete question with a table is given below ;

From the table below, determine whether the data shows an exponential function. Explain why or why not.

a No, the domain values are at regular intervals and the range values have a common factor of 0.25.

b. No, the domain values are not at regular intervals although the range values have a common factor.

c. Yes, the domain values are at regular intervals and the range values have a common factor 4.

d. Yes; the domain values are at regular intervals and the range values have a common factor of 0.25.

Answer:

Patrick from spongebob? He dosent do work

Step-by-step explanation:

Answer:

Combining and simplifying [tex]48(\frac{1}{4}x-\frac{1}{3}y-\frac{2}{6}x-\frac{3}{8}y-\frac{2}{3})[/tex] we get  [tex]\mathbf{-4x-34y-32}[/tex] or we can write as [tex]\mathbf{48(\frac{-x}{12} -\frac{17y}{24}- \frac{2}{3})}[/tex]

Step-by-step explanation:

We need to combine and simplify

[tex]48(\frac{1}{4}x-\frac{1}{3}y-\frac{2}{6}x-\frac{3}{8}y-\frac{2}{3})[/tex]

First we will combine like terms and then perform the mathematical operations like addition or subtraction.

Like terms: terms having same variable

[tex]48(\frac{1}{4}x-\frac{2}{6}x-\frac{1}{3}y-\frac{3}{8}y-\frac{2}{3})[/tex]

Now we take LCM of like terms

[tex]=48(\frac{1}{4}x-\frac{2}{6}x-\frac{1}{3}y-\frac{3}{8}y-\frac{2}{3})\\=48(\frac{x*3-2x*2}{12} +\frac{-y*8-3y*3}{24}- \frac{2}{3})\\=48(\frac{3x-4x}{12} +\frac{-8y-9y}{24}- \frac{2}{3})\\=48(\frac{-x}{12} +\frac{-17y}{24}- \frac{2}{3})\\=48(\frac{-x}{12} -\frac{17y}{24}- \frac{2}{3})[/tex]

Now, we can multiply 48 with terms inside the bracket.

we can simplify the terms if they are both divisible by same number.

[tex]=48(\frac{-x}{12} -\frac{17y}{24}- \frac{2}{3})\\=48(\frac{-x}{12} )-48(\frac{17y}{24})-48(\frac{2}{3}))\\=-4x-34y-32[/tex]

So, Combining and simplifying [tex]48(\frac{1}{4}x-\frac{1}{3}y-\frac{2}{6}x-\frac{3}{8}y-\frac{2}{3})[/tex] we get  [tex]\mathbf{-4x-34y-32}[/tex] or we can write as [tex]\mathbf{48(\frac{-x}{12} -\frac{17y}{24}- \frac{2}{3})}[/tex]

Answer:

Mark is 12 years old.

Step-by-step explanation:

Let's just define some variables:

J = Jason

A = Alex

M = Mark

Next, let's put the information given in the question into equations.

Since Jason is 10 years older than Alex we can represent it like this:

J = A + 10

Since Mark is 11 years younger than Alex we can represent it like this:

M = A - 11

All of their ages add up to 68 so we can represent that like this:

J + A + M = 68

We can now do some substitutions to the J and M in this equation, like this:

(A + 10) + A + (A - 11) = 68

Combine like terms:

3A - 1 = 68

Solve for A

3A = 69

A = 23

Now that we found that Alex is 23 we can plug that back in to the first equations to find their ages:

J = 23 + 10

J = 33

M = 23 - 11

M = 12

Mark is the youngest out of the siblings being 12 years old.

Check:

23 + 33 + 12 = 68

68 = 68 :)

I hope this helps!!

- Kay :)

Answer:

Non-linear

Step-by-step explanation:

This equation represents a reciprocal function.

You can't divide by zero so it never passes the y-axis, therefore it cannot be linear.

The graph of this equation is attached below.

I hope this helps!!

- Kay :)

Non-linear. In linear equations, you don't divide a number by x.

Answer:

See the attached image.

Step-by-step explanation:

Remember the equation of the line is y = mx + b.

m = 3/2 (slope) ... rise/run. up 3 over 2.

b = -5 (y-intercept)

*These lines go on forever.

The graph of the line y = (3/2)x - 5 is given below.

Given that:

Equation of the line is y = (3/2)x - 5

The linear equation is given as,

x/a + y/b = 1

Where 'a' is the x-intercept of the line and ‘b’ is the y-intercept of the line.

Convert the equation into intercept form, then we have

y = (3/2)x - 5

(3/2)x - y = 5

x / 3.33 + y / (-5) = 1

The graph of the line is given below.

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The second function's output exceeds (get bigger than) the first function's output for x∈(-∞,[tex]\frac{1-\sqrt{29} }{2}[/tex])∪([tex]\frac{1+\sqrt{29} }{2}[/tex],∞)

Given the functions f(x)=x+7 and f(x)=[tex]x^{2}[/tex]

To know when to exceed, need to equate both functions.

⇒[tex]x^{2} =x+7[/tex]

⇒[tex]x^{2} -x-7=0[/tex]

x=[tex]\frac{-b+\sqrt{D} }{2a}[/tex] and [tex]\frac{-b-\sqrt{D} }{2a}[/tex]

⇒x=[tex]\frac{1-\sqrt{29} }{2}[/tex],[tex]\frac{1+\sqrt{29} }{2}[/tex]

f(x)=[tex]x^{2}[/tex] decreases from -∞ to 0 and increases from 0 to ∞ it cuts the graph of x+7 two times and for  x∈(-∞,[tex]\frac{1-\sqrt{29} }{2}[/tex])∪([tex]\frac{1+\sqrt{29} }{2}[/tex],∞) f(x)=[tex]x^{2}[/tex]  is greater than f(x)=x+7

Therefore,The second function's output exceeds (get bigger than) the first function's output for x∈(-∞,[tex]\frac{1-\sqrt{29} }{2}[/tex])∪([tex]\frac{1+\sqrt{29} }{2}[/tex],∞)

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Answer:

They will at the same height of 80cm at 12 months.

Step-by-step explanation:

Sapling A:

y = 10/3x + 40

Sapling B:

y = 5x + 20

Set the equations to equal each other.

10/3x + 40 = 5x + 20

10/3x - 5x = 20 - 40

10x - 15x = 60 - 120

-5x = -60

x = 12

Sub x = 12 into one of the two equations (It doesn't matter which one you choose)

y = 5(12) + 20

y = 80

Answer:

Step-by-step explanation:

The height of statue is 12.2 inches in Troy's drawing.

Step-by-step explanation:

Given,

Actual height of statue = 305 feet

Scale used by Troy;

25 feet = 1 inch

1 feet =

305 feet =

305 feet =

305 feet = 12.2 inches

The height of statue is 12.2 inches in Troy's drawing.

Answer:

12.2 inches

Step-by-step explanation:

The scale is 1 inch = 25 ft

305 ft * (1 inch)/(25 ft) = 305/25 inches = 12.2 inches

Answer: 12.2 inches

Answer:

I think it's 83

Step-by-step explanation:

Teacher explanation I still don't understand

Answer:

C) (1.8, -1.6)

Step-by-step explanation:

Answer:

Step-by-step explanation:Last pair of triangles represent congruence.

Step-by-step explanation:

If , it can be deducted the following:

Also,

Notice that the last imag shows the correct congruence, because it shows the congruence between sides as we said before.

Answer:

D

Step-by-step explanation:

I am doing the test

So area of the Circle ≈ 157.1 sq. unit .

Area is the quantity that expresses the extent of a region on the plane or on a curved surface. The area of a plane region or plane area refers to the area of a shape or planar lamina, while surface area refers to the area of an open surface or the boundary of a three-dimensional object.

Distance formula, Algebraic expression that gives the distances between pairs of points in terms of their coordinates (see coordinate system). In two- and three-dimensional Euclidean space, the distance formulas for points in rectangular coordinates are based on the Pythagorean theorem.

Point P(3,7) is on the Circle having Centre C(8,2).

Therefore, the Distance between points P and C is the radius r of the circle. To calculate r, use the distance formula .

Therefore, [tex]r^2=(8-3)^2+(2-7)^2=50[/tex]

∴ Area of the Circle =π×[tex]r^{2}[/tex]≈ (3.1416) ×(50)=157.08≈ 157.1 sq. unit ( nearest tenth).

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5.03 × 10^7

(word format): 5 and 3 hundredths times 10 to the 7th power

Answer:5.03 x 10^9

Step-by-step explanation:

The density in pounds per pint is 0.047 pounds per pint

Density is calculated using the formula -

Density = [tex]\frac{mass}{volume}[/tex]

To find the density in pounds per pint, we will convert mass and volume to the respective units.

Converting mass in kilograms to pounds -

1 kilogram = 2.205 pounds

9 kilograms = [tex]\frac{2.205*9}{1}[/tex]

9 kilograms = 19.84 ppounds

Converting volume in cubic feet to pints -

1 cubic foot = 59.844 pints

7 cubic foot = [tex]\frac{59.884*7}{1}[/tex]

7 cubic foot = 418.9 pints

Now, keeping the values in formula to find density

Density = [tex]\frac{19.84}{418.9}[/tex]

Performing division to find density -

Density = 0.047 pounds per pint

Hence, the density in pounds per pint is 0.047.

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Expected winning of professor Duque = -$4.8

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

Total no of participation = 500

The prize winner will be decided at random.

Number of favorable outcomes divided by the total number of outcomes gives Duque a chance of winning the reward.

Out of the 500 competitors, only one will be the winner.

Duque's chances of winning the prize are 1 in 500, or 0.002.

If a person wins, they will receive $100 as their prize.

The price of a ticket is $5.

Thus, the net amount prize pool is $100 - $5 = $95 total.

Participants 499  will not be successful.

Probability of losing is 499/500, which is 0.998.

Loss from losing = - $5 (negative sign represents loss).

For discrete random variable X:

E(X) = ∑[tex]_{i=0}^{n} x_{i}*p(x_{i})[/tex]

E(X) = [tex]x_{1}*p(x_{1})+x_{2}*p(x_{2})\\[/tex]

Given,

[tex]x_{1}=[/tex]$95 and [tex]p(x_{1})[/tex]=1/500

[tex]x_{2}[/tex]= -$5 and [tex]p(x_{2})\\[/tex] = 499/500

[tex]E(X)=(95*\frac{1}{500})+(-5*\frac{499}{500}) \\= -4.8\\[/tex]

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The monthly take-home pay is $2240.83.

What is Algebraic expression ?

Algebraic expression can be defined as combination of variables and constants.

To calculate the monthly take-home pay, we need to first find the annual take-home pay and then divide by 12 (since there are 12 months in a year).

We are given that the take-home pay is $1034.65 every two weeks, which means the total take-home pay for a year can be calculated as follows:

annual take-home pay = 1034.65 * 26 = 26889.9

Next, we divide the annual take-home pay by 12 to get the monthly take-home pay:

monthly take-home pay = 26889.9 / 12 = 2240.825

Rounding this to the nearest cent, we get:

monthly take-home pay = $2240.83

Therefore, the monthly take-home pay is $2240.83.

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9514 1404 393

Answer:

  UW = 24

Step-by-step explanation:

Midsegment XY is half the length of base UW, so we can write ...

  UW = 2·XY

  73 -7x = 2(54 -6x) . . . . substitute the given expressions

  73 -7x = 108 -12x . . . . . eliminate parentheses

  5x = 35 . . . . . . . . . . . . . add 12x-73

  x = 7 . . . . . . . . . . . . . . . divide by 5

Now, we can find UW:

  UW = 73 -7x = 73 -7·7

  UW = 24

Using a linear function, the costs are given as follows:

A linear function is modeled by:

y = mx + b

In which:

For this problem, we have that:

Hence the cost for r rides is given by the following linear function:

C(r) = 15 + 4r.

The cost for 7 rides is given by:

C(7) = 15 + 4(7) = 15 + 28 = $43.

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Answer:

Step-by-step explanation:

Answer:

The correct answer should be C. Hope I helped.

Answer:

C - an equation includes an equal sign, but an inequality doesn't

Step-by-step explanation:

Although both equations and inequalities are ways to show how expressions relate to one another, an equation is the relationship between expressions with an equals sign ( [tex]=[/tex] )  between them, however, an inequality is a way to express two or more expressions with [tex]<[/tex], [tex]\leq[/tex], [tex]>[/tex] or [tex]\geq[/tex] between them. They both include numbers, so the correct option is C.

Hope this helps :)

Answer:

A,B,D

Step-by-step explanation:

The equation that represents the relationship between g and m is; y = 55.5x

If two objects are proportional to each other, the link between them can be described by y = kx, where ‘k’ is the constant ratio of y-values to corresponding x-values.

Given that the water pump for a swimming pool can move 166.5 gallons of water in 3 minutes.

Here we need to determine the relationship between the water pump and the time for filling.

Consider x to be the number of minutes and y to be the amount of water that follows on the pump.

Then the proportionality is written as,

y = kx

Where k refers to the amount of water that flows in one minute.

Thus, equals,

=> 166.5/3

=> 55.5

Therefore, the value of k is; 55.5.

Hence, the equation that represents the relationship between g and m is; y = 55.5x

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the youngest of them is 42

i hope this was helpful:)

Answer:

Step-by-step explanation:

Two boxes have a volume of 5/6 and 1/12 cubic meters respectively. How many times does the petty box (1/12) fit in the big box (5/6)?

[tex]\frac{\frac{5}{6} }{\frac{1}{12} } =\frac{(5)(12)}{(6)(1)} =\frac{60}{6} =10[/tex]

ten times

Hope this helps

Answer:

A. x = 3, y = 2

Step-by-step explanation:

The hypotenuse and the length of one leg of one right triangle must be equal to the hypotenuse and corresponding length of the one leg of the other ∆ for both triangles to be equal by the HL Congruence Theorem.

Thus, let's find x and y by setting the corresponding lengths of the two right ∆s equal to each other.

Therefore:

x = y + 1 ----› eqn. 1

2x + 3 = 3y + 3 ----› eqn. 2

Substitute x = (y + 1) into eqn. 2, and solve for y.

2x + 3 = 3y + 3 ----› eqn. 2

2(y + 1) + 3 = 3y + 3

2y + 2 + 3 = 3y + 3

2y + 5 = 3y + 3

Collect like terms

2y - 3y = -5 + 3

-y = -2

Divide both sides by -1

y = 2

Substitute y = 2 into eqn. 1.

x = y + 1 ----› eqn. 1

x = 2 + 1

x = 3