What is another example of radiation
(A) Warm air rising
(B) Heat from an old-fashioned radiator
(C) Batteries
(D) Touching a stove and burring your hand

Answer:

7.53 km

Explanation:

We at given;

Speed of runner; v_r = 8.5 km/hr

Speed of bird; v_y = 17 km/hr

L = 6.4 km

We know that; time = distance/speed.

We are told that the bird starts from 6.4 km from the start and that it flies back to meet the runner after it reaches the finish line. If the total distance back to the runner is x, it means bird distance is 6.4 + (6.4 - x) = 12.8 - x

Thus;

Time of bird(t_y) = (12.8 - x)/17

Thus,

Time of runner(t_r) = x/8.5 hr

To find x, we have to equate the times of the runner and the bird.

Thus;

x/8.5 = (12.8 - x)/17

Multiply both sides by 17 to get;

2x = 12.8 - x

2x + x = 12.8

3x = 12.8

x = 12.8/3

x = 4.27 km

Thus, cumulative distance traveled by bird is; 12.8 - 4.27 = 7.53 km

Answer:

1) The radius of the tire is approximately 0.28966 meters

2) The centripetal force is the force that keeps a body moving on a circular path

Explanation:

1) The linear speed of the automobile tire = 20.0 m/s

The period with which the tire turns = 0.091 s

The period = The time it takes to make a complete turn

Therefore;

The number of turns in 1 second = 1/0.091 ≈ 10.989 turns

The distance covered with 10.989 turns, assuming no friction = 10.989 × The circumference of the tire

∴ The distance covered with 10.989 turns, assuming no friction = 10.989 × 2 × π × Radius of the tire

From the speed of the car, 20.0 m/s, we have;

The distance covered in 1 second = 20.0 meters

Therefore;

10.989 × 2 × π × Radius of the tire = 20.0 meters

Radius of the tire = (20.0 meters)/(10.289 × 2 × π) ≈ 0.28966 meters

The radius of the tire ≈ 0.28966 meters

2) The centripetal force is the force required to maintain the curved motion of an object, and having a direction towards the center of the rotary motion.

The centripetal force is given by the formula, [tex]F = \dfrac{m \cdot v^2}{r}[/tex]

Where;

F = The centripetal force

m = The mass of the object

v = The linear velocity of the object

r = The radius of the rotational motion.

Answer:

B

Explanation:

V=IR    I= curren V=volt R=resistor

8=2.R   8/2=R R=4

Answer:

7.69km/hr due east

Explanation:

Given parameters:

Displacement due west  = 3km

Displacement due east = 2km

Time taken  = 8 minutes

Unknown:

Average velocity  = ?

Solution:

Average velocity is the rate of change of displacement with time.

  Velocity  = [tex]\frac{displacement}{time }[/tex]

 Displacement is deals with the start and the end;

  Here, displacement  = 3km - 2km  = 1km due east

Time  = 8min

     60min  = 1hr

       8min = [tex]\frac{8}{60}[/tex]   = 0.13hr

 Average velocity = [tex]\frac{1km}{0.13hr}[/tex]   = 7.69km/hr due east

Answer:

a. 2 kg*m/s

b. [tex]p_{T_{f}} = 0.5v_{f} = 2 kg*m/s[/tex]

c. 4 m/s

Explanation:

a. The momentum of the system ([tex]p_{Ti}[/tex]) before the blob of clay strikes the cart is:

[tex] p_{Ti} = p_{b} + p_{c} [/tex]

Where:

[tex]p_{b}[/tex] is the momentum of the blob clay

[tex]p_{c}[/tex] is the momentum of the car      

[tex] p_{Ti} = m_{b}v_{b} + m_{c}v_{c} [/tex]

Since the car is initially at rest, [tex]v_{c}[/tex] = 0

[tex] p_{Ti} = 200 g*\frac{1 kg}{1000 g}*10 m/s + 0 = 2 kg*m/s [/tex]

b. The momentum of the system after they come together:

[tex]p_{T_{f}} = m_{b}v_{b} + m_{c}v_{c}[/tex]

Since they come together, [tex]v_{b}[/tex] =

[tex]p_{T_{f}} = v_{f}(m_{b} + m_{c}) = v_{f}(0.2 kg + 0.3 kg) = 0.5v_{f}[/tex]   (1)

Because we do not have the final speed we can not calculate the final momentum.

c. We can find the speed of the clay and car by conservation of the momentum:

[tex] p_{i} = p_{f} [/tex]

The initial momentum of the system was founded in part "a" (p = 2 kg*m/s), so we have:

[tex] 2 kg*m/s = m_{b}v_{b_{f}} + m_{c}v_{c_{f}} [/tex]

Again, when they come together, the final speed is the same:

[tex] 2 kg*m/s = v_{f}(m_{b} + m_{c}) [/tex]                

[tex] v_{f} = \frac{2 kg*m/s}{0.2 kg + 0.3 kg} = 4 m/s [/tex]

Now, since we found the final speed we can calculate the momentum of the system after they come together (equation 1):        

[tex] p_{T} = 0.5v_{f} = 0.5 kg*4m/s = 2 kg*m/s [/tex]

I hope it helps you!                  

Answer:

Spoken Peer Pressure

Positive Peer Pressure

Direct Peer Pressure

Negative Peer Pressure

Positive Peer Pressure

Unspoken Peer Pressure

Indirect Peer Pressure

Sorry this is all I know

Hope this Helps!

Answer:

See the explanation below

Explanation:

We must perform a sum of forces on the body, that sum of forces is equal to zero. That is, the body is in balance and does not move.

ΣF = 0

3 - 3 = 0

This force is negative and acts by pointing downwards.

Answer: ow consider a book sliding from left to right across a tabletop. Sometime in the prior history of the book, it may have been given a shove and set in motion from a rest position. Or perhaps it acquired its motion by sliding down an incline from an elevated position. Whatever the case, our focus is not upon the history of the book but rather upon the current situation of a book sliding to the right across a tabletop.

Explanation:

Answer:

I'm sorry to inform that I couldn't find an answer to this question. Socratic can help! This learning app, powered by Google AI, helps you understand your school work at a high school and university level. Ask Socratic a question and the app will find the best online resources for you to learn the concepts.

Explanation:

Answer:

There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.

Explanation:

From Physics we know that radioactive materials decay at exponential rate, whose differential equation is:

[tex]\frac{dm}{dt} = -\lambda\cdot m[/tex] (1)

Where:

[tex]\frac{dm}{dt}[/tex] - Rate of change of the mass of the radioactive material, measured in kilograms per second.

[tex]m[/tex] - Current mass of the radioactive material, measured in kilograms.

[tex]\lambda[/tex] - Decay constant, measured in [tex]\frac{1}{s}[/tex].

The solution of the differential equation is:

[tex]m(t) = m_{o}\cdot e^{-\lambda\cdot t}[/tex] (2)

Where:

[tex]m_{o}[/tex] - Initial mass of the radioactive material, measured in kilograms.

[tex]t[/tex] - Time, measured in seconds.

If we know that [tex]m_{o} = 20\,kg[/tex], [tex]\lambda = 0.179\,\frac{1}{s}[/tex] and [tex]t = 300\,s[/tex], then the initial mass of the radioactive material is:

[tex]m(t) = (20\,kg)\cdot e^{-\left(0.179\,\frac{1}{s} \right)\cdot (300\,s)}[/tex]

[tex]m(t) \approx 9.537\times 10^{-23}\,kg[/tex]

There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.

Answer:

400N is applied to the rope

Answer:

300N

Explanation:

Assuming his friend didn't throw the box, they would need a total of 1,500N to lift it, if the first person is already applying 1,200N, the only other amount of force needed is 300N to make a total of 1,500N! Simple math problem :)

Hope this helps! <3

Answer: The answer is c!

A heater in a fish tank warming the water at the bottom of the tank is an another example of convection.

Convection, which is the extensive movement of molecules within gases and liquids, is the mechanism through which heat is transported. Although most of the heat transfer occurs as a result of fluid motion, conduction is initially employed to transfer heat from the item to the fluid.

Convection is therefore demonstrated by a heater in a fish tank warming the water at the tank's bottom.

Learn more about convection of heat here:

brainly.com/question/16600140

#SPJ2

Answer:

Speed of lighter ball is 4 m/s.

Explanation:

Applying the principle of conservation of linear momentum,

momentum before collision = momentum after collision.

[tex]m_{1}[/tex][tex]u_{1}[/tex] + [tex]m_{2}[/tex] [tex]u_{2}[/tex] = [tex]m_{1}[/tex][tex]v_{1}[/tex] - [tex]m_{2}[/tex][tex]v_{2}[/tex]

[tex]m_{1}[/tex] = 3 kg, [tex]u_{1}[/tex] = 8 m/s, [tex]m_{2}[/tex] = 2 kg, [tex]u_{2}[/tex] = 0 m/s ( since it is at rest), [tex]v_{1}[/tex] = 2 m/s, [tex]v_{2}[/tex] = ?

(3 x 8) + (2 x 0) = (8 x 2) - (2 x [tex]v_{2}[/tex])

24 + 0 = 16 - 2[tex]v_{2}[/tex]

2[tex]v_{2}[/tex] = 16 - 24

2[tex]v_{2}[/tex] = -8

[tex]v_{2}[/tex] = [tex]\frac{-8}{2}[/tex]

   = -4 m/s

This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.

Given :

The diagram below shows a force of 5N acting on an object P at an angle of 30° to the horizontal.

To Find :

By drawing appropriate lines on the diagram using a ruler to determine:

a.)The horizontal component of the 5N force.

b.)The vertical component of the 5N force.​

Solution :

Horizontal component is given by :

=F cos θ

=5 cos 30°

= 5×0.866

= 4.33 N

Vertical component is given by :

= F sin θ

= 5 sin 30°

= 5×0.5

= 2.5 N

Therefore, horizontal and vertical component are 4.33 N and 2.5 N.

Hence, this is the required solution.

V = I • R

V = (0.054 A) • (152 ohms)

V = 8.208 volts

None of the listed choices is correct.

solid...............

Answer:

Tension = 60 N

Explanation:

The ball is executing a motion like a pendulum. The lowest point of a pendulum's motion is the mean position, where its potential energy becomes zero and kinetic energy becomes maximum. At this point the rope becomes straight vertical. Hence, the tension in the rope becomes exactly equal to the weight of the object at the lowest point. Also, in this case when the ball swings through the lowest point during its motion like a pendulum, the tension in the rope will become equal to the weight of the ball.

Tension = Weight

Tension = 60 N

Answer:

t = 2.38 [s]

Explanation:

To solve this problem we must use the following equation of kinematics. We must clarify that both the acceleration and the initial velocity were taken as positive, since the velocity of the movement coincides with the direction of the acceleration.

[tex]x =x_{o} +v_{o} *t+(\frac{1}{2} )*a*t^{2}[/tex]

where:

x - Xo = distance = 47 [m]

Vo = initial velocity = 8 [m/s]

a = gravity acceleration = 9.81 [m/s²]

t = time [s]

Now replacing these values in the equation:

47 = 8*t + 0.5*9.81*t²

47 = 8t + 4.905t²

47 = 4.905*t(1.63 + t)

9.58 = t*(1.63 + t) solving this equation (cuadratic)

we found that t = 2.38 [s]

Answer:

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{12}{4} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

12.0V

12.0V

Explanation:

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Answer:

2.00 A

Explanation:

Answer:

b I think. sorry if it's wrong

Answer:

Explanation:

Given

1 ) 140 m west in 45 s .

2 ) 90 m east in 25 s .

a )

distance travelled in first 45 s = 140 m

b ) distance travelled in next 25 s = 90 m

c ) Total distance travelled = 140 m + 90 m

= 230 m

d ) average speed in first 45 s

= distance in 45 s  45

= 140 / 45 = 3.11 m /s

e ) average speed in next 25 s

distance in 25 s / 25

= 90 / 25 = 3.6 m /s

f ) average in entire trip

=  total distance / total time

= (140 + 90) / ( 25 + 45 )

= 3.28 m /s

g )

displacement in first 45 s = 140 m towards west

h )

displacement in next 25 s = 90 m towards east

i )

total displacement = 140 - 90

= 50 m towards west .

Answer:D

Explanation:

It was right o khan academy

A dog jumps 0.80 M to catch a treat. The dog's displacement vector is shown below.

Which diagram shows the vertical and horizontal components of the dog's displacement?

THE ANSWER IS IN THE ATTACHMENT!

By listening for it underwater, using SONAR.

Hope this helped!

Answer:

5 no

Explanation:

actually the 4kg lying on table has no influence

it slides towards 4kg weight hung

as it has excess 2kg force

force=miu × m ×g

The magnitude of acceleration of the entire system is  [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.

Given data:

The masses  suspended from the table are, m = 2 kg and m' = 4 kg.

And the mass kept on the table is, m'' = 4 kg.

The frictional force will oppose the motion of mass 4 kg, kept on the table. Then the required value of frictional force is,

[tex]f = \mu \times m'' \times g\\\\f = 0.11 \times 4 \times 9.8\\\\f = 4.312 \;\rm N[/tex]

Since, the mass kept on the right side is more. Then at equilibrium,

-f + m''g + (m' +m)a = m'g

Here,

a is the magnitude of acceleration of the system.

Solving as,

-4.312+ 4(9.8) + (4 -2)a = 4(9.8)

2a = 4.312

[tex]a \approx 2.1315 \;\rm m/s^{2}[/tex]

Thus, we can conclude that the magnitude of acceleration of the entire system is  [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.

Learn more about the linear acceleration here:

https://brainly.com/question/14214161