if a rock has a speed of 12 m/s as it hits the ground, from what height did it fall assuming the speed was zero.its mass is 50 kg

Answer:

imma have to come back to you on that one

Answer:

The Sun is at the center of the solar system and the planets move around it.

Explanation:pluto/edmentum

Answer:

(a) The package lands 682 meters horizontally ahead from the point the package was dropped from the plane

(b) The horizontal component = 39.0 m/s

The vertical component = 171.55 m/s

(c) The angle of impact is 77.19°

Explanation:

The parameters given are;

Velocity of the plane, vₓ = 39.0 m/s

Height of the plane above the ground, h = 1.50 × 10² m = 1,500 m

(a) The time, t, before the package hits the ground when dropped from the plane is given by the relation;

h = u·t + 1/2×g×t²

Where:

g = Acceleration due to gravity = 9.81 m/s²

u = Initial vertical velocity = 0 m/s

Hence;

1500 = 0×t + 1/2 × 9.81 × t² = 4.905·t²

∴ t = √(1500/4.905) = 17.49 s

The horizontal distance the package travels before landing = 17.49 × 39 ≈ 682 m

The package lands 682 meters horizontally ahead from the point the package was dropped from the plane

(b) The vertical velocity, [tex]v_y[/tex], of the package just before landing is given by the relation;

[tex]v_y[/tex]² = u² + 2·g·h

u = 0 m/s

∴ [tex]v_y[/tex]² = 0 + 2×9.81×1500 = 29430 m²/s²

[tex]v_y[/tex] = √29430  = 171.55 m/s

Hence the horizontal component = 39.0 m/s

The vertical component = 171.55 m/s

(c) The angle of impact, θ, is given as follows;

[tex]tan \theta = \dfrac{v_y}{v_x} = \dfrac{171.55}{39.0 } = 4.4[/tex]

∴ θ = tan⁻¹(4.4) = 77.19°.

Answer:

To calculate the mechanical advantage of a pulley you simply have to count the number of rope sections that support whatever object you are lifting (not counting the rope that is attached to the effort)

Example:

For example, in a one pulley system the MA is 1. In a two pulley system the MA is 2. The more compound the pulley is the easier the load is to lift. If you were lifting a 600kg object with 2 pulleys you would have to use enough effort to pull 300kg to lift the 600kg object! Therefore your mechanical advantage would be 2 (600/300).

               MA= load/effort OR number of rope sections

Answer:

F = 37.5 N

Explanation:

It is given that,

Mass of the object is 5 kg

Acceleration of the object is 7.5 m/s²

We need to find the force experienced by the object. The force is given by the product of mass and acceleration of an object. So,

F = m

[tex]F=5\times 7.5\\\\F=37.5\ N[/tex]

So, the force acting on the object is 37.5 N.    

Answer: 180 m south

Explanation:

The displacement of the horse in this time is 180 m south. The correct option is A.

The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.

Velocity is the time rate of change of displacement with time.

Given is a horse runs for 15 seconds to the south at a speed of 12 m/s. So, the displacement is

Displacement = Speed x Time

Put the values, we get

Displacement = 12 m/s x 15s

                      = 180 m

Thus, the displacement of the horse in this time is 180 m south.

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Answer:

9 volts (assuming 0.60 is in Amperes)

Explanation:

Recall that Ohms law can be expressed as

V = IR, where

V = voltage,

I = current (given as 0.6. I'm going to assume that the units is Amperes because it is not given)

R = resistance (given as 15 ohm)

substituting the above values into the formula

V = IR

V = (0.6)(15)

V = 9 Volts

Answer:

Fgrav. = GM1×M2/R2

Explanation:

Gravitational force is mostly related

to planetary bodies by Newton's law of gravitation which states that the gravitional force is proportional to the product of the mass of the object and inversely proportional to the square of the distance between them.

Hence in this case the Gravitational force,

Fgrav. = GM1×M2/R2

M1 and M2 are the mass of the two students and R is their distance apart

G is a constant known as gravitational constant.6.67408 × 10-11 m3/kgs2

Answer:

Explanation:

Do you mean the theory that space-time is defined by what's in it? And that mass warps space-time?

There are many instances where his observation turned out to be correct. The most popular one is the phenomena of gravitational lensing. We can see the light from stars that are actually behind the sun. The huge gravity of the sun bends space-time and this also bends light. We use gravitational lensing alllll the time when trying to see very distant stars or galaxies.

Answer:

The Sun bent the light from a star. This bending made the star appear in a slightly different position from its actual position. This observation supported Einstein’s theory.

Explanation:

This is the answer on Edmentum! :)

Answer:

Mass is the amount of matter in a substance.

Explanation:

The basic SI unit for mass is the kilogram (kg).

Answer:

The time between the emission of the wave and it's reception was 0.4 seconds.

Explanation:

The sound wave emitted by the sonar traveled from the boat to the fishes and came back, therefore the distance of it's total route is twice the distance from the boat to the fishes. We can apply the average speed formula in order to solve this problem, this is done below:

[tex]\text{speed} = \frac{\text{distance}}{\text{time}}[/tex]

We were given the distance traveled by the wave and it's speed, therefore we can solve for the time:

[tex]\text{time} = \frac{\text{distance}}{\text{speed}}\\\\\text{time} = \frac{(2*300)}{1500}\\\\\text{time} = \frac{600}{1500} = 0.4 \text{ s}[/tex]

The time between the emission of the wave and it's reception was 0.4 seconds.

Answer:

Explanation:

Size of the image: 2 cmIn order to calculate the size of the image, we can use the following proportion:wherep = 80 m is the distance of the tree from the pinholeq = 20 cm = 0.2 m is the distance of the image from the pinhole = 8 m is the heigth of the object is the height of the imageBy re-arranging the proportion, we find2) Magnification: 0.0025The magnification of a camera is given by the ratio between the size of the image and the size of the real object:so, in this problem we have

Answer:

t = 5.19 s

Explanation:

We have,

Height of the cliff is 132 m

It is required to find the time taken by the ball to fall to the ground. Let t is the time taken. So, using equation of kinematics as :

[tex]y=ut+\dfrac{1}{2}gt^2\\\\\text{since}\ u=0\\\\y=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2y}{g}}\\\\t=\sqrt{\dfrac{2\times 132}{9.8}}\\\\t=5.19\ s[/tex]

So, it will take 5.19 seconds to fall to the ground.

Answer:

Why do insects fly so high?

Because the angle of attack is so high, a lot of momentum is transferred downward into the flow. These two features create a large amount of lift force as well as some additional drag. The important feature, however, is the lift.

Why an Aeroplane flying has kinetic  

A flying aeroplane has potential energy has it flies above the ground level. And since the aeroplane is flying motion is associated with it and thus possesses kinetic energy. Hence a flying aeroplane has both potential and kinetic energ

Explanation:

Answer:

50 %

Explanation:

It's Fifty percent

Explanation:

presence of food, water ,etc

Explanation:

here is five all you have to do is just pick

Answer: The degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

Answer:

A

Explanation:

KE = 1/2 mv^2

=1/2(30kg)( 3.4 m/s)^2

=173.4 joules

=1.7×10^2 joules

Answer:

Option A:  F/4

Explanation:

Centripetal force, [tex]F = \frac{mv^{2} }{r}[/tex]

Where v = speed

r = radius

Since Kinetic Energy, [tex]E_{k} = 0.5 mv^{2}[/tex]

Writing centripetal force in terms of kinetic energy, [tex]F = \frac{2 E_k}{r}[/tex]

If the initial radius of the circle, r₁ =r

The doubled radius, r₂ = 2r

If the initial kinetic energy, [tex]KE_1 = E_{k}[/tex]

The halved kinetic energy,  [tex]KE_2 = 0.5E_{k}[/tex]

Therefore, the new Centripetal force becomes:

[tex]F_{2} = \frac{2(0.5 E_k)}{2r} \\F_{2} = \frac{0.5 E_k}{r}\\F_{2} =\frac{1}{4} * \frac{2 E_k}{r}\\Since, F = \frac{2 E_k}{r} \\F_{2} =\frac{1}{4} * F\\F_{2} =\frac{F}{4}[/tex]

Answer:

10.2 m/s

Explanation:

Using conservation of energy:

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)

v = 10.2 m/s

The velocity when car reaches the bottom of the hill is 10.2 m/s.

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

M.E = ½ mv² + mgh

where g is the acceleration due to gravity, v is the velocity, m is the mass and h is the height of the object.

Given is a 1380 kg car starts from rest at the top of a 28.0 m long hill inclined at 11.00 degrees.

Using conservation of energy principle, we have

PE = KE

mgh = ½ mv²

v = √(2gh)

Substitute the values, we get

v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)

v = 10.2 m/s

Thus, the velocity when car reaches the bottom of the hill is 10.2 m/s.

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Answer:

48.26 m

Explanation:

time to goes up (till stop for a while in the air - maximum height)

vt = vo + a t

0 = 15 + g . t

0 = 15 + (-9.8) . t

9.8t = 15

t = 1.531 s

so the time left to goes down is

4.0 - 1.531 = 2.469 s

height from the top of building can find it by using

vo =√(2gh)

15 = √(2)(9.8).h

15² = 19.6h

h = 225/19.6 = 11.48 m

so the distance of maximum height to the ground is

t = √(2H/g)

2.469 = √(2H/9.8)

2.469² = 2H/9.8

6.096 = 2H/9.8

2H = 6.096 x 9.8 = 59.74 m

so the vertical distance of the building (or the building height's is)

H - h = 59.74 - 11.48 = 48.26 m

Answer:

0.125m/s^2

Explanation:

20-10=10

10 divided by 80=0.125m/s^2

The average velocity of the car is 15 m/s. The time taken to travel over the distance with this velocity is 5.3 seconds. Then the acceleration of the car is 1.8 m/s².

Acceleration is a physical quantity measuring the rate  of change in velocity of a moving object. Like velocity, acceleration is a vector quantity having magnitude and direction.

Acceleration is the ratio of change in velocity to the change in time.

a = Δv/Δt

Given, the car is accelerating from 10 to 20 m/s. Hence, it travelled with average velocity of 15 m/s over the distance of 80 m.

Then , time taken  = distance/velocity

t = 80 m/15 m/s = 5.3 s

Acceleration = Δv/t = (20 -10 m/s) /5.3 s = 1.8 m/s².

Therefore, the acceleration of the car is about  1.8 m/s².

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Answer:

Joseph proust's law of difinite composition

Law of conservation of mass

Explanation:

Dalton's law of multiple proportions is part of the basis for modern atomic theory, along with Joseph Proust's law of definite composition (which states that compounds are formed by defined mass ratios of reacting elements) and the law of conservation of mass that was proposed by Antoine Lavoisier.

Answer:

law of conservation of mass

law of definite proportions

Explanation:

Answer:

Explanation:

Kinetic energy

Answer:

Diploid is often noted as 2N where N is the number of chromosomes. So in humans 2N=46. During sexual reproduction, the sex cells of parent organisms unite with one another and form a fertilized egg cell. In this situation, each sex cell is a gamete.

Explanation:

Answer:

visual art in which one uses to mark drawing and express feelings

Explanation:

In my own opinion. Hope it helps.

Answer:

20

Explanation:

because I am always right yo bro be like me

Newton's law of universal gravitation doesn't say anything about the cause of gravity.

Einstein's theory of relativity does.