Which is a disaccharide

Answer:

B. Herbicides

Explanation:

Nonnative species are species that are found outside their natural habitat. They are also called foreign species. They are introduced through the activities of man either deliberately or in-deliberately . They can be controlled by chemical, biological and mechanical means.

Mowing, net barriers and inspections are mechanical controls.

Biological control is the deliberate introduction of natural enemies of these nonnative/foreign species.

The use of herbicides is a chemical control of plants that grow where they are not wanted.

Answer:

Example of Chemical Control of Non-native species.

B) Herbicides

Explanation:

In the given options, all of them are can be used to remove or control non-native species. but among them only Herbicides is the chemical solution to control non-native species.

Herbicides are chemicals that are used to kill unwanted plants, which can be taken as non-native species.

Some of the herbicides kill the unwanted plants while leaving the desired crops unharmed, some interfere with the growth of such species while some kill all the plant material with which they come in contact with

Answer:

The moment when Minerva disguises Ulysses as an old beggar.

Explanation:

Answer:

45002

Explanation:

Answer:

Formula of the function is found:

[tex]H(t) = 8.5cos(\frac{2\pi}{3}(t-1.3))-35.5[/tex]

For t= 2.5s , vertical distance is:

H(2.5) = +42.38cm , H(2.5) = -42.38cm

Explanation:

General form of trigonometric function H(t) is given by:

[tex]H(t)=Acos(B(t-C))+D[/tex]

Where

A = Amplitude

Period = 3s = 2π/B

B = 2π/3

C = Phase shift = 1.3s

D = Vertical Shift

Find A (Amplitude):

Amplitude = (highest value - lowest value)/2

Amplitude = (-27-(-44))/2

Amplitude = (-27+44)/2

Amplitude = 8.5

Find D (Vertical Shift)

Vertical shift can be found by finding midpoint

Midpoint = (highest value + lowest value)/2

Midpoint = (-27-44)/2

Midpoint = -35.5

[tex]H(t) = 8.5cos(\frac{2\pi}{3}(t-1.3))-35.5[/tex]

which is the formula of the function

[tex]H(2.5)=8.5cos(\frac{2\pi}{3}(2.5-1.3))-35.5 \\H(2.5)= +42.38 {cm} ,H(2.5)=-42.38cm[/tex]

Answer:

The mean of the distribution is 4.00 and the standard deviation is 2.31

Explanation:

Given

Range = 2 to 10

Type of distribution = uniform distribution

Required

1. Mean

2. Standard Deviation

The mean of uniform distribution is calculated as thus;

[tex]Mean = \frac{1}{2}(a + b)[/tex]

Where b and a are the intervals of the distribution

b = upper bound = 10

a = lower bound = 2

So,

[tex]Mean = \frac{1}{2}(a + b)[/tex]

Substitute 10 for b and 2 for a

[tex]Mean = \frac{1}{2}(2 + 10)[/tex]

[tex]Mean = \frac{1}{2}(12)[/tex]

[tex]Mean = \frac{1}{2} * 12[/tex]

[tex]Mean = 6[/tex]

[tex]Mean = 6.00[/tex] (Approximated to 2 decimal places)

The standard deviation of uniform distribution is calculated as thus;

σ = √σ²

Where σ represents the standard deviation and σ² represents the variance.

Calculate variance

σ² = Var

[tex]Var = \frac{(b-a)^2}{12}[/tex]

Substitute 10 for b and 2 for a

[tex]Var = \frac{(10 - 2)^2}{12}[/tex]

[tex]Var = \frac{8^2}{12}[/tex]

[tex]Var = \frac{64}{12}[/tex]

[tex]Var = 5.33[/tex]

Recall that

σ = √σ² = √Var

Substitute 5.33 for Var

σ = √5.33

σ = 2.309401076758503

σ = 2.31 (Approximated)

Hence, the mean of the distribution is 4.00 and the standard deviation is 2.31

Complete question reads;

3. It's most accurate to say that hand-tied arrangements

A. are especially popular for weddings.

B. include only one or two floral materials.

C. are difficult to carry.

D. require a concealed water supply.

Answer:

B. include only one or two floral materials.

Explanation:

Remember, when flowers are been arranged by a florist consideration is made to allow for efficient handling. This involves using a few flower stems and constructing them using one’s hand to form the arrangement. The stems therefore would form a handle which could be held, thus only one or two floral materials are used.