The proportion of observations from a standard Normal distribution that take values larger than -0.75 is about A) 0.2266 B) 0.7704 C) 0.7734 D) 0.7764 E) 0.8023

Answer:

c

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

Answer:here is the right answer took the test and got it right trust and believe Jonathan’s answer is reasonable because is 16, and 16 is close to 15.77.

Step-by-step explanation:

Answer:

Step-by-step explanation:

fx^3

Answer:

hhhhhhhhhhhhhhhhhhjhhhhhhhhh

Answer:

5/3

Step-by-step explanation:

Looking at the two points, we count the rise (rise/run). It'd be 5 going up from the bottom point all the way to the same level as the top point. Then we count how many units over, which is 3. The slope of this would be 5/3. in slope form would be y=5/3x

Answer:

The slope is 6

Step-by-step explanation:

To find the slope you use the formula rise/run

The rise is the second y coordinate minus the first y coordinate

The run is the second x coordinate minus the first y coordinate

Step one:

Take any 2 points: I used (-1,2) and (-4,-3)

Step two:

Use the formula: rise/run

-4-2/-2-(-1)

-6/-1

6

I hope this helps :)

Answer:

I believe it is A.

Let me know if this helps!

Answer:

50 days?

Step-by-step explanation:

Answer:

i think it is 2 because

10 divide by 5 = 2

1 x 2 = 2

2 days

Answer:

D

Step-by-step explanation:

in answer D, the values would equal "6" and "18" which is not equivalent to the given equation

Answer:

Reasoning:

You multiply x by 9 and 2 by 9 and it expands out from 9(x+2) to 9x+18

I hope this helps and good luck!

Answer:

9x + 18

Step-by-step explanation:

9 times x = 9x

9 x 2 = 18

Answer:

The slope seems to be 4.

Step-by-step explanation:

The line seems to be starting at (3,0) and if you use the rule rise/run, it goes up (rises) 4 units and moves over (runs) 1 unit. You then rewrite this as 4/1 and you get 4 as the slope!

Answer:

The slope is 4

My logic:

Slope is delta y over delta x so if you take any 2 points on that graph and get the x and y of each point and find the change of the two x and the two y and put the change in y over the change in x. you get slope. like so= 16/4 or 4

Answer:

Answer:

Step-by-step explanation:

      Statements                                       Reasons

1). UW bisects ∠VUX                1). Given

2). UW bisects ∠VWX              2). Given

3). ∠VUW = ∠WUX                   3). Definition of angle bisector

4). ∠UWV = ∠UWX                   4). Definition of angle bisector

5). UW = UW                             5). Reflexive property of congruence

6). ΔUWX ≅ ΔUWV                  6). ASA postulate of congruence

Answer: The ball will hit the ground 6 seconds after it has ben thrown, at t = 6s.

Step-by-step explanation:

The equation for the height of the ball should be:

s(t) = (-16ft/s^2)*t^2 + 96ft/s*t

When s(t) = 0ft, means that the ball is in the ground

This represents the height of the ball as a function of t, the time in seconds.

We can see that at t = 0s:

s(0s) = (-16ft/s^2)*(0s)^2 + 96ft/s*(0s) = 0ft

Then at the time 0 seconds, the ball is in the ground, so we must look at the other root of the equation

(-16ft/s^2)*t^2 + 96ft/s*t = 0ft

To find it, we can use the Bhaskara equation, in this case is:

[tex]t = \frac{-96ft/s +- \sqrt{(96ft/s)^2 - 4*(-16ft/s^2)*0} }{-2*16ft/s^2} = \frac{-96ft/s^2 +-96ft/s^2}{-32ft/s^2}[/tex]

Then we have the two solutions:

t = (-96ft/s + 96ft/s)/(-32 ft/s^2) = 0s  (the one that we already found)

And the other one is:

t = (-96ft/s - 96ft/s)/(-32ft/s^2) = 6s

Then:

s(6s) = 0ft

This means that the ball will hit the ground at t = 6 seconds.

The time required to hit the ground is required.

The time taken by the ball to reach the ground is 2.45 seconds.

The equation is

[tex]s(t)=-16t^2+96[/tex]

At the ground [tex]t=0[/tex]

so,

[tex]0=-16t^2+96\\\Rightarrow 16t^2=96\\\Rightarrow t=\sqrt{\dfrac{96}{16}}\\\Rightarrow t=2.45\ \text{s}[/tex]

The time taken by the ball to reach the ground is 2.45 seconds.

Learn more:

https://brainly.com/question/18769085?referrer=searchResults

∠A ≅ ∠Z

you can determine this by seeing that both angles have two curved lines, therefor showing they have the same measurement.

∠B ≅ ∠Y

you can also determine this by seeing that they both have one curved line showing that they share the same measurement.

∠C ≅ ∠X

once again, you can determine this by seeing that both angles are marked with three curved lines, meaning they share the same measurements.

line AB ≅ line ZY

just like before, you can determine that they are equivalent to each other by seeing that both lines have three dashes showing that they have the same measurement.

line AC ≅ line ZX

you can determine these lines are equivalent because they both have one dash showing they are the same length as each other.

line BC ≅ line YX

once again, both lines have two dashes, showing that they are equivalent in length.

ΔCAB ≅ XZY

you can determine this by seeing that all three angles and all three sides on both triangles share measurements with the other triangle

Answer:

A)

534 rounds to 500

395 rounds to 400

B) 100

Step-by-step explanation:

A)

534 rounds to 500 because the next digit 3 is less than 5 which means that you round down.

395 rounds to 400 because the next digit 9 is greater than 5 which means that you round up.

B)

500-400=100

Hope this helps! :)

Answer:

20%

Step-by-step explanation:

i actually dont know sorry :(

Answer:

20% discount

Step-by-step explanation:

4/5 = 80%

5/5 - 4/5 = 1/5

1/5 = 20%

Answer:

y=mx + b

Step-by-step explanation:

y= y intercept coordinate

m=slope=x coordinate

b = y intercept

Answer:

Step-by-step explanation:

If 41 students is in the roll (total), then

[tex]\frac{3}{41}[/tex] = [tex]\frac{x}{100}[/tex] ⇒ x = [tex]\frac{3*100}{41}[/tex] ≈ 7.3 %

Answer:

0.02

Step-by-step explanation:

Given a normal distribution :

Mean income (m) = 25000

Standard deviation of income (s) = 6000

X ≥ 12000

Using the relation to fund the standardized score :

Zscore =(x - m) / s

Zscore = ( 12000 - 25000) / 6000

Zscore = -13000 / 6000

Zscore = - 2.167

Using a z probability calculator :

P(Z ≤ - 2.167) = 0.015117

= 0.02

Answer:

A

Step-by-step explanation:

beacause Harry loves school so he go to school

Answer:

26.

Step-by-step explanation:

Given, BD is a median. As it divides the AC equally, that's why it will AD=CD. Given, AD= 6x+10 and CD= 2x+12

Now, AD=  CD

or, 6x+10=2x+12

or, 6x-2x= 12-10

or, 4x= 2

or, x= 1/2

So the value of x is 1/2. As BD divided AC equally, both AD and CD will be equal and AD+CD= AC.

So, 6x+10+2x+12= AC

or, 8x+22= AC

or, 8 X (1/2) + 22= AC

or, 4+22 = AC

or, AC= 26.=

Answer: The bag of candy corn will take 5 seconds to land on the floor and it will hit it with velocity of 49m/s.

Step-by-step explanation: A free falling object has only Gravitational Force acting on it, so acceleration will be due to gravity, which has magnitude

g = 9.8m/s².

As Professor Sosa drops the bag, its initial velocity and time are 0.

The building has a height of 400ft, so adjusting units: y = 121.92 m and [tex]y_{0}[/tex] = 0.

For this problem, going down will be the positive reference.

Then:

[tex]y=y_{0}+v_{0}t+\frac{g}{2}t^{2}[/tex]

[tex]\Delta y=v_{0}t+\frac{g}{2}t^{2}[/tex]

[tex]121.92=\frac{9.8}{2}t^{2}[/tex]

[tex]t=\sqrt{\frac{121.92*2}{9.8} }[/tex]

t ≈ 5

It will take 5s for the candy corn bag to land on the ground.

Acceleration is the change in velocity per change in time, so:

[tex]g=\frac{\Delta v}{\Delta t}[/tex]

As initial velocity and time are 0 and rearraging it:

v = g.t

v = 9.8*5

v = 49

The bag will hit the ground with velocity of magnitude 49 m/s.

Answer:

The sector given in the figure is a semi-circle because the degree measure of the chord is 180 degrees.

Area of semicircle = 0.5π[tex]r^{2}[/tex] = 0.5π×4.5 = 6.75 sq. inches

Answer:

$62.50

Step-by-step explanation: 250 divided by 4 equals $62.10

Answer:

Solving [tex](4g^2-9) \div (2g-3)[/tex] we get 2g+3

Option B is correct.

Step-by-step explanation:

We need to solve [tex](4g^2-9) \div (2g-3)[/tex]

We know that [tex]a^2-b^2=(a-b)(a+b)[/tex]

So, [tex]4g^2-9[/tex] can be written as [tex](2g)^2-(3)^2[/tex]

So, using above formula we will get:

[tex]4g^2-9\\=(2g^2)-(3)^2 \\Using \ formula a^2-b^2 = (a-b)(a+b)\\=(2g-3)(2g+3)[/tex]

So, numerator will become

[tex]\frac{(2g-3)(2g+3)}{(2g-3)} \\Simplifying:\\=2g+3[/tex]

So, solving [tex](4g^2-9) \div (2g-3)[/tex] we get 2g+3

Option B is correct.