Answer:
The number of the class containing the largest score can be found in frequency 24 and the class is 98 - 103
For the third class 78 - 83 ; the upper limit = 83
The class width for this histogram 5
The number of students that took the exam simply refers to the frequency is 84
The percentage of students that scored higher than 95.5 is 53%
Step-by-step explanation:
The objective of this question is to use the following histogram that shows the exam scores for a Pre-algebra class to answer the question given:
NOW;
The table given in the question can be illustrated as follows:
S/N Class Score Frequency
1 68 - 73 70.5 0
2 73 - 78 75.5 4
3 78 - 83 80.5 8
4 83 - 88 85.5 12
5 88 - 93 90.5 16
6 93 - 98 95.5 20
7 98 - 103 100.5 24
TOTAL: 84
a) The number of the class containing the largest score can be found in frequency 24 and the class is 98 - 103
b) For the third class 78 - 83 ; the upper limit = 83 ( since the upper limit is derived by addition of 5 to the last number showing in the highest value specified by the number in the class interval which is 78 ( i.e 78 + 5 = 83))
c) The class width for this histogram 5 ; since it is the difference between the upper and lower boundaries limit of the given class.
So , from above the difference in any of the class will definitely result into 5
d) The number of students that took the exam simply refers to the frequency ; which is (0+4+8+12+16+20+24) = 84
e) Lastly; the percentage of students that scored higher than 95.5 is ;
⇒[tex]\dfrac{20+24}{84} *100[/tex]
= 0.5238095 × 100
= 52.83
To the nearest percentage ;the percentage of students that scored higher than 95.5 is 53%
Answer:
1. 98-103 (6th class)
2. 88
3. 5
4. 84
5. 52%
Step-by-step explanation:
Find attached the frequency table.
The class of exam scores falls between (1, 2, 3, 4, 5, or 6).
The exam score ranged from 68-103
1) The largest number of exam scores = 24
The largest number of exam scores is in the 6th class = 98 -103
Step 2 of 5:
The upper class limit is the higher number in an interval. Third class interval is 83-88
The upper class limit of the third class 88.
Step 3 of 5:
Class width = upper class limit - lower class limit
We can use any of the class interval to find this as the answer will be the same. Using the interval between 73-78
Class width = 78 - 73
Class width for the histogram = 5
Step 4 of 5:
The total of students that took the test = sum of all the frequency
= 0+4+8+12+16+20+24 = 84
The total of students that took the test = 84
Step 5 of 5:Find the percentage of students that scored higher than 95.5
Number of student that scored higher than 95.5 = 20 + 24 = 44
Percentage of students that scored higher than 95.5 = [(Number of student that scored higher than 95.5)/(total number of students that took the test)] × 100
= (44/84) × 100 = 0.5238 × 100 = 52.38%
Percentage of students that scored higher than 95.5 = 52% (nearest percent)
Researchers want to know about the true proportion of adults with at least a high school education. 1000 adults are surveyed, and 710 of them have at least a high school education. Create a 95% confidence interval for the true population proportion of adults with at least a high school education. Interpret this interval in context of the problem.
Answer:
The 95% confidence interval for the true population proportion of adults with at least a high school education is (0.6819, 0.7381). This means that we are 95% sure that the true proportion of adults in the entire population surveyed with at least a high school education is (0.6819, 0.7381).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
For this problem, we have that:
[tex]n = 1000, \pi = \frac{710}{1000} = 0.71[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.71 - 1.96\sqrt{\frac{0.71*0.29}{1000}} = 0.6819[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.71 + 1.96\sqrt{\frac{0.71*0.29}{1000}} = 0.7381[/tex]
The 95% confidence interval for the true population proportion of adults with at least a high school education is (0.6819, 0.7381). This means that we are 95% sure that the true proportion of adults in the entire population surveyed with at least a high school education is (0.6819, 0.7381).
Name the x-axis of symmetry for the parabola sketched below
Answer:
x=-3
Step-by-step explanation:
The vertex is at x = -3
The axis of symmetry is along the vertex
x=-3
Answer:
x=-3
Step-by-step explanation:
To find the axis of symmetry, you just need to find the x-coordinate of the vertex using this formula: -b/2a=x
*Only when provided a three variable quadratic equation.
For looking at a graph, you find the center of the parabola in which when you reflect it over itself, it will be symmetrical.
According to the graph, x=-3 is the line which you can draw to fold over to the other side and it can fit perfectly.
A fluctuating electric current II may be considered a uniformly distributed random variable over the interval (9, 11)(9,11). If this current flows through a 2-ohm resistor, find the probability density function of the power P = 2I^2P=2I 2 .
Answer:
Step-by-step explanation:
A fluctuating electric current II may be considered a uniformly distributed random variable over the interval (9, 11)
[tex]p_1=\{^{\frac{1}{2}:9\leq i\leq 11}_{0:otherwise[/tex]
Now define
[tex]p = 2I^2[/tex]
[tex]\Rightarrow I^2=(\frac{p}{2} )\\\\\Rightarrow I=(\frac{p}{2} )^{\frac{1}{2} }\\\\\Rightarrow h^{-1}(p)=(\frac{p}{2} )^{\frac{1}{2}}[/tex]
[tex]\frac{dh^{-1}}{dp} =\frac{d[h^{-1}(p)]}{dp} \\\\=\frac{d(p/2)^{\frac{1}{2} }}{dp}[/tex]
[tex]=\frac{1}{2} \times \frac{1}{2} (\frac{p}{2} )^{{\frac{1}{2}-1} }\\\\=\frac{1}{4}(\frac{p}{2} )^{{\frac{1}{2}-1} }\\\\=\frac{1}{2}(\frac{2}{p} )^{{\frac{1}{2}} }[/tex]
using the transformation method, we get
[tex]f_p(p)=f_1(h^{-1}(p))|\frac{d[h^{-1}(p)]}{dp} |\\\\=\frac{1}{2} \times \frac{1}{4} (\frac{2}{p} )^{\frac{1}{2} }\\\\=\frac{1}{8} (\frac{2}{p} )^{\frac{1}{2} }[/tex]
[tex]f_p(p)=\{^{\frac{1}{8} (\frac{2}{p} )^{\frac{1}{2} },162\leqp\leq 242} }_{0,otherwise}[/tex]
From a sample with nequals24, the mean number of televisions per household is 4 with a standard deviation of 1 television. Using Chebychev's Theorem, determine at least how many of the households have between 2 and 6 televisions. At least nothing of the households have between 2 and 6 televisions.
Answer:
At least 18 of the households have between 2 and 6 televisions.
Step-by-step explanation:
Chebyshev Theorem
The Chebyshev Theorem can also be applied to non-normal distribution. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.
At least 89% of the measures are within 3 standard deviations of the mean.
An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]100(1 - \frac{1}{k^{2}})[/tex].
In this question:
Mean = 4
Standard deviation = 1
Percentage of households that have between 2 and 6 televisions.
2 = 4 - 2*1
So 2 is two standard deviations below the mean
6 = 4 + 2*1
So 6 is two standard deviations above the mean
By Chebyshev's Theorem, at least 75% of the measures are within 2 standard deviations of the mean.
Out of 24
0.75*24 = 18
At least 18 of the households have between 2 and 6 televisions.
Let two cards be dealt successively, without replacement, from a standard 52-card deck. Find the probability of the event. The first card is a queen and the second is a seven
Answer: 4 / 663
Step-by-step explanation:
There are 4 queens in a deck of 52 cards.
Probability = 4/52 = 1/13
There are 4 sevens
Probability = 4/51
Total probability = 1/13 x 4/51 = 4 / 663
The probability of drawing a queen first and a seven-second is 3/613.
What is probability?Probability is defined as the possibility of an event being equal to the ratio of the number of favorable outcomes and the total number of outcomes.
There are 4 queens in a standard deck, and once one queen is drawn, there are 51 cards left, including 3 sevens.
So, the probability of drawing a queen first is 4/52 or 1/13, and the probability of drawing a seven-second is 3/51.
By the multiplication rule of probability, multiply the probabilities of each event occurring:
P(Queen and Seven) = P(Queen) × P(Seven after Queen)
P(Queen and Seven) = (1/13) × (3/51)
P(Queen and Seven) = 3/613
Thus, the probability of drawing a queen first and a seven-second is 3/613.
Learn more about the probability here:
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The mean of 6 numbers is 32.If one of the numbers is excluded, the mean reduces by 2.Find the excluded number.
Answer:
42
Step-by-step explanation:
Mean = Sum of numbers/ Total numbers
Sum of 6 numbers = 32 x 6
= 192
If one number is excluded the mean reduce by 2 . so it becomes 30
Sum of 5 Numbers = 5 x 30
=150
Therefore the excluded number is
= 192 - 150
= 42.
ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. I say no guessing because people usually guess on my questions.
Answer:
D. It would be less steep.
Step-by-step explanation:
→When the absolute value of the number in front of x is greater than 1, the function on the graph narrows. When the absolute value of the number in front of x is less than 1, the function on the graph widens.
In this case, the number is less than 1, making it grow wider. And as a result of it growing wider, it also becomes less steep.
WILL GIVE BRAINLIEST! HURRY
Answer:
4
Step-by-step explanation:
2(6x+4)-6+2x=3(4x+3)+1
=14x+2=12x+10
=14x+2-2=12x+10-2
=14x=12x+8
=14x-12x=12x+8-12x
=2x=8
=2x/2=8/2
x=4
need answers to 30 and 31
Answer:
C ; A
Step-by-step explanation:
Question 30:
Perimeter is the sum of all sides.
Perimeter for a recatngle can be found with the formula:
2(L+W)
Length is 7
Width is 4
Plug our values in.
2(7+4)
2(11)
22
Answer C
Question 31:
Circumference of a circle can be found with the formula:
πd.
Diameter of the given circle is 6.
Plug it in
6π
Round π to 3.14
6(3.14)
18.84
Answer A
Find the values of x in the figure below. Express your answer in simplest radical form.
Answer:
Step-by-step explanation:I don't say u must have to mark my ans as brainliest but if it has really helped u plz don't forget to thank me...
What is the image of (-4,12) after a dilation by a scale factor of 1/4 centered at the origin
Answer:
(-1,4)
Step-by-step explanation:
Divide each imput by 4
The required image of the given point (-4, 12) dilation by a scale factor of 1/4 and centered at the origin is (1, -3).
Given that,
To determine the image of (-4,12) after dilation by a scale factor of 1/4 centered at the origin.
The graph is a demonstration of curves that gives the relationship between the x and y-axis.
What is coordinate?Coordinate, is represented as the values on the x-axis and y-axis of the graph
Here,
For the point, we have a dilation factor of 1/4,
So dilated coordinate,
= (1/4 * - 4 , 1/4 * 12)
= (-1 , 3)
To form the image across the origin
= - (-1, 3)
= (1, -3)
Thus, the required image of the given point (-4, 12) with a scale factor of 1/4 and centered at the origin is (1, -3).
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A recent national survey found that parents read an average (mean) of 10 books per month to their children under five years old. The population standard deviation is 5. The distribution of books read per month follows the normal distribution. A random sample of 25 households revealed that the mean number of books read last month was 12. At the .01 significance level, can we conclude that parents read more than the average number of books to their children
Answer:
Step-by-step explanation:
Null hypothesis: u = 10
Alternative hypothesis: u =/ 10
Using the formula: t = (x - u) / (s /√n)
Where x = 12, u = 10, s = 5 and n = 25
t= (12-10) / (5/√25)
t = (2)/(5/5)
t = 2/1= 2
t = 2.0
At a 0.01 level of significance with a degree of freedom of 24, the p-value is 0.0569, which is greater than 0.01 we will fail to reject the null and conclude that parents do not read more than the average number of books to their children
A washer and a dryer cost $639 combined. The washer costs $61 less than the dryer. What is the cost of the dryer?
Answer:
$350
Step-by-step explanation:
Let d = price of dryer
Then d - 61 is the price of the washer.
The sum of the prices is $639.
d + d - 61 = 639
2d - 61 = 639
2d = 700
d = 350
The price of the dryer is $350
Is f(x) continuous at x equals 4? Why or why not? A. No, f(x) is not continuous at x equals 4 because ModifyingBelow lim With x right arrow 4 f (x )does not exist. B. Yes, f(x) is continuous at x equals 4 because f (4 )exists. C. No, f(x) is not continuous at x equals 4 because f (4 )is undefined. D. Yes, f(x) is continuous at x equals 4 because ModifyingBelow lim With x right arrow 4 f (x )equals f (4 ).
Corrected Question
Is the function given by:
[tex]f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right[/tex]
continuous at x=4? Why or why not? Choose the correct answer below.
Answer:
(D) Yes, f(x) is continuous at x = 4 because [tex]Lim_{x \to 4}f(x)=f(4)[/tex]
Step-by-step explanation:
Given the function:
[tex]f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right[/tex]
A function to be continuous at some value c in its domain if the following condition holds:
f(c) exists and is defined.[tex]Lim_{x \to c}$ f(x)[/tex] exists. [tex]f(c)=Lim_{x \to c}$ f(x)[/tex]At x=4
[tex]f(4)=\dfrac{1}{4}*4+1=2[/tex][tex]Lim_{x \to 4}f(x)=2[/tex]Therefore: [tex]Lim_{x \to 4}f(x)=f(4)=2[/tex]
By the above, the function satisfies the condition for continuity.
The correct option is D.
The Gleason family has a monthly budget of $4,500. Mr. Gleason has a full-time job and takes home $900 each week. Mrs. Gleason works part time and brings home $9 each week. For every hour she works. How many hours per month must Mrs. Gleason work to make sure that she and Mr. Gleason have met their monthly budget?
Answer:
The value of x from the equation is 100. Thus, Mrs. Gleason should work for 100 hours per month.
Step-by-step explanation:
To answer this item, we let x be the number of hours per month that Mrs. Gleason should work. The total budget is equal to sum of the amount acquired by Mr. Gleason and Mrs. Gleason. The equation that would express this is,
4,500 = 900(4) + 9x
The value of x from the equation is 100. Thus, Mrs. Gleason should work for 100 hours per month.
I am sorry if you get this wrong.
HELP WITH THIS PLEASE
Answer:
a = 35º
b = 140º
c = 40º
d = 140º
e = 58º
Step-by-step explanation:
Angle A is supplementary to the angle that is 145º, and supplementary angles always add up to 180º. Therefore, 180 - 145 = 35, the measure of angle a. Angle B is supplementary to the 40º angle, so its measure is 140. Angle C is opposite the 40º angle, and opposite angles are congruent, so its measure would also be 40º. Angle D is also 140º because it is opposite of angle B. Angle E is supplementary to the angle that measures 122º, so 180 - 122 = 58. Hope this helped!
The Employment and Training Administration reported that the U.S. mean unemployment
insurance benefit was $238 per week (The World Almanac, 2003). Aresearcher in the state
of Virginia anticipated that sample data would show evidence that the mean weekly unemployment
insurance benefit in Virginia was below the national average.
a. Develop appropriate hypotheses such that rejection of H0 will support the researcher’s
contention.
b. For a sample of 100 individuals, the sample mean weekly unemployment insurance
benefit was $231 with a sample standard deviation of $80. What is the p-value?
c. At αα = .05, what is your conclusion?
d. Repeat the preceding hypothesis test using the critical value approach.
Answer:
Step-by-step explanation:
a) We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
H0: µ = 238
For the alternative hypothesis,
H1: µ < 238
This is a left tailed test
b) Since the population standard deviation is not given, the distribution is a student's t.
Since n = 100
Degrees of freedom, df = n - 1 = 100 - 1 = 99
t = (x - µ)/(s/√n)
Where
x = sample mean = 231
µ = population mean = 238
s = samples standard deviation = 80
t = (231 - 238)/(80/√100) = - 0.88
We would determine the p value using the t test calculator. It becomes
p = 0.19
c) Since alpha, 0.05 < than the p value, 0.19, then we would fail to reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed insignificant evidence that the mean weekly unemployment insurance benefit in Virginia was below the national average.
d) Since α = 0.05, the critical value is determined from the t distribution table. Recall that this is a left tailed test. Therefore, we would find the critical value corresponding to 1 - α and reject the null hypothesis if the test statistic is less than the negative of the table value.
1 - α = 1 - 0.05 = 0.95
The negative critical value is - 1.66
Since - 0.88 is greater than - 1.66, then we would fail to reject the null hypothesis.
There are nine saxophone players in the band. The number of saxophone players is one less than twice the number of tuba players. Find the number of tuba players.
Answer:
[tex]5[/tex]
Step-by-step explanation:
Let [tex]x[/tex] be the number of tuba players.
We are given that the number of saxophone players is one less than twice the number of tuba players.
There are 9 saxophone players.
[tex]9 = 2 x-1[/tex]
[tex]9+1=2x[/tex]
[tex]10=2x[/tex]
[tex]10 \div 2=x[/tex]
[tex]5=x[/tex]
a ford truck enters a highway and travles uniform speed of 50 mph. half an hour later a jaguar enters the highway at the same junction and heads in the same direction at 55 mph. how long after the ford enters the highway does the jaguard catch up
Answer:
5.5 hours
Step-by-step explanation:
We have that the distance is given by:
d = v * t = 50 mph * 1/2 h = 25 miles
The relative speed is given by:
vr = 55 mph - 50 mph = 5 mph
Now the time required to reach
would come being:
t = t '+ d / vr
we know that t '= 1/2 h, replacing:
t = 1/2 h + 25 mi / 5 mph
t = 1/2 h + 5 h
t = 5.5 h
Therefore, the required time is 5.5 hours.
Landes is a sales representative for a company. She earns a basic pay of $2,750 a month plus commission of 1.5%. How much does Landes [now that the moderators are gone just answer this question and claim points lol]
Answer:
2,748.5
Step-by-step explanation:
Answer:
thank uuu
Step-by-step explanation:
An individual closes out help desk tickets at a rate of 4 tickets per hour for h hours. Write an equation that expresses the situation, let x be the independent variable and y be the dependent variable
Answer:
y=4x
Step-by-step explanation:
an independent variable is the variable that is changed or controlled in an experiment or observation to test the effects on the dependent variable
a dependent variable is variable being tested and measured in a scientific experiment
in this case, the number of help desk tickets closed out is dependent on the number of hours the individual works so y is the number of tickets closed (dependent variable). The number of tickets closed of will be 4 multiplied by the number of hours worked i.e. y=4x
At the beginning of an experiment, a scientist has 300 grams of radioactive goo. After 150 minutes, her sample has decayed to 37.5 grams.
What is the half-life of the goo in minutes?
________
Find a formula for
G(t),
the amount of goo remaining at time T.
G= _________
How many grams of goo will remain after 32 minutes?
Answer:
Half-life of the goo is 49.5 minutes
[tex]G(t)= 300e^{-0.014t}[/tex]
191.7 grams of goo will remain after 32 minutes
Step-by-step explanation:
Let [tex]M_0\,,\,M_f[/tex] denotes initial and final mass.
[tex]M_0=300\,\,grams\,,\,M_f=37.5\,\,grams[/tex]
According to exponential decay,
[tex]\ln \left ( \frac{M_f}{M_0} \right )=-kt[/tex]
Here, t denotes time and k denotes decay constant.
[tex]\ln \left ( \frac{M_f}{M_0} \right )=-kt\\\ln \left ( \frac{37.5}{300} \right )=-k(150)\\-2.079=-k(150)\\k=\frac{2.079}{150}=0.014[/tex]
So, half-life of the goo in minutes is calculated as follows:
[tex]\ln \left ( \frac{50}{100} \right )=-kt\\\ln \left ( \frac{50}{100} \right )=-(0.014)t\\t=\frac{-0.693}{-0.014}=49.5\,\,minutes[/tex]
Half-life of the goo is 49.5 minutes
[tex]\ln \left ( \frac{M_f}{M_0} \right )=-kt\Rightarrow M_f=M_0e^{-kt}[/tex]
So,
[tex]G(t)= M_f=M_0e^{-kt}[/tex]
Put [tex]M_0=300\,\,grams\,,\,k=0.014[/tex]
[tex]G(t)= 300e^{-0.014t}[/tex]
Put t = 32 minutes
[tex]G(32)= 300e^{-0.014(32)}=300e^{-0.448}=191.7\,\,grams[/tex]
Find the range of the set of numbers shown by the box-and-whisker plot.
6
6
7
8
9
10
11
12
13
14
16
16
17
18
19
20
21
22
Answer:
16
Step-by-step explanation:
The range is the difference between the highest and lowest number of a data set. 22-6=16
What is the slope intercept form.
Answer:
y = 1/4x + 2
Step-by-step explanation:
Since they gave you point slope form already, all you need to do is convert that into slope-intercept form. Just distribute the parenthesis and move the 4 over. Once you do so, you should get C/3rd option as your answer.
x^2 + 5x - 24 = 0 How do I solve by factoring
Answer:
x = -8 or x = 3
Step-by-step explanation:
To factor ax² + bx + c, use AC method.
a times c is 1 × -24 = -24.
Factors of ac (-24) that add up to b (5) are 8 and -3.
Divide by a and reduce: 8/1 and -3/1.
Therefore, the factors are x + 8 and x − 3.
x² + 5x − 24 = 0
(x + 8) (x − 3) = 0
x = -8 or 3
$17,500,000 is what percent of $70,000,000?
Answer: 1/4 of 70,000,000
Step-by-step explanation: 17,500,000 / 70,000,000 = 0.25
Answer:
[tex]25\%[/tex]
Step-by-step explanation:
[tex]\frac{17,500,000}{70,000,000}[/tex]
[tex]\frac{1}{4}=0.25=25/100=25\%[/tex]
Question 1 Muit Choice Worth 1 points)
(08.01 LC)
The school principal wants to know whether the students in the entire school prefer football or basketball. The principal draws a random sample from the following groups:
• All school teachers
. All girls in each grade
. All students in each grade
• All students on the basketball team
Which of the following groups best represents the population she should take a random sample from to get the best results for her survey?
All school teachers
All girls in each grade
All students in each grade
All students on the basketball team
Answer:
I think its C. All students in each grade
Step-by-step explanation:
because it should be the students choice.
Please answer this correctly
Answer:
432
Step-by-step explanation:
l x w
4x3
4x19
8x24
8x19
432
A sample mean, sample size, and population standard deviation are provided below. Use the one-mean z-test to perform the required hypothesis test at the 10% significance level.
x = 20, n = 36, sigma = 9, H0: mu = 25, H amu : < 25.
Answer:
[tex]z=\frac{20-25}{\frac{9}{\sqrt{36}}}=-3.33[/tex]
The p value for this case is given by:
[tex]p_v =P(z<-3.33)=0.000434[/tex]
For this case the p value is a very low value compared to the significance level of 0.1 so then we can reject the null hypothesis and we can conclude that the true mean is significantly less than 25 at 10% of significance.
Step-by-step explanation:
Information given
[tex]\bar X=20[/tex] represent the sample mean
[tex]\sigma=9[/tex] represent the population deviation
[tex]n=36[/tex] sample size
[tex]\mu_o =25[/tex] represent the value to verify
[tex]\alpha=0.1[/tex] represent the significance level
tzwould represent the statistic
[tex]p_v[/tex] represent the p value
System of hypothesis
We want to test the hypothesis that the true mean is lower than 25 and the system of hypothesis are:
Null hypothesis:[tex]\mu \geq 25[/tex]
Alternative hypothesis:[tex]\mu < 25[/tex]
The statistic is given by:
[tex]z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}[/tex] (1)
Replacing the info given:
[tex]z=\frac{20-25}{\frac{9}{\sqrt{36}}}=-3.33[/tex]
The p value for this case is given by:
[tex]p_v =P(z<-3.33)=0.000434[/tex]
For this case the p value is a very low value compared to the significance level of 0.1 so then we can reject the null hypothesis and we can conclude that the true mean is significantly less than 25 at 10% of significance.
if you start with (2,6) and move 2 units right and 3 units down what will you end up with?
For (2,6) the 2 is the x value which is the left/right position and 6 is the y value which is the up/down position.
Moving 2 units to the right, you would add 2 to the x value. Moving 3 units down you would subtract 3 from the y value.
The answer would be (4,3)