3/4, 6/8, 9/12, 12/16 , 15/20, 18/24, 21/28, 24/32 , 27/36, 30/40, 33/44, 36/48 , 39/52, 42/56, 45/60, 48/64 , 51/68, 54/72, 57/76, 60/80, ect..
I hope this is what you are looking for :)
Please help ASAP thank you
Answer:
q
Step-by-step explanation:
Since AB is a transversal of the two parallel lines, the angle with measure 135 degrees and angle q are vertical angles. Therefore, their measure must be equal.
Hope this helps!
What is the slope of the line that passes through the points (-3, -3) and
(-18, -23)? Write your answer in simplest form.
Answer:
work is shown and pictured
URGERNT!!!PLS AT LEAST TAKE A LOOK!!! SHARE YO SMARTNESSS!! AND BLESS YOUR GRADES!
1. What could you prove about the following diagram, using the Hinge Theorem?
PIC BELOW
A) IJ>jk
B) HJ>HK
C) HK>HI
D) HI>HJ
2. Which theorem would explain why m∠CBD > m∠ADB? SECOND PICTURE
A) Hinge Theorem
B) Converse of Hinge Theorem
C) Pythagorean Theorem
Answer:
Dear Laura Ramirez
Answer to your query is provided below
1) option A is correct
2) option B is correct
Step-by-step explanation:
Explanation for the first question attached in image
Also note - The converse of the hinge theorem states that if two triangles have two congruent sides, then the triangle with the longer third side will have a larger angle opposite that third side.
Answer:
1) option A is correct2) option B is correct
Step-by-step explanation:
What else would need to be congruent to show that ABC=DEF by SAS?
Answer:
A
Step-by-step explanation:
Answer:
The answer here is A.
A) A is congruent to D.
A=
Step-by-step explanation:
AP E
What’s the correct answer for this question?
Answer:
D.
Step-by-step explanation:
In the attached file
Find the value of y. -6y+14+4y=32
Answer:
So first subtract 14 from 32
That means that -6y+4y = 18
Simplify the left side 4-6=-2
-2y = 18
Divide by -2
-9 = y
Step-by-step explanation:
Answer:
-9
Step-by-step explanation:
-6y+14+4y=32
Combine like terms
-2y +14 = 32
Subtract 14 from each side
-2y +14-14 = 32-14
-2y =18
Divide each side by -2
-2y/-2 = 18/-2
y = -9
Please show me how to solve 40% of X is 23?
NOT what is 40% of 23. But what number is 40% of to equal 23.
Thank you!!
Answer: The answers are in the steps hopes it helps.
Step-by-step explanation:
40% * x = 23 convert 40% to a decimal
0.4 * x = 23 multiply 0.4 is by x
0.4x = 23 divide both sides by 0.4
x= 57.5
Check:
57.5 * 40% = ?
57.5 * 0.4 = 23
What is the slope of the line given by the equation below?
y-20 = 5(x-2)
Answer:
5
Step-by-step explanation:
first you need to simplify this equation and put it in slope intercept form which is y = mx + b
after simplifying you will get y = 5x + 10
since the slope is m , the answer will be 5
A company plans to manufacture a rectangular box with a square base, an open top, and a volume of 452 cm3. The cost of the material for the base is 0.4 cents per square centimeter, and the cost of the material for the sides is 0.6 cents per square centimeter. Determine the dimensions of the box that will minimize the cost of manufacturing it. What is the minimum cost
Answer:
The box has sides of 11.07 cm and height of 3.69 cm.
The cost (minimum) is 147 cents per box.
Step-by-step explanation:
We have a box with open top, with a volume of 452 cm^3.
Let x: base side of the box, in cm, and y: height of the box, in cm.
Then, the volume can be expressed as:
[tex]V=x^2\cdot y=452\\\\y=452x^{-2}[/tex]
This box has 4 sides and 1 base. The material cost is 0.4 cents/cm^2 for the base and 0.6 cents/cm^2 for the sides.
Then, we can write the cost as:
[tex]C=0.4\cdot 1\cdot (x^2)+0.6\cdot 4\cdot (xy)\\\\\\xy=x\cdot(452x^{-2})=452x^{-1}\\\\\\C=0.4x^2+2.4(452x^{-1})\\\\\\C=0.4x^2+1084.8x^{-1}[/tex]
The value for x that gives a minimum cost can be found deriving the function C and equal to 0:
[tex]\dfrac{dC}{dx}=0.4(2x)+1084.8(-1\cdot x^{-2})=0\\\\\\0.8x-1084.8x^{-2}=0\\\\0.8x=1084.8x^{-2}\\\\0.8x^{1+2}=1084.8\\\\x^3=1084.8/0.8=1356\\\\x=\sqrt[3]{1356}\\\\x=11.07[/tex]
The height can be calculated with the equation:
[tex]y=452x^{-2}=452(11.07^{-2})=452\cdot 0.00816 =3.69[/tex]
The minimum cost can be calculated as:
[tex]C=0.4x^2+1084.8x^{-1}\\\\C(11.07)=0.4(11.07)^2+1084.8(11.07)^{-1}\\\\C(11.07)=0.4\cdot 122.51+1084.8\cdot0.09\\\\C(11.07)=49+98\\\\C(11.07)=147[/tex]
Trapezoid ABCD is graphed in a coordinate plane,
What is the area of the trapezoid?
4
3
B
С
16 square units
O 24 square units
32 square units
48 square units
-5 4 3 2 -11
1 2 3 4 5 x
-5
Answer:
24 square units
Step-by-step explanation:
The formula for computing the area of a trapezoid is shown below:
As we know that
Area of a trapezium is
[tex]= \frac{1}{2} \times h(a+b)[/tex]
where
h = perpendicular height
The a and b = length of the parallel sides.
Now,
h = 2 - -2 = 4 units
a = 5 - -3 = 8 units
b = 3 - -1 = 4 units
Now placing these values to the above formula
So, the area of a trapezoid is
[tex]= \dfrac{1}{2} \times 4(8+4)[/tex]
[tex]= 2 \times 12[/tex]
= 24 square units.
Hence we applied the above formula so that the area of trapezoid could come
There is a bag with only red marbles and blue marbles.
The probability of randomly choosing a red marble is
7/10
There are 42 red marbles in the bag and each is equally likely to be chosen.
How many marbles in total must there be?
Answer:
There are 60 marbles in the bag
Step-by-step explanation:
The total number of marbles times the probability of red marbles = number of red marbles
total * 7/10 = 42
Multiply each side by 10/7
total * 7/10 * 10/7 = 42*10/7
total
60
There are 60 marbles in the bag
An office building loses a third of its heat between sundown and midnight and an additional half of the original amount of heat between midnight and 4 AM. If five-eighths of the remaining heat is lost between 4 AM and 5 AM, what proportion of the total heat loss occurs between 5 AM and sunrise?
Answer:
[tex]\dfrac{1}{16}[/tex]
Step-by-step explanation:
Proportion of Heat Loss Between sundown and midnight[tex]=\dfrac{1}{3}[/tex]
Proportion of Heat Loss between midnight and 4 AM [tex]=\dfrac{1}{2}[/tex]
Proportion of Total Heat Already Lost [tex]=\dfrac{1}{3}+\dfrac{1}{2} =\dfrac{5}{6}[/tex]
Proportion of Remaining Heat [tex]=1-\dfrac{5}{6}=\dfrac{1}{6}[/tex]
Between 4 AM and 5 AM, five-eighths of the remaining heat is lost.
Proportion of Heat Loss between 4 AM and 5 AM= [tex]\dfrac{5}{8}$ X \dfrac{1}{6} = \dfrac{5}{48}[/tex]
Therefore, Proportion of Remaining Heat Left [tex]=\dfrac{1}{6}- \dfrac{5}{48}=\dfrac{1}{16}[/tex]
We therefore say that:
[tex]\dfrac{1}{16}$ of the total heat loss occurs between 5 AM and sunrise.[/tex]
Problem 3.3.9 • (a) Starting on day 1, you buy one lottery ticket each day. Each ticket is a winner with probability 0.1. Find the PMF of K, the number of tickets you buy up to and including your fifth winning ticket. (b) L is the number of flips of a fair coin up to and including the 33rd occurrence of tails. What is the PMF of L? (c) Starting on day 1, you buy one lottery ticket each day. Each ticket is a winner with probability 0.01. Let M equal the number of tickets you buy up to and including your first winning ticket. What is the PMF of M?
Answer:
a) The probability mass function of K = [tex]P(K=k) = \binom{k-1}{4}0.1^{4}*0.9^{k-5} ; k =5,6,...[/tex]
b)
c)
Step-by-step explanation:
a) Let p be the probability of winning each ticket be = 0.1
Then q which is the probability of failing each ticket = 1 - p = 1 - 0.1 = 0.9
Assume X represents the number of failure preceding the 5th success in x + 5 trials.
The last trial must be success whose probability is p = 0.1 and in the remaining (x + r- 1) ( x+ 4 ) trials we must have have (4) successes whose probability is given by:
[tex]\binom{x+r-1}{r-1}*p^{r-1}*q^{x} = \binom{x+4}{4}0.1^{4}*0.9^{x} ; x =0, 1, .........[/tex]
Then, the probability distribution of random variable X is
[tex]P(X=x) = \binom{x+4}{4}0.1^{4}*0.9^{x} ; x =0, 1, .........[/tex]
where;
X represents the negative binomial random variable.
K= X + 5 = number of ticket buy up to and including fifth winning ticket.
Since K =X+5 this signifies that X = K-5
as X takes value 0, 1 ,2,...
K takes value 5, 6 ,...
Therefore:
The probability mass function of K = [tex]P(K=k) = \binom{k-1}{4}0.1^{4}*0.9^{k-5} ; k =5,6,...[/tex]
b)
Let p represent the probability of getting a tail on a flip of the coin
Thus p = 0.5 since it is a fair coin
where L = number of flips of the coin including 33rd occurrence of tails
Thus; the negative binomial distribution of L can be illustrated as:
[tex]P(X=x) = \binom{x-1}{r-1}(1-p)^{x-r}p^r[/tex]
where
X= L
r = 33 &
p = 0.5
Since we are looking at the 33rd success; L is likely to be : L = 33,34,35...
Thus; the PMF of L = [tex]P(L=l) = \binom{l-1}{33-1}(1-0.5)^{l}(0.5)^{33} \\ \\ \\ \mathbf{P(L=l) = \binom{l-1}{33-1}(0.5)^{l} }[/tex]
c)
Given that:
Let M be the random variable which represents the number of tickets need to be bought to get the first success,
also success probability is 0.01.
Therefore, M ~ Geo(0.01).
Thus, the PMF of M is given by:
[tex]P(M = m) = (1-0.01)^{m-1} * 0.01 , \ \ \ since \ \ \ (m = 1,2,3,4,....)[/tex]
[tex]P(M=m) = (0.99)^{m-1} * 0.01 , m = 1,2,3,4,....[/tex]
29.) in Mongolia the temperature can dip down to - 45°C
in January. The temperature in July may reach 40°C.
What is the temperature range in Mongolia?
Answer:
The temperature range is [tex]95^o[/tex] , going from [tex]-45^0[/tex] to [tex]40^o[/tex]
Step-by-step explanation:
The temperature range is the difference between the maximum and the minimum temperature:
[tex]40^o-(-45^o)=40^o+45^o=95^o[/tex]
The temperature range is [tex]95^o[/tex] , going from [tex]-45^0[/tex] to [tex]40^o[/tex]
The strength of paper used in the manufacturing of cardboard boxes (y) is related to percentage of hardwood concentration in the original pulp (x). Under controlled conditions, a pilot plant manufactures 16 samples, each from differential batch of pulp, and measures the tensile strength. Determine if there is significance relationship between x and y.
y = 101, 117, 117, 106, 132, 147, 147, 134, 111, 123, 125, 145, 134, 145, 144, 146.9
x = 1.0, 1.5, 1.5, 1.5, 2.0, 2.0, 2.2, 2.4, 2.5, 2.5, 2.8, 2.8, 3.0, 3.0, 3.2, 3.3
Answer:
At a significance level of 0.05, there is enough evidence to claim that there is a significant relationship between x and y.
P-value = 0.003.
Step-by-step explanation:
If we perform a regression analysis relating x and y, we get the best fitting line with equation:
[tex]y=15.82x+92.9[/tex]
and a correlation coefficient r:
[tex]r=0.693[/tex]
We have to test the hypothesis, where the alternative hypothesis claims that there is a relationship between these two variables, and the null hypothesis claiming there is no relationship (meaning that the correlation is not significantly different from 0).
This can be written as:
[tex]H_0: \rho=0\\\\H_a:\rho\neq0[/tex]
where ρ is the population correlation coefficient for x and y.
The significance level is assumed to be 0.05.
The sample size is n=16.
The degrees of freedom are df=14.
[tex]df=n-2=16-2=14[/tex]
The test statistic can be calculated as:
[tex]t=\dfrac{r\sqrt{n-2}}{\sqrt{1-r^2}}=\dfrac{0.693\sqrt{14}}{\sqrt{1-(0.693)^2}}=\dfrac{2.593}{0.721}=3.597[/tex]
For a test statistic t=2.05 and 14 degrees of freedom, the P-value is calculated as:
[tex]\text{P-value}=2\cdot P(t>3.597)=0.003[/tex]
The P-value (0.003) is smaller than the significance level (0.05), so the effect is significant enough.
The null hypothesis is rejected.
At a significance level of 0.05, there is enough evidence to claim that there is a significant relationship between x and y.
8. Mr. Azu invested an amount at rate of 12% per annum and invested another amount. GHe
580.00 more than the first at 14%. IN Mr. Azu had total accumulated amount of
GH42.358.60. how much was his total investment?
Ans:
Answer:
GH¢.37480.36
Step-by-step explanation:
Let the amount invested at 12% per annum =GH¢.x
He invested 580.00 more than the first at 14%.
Therefore:
The amount invested at 14% =GH¢.(x+580)
For each investment option:
Amount Accrued =Principal + Simple Interest
Amount Accrued at 12%
[tex]=x+x*0.12\\=1.12x[/tex]
Amount Accrued at 14%
[tex]=(x+580)+0.14(x+580)\\=x+580+0.14x+81.2\\=1.14x+661.2[/tex]
Mr. Azu had total accumulated amount of GH42,358.60
Therefore:
1.12x+1.14x+661.2=42,358.60
2.26x=42,358.60-661.2
2.26x=41697.4
x=GH¢.18450.18
Therefore:
The amount invested at 12% per annum= GH¢.18450.18
The amount invested at 14% per annum= GH¢.18450.18+580
=GH¢.19030.18
Mr Azu's Total Investment = 18450.18 +19030.18
=GH¢.37480.36
The escape time (sec) for oil workers in a simulated exercise, gave the sample mean 370.69, sample standard deviation 24.36, and number of observations as n =26. Suppose the investigators had believed a priori that true average escape time would be at most 6 minutes. Does the data contradict this prior belief? Assuming normality, test the appropriate hypothesis using a significance level of .05.
Answer:
Null hypothesis:[tex]\mu \leq 6[/tex]
Alternative hypothesis:[tex]\mu > 6[/tex]
The statistic is given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
Replacing the info we got:
[tex]t=\frac{6.178-6}{\frac{0.68}{\sqrt{26}}}=1.335[/tex]
[tex]p_v =P(t_{25}>1.335)=0.097[/tex]
And for this case the p value is higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is at most 6 minutes
Step-by-step explanation:
Information given
[tex]\bar X=370.69/60 =6.178[/tex] represent the sample mean
[tex]s=24.36/36=0.68[/tex] represent the standard deviation for the sample
[tex]n=26[/tex] sample size
[tex]\mu_o =6[/tex] represent the value to verify
[tex]\alpha=0.05[/tex] represent the significance level
t would represent the statistic
[tex]p_v[/tex] represent the p value
System of hypothesis
We want to test if the true mean is at least 6 minutes, the system of hypothesis would be:
Null hypothesis:[tex]\mu \leq 6[/tex]
Alternative hypothesis:[tex]\mu > 6[/tex]
The statistic is given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
Replacing the info we got:
[tex]t=\frac{6.178-6}{\frac{0.68}{\sqrt{26}}}=1.335[/tex]
The degrees of freedom are:
[tex]df=n-1=26-1=25[/tex]
The p value would be given by:
[tex]p_v =P(t_{25}>1.335)=0.097[/tex]
And for this case the p value is higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is at most 6 minutes.
Please answer this correctly
Answer: 1-20=2 and 60-80=4
Step-by-step explanation:
the first is 2 number of building
and the third one is 4 number of buldings
Hope this helps :)
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents. How long will it take for this population to grow to
Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;
[tex]\frac{dp}{dt} =kp^2\\\\1=k(10)^2\\\\k=\frac{1}{100}[/tex]
Seperate the differential equation and solve for the constant C.
[tex]\frac{dp}{p^2}=kdt\\\\-\frac{1}{p}=kt+C\\\\\frac{1}{p}=-kt+C\\\\p=-\frac{1}{kt+C} \\\\2=-\frac{1}{0+C}\\\\-\frac{1}{2}=C\\\\p(t)=-\frac{1}{\frac{t}{100}-\frac{1}{2} }\\\\p(t)=-\frac{1}{\frac{2t-100}{200} }\\\\-\frac{200}{2t-100}[/tex]
You have 100 rodents when:
[tex]100=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{100} \\\\2t=98\\\\t=49\ months[/tex]
You have 1000 rodents when:
[tex]1000=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{1000} \\\\2t=99.8\\\\t=49.9\ months[/tex]
Consider the vector x: x <- c(2, 43, 27, 96, 18) Match the following outputs to the function which produces that output. Options include sort(x), order(x), rank(x) and none of these
Completed Question
Outputs to be matched to the functions are:
1,2,3,4,51,5,3,2,41, 4, 3, 5, 2 2, 18, 27, 43, 96Answer:
sort(x): 2, 18, 27, 43, 96 order(x): 1, 5, 3, 2, 4 rank(x) : 1, 4, 3, 5, 2none of these : 1, 2, 3, 4, 5Step-by-step explanation:
Given the vector x: x <- c(2, 43, 27, 96, 18)
Sort
In R, the sort(x) function is used to arrange the entries in ascending or descending order. By default, R will sort the vector in ascending order.
Therefore, the output that matches the sort function is:
sort(x): 2, 18, 27, 43, 96
Rank
The rank function returns a vector with the "rank" of each value.
x <- c(2, 43, 27, 96, 18)
2 has a rank of 143 has a rank of 427 has a rank of 396 has a rank of 518 has a rank of 2Therefore, the output of rank(x) is: 1, 4, 3, 5, 2
Order
When the function is sorted, the order function gives the previous location of each of the element of the vector.
Using the sort(x) function, we obtain: 2, 18, 27, 43, 96
In the vector: x <- c(2, 43, 27, 96, 18)
2 was in the 1st position18 was in the 5th position27 was in the 3rd position43 was in the 2nd position96 was in the 4th positionTherefore, the output of order(x) is: 1, 5, 3, 2, 4
A lot of 1000 components contains 350 that are defective. Two components are drawn at random and tested. Let A be the event that the first component drawn is defective, and let B be the event that the second component drawn is defective.
a. Find P(A).b. Find P(B|A) .c. Find P(A ∩ B).d. Find P(Ac ∩ B).e. Find P(B) .f. Find P(A|B).g. Are Aand B independent? Is it reasonable to treat A and B as though they were independent? Explain.
The probabilities are:
a. P(A) = 0.35
b. P(B|A) ≈ 0.349
c. P(A ∩ B) ≈ 0.122
d. P(A^c ∩ B) ≈ 0.228
e. P(B) = 0.35
f. P(A|B) = 0.349
g. A and B are independent.
Yes, it is reasonable to treat A and B as though they were independent because P(A) * P(B) = P(A ∩ B).
We have,
Given:
Total number of components (n) = 1000
Number of defective components (d) = 350
a.
P(A) is the probability that the first component drawn is defective:
P(A) = d/n = 350/1000 = 0.35
b.
P(B|A) is the probability that the second component drawn is defective given that the first component drawn is defective:
Since one defective component has already been drawn, the total number of components is now 999, and the number of defective components remaining is 349.
P(B|A) = Number of defective components remaining / Total number of components remaining = 349/999 ≈ 0.349
c.
P(A ∩ B) is the probability that both the first and second components drawn are defective:
P(A ∩ B) = P(A) * P(B|A) = 0.35 * 0.349 ≈ 0.122
d.
P([tex]A^c[/tex] ∩ B) is the probability that the first component drawn is not defective (complement of A) and the second component drawn is defective:
[tex]P(A^c)[/tex] is the probability that the first component drawn is not defective:
[tex]P(A^c)[/tex] = 1 - P(A) = 1 - 0.35 = 0.65
Since the first component drawn is not defective, the total number of components remaining is now 999, and the number of defective components remaining is still 350.
P([tex]A^c[/tex] ∩ B) = P([tex]A^c[/tex]) * P(B) = 0.65 * (350/999) ≈ 0.228
e.
P(B) is the probability that the second component drawn is defective:
P(B) = Number of defective components / Total number of components
= 350/1000
= 0.35
f.
P(A|B) is the probability that the first component drawn is defective given that the second component drawn is defective:
P(A|B) = P(A ∩ B) / P(B)
= (0.35 * 0.349) / 0.35
= 0.349
g.
To determine if A and B are independent, we need to compare
P(A) * P(B) with P(A ∩ B).
P(A) * P(B) = 0.35 * 0.35 = 0.1225
P(A ∩ B) = 0.122
Since P(A) * P(B) = P(A ∩ B), A and B are independent events.
It is reasonable to treat A and B as independent because the probability of A and the probability of B are not affected by each other.
The occurrence or non-occurrence of A does not impact the probability of B.
Thus,
The probabilities are:
a. P(A) = 0.35
b. P(B|A) ≈ 0.349
c. P(A ∩ B) ≈ 0.122
d. P(A^c ∩ B) ≈ 0.228
e. P(B) = 0.35
f. P(A|B) = 0.349
g. A and B are independent.
Yes, it is reasonable to treat A and B as though they were independent because P(A) * P(B) = P(A ∩ B).
Learn more about probability here:
https://brainly.com/question/14099682
#SPJ4
For the given equation, find the values of a, b, and c, determine the direction in which the parabola opens, and determine the y-intercept. Decide which table best illustrates these values for the equation: y = x squared minus 6 x Table A a b c up or down y-intercept 1 -6 0 up (0,0) Table B a b c up or down y-intercept 1 0 0 up (0,-6) Table C a b c up or down y-intercept 1 6 0 up (0,0) Table D a b c up or down y-intercept 1 -6 0 down (0,0) a. Table A c. Table C b. Table B d. Table D Please select the best answer from the choices provided
Answer:
The table that illustrates this equation is table A:
1 -6 0 up (0,0)
Step-by-step explanation:
The values of the parameters a, b, and c have to agree with the values for the general quadratic equation in standard form:
[tex]y = a\,x^2+b\,x+c[/tex]
compared to:
[tex]y=x^2-6\,x[/tex]
So the coefficient "a" of the quadratic term in our case is: "1"
the coefficient "b" of the linear term is : "-6"
the coefficient "c" for the constant term s : "0" (zero)
since the coefficient "a" is a positive number, we know that the parabola's branches must be opening "UP".
The y intercept can be found by evaluating the expression for x = 0:
[tex]y=x^2-6x\\y=(0)^2-6\,(0)\\y=0[/tex]
Therefore the y-intercept is at (0, 0)
These results agree with those of Table "A"
Answer:
Table A.)
Step-by-step explanation:
a 1, b -6, c 0, up, (0, 0), Table A.
Lindsay needs to make some house repairs in four years that will cost $8,000. She has some money in an account earning 8% annual interest. How much money needs to be in the account today so she will have enough to pay for the repairs
Answer:
$5,882
Step-by-step explanation:
To calculate the money Lindsay needs today, you can use the following formula to calculate the present value:
PV=FV/(1+i)^n
PV= present value
FV= future value= $8,000
i= interest rate= 8%
n= number of periods= 4
PV= 8,000/(1+0.08)^4
PV=8,000/1.08^4
PV=8,000/1.36
PV= 5,882
According to this, Lindsay will need to have $5,882 in the account today so she will have enough to pay for the repairs in four years.
A hiker starts at an elevation of 65 feet and descends 30 feet to the base camp . What is the elevation of the base camps ?
Answer:
the elevation of base camp is 35 ft
Step-by-step explanation:
Starting at 65 feet elevation, and the descending 30 feet to reach base camp, that means that base camp is at: 65 ft - 30 ft = 35 ft elevation
Answer:
35 feet
Step-by-step explanation:
65 feet- 30 feet= 35 feet is the elevation of the base
Fernando bought 8 pints of milk. How many fluid ounces of milk did Fernando buy? A. 16 fluid ounces B. 64 fluid ounces C. 128 fluid ounces D. 256 fluid ounces
Answer:
C.
Step-by-step explanation:
There are 16 ounces in a pint. 8 * 16 = 128
Please answer this correctly
Answer: 207^2 + 9km^2 = 216km^2
Step-by-step explanation:
(my explanation is wrong)
All you want to do is break this figure up into rectangles and triangles.
I see 3 rectangles and 1 triangle.
Three Rectangles:
The bottom one has the dimension of 5 and 20. 5 x 20 = 100 km^2
The middle one has the dimensions of 5+4 and 7. 9 x 7 = 63 km^2
The top one has the dimensions of 4 and 11. 4 x 11 = 44 km^2
Add them all up to get 207km^2
One Triangle:
We can see at the bottom rectangle that the left side is 5 and the right side is 3 + x. X being our missing height of the triangle. The height equals 2.
The triangle now has the dimensions of 2 and 6. 2 x 6 = 12. Then divide by 2 to get 6 km^2
Answer:
216 km²
Step-by-step explanation:
To solve this, you have to divide the figure into different parts. I divided the parts up into four sections. I will work on the parts in numerical order.
1. At the top of the rectangle, it is marked 4 km. On the left side, it is marked 11 km. This is the length and width.
A = lw
A = 11 × 4
A = 44 km²
2. On the left side of this rectangle, it is marked 7 km. At the top it is marked 5 km, but there is a portion that does not have a measurement (the part with a different color than the rest. Because this line is also part of rectangle 1, we know that the line is 4 km. Adding up the two numbers gives you 9 km.
4 + 5 = 9
A = lw
A = 7 × 9
A = 63 km²
3. On the left side, it is marked 5 km. On the bottom, it is marked 20 km.
A = lw
A = 20 × 5
A = 100 km²
4. This is one is a bit more tricky. This is a triangle, so we have to find the base and the height. The base is 6 km. You have to figure the height. Look at the picture with the red lines.
The red line on the right side has a length of 17 + 3 + x = 20 + x. The length is 20 + x because there is a portion of the line that is missing.
The red lines on the left side have a length of 5 + 7 + 11 = 23. The two side should be equal so
23 = 20 + x
x = 3
Now, you have the height. Use the equation for area of a triangle to solve.
A = 1/2bh
A = 1/2(3)(6)
A = 1/2(18)
A = 9 km²
Now you have to add up all the areas to find the total area.
44 km² + 63 km² + 100 km² + 9 km² = 216 km²
Older people often have a hard time finding work. AARP reported on the number of weeks it takes a worker aged 55 plus to find a job. The data on number of weeks spent searching for a job collected by AARP (AARP Bulletin, April 2008) Shows that the mean number of weeks a worker aged 55 plus spent to find a job is 22 weeks. The sample standard deviation is 11.89 weeks and sample size is 40.a) Provide a point estimate of the population mean number of weeks it takes a worker aged 55 plus to find a job.
b) At 95% confidence, what is the margin of error?
c) What is the 95% confidence interval estimate of the mean?
d) Discuss the degree of skewness found in the sample data. What suggestion would you make for a repeat of this study?
Answer:
Step-by-step explanation:
Hello!
Be the variable of interest:
X: Number of weeks it takes a worker aged 55 plus to find a job
Sample average X[bar]= 22 weeks
Sample standard deviation S= 11.89 weeks
Sample size n= 40
a)
The point estimate of the population mean is the sample mean
X[bar]= 22 weeks
It takes on average 22 weeks for a worker aged 55 plus to find a job.
b)
To estimate the population mean using a confidence interval, assuming the variable has a normal distribution is
X[bar] ± [tex]t_{n_1; 1-\alpha /2}[/tex] * [tex]\frac{S}{\sqrt{n} }[/tex]
[tex]t_{n-1; 1-\alpha /2}= t_{39; 0.975}= 2.023[/tex]
The structure of the interval is "point estimate" ± "margin of error"
d= [tex]t_{n_1; 1-\alpha /2}[/tex] * [tex]\frac{S}{\sqrt{n} }[/tex]= 2.023*[tex](\frac{11.89}{\sqrt{40} })[/tex]= 3.803
c)
The interval can be calculated as:
[22 ± 3.803]
[18.197; 25.803]
Using s 95% confidence level, you'd expect the population mean of the time it takes a worker 55 plus to find a job will be within the interval [18.197; 25.803] weeks.
d)
Job Search Time (Weeks)
21 , 14, 51, 16, 17, 14, 16, 12, 48, 0, 27, 17, 32, 24, 12, 10, 52, 21, 26, 14, 13, 24, 19 , 28 , 26 , 26, 10, 21, 44, 36, 22, 39, 17, 17, 10, 19, 16, 22, 5, 22
To study the form of the distribution I've used the raw data to create a histogram of the distribution. See attachment.
As you can see in the histogram the distribution grows gradually and then it falls abruptly. The distribution is right skewed.
Mops
News
Mamai
by Compusiogin New Tob
& Page 3 of the laws 0.
Question
Unit 2 Tutorials
Question 20
Mark this question
For the arithmetic sequence beginning with the terms (-2,0,2,4,6,8...), What is the sum of the first
18 terms?
0 238
0 340
o 304
0 270
Sove and continue
Answer:
270
Step-by-step explanation:
For any arithmetic sequence
nth term is given by
nth term = a + (n-1)d
where a is first term,
d is common difference
d is given by nth term - (n-1)th term
sum of n terms given by
sum = n/2(2a + (n-1)d)
________________________________________________
Given arithmetic sequence
-2,0,2,4,6,8...
first term a = -2
lets take third term as nth term and second term as (n-1)th term to find common difference d.
d = 2 - 0 = 2
using a = -2 , d = 2, n = 18
thus, sum of first 18 terms = n/2(2a + (n-1)d)
=18/2( 2*(-2) + (18-1) 2)
=9 ( -4 + 34)
=9 ( 30) = 270
Thus, sum of first 18 terms is 270.
Simplify the quotient shown 3480 divided by 29
Answer:
120
Step-by-step explanation:
3480/29=120
120
Simplify ———
1
final result is 120
A tank contains 60 kg of salt and 1000 L of water. A solution of a concentration 0.03 kg of salt per liter enters a tank at the rate 9 L/min. The solution is mixed and drains from the tank at the same rate. Let y be the number of kg of salt in the tank after t minutes. Write the differential equation for this situation
Answer:
[tex]\dfrac{dy}{dt}=0.27-0.009y(t),$ y(0)=60kg[/tex]
Step-by-step explanation:
Volume of water in the tank = 1000 L
Let y(t) denote the amount of salt in the tank at any time t.
Initially, the tank contains 60 kg of salt, therefore:
y(0)=60 kg
Rate In
A solution of concentration 0.03 kg of salt per liter enters a tank at the rate 9 L/min.
[tex]R_{in}[/tex] =(concentration of salt in inflow)(input rate of solution)
[tex]=(0.03\frac{kg}{liter})( 9\frac{liter}{min})=0.27\frac{kg}{min}[/tex]
Rate Out
The solution is mixed and drains from the tank at the same rate.
Concentration, [tex]C(t)=\dfrac{Amount}{Volume} =\dfrac{y(t)}{1000}[/tex]
[tex]R_{out}[/tex] =(concentration of salt in outflow)(output rate of solution)
[tex]=\dfrac{y(t)}{1000}* 9\dfrac{liter}{min}=0.009y(t)\dfrac{kg}{min}[/tex]
Therefore, the differential equation for the amount of Salt in the Tank at any time t:
[tex]\dfrac{dy}{dt}=R_{in}-R_{out}\\\\\dfrac{dy}{dt}=0.27-0.009y(t),$ y(0)=60kg[/tex]