Answer:
6.1 × 10^9 Nm-1
Explanation:
The electric field is given by
E= Kq/d^2
Where;
K= Coulombs constant = 9.0 × 10^9 C
q = magnitude of charge = 1.62×10−6 C
d = distance of separation = 1.53 mm = 1.55 × 10^-3 m
E= 9.0 × 10^9 × 1.62×10−6/(1.55 × 10^-3 )^2
E= 14.58 × 10^3/2.4 × 10^-6
E= 6.1 × 10^9 Nm-1
galileo was the first scientist to do which of the following?
A 40kg mass is pulled along a surface by a horizontal force of 300N. Friction on the mass is 30N. What is the acceleration of the mass???
Answer:
6.75 m/s²
Explanation:
The following data were obtained from the question:
Mass (m) of object = 40 Kg
Force applied (Fₐ) = 300 N
Force of friction (Fբ) = 30 N
Acceleration (a) =?
Next, we shall determine the net force acting on the mass. This can be obtained as follow:
Force applied (Fₐ) = 300 N
Force of friction (Fբ) = 30 N
Net force (Fₙ) =?
Fₙ = Fₐ – Fբ
Fₙ = 300 – 30
Fₙ = 270 N
Thus, the net force acting on the mass is 270 N.
Finally, we shall determine acceleration of the mass. This can be obtained as follow:
Mass (m) of object = 40 Kg
Net force (Fₙ) = 270 N
Acceleration (a) =?
Net force = mass × acceleration
Fₙ = m × a
270 = 40 × a
Divide both side by 40
a = 270 / 40
a = 6.75 m/s²
Therefore, the acceleration of the mass is 6.75 m/s²
A drum is struck first with little energy. The drum is then struck with a lot of energy. Which sound will be louder? Why?
Answer:
The drum struck with a lot of energy would be louder than the drum struck with little energy because there is a harder impact on it
Explanation:
What is the average power developed by a motor as it lifts a 400.-kilogram mass at constant speed through a vertical distance of 10.0 meters in 8.0 seconds
Answer:
The average power developed by a motor is 4905 Watts.
Explanation:
The average power is given by:
[tex] P = \frac{W}{t} [/tex]
Where:
W: is the work
t: is the time = 8.0 s
First, let's find the work:
[tex] W = F*d [/tex]
Where:
F: is the force
d: is the displacement = 10.0 m
The force is in the vertical motion, and since the movement of the mass is at constant speed the force is:
[tex] F = mg = 400 kg*9.81 m/s^{2} = 3924 N [/tex]
Hence, the average power is:
[tex] P = \frac{F*d}{t} = \frac{3924 N*10.0 m}{8.0 s} = 4905 J/s = 4905 W [/tex]
Therefore, the average power developed by a motor is 4905 Watts.
I hope it helps you!
The average power developed by a motor as it lifts the mass is 4,900 W.
The given parameters:
mass lifted, m = 400 kgdistance traveled, d = 10 mtime of motion, t = 8.0 sThe average power developed by a motor as it lifts the mass is calculated as follows;
[tex]P = \frac{E}{t} \\\\P = \frac{mgh}{t} \\\\P = \frac{400 \times 9.8 \times 10}{8} \\\\P = 4,900 \ J/s[/tex]
Thus, the average power developed by a motor as it lifts the mass is 4,900 W.
Learn more about average power here:https://brainly.com/question/19415290
c. Describe how to use right-hand rules to relate the directions of magnetic fields, currents, moving charges, and forces. (1 point) pls some one help me
Answer:
If you point your pointer finger in the direction the positive charge is moving, and then your middle finger in the direction of the magnetic field, your thumb points in the direction of the magnetic force pushing on the moving charge.
Explanation:
it’s right
An adjustable tennis ball launcher launches tennis balls into the air from level ground and that return to level ground. The tennis balls are first launched with an initial velocity (vi) of 8.0 meters per second at an angle of 50° above the horizontal. The ball has an initial horizontal velocity of 5.1 meters per second. [Neglect friction.]
Calculate the vertical component of the ball’s initial velocity.
Calculate the maximum height reached by the ball.
Calculate the time elapsed to reach its maximum height.
Calculate the total horizontal distance travelled during its flight.
Answer:
Explanation:
I just need points
A football player kicks a ball with a mass of .55 kg. The average acceleration of the
football was 14.9 m/s2. How much force did the kicker supply to the football?
A.8.2 m/s2
B.)8.2 N
C.)35.24 N
D.)35.24 m/s2
Answer:
8.2N
Explanation:
I took the test and got it right :)
A tired squirrel (mass of approximately 1 kg) does push-ups by applying a force to elevate its center-of-mass by 5 cm in order to do a mere 0.50 Joule of work. If the tired squirrel does all this work in 2 seconds, then determine its power.
Answer:
Power = 0.25 Watts
Explanation:
Given:
Work done = 0.50 Joule of work
Time taken = 2.0 second
Find:
Power
Computation:
Power = Work done / Time taken
Power = 0.50 J / 2
Power = 0.25 Watts
If the tired squirrel does all this work in 2 seconds with work of 0.5 J the power is 0.25 Watts.
Given:
Mass, m = 1 kg
Work, W = 0.5 J
Time, t = 2 s
The concept of power, which measures the pace at which work is done or the rate at which energy is transmitted or converted, is crucial to physics. It measures how quickly energy is produced or utilized in a system, to put it simply. In the International System of Units (SI), power is a scalar quantity and is measured in watts (W).
The power is given by:
Power = Work ÷ Time
P = 0.50 Joules ÷ 2 seconds
P = 0.25 Watts
Hence, the power exerted by the tired squirrel is 0.25 Watts.
To learn more about Power, here:
https://brainly.com/question/13097380
#SPJ6
A redecor travelling of 94 m/s s lows at a anstant
race to a velocity of 22m Is over Ils How
ar dies it move during this time?
Answer:
638 m.
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 94 m/s
Final velocity (v) = 22 m/s
Time (t) = 11 s
Distance (s) =?
We can obtain the distance travelled by using the following formula:
s = (u + v) t /2
s = (94 + 22) × 11 /2
s = 116 × 11 /2
s = 1276 /2
s = 638 m
Thus, the distance travelled is 638 m.
what is the force on a 1000 kg elevator that is falling freely at 9.8m/s2
Answer:
Since it is falling freely, the only force on it is its weight, w. w = m ⋅ g = 1000kg ⋅ 9.8m s2 = 9800N To draw a Free Body Diagram, draw an elevator cage (I am sure you would get lots of points for drawing it with intricate detail) with a downward force of 9800 N. I hope this helps,
Explanation:
Explanation:
❀ [tex] \underline {{\underline{ \text{Given} }}}: [/tex]
Mass ( m ) = 1000 kgAcceleration ( a ) = 9.8 m/s²❀ [tex] \underline{ \underline{ \text{To \: find}}} : [/tex]
Force ( F )❀ [tex] \underline{ \underline{ \text{Solution}}} : [/tex]
[tex] \boxed{ \sf{force = mass \times acceleration}}[/tex]
Plug the known values :
⟶[tex] \sf{1000 \times 9.8}[/tex]
⟶ [tex] \sf{9800 \: N}[/tex]
[tex] \red{\boxed{ \boxed{ \tt{⟿ \: Our \: final \: answer : 9800 \: N}}}}[/tex]
Hope I helped !♡
Have a wonderful day / night ! ツ
▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
This is about net force
So the question is what is the net force on the rope? Be sure to include units. So the answer has to be like this ex: 15N left. This isn’t the answer for the first one. And then say which team won so pls help me. Please please help
Answer:
(a) [tex]Net\ Force = 2N[/tex] towards the right
(b) The green team wins
Explanation:
Given
[tex]Blue = 40N[/tex]
[tex]Green = 42N[/tex]
Solving (a): The net force
Because the force in the opposite directions, the net force is the subtraction of the smaller force from the bigger one.
So, we have:
[tex]Net\ Force = Green - Blue[/tex]
Substitute values for Blue and Green
[tex]Net\ Force = 42N- 40N[/tex]
[tex]Net\ Force = 2N[/tex]
Solving (b): Who wins the round
The body will move toward the Green Team because the force larger [tex](42N > 40N)[/tex]
So, the green team will win
How is a controlled variable different from a responding variable?
A. A controlled variable changes due to changes in the respondin
variable during the experiment.
B. A controlled variable stays the same due to changes in the
responding variable during the experiment.
C. A controlled variable changes throughout an experiment, but a
responding variable stays the same.
D. A controlled variable stays the same throughout an experiment,
but a responding variable changes.
spaceship of mass m travels from the Earth to the Moon along a line that passes through the center of the Earth and the center of the Moon. (a) At what distance from the center of the Earth is the force due to the Earth twice the magnitude of the force due to the Moon
Answer:
the correct result is r = 3.71 10⁸ m
Explanation:
For this exercise we will use the law of universal gravitation
F = [tex]- \frac{m_{1} m_{2} }{r^2}[/tex]
We call the masses of the Earth M, the masses of the moon m and the masses of the rocket m ', let's set a reference system in the center of the Earth, the distance from the Earth to the moon is d = 3.84 108 m
rocket force -Earth
F₁ = - \frac{m' M }{r^2}
rocket force - Moon
F₂ = - \frac{m' m }{(d-r)^2}
in the problem ask for what point the force has the relation
2 F₁ = F₂
let's substitute
2 [tex]2 \frac{M}{r^2} = \frac{m}{(d-r)^2}[/tex]
(d-r) ² = [tex]\frac{m}{2M}[/tex] r²
d² - 2rd + r² = \frac{m}{2M} r²
r² (1 -\frac{m}{2M}) - 2rd + d² = 0
Let's solve this quadratic equation to find the distance r, let's call
a = 1 - \frac{m}{2M}
a = 1 - [tex]\frac{7.36 10^{22} }{2 \ 5398 10^{24}}[/tex] = 1 - 6.15 10⁻³
a = 0.99385
a r² - 2d r + d² = 0
r = [tex]\frac {2d \frac{+}{-} \sqrt{4d^2 - 4 a d^2}} {2a}[/tex]
r = [2d ± 2d [tex]\sqrt{1-a}[/tex]] / 2a
r = [tex]\frac{d}{a}[/tex] (1 ± √ (1.65 10⁻³)) = [tex]\frac{d}{a}[/tex] (1 ± 0.04)
r₁ = \frac{d}{a} 1.04
r₂ = \frac{d}{a} 0.96
let's calculate
r₁ = [tex]\frac{3.84 10^8}{0.99385}[/tex] 1.04
r₁ = 401.8 10⁸ m
r₂ = \frac{3.84 10^8}{0.99385} 0.96
r₂ = 3.71 10⁸ m
therefore the correct result is r = 3.71 10⁸ m
Explain why there are missing harmonics for standing waves on a string with a loose (free) end. (Hint: Is there a pattern to how much of a wavelength fits between the ends of the string with a loose end
Answer:
It is because there are a odd number of wavelengths fitting onto the string
Explanation:
The general formula for the harmonics on a string loose at one end is f = nv/2L where n = odd integer, v = speed of wave in string and L = length of string.
For a string loose at one end, there are a odd number of wavelengths which can fit onto the string. Since this is the case, we only have harmonics of odd numbers and thus we have even number harmonics missing.
total potential and kinetic energy of an object.
you have to finish the word
__c____c__ pls help
Answer:
The Total Mechanical Energy
As already mentioned, the mechanical energy of an object can be the result of its motion (i.e., kinetic energy) and/or the result of its stored energy of position (i.e., potential energy). The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.
Explanation:
On moving a charge of 20 coulombs by 2 cm, 2J of work is done then the potential difference between the points is
Answer:
The potential difference between the points is: 0.1 V
Explanation:
Given
Work W = 2JCharge q₀ = 20 CTo determine
The potential difference between the points is
We can use the formula to determine the potential difference between the points
[tex]V_A-V_B=\frac{W}{q_0}[/tex]
where W is done by moving charge q₀ from point A and point B
substituting W = 2J, and q₀ = 20 C
[tex]=\frac{2}{20}[/tex]
[tex]= 0.1[/tex] V
Therefore, the potential difference between the points is: 0.1 V
When energy changes form, energy is...
A) lost.
B) created.
C) not lost or created.
Answer:
C
Explanation:
Energy is neither created or destroyed, but it can change forms...
Length of table is 1.0 metre, 1.00 metre and 1.000 metre. Which one is more accurate?
Answer:
1.000 metre
Explanation:
I hope it's helpful
The matter between stars is called?
A. asteroid belt
B. space
C. interstellar medium
D. Kuiper Belt
Answer:
your answer is C
Explanation:
A motorcycle skids to a stop on a road.
What is the equal and opposite force for the force of the motorcycle's friction pushing on the road as
described by Newton's third law?
Choose 1 answer:
Normal force of the road pushing up on the motorcycle
Earth's force of gravity pulling down on the motorcycle
Motorcycle's force of gravity pulling up on the Earth
Friction of the road on the motorcycle in the opposite direction
Answer:
Friction of the road on the motorcycle in the opposite direction
Explanation:
Khanacademy
what should be done in order to increase the gravitational force between two objects? Decrease the mass of both of the objects. Decrease the mass of one of the objects. Decrease the distance between the two objects. Increase the distance between the two objects.
Answer:
Decrease the distance between the two objects.
Explanation:
The force (F) of attraction between two masses (M₁ and M₂) separated by a distance (r) is given by:
F = GM₁M₂ / r²
NOTE: G is the gravitational force constant.
From the equation:
F = GM₁M₂ / r²
We can say that the force is directly proportional to the masses of the object and inversely proportional to the square of the distance between them. This implies that an increase in any of the masses will increase the force of attraction and likewise, a decrease in any of the masses will lead to a decrease in the force of attraction.
Also, an increase in the distance between the masses will result in a decrease in the force of attraction and a decrease in the distance between the masses, will result in an increase in the force of attraction.
Considering the question given above,
To increase the gravitational force between the two objects, we must decrease the distance between the two objects as explained above.
Answer:
Decrease the distance between the two objects.
Explanation:
hit me wit that brainliest, please and thank you
Which property describes if a mineral breaks down into flat pieces? this is science
A Cleavage
B Color
C Fracture
D Luster
A different scaffold that weighs 400 N supports two painters, one 500 N and the other 400 N. The reading in the left scale is 800 N. What is the reading in the right-hand scale
Answer:
500 N
Explanation:
Given that,
The upward force is 800 N and the downward forces are 400 N, 500 N, 400 N.
At equilibrium, the upward forces will become equal to the downward forces. Let the reading in the right hand scale.
x + 800 = 400 + 500 + 400
x + 800 = 1300
x = 1300 - 800
= 500 N
So, the reading in the right hand scale is 500 N.
the mass of the earth is 6×10²⁴ kg and the it's radius is 6400 km . what is the mass of a man weighing 977 N in spring balance ? { G= 6.67×10-¹¹ }
Answer:
Mass of the man = 100 kg
Explanation:
Given that,
Mass of the Earth, M = 6×10²⁴ kg
The radius of the Earth, r = 6400 km
Force on man, F = 977 N
We need to find the mass of the man. Let the mass of the man be m. The gravitational force acting between two objects is given by :
[tex]F=G\dfrac{mM}{r^2}\\\\m=\dfrac{Fr^2}{GM}\\\\m=\dfrac{977\times (6400\times 10^3)^2}{6.67\times 10^{-11}\times 6\times 10^{24}}\\\\m=99.99\ kg[/tex]
or
m = 100 kg
So, the mass of the man is 100 kg.
Two masses are precisely 1 m apart from each other. The gravitational force each exerts on the other is exactly 1 N. If the masses are identical, what is each mass?
Answer:
122444 Kg
Explanation:
Using the formula for gravitational force;
F= Gm1m2/r^2
Given that
G = constant of gravitation = 6.67 × 10−11 newton-metre2-kilogram−2.
m1 and m2 = the masses
r= distance of separation
Note that the question specifically mentioned that the masses are identical
so m1=m2 = m^2
F= Gm^2/r^2
Fr^2 = Gm^2
m^2 = Fr^2/G
m^2 = 1 × 1^2/6.67 × 10−11:
m =√ 6.67 × 10−11
m= 122444 Kg
Scenario
Andrea is driving her car and getting on Interstate 70. She is traveling 10 m/s at the beginning of the
highway on-ramp and accelerates to 30 m/s at the end of the on-ramp. It takes her 4 seconds to get to
full speed
What is Andrea's acceleration to get on the on-ramp ?
Answer:
5m/s/s
Explanation:
The units for velocity is m/s.
The units for acceleration is m/s/s
So, Determine the change in velocity and divide it by the time that change took place.
(30m/s - 10m/s)/4s = 20m/s/(4s) = 5m/s/s
An 82 kg man drops from rest on a diving board 3.0 m above the surface of the water. What is his speed when he hits the water? On hitting the water, it takes him 0.55 s to slow down to a stop. Calculate the net force on him inside the water that brings him to a stop. What are the forces on him when he slows down inside the water?
Answer:1.1x10^3N upward
Explanation:
Brendan Gan is about to drive to Kuala Lumpur from Johor Bahru. The distance from Johor Bahru to Kuala Lumpur is 330 km. Brendan's car can drive 60 miles using 1 gallon of petrol The current petrol costs are RM1.85 per liter.
Calculate the total petrol cost for Brendan to drive from Johor Bahru to Kuala Lumpur.
Use: 1 gallon = 4.5 liters
1 mile = 1.61 km
Round up answer to 2 decimal places (8 marks)
Answer:
The total cost in petrol will be: RM 28.43
Explanation:
The distance to be covered is: 330 km
The car does 60 mi per 1 gallon
so we convert this into km per liter as
60 mi/gal = 60 * 1.61 / 4.5 = 21.47 km/liter
Then, if 1 liter is needed to cover 21.47 km, then to cover 330 km one would need:
330 / 21.47 liters = 15.37 liters
Since each liter costs RM 1.85, then the cost in gas will be:
1.85 * 15.37 = RM 28.43
Sunita uses a lever of length 5m to lift a piece of stone weighing 1000N.
If the distance of the load from the fulcrum is Im, how much effort does she
apply to lift the piece of stone
Answer:
F = 250 [N] (Force exerted by Sunita)
Explanation:
First we must understand the use of the lever, in the attached picture we see that it is fulcrum and other features.
The moment that the load exerts with respect to the fulcrum should be calculated, as the distance is 1 [m].
[tex]M=F*d\\M=1000*1\\M=1000[N*m][/tex]
Now Sunita must exert the same moment using the remaining distance (4 [m]).
[tex]1000=F_{sunita}*4\\F_{sunita}=1000/4\\F_{sunita}=250 [N][/tex]
Is it possible to stand backwards on a flight of stairs?
Answer:
yes
Explanation:
if your destination is on the top floor, but you are facing towards the bottom floor, you are facing the wrong way. It's all relative. Honestly, I hate this question, because then it turns into, is it possible to go backwards anywhere. Backwards and forwards, right and left, it's all relative to which way you are facing and where you want to go. If something is on the left and you turn 180 degrees, then that thing is on the right. If you are going forward towards your house and you turn around, you are now going backwards, relative to your house. But if your perspective is relative to that tree in the opposite direction of your house, you are now facing the right way. See, it's all relative to where you are going.