Answer:
[tex]\frac{dV}{dt}[/tex] = 1017.87 in³/min
[tex]\frac{dV}{dt}[/tex] = 17203.35 in³/min
Step-by-step explanation:
given data
radius r of a sphere is increasing at a rate = 3 inches per minute
[tex]\frac{dr}{dt}[/tex] = 3
solution
we know volume of sphere is V = [tex]\frac{4}{3} \pi r^3[/tex]
so [tex]\frac{dV}{dt} = \frac{4}{3} \pi r^2 \frac{dr}{dt}[/tex]
and when r = 9
so rate of change of the volume will be
rate of change of the volume [tex]\frac{dV}{dt} = \frac{4}{3} \pi (9)^2 (3)[/tex]
[tex]\frac{dV}{dt}[/tex] = 1017.87 in³/min
and
when r = 37 inches
so rate of change of the volume will be
rate of change of the volume [tex]\frac{dV}{dt} = \frac{4}{3} \pi (37)^2 (3)[/tex]
[tex]\frac{dV}{dt}[/tex] = 17203.35 in³/min
If y varies directly as x, and y is 48 when x is 6, which expression can be used to find the value of y when x is 2?
Answer:
When x is 2, y is 16
Step-by-step explanation:
If y is 48 and x is 6, then y is 8 when x is 1.
Because of this, when x is 2, y will be 16.
Please mark Brainliest
The function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=69 and s(6)=141.Find the average velocity of the object over the interval of time [2,6 ].
Answer:
The average velocity of the object over the interval of time [2,6] is of 18 units of distance per unit of time.
Step-by-step explanation:
The average velocity can be calculated as the division of the position change by the time change.
Find the average velocity of the object over the interval of time [2,6 ].
6 - 2 = 4 units of time (t, min,...)
s(6) = 141, s(2) = 69
141 - 69 = 72 units of distance(m, km...)
72/4 = 18 u.d./u.t.
The average velocity of the object over the interval of time [2,6] is of 18 units of distance per unit of time.
Solve 5(2x-3a)+2b=3ax-4, for x
Answer:
10x-15a
Step-by-step explanation:
What’s the correct answer for this ? Two chords AB and CD intersect at E. If AE = 2cm, EB =4, and CE = 2.5 cm, find the length of ED
Answer:
ED = 3.2 cm
Step-by-step explanation:
According to chord-chord power theorem,
(AE)(EB) = (CE)(ED)
2*4 = 2.5 *ED
8/2.5 = ED
ED = 3.2 cm
A spherical gemstone just fits inside a plastic cube with edges 12cm. a) calculate the volume of gemstone, to the nearest cubic centimeter. b) how much empty space is there.
Answer:
a) (V) = 904.78 of a sphere = 288pi diameter = 12
(V) = 1728cm^3 of a cube = face diagonal = 16.9cm
b) Difference Volume = 1728-904.78 = 823.22cm^3
Step-by-step explanation:
To find volume of an inscribed sphere within a square cube
We use 4 π/3 * r^3 for the equation
As Radius = 6 = 6cm this is the only thing plugged into the equation to create a division first then a multiplication square of radius and then a multiplication. 4pi /3 * 6^3
r^3 = 216
4pi/3 = 4.18
4.18 * 216 = 904.78
This means the answer is 288 pi cm^3.
Answer:
volume of gemstone = 905 cm^3
volume of empty space = 823 cm^3
Step-by-step explanation:
volume of cube = s^3, where s = length of edge
volume of sphere = (4/3)(pi)r^3, where r = radius of sphere
The cube has a 12-cm edge. The sphere fits tightly inside the cube, so the diameter, d, of the sphere is 12 cm. The radius is half the diameter, so radius = r = diameter/2 = 12 cm/2 = 6 cm.
a)
volume of sphere = (4/3)(pi)r^3
volume of sphere = (4/3)(3.14159)(6 cm)^3
volume of sphere = 905 cm^3
b)
The empty space is the difference between the volume of the cube and the volume of the sphere.
volume of cube = s^3
volume of cube = (12 cm)^3
volume of cube = 1728 cm^3
empty space = volume of cube - volume of sphere
empty space = 1728 cm^3 - 905 cm^3
empty space = 823 cm^3
Please answer this correctly as soon as possible.I have to finish this today. A triangular prism is 19 yards long and has a triangular face with a base of 12 yards and a height of 8 yards. The other two sides of the triangle are each 10 yards. What is the surface area of the triangular prism?
total SA = 764 yd²
A triangular prism is 13 yards long and has a triangular face with a base of 12 yards and a height of 8 yards. The other two sides of the triangle are each 10 yards. What is the surface area of the triangular prism?
See attachment.
if length = 13 yards then total SA = 512 yd²
if length = 19 yards then total SA = 764 yd²
HELP...it has timer
Answer:
lily has a larger ratio
Step-by-step explanation:
3(5 − 2 x) = −2(6 – 3 x) − 10 x
Answer:
15-6x= -12-4x
15-2x= -12
-2x= -27
x= -13.5
Step-by-step explanation:
What is the range of the function y = -x ^2 + 1?
A. y ≤ -1
B. y ≥ -1
C. y ≤ 1
D. y ≥ 1
Answer:
C. y ≤ 1
Step-by-step explanation:
The maximum value of the function is 1. So, the range is all values of y less than or equal to that.
y ≤ 1
A=(-2,-7) B=(-6,4) C=(-2,7) D=(2,4) What is the perimeter?
[tex]\displaystyle\bf\\AB=\sqrt{\Big(-6-(-2)\Big)^2+\Big(4-(-7)\Big)^2}\\\\AB=\sqrt{\Big(-6+2\Big)^2+\Big(4+7\Big)^2}\\\\AB=\sqrt{\Big(-4\Big)^2+\Big(11\Big)^2}\\\\AB=\sqrt{16+121}\\\\\boxed{\bf AB=\sqrt{137}}[/tex]
.
[tex]\displaystyle\bf\\BC=\sqrt{\Big(-2-(-6)\Big)^2+\Big(7-4\Big)^2}\\\\BC=\sqrt{\Big(-2+6\Big)^2+\Big(7-4\Big)^2}\\\\BC=\sqrt{\Big(4\Big)^2+\Big(3\Big)^2}\\\\BC=\sqrt{16+9}\\\\BC=\sqrt{25}\\\\\boxed{\bf BC=5}[/tex]
.
[tex]\displaystyle\bf\\CD=\sqrt{\Big(2-(-2)\Big)^2+\Big(4-7\Big)^2}\\\\CD=\sqrt{\Big(2+2\Big)^2+\Big(4-7\Big)^2}\\\\CD=\sqrt{\Big(4\Big)^2+\Big(-3\Big)^2}\\\\CD=\sqrt{16+9}\\\\CD=\sqrt{25}\\\\\boxed{\bf CD=5}[/tex]
.
[tex]\displaystyle\bf\\AD=\sqrt{\Big(2-(-2)\Big)^2+\Big(4-(-7)\Big)^2}\\\\AD=\sqrt{\Big(2+2\Big)^2+\Big(4+7\Big)^2}\\\\AD=\sqrt{\Big(4\Big)^2+\Big(11\Big)^2}\\\\AD=\sqrt{16+121}\\\\\boxed{\bf AD=\sqrt{137}}[/tex]
.
[tex]\displaystyle\bf\\P=AB+BC+CD+AD=\sqrt{137}+5+5+\sqrt{137}\\\\\boxed{\bf P=10+2\sqrt{137}}[/tex]
Solve the following system of equations using the elimination method. 5x – 5y = 10 6x – 4y = 4
Answer:
11×-9y=14
Step-by-step explanation:
123hsvwjwjbe
Answer:
(-2,-4)
Step-by-step explanation:
add the equations in order to solve the first variable. put the value into the other equations in order to solve the other variables.
X+4 is prime. X2-9can be factored using the __formula
[tex] \purple \bold{a^2 - b^2} [/tex]
Step-by-step explanation:
X+4 is prime. X2-9can be factored using the [tex] \purple \bold{a^2 - b^2} [/tex] formula
[tex] x^2 - 9\\
=x^2 - 3^2 \\
= (x+3)(x-3)[/tex]
Answer: difference-of-squares
next one is (x+3)(x-3)(x+4)
Step-by-step explanation:
just took it on ed genuity :)
Assuming the below results were obtained in a study used to test the accuracy of the rapid diagnostic test for influenza, calculate and interpret the sensitivity of the rapid diagnostic influenza test.
Frequency of Flu Cases Frequency of Non-Fu Cases
Frequency of Individuals who 47 10
Screened Positive
Frequency of individuals who 43 100
Screened Negative
A) When the rapid diagnostic influenza test is used, 52.22% of individuals who have the flu test positive for the flu.
B) When the rapid diagnostic influenza test is used, 90.91% of individuals who have the flu test positive for the
C) When the rapid diagnostic influenza test is used, 47.78% of individuals who have the flu test positive for the flu.
D) When the rapid diagnostic influenza test is used, 9.09% of individuals who have the flu test positive for the flu.
Answer:
c
Step-by-step explanation:
select the statements and number line that can represent the inequality.
Answer:
every equivalent to 6 ≤ x
Step-by-step explanation:
We can subtract 5+11/6x to get ...
7 ≤ -(11/6)x +3x = (7/6)x
Multiplying by 6/7 gives ...
6 ≤ x
__
When x is in the set of real numbers, x in any real number that is 6 or more.
When x is in the set of integers, x is any integer that is 6 or more: {6, 7, 8, ...}.
When no set is specified, the solution is simply ...
6 ≤ x
During the calendar year of 1971 a total of 171 deaths were caused by influenza in a city of 450,000 persons. The temporal distribution of these deaths was as follows: First Quarter, 54; Second Quarter, 43; Third Quarter, 35; and Fourth Quarter, 39. Calculate the annual and quarterly mortality rates per 100,000 population.
Answer and Step-by-step explanation:
The computation of annual and quarterly mortality rates per 100,000 population is shown below:-
Quarterly mortality rates are
[tex]= \frac{Deaths}{Population\ in\ the\ city}\times Population[/tex]
For the first quarter
[tex]= \frac{54}{450,000}\times 100,000[/tex]
= 12 death per 100,000 population
For the second quarter
[tex]= \frac{43}{450,000}\times 100,000[/tex]
= 9.5 death per 100,000 population
For the third quarter
[tex]= \frac{35}{450,000}\times 100,000[/tex]
= 7.7 death per 100,000 population
For the fourth quarter
[tex]= \frac{39}{450,000}\times 100,000[/tex]
= 8.6 death per 100,000 population
Now the annual mortality is
[tex]= \frac{Deaths}{Population\ in\ the\ city}\times Population[/tex]
[tex]= \frac{171}{450,000}\times 100,000[/tex]
= 38 death per 100,000 population
convert 6 kilograms to grams
Answer:
6000 grams the formula would be multiply the mass value by 1000
Step-by-step explanation:
Answer:
6000 grams
Step-by-step explanation:
6 kilograms
To convert kg into grams, we multiply by 1000
So,
=> 6 * 1000 grams
=> 6000 grams
You have 10 shirts 2 of them are black what is the probability of not choosing a black shirt.
Answer:
80% or 4/5
Step-by-step explanation:
the probability of not choosing a black shirt
P = number of shirts that are not black ÷ total number of shirts
Total number of shirts = 10
Number of black shirts = 2
Number of shirts that are not black = 10-2 = 8
P = 8/10 = 4/5 or 80%
Florian ran 1.2 miles and walked 4.8 laps around the path at the park for a total distance of 3.6 miles. Which shows the correct equation and value of x, the distance of 1 lap around the path at the park? 3.6 x + 1.2 = 4.8; x = 1 mile 4.8 x + 1.2 = 3.6; x = 1 mile 3.6 x + 1.2 = 4.8; x = 0.5 mile 4.8 x + 1.2 = 3.6; x = 0.5 mile
Answer:
The correct answer would be D) 4.8x + 1.2 = 3.6; x = 0.5 mile
Step-by-step explanation:
This is because laps would be the dependent variable, so we know the number of them (4.8) would be multiplied by the variable (x). We also know that 1.2 is the constant. Now we can solve to make sure this is the right equation.
4.8x + 1.2 = 3.6
4.8x = 2.4
x = 0.5
Answer:
D) 4.8x + 1.2 = 3.6; x = 0.5 miles
A report about how American college students manage their finances includes data from a survey of college students. Each person in a representative sample of 793 college students was asked if they had one or more credit cards and if so, whether they paid their balance in full each month. There were 500 who paid in full each month. For this sample of 500 students, the sample mean credit card balance was reported to be $825. The sample standard deviation of the credit card balances for these 500 students was not reported, but for purposes of this exercise, suppose that it was $200. Is there convincing evidence that college students who pay their credit card balance in full each month have a mean balance that is lower than $905, the value reported for all college students with credit cards
Answer:
Yes. There is enough evidence to support the claim that college students who pay their credit card balance in full each month have a mean balance that is lower than $905.
Step-by-step explanation:
We want to test the claim that college students who pay their credit card balance in full each month have a mean balance that is lower than $905.
To perform this test we have a sample of 500 students which have paid their balance in full each month. The sample mean is $825 and the estimated sample deviation is considered $200.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=905\\\\H_a:\mu< 905[/tex]
The significance level is 0.05.
The sample has a size n=500.
The sample mean is M=825.
The estimated standard error of the mean is computed using the formula:
[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{200}{\sqrt{500}}=8.94[/tex]
Then, we can calculate the t-statistic as:
[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{825-905}{8.94}=\dfrac{-80}{8.94}=-8.94[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=500-1=499[/tex]
This test is a left-tailed test, with 499 degrees of freedom and t=-8.94, so the P-value for this test is calculated as (using a t-table):
[tex]\text{P-value}=P(t<-8.94)=0[/tex]
As the P-value (0) is smaller than the significance level (0.05), the effect is significant.
The null hypothesis is rejected.
There is enough evidence to support the claim that college students who pay their credit card balance in full each month have a mean balance that is lower than $905.
PLEASE HELP ?
The range is the set of
A: first coordinates
B: ordered pairs
C:second coordinates
Answer:
C:second coordinates
Step-by-step explanation:
A range is the set of output coordinates
The domain is the input coordinates
Domain is the x, range is the y
Answer: its definitly c
Step-by-step explanation:
A survey asks teachers and students whether they would like the new school
mascot to be a shark or a moose. This table shows the results. Which
statement is true?
Will pick brainliest! Please help with the attached file!
Answer:
25 degrees
Step-by-step explanation:
The value of an exterior angle is the difference between the two arcs that it forms divide by two. Therefore:
[tex]x+10=\dfrac{146-(6x+6)}{2}[/tex]
Multiply both sides by 2:
[tex]2x+20=146-6x-6[/tex]
Move all of the x's to one side:
[tex]8x+20=146-6[/tex]
Combine all of the constants on the other side:
[tex]8x=120[/tex]
Divide both sides by 8:
[tex]x=15[/tex]
Therefore, ECB=x+10=15+10=25 degrees.
Hope this helps!
Tony rode his bicycle 3 7/10 miles to school. What is this distance written as a decimal?
Answer:
7/10=0.7
3+0.7=3.7
3.7
Hope this helps
Step-by-step explanation:
Aakash has a liability of 6000 due in four years. This liability will be met with payments of A in two years and B in six years. Aakash is employing a full immunization strategy using an annual effective interest rate of 5%.Calculate |A-B|
Answer:
|A-B|= 586.411565Step-by-step explanation:
We know that = Liability
[tex]PLiability= \frac{6000}{1.05^{4} }[/tex]
[tex]\frac{6000}{1.05^{4} }=\frac{A}{1.05^{2} }+\frac{B}{1.05^{6} }\\\\6000(1.05^{2} ) = (1.05^{4} ) +B\\B= 6000(1.05^{2} )-(1.05^{4} )----------(1)\\\\[/tex]
dAssets =dLiability
[tex]4=2*\frac{\frac{A}{1.05^2} }{\frac{6000}{1.05^4} } +6*\frac{\frac{B}{1.05^6} }{\frac{6000}{1.05^4} } \\4={\frac{6000}{1.05^4}= 2*\frac{A}{1.05^2} +6*\frac{B}{1.05^6}\\\\4[6000(1.05^2)]= 2*A(1.05^4)+6*B[/tex]
From equation 1 we have
[tex]4[6000(1.05^2)]= 2*A(1.05^4)+6*6000(1.05^2)-6*A(1.05^4)\\4*A(1.05^4)=2*6000(1.05^2)\\A=\frac{2*6000(1.05^2)}{4*(1.05^4)} \\A=272.088435\\[/tex]
Going back to equation 1 we have
[tex]B= 6000(1.05^2)-A(1.05^4)\\B= 3307.5\\|A-B|= |2721.088435-3307.5|= 586.411565[/tex]
250cm3 of fresh water of density 1000kgm-3 is mixed with 100cm3 of sea water of density 1030kgm-3. Calculate the density of the mixture. *
Answer:
[tex] m_{fresh}= 1000 \frac{Kg}{m^3} * 2.5x10^{-4} m^3 = 0.25 Kg[/tex]
And we can do a similar procedure for the sea water:
[tex] m_{sea}= \rho_{sea} V_{sea} [/tex]
And after convert the volume to m^3 we got:
[tex] m_{sea}= 1030 \frac{Kg}{m^3} * 1x10^{-4} m^3 = 0.103 Kg[/tex]
And then the density for the mixture would be given by:
[tex] \rho_{mixture}= \frac{m_{fresh} +m_{sea}}{v_{fresh} +v_{sea}}[/tex]
And replacing we got:
[tex] \rho_{mixt}= \frac{0.25 +0.103 Kg}{2.5x10^{-4} m^3 +1x10^{-4} m^3} = 1008.571 \frac{Kg}{m^3}[/tex]
Step-by-step explanation:
For this case we can begin calculating the mass for each type of water:
[tex] m_{fresh}= \rho_{fresh} V_{fresh} [/tex]
And after convert the volume to m^3 we got:
[tex] m_{fresh}= 1000 \frac{Kg}{m^3} * 2.5x10^{-4} m^3 = 0.25 Kg[/tex]
And we can do a similar procedure for the sea water:
[tex] m_{sea}= \rho_{sea} V_{sea} [/tex]
And after convert the volume to m^3 we got:
[tex] m_{sea}= 1030 \frac{Kg}{m^3} * 1x10^{-4} m^3 = 0.103 Kg[/tex]
And then the density for the mixture would be given by:
[tex] \rho_{mixture}= \frac{m_{fresh} +m_{sea}}{v_{fresh} +v_{sea}}[/tex]
And replacing we got:
[tex] \rho_{mixt}= \frac{0.25 +0.103 Kg}{2.5x10^{-4} m^3 +1x10^{-4} m^3} = 1008.571 \frac{Kg}{m^3}[/tex]
In Georgetown, the library is 8 miles due south of the courthouse and 6 miles due west of the community swimming pool. What is the distance between the courthouse and the community swimming pool?
Answer:
10 miles
Step-by-step explanation:
tree points form a right triangle with sides 8, 6 and x
x is the hypotenuse of the triangle
x²=8²+6²=100
x=√100=10 miles
Jeff rear-ended a car on his way to work and damaged his vehicle. He drove his car to the local body shop for an
estimate of the cost to repair his car. Jeff has a $500 deductible. The local body shop provided an estimate of $3725,
How much will Jeff have to pay?
A $3225
B $3725
C $4225
D $500
Answer:
A $3225
Step-by-step explanation:
Total = $3725
Dectuable = Able to be deducted
$3725 - $500 = $3225
A local country officials need to calculate the capacity of a large hole for the garbage refuse dump. The dump hole is 250 feet long,120 feet wide and 30 feet deep. What is the capacity of the dump hole in cubic feet.
Answer:
900000cubic feet
Step-by-step explanation:
capacity of dump hole= 250*120*30
= 900000cubic feet
which of the following represents a function
Answer:
Second option
Step-by-step explanation:
For a set to represent a function, each input value in the set domain should match with one and only one output value of set range.
The option that follows this rule os second option as 1 is matched with 2 only, and 3 is matched with 3 only, and 5 is matched with 7 only.
Electricity usage data consists of 45 months has a mean number of units consumed is 390.47 per month with a standard deviation of 170.5 units per month. Assume that the number of units consumed are approximately normally distributed. Estimate 95% confidence interval for the average monthly electricity consumed units.
Answer:
The 95% confidence interval for the average monthly electricity consumed units is between 47.07 and 733.87
Step-by-step explanation:
We have the standard deviation for the sample. So we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 45 - 1 = 44
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 44 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.0141
The margin of error is:
M = T*s = 2.0141*170.5 = 343.4
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 390.47 - 343.40 = 47.07 units per month
The upper end of the interval is the sample mean added to M. So it is 390.47 + 343.40 = 733.87 units per month
The 95% confidence interval for the average monthly electricity consumed units is between 47.07 and 733.87