While eating lunch high up in a skyscraper, two construction workers calculate their gravitational potential
energies, and find them to be equal. If the lighter construction worker has a mass of 90kg, and the other worker
is twice as high up in the skyscraper, what is the mass of the other worker?

Answers

Answer 1

Answer:

The mass of the other worker is 45 kg

Explanation:

The given parameters are;

The gravitational potential energy of one construction worker = The gravitational potential energy of the other construction worker

The mass of the lighter construction worker, m₁ = 90 kg

The height level of the lighter construction worker's location = h₁

The height level of the other construction worker's location = h₂ = 2·h₁

The gravitational potential energy, P.E.,  is given as follows;

P.E. = m·g·h

Where;

m = The mass of the object at height

g = The acceleration due to gravity

h = The height at which is located

Let P.E.₁ represent the gravitational potential energy of one construction worker and let P.E.₂ represent the gravitational potential energy of the other construction worker

We have;

P.E.₁ = P.E.₂

Therefore;

m₁·g·h₁ = m₂·g·h₂

h₂ = 2·h₁

We have;

m₁·g·h₁ = m₂·g·2·h₁

m₁ = 2·m₂

90 kg = 2 × m₂

m₂ = (90 kg)/2 = 45 kg

The mass of the other construction worker is 45 kg.


Related Questions

a boy pulls his toy on a smooth horizontal surface with a rope inclined at 60° to the horizontal if the effective Force pulling the toy along the horizontal surface is 5-newton calculate the tension in the rope

Answers

Answer:

The tension in the rope is 10 N

Explanation:

The Force Vector

Like all vectors, the force has a magnitude and direction. Vectors can be decomposed into two perpendicular components on both axes.

The tension in the rope (F) can be calculated by using vector decomposition as follows.

The figure included below shows a force F which horizontal component is known to have a value of Fx= 5 Nw. The angle formed by the force and its horizontal component is 60°.

We can use the trigonometric ratio called the cosine to find the magnitude of F as follows:

[tex]\displaystyle \cos 60^\circ = \frac{5}{F}[/tex]

Solving for F:

[tex]\displaystyle F = \frac{5}{\cos 60^\circ}[/tex]

[tex]\displaystyle F = \frac{5}{\frac{1}{2}}[/tex]

Thus, F = 10 N

The tension in the rope is 10 N

If a 2000 N force is used to raise a piano at a rate of 10 m/s2, what is the mass of the piano?

Answers

Answer:

To solve this problem we will apply the principle of conservation of energy for which we have that the potential energy on a body, is equivalent to the work done on it at the given point. Therefore we will have the following equality

At the same time we know that work is equivalent to the Force applied over a given distance, so,

The potential energy is equivalent to the product between mass, gravity and height. Recall that the product of mass and gravity is equivalent to weight (The same given in the statement)

Equating,

Then,

Replacing,

Therefore the force needed to lift the piano is 600N

Explanation:

HOPE THIS HELPS!!!

Force=mass x acceleration which of newtons laws does this best describe

Answers

Second law! Good luck
Second law

What he said

WILL MARK BRAINLIEST

How much heat is required to raise the temperature of 150 grams of water from 15
C to 20 C, give that the specific heat of water is 4.18 J/g/C?
- 7.18 J
- 125 J
- 179 J
- 3,140 J

Answers

Answer:

aww that's simple! its B can i get brainliest? i really need some points rn <3

Explanation:

Answer:

B

Explanation:

How much is the velocity of a body when it travels 600m in 5 minutes?( with the full process)​

Answers

Its average speed, pretending that it traveled at a constant speed, is

v = s / t

= 600 m

5 x 60 s

= 2 m/s

but to be a velocity it needs a direction as well as a speed.

( Sorry. Can’t find a division line to put between the 600 m and the 5 x 60 s )

A football player kicks a ball with a mass of .55 kg. The average acceleration of the football was 14.9 m/s2. How much force did the kicker supply to the football?

A. 35.24 N

B. 8.2 N

C. 35.24 m/s^2

D. 8.2 m/s^2

Answers

Answer:8.2N

Explanation:I did the quiz on k12 and that’s the answer i got :)

- A 9,300 kg. railroad car traveling at a velocity of 15m/s strikes a second boxcar
at rest. If the two cars stick together and move off with a velocity of 6m/s, what is the mass
of the second car?

Answers

Answer:

13950kg

Explanation:

If we make the system both railroad cars, we know that the momentum of the whole system doesn't change because the forces are internal.

Let a be the mass of the second car.

The original momentum is 9300*15 kg*m/s+ a*0 kg*m/s = 139500 kg*m/s

After sticking together, the momentum is (9300+a)kg*6m/s, which should be equal to 139500 kg*m/s

Therefore (9300+a)*6 = 139500

9300+a = 23250

a = 13950 kg

A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10m s -2 , with what velocity will it strike the ground? After what time will it strike the Ground?

Answers

Height,h= 20m

"gently dropped" means initial velocity, u, =0m/s

Uniform acceleration, g=10m/s²

using the formula v²=u²+2gs

Substituting, v²=0²+2*10*20

v²=400

v=

[tex] \sqrt{400} [/tex]

v=20m/s

Time, t at which is strike the ground

using the formula v=u+at

Substituting, 20=0+10t

20=10t

t=2s

This means that the bank strike the ground with a velocity of 20m/s in 2s.

3. What is a manometer used to determine?
A the difference between two densities
B the difference between two forces
C the difference between two heights
D the difference between two pressures​

Answers

Answer:

D the difference between two pressures​

Explanation:

A manometer is a device used to measure the difference between the pressure in a place. Manometer is solely used to determine gas pressure.

The device compares gas pressure to atmospheric pressure at any given point. It measures pressure against a fixed reference or with respect to a differential pressure in a place. The column of liquid is the medium it uses to measure the pressure differences. Pressure is the force exerted per unit area.

A 56 kg object is attached to a rope, which can be used to move the load vertically.

a. What is the tension force in the rope when the object moves upward at a constant velocity?

b. What is the tension force in the rope when the object accelerates downward at a constant

acceleration of 1.8 m/s2

c. What is the tension force in the rope when the object accelerates upward at a constant

acceleration of 1.8 m/s2

Answers

Answer:

a) T=549.36N Upwards

b) T=448.56N Upwards

c) T=650.16N Upwards

Explanation:

The very first thing we can do to solve this problem is to draw a free body diagram we can use to analyze the situation (see attached picture).

On the diagram we can see there are only two forces acting on the object: the tension of the rope and the weight of the object itself.

a)

Since the object is moving at a constant speed, this means that its acceleration will be zero. So we can do a sum of forces like this:

[tex]\sum F=0[/tex]

T-W=0

T=W

T=mg

[tex]T=(56kg)(9.81m/s^{2})[/tex]

T=549.36N upwards

b)

For part b, since the object is accelerating downwards, we wil say that it's acceleration is negative, so [tex]a=-1.8m/s^{2}[/tex]

so we can do a sum of forces again:

[tex]\sum F=ma[/tex]

so

T-W=ma

T=ma +W

T=ma+mg

T=m(a+g)

and now we substitute:

[tex]T=(56kg)(-1.8 m/s^{2}+9.81 m/s^{2})[/tex]

which yields:

T=448.56N upwards (in this particular case, the tension always goes upwards)

c)

Since the object is moving upwards, we can say that its acceleration will be positive, so [tex]a =1.8m/s^{2}[/tex]

we can take the solved equation we got on the previous part of the problem, so we get:

T=m(a+g)

[tex]T =(56kg)(1.8 m/s^{2}+9.81 m/s^{2})[/tex]

which yields:

T=650.16N upwards

The tension force in the rope when the object moves upward at a constant velocity is 548.8 N.

The tension force in the rope when the object accelerates downward at a constant acceleration is 448 N.

The tension force in the rope when the object accelerates upward at a constant acceleration is 649.6 N.

The given parameters:

Mass of the object, m = 56 kg

The tension force in the rope when the object moves upward at a constant velocity;

T = ma + mg

at constant velocity, a = 0

T = mg

T = 56(9.8)

T = 548.8 N

The tension force in the rope when the object accelerates downward at a constant acceleration of 1.8 m/s².

T = mg - ma

T = m(g - a)

T = 56(9.8 - 1.8)

T = 448 N

The tension force in the rope when the object accelerates upward at a constant acceleration of 1.8 m/s².

T = mg + ma

T = m(g + a)

T = 56(9.8 + 1.8)

T = 649.6 N

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The value of acceleration due to gravity is less at the top of Mount Everest then that in the terai reason, why?​

Answers

Answer:

The value of acceleration due to gravity is greater in terai than in mountain. In terai region the radius of earth is less as it lies close to the centre of the earth. Thus, the value of g is more in terai region.

A box of weight 200N is placed on a ground of 20m square . Find the pressure
exerted by the box.​

Answers

Answer:

10 Pascal

Explanation:

[tex]pressure =\frac{force}{area}[/tex]

[tex]pressure= \frac{200}{20}[/tex]

pressure = 10 Pa

Which of the following best explains why the noble gases are less likely to chemically
bond with other elements?
A They are all non-metals. |
B They are all rare elements.
C They all have a full outer shell of electrons.
D They have the highest atomic number in the row.

Answers

Answer:

a

Explanation:

Will someone please look at my other questions

Answers

Answer:

eeeeeeeeeeeeeeeeeeeeeeeeeeeee

Explanation:

A element source has a decayed constant of 13.6pico per second. Calculate the half life of this element. ​

Answers

Answer:

5.1 x 10¹⁰s

Explanation:

Given parameters:

Decay constant  = 13.6 x 10⁻¹²/s

Unknown:

Half life of the element  = ?

Solution:

From the decay constant, we can find the half-life of this radioactive element.

  Half-life  = [tex]\frac{0.693}{decay constant}[/tex]  

     Half-life  = [tex]\frac{0.693}{13.6 x 10^{-12} }[/tex]   = 5.1 x 10¹⁰s

Medium is water. The wavelength is 4.75 m and the frequency is 600 Hz. Calculate the speed of the wave.

Answers

Answer:

126.32m/s

Explanation:

The formula for calculating the speed of wave is expressed as:

Speed of wave = frequency/wavelength

Given

Wavelength = 4.75m

Frequency = 600Hz

Required

Speed of the wave

Substitute the given value into the formula

Speed = 600/4.75

Speed = 126.32m/s

Hence the speed of the wave is 126.32m/s

If you pluck a guitar string hard the sound waves it gives off will have __________ amplitudes.
small
large

Answers

Answer:

large

Explanation:

the harder you pluck the louder it gets

If you pluck the guitar string hard, the sound waves it gives off will have larger amplitudes

What will be the amplitudes of the waves?

We know that, for soundwaves, the amplitude is related to the intensity of the sound.

If you pluck the guitar string hard, you will notice that the intensity of the sound increases. So we can conclude that the amplitude of the soundwaves will be larger than if you plucked the guitar string softer.

Then the complete statement would be:

"The sound waves it gives off will have larger amplitudes."

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velocity is vector quantity but speed is scalor quantity . why ?​

Answers

speed speed scalar quantity is the rate of at which an object covers distance on the other hand velocity is a vector quantity it is direction aware.velocity is the rate at which the position changes.the average velocity is the displacement or position change Per time ratio.so velocity is a vector quantity but speed is a scalar quantity

Pls help I think it's pretty easy
Electromagnetic waves transfer energy and are produced by _____.

Answers

the transfer of energy by electromagnetic waves is called electromagnetic radiation. ... This causes a vibrating electric field, which in turn creates a vibrating magnetic field.

Drag the tiles to the correct boxes to complete the pairs. Match each expression to its simplified form.

Answers

Answer:

3a^5 - (-a^5) = 3a^5 + a^5 = 4a^5

6a^7 - 2a^7 = 4a^7

-3a^5 - (-2a^5) = -3a^5 + 2a^5 = -a^5

7a^7 - 8a^7 = -a^7

Answer:

here ya go

Explanation:

Carmen is helping load furniture and boxes onto a moving truck. She picks up boxes of her things, places them on a cart, and pushes the cart to the moving van. Which term best describes the type of force Carmen is using? * contact speed gravity noncontact

Answers

Answer:

contact

Explanation:

A contact force is defined as a force which requires some contact to occur. When we apply force that is in contact with the objects are called as contact forces.

In the context, Carmen is loading furniture and boxes on a moving van by picking up by picking up the boxes or furniture on a cart and pushing it onto the van. Carmen uses contact forces to lift the boxes and furniture onto the van.

A person drops an egg onto a carpet, and the egg doesn't break. Then she drops the egg onto a tile floor and it breaks. Which floor most likely had a greater amount of force, and a shorter collision time?

Answers

Answer: The tile floor.

Explanation:

We can think of this as follows:

By the second Newton's law, we know that:

F = m*a

force is equal to mass times acceleration.

Now, as the egg hits the ground, we can think that there is a force that is applied in a very short period of time.

(similar to the case of a bat hitting a baseball)

Ok, the total energy of the impact will be the same for any surface in which the egg falls.

But suppose that the egg falls in a carpet, in this case, the carpet has a kinda large collision time (the time that the force is applied to the egg), this means that we will have a smaller force, acting for a long period of time. Now if the egg falls on something harder, like the tile floor, the collision time will be a lot shorter, then the force must be a lot stronger to compensate, this force is so large, that breaks the shell of the egg.

the tile floor is then the correct answer.

An ice skater initially skating at a velocity of 3 m/s speeds up to a velocity of 5 m/s. The momentum
of the skater
A Remains the same
B Increases
C Becomes zero
D Decreases

Answers

Answer:

B. Increases

Explanation:

Momentum is given as [tex]p=mv[/tex]. Since [tex]m[/tex] is maintained, as the velocity decreases, the momentum decreases, and similarly, as the velocity increases, the momentum increases.

the ... in an atom move about in the space surrounding the nucleus

what is the missing word- ...

Answers

electrons

the in an atom move about in the space surrounding the nucleus

Suppose that two objects attract each other with a gravitational force of 16 units. If the mass of both objects was doubled, and if the distance between the objects was doubled, then what would be the new force of attraction between the two objects?

Answers

Answer:

Distance, such that displacement over time is taken into account doesn't change regardless of the length in x meters or mass in kg So the force will remain constant given 16 units

The new force of attraction between the two objects will be remain the same.

What is the gravitational law?

The gravitational law states that the gravitation force is the ratio of the product of the masses and the square of the distance between them.

Let the masses be m and M and the distance between them is r. Then the force is given as,

F = GmM / r²

Suppose that two objects attract each other with a gravitational force of 16 units.

F = 16

GmM / r² = 16 units

If the mass of both objects was doubled, and if the distance between the objects was doubled. Then we have

F' = G(2m)*(2M) / (2r)²

F' = 4GmM / 4r²

F' = GmM / r²

F' = 16 units

The new force of attraction between the two objects will be remain the same.

Learn more about gravitational law:

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Charlie graduated with a bachelor’s degree in construction management. As he aspires to work in his dad’s construction firm, which educational institute does Charlie need to enroll in for professional certifications in construction?

Charlie needs to enroll himself in the BLANK for various professional certifications, and a master’s degree in construction science from the best university.

Answers

Answer:

He needs to enroll himself in CMMA. This company help young students obtain a well future in Construction Science.

A 70 kg astronaut throws a 5 kg ball with a velocity of 20 m/s east. What is the velocity of the astronaut?

Answers

Answer:

[tex]V_a =1.4285m/s[/tex]

Explanation:

From the question we are told that

70 kg astronaut

5 kg ball

A velocity of 20 m/s east

Generally with Law of conservation of momentum in place for a body in space

initial and final momentum must be equal

Therefore

[tex]M_b*V_b=M_a*V_a[/tex]

[tex]M_b=Mass of ball \\V_b=Ball velocity \\M_a= Mass of astronaut \\V_a= Astronaut velocity[/tex]

Mathematically solving for[tex]V_a[/tex]

[tex]V_a =\frac{5*20}{70}[/tex]

[tex]V_a =1.4285m/s[/tex]

Therefore the Astronauts velocity relative to his mass is given to be

[tex]V_a =1.4285m/s[/tex]

The velocity of the astronaut is 1.43 m/s.

From Newton's third law of motion,

To get the velocity of the astronaut, we use the formula below.

Formula:

MV = mv.................... Equation 1

Where:

M = mass of the astronautV = Velocity of the astronautm = mass of the ballv = velocity of the ball.

make V the subject of the equation

V = mv/M................. Equation 2

From the question,

Given:

m = 5 kgv = 20 m/sM = 70 kg

Substitute these values into equation 2.

V = 5(20)/70V = 1.43 m/s.

Hence, the velocity of the astronaut is 1.43 m/s.

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A rocket travels 200,000 meters in a time of 4.40 seconds . what of the speed of the rocket ?

Answers

Answer:

the speed of the rocket is 45454.5455

Explanation: Because the speed formula is basically just distance/ divided by time all you need to do is divide 200,000 meters by 4.40 seconds. And then thus you will get the speed.

Answer:

45454.55 m/s

Explanation:

[tex]S=\frac{d}{t}[/tex]

= [tex]\\S=\frac{200000}{4.40}[/tex]

=45454.55 m/s

Why doesn't the earth block out the light between the sun and the moon during a normal month

Answers

Answer:

Explanation:

Will anyone please help me solve this physics Problem?​

Answers

Answer:

I. Clockwise moment = 150 Nm

II. Anticlockwise moment = 400 Nm

III. 200 N

III. The anticlockwise moment.

Explanation:

From the question given above, we can obtain the answers to the questions as follow:

I. Determination of the clockwise moment.

Distance (d) = 1.5 m

Force (F) = 100 N

Clockwise Moment =?

Moment = Force × distance.

Clockwise moment = 100 × 1.5

Clockwise moment = 150 Nm

II. Determination of the anticlockwise moment.

Distance (d) = 2 m

Force (F) = 200 N

Anticlockwise Moment =?

Moment = Force × distance.

Anticlockwise moment = 200 × 2

Anticlockwise moment = 400 Nm

III. Determination of who will turn the sea saw.

Clockwise moment = 150 Nm

Anticlockwise moment = 400 Nm

Since the anticlockwise moment is greater than the clockwise moment, it therefore means that the anticlockwise moment will turn the sea saw.

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