Answer:
[tex]Kc=\frac{[HI]^2}{[I_2][H_2]}[/tex]
Explanation:
Hello there!
In this case, for these equilibrium problems it is firstly necessary to know the balanced reaction at equilibrium:
H2((g) + I2(g) ⇋ 2HI(g)
Next, by means of the law of mass action, it turns out possible for us to write the required and correct expression for the equilibrium constant by considering the concentrations and the coefficients in the aforementioned reaction:
[tex]Kc=\frac{[HI]^2}{[I_2][H_2]}[/tex]
Best regards!
For each pair of covalently bonded atoms, choose the one expected to have the shortest bond length. (A) C-I (B) H-I ...... (A,B) fill in the blank 1 (C) H-Cl (D) H-I ...... (C,D) fill in the blank 2
Answer:
i) B
ii) D
Explanation:
Bond length is determined by the size of the atoms involved and the bond order
A) C-I
B) H-I
answer : H-I has the shortest bond length because H has an electronegativity value of 2.2 while C has an electronegativity value of 2.5 hence the bond between H-I is greater than C - I due the electronegativity difference between H-I is greater as well.
C) H-Cl
D) H-I
answer : H-Cl has the shortest bond length due the electronegativity difference between H-CI is greater as well.
The addition, removal, or substitution of nitrogenous bases in a DNA molecule may be caused by . Synapsis C. Disjunction B. Hybridization D. Mutation
Answer:
D. Mutation
Explanation:
Mutation is any change or alteration that occurs to the nucleotide sequence of a gene induced during DNA replication or by mutation-causing substances called MUTAGENS.
Mutation can be in the form of addition, removal, or substitution of nitrogenous bases in a DNA molecule. For example, in an original DNA sequence as follows: GAT ATC TGA, the following mutation can occur:
Addition: GAT ATC CTG A
Removal: GAT ATT GA
Substitution: GAT CTC TGA
what is an example of an electrolyte solution?
Answer:
nacl with water
they are capable of conducting electricity
Atoms in the same PERIOD have the same...
A. Number of energy levels
B. Size
C. Temperature
D. Reactivity
Answer:
A. Number of energy levels
Explain how a neutral paper fragment can be attracted to a charged rod
Answer:
The particles in the neutral paper can shift, causing the paper to become polarized and attracted to the rod.
Explanation:
The neutral paper has an even distribution of its electrons throughout the paper. If a charged rod is brought near the neutral paper, this can cause the electrons in the paper to shift. If the rod is negative, the electrons will be repelled from the rod and cause the molecules in the paper to have a slight positive charge on the part of the paper closest to the rod. If the rod is positive, the electrons will be attracted to the rod and cause a slight negative charge on the side of the paper closest to the rod.
Two gas particles collide together in a sealed container. What can be said about the kinetic energy of the two gas particles?
a)During the collision, each gas particle transfersall of its kinetic energy to the other particle.
b)The total kinetic energy of both gas particles will remain the same, but they can transfer any amount to each other.
c)The new kinetic energy of each gas particle is the sum of the kinetic energy that each particle is traveling with.
d)The kinetic energy of each gas particle remains the same as kinetic energy cannot be transferred between particles with zero volume.
Explanation:
c)The new kinetic energy of each gas particle is the sum of the kinetic energy that each particle is traveling with.
NEED HELP FOR THIS ONE
Answer:
C₆H₁₂O₆ + 6 O₂ = 6 CO₂ + 6 H₂O
2 KO₂ + H₂O = 2 KOH + 1.5 O₂
Explanation:
Let's consider the following unbalanced equation.
C₆H₁₂O₆ + O₂ = CO₂ + H₂O
We will start balancing H atoms (higher atomicity) by multiplying H₂O by 6.
C₆H₁₂O₆ + O₂ = CO₂ + 6 H₂O
Then, we will balance C atoms by multiplying CO₂ by 6.
C₆H₁₂O₆ + O₂ = 6 CO₂ + 6 H₂O
Finally, to get the balanced equation, we will multiply O₂ by 6.
C₆H₁₂O₆ + 6 O₂ = 6 CO₂ + 6 H₂O
---
Let's consider the following unbalanced equation.
KO₂ + H₂O = KOH + O₂
We will multiply KO₂ and KOH by 2 to balance K and H atoms.
2 KO₂ + H₂O = 2 KOH + O₂
Finally, to get the balanced equation, we will multiply O₂ by 1.5.
2 KO₂ + H₂O = 2 KOH + 1.5 O₂
arrange the following group of atoms in order of increasing atomic size:B,Al,Ga
Answer:
Al,Ga,B
Explanation:
Now since i helped you can you help me with this plz
Matteo took 5 math quizzes. The mean of the 5 quizzes was 8.2. Here are four of his quiz scores 7, 7, 8, 10. What is the 5th quiz score? Show work.
Boron ( B )
Aluminium ( Al )
Gallium ( Ga )
Which of the following is NOT an abiotic factor that influences an ecosystem?
Amount of water available
Average rainfall
Average temperature
Number of different animals
Answer:
Number of different animals
Explanation:
Number of different animals is not an abiotic factor that influences an ecosystem rather it is a biotic factor.
What is an ecosystem?Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.
Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.
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If the rate of decomposition of ammonia, NH3, at 1150 K is 2.10 x 10-6 mol/L/s, what is the
rate of production of nitrogen and hydrogen? Given 2NH3 3H2 + N2
Answer:
3.15 × 10⁻⁶ mol H₂/L.s
1.05 × 10⁻⁶ mol N₂/L.s
Explanation:
Step 1: Write the balanced equation
2 NH₃ ⇒ 3 H₂ + N₂
Step 2: Calculate the rate of production of H₂
The molar ratio of NH₃ to H₂ is 2:3. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of H₂ is:
2.10 × 10⁻⁶ mol NH₃/L.s × 3 mol H₂/2 mol NH₃ = 3.15 × 10⁻⁶ mol H₂/L.s
Step 3: Calculate the rate of production of N₂
The molar ratio of NH₃ to N₂ is 2:1. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of N₂ is:
2.10 × 10⁻⁶ mol NH₃/L.s × 1 mol N₂/2 mol NH₃ = 1.05 × 10⁻⁶ mol N₂/L.s
Step 1: When we Write the balanced equation
Then 2 NH₃ ⇒ 3 H₂ + N₂Step 2: Calculate the rate of production of H₂
After that, The molar ratio of NH₃ to H₂ is 2:3. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of H₂ is:Now 2.10 × 10⁻⁶ mol NH₃/L.s × 3 mol H₂/2 mol NH₃ = 3.15 × 10⁻⁶ mol H₂/L.sStep 3: Calculate the rate of production of N₂
After that, The molar ratio of NH₃ to N₂ is 2:1. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of N₂ is:Now 2.10 × 10⁻⁶ mol NH₃/L.s × 1 mol N₂/2 mol NH₃ = 1.05 × 10⁻⁶ mol N₂/L.sLearn more about:
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PART A: Which of the following statements best identifies a central idea of the article?
A. The media attention on Mars enthusiasts has caused space exploration to become one of the
most important issues facing Americans today.
B. While some private agencies are working on sending humans to Mars, many experts believe
that the barriers to such a voyage still remain high.
C. Despite the publicity surrounding private space missions, NASA remains optimistic that it
will be the first agency in the U.S. to send humans to Mars.
D. Private space agencies have no plans beyond landing on Mars, as opposed to the people of
NASA, who genuinely want to colonize Mars and explore space.
The central idea is despite publicity surrounding private space missions, NASA remains optimistic that it will be the first agency to send humans to Mars.
What is NASA?This is referred to as National Aeronautics and Space Administration and are involved in the science and technology related to space.
The article talks about publicity of private space missions and NASA being optimistic about being the first to achieve the feat of sending humans to Mars.
Read more about NASA here https://brainly.com/question/1350178
wich strong nucleophil h2s or water??and why??
According to my notes, nucleophilicity order is directly proportional to basicity order in an aprotic medium, and is inversely proportional to basicity order in protic medium. And H2O is a stronger base than H2S, so it should be the strong nucleophile, but the answer is given as H2S is the stronger nucleophile.
hope this helped, good luck <3
Choose all the answers that apply.
The atmosphere:
is made mostly of nitrogen
can be used to transmit radio signals
traps heat from the sun
protects the earth from harmful radiation
is important in the water cycle
Answer:1 2 and 4
Explanation:
How many molecules of N204 are in 85.0 g of N2O4?
Answer:
5.56 x 10^23
Explanation:
Just convert and cancel out.
85 g N2O4 x 1 mol/92.01 g x 6.02 x 10^23 molecules /1 mol
is sublimation a chemical change or chemical property or physical change?
Answer:
Physical Change
Explanation:
Sublimation is a physical change. When a substance sublimes, it changes from a solid to a gas without going through the liquid phase.
why are electrical wires covered with plastic coating
Answer:
For safety.
Explanation:
Because uncovered wires are conductors, an electric current could damage someone if touched. Plastic and rubber are insulators, meaning that current cannot pass through them.
Which metals will switch in this single replacement reaction Zn + MgO -->
a. Mg and Zn
b. Zn and O
c. Mg and O
d. This is not a single replacement reaction
Answer:
D
Explanation:
Magnesium is more reactive than zinc so no reaction will take place
define the term semiconductor and give an example of a metalloid
Answer:
A metalloid is a chemical element that exhibits some properties of metals and some of nonmetals.The closer you get to the zone, the more blurred the properties become. Metalloids tend to be semiconductors; silicon is the best known example of a semiconductor. Most microchips and microprocessors are made with silicon.
Explanation:
That is what i know on the answer
To solve this we must be knowing each and every concept related to metalloid. Therefore, in above given ways semiconductor can be defined.
What is metalloid?Metalloids are chemical elements with physical and chemical characteristics that fall between between metal and nonmetal.
A metalloid is indeed a chemical element with characteristics of both metals and nonmetals. The properties grow increasingly blurred as you move closer to the zone. The seven most well-known metalloids are boron, germanium, silicon, antimony, arsenic, tellurium, and polonium.
Metalloids are often semiconductors, with silicon being the most well-known example. Silicon is used to make the majority of microchips and microprocessors.
Therefore, in above given ways semiconductor can be defined.
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g At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H 2 (g) Br 2 (g) 2HBr (g) A mixture of 0.682 mol of H 2 and 0.440 mol of Br 2 is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 700 K, there are 0.516 mol of H 2 present. At equilibrium, there are ________ mol of Br 2 present in the reaction vessel.
Answer: At equilibrium , there are 0.274 moles of [tex]Br_2[/tex]
Explanation:
Moles of [tex]H_2[/tex] = 0.682 mole
Moles of [tex]Br_2[/tex] = 0.440 mole
Volume of solution = 2.00 L
Initial concentration of [tex]H_2[/tex] = [tex]\frac{0.682}{2.00}=0.341 M[/tex]
Initial concentration of [tex]Br_2[/tex] = [tex]\frac{0.440}{2.00}=0.220 M[/tex]
Equilibrium concentration of [tex]H_2[/tex] = [tex]\frac{0.516}{2.00}=0.258 M[/tex]
The given balanced equilibrium reaction is,
[tex]H_2(g)+Br_2(g)\rightleftharpoons 2HBr(g)[/tex]
Initial conc. 0.341 M 0.220 M 0 M
At eqm. conc. (0.341-x) M (0.220-x) M (2x) M
Given : (0.341-x) M = 0.258 M
x= 0.083 M
Thus equilibrium concentartion of [tex]Br_2[/tex] = (0.220-0.083) M = 0.137 M
Thus moles of [tex]Br_2[/tex] at equilibrium = [tex]0.137M\times 2.00L=0.274mol[/tex]
At equilibrium , there are 0.274 moles of [tex]Br_2[/tex]
What are the final units when you have a mass (in grams), and then divide it by molar
mass
Answer:
The final units are mol
Explanation:
The units of molar mass are grams per mole, g/mol.
This means that when dividing mass by molar mass, the units of grams cancel each other, leaving only units of moles:
Grams ÷ Grams/molAnother way of writing that might help is as follows:
[tex]\frac{g}{\frac{g}{mol}}[/tex]Thus, the final units are moles.
Use this picture to explain that an electrically charged object can attract an uncharged object without any contact. Your answer should be at least three sentences long. (2 points) a balloon hanging from a string with small pieces of paper stuck to the bottom of it, with a few pieces on the ground
Answer: Insufficient amount of work provided.
Explanation:
A 72.0 g sample of an organic solid is dissolved in 180mL of water. The solid is extracted using one 60 mL extraction in the first extraction of an organic solvent which has a partition (distribution) coefficient with water of 10. The first extraction removed 55.4 g of solid from water. What are the numbers that need to go in box A and B to calculate the volume of solvent (y) that would be necessary to remove an additional 7.0g from the remaining sample dissolved in water. You DON'T have to complete the calculation to solve for y.
Answer:
[tex]V_{7.0}\approx 235ml[/tex]
Explanation:
From the question we are told that
mass of sample [tex]M=72.0 grams[/tex]
volume of water [tex]V=180 mL[/tex]
volume for extraction [tex]V'=60mL[/tex]
partition (distribution) coefficient water [tex]d=10[/tex]
initial extraction removal [tex]x=55.4g[/tex]
Generally the equation for the weight of sample [tex]x_n[/tex] is mathematically given by
[tex]x_n=x*(\frac{DV}{DV+V'})^n[/tex]
[tex]x_n=55.4(\frac{10*180}{10*180+60})^1[/tex]
[tex]x_n=53.613g[/tex]
Generally the weight extracted [tex]x_e[/tex] is therefore
[tex]w_e=x-x_n[/tex]
[tex]w_e=55.4-53613[/tex]
[tex]w_e=1.787[/tex]
[tex]w_e=1.787[/tex] is extracted with 60ml solvent .
Therefore volume of solvent (y) that would be necessary to remove an additional 7.0g
[tex]V_{7.0}=\frac{60}{1.767}*7[/tex]
[tex]V_{7.0}=235.030ml[/tex]
[tex]V_{7.0}\approx 235ml[/tex]
Which of these compounds are molecular?
CBr4
FeS
P4O6
PbF2
Answer:
I think it's answer is P4O6
I hope it's helpful for you...
A student dissolves 10.7 g of lithium chloride (LiCl) in 300. g of water in a well-insulated open cup. He then observes the temperature of the water rise from 22.0 °C to 28.6 °C over the course of 3.8 minutes. Use this data, and any information you need from the ALEKS Data resource:
LiCl(s) rightarrow Li+(aq) + Cl-(aq)
You can make any reasonable assumptions about the physical properties of the solution. Note for advanced students: it's possible the student did not do the experiment carefully, and the values you calculate may not be the same as the known and published values for this reaction.
1) Is this reaction exothermic, endothermic, or neither?
2) If you said the reaction was exothermic or endothermic, calculate the amount of heat that was released or absorbed by the reaction in this case.
3) Calculate the reaction enthalpy delta Hrxn per mole of LiCl.
Answer:
1) Exothermic.
2) [tex]Q_{rxn}=-8580J[/tex]
3) [tex]\Delta _rH=-121.0kJ/mol[/tex]
Explanation:
Hello there!
1) In this case, for these calorimetry problems, we can realize that since the temperature increases the reaction is exothermic because it is releasing heat to solution, that is why the temperature goes from 22.0 °C to 28.6 °C.
2) Now, for the total heat released by the reaction, we first need to assume that all of it is absorbed by the solution since it is possible to assume that the calorimeter is perfectly isolated. In such a way, it is also valid to assume that the specific heat of the solution is 4.184 J/(g°C) as it is mostly water, therefore, the heat released by the reaction is:
[tex]Q_{rxn}=-m_{Total}C(T_2-T_1)\\\\Q_{rxn}=-(300g+10.7g)*4.184 \frac{J}{g\°C} (28.6\°C-22.0\°C)\\\\Q_{rxn}=-8580J[/tex]
3) Finally, since the enthalpy of reaction is calculated by dividing the heat released by the reaction over the moles of the solute, in this case LiCl, we proceed as follows:
[tex]\Delta _rH=\frac{Q_{rxn}}{n_{LiCl}} \\\\\Delta _rH=\frac{-8580J}{10.7g*\frac{1mol}{150.91g} }*\frac{1kJ}{1000J} \\\\\Delta _rH=-121.0kJ/mol[/tex]
Best regards!
calculate the difference in slope of the chemical potential against temperature on either side of the normal freezing point of water and the normal boiling point of water the molar entropy change accompanying fussion is 22.0 and that accompanying evaporation
Answer:
(a) The normal freezing point of water (J·K−1·mol−1) is [tex]-22Jmole^-^1k^-^1[/tex]
(b) The normal boiling point of water (J·K−1·mol−1) is [tex]-109Jmole^-^1K^-^1[/tex]
(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is 109J/mole
Explanation:
Lets calculate
(a) - General equation -
[tex](\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p[/tex] = [tex]-5_m(\beta )+5_m(\alpha )[/tex] = [tex]-\frac{\Delta H}{T}[/tex]
[tex]\alpha ,\beta[/tex] → phases
ΔH → enthalpy of transition
T → temperature transition
[tex](\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p[/tex] =[tex]= -\frac{\Delta_fH}{T_f}[/tex]
= [tex]\frac{-6.008kJ/mole}{273.15K}[/tex] ( [tex]\Delta_fH[/tex] is the enthalpy of fusion of water)
= [tex]-22Jmole^-^1k^-^1[/tex]
(b) [tex](\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}[/tex]
= [tex]\frac{40.656kJ/mole}{373.15K}[/tex] ([tex]\Delta_v_a_p_o_u_rH[/tex] is the enthalpy of vaporization)
= [tex]-109Jmole^-^1K^-^1[/tex]
(c) [tex]\Delta\mu =\Delta\mu(l)-\Delta\mu(s)[/tex] =[tex]-S_m\DeltaT[/tex]
[tex][\mu(l-5[/tex]°[tex]C)-\mu(l,0[/tex]°[tex]C)][/tex] = [tex][\mu(s-5[/tex]°[tex]C)-\mu(s,0[/tex]°[tex]C)][/tex][tex]=-S_m[/tex]ΔT
[tex]\mu(l,-5[/tex]°[tex]C)-\mu(s,-5[/tex]°[tex]C)=-Sm\DeltaT [\mu(l,0[/tex]
[tex]\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)[/tex]
= 109J/mole
Is chemistry required to get into speech language pathology?
Answer:
As of right now (4-7-2021), the physical science requirement for the SLP certificate must be met by completing coursework in the areas of either chemistry or physics.
2. Some nitrogen at a pressure of 35.75 p.s.i is in a 100 L container. If the container's volume is reduced to 2250 ml then what is the resulting pressure?
Answer:
1455.6
Explanation: you first convert 2250ml to l by dividing by 1000 so you get 2.25l then you use Boyles law which is p1v1=p2v2 then insert values
35.75*100=p2*2.25 then divide both sides by 2.25 then you get 1455.6
Convert 8.19 x 10-14 moles of gold to atoms.
Answer:
4.932018 × 10¹⁰ atoms
Explanation:
Recall that:
1 mole = 6.022 × 10²³ atoms
To change 8.19× 10⁻¹⁴ moles to atoms;
Then, we have:
= (8.19× 10⁻¹⁴× 6.022 × 10²³ atoms)
= 4.932018 × 10¹⁰ atoms
visible light travels from place to place as a
Answer:
Light can travel in three ways from a source to another location: (1) directly from the source through empty space; (2) through various media; (3) after being reflected from a mirror.
Explanation:
An organic compound which has the empirical formula CHO has an approximate
molar mass of 145 g/mol. What is its probable molecular formula?
Answer:
Molecular formula => C₅H₅O₅
Explanation:
From the question given above, the following data were obtained:
Empirical formula = CHO
molar mass of compound = 145 g/mol
Molecular formula =?
The molecular formula of the compound can be obtained as follow:
Molecular formula = Empirical formula × n
Molecular formula = [CHO]ₙ
[CHO]ₙ = 145
[12 + 1 + 16]n = 145
29n = 145
Divide both side by 29
n = 145 / 29
n = 5
Molecular formula = [CHO]ₙ
Molecular formula = [CHO]₅
Molecular formula => C₅H₅O₅