A cylindrical specimen of this alloy 12 mm in diameter and 188 mm long is to be pulled in tension. Assume a value of 0.34 for Poisson's ratio.Calculate the stress (in MPa) necessary to cause a 0.0105 mm reduction in diameter.

Answer:

45.32%

Explanation:

Given data:

pressure of high temperature steam = 6 MPa

low temperature heat rejection process ( Tr )  = 300 k

A) plot of cycle in t-s coordinates showing steam dome

attached below

B) Calculate thermal efficiency

thermal efficiency = 1 - (Tr / Tsat )

Tsat = 275.59°C  ≈  548.59 K  ( from steam table at Pa = 6 MPa )

back to equation 1

1 - (300 / 548.59 )

1 - 0.5468 = 0.4532 = 45.32%

Answer:

Two identical containers each of volume V 0 are joined by a small pipe. The containers contain identical gases at temperature T 0 and pressure P 0 .One container is heated to temperature 2T 0 while maintaining the other at the same temperature. The common pressure of the gas is P and n is the number of moles of gas in container at temperature 2T 0

Explanation:

Answer: Diagram associated with your question is attached below

5) B

6) C

Explanation:

5) The pin support at A allows ; Rotation about its central axis  

This is because pin supports does not allow the translation of its structural member in any direction i.e. y or x but only rotation about its axis

6)  The support at B does not allow displacement in y direction

This is because roller support allows displacement only in the direction that they are situated and in this case it is the x - direction

Answer:

c.Both A and B.

Explanation:

the wattage is c and d

Answer:

true

Explanation:

the answer is true because if u don't have a valid license when operating a vehicle and you get pulled over you will get in trouble i know this because my parents got in trouble for it once

Answer:

15x

Explanation:

Answer:

0.05%

Explanation:

From the question, we have;

The yield strength of the mild steel, [tex]\sigma _c[/tex] = 43.5 ksi

Young's modulus of elasticity, ∈ = 29,000 ksi

The total strain, [tex]\epsilon _c[/tex] = 0.2% = 0.002

The inelatic strain [tex]\epsilon_c^{in}[/tex] is given as follows;

[tex]\epsilon_c^{in}[/tex] = [tex]\epsilon _c[/tex] - [tex]\sigma _c[/tex]/∈

Therefore, we have;

[tex]\epsilon_c^{in}[/tex] = 0.002 - 43.5/(29,000) = 0.0005

Therefore, the inelastic strain, [tex]\epsilon_c^{in}[/tex] = 0.0005 = 0.05%

Taking the inelastic strain as the residual strain, we have;

The residual strain = 0.05%

Answer: Cleaning of mechanical parts is necessary to remove contaminants, and to avoid clogging of wastes which could restrict the functioning of the machine.

Explanation:

There are different agents used for cleaning different machine instruments to prevent their corrosion and experience proper cleaning.

Backing plates must be dry cleaned using a cotton cloth to remove the dirt, dust or any other dry contaminant.

Struts can be wet cleaned by applying alcoholic solvent.

Levers can be cleaned using a mineral spirit.

Metallic plates can be cleaned using water based solution or water.

Answer:

Attached below

Explanation:

Attached below is the schematic diagram of a small cube representing volume of material and all the six independent components of strains that will determine the state of strain  

Note : Attached below is a free hand diagram of the cube indicating the six independent components of strains  and a screen shot of the change in shape produced by each of the normal strain and shear strain components

( drawn with online tools )

Answer:

hi = 7026.8  W/m^2.k

Explanation:

Given data :

pressure of saturated steam = 1.2 bar

Horizontal steel pipe : inside diameter = 0.620 , outside diameter = 0.750 inches

temperature of water at entry = 60°F

temperature of water at exit = 75°F

velocity of water = 6 ft/s

Calculate the Inside convective heat transfer coefficient ( hi )

mean temperature ( Tm ) = 60 + 75 / 2 = 67.5°F ≈ 292.877 K ≈ 19.727°C

next : find the properties of water at this temperature ( 19.727°C )

thermal conductivity = 0.598  w/m.k

density = 1000 kg/m^3

specific heat ( Cp ) = 4.18 KJ/kg.k

viscosity = 0.001 pa.s

velocity of water = 6 ft/s ≈ 1.8288 m/s

∴ Re ( Reynolds number ) = 28712.16

and Prandtl number ( Pr ) = (4180 * 0.001) / 0.598  = 6.989

finally to determine the inside convective heat transfer coefficient we will apply the Dittos - Bolter equation

hi = 7026.8 w/m^2.k

attached below is the remaining solution

Answer:

the correct distance is 202 ft

Explanation:

The computation of the correct distance is shown below:

But before that correction to be applied should be determined

= (101 ft - 100 ft) ÷ (100 ft) × 200 ft

= 2 ft

Now the correct distance is

= 200 ft +  2 ft

= 202 ft

Hence, the correct distance is 202 ft

The same would be relevant and considered too

Answer:

industrial engineering

Explanation:

Answer:

(i) [tex]\frac{2}{3}[/tex][tex]\pi[/tex]rh

(ii) [tex]\frac{16}{3}[/tex][tex]\pi[/tex]

Explanation:

Given:

V = [tex]\frac{1}{3}[/tex][tex]\pi[/tex]r²h

Where;

V = volume of a right circular cone.

r = radius of the cone

h = height of the cone.

(i) The rate of change of V with respect to r if r changes and h remains constant is [tex]\frac{dV}{dr}[/tex], and is given by finding the differentiation of V with respect to r as follow:

[tex]\frac{dV}{dr}[/tex] = [tex]\frac{d}{dr}[/tex][[tex]\frac{1}{3}[/tex][tex]\pi[/tex]r²h]

[tex]\frac{dV}{dr}[/tex] = [tex]\frac{2}{3}[/tex][tex]\pi[/tex]rh     --------------------(i)

(ii)

Given;

h = 2

r = 4

Substitute these values into equation (i) as follows;

[tex]\frac{dV}{dr}[/tex] = [tex]\frac{2}{3}[/tex][tex]\pi[/tex](4 x 2)

[tex]\frac{dV}{dr}[/tex] = [tex]\frac{2}{3}[/tex][tex]\pi[/tex](8)

[tex]\frac{dV}{dr}[/tex] = [tex]\frac{16}{3}[/tex][tex]\pi[/tex]

[tex]\frac{dV}{dr}[/tex] = [tex]\frac{16}{3}[/tex][tex]\pi[/tex]

A right circular cone is one where the axis of cones is the line connecting the vertex to circular base's midway, the volume of right circular cone as follows:

Formula:

[tex]V = \frac{1}{3} \pi r^2h[/tex]

Where;

V = right circular cone volume  

r = Cone radius.

h = Cone height.

The calculation for part 1:

[tex]\frac{dV}{dr}[/tex] is indeed the rate of change of V with reference to r when r changes but h remains constant, and it is calculated via calculating the differentiation of V with respect to r as follows:

[tex]\to \frac{dV}{dr} =\frac{d}{d}r [ \frac{1}{3} \pi r^2h] =\frac{2}{3} \pi r h[/tex]

The calculation for part 2:

When  h = 2  and r = 4 then substituting the value into the part 1 equation then:

[tex]\to \frac{dV}{dr} = \frac{2}{3} \pi (4 \times 2) = \frac{2}{3} \pi (8) = \frac{16}{3} \pi[/tex]

Find out more about the volume here:

brainly.com/question/24086520

Answer:

newspaper, radio, televison

Explanation:

had avid in 7th :)

Answer:

1. will help for colcollares.

2. gives you money for studies

3. helps you choose the perfect collage

Answer:

Which option identifies the step of the implementation phase represented in the following scenario?

A company in the gaming industry decides to integrate movement controls in its newest hardware release. It sends an online survey to interactive gamers to identify their highest priorities.

establishing a process and budget

using communication tools

building and assembling a team

setting up a change order process

Explanation:

#carryonml

Answer:

using communication tools

Explanation:

The correct answer is using communication tools. Communication tools such as online surveys help project teams identify customers’ wants and needs.

Answer:

1791 secs  ≈ 29.85 minutes

Explanation:

( Initial temperature of slab )  T1 = 300° C

temperature of water ( Ts ) = 25°C

T2 ( final temp of slab ) = 50°C

distance between slab and water jet = 25 mm

Determine how long it will take to reach T2

First calculate the thermal diffusivity

∝  = 50 / ( 7800 * 480 ) = 1.34 * 10^-5 m^2/s

next express Temp as a function of time

T( 25 mm , t ) = 50°C

next calculate the time required for the slab to reach 50°C at a distance of 25mm

attached below is the remaining part of the detailed solution

Answer:

No,  it is not a periodic Signal

Explanation:

No,  it is not a periodic Signal

This signal is repeating itself with the fixed on and off values but the major point to note here is that is this signal repeating after a fixed length of time every time. No, such information is provided in the question and hence, this signal cannot be termed as periodic.

Answer:

reduced cost, faster marketing, and process transparency

Explanation:

The correct answer is reduced cost, faster marketing, and process transparency. PLM software helps coordinate tasks during implementation.

Answer:

In the absence of dark energy, a flat universe expands forever but at a continually decelerating rate, with expansion asymptotically approaching zero; with dark energy, the expansion rate of the universe initially slows down, due to the effects of gravity, but eventually increases, and the ultimate fate of the universe ...

Explanation:

I think it goes on forever.

Answer:

a) 0.347 mm

b)  - 0.0126 mm

Explanation:

Diameter of metal bar = 19.9 mm

length = 186 mm = 0.186 m

Tension force = 42600 N

elastic modulus = 67.1 GPa

Poisson's ratio = 0.34

a) calculate the amount by which the specimen will elongate

first calculate the area of metal bar

Area = πd^2 / 4 = π/4 ( 19.9 )^2  = 3.11 * 10^-4 m^2

Elongation ( E ) = б / e = P/A * L / ΔL

and ΔL = PL / AE

hence the elongation ( ΔL) = [ (42600 * 0.186 ) / ( 3.4*10^-4 *  67.1 * 10^9 ) ]

                                            = 3.47 * 10^-4 m ≈ 0.347 mm

b) Calculate the change in diameter of specimen

μ = -( Δd / d) / ( ΔL/L )

0.34 = - (Δd / 19.9 ) / ( 0.347 / 186 )

∴ Δd = 0.34 * 0.00186 * 19.9  = - 0.0126 mm

Answer:

hello your question poorly written attached below is the well written question

answer : ∅[tex]( \frac{Pg}{Pa} , \frac{h}{d})[/tex][tex]( \frac{p_{g} }{p_{a} } , \frac{h}{d} )[/tex]

Explanation:

Develop a set of pi terms that could be used to describe the problem

attached below is the required solution

Answer

a) 62 percent

b) 40 percent

Explanation:

Original diameter ( d[tex]_{i}[/tex] ) = 10.33 mm

Original Gauge length ( L[tex]_{i}[/tex] ) = 52.8 mm

diameter at point of fracture ( d[tex]_{f}[/tex] ) = 6.38 mm

New gauge length ( L[tex]_{f}[/tex] ) = 73.9 mm

Calculate ductility in terms of

a) percent reduction in area

percentage reduction = [ (A[tex]_{i}[/tex] - A[tex]_{f}[/tex] ) / A[tex]_{i}[/tex] ] * 100

A[tex]_{i}[/tex] ( initial area ) = π /4 di^2

= π /4 * ( 10.33 )^2 = 83.81 mm^2

A[tex]_{f}[/tex] ( final area ) = π /4 df^2

= π /4 ( 6.38)^2 = 31.97 mm^2

hence : %reduction = ( 83.81 - 31.97 ) / 83.81

= 0.62 = 62 percent

b ) percent elongation

percentage elongation = ( L[tex]_{f}[/tex] - L[tex]_{i}[/tex] ) / L[tex]_{i}[/tex]

= ( 73.9 - 52.8 ) / 52.8 = 0.40 = 40 percent

Answer:

D. Categorizing

Explanation:

pls mark me as your brainlist

Answer:

D

Explanation:

the picture is blank for me what does it say i can comment the answer plz mark brainlyist

Answer:

Explanation:

The missing diagram is attached in the image below which shows the deformation map of the Tungsten.

Given that:

Stress  level [tex]\sigma = 160 MPa[/tex]

T = 0.5 Tm

[tex]\implies \dfrac{T}{Tm} = 0.5[/tex]

G = 160 GPa

[tex]\implies \dfrac{\sigma}{G} = 10^{-3}[/tex]

a)

The regulating creep mechanism is dislocation driven, as we can see from the deformation mechanism.

The engineer's recommendation would not be approved because increasing grain size results in a decrease in the grain-boundary count, preferring dislocation motion. The existence of grain borders is a hindrance to dislocation motion, as the dislocation principle explicitly states. To stop the motion, we'll need a substance with finer grains, which would result in more grain borders, or a material with higher pressure. In the case of Nabarro creep, which is diffusion-driven, an engineer's recommendation would be useful.

b)

If stress level reduced to [tex]\sigma = 1.6 MPa[/tex]

[tex]\implies \dfrac{\sigma }{G} = 10^{-5}[/tex]

Cable creep is now the controlling creep mode, which entails tension-driven atom diffusion along grain borders to elongate grain along the stress axis, a process known as grain-boundary diffusion. Cable creep is more common in fine-grained materials. As a result, the engineer's advice would succeed in this case. The affinity for cable creep is reduced when the grain size is increased.

c)

From the map of creep mechanism for [tex]\dfrac{\sigma}{G} = 10^{-3} \ and \ \dfrac{T}{Tm} = 0.5[/tex]

We read strain rate [tex](e) = 10^{-6}/sec[/tex]

Therefore,

[tex]Strain (E) = e * \Delta t[/tex]

[tex]= 10^{-6} \times 10000 \times 3600[/tex]

= 36

Therefore, [tex]\Delta L = E \times Li[/tex]

= [tex]36 * 10 cm[/tex]

= 360 cm

Thus, the increase in length = 360 cm

Answer:

i) 796.18 N/mm^2

ii) 1111.11 N/mm^2

Explanation:

Initial diameter ( D ) = 12 mm

Gage Length = 50 mm

maximum load ( P ) = 90 KN

Fractures at =  70 KN

minimum diameter at fracture = 10mm

Calculate the engineering stress at Maximum load and the True fracture stress

i) Engineering stress at maximum load = P/ A

= P / [tex]\pi \frac{D^2}{4}[/tex]  = 90 * 10^3 / ( 3.14 * 12^2 ) / 4

= 90,000 / 113.04 = 796.18 N/mm^2

ii) True Fracture stress =  P/A

= 90 * 10^3 / ( 3.24 * 10^2) / 4

= 90000 / 81  =  1111.11 N/mm^2

Answer:

hello the figure attached to your question is missing attached below is the missing diagram

answer :

i) 1.347 kW

ii) 1.6192 kW

Explanation:

Attached below is the detailed solution to the problem above

First step : Calculate for Enthalpy

h1 - hf = -3909.9 kJ/kg ( For saturated liquid nitrogen at 600 kPa )

h2- hg = -222.5 kJ/kg ( For saturated vapor nitrogen at 600 kPa )

second step : Calculate the rate of heat transfer in boiler

Q1-2 = m( h2 - h1 )  = 0.008( -222.5 -(-390.9) = 1.347 kW

step 3 : find the enthalpy of superheated Nitrogen at 600 Kpa and 280 K

from the super heated Nitrogen table

h3 = -20.1 kJ/kg

step 4 : calculate the rate of heat transfer in the super heater

Q2-3 = m ( h3 - h2 )

        = 0.008 ( -20.1 -(-222.5 ) = 1.6192 kW

Answer:A

Explanation:The minimum level of education required to become an electrician is a high school diploma or equivalency degree, like the General Education Diploma (GED). This educational step is important on the journey to becoming an electrician because the high school curriculum covers the basic principles used on the job.

Answer:

Tack coat is a sprayed application of an asphalt binder upon an existing asphalt or Portland cement concrete pavement prior to an overlay, or between layers of new asphalt concrete.

Explanation:

Answer:

The issues related to the privacy are:

1. Informational privacy

2. Discrimination factors

3. Biased grouping on the basis of Data mining

4. Lack of consent

5. Morally wrong

6. Illegal distribution of information risks

7. Possibility of threat to life

Let's look at some major concerns:

1. Informational privacy : The concept of privacy of the personal information is totally nullified when the information is being used for a purpose other than the intended one for which it was given. This unethical use of information even for general purposes is not correct and is a matter of concern. It is more like using the sensitive data of others for personal benefit which is purely objectionable and raises security issues. Sometimes the data is also shared with the potential employers which might have certain impacts we are unaware of.

2. Data mining issues : The process of using a certain information to arrive and understand the trend and outcomes is called data mining. In this case, the consumer's data undergoes grouping and might get placed in the wrong group rather than the actual one. Also, there can be a case of biasing towards the groups which are not be focused on, or are not a part of the intended audience. This leads to the discrimination factors if we see it from a social point of view.

3. Lack of consent : Use of information without the consent or awareness of the consumers raises concern over the business ethics followed by the company. No one deserves the right to misuse information for his personal benefits without any of its information to the consumer. It is morally wrong and againt the work ethics. Moreover, it raises trust issues between the two involved, and hence is socially unacceptable.Explanation: