The number of pieces of popcorn in a large movie theatre popcorn bucket is normally distributed, with a mean of 1610 and a standard deviation of 10. Approximately what percentage of buckets contain between 1600 and 1620 pieces of popcorn?

Step-by-step explanation:

=> The volume of a triangular pyramid can be found using the formula V = 1/3AH where A = area of the triangle base, and H = height of the pyramid

=> The volume of a cone can be found by V = 1/3(Ab)(H) where Ab is base area and H is the height of the cone

The difference between both is that is it's base. A cone has a polygonal base while a pyramid has a tetragonal base

Answer:

299.97 is the actual answer

Step-by-step explanation:

I took the test.

Answer:

[tex]x=2+\sqrt{11},\:x=2-\sqrt{11}[/tex]

Step-by-step explanation:

[tex]x^2-4x-7=0\\\mathrm{Solve\:with\:the\:quadratic\:formula}\\Quadratic\:Equation\:Formula\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\mathrm{For\:}\quad a=1,\:b=-4,\:c=-7:\quad x_{1,\:2}=\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}\\x=\frac{-\left(-4\right)+\sqrt{\left(-4\right)^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}:\quad 2+\sqrt{11}[/tex]

[tex]x=\frac{-\left(-4\right)-\sqrt{\left(-4\right)^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}:\quad 2-\sqrt{11}\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\x=2+\sqrt{11},\:x=2-\sqrt{11}[/tex]

Answer:

Hypotenuse = 13.798 cm, Angle1 = 27.4° and Angle2 = 62.59°

Step-by-step explanation:

The first step to help us understand the question would be to draw it out.

A right angled triangle, with the two sides that make the right angle being x and y (it does not matter which way you put x and y).

I have attached the quick sketch I will refer to.

To find the length of the hypotenuse (lets call it H) we can use Pythagoras theorem as shown below

[tex]{x^{2}+y^{2}} = H^{2}[/tex]

Substitute in our values for x and y, and solve for H

[tex]{6.35^{2}+12.25^{2}} = H^{2}[/tex]

[tex]190.385 = H^{2}[/tex]

[tex]\sqrt{190.385} = H[/tex]

H = 13.79 cm

To find the other two angles of the triangle we will use trigonometry

I will first look for angle ∅. Since we have all three sides of the triangle we can use any of the three trig functions, I chose to use Tan

Tan ∅ [tex]= \frac{opposite}{adjacent}[/tex]

Substitute in our values for x and y, and solve for ∅

Tan ∅ = [tex]\frac{6.35}{12.25}[/tex]

∅ = [tex]tan^{-1} \frac{6.35}{12.25}[/tex]

∅ = 27.4°

Now do the same for angle β. I chose to use Tan again

Tan β [tex]= \frac{opposite}{adjacent}[/tex]

Substitute in our values for x and y, and solve for β

Tan β = [tex]\frac{12.25}{6.35}[/tex]

β = [tex]tan^{-1} \frac{12.25}{6.35}[/tex]

β = 62.59°

Answer:

Step-by-step explanation:

1) Parallel lines have same slope

y =  3x + 2

m = 3

(2, -4)  ;  m = 3

equation:  y - y1 = m (x - x1)

y - [-4] = 3(x - 2)

y + 4 = 3x - 6

y = 3x - 6 - 4

y = 3x - 10

2) y = 18x + 2

m1 = 18

Slope the line perpendicular to  y = 18x + 2,  m2 = -1/m1 = -1/18

m2 = -1/18

(1 , -5)

[tex]y-[-5]=\frac{-1/18}(x-1)\\\\y+5=\frac{-1}{18}x + \frac{1}{18}\\\\y=\frac{-1}{18}x+\frac{1}{18}-5\\\\y=\frac{-1}{18}x+\frac{1}{18}-\frac{5*18}{1*18}\\\\y=\frac{-1}{18}x+\frac{1}{18}-\frac{90}{18}\\\\y=\frac{-1}{18}x-\frac{89}{18}\\\\[/tex]

Answer:person up top is right it’s B

Step-by-step explanation: on edg 2020

Answer:

The answer is B

Step-by-step explanation:

lol yw guys

Answer: To increase an amount by 7%, you would want to use 1.07 as the multiplier. To decrease it, you would use 0.93

Step-by-step explanation:

Answer:

  188 m

Step-by-step explanation:

The tangent of the angle is the ratio of the side opposite (height of the lighthouse) to the side adjacent (distance to the lighthouse):

  tan(28°) = (100 m)/distance

  distance = (100 m)/tan(28°) ≈ 188 m

The distance between the sailboat and the lighthouse is about 188 m.

Answer:

22,203 ft^2

Step-by-step explanation:

The area of a triangle with angle ∅ and two sides a and b is;

Area A = 1/2 × absin∅ ......1

The park is in the shape of a triangle, with two sides and an angle given;

Given;

a = 190 ft

b = 235 ft

∅ = 84°

Substituting the values into equation 1;

Area of the park;

A = 1/2 × 190 × 235 × sin84°

A = 22,202.70131409 ft^2

A = 22,203 ft^2 (to the nearest whole number)

Area of the park is 22,203 ft^2

Answer:

The total repair cost was around $300 .

Step-by-step explanation:

I wasn't sure when you were saying to round, so here are two options.

(For rounding at the end) :

82+157+58 = 297

Rounds to 300.

(For rounding as he's adding everything up) :

80+160+60= 300.

So either way it's 300!

Hope this helped!

Answer: The complete question is "A circle has a radius of \blue{3}3start color #6495ed, 3, end color #6495ed. An arc in this circle has a central angle of 20^\circ20 ∘ 20, degrees. What is the length of the arc?"

The length of the arc is 1.06667 units.

Step-by-step explanation:

According to the question the radius of the circle [tex]R=3 \, units[/tex] and central angle of arc is [tex]\Theta =20^{o}[/tex]

As we know that the length of the arc is given as: [tex]L=R\Theta[/tex]

Where R is radius of the circle, L is the length of the arc and  [tex]\Theta[/tex] is central angle in radian.

Now, [tex]\Theta =20^{o}\times \frac{\Pi }{180}=\frac{\Pi }{9} \, rad[/tex]

Therefore, length of the arc is

[tex]L=3\times \frac{\Pi }{9}=\frac{\Pi }{3} =\frac{3.14}{3}=1.0466667 \, units[/tex]

Answer:

y=-5/2x-1

Step-by-step explanation:

first find the gradient whereas since the two lines are parallel they hav the same gradient. y=mx+c whereas m is the gradient. 5x+2y=12

2y=-5x+12

y=-5/2x+12(so the gradient is -5/2x..... gradient=-5/2

y-4=-5/2

x+2

y-4=-5/2(x+2)

y-4=-5/2x-5

y=-5/2x-5+4

y=-5/2x-1

The equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (-2, 4) is y = -5/2 x - 1.

Equation of a line in slope intercept form is y = mx + b, where m is the slope of the line and b is the y intercept, which is the y coordinate of the point where it touches the Y axis.

Given that the equation of the line is,

5x + 2y = 12

2y = -5x + 12

y = -5/2 x + 6

This is in the slope intercept form, where the slope = -5/2.

Slopes of two parallel lines are equal.

So any line parallel to the given line will be of the form y = -5/2 x + c

Given line passes through (-2, 4).

Substituting (-2, 4) in y = -5/2 x + c, we get,

(-5/2) (-2) + c = 4

c = -1

So the equation is, y = -5/2 x - 1

Hence the required equation is y = -5/2 x - 1.

Learn more about Slope Intercept form here :

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Answer:

Aisha is shorter than 43 inches.

Step-by-step explanation:

[tex]x+5=48[/tex]

[tex]x=48-5[/tex]

[tex]x=43[/tex]

[tex]x >43[/tex]

Answer:

The answer is B!

Step-by-step explanation:

Test taking! <3

Answer:

0.2946

Step-by-step explanation:

Number of tosses, n = 200

P(obtaining a 5), p = 1/6

q = 1 - p = 5/6

Normal approximation for binomial distribution

P(X < A) = P(Z < (A - mean)/standard deviation)

Mean = np

= 200 x 1/6

= 33.33

Standard deviation = √npq

= √(200(1/6)(5/6) )

= 5.27

P(at most 30 fives) = P(X ≤ 30)

= P(Z < (30.5 - 33.33)/5.27) (continuity correction of 0.5 is added to 30)

= P(Z < -0.54)

= 0.2946

Answer:

  a.  235°

  b. 146.03 km

  c. 105 km

  d. 193 km

Step-by-step explanation:

a. The bearing of E from A is given as 55°. The bearing in the opposite direction, from E to A, is this angle with 180° added:

  bearing of A from E = 55° +180° = 235°

__

b. The internal angle at E is the difference between the external angle at C and the internal angle at A:

  ∠E = 134° -55° = 79°

The law of sines tells you ...

  CE/sin(∠A) = CA/sin(∠E)

  CE = CA(sin(∠A)/sin(∠E)) = (175 km)·sin(55°)/sin(79°) ≈ 146.03 km

  CE ≈ 146 km

__

c. The internal angle at C is the supplement of the external angle, so is ...

  ∠C = 180° -134° = 46°

The distance PE is opposite that angle, and CE is the hypotenuse of the right triangle CPE. The sine trig relation is helpful here:

  Sin = Opposite/Hypotenuse

  sin(46°) = PE/CE

  PE = CE·sin(46°) = 146.03 km·sin(46°) ≈ 105.05 km

  PE ≈ 105 km

__

d. DE can be found from the law of cosines:

  DE² = DC² +CE² -2·DC·CE·cos(134°)

  DE² = 60² +146.03² -2(60)(146.03)cos(134°) ≈ 37099.43

  DE = √37099.43 ≈ 192.6 . . . km

  DE is about 193 km

Answer:

Camera 2nd has to cover the maximum angle, i.e. [tex]78.70^\circ[/tex].

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle [tex]\triangle ABC[/tex] with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles [tex]\angle A, \angle B, \angle C[/tex]

As per Law of cosine:

[tex]cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}[/tex]

Putting the values of a,b and c to find out angles [tex]\angle A, \angle B, \angle C[/tex].

[tex]cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ[/tex]

[tex]cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ[/tex]

[tex]cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ[/tex]

Camera 2nd has to cover the maximum angle, i.e. [tex]78.70^\circ[/tex].

Answer:

65

Step-by-step explanation:

C^2= A^2 + B^2

C^2 = (60)^2 + (25)^2

C^2 = 4225

Take the square root of C

C = 65

Answer:

65

Step-by-step explanation:

Use the Pythagorean Theorem to find the length of the hypotenuse.

[tex]a^2+b^2=c^2[/tex]

I'm assuming that '60' and '25' are measures of the legs, since the question asks to find the hypotenuse.

[tex]60^2+25^2=c^2\\\rightarrow 60^2=3600\\\rightarrow 25^2 = 625\\3600+625=c^2\\4225=c^2\\\sqrt{4225}=\sqrt{c^2}\\\boxed{65=c}[/tex]

The hypotenuse should measure 65 units.

Answer:

Step-by-step explanation:

Hello,

qop(2)=q(p(2))

p(2) = 4+3=7

[tex]q(7) = \sqrt{7+2}=\sqrt{9}=3[/tex]

so

qop(2)=3

and poq(2)=p(q(2))

[tex]q(2)=\sqrt{2+2} = \sqrt{4}=2[/tex]

p(2) = 7

so poq(2)=7

thanks

The answer is "[tex]\bold{(q \circ p)(2)= 3}\ and \ \bold{(p \circ q)(2)=7}[/tex]" and the further explanation can be defined as follows;

Given:

[tex]\to \bold{p(x)=x^2+3}\\\\\to \bold{q(x)=\sqrt{x+2}}[/tex]

Find:

[tex]\bold{(q \circ p)(2)=?}\\\\\bold{(p \circ q)(2)=?}[/tex]

Solve the value for [tex]\bold{(q \circ p)(2)}\\\\[/tex]:

[tex]\to \bold{(q \circ p)(2)= q \circ p(2) =q(p(2))}\\\\[/tex]

[tex]\therefore\\\\ \to \bold{p(2)=2^2+3= 4+3=7}\\\\\ \because \\\\ \to \bold{q(p(2))=\sqrt{7+2}=\sqrt{9}=3}[/tex]

Solve the value for [tex]\bold{(p \circ q)(2)}\\\\[/tex]:

[tex]\to \bold{(p \circ q)(2)= p \circ q(2)= p (q(2))}\\\\[/tex]

[tex]\therefore\\\\ \to \bold{q(2)=\sqrt{2+2}=\sqrt{4}=2}\\\\\ \because \\\\ \to \bold{p(q(2))=2^2+3= 4+3=7}[/tex]

Therefore the final answer of "[tex]\bold{(q \circ p)(2)= 3}\ and \ \bold{(p \circ q)(2)=7}[/tex]"

Learn more:

brainly.com/question/14270968

Answer:

a number that is divisible by 10 is also divisible by 5 because 5 is a factor of 10.

Step-by-step explanation:

Given : Statement  'The relationship between numbers divisible by 5 and 10'.

To find : What statement BEST explains the statement?

Solution :

First we study the divisibility rules,

Rule for the number divisible by 5 is that number must end in 5 or 0.

Rule for the number divisible by 10 is that number need to be even and divisible by 5, as the prime factors of 10 are 5 and 2 and the number to be divisible by 10, the last digit must be a 0.

According to the divisibility rules Option D is correct.

Therefore, The correct statement explains the relationship between numbers divisible by 5 and 10 is a number that is divisible by 10 is also divisible by 5 because 5 is a factor of 10.

Answer:

Due to the higher z-score, Norma should be offered the job

Step-by-step explanation:

Z-score:

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

Whoever has the higher z-score should get the job.

Norma:

Norma got a score of 84.2; this version has a mean of 67.4 and a standard deviation of 14.

This means that [tex]X = 84.2 \mu = 67.4, \sigma = 14[/tex]

So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{84.2 - 67.4}{14}[/tex]

[tex]Z = 1.2[/tex]

Pierce:

Pierce got a score of 276.8; this version has a mean of 264 and a standard deviation of 16.

This means that [tex]X = 276.8, \mu = 264, \sigma = 16[/tex]

So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{276.8 - 264}{16}[/tex]

[tex]Z = 0.8[/tex]

Reyna:

Reyna got a score of 7.62; this version has a mean of 7.3 and a standard deviation of 0.8.

This means that [tex]X = 7.62, \mu = 7.3, \sigma = 0.8[/tex]

So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{7.62 - 7.3}{0.8}[/tex]

[tex]Z = 0.4[/tex]

Due to the higher z-score, Norma should be offered the job

Answer:

The probability is 0.31

Step-by-step explanation:

To find the probability, we will consider the following approach. Given a particular outcome, and considering that each outcome is equally likely, we can calculate the probability by simply counting the number of ways we get the desired outcome and divide it by the total number of outcomes.

In this case, the event of interest is  choosing 3 laser printers and 3 inkjets. At first, we have a total of 25 printers and we will be choosing 6 printers at random. The total number of ways in which we can choose 6 elements out of 25 is [tex]\binom{25}{6}[/tex], where [tex]\binom{n}{k} = \frac{n!}{(n-k)!k!}[/tex]. We have that [tex]\binom{25}{6} = 177100[/tex]

Now, we will calculate the number of ways to which we obtain the desired event. We will be choosing 3 laser printers and 3 inkjets. So the total number of ways this can happen is the multiplication of the number of ways we can choose 3 printers out of 10 (for the laser printers) times the number of ways of choosing 3 printers out of 15 (for the inkjets). So, in this case, the event can be obtained in [tex]\binom{10}{3}\cdot \binom{15}{3} = 54600[/tex]

So the probability of having 3 laser printers and 3 inkjets is given by

[tex] \frac{54600}{177100} = \frac{78}{253} = 0.31[/tex]

Answer:

Part 1.

Juice = 8 L.

Lemonade = 32 L.

Part 2.

20 L punch Josie can make.

Part 3.

New ratio juice : lemonade = 2 : 9

Step-by-step explanation:

Part 1.

1+4 = 5 parts altogether, 1 parts for juice and 4 parts for lemonade.

40 : 5 = 8 L is 1 part.

Juice - 1 part - 8 L.

Lemonade - 4 parts - 4*8 = 32 L.

Part 2.

1 parts of juice needs 4 parts of lemonade

4 L of juice     needs  x L of lemonade

1 : 4 = 4 : x

x = 4*4/1 = 16 L lemonade

4+ 16 = 20 L punch Josie can make

Part 3.

It was 4 L of juice and 16 L of lemonade.

After 2 L lemonade was added, we have 4 L of juice and (16+2) = 18 L of lemonade.

4 L juice : 18 L lemonade = 4/2 L juice : 18/2 L lemonade =

= 2 L juice: 9L lemonade

New ratio juice : lemonade = 2 : 9

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from T (Kano Airport) to point U in the diagram.

Distance = Speed X Time

Therefore: Distance from T to U =50km/hr X 2 hr =100 km

It moves from Point U at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, UA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

[tex]\angle U=110^\circ[/tex]

(a)First, we calculate the distance traveled, TA by plane Y.

Using Cosine rule

[tex]u^2=t^2+a^2-2ta\cos U\\u^2=100^2+125^2-2(100)(125)\cos 110^\circ\\u^2=34175.50\\u=184.87$ km[/tex]

Plane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

[tex]=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)[/tex]

b)Flight Direction of Y

Using Law of Sines

[tex]\dfrac{t}{\sin T} =\dfrac{u}{\sin U}\\\dfrac{125}{\sin T} =\dfrac{184.87}{\sin 110}\\123 \times \sin T=125 \times \sin 110\\\sin T=(125 \times \sin 110) \div 184.87\\T=\arcsin [(125 \times \sin 110) \div 184.87]\\T=39^\circ $ (to the nearest degree)[/tex]

The direction of flight Y to the nearest degree is 39 degrees.

Answer:

Due to the fact that there is 21% chance of getting that many girls by chance and also In conjunction to that; there is no test involved as well , we can conclude that the method does not have statistical significance.

The result does not appear to have a practical significance.

Step-by-step explanation:

Given that:

In  a random selection 1936 users, we observed that the method gave birth to  950 boys and 986 girls

There is about a 21​% chance of getting that many girls if the method had no effect.

Due to the fact that there is 21% chance of getting that many girls by chance and also In conjunction to that; there is no test involved as well , we can conclude that the method does not have statistical significance.

Given that:

The number of girls = 986

Number of boys = 950

Number of babies born = 1936

The percentage of girls = number of girls born/ number of babies born

The percentage of girls = 986 /1936

The percentage of girls = 0.5093

The percentage of girls =  50.93%

We can infer that this method does not have a practical significance  because most couples would not prefer to use a method that raise the likelihood of a girl from the approximately 50% rate expected by chance to the 50.93% .

Answer:

a. Standard deviation: 4.082

Standard error: 2.041

b. The 95% confidence interval for the actual temperature is (298.5, 311.5).

Upper bound: 311.5

Lower bound: 298.5

c. Test statistic t=2.45

P-value = 0.092

d. There is no enough evidence to claim that the dial of the oven is not properly calibrated. The actual temperature does not significantly differ from 300 °F.

e. If we use a significance level of 10% (a less rigorous test, in which the null hypothesis is rejected with with less requirements), the conclusion changes and now there is enough evidence to claim that the dial is not properly calibrated.

This happens because now the P-value (0.092) is smaller than the significance level (0.10), given statististical evidence for the claim.

Step-by-step explanation:

The mean and standard deviation of the sample are:

[tex]M=\dfrac{1}{4}\sum_{i=1}^{4}(305+310+300+305)\\\\\\ M=\dfrac{1220}{4}=305[/tex]

[tex]s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{4}(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{3}\cdot [(305-(305))^2+(310-(305))^2+(300-(305))^2+(305-(305))^2]}\\\\\\ s=\sqrt{\dfrac{1}{3}\cdot [(0)+(25)+(25)+(0)]}\\\\\\ s=\sqrt{\dfrac{50}{3}}=\sqrt{16.667}\\\\\\s=4.082[/tex]

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=305.

The sample size is N=4.

When σ is not known, s divided by the square root of N is used as an estimate of σM (standard error):

[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{4.082}{\sqrt{4}}=\dfrac{4.082}{2}=2.041[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=4-1=3[/tex]

The t-value for a 95% confidence interval and 3 degrees of freedom is t=3.18.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=3.18 \cdot 2.041=6.5[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 305-6.5=298.5\\\\UL=M+t \cdot s_M = 305+6.5=311.5[/tex]

The 95% confidence interval for the actual temperature is (298.5, 311.5).

This is a hypothesis test for the population mean.

The claim is that the actual temperature of the oven when the dial is at 300 °F does not significantly differ from 300 °F.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=300\\\\H_a:\mu\neq 300[/tex]

The significance level is 0.05.

The sample has a size n=4.

The sample mean is M=305.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=4.028.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{4.082}{\sqrt{4}}=2.041[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{305-300}{2.041}=\dfrac{5}{2.041}=2.45[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=4-1=3[/tex]

This test is a two-tailed test, with 3 degrees of freedom and t=2.45, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=2\cdot P(t>2.45)=0.092[/tex]

As the P-value (0.092) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the actual temperature of the oven when the dial is at 300 °F does not significantly differ from 300 °F.

If the significance level is 10%, the P-value (0.092) is smaller than the significance level (0.1) and the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the actual temperature of the oven when the dial is at 300 °C does not significantly differ from 300 °C.

Answer:

The margin of error is 370.8.

The 90​% confidence interval for the population mean is between $167.2 and $908.8

The correct interpretation is that we are 90% sure that the true mean price for all cellphones in within the interval end-points, so option B.

Step-by-step explanation:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 2.0150

The margin of error is:

M = T*s = 2.0150*184 = 370.8.

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 538 - 370.8 = $167.2

The upper end of the interval is the sample mean added to M. So it is 538 + 370.8 = $908.8

The 90​% confidence interval for the population mean is between $167.2 and $908.8

The correct interpretation is that we are 90% sure that the true mean price for all cellphones in within the interval end-points, so option B.

Answer:

g-7

Step-by-step explanation:

Multiply the numbers

g-(1*7)

g-7

Answer:

5

Step-by-step explanation:

We know that g is an invertible function and so it must also be a one-to-one function.

This means that each input is paired with exactly one output and that each output is paired with exactly one input.

We know that g(a)=7g and g(5)=7. If the output of 7 is to be paired with exactly one input, then a must be equal to 5.

Answer:

2 acute and one right.

Step-by-step explanation:

plz mark brainliest!

Answer:

2 acute 1 right, you asked for ASAP so theres no explanation

You cant mix right and obtuse, and you cant have more than 1 obtuse in a triangle. There has to be at least 2 acute angles.

Answer:

the dimension of the poster = 90 cm length and 60 cm  width i.e 90 cm by 60 cm.

Step-by-step explanation:

From the given question.

Let p be the length of the of the printed material

Let q be the width of the of the printed material

Therefore pq = 2400 cm ²

q = [tex]\dfrac{2400 \ cm^2}{p}[/tex]

To find the dimensions of the poster; we have:

the length of the poster to be p+30 and the width to be [tex]\dfrac{2400 \ cm^2}{p} + 20[/tex]

The area of the printed material can now be:  [tex]A = (p+30)(\dfrac{2400 }{p} + 20)[/tex]

=[tex]2400 +20 p +\dfrac{72000}{p}+600[/tex]

Let differentiate with respect to p; we have

[tex]\dfrac{dA}{dp}= 20 - \dfrac{72000}{p^3}[/tex]

Also;

[tex]\dfrac{d^2A}{dp^2}= \dfrac{144000}{p^3}[/tex]

For the smallest area [tex]\dfrac{dA}{dp }=0[/tex]

[tex]20 - \dfrac{72000}{p^2}=0[/tex]

[tex]p^2 = \dfrac{72000}{20}[/tex]

p² = 3600

p =√3600

p = 60

Since p = 60 ; replace p = 60 in the expression  q = [tex]\dfrac{2400 \ cm^2}{p}[/tex]   to solve for q;

q = [tex]\dfrac{2400 \ cm^2}{p}[/tex]

q = [tex]\dfrac{2400 \ cm^2}{60}[/tex]

q = 40

Thus; the printed material has the length of 60 cm and the width of 40cm

the length of the poster = p+30 = 60 +30 = 90 cm

the width of the poster = [tex]\dfrac{2400 \ cm^2}{p} + 20[/tex] = [tex]\dfrac{2400 \ cm^2}{60} + 20[/tex]  = 40 + 20 = 60

Hence; the dimension of the poster = 90 cm length and 60 cm  width i.e 90 cm by 60 cm.