1. What is the approximate area of a circle with a diameter of 20 inches?
2. What is the volume of a cube with a side length of 3 cm?
3. What is the median of the data set { 35,20, 30,25,20 }?
Answer:
1. 100[tex]\pi[/tex]
2. 27 [tex]cm^{3}[/tex]
3. 30
Step-by-step explanation:
Area = [tex]\pi[/tex][tex]r^{2}[/tex]
= [tex]\pi[/tex] x [tex]10x^{2}[/tex]
= 100[tex]\pi[/tex]
Volume = l x w x h
= 3 x 3 x 3
= 27
Consider the following geometric series.
[infinity]∑n=1 (−8)n−19n
a) Find the common ratio.
b) Determine whether the geometric series is convergent or divergent.
c) If it is convergent, find its sum. (If the quantity diverges, answer diverges.)
Answer:
a) -8/9
b) The series is a convergent series
c) 1/17
Step-by-step explanation:
The series a+ar+ar²+ar³⋯ =∑ar^(n−1) is called a geometric series, and r is called the common ratio.
If −1<r<1, the geometric series is convergent and its sum is expressed as ∑ar^(n−1) = a/1-r
a is the first tern of the series.
a) Rewriting the series ∑(-8)^(n−1)/9^n given in the form ∑ar^(n−1) we have;
∑(-8)^(n−1)/9^n
= ∑(-8)^(n−1)/9•(9)^n-1
= ∑1/9 • (-8/9)^(n−1)
From the series gotten, it can be seen in comparison that a = 1/9 and r = -8/9
The common ratio r = -8/9
b) Remember that for the series to be convergent, -1<r<1 i.e r must be less than 1 and since our common ratio which is -8/9 is less than 1, this implies that the series is convergent.
c) Since the sun of the series tends to infinity, we will use the formula for finding the sum to infinity of a geometric series.
S∞ = a/1-r
Given a = 1/9 and r = -8/9
S∞ = (1/9)/1-(-8/9)
S∞ = (1/9)/1+8/9
S∞ = (1/9)/17/9
S∞ = 1/9×9/17
S∞ = 1/17
The sum of the geometric series is 1/17
Pedro owns a shrimp truck near the beach. He sells garlic shrimp for $8 a plate and spicy shrimp for $6 a plate. Each day Pedro stocks enough shrimp to sell at most 120 plates total, but he would like to earn at least $800. Which combination of garlic shrimp plates and spicy shrimp plates can Pedro sell to meet his goal? A. 15 garlic shrimp plates and 110 spicy shrimp plates B. 80 garlic shrimp plates and 20 spicy shrimp plates C. 90 garlic shrimp plates and 25 spicy shrimp plates D. 70 garlic shrimp plates and 55 spicy shrimp plates
Answer:
C
Step-by-step explanation:
You can plug in each combination to see what would work
C is the only combination that satisfies all the constraints: it earns him more than $800 and is less than 120 plates.
The combination of 40 plates of garlic shrimp was sold, and 80 plates of spicy shrimp were sold can Pedro sell to meet his goal.
Given that,
Pedro owns a shrimp truck near the beach.
He sells garlic shrimp for $8 a plate and spicy shrimp for $6 a plate.
Each day Pedro stocks enough shrimp to sell at most 120 plates total, but he would like to earn at least $800.
We have to determine,
Which combination of garlic shrimp plates and spicy shrimp plates can Pedro sell to meet his goal?
According to the question,
Let the x plates of garlic shrimp sold,
And y plates of spicy shrimp sold.
Each day Pedro stocks enough shrimp to sell at most 120 plates,
Then,
Plates of garlic shrimp + Plates of spicy shrimp = Total number of shrimp sell each day.
[tex]\rm x + y =120[/tex]
And He sells garlic shrimp for $8 a plate and spicy shrimp for $6 a plate.
He would like to earn at least $800.
Then,
Cost of garlic shrimp per plate + Cost of spicy shrimp per plate = Total earning,
[tex]\rm 8x + 6y = 800[/tex]
On solving both the equation,
[tex]\rm x+y = 120\\\\8x + 6y = 800[/tex]
From equation 1,
[tex]\rm y= 120-x[/tex]
Substitute the value of x in equation 2,
[tex]\rm 8x +6y = 800\\\\8(120-y) + 6y = 800\\\\960 - 8y + 6y = 800\\\\-2y = 800-960\\\\-2y = -160\\\\y = \dfrac{-160}{-2}\\\\y = 80[/tex]
Substitute the value of y in equation 1,
[tex]\rm x + y =120\\\\x +80=120\\\\x = 120-80\\\\x =40[/tex]
Hence, The combination of 40 plates of garlic shrimp was sold, and 80 plates of spicy shrimp were sold can Pedro sell to meet his goal.
For more details refer to the link given below.
https://brainly.com/question/475594
An OSU senior is studying for exams in psychology and economics. The student has time to read 50 pages of psychology and 10 pages of economics. Or, in the same amount of time the student could read 30 pages of psychology and 70 pages of economics. How many pages of economics can the student read instead of reading just 1 page of psychology
Answer:
3 Pages
Step-by-step explanation:
Let the pages of economics read = eLet the pages of psychology read = pLet the total time taken on each instance=tIn the first instance, the student has time to read 50 pages of psychology and 10 pages of economics.
t=50p+10eThe student could read 30 pages of psychology and 70 pages of economics.
t=30p+70eSince the two situations take the same amount of time, we have:
50p+10e=30p+70e
Collect like terms
50p-30p=70e-10e
20p=60e
Divide both sides by 20
p=3e
Therefore, in the time it will take the student to read 1 page of psychology, the student can read 3 pages of economics.
f(x)=x^3+10x^2-25x-250
Answer:
-16x^5
Step-by-step explanation:
f(x)=x^3+10x^2-25x-250
f(x) = x^3-15x+x^2-250
f(x) = x^5-15x-250
f(x) = x^5 -x + 16
f(x) = -x^5+16
f(x) = -16x^5
// have a great day //
Given ∠E≅∠P, K is the midpoint of EP Prove EG≅MP
Answer:
∠E≅∠P || Given
∠EKG≅∠PKM || Vertical angles
EK≅KP || Midpoint Theorem
EKG≅PKM || AAS(Angle Angle Side)
EG≅MP || CPCTC (Corresponding Parts of Congruent Triangles are Congruent)
Step-by-step explanation:
Find the number of possible outcomes if the numbers 1 through 7 are written on different pieces of paper and placed in a hat. Two of these numbered pieces of paper are selected without replacement, and a 2-digit number is formed using the first number drawn in the tens place and the second number drawn used in the ones place.
Answer:
The number of the possible outcomes are:
12,13,14,15,16,17
21,23,24,25,26,27
31,32,34,35,36,37
41,42,43,45,46,47
51,52,53,54,56,57
61,62,63,64,65,67
71,72,73,74,75,76
The total number of possible outcomes = 42
Step-by-step explanation:
Given that :
the numbers 1 through 7 are written on different pieces of paper; &
Two of these numbered pieces of paper are selected without replacement;
Also,
a 2-digit number is formed using the first number drawn in the tens place and the second number drawn used in the ones place.
Then:
if the first number drawn is 1 , then the possible outcomes will be :
12,13,14,15,16,17
If the first number drawn is 2; then the possible outcomes will be:
21,23,24,25,26,27
If the first number drawn is 3; then the possible outcomes will be:
31,32,34,35,36,37
If the first number drawn is 4; then the possible outcomes will be:
41,42,43,45,46,47
If the first number drawn is 5; then the possible outcomes will be:
51,52,53,54,56,57
If the first number drawn is 6; then the possible outcomes will be:
61,62,63,64,65,67
If the first number drawn is 7; then the possible outcomes will be:
71,72,73,74,75,76
The number of the possible outcomes are:
12,13,14,15,16,17
21,23,24,25,26,27
31,32,34,35,36,37
41,42,43,45,46,47
51,52,53,54,56,57
61,62,63,64,65,67
71,72,73,74,75,76
The total number of possible outcomes = 7 × 6 = 42
What’s the correct answer for this question?
Answer:
C:
Step-by-step explanation:
In a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc
So
AQD = ARC AD/2
<AQD = 78/2
<AQD = 39°
PLEASE HELP ?
The range is the set of
A: first coordinates
B: ordered pairs
C:second coordinates
Answer:
C:second coordinates
Step-by-step explanation:
A range is the set of output coordinates
The domain is the input coordinates
Domain is the x, range is the y
Answer: its definitly c
Step-by-step explanation:
The mean annual salary for intermediate level executives is about $74000 per year with a standard deviation of $2500. A random sample of 36 intermediate level executives is selected. What is the probability that the mean annual salary of the sample is between $71000 and $73500?
Answer:
11.51% probability that the mean annual salary of the sample is between $71000 and $73500
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question, we have that:
[tex]\mu = 74000, \sigma = 2500, n = 36, s = \frac{2500}{\sqrt{36}} = 416.67[/tex]
What is the probability that the mean annual salary of the sample is between $71000 and $73500?
This is the pvalue of Z when X = 73500 subtracted by the pvalue of Z when X = 71000. So
X = 73500
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{73500 - 74000}{416.67}[/tex]
[tex]Z = -1.2[/tex]
[tex]Z = -1.2[/tex] has a pvalue of 0.1151
X = 71000
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{71000 - 74000}{416.67}[/tex]
[tex]Z = -7.2[/tex]
[tex]Z = -7.2[/tex] has a pvalue of 0.
0.1151 - 0 = 0.1151
11.51% probability that the mean annual salary of the sample is between $71000 and $73500
If the ratio of the ages of Kissi and Esinam is 3:5 and that of Esinam and Lariba is 3:5 and the sum of the ages of all 3 is 147 years, what is the age difference between oldest the youngest?
Answer:
48
Step-by-step explanation:
Esinam shere a common ratio hence,
the lcm of 3 and 5 is 15
Kissi:Esinam= 9:15 and Esinam:Lariba=15:25
Combining; 9:15:25
Let x be the ages such that,
Kissi=9x and Esinam=15x and Lariba=25x
9x+15x+25x=147
49x=147
x=3
Youngest; Kissi=9x=9(3)=27
Oldest; Lariba=25x=25(3)=75
Difference 75-27=48
what is an example of a literal question
Answer:
an example of a literal question is "what size do you wear", "what time does the show start", "who was the protagonist in your story" etc
Step-by-step explanation:
Venera sent a chain letter to her friends, asking them to forward the letter to more friends.
The relationship between the elapsed time t, in months, since Venera sent the letter, and the number of
people, P(t), who receive the email is modeled by the following function:
3t+7
P(t) = 2
Complete the following sentence about the monthly rate of change in the number of people who receive
the email.
Round your answer to two decimal places.
Every month, the number of people who receive the email is multiplied by a factor of
Answer:
It is multiplied by a factor of 8
Step-by-step explanation:
Every month, the number of people who receive the email is multiplied by a factor of 8.
What is an exponent?Let b is the base and x is the power of the exponent function and a is the leading coefficient. The exponent is given as
y = a(b)ˣ
Venera sent a chain letter to her friends, asking them to forward the letter to more friends.
The relationship between the elapsed time t, in months, since Venera sent the letter, and the number of people, P(t), who receive the email is modeled by the following function:
[tex]\rm P(t) = 2^{3t+7}[/tex]
Every month, the number of people who receive the email is multiplied by a factor will be
For t = 2, we have
P(2) = 2³⁽²⁾⁺⁷
P(2) = 2¹³
For t = 3, we have
P(3) = 2³⁽³⁾⁺⁷
P(3) = 2¹⁶
Then the factor will be
⇒ P(3) / P(2)
⇒ 2¹⁶ / 2¹³
⇒ 2³
⇒ 8
More about the exponent link is given below.
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250cm3 of fresh water of density 1000kgm-3 is mixed with 100cm3 of sea water of density 1030kgm-3. Calculate the density of the mixture. *
Answer:
[tex] m_{fresh}= 1000 \frac{Kg}{m^3} * 2.5x10^{-4} m^3 = 0.25 Kg[/tex]
And we can do a similar procedure for the sea water:
[tex] m_{sea}= \rho_{sea} V_{sea} [/tex]
And after convert the volume to m^3 we got:
[tex] m_{sea}= 1030 \frac{Kg}{m^3} * 1x10^{-4} m^3 = 0.103 Kg[/tex]
And then the density for the mixture would be given by:
[tex] \rho_{mixture}= \frac{m_{fresh} +m_{sea}}{v_{fresh} +v_{sea}}[/tex]
And replacing we got:
[tex] \rho_{mixt}= \frac{0.25 +0.103 Kg}{2.5x10^{-4} m^3 +1x10^{-4} m^3} = 1008.571 \frac{Kg}{m^3}[/tex]
Step-by-step explanation:
For this case we can begin calculating the mass for each type of water:
[tex] m_{fresh}= \rho_{fresh} V_{fresh} [/tex]
And after convert the volume to m^3 we got:
[tex] m_{fresh}= 1000 \frac{Kg}{m^3} * 2.5x10^{-4} m^3 = 0.25 Kg[/tex]
And we can do a similar procedure for the sea water:
[tex] m_{sea}= \rho_{sea} V_{sea} [/tex]
And after convert the volume to m^3 we got:
[tex] m_{sea}= 1030 \frac{Kg}{m^3} * 1x10^{-4} m^3 = 0.103 Kg[/tex]
And then the density for the mixture would be given by:
[tex] \rho_{mixture}= \frac{m_{fresh} +m_{sea}}{v_{fresh} +v_{sea}}[/tex]
And replacing we got:
[tex] \rho_{mixt}= \frac{0.25 +0.103 Kg}{2.5x10^{-4} m^3 +1x10^{-4} m^3} = 1008.571 \frac{Kg}{m^3}[/tex]
Debby is working on her typing.
• At first, Debby typed at a rate of 80 words per minute
After she took a typing class, she could type 300 more words per hour than she could before the typing class.
How many words per minute could Debby type after taking the typing class?
85
130
220
e
300
Answer:
300/60=5 more words per minute
80+5 = 85 words per minute
or
80 x 60 = 4800 + 300 = 5100
5100 / 60 = 85 words per minute
Hope this helps
Step-by-step explanation:
Assuming the below results were obtained in a study used to test the accuracy of the rapid diagnostic test for influenza, calculate and interpret the sensitivity of the rapid diagnostic influenza test.
Frequency of Flu Cases Frequency of Non-Fu Cases
Frequency of Individuals who 47 10
Screened Positive
Frequency of individuals who 43 100
Screened Negative
A) When the rapid diagnostic influenza test is used, 52.22% of individuals who have the flu test positive for the flu.
B) When the rapid diagnostic influenza test is used, 90.91% of individuals who have the flu test positive for the
C) When the rapid diagnostic influenza test is used, 47.78% of individuals who have the flu test positive for the flu.
D) When the rapid diagnostic influenza test is used, 9.09% of individuals who have the flu test positive for the flu.
Answer:
c
Step-by-step explanation:
On average, a major earthquake (Richter scale 6.0 or above) occurs three times a decade in a certain California county. Find the probability that at least one major earthquake will occur within the next decade. A. .1992 B. .7408 C. .9502 D. .1494
the sum of the three numbers in 2003,two of the numbers are 814 and 519 what is the third number
Answer:
idk dont ask me
Step-byi-step explanation:
Answer:
a+b+c=2003
a+b=814
2003-819=189
Step-by-step explanation:
What’s the correct answer for this question ?
Answer:
C
Step-by-step explanation:
It closely resembles to a sphere.
Please answer this correctly
Answer:
698 cm²
Step-by-step explanation:
The volume is given by ...
V = LWH
Filling in the given values, we have ...
1020 = (17)(5)y . . . . . . . using L=17, W=5, H=y
y = 1020/(17·5) = 12
The surface area is given by ...
A = 2(LW +H(L+W))
A = 2(17·5 +12(17+5)) = 2(85 +264) . . . . . . . using L=17, W=5, H=y=12
A = 698 . . . . square centimeters
Express (In 35+ln(1/7))/ In 25 in terms of In 5 and In 7
Properties of the logarithm: for any base of logarithm,
log(a*b) = log(a) + log(b)
If we replace b with 1/b, or b^-1, we have
log(a/b) = log(a) + log(1/b) = log(a) - log(b)
since
log(1/b) = log(b^-1) = - log(b)
using the power property of logarithms,
log(b^n) = n log(b)
Now,
ln35 = ln(5*7) = ln5 + ln7
ln(1/7) = - ln7
ln25 = ln(5^2) = 2 ln5
Putting everything together, we have
(ln35 + ln(1/7))/ln25 = (ln5 + ln7 - ln7)/(2 ln5) = ln5/(2 ln5) = 1/2
What is 11/12 divided 1/3
Answer:
2.75 or 2 3/4
Step-by-step explanation:
so here you use the recipricle of 1/3. so you would do 11/12 X 3/1 =33/12= 2 3/4
Answer: 11/4
Step-by-step explanation:
to divide a fraction by another, you multiply by the reciprocal(the opposite of a certain fraction). the reciprocal of 1/3 is 3/1. so:
[tex]\frac{11}{12} / \frac{1}{3} = \frac{11}{12} * \frac{3}{1} = \frac{33}{12} = \frac{11}{4}[/tex] (divide both sides by 3 to simplify for the last one)
Which system of linear inequalities is represented by the
graph?
O y2x - 2 and y = x + 1
O y< x-2 and y> x + 1
O y < x-2 and y? x + 1
O y> x-2 and y < x + 1
Answer:
answer c.
y <= x - 2 and y >= x + 1
Step-by-step explanation:
You wrote the given answers wrong. Here are the right choices that are given as possible solutions:
O y >= x - 2 and y <= x + 1
O y < x - 2 and y > x + 1
O y <= x - 2 and y >= x + 1
O y > x - 2 and y < x + 1
The graph clearly shows two lines and the intended area is shaded and it is clearly including the lines.
Because the lines are included in the solution, by that alone, you can exclude two answers b and d.
Now you still need to decide between the in equalities in answer a and c. Both lines have a gradient of 1, so that does not help to distinguish...
The y intercept of the top line is at y= +1 and the shaded area is bigger then that....
So y >= x + 1 is the right inequality.By now it is absolutely clear that answer c must be the right answer and you are done!
EXTRA
Although you have deduced beyond any doubt, that answer c must be the right answer, you still can check your findings 'to be sure' by looking and checking for the bottom line...
BE CAREFUL, ONLY DO THIS IF YOU HAVE ENOUGH TIME. Again, you already know the right answer, and this is "just to confirm", so what is the harm in that?
By double checking yourself, it will sort of "undermine" your appproach. Basically you are doing something which is strictly spoken not nessasary any more. So I urge you to basically step over the urge to check yourself, and stick to your answer.
However, if you can not resit the temptation of checking to see if you actually found the right answer, you could test the y intercept of the bottom line, which is at y= -2 and the shaded area is smalller then that....
So y <= x - 2 is the right inequality.So again, it is now confirmed that answer c is indeed the right answer.
The correct system of linear inequalities is represented by the graph are,
⇒ y > x - 2
⇒ y < x + 1
What is mean by Inequality?A relation by which we can compare two or more mathematical expression is called an inequality.
Given that;
The system of linear inequalities is shown in graph.
Hence, By graph;
The value of y - intercepts are,
⇒ - 2 and - 1
Hence, The correct system of linear inequalities is represented by the graph are,
⇒ y > x - 2
⇒ y < x + 1
Thus, The correct system of linear inequalities is represented by the graph are,
⇒ y > x - 2
⇒ y < x + 1
Learn more about the inequality visit:
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The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 28 mm and standard deviation 7.6 mm.(a)What is the probability that defect length is at most 20 mm
Answer:
14.69% probability that defect length is at most 20 mm
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 28, \sigma = 7.6[/tex]
What is the probability that defect length is at most 20 mm
This is the pvalue of Z when X = 20. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{20 - 28}{7.6}[/tex]
[tex]Z = -1.05[/tex]
[tex]Z = -1.05[/tex] has a pvalue of 0.1469
14.69% probability that defect length is at most 20 mm
write eight hundred and seven thousand, two hundred and five in figures
Answer:
807,205
Step-by-step explanation:
Take the eight hundred and seven thousand and express that has 807,000. Then, add the two hundred and five at the end to get 807,205
The given statement is written in figures 807,205.
The given statement is eight hundred and seven thousand, two hundred and five in figures.
We need to write the given statement as the number.
What are numbers?A number is a mathematical object used to count, measure, and label. The original examples are the natural numbers 1, 2, 3, 4, and so forth. Numbers can be represented in language with number words.
Now, eight hundred and seven thousand, two hundred and five=807,205.
Therefore, the given statement is written in figures 807,205.
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Find the area of the compound shape below..
Answer:
32 cm²
Step-by-step explanation:
6*4+ 1/2*4*4= 32 cm²
Simplify [tex]4(y+11)2-3y^2[/tex]
Answer:
[tex]y^2+88y+484[/tex]
Step-by-step explanation:
[tex]4(y+11)^2-3y^2= \\\\4(y^2+22y+121)-3y^2= \\\\4y^2-3y^2+88y+484= \\\\y^2+88y+484[/tex]
Hope this helps!
What is the approximate value for the modal daily sales?
Answer:
Step-by-step explanation:
Hello!
The table shows the daily sales (in $1000) of shopping mall for some randomly selected days
Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5
Days 18 27 31 40 56 55 23
Use it to answer questions 13 and 14.
13. What is the approximate value for the modal daily sales?
To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)
The modal interval is [3.1-3.5]
Now using the following formula you can calculate the Mode:
[tex]Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ][/tex]
Li= Lower limit of the modal interval.
c= amplitude of modal interval.
fmax: absolute frequency of modal interval.
fprev: absolute frequency of the previous interval to the modal interval.
fpost: absolute frequency of the posterior interval to the modal interval.
[tex]Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47[/tex]
A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53
Of all options the closest one to the estimated mode is A.
14. The approximate median daily sales is …
To calculate the median you have to identify its position first:
For even samples: PosMe= n/2= 250/2= 125
Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.
F(1)= 18
F(2)= 18+27= 45
F(3)= 45 + 31= 76
F(4)= 76 + 40= 116
F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]
[tex]Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ][/tex]
Li: Lower limit of the median interval.
c: Amplitude of the interval
PosMe: position of the median
F(i-1)= accumulated absolute frequency until the previous interval
fi= simple absolute frequency of the median interval.
[tex]Me= 3,100+400[\frac{125-116}{56} ]= 3164.29[/tex]
A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664
Of all options the closest one to the estimated mode is C.
Charlotte is creating a triangular pennant with geometry software.
The base measure of the pennant on screen is 550 pixels. The height
is 275 pixels. Charlotte resizes the pennant, keeping the aspect ratio
constant, so the height is 165 pixels. What is the scale factor of the
dilation? What is the base of the pennant?
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pls help T-T
Answer:
Base of the Pennant = 330 pixels
Scale Factor =0.6
Step-by-step explanation:
The base measure of the pennant on screen is 550 pixels.
The height is 275 pixels.
[tex]A$spect Ratio=\dfrac{Base}{Height}=\dfrac{550}{275} =2:1[/tex]
If Charlotte resizes the pennant, keeping the aspect ratio constant.
Height = 165 pixels
Therefore:
[tex]\dfrac{Base}{165}=\dfrac{2}{1} \\\\$Base= 2 *165 =330[/tex]
Therefore, the scale factor of the dilation [tex]=\dfrac{330}{550}= \dfrac{165}{275}=0.6[/tex]
Base of the Pennant = 330 pixels
Scale Factor =0.6
Tony rode his bicycle 3 7/10 miles to school. What is this distance written as a decimal?
Answer:
7/10=0.7
3+0.7=3.7
3.7
Hope this helps
Step-by-step explanation: