The standard test to determine the maximum lateral acceleration of a car is to drive it around a 200-ft diameter circle painted on a level asphalt surface. The driver slowly increases the vehicle speed until he is no longer able to keep both wheel pairs straddling the line. If the maximum speed is 35 mi/hr for a 3000-lb car, compute the magnitude F of the total friction force exerted by the pavement on the car tires.

Answer:

c

Explanation:

it is stored energy because it is built up in said object

Answer:

1.52 × 10⁻²⁰ J

Explanation:

The electrical potential difference is defined as the amount of work done in carrying a unit charge from one point to another point in an electric field. Electric potential difference is measured in volts. It is given by the formula:

ΔV = ΔU / q

ΔV is electric potential difference between the two points, ΔU is the work done and q is the unit charge.

Given that ΔV = 0.095 V, q = 1.6 × 10⁻¹⁹ C. Hence:

ΔU = ΔV.q

ΔU = 0.095 V * 1.6 × 10⁻¹⁹ C

ΔU = 1.52 × 10⁻²⁰ J

The electric potential difference is the amount of effort done in an electrical field to shift a unit charge from one spot to another.The electric potential difference will be 1.52×10⁻²⁰J.

What is the electric potential difference ?

The electrical potential difference is the amount of effort done in an electrical field to shift a unit charge from one spot to another.

Traditional current flows from positive to negative terminals, signifying positive charge transfer in that direction.

The given data in the problem is

[tex]\triangle V[/tex] is the electric potential difference between the inner and the outer cell wall = 0.095 V

[tex]\triangle U[/tex] is the amount of work done

q is the charge on the electron =1.6×10⁻¹⁹C

Electric potential difference is given by the formula

[tex]\triangle V=\frac{\triangle U}{q} \\\\ \triangle U=\triangle Vq\\\\\triangle U=0.095 V\times1.6\times10^{-19}\\\\ \triangle U=1.52\times10^{-20}J[/tex]

Hence the electric potential difference will be 1.52×10⁻²⁰J.

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Answer:

the small angle measurement from the central maximum is

Explanation:

The computation of the small angle measurement is as follows:

The constructive interference condition is

[tex]d \sin \theta = m \lambda \\\\Now \\\\\theta = sin^{-1} (\frac{\lambda}{d}) \\\\= sin^{-1}(\frac{610\times10^{-9}}{0.0250\times10^{-3}} )\\\\= 1.40^{\circ}[/tex]

hence the small angle measurement from the central maximum is [tex]1.40^{\circ}[/tex]

Answer:

This same Hawaii telescope, which would be 4 km across water level, can't provide an appropriate version of distanced planetary bodies. A further overview is provided below.

Explanation:

Answer:

A. oceanic crust

Explanation:

I remember that the ocean is said to cover 71% of the Earth's surface. If you look at a globe, notice that most all the surface is blue like the ocean.

One other note: the surface is the Earth's outermost layer. Think of it this way: surface implies the top of something, something exposed to the outside.

Therefore, the answer is A. Hope this helps you understand the question more! Have a great day, 'kay?

Answer:

2880 N/c

Explanation:

Given that:

Charge per unit length ; λ = 4 * 10^-9

radius, r = 10

Radius, R = 0.5m

Using the relation :

2λr / 4πE0R²

Columb's constant, k = 1/4πE0 =. 9* 10^9Nm²/C²

Hence, we have :

2λrk/ R²

(2 * 4 * 10^-9 * 10 * 9 * 10^9) / 0.5^2

(720 ÷ 0.25)

= 2880 N/c

This question involves the concepts of compression and rarefraction.

This wave should be classified as "A) a longitudinal wave".

A surface wave is a mechanical wave which propagates on the boundary interface between two different media.

A longitudinal wave is the wave in which the direction of travel of the wave and medium are the same. This wave consists of compressions and rarefactions.

A transverse wave is the wave in which the direction of travel of the wave and medium are perpendicular to each other. It consists of crests and troughs.

An electromagnetic wave is the one which consists of electric field and magnetic field vibrating perpendicular to each other.

Hence, the wave with compressions and rarefactions is classified as a longitudinal wave.

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Heart disease is the leading cause of death for both men and women. This is the case in the U.S. and worldwide. More than half of all people who die due to heart disease are men.

TRUE

Answer:

Part A: The speed the car should be travelling when leaping the river is approximately 37.948 m/s

Part B: The speed of the car just before it lands is approximately 41.92345 m/s

Explanation:

The parameters of the car attempting leaping the river are;

The height of the car over the river = 18 m

The height of the opposite side of the bridge above the river = 1.8 m

The width of the river, x = 69.0 m

Part A

The time, 't' it would take the car to fall from 18 m above the river to 1.8 m above the river is given as follows;

t = √(2·h/g)

Where;

h = The height of the fall = 18 m - 1.8 m = 16.2 m

g = The acceleration due to gravity = 9.8 m/s²

∴ t = √(2×16.2 m/(9.8 m/s²)) = (9/7)·√2 s

The horizontal speed, 'vₓ', with which the car should be travelling at the time it leaves the road in order just to clear the river and land safely on the opposite side is given as follows;

vₓ = x/t = 69.0 m/((9/7)·√2 s) = (161/6)·√2 m/s ≈ 37.948 m/s

The horizontal speed the car should be travelling when leaping the river, vₓ ≈ 37.948 m/s

Part B;

The vertical velocity of the car is given as follows;

[tex]v_y[/tex]² = [tex]u_y[/tex]² + 2·g·h

∴ [tex]v_y[/tex]² =2·g·h = 2 × 9.8 m/s² × 16.200 m = 317.52m²/s²

[tex]v_y[/tex] = √(317.52 m²/s²) = (63/5)·√2 ≈ 17.819 m/s

The magnitude of the speed of the car, 'v', just before it lands is given using Pythagoras' theorem for resultant vectors as follows;

v = √([tex]v_y[/tex]² + vₓ²) = √(317.52 m²/s² +((161/6)·√2 m/s)²) ≈ 41.92345 m/s

The speed of the car just before it lands, v ≈ 41.92345 m/s.

Answer:

Its D

Explanation:

They are at a 90° angle to each other.

Do good on your tests :]

The answer is D) They are at a 90° angle to each other.

One of the waves which are propagated with the aid of simultaneous periodic versions of electrical and magnetic subject depth and consists of radio waves, infrared, seen mild, ultraviolet, X-rays, and gamma rays.

Radio waves, microwaves, seen light, and x-rays are all examples of electromagnetic waves that range very differently in wavelength. (a) Longer wavelength; (b) shorter wavelength. Electromagnetic waves are produced by means of the motion of electrically charged debris.

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Electrons are the particle pr4esent inside the atom that does not affect the stability of the atom,

The ability of some unstable atoms to emit nuclear radiation spontaneously, typically in the form of alpha or beta particles frequently accompanied by gamma rays, is known as radioactivity.

An overabundance of neutrons or protons can make the nucleus of an atom unstable.

A radioactivity atom will try to become stable by extruding other particles, such as protons or neutrons, or by releasing energy in various ways.

Thus, Electrons are the particle present inside the atom that does not affect the stability of the atom,

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Answer:

A

Explanation:

Because I said so

Answer:

A

Explanation:

i took the test and got it right please mark me ❤️

Answer:

X axis   F=0

Y axis    Fg = - 2.94 j ^

Explanation:

The motion of a ball in air where the air residence is indicated to be negligible can be analyzed using Newton's second law.

We set a reference system, where the x-axis is horizontal and the y-axis vertical.

X axis

There are no forces on this axis, therefore the ball goes at constant speed.

Force is zero

Y axis  

In this axis it is subjected to the acceleration of gravity that creates a force equal to the weight of the body, in a vertical direction.

           Fg = m g

           Fg = 0.3 9.8

           Fg = 2.94 N

           Fg = - 2.94 j ^

the boold are vectors; negative sign indicates that the force eta directed vertically downward

Answer:

The definition of a fulcrum is a pivot point around which a lever turns, or something that plays a central role in or is in the center of a situation or activity.

Answer:

Momentum can be defined as "mass in motion." All objects have mass; so if an object is moving, then it has momentum - it has its mass in motion.  The amount of momentum that an object has is dependent upon two variables: how much stuff is moving and how fast the stuff is moving.

Explanation:

Answer:

Angle of incline is 20.2978°

Explanation:

Given that;

Gravitational acceleration on a planet a = 3.4 m/s²

Gravitational acceleration on Earth g = 9.8 m/s²

Angle of incline = ∅

Mass of the stone = m

Force on the stone along the incline will be;

F = mgSin∅

F = ma

The stone has the same acceleration as that of the gravitational acceleration on the planet.

so

ma = mgSin∅

a = gSin∅

Sin∅ = a / g

we substitute

Sin∅ = (3.4 m/s²) / (9.8 m/s²)

Sin∅ = 0.3469

∅ = Sin⁻¹( 0.3469 )

∅ = 20.2978°

Therefore, Angle of incline is 20.2978°

Answer:

energy= MGH

2*9.8*h=180

h=180/19.6

h=9.32 m

The height of the object above the ground would be equal to 9.18 m.

When an object of mass (m) is moved from infinity to a certain point inside the gravitational influence, the amount of work done in displacing it is stored in the form of potential energy and is known as gravitational potential energy.

The mathematical equation for gravitational potential energy can be written as:

Gravitational potential energy = m⋅g⋅h

Where m is the mass, g is the gravitational acceleration and h is the height above the ground.

Given, the mass of the given object, m = 2 Kg

The gravitational potential energy = 180 J

[tex]GPE = m\times g\times h[/tex]

180 = 2 × 9.8 × h

h = 9.18 m

Therefore, the object should be at a height of 9.18 meters in order to have 180 J of gravitational potential energy.

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Answer:

Roro's total travel time = 6 seconds out of which he rested for 2 seconds

Distance covered by Roro = 8 meters

Explanation:

Given that :

Jojo:

Constant velocity, v = 3m/s

Travel time = h

Roro:

Constant velocity, v = 2m/s

Roro rest for 2 seconds

Travel time = h - 2

Recall:

Distance = speed * time

Distance covered by Jojo:

3 * h = 3h

At this distance ;

Roro's distance = 3h - 10

Using formula :

Roro's distance = 2 * (h - 2)

Hence,

2(h - 2) = 3h - 10

2h - 4 = 3h - 10

2h - 3h = - 10 + 4

-h = - 6

h = 6

Hence, Roro moved for :

h - 2 = 6 - 2 = 4seconds

Distance moved by Roro:

2(h - 2) = 2(6 - 2) = 2(4) = 8 meters

Answer:

Atom - the basic particle of matter

Density - calculated from measurements of mass and volume

Motion - calculated from measurements of distance and time

Energy - can change form and move matter

Matter - the scientific word for stuff

Hope this helps! Please mark brainliest if correct :D

Answer:

Momentum, [tex]p=7.8\times 10^{-5}\ N-m[/tex]

Explanation:

Given that,

Mass of a mosquito, m = 0.000015 kg

Velocity of the mosquito, v = 5.2 m/s

We need to find the momentum of the mosquito. The momentum of an object is given by :

p = mv

Put all the values in the above formula.

[tex]p=0.000015\ kg\times 5.2\ m/s\\\\p=0.000078\ N-m\\\\\text{or}\\\\p=7.8\times 10^{-5}\ N-m[/tex]

So, the momentum of the mosquito is [tex]7.8\times 10^{-5}\ N-m[/tex].

Answer:

Convection

Explanation:

Convection refers to the transfer of heat by the actual movement of the heated molecules from the hot parts to the cooler parts.

Thus, the two diagrams show illustrate transfer of heat by the movement of molecules of a fluid.

This mode of heat transfer is known as convection. It is the concept illustrated by both diagrams.

Answer:

PE = (|accepted value – experimental value| \ accepted value) x 100%

Explanation:

Answer:

(a) 1.21 m/s² (b) 1.75 m/s²

Explanation:

The initial speed of the car, u = 17.8 m/s

Case 1.

Final speed of the car, v = 23.5 m/s

Time, t = 4.68-s

Acceleration = rate of change of velocity

[tex]a=\dfrac{23.5 -17.8 }{4.68}\\\\a=1.21\ m/s^2[/tex]

Case 2.

Final speed of the car, v = 15.3 m/s

[tex]a=\dfrac{23.5 -15.3}{4.68}\\\\a=1.75\ m/s^2[/tex]

Hence, this is the required solution.

Acceleration is the change in the velocity of a body with time.

The term acceleration is the change in the velocity of a body with time. We have to find the acceleration in two separate cases;

Case 1;

a = -(23.5 m/s - 17.8 m/s)/4.68-s

a = -1.2 m/s^2

Case 2;

a = -(15.3 m/s - 17.8 m/s)/4.68-s

a = 0.53 ms-2

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Answer:

Option B. 300 m/s².

Explanation:

From the question given above, the following data were obtained:

Mass (m) of student = 100 Kg

Mass (m) of ball = 1.5 Kg

Force (F) applied on the ball = 450 N

Acceleration (a) of ball =?

From Newton's 2nd law,

F = ma

Where

F => Force applied

m => mass of object

a => acceleration of object.

With the above formula, we can obtain the acceleration of the ball as follow:

Mass (m) of ball = 1.5 Kg

Force (F) applied on the ball = 450 N

Acceleration (a) of ball =?

F = ma

450 = 1.5 × a

Divide both side by 1.5

a = 450 / 1.5

a = 300 m/s²

Therefore, the acceleration of the ball is 300 m/s²

Answer:

1.40 m/s^2

Explanation:

Given data

Velocity= 17.4 m/s

time= 12.4 seconds

We want to find the acceleration of the rock

We know that

acceleration = velocity/time

Substitute

acceleration= 17.4/12.4

acceleration=1.40 m/s^2

Hence the acceleration is 1.40 m/s^2

Answer:

(a) The negative charge on one of the charges is -8.79630245 × 10⁻⁷C

(b) The positive charge on one of the other charges is 8.79630245 × 10⁻⁷C

Explanation:

The given parameters are;

The force of attraction between the two spheres = 0.0988 N

The distance between their centers = 44.5 cm = 0.445 m

Therefore, we have;

[tex]F = \dfrac{k \cdot q_1 \cdot q_2}{d^2}[/tex]

Therefore, we have;

[tex]0.0988 \ N = -\dfrac{8.99 \times 10^9 N\cdot m^2 \cdot C^{-2}\cdot q_1 \cdot q_2}{(0.445 \ m)^2}[/tex]

Therefore, we have;

q₁·q₂ = -0.0988 N × (0.445 m)²/(8.99 × 10⁹ N·m²·C⁻²) = -2.17629255 × 10⁻¹² C²

q₁·q₂ = -2.17629255 × 10⁻¹² C²...(1)

When the two charges are connected, we get;

[tex]F_2 = \dfrac{k \cdot \left (\dfrac{q_1 + q_2}{2} \right) ^2}{d^2}[/tex]

Therefore, we have;

[tex]q_1 + q_2 = \sqrt{\dfrac{4 \cdot F_2 \cdot d^2}{k} }[/tex]

[tex]q_1 + q_2 = \sqrt{\dfrac{4 \times 0.0276 \ N \times(0.445 \ m)^2}{8.99 \times 10^9 N\cdot m^2 \cdot C^{-2}} } = 1.59446902743 \times 10^{-6} \ C[/tex]

q₁ + q₂ = 1.59446902743 × 10⁻⁶ C...(2)

From, equation (2), we have;

q₁ = 1.59446902743 × 10⁻⁶ C -  q₂

Plugging in the value of q₁ in equation (1) givens;

q₁·q₂ = -2.17629255 × 10⁻¹²

Therefore, we have;

(1.59446902743 × 10⁻⁶ -  q₂) × q₂ = -2.17629255 × 10⁻¹²

Which gives;

-q₂² + 1.59446902743 × 10⁻⁶·q₂+2.17629255 × 10⁻¹² = 0

Solving, with a graphing calculator, we get;

q₂ = 2.4741×10⁻⁶ C, or -8.79630245 × 10⁻⁷C

q₁ = 8.79630245 × 10⁻⁷C or -2.4741×10⁻⁶ C

Therefore, we have;

(a) The negative charge on one of the charges = -8.79630245 × 10⁻⁷C

(b) The positive charge on one of the other charges = 8.79630245 × 10⁻⁷C

Answer:

68600Nm

Explanation:

Given that:

Lenght, L = 7

Width, W = 2

Depth, d = 1

Triangle = with height 1 meters, and base, on top, of length 2 meters

Area of triangle = 0.5 * base * height

Area of triangle = 0.5 * 2 * 1 = 1m²

Volume = area * length

Volume = 1m² * 7m

Volume = 7m³

Weight of water = Volume * density * g

g = acceleration due to gravity

Density of water , d = 1000kg/m³

Weight = 7m³ * 1000kg/m³ * 9.8m/s²

Weight = 68,600 Kgm/s² = 68600 N

Workdone = Force * distance = weight * depth

Workdone = 68600N * 1m

Workdone = 68600Nm