what are three considerations diamond discusses as he ponders yali’s question in guns, germs, and steel

Apparent magnitude refers to the properties which best measures a star's brightness and is denoted as option D.

This is a term commonly used in astronomical system which talks about the brightness of a star based on its composition such as hydrogen and helium.

it is also determined by how far or bright it is from the planet such as earth when they are viewed by individuals which is regarded as the property in which astronomers use to define its brightness.

This is therefore the reason why apparent magnitude was chosen as the correct choice.

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Answer:

A: Absolute magnitude

Explanation:

I Just did it and the correct answer is ABSOLUTE MAGNITUDE

Answer:

(3504 m/s, 66°)

The final velocity of the missile is approximately 3504 m/s at an angle of 66 degrees.

Explanation:

We are going to use the horizontal and vertical components of this object since it is in projectile motion.

We are given the initial velocity of the missile; 1350 m/s at an angle of 25 degrees. We are also given the displacement in the x-direction: 23,500 meters at an angle of 55 degrees. The total time of this projectile in motion is 10.20 seconds.

Using this information, we can break up the motion of the projectile into its horizontal and vertical components and solve for the unknown variables [tex]a[/tex] and [tex]v_f[/tex].

List out the known variables:

Since we have initial velocity, displacement, and time, we can use one of the kinematic equations for constant acceleration that contains these variables, including acceleration, and solve for a:

We are solving for acceleration in the x-direction, so this equation should be in terms of the x-direction:

Let's break up the displacement into its horizontal (x) component:

Let's break up the initial velocity into its horizontal component:

Plug these values into the equation and 10.20 seconds for t.

Solve for [tex]a_x[/tex].

The acceleration in the x-direction is about 19.21 m/s².

Now, we can use this acceleration and solve for the final velocity in the x-direction using this constant acceleration kinematic equation:

Use this equation in terms of the x-direction:

Plug the known values into the equation and solve for [tex](v_f)_x[/tex].

The final velocity in the x-direction is about 1419.43 m/s.

This process will be the same as solving for acceleration and final velocity in the x-direction, except this time we will be using the vertical (y) components.

Vertical component of initial velocity:

Vertical component of displacement:

Plug known values into the equation and solve for [tex]a_y[/tex].

The acceleration in the y-direction is about 258.18 m/s².

Now let's use the same equation we used previously to solve for the final velocity in the y-direction.

Use this equation in terms of the y-direction:

Plug known values into the equation and solve for [tex](v_f)_y[/tex].

The final velocity in the y-direction is about 3203.99 m/s.

The magnitude of the final velocity is the square root of the final velocity in the horizontal and vertical directions squared and added together.

Plug the final velocity in the x and y-directions into the equation.

The magnitude of the final velocity is about 3504 m/s. We can solve for the direction of the final velocity by using arccos to find the angle that is formed with the x-axis.

Plug in the x-component of the initial velocity and the magnitude of the final velocity of the projectile into the equation.

The direction of the final velocity is about 66 degrees.

Answer:

A. higher, lower

Explanation:

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Answer:

12500W

Explanation:

Given parameters:

Work done  = 250000J

Time taken  = 20s

Unknown:

Power of the crane = ?

Solution:

Power is the defined as the rate at which work is being done;

  Mathematically;

        Power = [tex]\frac{work done}{time }[/tex]

 insert the parameters and solve;

      Power  = [tex]\frac{250000}{20}[/tex]   = 12500W

The velocity of Jay after five minutes is 1 Km/min. The greatest speed occurred at 45 mins.

The velocity time graph is a representation of the movement of a body a body from one point to another. It is the plot of the velocity on the vertical axis against the time on the horizontal axis. Ideally this graph would be divided into three portions;

We can be able to read off from the graph, the instantaneous velocity of the object at any time. This could be done by tracing the time against the velocity axis and extrapolating according from the graph as shown.

Recall that the acceleration of the body is obtained as the slope of the velocity time graph at any point and the acceleration could be uniform or non uniform as judged from the velocity time graph.

Having said all these, it is clear that the velocity of Jay after five minutes is 1 Km/min.

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For this we have the hidrostatic equation:

[tex]\boxed{P = \rho gh}[/tex]

Being:

P = Pressure

ρ = Density of liquid (water) = 1000 kg/m

g = Gravity = 9,81 m/s²

h = Height = 4 m

Replacing acording formula:

[tex]\boxed{P = 1000 \ kg/m ^{3} * 9,81 \ m/s^{2} * 4 \ m}[/tex]

Resolving:

[tex]\boxed{P = 39240 \ Pa}[/tex]

Result:

The pression at the bottom is 39240 Pa.

Force is measured in Newton ( kg.m. /s²)

Answer:

a) 800 J

Explanation:

Work is said to be done when a force induces movement over a distance in an object. The amount of work done (W) is calculated by multiplying the force by the distance traveled.

That is;

W = F × d

Where;

W = work done (J or N/m)

F = force (N)

d = distance (m)

In the information given in this question, F = 40N, d = 20m

Hence,

Work done = 40N × 20m

Work done = 800N/m or 800 J

Answer:

Gravitational potential energy and Elastic potential energy

Explanation:

The two types of potential energy the springs described in the question have are Gravitational potential energy and Elastic potential energy.

Firstly, it must be noted that potential energy is the energy stored/present in a stationary (non-moving) object (or object at rest).

Gravitational potential energy is the potential energy as a result of the vertical position of an object due to force of gravity acting to pull it down. The gravitational potential energy is as a result of the springs been attached to the ceiling which causes the force of gravity to want to pull it down. This gravitational force is further increased when the swing is attached causing the weight of swing to act in the direction of the force of gravity.

Elastic potential energy is the potential energy stored in an elastic object or energy stored in an object that can be stretched or compressed. This is the energy that would always be found in a spring, so when the springs have been attached to the ceiling and the swing has been fastened to them, there elastic potential energy would reduce as a result of the kinetic energy that must have been used to stretch the springs.

Answer:

1) The Speed of the plane is approximately 39.596 m/s

2) Please find attached the required velocity and acceleration graphs

Explanation:

1) The height at which the plane was flying, h = 500 m

The location the bottle lands from the initial dropping point = 400 m

The time it takes the bottle to land is given by the equation for free fall as follows;

h = 1/2·g·t²

Where;

g = The acceleration due to gravity = 9.8 m/s²

t = √(h/(1/2·g) = √(500/(1/2×9.8) ≈ 10.102

The Speed of the plane = The horizontal velocity of the bottle = 400/10.102 ≈ 39.596

The Speed of the plane ≈ 39.596 m/s

2) Please find attached the velocity graph for the vertical and horizontal velocities of the bottle and the acceleration graph for the vertical motion of the bottle, created with Microsoft Excel

Answer:

Gravity, or gravitation, is a natural phenomenon by which all things with mass or energy—including planets, stars, galaxies, and even light—are brought toward one another. On Earth, gravity gives weight to physical objects, and the Moon's gravity causes the ocean tides.

(a) The height reached by cat A is 2.5 m.

(b) The speed of cat A before it hits the ground is 36.4 m/s.

(c) The speed of cat B before it hits the ground is 22.39 m/s.

(d) The time spent in air by cat A than cat B is 1.43 seconds.

The time of motion of cat A is calculated as follows;

h = vt - ¹/₂gt

-23 = 7t - 4.9t²

4.9t² - 7t - 23 = 0

solve the quadratic equation using formula method;

a = 4.9, b = -7, c = - 23

t = 3.0 seconds

The time of motion of cat B is calculated as follows;

h = vt - ¹/₂gt

23 = 7t + 4.9t²

4.9t² + 7t - 23 = 0

solve the quadratic equation using formula method;

a = 4.9, b = 7, c = -23

t = 1.57 seconds

h = u²/2g

h = (7²)/(2 x 9.8)

h = 2.5 m

v = u + gt

v = 7  + 3(9.8)

v = 36.4 m/s

v = u + gt

v = 7  + 1.57(9.8)

v = 22.39 m/s

Time difference = 3 s - 1.57 s = 1.43 seconds

Thus, the height reached by cat A is 2.5 m.

The speed of cat A before it hits the ground is 36.4 m/s.

The speed of cat B before it hits the ground is 22.39 m/s.

The time spent in air by cat A than cat B is 1.43 seconds.

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The tangential velocity is proportional to the length of the rope hence when the length of the rope is doubled, the tangential velocity becomes two times greater.

We know that the tangential velocity of an object moving along a circular path depends on its radius and it's angular velocity.

In this case, we have been told that the motion of the object is uniform meaning that the angular velocity is held constant and the length of the rope which is the radius was doubled.

Since the tangential velocity is directly proportional to the length of the rope, the tangential velocity will be two times greater when the length of the rope is doubled.

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Answer:

Electrical energy

Explanation:

electrical energy Essentials. A battery is a device that stores chemical energy and converts it to electrical energy. The chemical reactions in a battery involve the flow of electrons from one material (electrode) to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work.

There exists a point on the path the Courtney will cross at exactly the same time of day on both days.

Given that Courtney first takes his usual path and travel between 7.a.m. and 7.p.m.

Next morning, she travel backs between the time 7 a.m. and 7 p.m.

The time taken by Courtney on each day = 12 hours

12/2 = 6 hours.

6 hours from 7 a.m. is 1 pm. So this 6 hours will divide the total journey into two equal parts.

At 1 p.m. on first day, she will be in the middle of her way from home to Mount Elbert.

At 1.p.m. of the second day also, she will be in the middle of her way from Mount Elbert to her home.

So she cross the exact middle point of the path at exactly 1.pm on both days.

Intermediate Value theorem states this result. Since the distance travelled is a continuous function, there is a particular value of time corresponding to the exact same point crossed by Courtney on both days.

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Answer:

Moon's Orbit

Explanation:

Answer:

saaaaaaaaaaaay it please

Explanation:

Hello!

C. KE ≈ 9120.105 J

D. m = 151.45 kg

Question C:

Calculate kinetic energy using the formula:

[tex]KE = \frac{1}{2}mv^{2}[/tex]

Substitute in the given mass. We have to convert kilometers to meters in order to solve.

[tex]\frac{42km}{1hr} * \frac{1hr}{3600sec} *\frac{1000m}{1km} = 11.67 m/s[/tex]

Use the equation above:

KE = 1/2(1563)(11.67)

KE ≈ 9120.105 J

Question D:

Plug in the given Kinetic Energy and velocity to solve. Convert kilometers/hour to meters/second:

[tex]\frac{7km}{1hr} * \frac{1hr}{3600sec} *\frac{1000m}{1km} = 1.94 m/s[/tex]

[tex]KE = \frac{1}{2}mv^{2}[/tex]

285 = 1/2(m)(1.94²)

570 = (1.94²)m

151.45kg = m

Answer:

D. Time t = 1 [s]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}=v_{o}-g*t[/tex]

where:

Vf = final velocity = 0 (when the ball reaches the maximum height its elevation won't be increased since the velocity is zero)

vi = initial velocity = 10 [m/s]

g = gravity acceleration = 10 [m/s²]

t = time [s]

Now replacing:

[tex]0 = 10-10*t\\10 = 10*t\\t = 1 [s][/tex]

Phase conductors 6 awg and smaller are not permitted to be re-identified as equipment ground conductors using green paint, tape, or other effective means.

Depending on the type of system offered, the grounded conductor of a service is typically a neutral conductor, though it can also be a phase conductor. A grounded phase conductor and no grounded neutral conductor are present in a corner-grounded delta system, for instance. The unbalanced load is returned to the source by the neutral. The conductor that has been purposefully grounded is the grounded conductor. The neutral is the conductor that is purposefully grounded in the majority of wiring systems used in industrial facilities, businesses, and homes. For safety reasons, the grounding conductor is employed. The grounding wire does not carry current under typical circumstances. The grounding wire offers a low resistance channel for the current in a fault situation.

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Answer:

the answer would be D because not only is it going up but it's going up as an angle

Answer:

5.9 x 10⁻⁷m

Explanation:

Given parameters:

Frequency = 5.085 x 10¹⁴Hz

Speed of light  = 3.0 x 10⁸m/s

Unknown:

Wavelength of the orange light  = ?

Solution:

The wavelength can be derived using the expression below;

            wavelength  = [tex]\frac{v}{f}[/tex]

v is the speed of light

f is the frequency

            wavelength  = [tex]\frac{3 x 10^{8} }{5.085 x 10^{14} }[/tex]   = 5.9 x 10⁻⁷m

The electric flux is 2chω² where the k^ term was eliminated since k. k^ =0

The electric force per unit charge is referred to as the electric field. It is assumed that the field's direction corresponds to the force it would apply to a positive test charge. From a positive point charge, the electric field radiates outward, and from a negative point charge, it radiates in.

We are given an electric field in the general form

E→ =ay i^+bz j^+cx k^

In the xy plane z=0 so that the electric field reduces to

E→ =ay i^+cx k^

To obtain the flux, we integrate

ϕ E=∫ E→⋅d A→ =∫ (ay i^ +cx k^) ⋅k^

dAϕE=ch∫

x=0w

​xdx=2chω²

where the k^ term was eliminated since k. k^ =0

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Answer:c

Explanation:

The the direction of magnetic field is perpendicular to the velocity of proton and is directed towards the + z axis.

We have a proton entering a uniform magnetic field which is in a direction perpendicular to the proton's velocity.

We have to determine the direction of magnetic field.

The magnitude of force on the charged particle moving in a uniform magnetic field is given by -

F = qvB sinθ

According to the question, we have -

Entering Velocity (v) = 20 i  m/s.

Magnetic field intensity (B) = 0.3 T.

Leaving velocity (u) = - 20 j  m/s.

Now -

F = q |v| |B| sinθ

F = 1.6 x [tex]10^{-19}[/tex] x 20 x 0.3 x sin(90)

F = 9.6 x  [tex]10^{-19}[/tex]  Newton.

Now, using the Fleming's left hand rule, the the direction of magnetic field is perpendicular to the velocity of proton and is directed towards the + z axis. The force is towards the '- y' axis. Therefore -

B = + 0.3 k

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Answer:

10

Explanation:

would

Distanced travelled by a ship with a constant velocity in a day is 719712m

VELOCITY is defined as rate of change of displacement in a given interval of time.

it is a vector quantity.

its unit is m/s

to calculate the distance of a ship travelled

distance = speed x time

d = s x t   ----1.

velocity of ship = 8.33m/s

time taken = 1 day =86400 sec

now using the above values in equation 1 we get

d =8.33m/s x  86400 sec

d = 719712m

thus a ship travels 719712m in a day.

Distanced travelled by a ship with a constant velocity in a day is 719712m

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Answer:

Exposing it to a very strong magnetic field

Explanation:

Aluminium is a non magnetic metal thus it is not magnetic under normal conditions. This is because it interacts with other magnets. The only condition that magnetism can be induced in aluminium is exposing it to a very strong magnetic field.

Answer:

plastics are susceptible to degradation due to ultraviolet (UV) light from the sun. With enough exposure, UV light can cause a chemical reaction in the plastic, which results in scission, or severing, of those big polymer molecules.

Explanation:

Answer:

the short answer is yes and sun or strong uv lights

Explanation:

LEDs cannot melt plastic fixtures as they just do not get that hot, not even at the base These new bulbs are based on field-induced polymer electroluminescent (FIPEL) technology, with a twist. Without heat as a continual stressor, the polymer should remain stable for years. Any kind of light bulbs, from fluorescent to incandescent to halogen, can cause fires if they are not used correctly. As more heat is put into the plastic, more bonds are broken and the material becomes more like a liquid and less like a solid. Semi-crystalline polymers have a melting temperature which is the point at which the secondary bonds in the crystalline regions break. At this point the mateiral is completely liquid. There is melt and there is soften. Certainly they soften and become weak in sunlight both by the heat and by the UV degredation of the plastic. Unfortunately, the plastics used for garbage bags have a low melting point but by design, they should not melt in strong sunlight. the underlined sentences are the most important

The energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ

U = [tex]c_{p}[/tex] m ΔT

U = Energy

[tex]c_{p}[/tex] = Specific heat

m = Mass

ΔT = Change in temperature

ρ = Density

V = Volume

ρ = 1000 g / m³ (Dry air )

= 1 J / g K

ΔT = 5 °C

V = 4 * 4 * 3

V = 48 m³

m = ρ V

m = 1000 * 48

m = 48000 g

U = 1 * 48000 * 7

U = 336000 J

U = 336 kJ

Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ

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