Which units are used to express sound intensity?

Answer:

I think that is d option 1.0Nm anticlockwise

The correct answer is :

Mirror Parabola A mirror with a parabola-shaped reflecting surface is referred to as a parabolic mirror. The mirror is employed in search lights because it can precisely converge a broad parallel beam of light at the focus. Therefore, even at a great distance, the intensity of the reflected beam is unaffected.

Parabolic In search lights, concave mirrors with sizable apertures are utilized. For searching items in search light, we require a powerful parallel beam of light. The reflected rays from an object placed at a concave mirror's focus are parallel to one another and likewise parallel to the main axis. So, we position a light source at the concave mirror's focal point.

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Answer:

Work=force × distance

=45×15

=675

Explanation:

need thanks and make me brainiest if it helps you

Answer:

You need a motor and a battery

Explanation:

The currents through 4 ohm, 2 ohm and 5 ohm are 0.42 amp, 0.15 amp and 0.26 amp respectively.

Kirchhoff's Current Law states that no charge is lost and that the total current flowing into a junction or node equals the charge leaving it.

Kirchhoff's Voltage Law states that for any closed network, the voltage around a loop is equal to the total of all voltage drops in that loop and is equal to zero.

Let the current through 4 ohm is I₁.

the current through 2 ohm is I₂.

Applying Kirchhoff's Current Law, current through 5 ohm is I = I₁ + I₂.

Applying Kirchhoff's Voltage Law in two loops we get:

4 I₁ + 5(I₁+I₂) = 3

2I₂ + 5(I₁+I₂) = 1

Hence, I₁ = 0.42 amp

I₂ = - 0.15 amp

I₃ = 0.26 amp

Hence, the currents through 4 ohm, 2 ohm and 5 ohm are 0.42 amp, 0.15 amp and 0.26 amp respectively.

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The radiation pressure directed at normal incidence onto a perfectly reflecting sheet is 2.71 × 10⁻⁷ Pa

Given that a linearly polarized microwave of wavelength 1.50cm is directed along the positive x axis and the electric field vector has a maximum value of 175V/m and vibrates in the x y plane.

Also, assuming the magnetic field component of the wave can be written in the form B=Bmax sin (k x-Ω t) give values for (f) If this wave were directed at normal incidence onto a perfectly reflecting sheet, we desire to find the radiation pressure.

The radiation pressure for total reflection is given by P = 2I/c where

So, P = 2I/c

P = 2E²/2μ₀c ÷ c

P = E²/μ₀c²

Substituting the values of the variables intot he equation, we have

P = E²/μ₀c²

P = (175 V/m)²/[4π × 10⁻⁷ T/m × (3 × 10⁸ m/s)²]

P = 30625 V²/m²/[4π × 10⁻⁷ T/m × 9 × 10¹⁶ m²/s²]

P = 30625 V²/m²/[36π × 10⁹ Tm/s²]

P = 30625 V²/m²/113.097 × 10⁹ Tm/s²

P = 270.78 × 10⁻⁹ Pa

P = 2.7078 × 10⁻⁷ Pa

P ≅ 2.71 × 10⁻⁷ Pa

So, the radiation pressure directed at normal incidence onto a perfectly reflecting sheet is 2.71 × 10⁻⁷ Pa

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Answer:50kg

Explanation:

Answer:

There is a blue sky with clouds

There is cracks in the ground and the ground is brown

There is stuff in the dictance

Explanation:

Hope this helps

Simple pendulum takes 0.01 s to reach the maximum displacement from the equilibrium position, so it's frequency equals to 100 Hz

The time period of a simple pendulum: It is defined as the time taken by the pendulum to finish one full oscillation and is denoted by “T”. The amplitude of simple pendulum: It is defined as the distance travelled by the pendulum from the equilibrium position to one side.

The frequency of the pendulum defines how many times the pendulum moves back and forth in a specific period of time

time period of simple pendulum = 1 / frequency

given

time period = 0.01 second

frequency = 1 / 0.01

                 = 100 Hz

correct answer will be d) 100 HZ​

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Although not always practical, Ampere's law is true for all closed channels around a conductor. The integral can be calculated along many different paths, although it is difficult to do so. Think about a path that is circular but not coaxial with a long, straight wire that carries current. If the current in a conductor has enough symmetry to allow the line integral to be reduced to the size of B times an integral, Ampere's law can be used to calculate B.

Ampere's Law is applied to,

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Answer:

the larger-heavier would fall faster than lighter-smaller ball

Explanation:

Answer: Created Fall 2016 by Ronald Wilson Inductive reasoning uses a set of specific observations to reach an overarching conclusion; it is the opposite of deductive reasoning. So, a few particular premises create a pattern which gives way to a broad idea that is likely true.

Explanation: No explanation lol. But I hope this is helpful!

Answer:

100 foot

Explanation:

Using the formula for calculating range to calculate the speed first as shown;

U is the speed

theta is the observe angle

g is the acceleration due to gravity.

200 = U²sin 2(45)/9.8

Usin90 = 200 * 9.8

U² = 1960

U = √1960

U = 44.27 m/s

Get the required altitude

Altitude H = u²/2g

H = 44.27²/2(9.8)

H = 1,959.8329/19.6

H = 99.99 feet

Hence the altitude of the rocket to the nearest foot is 100 foot

Answer:

2m/s²

Explanation:

F = 12 N

m = 3kg

a = ?

F = ma

a = F/m = 12/3 = 4 m/s²

when m = 6kg

a = F/m = 12/6

a = 2 m/s²

The current in the load will be 10 A.

given,

resistance of the load (R) = 6.5Ω

voltage in the load (V) = 120V

Back emf in the load (E)= 108V

now to measure current we will use the formula

current (I)= {voltage (V)-Back emf (E)}/resistance(R)

now as the speed is halved so will the back electro motive force will be halved.

i.e.

back  electro motive force will be =  108V/2

=54V

now,

substituting this value in the formula we get,

current (I) = (120-54)/6.5

current (I) = 66/6.5

current (I) =10A

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It is proved that the speed of the light measured in the laboratory frame is , u =c/n(1+ nv/c)/(1+ v/nc) .

Given ,

The motion of a transparent medium influences the speed of light .

The water moves with speed v in a horizontal pipe .

Assume that the light travels in the same direction as the water moves .

The speed of the light with respect to the water is c/n

Where n = 1.33 is the refractive index of water .

Let us assume ,

u' be the speed of light in water , in the frame moving with the water .

u' is related to the refractive index of water ,n as :

u'=c/n

where , c is the speed of light .

let , u be the speed of light in water in the lab frame .

Now , u and u' are related as : u = (u'+ v )/(1+ u'v/c^2)

Here v is the speed of water in the horizontal pipe .

we know the value of u' , so by substituting the value , we will get ,

u= (c/n+ v)/(1+cv/nc^2)

u= c/n(1+ nv/c)/(1+v/nc)

Hence , it is proved that the speed of the light measured in the laboratory frame is , u =c/n(1+ nv/c)/(1+ v/nc) .

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Electron , photon and proton carry energy which is option (a) , (b) ,(c)

Photons are massless, but they have energy [tex]E = hv= \frac{hc}{\lambda}[/tex]

Here 'h' is called Planck's constant .

For electron and proton energy is given by

 [tex]E=\frac{1}{2} \times mv^2[/tex]

Where m is the mass of the particle and v is the speed of particle .

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Thomson could not observe any deflection of the beam due to gravitation.

Cathode ray refers to the beam of electrons that moves from the negatively charged cathode to the positive anode at the other end of the pipe.

J. J. Thomson demonstrated that the identical beam deflections produced tubes with cathodes composed of varied materials and containing a range of gases prior to evacuation.

The gravitational force is approximately 10⁴⁰.

The movement of the light beam shouldn't be impacted because it is 10²⁸ times weaker than the electric force.

Thomson was unable to detect any gravitational beam deflection.

Thus, Thomson could not observe any deflection of the beam due to gravitation.

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Electromagnetic force can not be considered because it very less as compared to gravitational force.

There are four types of Nuclear Forces :

1. Gravitational force

2. Electromagnetic force

3. Strong nuclear force

4. Weak nuclear force

The force acting between  the sun and the earth is gravitational force it is about

3.54 ×10²²N

Earth rotates around the sun because it is contained in the sun's gravitational field.

Due to the centripetal force Earth doesn't falls into  the sun.

Electromagnetic force can not be considered because it very less as compared to gravitational force. The electromagnetic force between two charged bodies is nearly equal to 10⁵N.

Electromagnetic force can not be considered because it very less as compared to gravitational force.

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Answer:

2.64 m/s

Explanation:

Given that a 600 kilogram great "yellow" shark swimming to the right at a speed of 3 meters traveled each second as it tries to get lunch. An unsuspecting 100 kilogram blue fin tuna is minding its own business swimming to the left at a speed of 0.5 meters traveled each second. GULP! After the great "yellow" shark "collides" with the blue fin tuna

Momentum = MV

Momentum of the yellow shark before collision = 600 × 3 = 1800 kgm/s

Momentum of the tun final before collision = 100 × 0.5 = 50 kgm/s

Total momentum before collision = 1800 + 50 = 1850 kgm/s

Let's assume that they move together after collision. Then,

1850 = ( 600 + 100 ) V

1850 = 700V

V = 1850 / 700

V = 2.64285 m/s

Therefore, the momentum of the shark after collision is 2.64 m/ s approximately

The aqueous humor in a person’s eye exerts a force of 0.295 n on the 1.15-cm2 area of the cornea pressure is this in mm Hg P = 2565.2173 N/m².

Pressure is defined as the normal force F per unit area A over which the force is applied or

P = F / A

Where :

P is the pressure acting on the cornea .

F if the force acting on the cornea .

A is the area of the cornea .

Givens : F = 0.3 N and A = 0.00011 m

Plugging known information to get :

P = F / A

P = 0.295 / 0.000115

P = 2565.2173

P =2565.2173 N/m²

The ciliary body produces aqueous humor, which travels along the uveoscleral pathway from the posterior chamber through the pupil and anterior chamber (shown by dashed lines and arrowheads) to the ciliary muscle and suprachoroidal region.

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I understand the question you are looking for :

suppose the aqueous humor in a person’s eye exerts a force of 0.295 n on the 1.15-cm2 area of the cornea. What pressure is this in mm Hg?

Answer:

You should weigh about 16 pounds.

Explanation:

To find this, you need to find your weight and divide it by 6 to find your weight on the moon.

Answer:

Ahmed did more work in lifting the weight than Omar.

Explanation:

Work done can be determined as the product of a force and the distance moved in the direction of the force.

Work done = F x s

In the given question, since the weight is lifted through a height, then the work done equals potential energy.

i.e Work done = Potential energy

                       = mgh

But,

Force = weight = mg

So that,

Work done = Fh

where F is the weight and h is the height.

i. Work done by Omar = Fh

                            = 200 x 2.0

                            = 400

Work done by Omar is 400 Nm.

ii. Work done by Ahmed = Fh

                                     = 200 x 2.1

                                     = 420

Work done by Ahmed is 420 Nm.

Thus, Ahmed did more work in lifting the weight than Omar.

Edwin Hubble was the astronomer which measured the motion of stars in the sky and is therefore denoted as option D.

This refers to an aspect of a science called natural science and is the study of celestial bodies such as the moon, stars etc and the different phenomena which occurs between them.

An astronomer called  Edwin Hubble was responsible for the measurement of the motion of stars through when he was in the process of the formulation of his law which involves the determination of distances to galaxies and quasars which is therefore the reason why option D was chosen as the correct choice.

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The distance to the Earth at the moment of the landing craft's launch as measured by the aliens is 0.16 light years.

To find the answer, we have to know about the Lorentz transformation.

It is given that, an alien spaceship traveling at 0.600 c toward the Earth, in the same direction the landing craft travels with a speed of 0.800 c relative to the mother ship. We have to find the distance to the Earth at the moment of the landing craft's launch as measured by the aliens.

        [tex]L=L_0\sqrt{1-\frac{V^2}{c^2} } =0.2ly\sqrt{1-\frac{(0.6c)^2}{c^2} }=0.2ly\sqrt{1-0.36}= 0.16ly[/tex]

Thus, we can conclude that, the distance to the Earth at the moment of the landing craft's launch as measured by the aliens is 0.16 light years.

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Answer:   The greatest force of gravity on the ball will occur at the point when the ball is near to hit the ground ... hope this helps have a good day :P

The correct answer is FM-MF

The crust of the Earth does not naturally contain ferromium. The heaviest element that can be created by neutron bombardment of lighter elements, fermium was first discovered in December 1952 by American scientists from the Argonne National Laboratory near Chicago, Illinois, the Los Alamos National Laboratory in Los Alamos, New Mexico, and The University of California Laboratory in Berkeley. Fermium is the heaviest element that can be synthesized in macroscopic quantities.

We can prove this by saying that if a point's distance from another point is six units, then the distance between those two points will also be six units. Therefore, FM-MF

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Answer:

F = Δ(mv)/Δt = ma

Explanation:

Newton's second law states that the force exerted on an object is equal to the rate of change of its momentum.

Let F represent force and p momentum and p = mv where m = mass and v = velocity

This implies that F = Δp/Δt = Δ(mv)/Δt if the mass is constant, we have

F = mΔv/Δt and we know that acceleration, a = Δv/Δt

So, F = ma which is Newton's second Law.