If a car travels 60 mph for a distance of 180 miles, how much time
did it take?

Answer:

Decrease the distance between the two objects.

Explanation:

The force (F) of attraction between two masses (M₁ and M₂) separated by a distance (r) is given by:

F = GM₁M₂ / r²

NOTE: G is the gravitational force constant.

From the equation:

F = GM₁M₂ / r²

We can say that the force is directly proportional to the masses of the object and inversely proportional to the square of the distance between them. This implies that an increase in any of the masses will increase the force of attraction and likewise, a decrease in any of the masses will lead to a decrease in the force of attraction.

Also, an increase in the distance between the masses will result in a decrease in the force of attraction and a decrease in the distance between the masses, will result in an increase in the force of attraction.

Considering the question given above,

To increase the gravitational force between the two objects, we must decrease the distance between the two objects as explained above.

Answer:

Decrease the distance between the two objects.

Explanation:

hit me wit that brainliest, please and thank you

Answer:

-16i kgm/s

Explanation:

Impulse I = m(v - u) where m = mass of ball = 2.0 kg, u = initial velocity of ball = (4i + 3j) m/s  and v = final velocity of ball = (-4i + 3j) m/s.

So, the impulse is thus

I = m(v - u)

= 2.0 kg[(-4i + 3j) m/s - (4i + 3j) m/s]

= 2.0 kg[(-4i - 4i) + (3j - 3j) m/s]

= 2.0kg[-8i + 0j] m/s

= -16i kgm/s

The impulse on a 2.0-kg ball with an initial velocity of (4i + 3j) m/s collides with a wall and rebounds with a velocity of (–4i + 3j) m/s = 16i

Impulse: This can be defined as change in momentum of a body. The s.i unit of impulse is kgm/s²

The formula of impulse is

I = m(v-u)................ Equation 1

Where, I = impulse exerted on the ball by the wall, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball

From the question,

Given: m = 2.0 kg, v = (-4i+3j) m/s, u = (4i+3j)  m/s

Substitute these values into equation 1

I = 2.0[(-4i+3j)-(4i+3j)

I = 2.0(-4i-4i+3j-3j)

I  = 2.0(-8i+0j)

I = -16i.

Hence the impulse exerted by the wall on the ball is -16i

Learn more about impulse here: https://brainly.com/question/22296861

Answer:

It is because there are a odd number of wavelengths fitting onto the string

Explanation:

The general formula for the harmonics on a string loose at one end is f = nv/2L where n = odd integer, v = speed of wave in string and L = length of string.

For a string loose at one end, there are a odd number of wavelengths which can fit onto the string. Since this is the case, we only have harmonics of odd numbers and thus we have even number harmonics missing.

Answer:

If you point your pointer finger in the direction the positive charge is moving, and then your middle finger in the direction of the magnetic field, your thumb points in the direction of the magnetic force pushing on the moving charge.

Explanation:

it’s right

Answer:

6.75 m/s²

Explanation:

The following data were obtained from the question:

Mass (m) of object = 40 Kg

Force applied (Fₐ) = 300 N

Force of friction (Fբ) = 30 N

Acceleration (a) =?

Next, we shall determine the net force acting on the mass. This can be obtained as follow:

Force applied (Fₐ) = 300 N

Force of friction (Fբ) = 30 N

Net force (Fₙ) =?

Fₙ = Fₐ – Fբ

Fₙ = 300 – 30

Fₙ = 270 N

Thus, the net force acting on the mass is 270 N.

Finally, we shall determine acceleration of the mass. This can be obtained as follow:

Mass (m) of object = 40 Kg

Net force (Fₙ) = 270 N

Acceleration (a) =?

Net force = mass × acceleration

Fₙ = m × a

270 = 40 × a

Divide both side by 40

a = 270 / 40

a = 6.75 m/s²

Therefore, the acceleration of the mass is 6.75 m/s²

Answer:

Mass of the man = 100 kg

Explanation:

Given that,

Mass of the Earth, M = 6×10²⁴ kg

The radius of the Earth, r = 6400 km

Force on man, F = 977 N

We need to find the mass of the man. Let the mass of the man be m. The gravitational force acting between two objects is given by :

[tex]F=G\dfrac{mM}{r^2}\\\\m=\dfrac{Fr^2}{GM}\\\\m=\dfrac{977\times (6400\times 10^3)^2}{6.67\times 10^{-11}\times 6\times 10^{24}}\\\\m=99.99\ kg[/tex]

or

m = 100 kg

So, the mass of the man is 100 kg.

Answer:

The total cost in petrol will be: RM 28.43

Explanation:

The distance to be covered is: 330 km

The car does 60 mi per 1 gallon

so we convert this into km per liter as

60 mi/gal = 60 * 1.61 / 4.5 = 21.47 km/liter

Then, if 1 liter is needed to cover 21.47 km, then to cover 330 km one would need:

330 / 21.47 liters = 15.37 liters

Since each liter costs RM 1.85, then the cost in gas will be:

1.85 * 15.37 = RM 28.43

Answer:

v = 22.58[m/s]  

Explanation:

To solve this problem we will use the principle of energy conservation, which tells us that potential energy is transformed into kinetic energy or vice versa.

[tex]E_{kin}=E_{pot}[/tex]

We must remember that potential energy is defined as the product of mass by gravity by height.

[tex]E_{pot}=m*g*h[/tex]

And the kinetic energy can be calculated by means of the following expression.

[tex]E_{kin}=0.5*m*v^{2}\\[/tex]

Now equalizing the two equations we can determine the initial velocity.

[tex]m*9.81*26=0.5*m*v^{2}\\255.06=0.5*v^{2}\\v=\sqrt{255.06/0.5}\\v=22.58[m/s][/tex]

Answer:

Images that are not aligned are laterally inverted

Explanation:

When a plane mirror reverses an image so that it becomes upside down and downside up or the other way round, we say that the image is laterally inverted.

Hence the effect produced when a plane mirror reverses an image is called lateral inversion

A good example of lateral inversion ins the lettering of an ambulance

Answer:

638 m.

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 94 m/s

Final velocity (v) = 22 m/s

Time (t) = 11 s

Distance (s) =?

We can obtain the distance travelled by using the following formula:

s = (u + v) t /2

s = (94 + 22) × 11 /2

s = 116 × 11 /2

s = 1276 /2

s = 638 m

Thus, the distance travelled is 638 m.

Answer:

Friction of the road on the motorcycle in the opposite direction

Explanation:

Khanacademy

Answer:1.1x10^3N upward

Explanation:

Answer:

The drum struck with a lot of energy would be louder than the drum struck with little energy because there is a harder impact on it

Explanation:

Answer:

The potential difference between the points is: 0.1 V

Explanation:

Given

To determine

The potential difference between the points is

We can use the formula to determine the potential difference between the points

[tex]V_A-V_B=\frac{W}{q_0}[/tex]

where W is done by moving charge q₀ from point A and point B

substituting W = 2J, and q₀ = 20 C

              [tex]=\frac{2}{20}[/tex]

               [tex]= 0.1[/tex] V

Therefore, the potential difference between the points is: 0.1 V

Answer:

300 m  

Explanation:

using constant acceleration equations:

v = vi + a * t, v = final velocity = 0m/s , vi =  initial velocity = 60m/s,

a = acceleration = -6m/s², t = time

solve t

t = 10s

x = vi * t + .5 * a * t²

plug

x = 300 m

Answer:

The Total Mechanical Energy

As already mentioned, the mechanical energy of an object can be the result of its motion (i.e., kinetic energy) and/or the result of its stored energy of position (i.e., potential energy). The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.

Explanation:

Answer:

Explanation:

I just need points

Answer:

Physicists use a hand mnemonic known as the right-hand rule to help remember the direction of magnetic forces. To form the mnemonic, first make an L-shape with the thumb and first two fingers of your right hand. Then, point your middle finger perpendicular to your thumb and index finger.

Answer:

If you point your pointer finger in the direction the positive charge is moving, and then your middle finger in the direction of the magnetic field, your thumb points in the direction of the magnetic force pushing on the moving charge.

Explanation:

Got it right

Answer:8.0 m/s^2

Explanation: The ball is traveling in uniform circular motion at the speed of 2 m/s in a path of the radius that is 0.50 meters.

v^2/r

2.0 m/s^2/ 0.50 m= 8.0 m/s^2

The magnitude of the ball's centripetal  acceleration is [tex]\rm 8 \;m/sec^2[/tex] and this can be determined by using the formula of the centripetal  acceleration.

Given :

A ball attached to a string is whirled at a constant speed of 2.0 meters per second in a horizontal circle of a radius of 0.50 meters.

The following steps can be used in order to determine the magnitude of the ball's centripetal  acceleration:

Step 1 - The formula of the centripetal acceleration can be used in order to determine the magnitude of the ball's centripetal  acceleration.

Step 2 - The formula of the centripetal acceleration is given below:

[tex]\rm a_c=\dfrac{v^2}{r}[/tex]

Step 3 - Substitute the values of the known terms in the above formula.

[tex]\rm a_c=\dfrac{2^2}{0.5}[/tex]

Step 4 - Simplify the above expression.

[tex]\rm a_c = 8\;m/sec^2[/tex]

For more information, refer to the link given below:

https://brainly.com/question/17689540

Answer:

The number of revolutions is 10.68 rev/min.

Explanation:

Given that,

Radius = 8 m

Suppose,  centripetal acceleration equal to the gravity

[tex]a_{c}=g=9.8[/tex]

We need to calculate the velocity

Using formula of centripetal acceleration

[tex]a_{c}=\dfrac{v^2}{r}[/tex]

[tex]v^2=a_{c}\times r[/tex]

Put the value into the formula

[tex]v=\sqrt{9.8\times8}[/tex]

[tex]v=8.85\ m/s[/tex]

We need to calculate the value of [tex]\omega[/tex]

Using formula of velocity

[tex]v=r\omega[/tex]

[tex]\omega=\dfrac{v}{r}[/tex]

Put the value into the formula

[tex]\omega=\dfrac{8.85}{8}[/tex]

[tex]\omega=1.12\rad/s[/tex]

We need to calculate the number of revolutions

Using formula of angular frequency

[tex]\omega=\dfrac{2\pi}{T}[/tex]

[tex]\omega=2\pi N[/tex]

[tex]N=\dfrac{\omega}{2\pi}[/tex]

Put the value into the formula

[tex]N=\dfrac{1.12}{2\pi}[/tex]

[tex]N=0.178\ rev/s[/tex]

Using conversion rev/s to rev/min

[tex]N=0.178\times 60[/tex]

[tex]N=10.68\ rev/min[/tex]

Hence,  The number of revolutions is 10.68 rev/min.

Answer:

The average power developed by a motor is 4905 Watts.

Explanation:

The average power is given by:

[tex] P = \frac{W}{t} [/tex]

Where:

W: is the work

t: is the time = 8.0 s

First, let's find the work:

[tex] W = F*d [/tex]

Where:

F: is the force

d: is the displacement = 10.0 m

The force is in the vertical motion, and since the movement of the mass is at constant speed the force is:

[tex] F = mg = 400 kg*9.81 m/s^{2} = 3924 N [/tex]

Hence, the average power is:

[tex] P = \frac{F*d}{t} = \frac{3924 N*10.0 m}{8.0 s} = 4905 J/s = 4905 W [/tex]                    

Therefore, the average power developed by a motor is 4905 Watts.

I hope it helps you!                  

The average power developed by a motor as it lifts the mass is 4,900 W.

The given parameters:

The average power developed by a motor as it lifts the mass is calculated as follows;

[tex]P = \frac{E}{t} \\\\P = \frac{mgh}{t} \\\\P = \frac{400 \times 9.8 \times 10}{8} \\\\P = 4,900 \ J/s[/tex]

Thus, the average power developed by a motor as it lifts the mass is 4,900 W.

Learn more about average power here:https://brainly.com/question/19415290

Answer:

500 N

Explanation:

Given that,

The upward force is 800 N and the downward forces are 400 N, 500 N, 400 N.

At equilibrium, the upward forces will become equal to the downward forces. Let the reading in the right hand scale.

x + 800 = 400 + 500 + 400

x + 800 = 1300

x = 1300 - 800

= 500 N

So, the reading in the right hand scale is 500 N.

Answer:

your answer is C

Explanation:

Answer:

GRAVITYYYYY

HOPE THIS HELPS

Answer: There is a net force acting on which is a force of gravity

Explanation:

Answer:

1.000 metre

Explanation:

I hope it's helpful