The gravitational force between two students sitting beside each other on Earth is

Answer:

Diploid is often noted as 2N where N is the number of chromosomes. So in humans 2N=46. During sexual reproduction, the sex cells of parent organisms unite with one another and form a fertilized egg cell. In this situation, each sex cell is a gamete.

Explanation:

Answer:

Explanation:

Do you mean the theory that space-time is defined by what's in it? And that mass warps space-time?

There are many instances where his observation turned out to be correct. The most popular one is the phenomena of gravitational lensing. We can see the light from stars that are actually behind the sun. The huge gravity of the sun bends space-time and this also bends light. We use gravitational lensing alllll the time when trying to see very distant stars or galaxies.

Answer:

The Sun bent the light from a star. This bending made the star appear in a slightly different position from its actual position. This observation supported Einstein’s theory.

Explanation:

This is the answer on Edmentum! :)

Answer:

10.2 m/s

Explanation:

Using conservation of energy:

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)

v = 10.2 m/s

The velocity when car reaches the bottom of the hill is 10.2 m/s.

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

M.E = ½ mv² + mgh

where g is the acceleration due to gravity, v is the velocity, m is the mass and h is the height of the object.

Given is a 1380 kg car starts from rest at the top of a 28.0 m long hill inclined at 11.00 degrees.

Using conservation of energy principle, we have

PE = KE

mgh = ½ mv²

v = √(2gh)

Substitute the values, we get

v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)

v = 10.2 m/s

Thus, the velocity when car reaches the bottom of the hill is 10.2 m/s.

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Answer:

Mass is the amount of matter in a substance.

Explanation:

The basic SI unit for mass is the kilogram (kg).

Answer:

The graph of G(x) is the graph of F(x) shifted 1 unit to the left and 3 units down.

Explanation:

f(x + q) which is left q units

f(x - q) which is right q units

f(x) + q which is up q units

f(x) - q which down q nits

and

G(x) = F(x + 1) - 3

So,

f(x + 1) shifts to left 1 unit

f(x) - 3 shifts to down 3 units

So, the correct answer is B.

The graph of G(x) is the graph of F(x) shifted 1 unit to the left and 3 units down.

Answer:

t = 5.19 s

Explanation:

We have,

Height of the cliff is 132 m

It is required to find the time taken by the ball to fall to the ground. Let t is the time taken. So, using equation of kinematics as :

[tex]y=ut+\dfrac{1}{2}gt^2\\\\\text{since}\ u=0\\\\y=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2y}{g}}\\\\t=\sqrt{\dfrac{2\times 132}{9.8}}\\\\t=5.19\ s[/tex]

So, it will take 5.19 seconds to fall to the ground.

Answer:

Joseph proust's law of difinite composition

Law of conservation of mass

Explanation:

Dalton's law of multiple proportions is part of the basis for modern atomic theory, along with Joseph Proust's law of definite composition (which states that compounds are formed by defined mass ratios of reacting elements) and the law of conservation of mass that was proposed by Antoine Lavoisier.

Answer:

law of conservation of mass

law of definite proportions

Explanation:

Answer:

A. 0.5m/s².

B. –0.5m/s².

C. –0.5m/s².

D. 100m.

Explanation:

A. Determination of the acceleration in the first 20s.

Initial velocity (u) = 0

Final Velocity (v) = 10m/s

Time (t) = 20secs.

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (10 – 0)/20 = 10/20

a = 0.5m/s²

Therefore, the acceleration of the cyclist in the first 20secs is 0.5m/s²

B. Determination of the acceleration between 20 and 30s. This can be obtained as follow:

Initial velocity (u) = 10m/s

Final Velocity (v) = 5m/s

Time (t) = 30 – 20 = 10s

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (5 – 10)/10 = –5/10

a = –0.5m/s²

Therefore, the acceleration of the cyclist between the 20 and 30secs is

–0.5m/s².

C. Determination of the acceleration in the last 10s.

Initial velocity (u) = 5m/s

Final Velocity (v) = 0

Time (t) = 10s

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (0 – 5)/10 = –5/10

a = –0.5m/s²

Therefore, the acceleration of the cyclist between the last 10secs is

–0.5m/s².

D. Determination of the distance travelled by the cyclist when he was moving at a constant speed.

Velocity (v) = 5m/s

Time (t) = 50 – 30 = 20secs

Displacement (d) =?

Velocity = Displacement /Time

v = d/t

5 = d/20

Cross multiply

d = 5 x 20

d = 100m

Therefore, the distance travelled by the cyclist at constant speed is 100m

Answer:

9 volts (assuming 0.60 is in Amperes)

Explanation:

Recall that Ohms law can be expressed as

V = IR, where

V = voltage,

I = current (given as 0.6. I'm going to assume that the units is Amperes because it is not given)

R = resistance (given as 15 ohm)

substituting the above values into the formula

V = IR

V = (0.6)(15)

V = 9 Volts

Answer:

Explanation:

Kinetic energy

Answer:

The time between the emission of the wave and it's reception was 0.4 seconds.

Explanation:

The sound wave emitted by the sonar traveled from the boat to the fishes and came back, therefore the distance of it's total route is twice the distance from the boat to the fishes. We can apply the average speed formula in order to solve this problem, this is done below:

[tex]\text{speed} = \frac{\text{distance}}{\text{time}}[/tex]

We were given the distance traveled by the wave and it's speed, therefore we can solve for the time:

[tex]\text{time} = \frac{\text{distance}}{\text{speed}}\\\\\text{time} = \frac{(2*300)}{1500}\\\\\text{time} = \frac{600}{1500} = 0.4 \text{ s}[/tex]

The time between the emission of the wave and it's reception was 0.4 seconds.

Answer:

0.125m/s^2

Explanation:

20-10=10

10 divided by 80=0.125m/s^2

The average velocity of the car is 15 m/s. The time taken to travel over the distance with this velocity is 5.3 seconds. Then the acceleration of the car is 1.8 m/s².

Acceleration is a physical quantity measuring the rate  of change in velocity of a moving object. Like velocity, acceleration is a vector quantity having magnitude and direction.

Acceleration is the ratio of change in velocity to the change in time.

a = Δv/Δt

Given, the car is accelerating from 10 to 20 m/s. Hence, it travelled with average velocity of 15 m/s over the distance of 80 m.

Then , time taken  = distance/velocity

t = 80 m/15 m/s = 5.3 s

Acceleration = Δv/t = (20 -10 m/s) /5.3 s = 1.8 m/s².

Therefore, the acceleration of the car is about  1.8 m/s².

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Answer: Dear Buddy ,the common brnches os physics are given below:

Explanation:

Mechanics

Classical physics

Modern physics

Thermodynamics

Electricity

Magnetism

Geo physics

Plasma physics

Optics

Sound and oscillation

Electronics

Chemical physics

Engineering physics

Solid state physics

Quantum physics

Nuclear physics

Particle physics

Bio physics

Astrophysics

Condensed matter physics

hope it helps

Answer:

Engineering is one of branches that uses physics mainly the most

Explanation:

as for engineering requires mathematics and physics principles in their everyday routine to calculate and measure accordingly to manufactur a product.

Answer:

F = 37.5 N

Explanation:

It is given that,

Mass of the object is 5 kg

Acceleration of the object is 7.5 m/s²

We need to find the force experienced by the object. The force is given by the product of mass and acceleration of an object. So,

F = m

[tex]F=5\times 7.5\\\\F=37.5\ N[/tex]

So, the force acting on the object is 37.5 N.    

Answer:

A

Explanation:

This is the first law of thermodynamics and it's called the law of conservation of energy

Answer:

Option A:  F/4

Explanation:

Centripetal force, [tex]F = \frac{mv^{2} }{r}[/tex]

Where v = speed

r = radius

Since Kinetic Energy, [tex]E_{k} = 0.5 mv^{2}[/tex]

Writing centripetal force in terms of kinetic energy, [tex]F = \frac{2 E_k}{r}[/tex]

If the initial radius of the circle, r₁ =r

The doubled radius, r₂ = 2r

If the initial kinetic energy, [tex]KE_1 = E_{k}[/tex]

The halved kinetic energy,  [tex]KE_2 = 0.5E_{k}[/tex]

Therefore, the new Centripetal force becomes:

[tex]F_{2} = \frac{2(0.5 E_k)}{2r} \\F_{2} = \frac{0.5 E_k}{r}\\F_{2} =\frac{1}{4} * \frac{2 E_k}{r}\\Since, F = \frac{2 E_k}{r} \\F_{2} =\frac{1}{4} * F\\F_{2} =\frac{F}{4}[/tex]

Answer:

To calculate the mechanical advantage of a pulley you simply have to count the number of rope sections that support whatever object you are lifting (not counting the rope that is attached to the effort)

Example:

For example, in a one pulley system the MA is 1. In a two pulley system the MA is 2. The more compound the pulley is the easier the load is to lift. If you were lifting a 600kg object with 2 pulleys you would have to use enough effort to pull 300kg to lift the 600kg object! Therefore your mechanical advantage would be 2 (600/300).

               MA= load/effort OR number of rope sections

Answer:

The difference in tension,  between adjacent sections of the pull cable at the given conditions is 17.701 kN

Explanation:

We take the cars as moving upwards such that the resultant pulling force on the car, F, along the cable is given by the relation

[tex]F_{car}[/tex] = Upward tension force,  [tex]Tension_{(upwards)}[/tex] - Downward tension force, [tex]Tension_{(downwards)}[/tex] - Component of the weight of the car along the taut cable

The parameters given are;

Mass of car, m = 2750 kg

Angle of inclination of taut cables, θ = 35°

The upward acceleration of the car, a = 0.81 m/s²

Given that the weight is acting vertically downwards, we have;

Component of the weight of the car along the taut cable = m × g × sin(θ)

∴ Component of the weight of the car along the taut cable = 2750 × 9.81 × sin (35°) = 15473.66 N

We therefore have;

[tex]F_{car}[/tex] =  [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] - 15473.66 N

[tex]F_{car}[/tex]  = m × a = 2750 × 0.81 =  [tex]T_{upwards}[/tex] - [tex]T_{downwards}[/tex] - 15473.66

∴  [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] = 2750 × 0.81 + 15473.66 = 17701.16 N

Hence the difference in tension,  [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] between adjacent sections of the pull cable if the cars are at the maximum permissible mass and are being accelerated up the incline = 17701.16 N or 17.701 kN.

Answer: The degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

Explanation:

presence of food, water ,etc

Explanation:

here is five all you have to do is just pick

Answer:

lift

weight

thrust

air resistance

Explanation:

plz mark me as brainliest

Answer: Upthrust, lift, air resistance,  and thrust

Explanation:

All of these 4 elements are taken into account during the design and creation of a plane.

Answer: 180 m south

Explanation:

The displacement of the horse in this time is 180 m south. The correct option is A.

The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.

Velocity is the time rate of change of displacement with time.

Given is a horse runs for 15 seconds to the south at a speed of 12 m/s. So, the displacement is

Displacement = Speed x Time

Put the values, we get

Displacement = 12 m/s x 15s

                      = 180 m

Thus, the displacement of the horse in this time is 180 m south.

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Answer:

20

Explanation:

because I am always right yo bro be like me

Answer:

50 %

Explanation:

It's Fifty percent

Answer:

(a) The package lands 682 meters horizontally ahead from the point the package was dropped from the plane

(b) The horizontal component = 39.0 m/s

The vertical component = 171.55 m/s

(c) The angle of impact is 77.19°

Explanation:

The parameters given are;

Velocity of the plane, vₓ = 39.0 m/s

Height of the plane above the ground, h = 1.50 × 10² m = 1,500 m

(a) The time, t, before the package hits the ground when dropped from the plane is given by the relation;

h = u·t + 1/2×g×t²

Where:

g = Acceleration due to gravity = 9.81 m/s²

u = Initial vertical velocity = 0 m/s

Hence;

1500 = 0×t + 1/2 × 9.81 × t² = 4.905·t²

∴ t = √(1500/4.905) = 17.49 s

The horizontal distance the package travels before landing = 17.49 × 39 ≈ 682 m

The package lands 682 meters horizontally ahead from the point the package was dropped from the plane

(b) The vertical velocity, [tex]v_y[/tex], of the package just before landing is given by the relation;

[tex]v_y[/tex]² = u² + 2·g·h

u = 0 m/s

∴ [tex]v_y[/tex]² = 0 + 2×9.81×1500 = 29430 m²/s²

[tex]v_y[/tex] = √29430  = 171.55 m/s

Hence the horizontal component = 39.0 m/s

The vertical component = 171.55 m/s

(c) The angle of impact, θ, is given as follows;

[tex]tan \theta = \dfrac{v_y}{v_x} = \dfrac{171.55}{39.0 } = 4.4[/tex]

∴ θ = tan⁻¹(4.4) = 77.19°.

Answer:

visual art in which one uses to mark drawing and express feelings

Explanation:

In my own opinion. Hope it helps.

Newton's law of universal gravitation doesn't say anything about the cause of gravity.

Einstein's theory of relativity does.

Answer:

[tex]\lambda=4.81\times 10^{-8}\ m[/tex]

Explanation:

We have,

The surface temperature of the star is 60,000 K

It is required to find the wavelength of a star that radiated greatest amount of energy. Wein's displacement law gives the relation between wavelength and temperature such that :

[tex]\lambda T=2.89\times 10^{-3}[/tex]

Here,

[tex]\lambda[/tex] = wavelength

[tex]\lambda=\dfrac{2.89\times 10^{-3}}{60000}\\\\\lambda=4.81\times 10^{-8}\ m[/tex]

So, the wavelength of the star is [tex]4.81\times 10^{-8}\ m[/tex].