Select the correct answer.
What are the asymptote and the y-intercept of the function shown in the graph?

f(x) = 3(0.2)^x + 2

A. asymptote: y = -2
y-intercept: (0,5)

B. asymptote: y = 2
y-intercept: (0,5)

C. asymptote: y = 2
y-intercept: (0,4)

D. asymptote: y = -2
y-intercept: (0,3)

Answer:

B

Step-by-step explanation:

The function reaches the y-axis at the point (0,5).

The asymptote is the line that the function follows but never quite reaches. In this case, the function follows the path of y = 2. However, it never exactly fits the line.

The y-intercept is (0,5) and the asymptote is y = 2. The answer, then, is B.

Good luck ^^

The equation of the asymptote is y = 2 and the coordinate of the y-intercept will be (0, 5). Then the correct option is B.

An asymptote is a line that constantly reaches a given curve, but does not touch at any infinite distance.

The equation of the function is given below.

[tex]\rm f(x) = 3(0.2)^x + 2[/tex]

The asymptote of the function is given as by substituting x as infinity, then the equation of the asymptote will be

[tex]\rm y = 3(0.2)^{\infty} + 2\\\\y = 2[/tex]

Then the y-intercept of the function will be given by substituting y = 0, then the y-intercept will be

y = 3(0.2)⁰ + 2

y = 3 + 2

y = 5

The coordinate of the y-intercept will be (0, 5).

Then the correct option is B.

More about the asymptote link is given below.

https://brainly.com/question/17767511

#SPJ5

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