Find the area of the circle

Answer:

No, because the​ z-score of Z = 1.06 is not unusual since it does not lie within the range of a usual​ event, namely within 2 standard deviations of the mean of the sample means.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Unusual

If X is more than two standard deviations from the mean, x is considered unusual.

In this question:

[tex]\mu = 511, \sigma = 119, n = 55, s = \frac{119}{\sqrt{55}} = 16.046[/tex]

A random sample of 55 students from this school was​ selected, and the mean math SAT score was 528. Is the high school justified in its​ claim?

If Z is equal or greater than 2, the claim is justified.

Lets find Z.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{528 - 511}{16.046}[/tex]

[tex]Z = 1.06[/tex]

1.06 < 2, so 528 is not unusually high.

The answer is:

No, because the​ z-score of Z = 1.06 is not unusual since it does not lie within the range of a usual​ event, namely within 2 standard deviations of the mean of the sample means.

The statement that could be made regarding the high school about the justification of its claim would be:

- No, because the​ z-score of Z = 1.06 is not unusual since it does not lie within the range of a usual​ event, namely within 2 standard deviations of the mean of the sample means.

Given that,

μ = 511

σ = 119

Sample(n) = 55

and

s = [tex]119/\sqrt{55}[/tex]

[tex]= 16.046[/tex]

As we know,

The claim of the high school could be valid and justified only when

[tex]Z > 2[/tex]

To find,

The value of Z

So,

[tex]Z = (X -[/tex] μ )/σ

by putting the values using Central Limit Theorem,

[tex]Z = (528 - 511)/16.046[/tex]

∵ [tex]Z = 1.06[/tex]

Since [tex]Z < 2[/tex], the claim is not justified.

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Answer:

A) y = -2/3x + 1

Step-by-step explanation:

Slope - intercept form is y = mx + b, where m is the slope and b is the y - intercept.

The line is falling from left to right, so it has a negative slope.

    y = -mx + b

The line has a slope of -2/3.

    y = -2/3x + b

The line has a y - intercept of 1.

    y = -2/3x + 1

I hope this helps :)

A) y = -2/3x + 1, the equation of the line shown in the graph above in slope-intercept form.

A straight line is an endless one-dimensional figure that has no width. It is a combination of endless points joined both sides of a point and has no curve.

here, we have,

Slope - intercept form is y = mx + b,

where m is the slope and b is the y - intercept.

The line is falling from left to right, so it has a negative slope.

 y = -mx + b

As, the line passes through (0,1) and (1.5,0)

The line has a slope of -2/3.

 y = -2/3x + b

The line has a y - intercept of 1.

y = -2/3x + 1

hence, A) y = -2/3x + 1, the equation of the line shown in the graph above in slope-intercept form.

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Answer:

10

Step-by-step explanation:

First multiply 9 by 2.5

Then divide 225 by 22.5

Complete Question:

Amit found and labeled the areas of each of the faces of the triangular prism as shown.

Which area calculation did Amit calculate incorrectly?

Rectangular face with area 30 cm2

Rectangular face with area 40 cm2

Rectangular face with area 50 cm2

Triangular faces with areas 48 cm2

Answer:

Triangular faces with areas 48 cm2

Step-by-step Explanation:

To find out which area calculation Amit got wrong, let's calculate each faces of the given triangular prism attached below:

There area of theb5 faces should be as follows:

Area  of rectangular face with L = 10 and B = 5 would be ==> 10*5= 50cm²

Area  of rectangular face with L = 8 and B = 5 would be 8*5 = 40cm²

Area  of rectangular face with L = 6 and B = 5 would 6*5 = 30cm²

Area  of each of the triangular faces will be ½*8*6 = 48/2 = 24cm²

From our calculations, we'd observe that Amit didn't calculate the area of the triangular faces correctly. Amit got 48cm² instead of 24cm²

Answer:

Triangular faces with areas 48 cm2

Step-by-step explanation:

ANSWER:

I believe you wish to calculate the sum of squares total (SST) for this regression analysis. The sum of squares total is 1053.15

Step-by-step explanation:

The sum of squares total is numerically derived by adding the sum of squares regression (regression sum of squares) to the sum of squares error (error sum of squares). The regression sum of squares here is 752.25 and the error sum of squares is 300.9

This gives us a total sum of squares of 1053.15

Sums of squares tell if a linear regression of one variable (or variables) on another is good or not.

The squared differences between the observed dependent variable and its mean is a measure of the total variability of the data set.

So the SST is equal to 752.25 + 300.9 = 1053.15

Answer:

a) For this case since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 750 hours

b) We can use a significance level minimum of 2% in order to ensure the conditions in favor to the alternative hypothesis and then the potential customer will decide to move forward with a purchase witht his condition.

Step-by-step explanation:

For this case we have the following info given after conduct the following system of hypothesis:

Null hypothesis: [tex]\mu \geq 750[/tex]

Alternative hypothesis: [tex]\mu< 750[/tex]

The output is:

Variable N Mean St Dev SEMean Z P-Value

lifetime 50 738.44 38.20 5.40 -2.14 0.016

For this case the statistic calculated was:

[tex] z = -2.14[/tex]

And the p value calculated is:

[tex] p_v =p(z<-2.14) = 0.016[/tex]

Part a

For this case since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 750 hours

Part b

We can use a significance level minimum of 2% in order to ensure the conditions in favor to the alternative hypothesis and then the potential customer will decide to move forward with a purchase witht his condition.

Answer:

5

Step-by-step explanation:

Since this is a right triangle we can use trig functions

sin theta = opp /hyp

sin 30 = x / 10

10 sin 30 = x

10 * 1/2 = x

5 =x

Answer:

An acute angle is open

Step-by-step explanation:

An acute angle is an angle that is less than [tex]90^{0}[/tex]. Two or more acute angles are set to be complementary if their sum equals a right angle.

Clara's diagram involves two acute angles JLK and KLM with both sharing the side LK.

If the acute angles are complementary angles, then JLM would be a right angle.

If the acute angles are not complementary angles, then JLM would be less than a right angle.

So the appropriate choice to select is an acute angle is open. Which implies that JLM may be a right angle or not depending on the degrees of the acute angles involved.

Answer:

C is the correct answer.

Step-by-step explanation:

The reason it is C is because pi/the symbol on top is irrational.

Hope you have a good rest of your day :)

[tex]answers \\ area = 153.86 \: {cm}^{2} \\ circumference = 43.96 \: cm \\ \\ solution \\ radius = 7cm \\ area \: of \: circle = \pi {r}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: 3.14 \times {7}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3.14 \times 49 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 153.86 \: {cm}^{2} \\ circumference \: of \: circle = 2\pi \: r \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times 3.14 \times 7 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 43.96 \: cm \\ hope \: it \: helps \\ good \: luck \: on \: you r \: assignment[/tex]

Answer:

[tex] Area \: of \: circle = 153.86 \: {cm}^{2} \\ \\ Perimeter \: of \: circle = 43.96 \: cm [/tex]

Given:

Radius of circle (r) = 7 cm

Step-by-step explanation:

[tex]Area \: of \: circle = \pi {r}^{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \pi \times ({7}^{2} ) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \pi \times 49 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3.14 \times 49 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 153.86 \: {cm}^{2} [/tex]

[tex]Circumference \: of \: circle = 2\pi r \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times \pi \times 7\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 14 \times \pi\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 14 \times 3.14\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 43.96 \: cm[/tex]

Answer:

[tex] Median = \frac{60+60}{2}=60[/tex]

And we see that the closest values to 60 are 62 and 63 and then the answer would be:

The values closest to the middle are 62 inches and 63 inches.

Step-by-step explanation:

We have the following dataser given:

62 33 50 90  80 50 40 70  50 63 74 53  55 64 60 60  78 70 43 82

We can sort the values from the lowest to the highest and we got::

33 40 43 50 50 50 53 55 60 60 62 63 64 70 70 74 78 80 82 90

Now we see that we have n=20 values and the values closest to the middle and we can use the middle as the median and for this case the median can be calculated from position 10 and 11th and we got:

[tex] Median = \frac{60+60}{2}=60[/tex]

And we see that the closest values to 60 are 62 and 63 and then the answer would be:

The values closest to the middle are 62 inches and 63 inches.

The values closest to these middle elements are 60 and 63 inches

The dataset is given as:

62 33 50 90 80 50 40 70 50 63 74 53 55 64 60 60 78 70 43 82

Next, we sort the data elements in ascending order

33 40 43 50 50 50 53 55 60 60 62 63 64 70 70 74 78  80 82 90

The length of the dataset is 20.

So, the elements at the middle are the 10th and the 11 elements.

From the sorted dataset, these elements are: 60 and 62

Hence, the values closest to these middle elements are 60 and 63

Read more about median at:

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Answer:

-15

Step-by-step explanation:

The solution of expression for x = - 4 is,

⇒ - 15

We have to given that,

An expression is,

⇒ 2x - 7

Now, We can simplify the expression for x = - 4 as,

An expression is,

⇒ 2x - 7

Plug x = - 4;

⇒ 2 × - 4 - 7

⇒ - 8 - 7

⇒ - 15

Thus, The solution of expression for x = - 4 is,

⇒ - 15

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Answer:

The answer is C because DC = BA and DA = CB (given) and AC = CA (reflexive property).

Answer:

D.) Converges; 256

Step-by-step explanation:

x0= 192

x1 = 48 = 192/4

x2 = 12 = 192/(4 x 4)

Therefore, this series can be written as:

[tex]x_n = \frac{192}{4^n}[/tex]

Applying limits at infinity:

[tex]\lim_{n \to \infty} x_n= \lim_{n \to \infty} (\frac{192}{4^n}) = \frac{192}{\infty}=0[/tex]

Since the terms of the series tend to zero, we can affirm that the series converges.

The sum of an infinite converging series is:

[tex]S=\frac{x_0}{1-r} \\S=\frac{192}{1-\frac{1}{4} }\\S=256[/tex]

Thus, the answer is D.) Converges; 256

First number = [tex]x[/tex]

Second number = [tex]x-11[/tex]

[tex]x+x-11+8=71[/tex]

[tex]2x-3=71[/tex]

[tex]2x=71+3[/tex]

[tex]2x=74[/tex]

[tex]x=37[/tex]

First number = [tex]x=37[/tex]

Second number =  [tex]x-11=37-11=26[/tex]

A becuase i worked it out and i got that so im really confident

Answer:

The answer is C.

Step-by-step explanation:

You have to divide it by 2 :

∠XYZ = 148° ÷ 2

= 74°

Answer:

Step-by-step explanation:

Hello!

Given the variables

X: daily hotel room rate

Y: amount spent on the entertainment

See second attachment for scatter plot.

The population regression equation is E(Yi)= α + βXi

To estimate the y-intercept and the slope of the regression equation you have to apply the following formulas:

[tex]b= \frac{sum XY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} }[/tex]

a= Y[bar]-bX[bar]

n= 9; ∑X= 945; ∑X²= 103325; ∑Y= 1134 ∑Y²= 148804; ∑XY= 123307

X[bar]= ∑X/n= 945/9= 105

Y[bar]= ∑Y/n= 1134/9= 126

[tex]b= \frac{123307-\frac{945*1134}{9} }{103325-\frac{(945)^2}{9} }= 1.03[/tex]

a= 126 - 1.03*105= 17.49

^Y= 17.49 + 1.03Xi

Slope interpretation: The estimated average amount spent on entertainment increases 1.03 every time the daily hotel room rate increases one unit.

If the room rate for Chicago is $128 (X), to predict the mount spent in entertainment (Y) you have replace it in the estimated regression line:

^Y= 17.49 + 1.03Xi= 17.49 + 1.03*128= 149.33

The expected amount spent on entertainment for Chicago is $149.33

I hope this helps!

Answer:

Brainleist to me!

Step-by-step explanation:

(4p – 6)(4p + 6) =

B)  16 p^2  - 36

just use a online calculator

Answer:

16p²-36

Step-by-step explanation:

1(4p-6)(4p+6)

as we know that (a+b)(a-b)=a²-b²

=(4p)²-(6)²

=16p²-36

Hey there! I'm happy to help!

The only thing we have to do is solve our inequality to find the answer!

30+15x ≥ 90

We subtract 30 from both sides.

15x ≥ 60

Finally, we divide both sides by four.

x ≥ 4

Therefore, Deepak can only accept jobs that last 4 or more hours.

I hope that this helps! Have a wonderful day!

The solution for the inequality is x≥4. Therefore, option A is the correct answer.

Given that, Deepak is a landscaper who charges $30 for each job he does plus an additional $15 for each hour he works.

Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

The inequality for the given situation is 30+15x≥90

Subtract 30 on the both the sides of an inequality, which is

30+15x-30≥90-30

⇒ 15x≥60

Divide 15 on the both the sides of an inequality, that is

15x/15≥60/15

⇒ x≥4

The solution for the inequality is x≥4. Therefore, option A is the correct answer.

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Answer:

Yes additive inverse is two complete opposite numbers if added = 0

Answer:

additive

Step-by-step explanation:

Because the point is not past the postive live or below the negative.

Answer:

The slope of two parallel lines will always be the same. If the slope was slightly different, then the lines would intersect at some point, which breaks the definition of parallel lines.

The y-intercepts of two parallel lines have to be different, or else the two lines would be the same line. If the y-intercept and the slope are the same, then the lines will essentially equal each other.

Answer:

Sample Response: Two parallel lines will have the same slope. The slopes of parallel lines have to be equal. The y-intercepts of those two lines have to be different, otherwise they would be the same line. The x-intercepts of the parallel lines would also be different.

Step-by-step explanation:

edge 2020

Answer: This was a bit hard to understand, x times the 5th root of x

Step-by-step explanation:

When you multiply square roots of the same root and inside value, they essentially get rid of the square roots. So the first two terms boil down to just x. Then multiply x by the 5th root of x to get:

[tex]x\sqrt[5]{x}[/tex]

Answer:

[tex]x[/tex]

Step-by-step explanation:

Apply exponent rules.

[tex]\sqrt{x} =x^\frac{1}{2}\\\:a^b\times \:a^c=a^{b+c}[/tex]

[tex]\sqrt[5]{x} \times\sqrt[5]{x} \times\sqrt[5]{x} \times\sqrt[5]{x} \times\sqrt[5]{x}[/tex]

[tex]x^{\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}}[/tex]

[tex]x^1[/tex]

Answer: B. although none are exactly 0.3 B is closest

Step-by-step explanation:

a. 35/999 = .0350

b. 31/99 = .3153

c. 105/7333 = .0143

d. 35/111 = .3135

Answer:

1

Step-by-step explanation:

Set the height of the bar to 1 because there is only 1 number between 40-49 i.e. 49

Complete Question

From the mid-1960's to the early 1990's, there was a slow but steady decline in SAT scores. For example, take the Verbal SAT. The average in 1967 was about 543; by 1994, the average was down to about 499. However, the SD stayed close to 110. The drop in average has a large effect on the tails of the distribution.

Estimate the percentage of students scoring over 700 on 1967.

A 0.7%

B  7%

C 7.67%

D 7.6%

Answer:

The correct option is D

Step-by-step explanation:

From the question we are told that

   The average  SAT score in 1967 is  [tex]\= x_1 =543[/tex]

     The  standard deviation of score in 1967 is  [tex]\sigma_ 1= 110[/tex]

     The average  SAT score in 1994 is  [tex]\= x_2 = 499[/tex]

      The  standard deviation of score in 1967 is  [tex]\sigma_ 2 = 110[/tex]

The percentage of students scoring over 700 on 1967 is mathematically represented as

   [tex]P(X > 700)[/tex]

Where X is the random variable representing score of student above 700

Now  normalizing the above probability we have

     [tex]P(X > 700) = P(Z > \frac{700 - \= x_1 }{\sigma } )[/tex]

substituting values

      [tex]= P(Z > \frac{700 - \= 543}{110 } )[/tex]

      [tex]= P(Z > 1.83 )[/tex]

Form the normalized z table  

      =  0.076

     =  7.6 %

Answer:

0.96 radians

Step-by-step explanation:

Formula

1° = [tex]\frac{\pi }{180}[/tex] radians

Multiplying both sides by 55, It becomes

55° = [tex](\frac{\pi }{180} )*55[/tex]

55° = [tex]\frac{55\pi }{180}[/tex]

= 172.8/180

= 0.96 radians

Answer: $264.54

Hope this helped! God bless!

Answer:

See Explanation

This question is answered using Microsoft Office Excel 2013

Step-by-step explanation:

Given

Browser A - 64%

Browser B - 24%

Browser C - 6%

Browser D - 3%

Browser E - 3%

Total Frequency = 50

a.

To tabulate the frequency of the choice of browser, the total frequency is multiplied by each individual percentage as follows;

Browser A - 64% * 50 = 32

Browser B - 24% * 50 = 12

Browser C - 6% * 50 = 3

Browser D - 3%* 50 = 1.5

Browser E - 3% * 50 = 1.5

See Attachment for frequency table (using software)

b. See Attachment for pie chart and bar chart.

Both charts are useful for data presentation but in this case, the pie chart is a better option to use because it shows how the distribution of each browser and how they make up as a whole.

The main circle of the pie chart shows how individual browser are distributed through segments; This is not so for the bars of the bar chart which.

c. Yes, there are changes in the choice of browser.

Aside from Browser D and E that has the same frequency, other browsers (A-C) have different frequency.

Also, the distribution shows that more users make use of browser A than other browsers and the least frequent used browser are browser D and E.