Answer:
1.5m/s2
Explanation:
F=ma
a=F/m
a=15/10
a=1.5m/s2
if the resistance of a car headlight is 15 ohm and the current through it is 0.60, what is the voltage across the headlight?
Answer:
9 volts (assuming 0.60 is in Amperes)
Explanation:
Recall that Ohms law can be expressed as
V = IR, where
V = voltage,
I = current (given as 0.6. I'm going to assume that the units is Amperes because it is not given)
R = resistance (given as 15 ohm)
substituting the above values into the formula
V = IR
V = (0.6)(15)
V = 9 Volts
describe three factors that influence the location of rural settlement
Explanation:
presence of food, water ,etc
Explanation:
here is five all you have to do is just pick
A car accelerates from 10m/s to 20m/s over a distance of 80m. What is its acceleration?
Answer:
0.125m/s^2
Explanation:
20-10=10
10 divided by 80=0.125m/s^2
The average velocity of the car is 15 m/s. The time taken to travel over the distance with this velocity is 5.3 seconds. Then the acceleration of the car is 1.8 m/s².
Wat is acceleration ?Acceleration is a physical quantity measuring the rate of change in velocity of a moving object. Like velocity, acceleration is a vector quantity having magnitude and direction.
Acceleration is the ratio of change in velocity to the change in time.
a = Δv/Δt
Given, the car is accelerating from 10 to 20 m/s. Hence, it travelled with average velocity of 15 m/s over the distance of 80 m.
Then , time taken = distance/velocity
t = 80 m/15 m/s = 5.3 s
Acceleration = Δv/t = (20 -10 m/s) /5.3 s = 1.8 m/s².
Therefore, the acceleration of the car is about 1.8 m/s².
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GENTE ME AJUDEM NESTA QUESTÃO POR FAVOR, TENHO PROVA ONLINE AMANHÃ! "Um sonar de um navio de pesca localizou um cardume de sardinhas a 300 m de profundidade. Sabendo que a velocidade de propagação do som na água tem o valor de 1500 m/s, calcula o tempo que decorre desde a emissão dos ultra-sons e a sua receção no navio." Por favor!
Answer:
The time between the emission of the wave and it's reception was 0.4 seconds.
Explanation:
The sound wave emitted by the sonar traveled from the boat to the fishes and came back, therefore the distance of it's total route is twice the distance from the boat to the fishes. We can apply the average speed formula in order to solve this problem, this is done below:
[tex]\text{speed} = \frac{\text{distance}}{\text{time}}[/tex]
We were given the distance traveled by the wave and it's speed, therefore we can solve for the time:
[tex]\text{time} = \frac{\text{distance}}{\text{speed}}\\\\\text{time} = \frac{(2*300)}{1500}\\\\\text{time} = \frac{600}{1500} = 0.4 \text{ s}[/tex]
The time between the emission of the wave and it's reception was 0.4 seconds.
How did Einstein’s and Newton’s theories differ in terms of explaining the cause of gravity?
Newton's law of universal gravitation doesn't say anything about the cause of gravity.
Einstein's theory of relativity does.
4 answers. Anyone know?
Answer:
lift
weight
thrust
air resistance
Explanation:
plz mark me as brainliest
Answer: Upthrust, lift, air resistance, and thrust
Explanation:
All of these 4 elements are taken into account during the design and creation of a plane.
Which of the following machines most likely has the greatest efficiency?
a
A. Airplane
B. Automobile
C. Bicycle
D. Human body
A 1380 kg car starts from rest at the top of a 28.0 m long hill inclined at 11.00 degrees. Ignoring friction, how fast is it going when it reaches the bottom of the hill?
Answer:
10.2 m/s
Explanation:
Using conservation of energy:
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)
v = 10.2 m/s
The velocity when car reaches the bottom of the hill is 10.2 m/s.
What is mechanical energy?The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.
M.E = KE +PE
M.E = ½ mv² + mgh
where g is the acceleration due to gravity, v is the velocity, m is the mass and h is the height of the object.
Given is a 1380 kg car starts from rest at the top of a 28.0 m long hill inclined at 11.00 degrees.
Using conservation of energy principle, we have
PE = KE
mgh = ½ mv²
v = √(2gh)
Substitute the values, we get
v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)
v = 10.2 m/s
Thus, the velocity when car reaches the bottom of the hill is 10.2 m/s.
Learn more about mechanical energy.
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If kinetic energy of a body is increased by 125%, the percentage increase in Momentum is?
Answer:
50 %
Explanation:
It's Fifty percent
The gravitational force between two students sitting beside each other on Earth is
Answer:
Fgrav. = GM1×M2/R2
Explanation:
Gravitational force is mostly related
to planetary bodies by Newton's law of gravitation which states that the gravitional force is proportional to the product of the mass of the object and inversely proportional to the square of the distance between them.
Hence in this case the Gravitational force,
Fgrav. = GM1×M2/R2
M1 and M2 are the mass of the two students and R is their distance apart
G is a constant known as gravitational constant.6.67408 × 10-11 m3/kgs2
how many chromosomes does an elephant's egg cell have ?
Answer:
Diploid is often noted as 2N where N is the number of chromosomes. So in humans 2N=46. During sexual reproduction, the sex cells of parent organisms unite with one another and form a fertilized egg cell. In this situation, each sex cell is a gamete.
Explanation:
What’s the When the temperature increases the viscosity of the liquids ??? Hurry someone plz help
Answer:
Decreases
Explanation:
Viscosity is inversely proportional to temperature
i.e. η ∝ [tex]\frac{1}{T}[/tex]
Where η is coefficient of viscosity and T is temperature,
Which means that when temperature increases, viscosity decreases and vice versa.
When heat is converted into another form of energy, the total amount of energy is constant. Which law best illustrates this statement?
A.
the first law of thermodynamics
B.
the second law of thermodynamics
C.
the third law of thermodynamics
D.
none of the above
Answer:
A
Explanation:
This is the first law of thermodynamics and it's called the law of conservation of energy
can someone help what are the common branches of physics
Answer: Dear Buddy ,the common brnches os physics are given below:
Explanation:
Mechanics
Classical physics
Modern physics
Thermodynamics
Electricity
Magnetism
Geo physics
Plasma physics
Optics
Sound and oscillation
Electronics
Chemical physics
Engineering physics
Solid state physics
Quantum physics
Nuclear physics
Particle physics
Bio physics
Astrophysics
Condensed matter physics
hope it helps
Answer:
Engineering is one of branches that uses physics mainly the most
Explanation:
as for engineering requires mathematics and physics principles in their everyday routine to calculate and measure accordingly to manufactur a product.
At what wavelength would a star radiate the greatest amount of energy if the star has a surface temperature of 60,000 K?
Answer:
[tex]\lambda=4.81\times 10^{-8}\ m[/tex]
Explanation:
We have,
The surface temperature of the star is 60,000 K
It is required to find the wavelength of a star that radiated greatest amount of energy. Wein's displacement law gives the relation between wavelength and temperature such that :
[tex]\lambda T=2.89\times 10^{-3}[/tex]
Here,
[tex]\lambda[/tex] = wavelength
[tex]\lambda=\dfrac{2.89\times 10^{-3}}{60000}\\\\\lambda=4.81\times 10^{-8}\ m[/tex]
So, the wavelength of the star is [tex]4.81\times 10^{-8}\ m[/tex].
What observation about light supported Einstein’s theory?
Answer:
Explanation:
Do you mean the theory that space-time is defined by what's in it? And that mass warps space-time?
There are many instances where his observation turned out to be correct. The most popular one is the phenomena of gravitational lensing. We can see the light from stars that are actually behind the sun. The huge gravity of the sun bends space-time and this also bends light. We use gravitational lensing alllll the time when trying to see very distant stars or galaxies.
Answer:
The Sun bent the light from a star. This bending made the star appear in a slightly different position from its actual position. This observation supported Einstein’s theory.
Explanation:
This is the answer on Edmentum! :)
Question 3 of 5
2 Points
Which term refers to a transfer of thermal energy between objects?
A. Potential energy
B. Kinetic energy
C. Heat
D. Temperature
SUSMIT
Answer:
Explanation:
Kinetic energy
How can one find the mechanical advantage of a pulley?
Answer:
To calculate the mechanical advantage of a pulley you simply have to count the number of rope sections that support whatever object you are lifting (not counting the rope that is attached to the effort)
Example:
For example, in a one pulley system the MA is 1. In a two pulley system the MA is 2. The more compound the pulley is the easier the load is to lift. If you were lifting a 600kg object with 2 pulleys you would have to use enough effort to pull 300kg to lift the 600kg object! Therefore your mechanical advantage would be 2 (600/300).
MA= load/effort OR number of rope sections
A ball hits a wall horizontally at 6m/s and rebounces at 4.4m/s the ball is in contact with wall for 0.04 sec. what is the acceleration.
Answer:
Acceleration (a) = 40 m/s²
Explanation:
Given:
Initial velocity (u) = 6 m/s
Final velocity (v) = 4.4 m/s
Time taken (t) = 0.04sec
Find:
Acceleration (a) = ?
Computation:
We know that,
⇒ v = u + at
⇒ a = (v - u) / t
⇒ Acceleration (a) = (4.4 - 6) / 0.04
⇒ Acceleration (a) = (-1.6) / 0.04
Acceleration (a) = 40 m/s²
A wire is placed between the poles of a horseshoe magnet. There is a current in the wire in the direction shown, and this causes a force to act on the wire.
A sheet of paper 3.0 cm by 4.0 cm is lying on the desk. If the atmospheric pressure is 1.013105 Pa, what is the total force exerted on the top side of the paper by the atmosphere?
Answer:
132.56N
Explanation:
Pressure is defined as force per unit area.
Expressed mathematically as;
P = F/A
Where P-pressure
F-force
A-area
From the above formula,
F= P×A
= 1.1013 × 10^5 × (3×4/10000)
= 11.013×12 =132.56N
Note: the unit of measure in cm is converted to m and since 100cm makes 1m for each sides 3cm and 4cm we convert to 'm' by dividing by 100 twice giving division by 10000)
The unit of measure Pa means Pascal and is the same as N/m2
A rubber band that has been stretched has gained ____ energy
OA) heat
OB) kinetic
OC) potential
D) chemical
Answer: potential
Explanation:
What is the unit of work? Explain whether the unit of work is a fundamental uint
or derived unit
1.
What do you mean by a unit?
2.
unit or a derived unit.
are the fundamental units used in physics?
al Bureau of Weights and Me
Answer:
1)the unit of work is joule. 2)it is derived unit because it is made by two different unit force and displacement .3)
drawing is a form of
Answer:
visual art in which one uses to mark drawing and express feelings
Explanation:
In my own opinion. Hope it helps.
Please give me concept to solve this.
Answer:
The difference in tension, between adjacent sections of the pull cable at the given conditions is 17.701 kN
Explanation:
We take the cars as moving upwards such that the resultant pulling force on the car, F, along the cable is given by the relation
[tex]F_{car}[/tex] = Upward tension force, [tex]Tension_{(upwards)}[/tex] - Downward tension force, [tex]Tension_{(downwards)}[/tex] - Component of the weight of the car along the taut cable
The parameters given are;
Mass of car, m = 2750 kg
Angle of inclination of taut cables, θ = 35°
The upward acceleration of the car, a = 0.81 m/s²
Given that the weight is acting vertically downwards, we have;
Component of the weight of the car along the taut cable = m × g × sin(θ)
∴ Component of the weight of the car along the taut cable = 2750 × 9.81 × sin (35°) = 15473.66 N
We therefore have;
[tex]F_{car}[/tex] = [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] - 15473.66 N
[tex]F_{car}[/tex] = m × a = 2750 × 0.81 = [tex]T_{upwards}[/tex] - [tex]T_{downwards}[/tex] - 15473.66
∴ [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] = 2750 × 0.81 + 15473.66 = 17701.16 N
Hence the difference in tension, [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] between adjacent sections of the pull cable if the cars are at the maximum permissible mass and are being accelerated up the incline = 17701.16 N or 17.701 kN.
suppose that g (x) equals f (x + 1) - 3 which statement best compares the graph of g (x) with the graph of f (x)
Answer:
The graph of G(x) is the graph of F(x) shifted 1 unit to the left and 3 units down.
Explanation:
f(x + q) which is left q units
f(x - q) which is right q units
f(x) + q which is up q units
f(x) - q which down q nits
and
G(x) = F(x + 1) - 3
So,
f(x + 1) shifts to left 1 unit
f(x) - 3 shifts to down 3 units
So, the correct answer is B.
The graph of G(x) is the graph of F(x) shifted 1 unit to the left and 3 units down.
The graph shows the motion of a cyclist.
Calculate;
a) The acceleration in the first 20 s.
b) The acceleration between 20 and 30s.
c) The acceleration in the last 10 s.
d) The distance travelled by the cyclist when he was moving at a constant speed?
Show working.
Answer:
A. 0.5m/s².
B. –0.5m/s².
C. –0.5m/s².
D. 100m.
Explanation:
A. Determination of the acceleration in the first 20s.
Initial velocity (u) = 0
Final Velocity (v) = 10m/s
Time (t) = 20secs.
Acceleration (a) =..?
Acceleration = change in Velocity /time
a = (v – u)/t
a = (10 – 0)/20 = 10/20
a = 0.5m/s²
Therefore, the acceleration of the cyclist in the first 20secs is 0.5m/s²
B. Determination of the acceleration between 20 and 30s. This can be obtained as follow:
Initial velocity (u) = 10m/s
Final Velocity (v) = 5m/s
Time (t) = 30 – 20 = 10s
Acceleration (a) =..?
Acceleration = change in Velocity /time
a = (v – u)/t
a = (5 – 10)/10 = –5/10
a = –0.5m/s²
Therefore, the acceleration of the cyclist between the 20 and 30secs is
–0.5m/s².
C. Determination of the acceleration in the last 10s.
Initial velocity (u) = 5m/s
Final Velocity (v) = 0
Time (t) = 10s
Acceleration (a) =..?
Acceleration = change in Velocity /time
a = (v – u)/t
a = (0 – 5)/10 = –5/10
a = –0.5m/s²
Therefore, the acceleration of the cyclist between the last 10secs is
–0.5m/s².
D. Determination of the distance travelled by the cyclist when he was moving at a constant speed.
Velocity (v) = 5m/s
Time (t) = 50 – 30 = 20secs
Displacement (d) =?
Velocity = Displacement /Time
v = d/t
5 = d/20
Cross multiply
d = 5 x 20
d = 100m
Therefore, the distance travelled by the cyclist at constant speed is 100m
A car starts from rest and develops an acceleration of 2 m/s2. If the distance covered by the car during its motion is 100m, what is the final velocity attained by the car?
Answer:
20
Explanation:
because I am always right yo bro be like me
Mass is the amount of what
Answer:
Mass is the amount of matter in a substance.
Explanation:
The basic SI unit for mass is the kilogram (kg).
What is the force experienced when a 5.0 kg mass is accelerated at 7.5 m/s??
Answer:
F = 37.5 N
Explanation:
It is given that,
Mass of the object is 5 kg
Acceleration of the object is 7.5 m/s²
We need to find the force experienced by the object. The force is given by the product of mass and acceleration of an object. So,
F = m
[tex]F=5\times 7.5\\\\F=37.5\ N[/tex]
So, the force acting on the object is 37.5 N.