The volume of a rock with a density of 45 g/mL and a mass of 855g is 19mL.
The volume of the rock can be calculated as
[tex]density = \frac{mass}{volume}[/tex]
Density is the measurement of how tightly a material is packed
together.
by using the above formula of density we can find volume as
[tex]volume = \frac{mass}{density }[/tex]
v = m/ρ
where v = volume
m = mass
ρ = density
density of a rock = 45 g/mL
mass of rock = 855g.
The volume of the rock can be calculated as follows:
Volume = 855g /45g/mL
Volume = 19mL
Therefore, the volume of a rock with a density of 45 g/mL and a mass of 855g is 19mL.
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A contact lens is made of plastic with an index of refraction of 1.60. The lens has an outer radius of curvature of 2.08 cm and an inner radius of curvature of 2.48 cm. What is the focal length of the lens?
Answer:
The value [tex]f = 21.49 \ cm[/tex]
Explanation:
From the question we are told that
The index of refraction is [tex]n = 1.60[/tex]
The outer radius of curvature is [tex]R = 2.08 \ cm = 0.0208 \ m[/tex]
The inner radius is [tex]r = 2.48 \ cm = 0.0248 \ m[/tex]
Generally from Maker's equation we have that
[tex]\frac{1}{f} = [n - 1 ][\frac{1}{(R)} - \frac{1}{r} ][/tex]
=> [tex]\frac{1}{f} = [1.60 - 1 ][\frac{1}{( 0.0208 )} - \frac{1}{0.0248} ][/tex]
=> [tex]\frac{1}{f} = 4.65[/tex]
=> [tex]f = 0.2149 \ m[/tex]
=> [tex]f = 21.49 \ cm[/tex]
On a chilly 12∘C day, you quickly take a deep breath--all your lungs can hold, 4.0 L. The air warms to your body temperature of 37∘C.
If the air starts at a pressure of 1.0 atm, and you hold the volume of your lungs constant (a good approximation) and the number of molecules in your lungs stays constant as well (also a good approximation), what is the increase in pressure inside your lungs?
Answer:
The increase in pressure inside the lungs is 0.09 atm
Explanation:
From the Pressure law
Pressure law states that the volume of a fixed mass of gas is directly proportional to the absolute temperature provided that the volume remains constant.
That is,
P ∝ T
Where P is the Pressure and T is the temperature.
Then, we can write that
P = kT
Where k is the proportionality constant
∴ [tex]\frac{P}{T} = k[/tex]
Then,
[tex]\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }[/tex]
From the question, [tex]P_{1}[/tex] = 1.0 atm
[tex]{T_{1}[/tex] = 12 °C = (12 + 273.15) K = 285.15K
[tex]{T_{2}[/tex] = 37 °C = (37 + 273.15) K = 310.15K
Therefore,
[tex]\frac{1.0}{285.15} = \frac{P_{2} }{310.15}[/tex]
[tex]P_{2} = \frac{1.0 \times 310.15}{285.15}[/tex]
[tex]P_{2} = 1.09[/tex] atm
Increase in pressure = [tex]P_{2} - P_{1}[/tex] = 1.09 atm - 1.0 atm
Increase in pressure = 0.09 atm
Hence, the increase in pressure inside the lungs is 0.09 atm
At constant volume, pressure of the gas is directly proportional to the temperature of the gas. The increased pressure inside the lungs is 0.9 atm.
From Gas law,
[tex]\bold {\dfrac {P_1} {T_1 } = \dfrac {P_2} {T_2 } }[/tex]
Where,
P1 - initial pressure = 0.1 atm
P2 - final pressure = ?
T1 - initial temperature = 12 °C = (12 + 273.15) K = 285.15 K
T2 - final temperature = 37 °C = (37 + 273.15) K = 310.15 K
Put the values in the formula,
[tex]\bold {\dfrac {1.0} {285.15 } = \dfrac {P_2} {310.15 } }[/tex]
[tex]\bold {P_2 = 1.09\ atm}[/tex]
Thus, increased pressure in the lungs
= 1.9 - 1.0
= 0.9 atm
Therefore, the increased pressure inside the lungs is 0.9 atm.
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A 5.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical oscillations having a period of 3.50 s. Find the force constant of the spring.
Answer:
17.71N/m
Explanation:
The period of the spring is expressed according to the expression;
[tex]T = 2 \pi \sqrt{\frac{m}{k} } \\[/tex]
m is the mass of the object
k is the force constant
Given
m = 5.50kg
T = 3.50s
Substitute into the formula;
[tex]T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} = \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k = 17.71N/m[/tex]
Hence the force constant of the spring is 17.71N/m
Which term is described as a seamount with a flattened top?
deep-sea trenches
guyots
continental shelf
abyssal plains
The term which is described as a seamount with a flattened top is called as guyots.
Guyot, commonly known as Tablemount, is an uninhabited submarine volcano with a flat peak that is more than 200 meters (660 feet) above sea level. These flat summits could be more than 10 kilometres in circumference (6 miles).
Seamounts called guyots have grown above sea level. The seamount's top was eroded by erosion by waves, leaving it with a flattened shape. The sea bottom gradually falls as a result of the ocean floor moving away from oceanic ridges, submerging the flattened guyots to form undersea flat-topped peaks. Once the guyot is formed, on it's top a coral colony will start developing and little by little make a circle shaped island, which represents the formation of the atoll.
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A pig on roller skates is moving with an initial velocity of -10 m/s and is accelerating at a rate of 2m/s/s, therefore the pig is __________during the next 2 seconds.
Question 7 options:
moving faster in the negative direction
moving faster in the positive direction
moving slower in the positive direction
moving slower in the in the negative direction
Answer:
Moving slower in the negative direction.
Explanation:
This pig has an initial velocity of -10 (negative) and is accelerating at a rate of 2 m/s/s (positive). Since the acceleration has an opposite sign than the velocity, the object will be slowing down. Since the initial velocity was negative, it will be slowing down in the negative direction.
A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. How long until the cannonball hits the ground?
96.7 s
55.3 s
65.3 s
45.5 s
Answer:
96.7 s
Explanation:
Time of flight in projectile can be calculated thus:
T = 2 × u × sin ϴ/ g
Where;
T = time of flight (s)
u = initial velocity (m/s)
ϴ = Angle of projectile (°)
g = acceleration due to gravity (9.8m/s²)
Based on the provided information; u = 670m/s, ϴ = 45°
Hence, using T = 2.u.sin ϴ/ g
T = 2 × 670 × sin 45° ÷ 9.8
T = 1340 × 0.7071 ÷ 9.8
T = 947.52 ÷ 9.8
T = 96.68
T = 96.7s
motion is a change in
8th grade science, Two questions.
Please help me
Answer:
for 10 some advantages are that it has a much better bandwidth,low power loss, and it allows for longer transmission distance.
A copper rod has a length of 1.7 m and a cross-sectional area of 3.2 × 10-4 m2. One end of the rod is in contact with boiling water and the other with a mixture of ice and water. What is the mass of ice per second that melts? Assume that no heat is lost through the side surface of the rod.
Given :
A copper rod has a length of 1.7 m and a cross-sectional area of [tex]3.2 \times 10^{-4} \ m^2[/tex].
One end of the rod is in contact with boiling water and the other with a mixture of ice and water.
To Find :
The mass of ice per second that melts.
Solution :
Amount of heat transfer from boiling water to ice through the copper bar is :
[tex]Q = \dfrac{kA\Delta T }{L}\\\\Q = \dfrac{390\times 3.2 \times 10^{-4} \times 100}{1.7}\\\\Q = 7.34 \ J/s[/tex]
Let, amount of ice melts per second is :
[tex]m=\dfrac{Q}{L_f}[/tex]
Here, [tex]L_f[/tex] is the latent of fusion of water and is equal to [tex]L_f = 3.34\times 10^5 \ J/s[/tex].
Putting all values in above equation, we get :
[tex]m=\dfrac{7.34}{3.34\times 10^5}\\\\m = 2.19 \times 10^{-5} \ kg/s[/tex]
Hence, this is the required solution.
A bowling ball with a mass of 5 kg is rolled at an acceleration of 2 m/s2. What is the force of the bowling ball when it hits the pins? (Hint: Force = ?)
Answer:
[tex]F=10\ N[/tex]
Explanation:
[tex]We\ are\ given\ that,\\Mass\ of\ the\ bowling\ bowl=5\ kg\\Acceleration\ of\ the\ ball=2\ m/s^2\\Hence,\\As\ we\ know\ that\ F=ma\\Here,\\Force\ of\ the\ bowling\ ball\ when\ it\ hits\ the\ pins=Mass\ of\ the\ bowling\ bowl* its\ Acceleration.\\Hence,\\F=5*2\\F=10\ Newtons\\[/tex]
A ball is thrown horizontally at a height of 1.5 meters at a velocity of 70 m/s. Assume no air resistance. How far did the ball travel horizontally when it hit the ground?
15.4 m
38.5 m
67 m
45.5 m
Answer:
38.5
Explanation:
Clear selection
10 points
A laptop battery stores energy with an efficiency of 80%. If 16 000 J of
energy are transferred to the laptop from the battery, how much energy
must have been transferred to the battery?
20 kJ
20 J
1.28 kJ
12 800 J
Next
Page 1 of 2
Answer:
20000J or 20kJ
Explanation:
Given parameters:
Efficiency of the battery = 80%
Amount of energy transferred = 16000J
Unknown:
How much energy was transferred to the battery = ?
Solution:
Since the battery is 80% efficient, it loses 20% of energy anytime it wants to store energy.
Now, 16000J of energy is contained in the battery, the original amount of energy sent to the battery;
Let the amount of energy sent to the battery be y
80% of y = 16000
0.8y = 16000
y = 20000J or 20kJ
Testosterone is used to treat breast cancer ? True or false?
Answer:
True
Explanation:
Because I had a test on this
A person travels by car from one city to another. She drives for 30.1 min at 82.1 km/h, 9.11 min at 83.1 km/h, 49.6 min at 41.3 km/h, and spends 18.7 min along the way eating lunch and buying gas. Determine the distance between the cities along this route. Answer in units of km.
The distance between the cities along the route is 87.95 Km
What is speed?Speed is the distance travelled per unit. Mathematically, it can be expressed as:
Speed = distance / time
How to determine the distance travelled in 30.1 minsTime = 30.1 mins = 30.1 / 60 hourSpeed = 82.1 Km/hDistance =?Speed = distance / time
Cross multiply
Distance = speed × time
Distance = 82.1 × (30.1 / 60)
Distance = 41.19 Km
How to determine the distance travelled in 9.11 minsTime = 9.11 mins = 9.11 / 60 hourSpeed = 83.1 Km/hDistance =?Speed = distance / time
Cross multiply
Distance = speed × time
Distance = 83.1 × (9.11 / 60)
Distance = 12.62 Km
How to determine the distance travelled in 30.1 minsTime = 49.6 mins = 49.6 / 60 hourSpeed = 41.3 Km/hDistance =?Speed = distance / time
Cross multiply
Distance = speed × time
Distance = 41.3 × (49.6 / 60)
Distance = 34.14 Km
How to determine the distance between the citiesDistance travelled in 30.1 mins = 41.19 KmDistance travelled in 9.11 mins = 12.62 KmDistance travelled in 49.6 mins = 34.14 KmTotal distance =?Total distance = 41.19 + 12.62 + 34.14
Total distance = 87.95 Km
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What is the velocity of a group of explorers traveling from Antarctica to Australia, traveling 1500 miles in 48 hours?31.25 mph south
72,000 mph
48 mph
31.3 mph north
Answer:
31.3mph North
Explanation:
Given parameters:
Distance traveled = 1500miles
Time taken = 48hrs
Unknown:
Velocity of the group of explorers = ?
Solution:
Velocity is the displacement divided by the time taken. It is a vector quantity with both magnitude and direction.
So;
Velocity = [tex]\frac{displacement}{time}[/tex]
Displacement is the distance moved in a specific direction = 1500miles North
Insert the parameters and solve;
Velocity = [tex]\frac{1500}{48}[/tex] = 31.3mph North
The sound level at 1.0 m from a certain bullfrog is 60 dB. You are surrounded by 18 such bullfrogs, all 1.0 m from you and all croaking equally loudly at the same time. What sound level are you being exposed to
Answer:
The value is [tex]S_a = 72.56 \ dB[/tex]
Explanation:
From the question we are told that
The sound level is [tex]S = 60 dB[/tex]
The distance from the source is d = 1 m
The number of sources is n = 18
Generally the sound which the person is been exposed to is mathematically represented as
[tex]S_a = S + 10log(18)[/tex]
=> [tex]S_a = 60 + 10log(18)[/tex]
=> [tex]S_a = 72.56 \ dB[/tex]
In the Vomitus carnival ride, passengers travel in a horizontal 4.0 m radius circle. For safe operation, the maximum sustained acceleration that riders may experience is 20 m/s2 , approximately twice the free fall acceleration. What is the period of the ride when it is being operated at the maximum acceleration?
Answer:
The period of the ride when it is being operated at the maximum acceleration is T=2.81 s.
Explanation:
We can use the centripetal acceleration here:
[tex]a_{c}=\frac{v^{2}}{R}=\omega^{2}R[/tex]
Let's find the angular velocity ω at the maximum acceleration.
[tex]20=\omega^{2}*4[/tex]
[tex]\omega=2.24 rad/s[/tex]
The period is given by:
[tex]T=\frac{2\pi}{\omega}[/tex]
[tex]T=\frac{2\pi}{2.24}[/tex]
Therefore, the period will be T=2.81 s.
I hope it helps you!
QUESTION 1
energy is the work done by a force acting through a distance.
[tex]acslerishne[/tex]
What makes ramps useful simple machines?
By increasing the distance, the force
required decreases
b. By increasing the distance, the required
work decreases
c. By increasing the force, the required
distance decreases
Answer:
It reduces the force necessary to move a load a certain distance up by providing a path for the load to move at a low angle to the ground.
Explanation:
Both the pressure and volume of an ideal gas of diatomic molecules are doubled. The ratio of the new internal energy to the old both measured relative to the internal energy at 0 K is
Answer:
The ratio of the new internal energy to the old is 4
Explanation:
let the old pressure of the gas = P₁
let the old volume of the gas = V₁
then, the new pressure of the gas = 2P₁
the new volume of the gas = 2V₁
The internal energy of the gas is given as;
PV = nRT
PV = k
P₁V₁ = P₂V₂
[tex]\frac{P_2V_2}{P_1V_1} = \frac{2P_1\ \times \ 2V_1}{P_1V_1} =\frac{4}{1} = 4[/tex]
The ratio of the new internal energy to the old is 4
A cyclist travels from point A to point B for 10 minutes. During the first 2.0 minutes of her trip, she maintains a uniform acceleration of 0.076 m/s2. She then travels at constant velocity for the next 5.0 minutes. Next, she decelerates at a constant rate so that she comes to a rest at point B 3.0 minutes later
What is the acceleration during the last 3.0 minutes
Answer:
im not really good at explaining, but i found this website url:
https://www.numerade.com/questions/a-cyclist-travels-from-point-a-to-point-b-in-10-min-during-the-first-20-min-of-her-trip-she-maintain/
same question just with the explanation
The scientific method can easily be misinterpreted as ___________. Question 1 options: a great magical trick, or slide of hands, rather than factual an "auto mechanics" guide to Science Investigation a "cookbook" recipe for performing scientific investigations the perfect method for finding the answers to all questions
Answer:
I think the answer is
a "cookbook" recipe for performing scientific investigations
Explanation:
The mass of an electron is 9.11 x 10-31 kg. If you want to increase the speed of the
electron from 90% of the speed of light to 95% of the speed of light (where the
speed of light is 2.997x108 m/s), the amount of work that must be done is:
8.2 x 10-13)
0 3.2× 10-13 ,
O 2.6% 10-13 ,
O 7.4× 10-14 ,
3.8 x 10-15)
I'm not sure of this question, yet i know you may get angry but, just know your loved and if going through a hard time i'm so so sorry, i know how it feels it sucks. take care of yourself, drink water, listen to that one song that makes you dance in your room and go do what YOU love. your beautiful your perfect and dont listen to what anyone says. i love u, everyone loves u, i know its scary but it happens to everyone life isnt a peice of cake unfortunatly and it sucks but woahh your strong! if you need someone to talk to leave a comment below, happy hoildays everyone!
P.S, im looking into the answer of this question. I may not answer it right on time (since i'm not the smartest...) but i promise ill try my best! Also, i am not doing this for points im doing this to make others smile. I hate how no one checks up on anyone, lots of people are going through a stressful time (including me) and i just want to let everyone know that its okay not to be okay! I hope that you all find happiness in every possible situation, once again HAPPY HOLIDAYS!
What is matter ?
...
Explanation:
a matter is solid gas and liquid
Answer:
matter is anything made of mass which occupys volume
Explanation:
matter is a thing which concludes mass and mentioned and also has volume ( volume is defined as space too) so everything is made of matter
A stunt man drives a car at a speed of 20m/s off a 30-m-high cliff. The road leading to the cliff is inclined upward at an angle of 20 degrees. How far from the base of the cliff does the car land?
The car lands at a distance of 60 m from the base of the cliff.
s = ut + 1 / 2 a[tex]t^{2}[/tex]
s = Displacement
u = Initial velocity
t =Time
a = Acceleration
u = 20 m / s
[tex]s_{y}[/tex] = 30 m
θ = 20°
g = 9.8 m / s²
Resolving the velocity into its horizontal and vertical components
sin θ = [tex]u_{y}[/tex] / u
[tex]u_{y}[/tex] = - 20 sin 20°
[tex]u_{y}[/tex] = - 6.84 m / s
Considering only the vertical components,
[tex]s_{y}[/tex] = [tex]u_{y}[/tex] t + 1 / 2 g t²
30 = - 6.84 t + 4.9 t²
4.9 t² + ( - 6.84 ) t - 30 = 0
This is in the form of a quadratic equation,
t = - ( - 6.84 ) + √ [ ( - 6.84 )² - ( 4 * 4.9 * ( - 30 ) ) ] / 2 ( 4.9 )
t = 3.2 sec
The distance we need to calculate is in horizontal direction,
[tex]v_{x}[/tex] = [tex]s_{x}[/tex] / t
[tex]s_{x}[/tex] = 20 cos 20° / 3.2
[tex]s_{x}[/tex] = 60 m
Therefore, the car lands at a distance of 60 m from the base of the cliff.
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Determine the inductance of a solenoid with 650 turns in a length of 28 cm . The circular cross section of the solenoid has a radius of 3.5 cm .
Answer:
The value is [tex]L = 0.0073 \ H[/tex]
Explanation:
From the question we are told that
The number of turns is [tex]N = 650 \ turns[/tex]
The length is [tex]l = 28 \ cm = 0.28 \ m[/tex]
The radius of the cross-section is [tex]r = 3.5 \ cm = 0.035 \ m[/tex]
Generally the cross-sectional area is mathematically represented as
[tex]A = \pi * r^2[/tex]
=> [tex]A = 3.142 * 0.035^2[/tex]
=> [tex]A = 0.00384 \ m^2[/tex]
Generally the inductance is mathematically represented as
[tex]L = \frac{N^2 * \mu _o * A }{ l}[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]
=> [tex]L = \frac{ 650^2 * 4\pi * 10^{-7} * 0.00384 }{0.28}[/tex]
=> [tex]L = 0.0073 \ H[/tex]
100 Points!
A projectile is launched in the horizontal direction. It travels 2.050 m horizontally while it falls 0.450 m vertically and then strikes the floor. How long is the projectile in the air? Show your work.
B. What is the original velocity of the projectile described? Show your work.
Answer:
A) 0.303 s (3 s.f.)
B) 6.76 ms⁻¹ (3 s.f.)
Explanation:
Constant Acceleration Equations (SUVAT)
[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
Consider the horizontal and vertical motion of the projectile separately.
Part AAs the projectile is fired horizontally, the vertical component of its initial velocity is zero.
Acceleration due to gravity = 9.8 ms⁻²
Resolving vertically, taking ↓ as positive:
[tex]s=0.450\quad u=0\quad a=9.8[/tex]
[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\0.450&= (0)t+\dfrac{1}{2}(9.8)t^2\\0.450&= 4.9t^2\\t^2&= \dfrac{0.450}{4.9}\\t&=\sqrt{\dfrac{0.450}{4.9}\\t &=0.3030457634...\\ \implies t&=0.303\:\sf s\;\;(3\:s.f.)\\\end{aligned}[/tex]
Part BThe horizontal component of velocity is constant, as there is no acceleration horizontally.
Resolving horizontally, taking → as positive:
[tex]s=2.050 \quad a=0 \quad t=0.3030457634...[/tex]
[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\2.050&= u(0.3030457634...)+\dfrac{1}{2}(0)(0.3030457634...)^2\\2.050&= 0.3030457634...u\\u&= \dfrac{2.050}{0.3030457634...}\\ u &=6.764654873...\\\implies u & = 6.76\:\sf ms^{-1}\;\;(3\:s.f.)\end{aligned}[/tex]
12) You find 13,406,190 pennies. If each penny weighs 4 grams, how much did all that loot weigh in lbs.? (2.2 lbs = 1 Kilogram)
(please show work!)
Answer:
here is the answer
Explanation:
117974.472
A roller coaster at an amusement park has a dip that bottoms out in a vertical circle of radius 11.0 m. A passenger feels the seat of the car pushing upward on her with a force equal to three times her weight at the bottom of the dip. What is her speed as she goes through the dip
Answer:
14.69
Explanation:
The circle of radius R = 11.0m
Force f = 3 times her Weight
= 3W = 3mg
Then the net force acting on her
F = W + F(centripetal)
= mg + mv²/r
= Mg + mv²/r = 3mg
Then her speed is going to be
V = √2gr
Where g =9.81m/s²
R = 11.0
When we put these values into the formula we get:
V = √2x9.81x11.0
V = √215.82
V = 14.69
Elements known as noble gases do not have the ability or the room in their valence
electron shell to form bonds with other elements.
O True
O False
Answer:
true
Explanation:
noble gases are octet meaning they they have eight electrons in their outer shell so the are stable