Answer:
4√73
Step-by-step explanation:
x^2= 12^2 + 32^2
x^2= 144+ 1024
x^2=1168
x= 4√73
The following data summarizes results from 1000 pre-employment drug screening tests. If one of the test subjects is randomly selected, find the probability that the subject had a positive test result or a negative test result.
Positive Test Result Negative Test Result
Subject Uses Drugs 76 6
Subject Is Not a Drug User 95 823
P (subject had a positive test result or a negative test result)= simplify your answer.
Answer:
P (subject had a positive test result or a negative test result) = 1
Step-by-step explanation:
Given
The table above
Required
P (subject had a positive test result or a negative test result)
This is calculated as follows;
P (subject had a positive test result or a negative test result) =
P (subject had a positive test result) + P (subject had a negative test result)
Calculating P (subject had a positive test result)
This can be calculated by number of subjects with positive results divided by 1000
Only data from the column of subjects with positive results will be considered.
Number of Subjects = Subjects that uses drugs + Subjects that do not use drugs
Number of subjects = 76 + 95
Number of Subjects = 171
P (Subject had a positive test Result) = 171/1000
Calculating P (subject had a negative test result)
This can be calculated by number of subjects with negative results divided by 1000
Only data from the column of subjects with negative results will be considered.
Number of Subjects = Subjects that uses drugs + Subjects that do not use drugs
Number of subjects = 6 + 823
Number of Subjects = 829
P (Subject had a negative test Result) = 829/1000
Hence, P (subject had a positive test result or a negative test result) =
P (subject had a positive test result) + P (subject had a negative test result) = 171/1000 + 829/1000
P (subject had a positive test result or a negative test result) = (171 + 829)/1000
P (subject had a positive test result or a negative test result) = 1000/1000
P (subject had a positive test result or a negative test result) = 1
If the mean of 5 positive integers is 15, what is the maximum possible difference between the largest and the smallest of these 5 numbers?
Answer:
The maximum possible difference between the largest and the smallest of these 5 numbers is 65( if numbers aren't repeated )
Identify the exponential function for this graph. (Be sure to look at the scales
on the x- and y-axes.)
The required exponential function will be F(x)= [tex]4(0.5)^{x}[/tex]
Hence, Option A is the correct.
What is function?A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output.
From the assumption graph as shown in attached figure, we can determine that when x = 0 then y = 4.
Also, we can closely observe that the graph represents decay
exponential function.
The reason is that when the value of x increases, the graph of the particular function decreases.
But, the rate of decay must be less than 1 for decay exponential function because if it is greater than 1, then it would represent the exponential growth function.
Hence, the option B and D should be completely ruled out as these values represent the exponential growth.
And from graph, it is clear that when x = 0 then y = 4
The exponential function will be F(x)= [tex]4(0.5)^{x}[/tex]
To learn more about function visit:
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Adam drew a line that was 6 4/10 inches long. If he drew a second line that was 2 2/3
inches longer, what is the length of the second line? Answer as a mixed number.
Answer:
The length of the second line is [tex]9\frac{1}{15}[/tex] inches
Step-by-step explanation:
Given
Length of first line = [tex]6\frac{4}{10}[/tex] inches
Length of second line = [tex]2\frac{2}{3}[/tex] inches longer
Required
Length of second line.
Let the length of the second line be represented by x.
From the question, x is [tex]2\frac{2}{3}[/tex] inches longer than the first line;
This implies that:
[tex]x = 2\frac{2}{3} + 6\frac{4}{10}[/tex]
Convert both fractions to improper fractions
[tex]x = \frac{8}{3} + \frac{64}{10}[/tex]
Take LCM
[tex]x = \frac{80 + 192}{30}[/tex]
[tex]x = \frac{272}{30}[/tex]
Convert to mixed fraction
[tex]x = 9\frac{2}{30}[/tex]
Reduce fraction to lowest term
[tex]x = 9\frac{1}{15}[/tex]
Hence, the length of the second line is [tex]9\frac{1}{15}[/tex] inches
Find the area and the circumference of a circle with radius 7 cm.
Use the value 3.14 for me, and do not round your answers. Be sure to include the correct units in your answers.
cm
7 cm
Area: 0
Circumference: 0
Х
[tex]answers \\ area = 153.86 \: {cm}^{2} \\ circumference = 43.96 \: cm \\ \\ solution \\ radius = 7cm \\ area \: of \: circle = \pi {r}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: 3.14 \times {7}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3.14 \times 49 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 153.86 \: {cm}^{2} \\ circumference \: of \: circle = 2\pi \: r \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times 3.14 \times 7 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 43.96 \: cm \\ hope \: it \: helps \\ good \: luck \: on \: you r \: assignment[/tex]
Answer:
[tex] Area \: of \: circle = 153.86 \: {cm}^{2} \\ \\ Perimeter \: of \: circle = 43.96 \: cm [/tex]
Given:
Radius of circle (r) = 7 cm
Step-by-step explanation:
[tex]Area \: of \: circle = \pi {r}^{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \pi \times ({7}^{2} ) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \pi \times 49 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3.14 \times 49 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 153.86 \: {cm}^{2} [/tex]
[tex]Circumference \: of \: circle = 2\pi r \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times \pi \times 7\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 14 \times \pi\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 14 \times 3.14\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 43.96 \: cm[/tex]
What is the measure of XYZ?
please help me out
Answer:
The answer is C.
Step-by-step explanation:
You have to divide it by 2 :
∠XYZ = 148° ÷ 2
= 74°
16. Convert 55° to radians.
Answer:
0.96 radians
Step-by-step explanation:
Formula
1° = [tex]\frac{\pi }{180}[/tex] radians
Multiplying both sides by 55, It becomes
55° = [tex](\frac{\pi }{180} )*55[/tex]
55° = [tex]\frac{55\pi }{180}[/tex]
= 172.8/180
= 0.96 radians
An on-line retailer identified the web browser being used by a sample of 50 shoppers to its online site. The accompanying data table identifies the browser being used by a shopper. Previously in 2010, 64% of shoppers used Browser A, 24% Browser B, 6% Browser C, 3% Browser D, and 3% Browser E.
Required:
a. Using software, tabulate the frequency of the choice of browser used by these shoppers.
b. Present a bar chart and a pie chart of these frequencies. Which is more useful to compare the distribution of these to those observed in 2010?
c. Do you see any changes in the distribution of the choice of browser?
Answer:
See Explanation
This question is answered using Microsoft Office Excel 2013
Step-by-step explanation:
Given
Browser A - 64%
Browser B - 24%
Browser C - 6%
Browser D - 3%
Browser E - 3%
Total Frequency = 50
a.
To tabulate the frequency of the choice of browser, the total frequency is multiplied by each individual percentage as follows;
Browser A - 64% * 50 = 32
Browser B - 24% * 50 = 12
Browser C - 6% * 50 = 3
Browser D - 3%* 50 = 1.5
Browser E - 3% * 50 = 1.5
See Attachment for frequency table (using software)
b. See Attachment for pie chart and bar chart.
Both charts are useful for data presentation but in this case, the pie chart is a better option to use because it shows how the distribution of each browser and how they make up as a whole.
The main circle of the pie chart shows how individual browser are distributed through segments; This is not so for the bars of the bar chart which.
c. Yes, there are changes in the choice of browser.
Aside from Browser D and E that has the same frequency, other browsers (A-C) have different frequency.
Also, the distribution shows that more users make use of browser A than other browsers and the least frequent used browser are browser D and E.
Write the equation 2x - 3y = 6 in slope-intercept form.
Answer:
[tex] y = \frac{ 2}{ 3} x - 2[/tex]
Step-by-step explanation:
[tex]2x - 3y = 6 \\ - 3y = - 2x + 6 \\ \\ y = \frac{ - 2}{ - 3} x + \frac{6}{ - 3} \\ \\ \huge \purple{ \boxed{ y = \frac{ 2}{ 3} x - 2}} \\ this \: is \: in \: the \: slope - intercept \: form.[/tex]
Answer:
y = 2/ 3 x − 2
Step-by-step explanation:
slope intercept is y=mx+b
Simplify: 5y + 2p – 4y – 6P
Answer:
[tex]y-4p[/tex]
Step-by-step explanation:
Add/subtract like terms.
[tex]5y+2p-4y-6p\\5y-4y+2p-6p\\y-4p[/tex]
A city has 5 new houses for every 7 old houses. If there are 45 new houses in the city, how many old houses are there?
Answer:
63
Step-by-step explanation:
Make a ratio:
5 : 7 = 45 : x
x = 63
Do the points shown represent additive inverses? Explain why or why not
Answer:
Yes additive inverse is two complete opposite numbers if added = 0
Answer:
additive
Step-by-step explanation:
Because the point is not past the postive live or below the negative.
PLEASE HELP IM STUCK ON A PROBLEM....
Answer:
Number line A.
Step-by-step explanation:
|-5x| - 11 = -1
Add 11 to both sides.
|-5x| = 10
-5x = 10 or -5x = -10
x = -2 or x = 2
Answer: Number line A.
What expression is equivalent to 6•6•6•6•6
Answer:
6^5
Step-by-step explanation:
6 multiplied with itself 5 times is equal to 6^5
A cereal box has a volume of 225 cubic inches. The length of the base is 9 inches and the width of the base is
2.5 inches. What is the height of the box?
Answer:
10
Step-by-step explanation:
First multiply 9 by 2.5
Then divide 225 by 22.5
Question 7 (5 points)
Which of the following is the simplified fraction that's equivalent to 0.3
OA) 35/999
OB) 31/99
C) 105
7333
OD) 35
D) 35/111
Answer: B. although none are exactly 0.3 B is closest
Step-by-step explanation:
a. 35/999 = .0350
b. 31/99 = .3153
c. 105/7333 = .0143
d. 35/111 = .3135
Concur Technologies Inc is a large expense-management company located in Redmond Washington. The wall street Journal asked Concur to examine the data from 8.3 million expense reports to provide insights regarding business travel expenses. Their analysis of the data showed that New York was the most expensive city with an avg daily hotel room rate of $198 and an avg amount speny on entertainment, including group meals and tickets for shows sports and other events of $172 in comparison the U.S averages for these two categories were $89 for the room rate and $99 for entertainment the following table shows the average daily hotel room rate and the amount spent on the entertainment for a sample of 9 of the 25 most visited U.S cities Room Rate EntertainmentCity ($) ($)Boston 148 161Denver 96 105Nashville 91 101New orleans 110 142Phoenix 90 100San Diego 102 120San Francisco 136 167San Jose 90 140Tampa 82 98 develop a scatter diagram for these data with the room rate as the independent variablewhat does the scatter diagram developed in part (a.) indicate about the relationship between the two variablesdevelop the least squares estimated regression equationprovide an interpretation for the slope of the estimated regression equationthe avg room rate in Chicago is $128 considerably higher than the U.S avg predict the entertainment expense per day in Chicago
Answer:
Step-by-step explanation:
Hello!
Given the variables
X: daily hotel room rate
Y: amount spent on the entertainment
See second attachment for scatter plot.
The population regression equation is E(Yi)= α + βXi
To estimate the y-intercept and the slope of the regression equation you have to apply the following formulas:
[tex]b= \frac{sum XY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} }[/tex]
a= Y[bar]-bX[bar]
n= 9; ∑X= 945; ∑X²= 103325; ∑Y= 1134 ∑Y²= 148804; ∑XY= 123307
X[bar]= ∑X/n= 945/9= 105
Y[bar]= ∑Y/n= 1134/9= 126
[tex]b= \frac{123307-\frac{945*1134}{9} }{103325-\frac{(945)^2}{9} }= 1.03[/tex]
a= 126 - 1.03*105= 17.49
^Y= 17.49 + 1.03Xi
Slope interpretation: The estimated average amount spent on entertainment increases 1.03 every time the daily hotel room rate increases one unit.
If the room rate for Chicago is $128 (X), to predict the mount spent in entertainment (Y) you have replace it in the estimated regression line:
^Y= 17.49 + 1.03Xi= 17.49 + 1.03*128= 149.33
The expected amount spent on entertainment for Chicago is $149.33
I hope this helps!
Simplify the expression. Write the answer using scientific notation. (7 × 105)2 a. 4.9 × 1010 b. 4.9 × 1011 c. 4.9 × 109 d. 49 × 1010
Answer:
b. 4.9 × 1011
Step-by-step explanation:
Using scientific notation is similar to expressing in standard form. Given that (7 × 105)2
We open the parenthesis. This may first be expressed as
7² × 10⁽⁵⁾²
Then expand,
= 49 × 10¹⁰
To put in scientific notation, 49 = 4.9 × 10
Hence the expression becomes
= 4.9 × 10 × 10¹⁰
Using the laws of indices
= 4.9 × 10¹¹ in scientific notation
Answer:
4.9 × 1011
Step-by-step explanation:
I did it in grandpoint
The average math SAT score is 511 with a standard deviation of 119. A particular high school claims that its students have unusually high math SAT scores. A random sample of 55 students from this school was selected, and the mean math SAT score was 528. Is the high school justified in its claim? Explain. ▼ No Yes , because the z-score ( nothing) is ▼ unusual not unusual since it ▼ does not lie lies within the range of a usual event, namely within ▼ 1 standard deviation 2 standard deviations 3 standard deviations of the mean of the sample means. (Round to two decimal places as needed.)
Answer:
No, because the z-score of Z = 1.06 is not unusual since it does not lie within the range of a usual event, namely within 2 standard deviations of the mean of the sample means.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Unusual
If X is more than two standard deviations from the mean, x is considered unusual.
In this question:
[tex]\mu = 511, \sigma = 119, n = 55, s = \frac{119}{\sqrt{55}} = 16.046[/tex]
A random sample of 55 students from this school was selected, and the mean math SAT score was 528. Is the high school justified in its claim?
If Z is equal or greater than 2, the claim is justified.
Lets find Z.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{528 - 511}{16.046}[/tex]
[tex]Z = 1.06[/tex]
1.06 < 2, so 528 is not unusually high.
The answer is:
No, because the z-score of Z = 1.06 is not unusual since it does not lie within the range of a usual event, namely within 2 standard deviations of the mean of the sample means.
The statement that could be made regarding the high school about the justification of its claim would be:
- No, because the z-score of Z = 1.06 is not unusual since it does not lie within the range of a usual event, namely within 2 standard deviations of the mean of the sample means.
Given that,
μ = 511
σ = 119
Sample(n) = 55
and
s = [tex]119/\sqrt{55}[/tex]
[tex]= 16.046[/tex]
As we know,
The claim of the high school could be valid and justified only when
[tex]Z > 2[/tex]
To find,
The value of Z
So,
[tex]Z = (X -[/tex] μ )/σ
by putting the values using Central Limit Theorem,
[tex]Z = (528 - 511)/16.046[/tex]
∵ [tex]Z = 1.06[/tex]
Since [tex]Z < 2[/tex], the claim is not justified.
Learn more about "Standard Deviation" here:
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1. If the ratio of the ages of Kissi and Esinam is 3:5 and that of Esinam and Lariba is 3:5 and the sum of the ages of all 3 is 147 years, what is the age difference between oldest the
youngest?
Answer:
Age difference between oldest the youngest = 48 years
Step-by-step explanation:
Given: Ratio of ages of Kissi and Esinam is 3:5, ratios of ages of Esinam and Lariba is 3:5 and sum of the ages of all 3 is 147 years
To find: age difference between oldest the youngest
Solution:
Let age of Lariba be x years
As ratios of ages of Esinam and Lariba is 3:5,
Age of Esinam = [tex]\frac{3}{5}x[/tex] years
As ratio of ages of Kissi and Esinam is 3:5,
Age of Kissi = [tex](\frac{3}{5}) (\frac{3}{5}x)=\frac{9}{25}x[/tex] years
Sum of the ages of all 3 = 147 years
[tex]x+\frac{3}{5}x+\frac{9}{25}x=147\\ \frac{25x+15x+9x}{25}=147\\ x=\frac{147(25)}{49}=75[/tex]
Age of Lariba = x = 75 years
Age of Esinam = [tex]\frac{3}{5}(75)=45\,\,years[/tex]
Age of Kissi = [tex]\frac{9}{25}(75)=27\,\,years[/tex]
So,
Age difference between oldest the youngest = 75 - 27 = 48 years
Please answer this correctly
Answer:
24.99
Step-by-step explanation:
If the area of the quarter circle is 38.465, then the equation to find this would be
3.14*r^2 / 4 = 38.465. we solve for r, the radius, and get two solutions. 7 and -7. Obviously the length of the radius can't be -7, so we know the radius is 7.
Now we must solve for the perimeter. The perimeter is equal to 2r + (2*3.14*r)/4
Plugging 7 in as the radius, r, we get 24.99 as our final answer.
20000 rupees to US dollars
Answer: $264.54
Hope this helped! God bless!
One number is 11 less than the other number. If their sum is increased by 8, the result is 71. Find the numbers.
First number = [tex]x[/tex]
Second number = [tex]x-11[/tex]
[tex]x+x-11+8=71[/tex]
[tex]2x-3=71[/tex]
[tex]2x=71+3[/tex]
[tex]2x=74[/tex]
[tex]x=37[/tex]
First number = [tex]x=37[/tex]
Second number = [tex]x-11=37-11=26[/tex]
Determine whether the geometric series 192 + 48 + 12 + ... converges or diverges, and identify the sum if it exists.
A.) Converges: 768
B.) Diverges
C.) Converges; 64
D.) Converges; 256
Answer:
D.) Converges; 256
Step-by-step explanation:
x0= 192
x1 = 48 = 192/4
x2 = 12 = 192/(4 x 4)
Therefore, this series can be written as:
[tex]x_n = \frac{192}{4^n}[/tex]
Applying limits at infinity:
[tex]\lim_{n \to \infty} x_n= \lim_{n \to \infty} (\frac{192}{4^n}) = \frac{192}{\infty}=0[/tex]
Since the terms of the series tend to zero, we can affirm that the series converges.
The sum of an infinite converging series is:
[tex]S=\frac{x_0}{1-r} \\S=\frac{192}{1-\frac{1}{4} }\\S=256[/tex]
Thus, the answer is D.) Converges; 256
Please help! Which statement is true, about the following of the two triangles? (Refer to image)
A: ΔADC≅Δ ACB, by the SSS congruence postulate.
B: ΔADC≅ΔACB, by the SAS congruence postulate.
C: ΔADC≅ ΔCBA, by the SSS congruence postulate.
D: ΔADC≅ΔCBA, by the SAS congruence postulate.
Answer:
The answer is C because DC = BA and DA = CB (given) and AC = CA (reflexive property).
Determine the magnitude of the resultant force by adding the rectangular components of the three forces.
a) R = 29.7 N
b) R = 54.2 N
c) R = 90.8 N
d) R = 24.0 N
From the mid-1960s to the early 1990s, there was a slow but steady decline in SAT scores. For example, take the Verbal SAT. The average in 1967 was about 543; by 1994, the average was down to about 499. However, the SD stayed close to 110. The drop in average has a large effect on the tails of the distribution. 0.7% 7% 7.67% 7.6%
Complete Question
From the mid-1960's to the early 1990's, there was a slow but steady decline in SAT scores. For example, take the Verbal SAT. The average in 1967 was about 543; by 1994, the average was down to about 499. However, the SD stayed close to 110. The drop in average has a large effect on the tails of the distribution.
Estimate the percentage of students scoring over 700 on 1967.
A 0.7%
B 7%
C 7.67%
D 7.6%
Answer:
The correct option is D
Step-by-step explanation:
From the question we are told that
The average SAT score in 1967 is [tex]\= x_1 =543[/tex]
The standard deviation of score in 1967 is [tex]\sigma_ 1= 110[/tex]
The average SAT score in 1994 is [tex]\= x_2 = 499[/tex]
The standard deviation of score in 1967 is [tex]\sigma_ 2 = 110[/tex]
The percentage of students scoring over 700 on 1967 is mathematically represented as
[tex]P(X > 700)[/tex]
Where X is the random variable representing score of student above 700
Now normalizing the above probability we have
[tex]P(X > 700) = P(Z > \frac{700 - \= x_1 }{\sigma } )[/tex]
substituting values
[tex]= P(Z > \frac{700 - \= 543}{110 } )[/tex]
[tex]= P(Z > 1.83 )[/tex]
Form the normalized z table
= 0.076
= 7.6 %
The drama club is selling candles for a fundraiser. They spend $100 on the candles and sell them for $4.50 each. How many candles must they sell to make more than $125 profit?
Let x represent the number of candles sold. Which inequality can you use to find x?
So I try to help
Step-by-step explanation:
I don't no sorrry
Answer:
the first one!!
Step-by-step explanation:
Consider two unique parallel lines. What aspects of
these two lines are the same? What aspects of these two
lines would have to be different? Explain your reasoning.
Answer:
The slope of two parallel lines will always be the same. If the slope was slightly different, then the lines would intersect at some point, which breaks the definition of parallel lines.
The y-intercepts of two parallel lines have to be different, or else the two lines would be the same line. If the y-intercept and the slope are the same, then the lines will essentially equal each other.
Answer:
Sample Response: Two parallel lines will have the same slope. The slopes of parallel lines have to be equal. The y-intercepts of those two lines have to be different, otherwise they would be the same line. The x-intercepts of the parallel lines would also be different.
Step-by-step explanation:
edge 2020
Find the product. (4p – 6)(4p + 6) a. 16p2 + 36 b. 16p2 – 36 c. 16p2 – 48p – 36 d. 16p2 + 48p + 36
Answer:
Brainleist to me!
Step-by-step explanation:
(4p – 6)(4p + 6) =
B) 16 p^2 - 36
just use a online calculator
Answer:
16p²-36
Step-by-step explanation:
1(4p-6)(4p+6)
as we know that (a+b)(a-b)=a²-b²
=(4p)²-(6)²
=16p²-36